Reflection by thin layers. In the figure, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) The waves of rays r1 and r2 interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in the table below refers to the indexes of refraction n1, n2, and n3, the type of interference, the thinlayer thickness L in nanometers, and the wavelength ? in nanometers of the light as measured in air. Where ? is missing, give the wavelength that is in the visible range. Where L is missing, give the second least thickness or the third least thickness as indicated.

Answers

Answer 1

Light is incident perpendicularly on a thin layer of material with index of refraction n2, which is sandwiched between two thicker materials with indices of refraction n1 and n3. The waves of rays r1 and r2 interfere, and the type of interference (either maximum or minimum) is specified.

To solve the problem, you can use the concept of reflection and refraction at the interfaces between the three materials. When light travels from one medium to another with a different refractive index, it will be refracted (bent) at the interface. The amount of bending is determined by the indices of refraction of the two media and the angle at which the light is incident on the interface.

If the light is incident at an angle that is greater than the critical angle for the interface, total internal reflection will occur, and the light will be reflected back into the first medium. If the light is incident at an angle that is less than the critical angle, it will be partially reflected and partially transmitted into the second medium.

In this problem, the light is incident perpendicularly on the interface between materials 1 and 2, so the angle of incidence is 90°. The critical angle for this interface can be calculated using Snell's Law: n1/n2 = sin(90°)/sin(θc) where θc is the critical angle. Once you have calculated the critical angle, you can determine the amount of reflection and refraction that occurs at the interface by comparing the angle of incidence to the critical angle.

If the angle of incidence is greater than the critical angle, total internal reflection will occur and all of the light will be reflected back into material 1. If the angle of incidence is less than the critical angle, some of the light will be reflected and some will be transmitted into material 2. The same process can be applied to the interface between materials 2 and 3 to determine the amount of reflection and refraction that occurs at this interface.

Once you have determined the amount of reflection and refraction at each interface, you can use this information to calculate the thickness of the thin layer (L) or the wavelength of the light (λ), depending on the values that are given in the problem.

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Related Questions

Determine the rTo understand the concept of nodes of a standing wave.
The nodes of a standing wave are points where the displacement of the wave is zero at all times. Nodes are important for matching boundary conditions, for example that the point at which a string is tied to a support has zero displacement at all times (i.e., the point of attachment does not move).
Consider a standing wave, where y represents the transverse displacement of a string that extends along the x direction. Here is a common mathematical form for such a wave:

y(x,t)=Acos(kx)sin(ωt),

where A is the maximum transverse displacement of the string (the amplitude of the wave), which is assumed to be nonzero, k is the wavenumber, ω is the angular frequency of the wave, and t is time.
Part A
Which one of the following statements about wave y(x,t) is correct?

adius of the 236U nucleus.

Answers

Answer:

The nodes of a standing wave are points where the displacement of the wave is zero at all times nodes are important for matching boundary conditions for example that the point at which a string is tied to a support has zero displacement at all times ie the point of attachment does not move consider a standing

A metal ball began a free fall from the top of a building towards a sandy soil ground so that its velocity at the moment of striking the ground was 30 m/s, if the ball stopped after 0.01 s of penetrating the sand and the average resistance force of the sand again the motion of the ball was-3010 N, the mass of the ball is approximately equal to (Given that: The acceleration due to gravity is 10 m/s²) ​

Answers

The mass of the metal ball is approximately equal to 0.1 kg.

Freefall is a type of motion in which an object falls with gravitational acceleration without resistance from air, surface, or medium. In a freefall, the only force acting on an object is the force of gravity. In a freefall, the acceleration of an object is given by the formula:  `g = 9.81 \(m/s^2`\)

The final velocity of a freefalling object can be calculated using the formula: `v = g*t `Where v is the final velocity, g is the gravitational acceleration, and t is the time taken to reach the final velocity. The force acting on an object is equal to the product of the mass of the object and the acceleration acting on the object. This is known as Newton's Second Law of Motion.

The formula for calculating force is:  `F = ma`.Where F is the force acting on the object, m is the mass of the object, and a is the acceleration acting on the object.Given that the velocity of the metal ball at the moment of striking the ground was 30 m/s, and that it stopped after penetrating the sand for 0.01 s, we can calculate the mass of the metal ball using the formula for force.

We can assume that the force acting on the metal ball is equal to the average resistance force of the sand against the motion of the ball.

The formula for calculating force is: `F = ma`.

Rearranging the formula, we get: `m = F/a` .

Substituting the given values, we get:  `

m = -3010/10`

Thus, the mass of the metal ball is approximately equal to 0.1 kg.

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Electricity is distributed from electrical substations to neighborhoods at 13000 V. This is a 60 Hz oscillating (AC) voltage. Neighborhood transformers, seen on utility poles, step this voltage down to the 120 V that is delivered to your house.

Required:
a. How many turns does the primary coil on the transformer have if the secondary coil has 130 turns?
b. No energy is lost in an ideal transformer, so the output power Pout from the secondary coil equals the input power Pin to the primary coil. Suppose a neighborhood transformer delivers 280 A at 120 V. What is the current in the 1.3×10^4 V line from the substation?

Answers

Answer:

a)  N₁ = 14083 turns,  b)   I₁ = 2.58 A

Explanation:

The relationship that describes the relationship between the primary and secondary of the transformer is

         \(\frac{V_2}{N_2} = \frac{V_1}{N_1}\)

a) They indicate that the secondary has N2 = 130 turns, the turns of the primary are

         N₁ = \(N_2 \frac{V_1}{V_2}\)

         N₁ = \(130 \ \frac{13000}{120}\)

         N₁ = 14083 turns

b) since there are no losses, the power of the neighboring transformer is

          P = V I

          P = 120 280

          P = 33600 W

this is the same power of the substation

          P = V₁  I₁

          I₁ = P / V₁

          I₁ = 33600/13000

          I₁ = 2.58 A

a ball is thrown directly downward with an initial speed of 8.45 m/s, from a height of 29.8m. After what time interval does it strike the ground?

Answers

Answer:

Approximately \(1.75\; {\rm s}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance is negligible.)

Explanation:

Find the velocity of the ball right before landing using the following SUVAT equation:

\(\displaystyle v^{2} - u^{2} = 2\, a\, x\),

Where:

\(v\) is the velocity of the ball right before landing,\(u = 8.45\; {\rm m\cdot s^{-1}}\) is the initial velocity,\(a = 9.81\; {\rm m\cdot s^{-2}}\) is the acceleration, and\(x = 29.8\; {\rm m}\) is the change in the height of the ball.

Rearrange this equation to find \(v\):

\(\begin{aligned}v &= \sqrt{u^{2} + 2\, a\, x} \\ &= \sqrt{(8.45)^{2} + 2\, (9.81)\, (29.8)}\; {\rm m\cdot s^{-1}} \\ &\approx 25.61\; {\rm m\cdot s^{-1}}\end{aligned}\).

Divide the change in velocity by acceleration to find the time elapsed:

\(\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{25.61 - 8.45}{9.81} \; {\rm s}\\ &\approx 1.75\; {\rm s}\end{aligned}\).

According to the FITT Principle you should exercise how many days ?

Answers

you should exercise 2-3 times per week

A projectile is launched at an angle of 60° from the horizontal and at a velocity of
12.0 m/s. What is the horizontal velocity of the projectile? *

Answers

Answer:

60*12.0= 720 = v/60 * 12.0 squared which is 1,728

Explanation:

Horizontal velocity component: Vx = V * cos(α)

The horizontal velocity of the projectile is 6.0m/s

If a projectile is launched at an angle from the horizontal and at a velocity v, the horizontal velocity of the projectile is expressed as:

\(v_x =vcos \theta\)

Given the following parameters

v = 12.0m/s

\(\theta=60^0\)

Substitute the given parameters into the formula to have:

\(v_x=12.0cos60\\v_x=12.0(0.5)\\v_x=6.0m/s\\\)

Hence the horizontal velocity of the projectile is 6.0m/s

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Your friend just challenged you to a race. You know in order to beat him, you must run 15 meters within 20 seconds in a northern direction. What does your average velocity need to be to win the race? .5 meters per second, north .75 meters per second, north 1.3 meters per second, north 300 meters per second, north

Answers

.75 meters per second

!! How much voltage is needed to generate a current of 20 Amps if a line has a resistance of 10 ohms ? How much power does the appliance from question number one give off ? If the appliance runs for 3 minutes , how much energy is used ? Please help me

Answers

Answer:

Power = 4000watts

Energy = 22.22Joules

Explanation:

Power = I²R

I is the current

R is the resistance

t is the time

Given the following

I = 20Amps

R = 10ohms

t = 3miuntes = 180secs

Substitute

P = 20²*10

P = 400*10

P = 4000Watts

Hence the amount of power used is 4000Watts

Energy used = Power/time

Energy used= 4000/180

Energy used = 22.22Joules

A student club is designing a trebuchet for launching a pumpkin into projectile motion. Based on an analysis of their design, they predict that the trajectory of the launched pumpkin will be parabolic and described by the equation y(x)=ax2+bx where a=−8.0×10−3m−1, b=1.0(unitless), x is the horizontal position along the pumpkin trajectory and y is the vertical position along the trajectory. The students decide to continue their analysis to predict at what position the pumpkin will reach its maximum height and the value of the maximum height. What is the derivative of the vertical position of the pumpkin trajectory with respect to its horizontal position?

Answers

Answer:

The maximum height the pumpkin reaches occurs at 62.5 horizontal meters from its launching spot.

Explanation:

Notice that we are given the actual trajectory equation:

\(y=-0.008 \, x^2+x\)

which corresponds to a curve represented by a parabola.

We can find the maximum of this parabola with arms pointing down requesting the derivative (slope of the tangent line to the curve) to be zero :

\(y'=-0.016\,x+1\\0=-0.016x+1\\x=\frac{1}{0.016} \\x=62.5\,\,m\)

The maximum height the pumpkin reaches occurs at 62.5 horizontal meters from its launching spot.

The calculation is as follows;

The equation is

\(y = -0.008x^2 + x\)

that corresponds to a curve presented by a parabola.

Now we can determine the maximum of this parabola with arms pointing down requesting the derivative slope of the tangent line to the curve to be zero

So,

\(y' = -0.016x + 1\\\\0 = -0.016x + 1\\\\x = 1/div 0.016\\\\\)

= 62.5m

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Three strings, attached to the sides of a rectangular frame, are tied together by a knot as shown in the figure. The magnitude of the tension in the string labeled C is 56.3 N. Calculate the magnitude of the tension in the string marked A.

Three strings, attached to the sides of a rectangular frame, are tied together by a knot as shown in

Answers

The magnitude of the tension in the string marked A is 39.5 N.

What is the tension in A?

The tension in A is determined thus:

The angle at A, θ = tan⁻¹(3/8) = 20.56

When extrapolated below negative x, the angle at B, α = tan⁻¹(5/4) = 51.34

When extrapolated below negative x, the angle at C, β = tan⁻¹(1/6) = 9.46

Taking the horizontal components of tension;

56.3cos(9.46) = A * cos(20.56) + B * cos(51.34)

0.6247B= 55.53 - 0.936A

B = (55.53 - 0.936A)/0.6247 ----(1)

Taking the vertical components of tension;

56.3 * sin(9.46) + A * sin(20.6) = B * sin(51.3)

9.25 + 0.35A = 0.78B  ---- (2)

substitute the value (1)  in (2)

9.25 + 0.35A = 0.78{(55.53 - 0.936A)/0.6247}

(9.25 + 0.35A) * 0.6247 = 43.31 - 0.73A

0.22A + 0.73A = 43.31 - 5.78

0.93A = 37.53

A = 39.5 N

In conclusion, the tension in A is determined by solving for the vertical and horizontal components of tension.

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Help !! I hate science

Help !! I hate science

Answers

Answer:

iron nail rusting

Explanation:

A) Iron nail rusting

Analyze the data on the plot below. Determine the speed of the hawksbill sea turtle during each interval listed below.

HELP PLEASE!!!

Analyze the data on the plot below. Determine the speed of the hawksbill sea turtle during each interval

Answers

Answer:

Day 0 to day 2: 5km/day

Day 2 to day 3: 2km/day

Explanation:

Day 0 to day 2: 10/2 = 5

Day 2 to day 3: 12 - 10 = 2

To Calculate:

The x-axis, or the days from 0 to 6, line up with the y-axis, or the distance from 0 to 24.  The point in the graph means that on that day, the turtle traveled that much distance.  For example, on the third point (2, 10), the day is 2 and the distance is 10.  To find the distance over multiple days, catalog the days in your mind and look for the points.  Then, find the difference.  For example, from day 2 (2, 10) to day 5 (5, 18), this would look like: 5 - 2 = 3, and 18 - 10 = 8, so this means that over 3 days, the turtle traveled 8 km.

If vector A represents displacement from point O(x1, y1,z1) and P(x2, Yz, Z2) ؟

If vector A represents displacement from point O(x1, y1,z1) and P(x2, Yz, Z2)

Answers

The magnitude of the displacement of the vector A is determined as 6.2 units.

What is the magnitude of displacement of the vector?

The magnitude of the displacement of the vector is calculated as follows;

| A | = √[ (x₂ - x₁ )²  +  (y₂ - y₁ )² +  (z₂ - z₁ )²]

where;

| A | is the magnitude of vector Ax₂  and x₁ are the final and initial position on  x - coordinate respectively.y₂ and y₁ are the final and initial position on  y - coordinate respectively.z₂ and z₁ are the final and initial position on  z- coordinate respectively.

The magnitude of vector A is calculated as;

| A | = √[ (2 - 0 )²  +  (3 - 0 )² +  (5 - 0 )²]

| A | = √ (4 + 9 + 25)

| A | = √ ( 38)

| A | = 6.2 units

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The complete question is below;

If vector A represents displacement from point O(x1, y1,z1) and P(x2, Yz, Z2). find the magnitude of the displacement of vector A.

When a 5 kg object is converted to pure energy, how many times larger is this than the amount of energy the Earth receives from the Sun every second? A. 3 times as much B. 2 times as much C. 4 times as much D. Same amount of energy

Answers

The answer is  energy 3 times as much. option A.

To calculate the amount of energy released when a 5 kg object is converted to pure energy, we can use Einstein's famous equation: E = mc². In this equation, E represents energy, m represents mass, and c represents the speed of light.

Given that the mass of the object is 5 kg, we can calculate the energy using the equation:

E = (5 kg) * (c²)

Now, to compare this energy with the amount of energy the Earth receives from the Sun every second, we need to determine the Earth's solar energy input.

The solar constant is the amount of solar radiation received per unit area at the Earth's distance from the Sun. Its average value is approximately 1361 Watts per square meter (W/m²). Multiplying this value by the surface area of the Earth (approximately 510 million square kilometers), we can estimate the total energy received by the Earth from the Sun every second.

Energy from the Sun = (1361 W/m²) * (510,000,000,000 m²)

To compare the energy released from converting a 5 kg object to energy with the energy received from the Sun, we divide the former by the latter:

Energy conversion / Energy from the Sun = [(5 kg) * (c²)] / [(1361 W/m²) * (510,000,000,000 m²)]

Simplifying the equation, we find:

Energy conversion / Energy from the Sun = (5 kg * c²) / (1361 W/m² * 510,000,000,000 m²)

The value of c² is approximately (3x10^8 m/s)² = 9x10^16 m²/s².

Plugging in the values, we get:

Energy conversion / Energy from the Sun = (5 kg * 9x10^16 m²/s²) / (1361 W/m² * 510,000,000,000 m²)

Simplifying further:

Energy conversion / Energy from the Sun ≈ 3.52

Therefore, the amount of energy released when a 5 kg object is converted to pure energy is approximately 3.52 times larger than the amount of energy the Earth receives from the Sun every second.

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What is the relationship between the density of the equipotential lines, the density of the electric field lines and the strength of the electric field?

Answers

Answer:

I dont. understand the question, maybe insert the picture?

Two horizontal forces act on an object. One force has a magnitude of 75.0 N and is directed due 30.0° south of east. The other force has a magnitude of 55.0 N and is directed due 70.0° north of west. What is the magnitude and direction of the sum of the two force vectors. Select one: 122.4 N, 43.2° north of east 130.0 N, 40.0° south of east 46.6 N, 17.1° south of east 48.3 N, 17.1° north of east 20.0 N, 40.0° north of east

Answers

Explanation:

70 degrees North of west = 110 degrees

30 degrees southof east = - 30 degrees:

Vertical components added together =

  75 (sin -30)   +    55 sin 110  =  14.18  N

Horizontal components added together =

 75 cos (-30)   + 55  cos 110    = 46.14  N

Magnitude =  sqrt ( 14.18^2 + 46.14^2 ) = 48.3   N

   direction = arctan ( 14.18 / 46.14) =  ~ 17.1 North of East

What is the momentum of a 6g bullet moving with a velocity of 1.5 × 10^3 m/s to the east?

Answers

Answer:

Momentum = Mass x Velocity

= 0.006 kg x 1.5 × 10^3 m/s

= 9 kg·m/s (to the east)

The 10/90 principle can help you take control of your situation in taking responsibility of what you can change rather than in being victim of what you cannot change. Give an example of a situation that can change for you in applying this principle.

Answers

The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.

The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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In each part calculate the kinetic energy of the given objects in joules a) an automobile whose mass is 1260kg moving at a speed of 66.3km/h b) a runner whose mass is 64.7 kg, moving at a speed of 8.52m/s c) an electron (mass 9.11x10^31kg) moving at a speed of 2.74x10^7m/s

Answers

a)

Kinetic energy (KE) = 1/2 m v^2

Where:

m = mass = 1260 kg

v = speed = 66.3 km/h = 18.42 m/s

Replacing:

KE = 1/2 (1260 kg ) (18.42 m/s )^2 = 213,756.7 J

Which correctly describes latent heat?

A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid

Answers

Option C. The heat absorbed or lost by a substance while it's changing state  correctly describes latent heat

Latent heat is the heat absorbed or lost by a substance while it is changing state.

The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.

For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.

Latent heat is not associated with a temperature change; rather, it's associated with a change of state.

For instance, the temperature of water remains at 100°C while boiling.

When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.

When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.

Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.

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Need a 5 paragraph essay in the eartsh layers and how they function/ benefit the earth!

Answers

There is more to the Earth than what we can see on the surface. In fact, if you were able to hold the Earth in your hand and slice it in half, you'd see that it has multiple layers. But of course, the interior of our world continues to hold some mysteries for us. Even as we intrepidly explore other worlds and deploy satellites into orbit, the inner recesses of our planet remains off limit from us.

However, advances in seismology have allowed us to learn a great deal about the Earth and the many layers that make it up. Each layer has its own properties, composition, and characteristics that affects many of the key processes of our planet. They are, in order from the exterior to the interior – the crust, the mantle, the outer core, and the inner core. Let's take a look at them and see what they have going on.

Like all terrestrial planets, the Earth's interior is differentiated. This means that its internal structure consists of layers, arranged like the skin of an onion. Peel back one, and you find another, distinguished from the last by its chemical and geological properties, as well as vast differences in temperature and pressure.

Explanation:

define standard atmospheric pressure ​

Answers

Standard atmospheric pressure is the average pressure exerted by the Earth's atmosphere at sea level under normal conditions. It is defined as 101.325 kPa or 1 atm and serves as a reference point for scientific measurements and comparisons related to atmospheric pressure.

Standard atmospheric pressure is the average pressure exerted by the Earth's atmosphere at sea level under normal conditions. It is defined as 101.325 kilopascals (kPa) or 1 atmosphere (atm). This pressure is used as a reference point for various scientific measurements and is crucial in fields such as meteorology, physics, and engineering.

Atmospheric pressure is caused by the weight of the air above a given point on the Earth's surface. The air is composed of molecules, mainly nitrogen (approximately 78%) and oxygen (approximately 21%), along with other trace gases. These molecules are in constant motion and exert a force on the surfaces they come into contact with, including the Earth's surface.

The standard atmospheric pressure of 101.325 kPa is equivalent to the pressure exerted by a column of mercury 760 millimeters (mm) in height in a barometer at sea level. This measurement was established as a reference point for atmospheric pressure, providing a consistent value for scientific calculations and comparisons.

It is important to note that atmospheric pressure can vary with altitude and weather conditions. As altitude increases, the atmospheric pressure decreases because the column of air above becomes thinner. In areas of high or low pressure systems associated with weather patterns, the atmospheric pressure deviates from the standard value.

The standard atmospheric pressure is a valuable reference in many applications. For instance, it is used as a standard for measuring gas pressure in laboratories and industrial processes. It is also used in meteorology to calculate and compare pressure systems and to study atmospheric phenomena such as wind patterns and weather changes.

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Final Answer:

If there is lower air pressure being "pushed" onto the surface of the water, then the water molecules do not need as much energy to overcome the force of atmospheric pressure pushing on the surface, and they can more easily escape and become a vapor. When the vapor pressure of the liquid is equal to the air pressure surrounding the liquid, it will boil. If you lower the air pressure, you will lower the temperature that water will boil at.

Explanation:

The boiling point of a liquid depends on the balance between the vapor pressure of the liquid and the external pressure, which is typically atmospheric pressure. When the external pressure is reduced, such as at higher altitudes or in a vacuum, the liquid molecules require less energy to escape the surface and become vapor. This is because there is less force pushing down on the liquid's surface, allowing for easier vaporization.

At lower air pressure, the water molecules can overcome the diminished force of atmospheric pressure more readily, requiring less heat energy to transition from liquid to vapor. When the vapor pressure of the liquid equals the surrounding air pressure, the liquid will start to boil.

Boiling point and vapor pressure are fundamental concepts in thermodynamics and phase transitions. Understanding how pressure affects the boiling point of liquids is crucial in various scientific and engineering applications, such as cooking, chemical processes, and high-altitude cooking.

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Question 1 of 10 The energy diagram shows the changes in energy during a chemical reaction. Which statement best describes the total energy change of the system? Potential energy Reaction progress O A. Energy is absorbed, and the products have higher potential energy. O B. Energy is absorbed, and the reactants have higher potential energy C. Energy is released, and the reactants have higher potential energy. O D. Energy is released, and the products have higher potential energy.​

Answers

Answer: The Answer is C

Explanation:

I just got this question and took a guess I got it correct lol. Higher potential energy and energy is released.

The statement which best describes the total energy change of the system is energy is absorbed, and the reactants have higher potential energy.

What is potential energy?

Potential energy is the energy which a body posses because of its position. The potential energy is the stored energy.

The energy diagram shows the changes in energy during a chemical reaction.

Potential energy and Reaction progress are shown in the problem. The reactants are the substance which reacts and form one or more than one product.

The reactants in a chemical reaction increases the potential energy for the reaction.



Thus, the statement which best describes the total energy change of the system is energy is absorbed, and the reactants have higher potential energy.

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Consider a rotating object. On that object, select a single point that rotates. How does the angular velocity vector of that point compare to the linear velocity vector at that point

Answers

Answer:

 v = w r

Explanation:

The linear and angular variables are related, specifically the linear velocity is equal to the angular velocity multiplied vectorially by the radius

          v = w x r

in general if the radius and the angular velocity are perpendicular

          sin  90 = 1

          v = w r

A bike accelerates from 0 m/s to 15 m/s over the span of 5 seconds. How fast is the bike
traveling after 2.5 seconds?

Answers

The bike is travelling at 22.5 m/s after 2.5 s

What is acceleration?

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a is the acceleration v is the final velocity u is the initial velocity t is the time

How to determine the acceleration Initial velocity (u) = 0 m/sFinal velocity (v) = 15 m/sTime (t) = 5 sAcceleration (a) =?

a = (v – u) / t

a = (15 – 0) / 5

a = 3 m/s²

How to determine the final velocity in the first 2.5 s Initial velocity (u) = 15 m/sAcceleration (a) = 3 m/s²Time (t) = 2.5 s Final velocity (v) = ?

a = (v – u) / t

3 = (v – 15) / 2.5

Cross multiply

v – 15 = 3 × 2.5

v – 15 = 7.5

Collect like terms

v = 7.5 + 15

v = 22.5 m/s

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An astronaut measure the period of a mass spring system on Earth. How would the period be affected if the astronaut measured the period of the same mass spring system on the moon? (Moon's gravity = 1/6 Earth's gravity.)

Answers

An astronaut measure the period of a mass spring system on Earth.

The period of a mass spring system on the moon would be longer than the period on Earth. This is because the period of a mass spring system is dependent on the square root of the ratio of the mass to the spring constant, and the acceleration due to gravity. Since the acceleration due to gravity on the moon is only 1/6th of that on Earth, the restoring force on the mass will be weaker, resulting in a longer period. Therefore, the astronaut would measure a longer period for the same mass spring system on the moon than on Earth.

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A spring oscillates with a frequency of 2.09 Hz. What is its period?
(Unit=s)

Answers

Time period of a wave is the inverse of its frequency. The period of the wave with a frequency of 2.09 Hz is 0.47 seconds.

What is frequency ?

Frequency of a wave is the number of wave cycles per unit time. Frequency is the inverse of the time period of the wave. Hence, it has the unit of s⁻¹ which is equivalent to Hz.

The higher frequency of a wave indicates more number of wave cycles in a short time. Frequency is directly proportional to the energy and inversely proportional to the  wavelength.

Given the time period of the wave = 2.09 Hz

then frequency = 1/2.09 Hz = 0.47 s.

Therefore, the time period  of the wave is 0.47 seconds.

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Assume that you have a meter stick balanced on a pivot, and pile of additional masses that you can hang on the meter stick.

What is the minimum number of additional masses that you need to hang from the meter stick in order to determine the mass of the meter stick itself?

0
1
2
3
It's a trick question, you cannot uses masses to determine the mass of the meter stick.

Answers

Answer:

You will not need any mass to determine the mass of the stick.

Explanation:

The mass of an object, like the stick, can only be determined according to Newton's second law, which states that the mass of an object is equal to the force of that object, divided by the mass of the object. It is obvious that we do not know what is the force and acceleration value of the stick shown in the question above, however, it is impossible to know what is the mass of it, adding external masses to the stick.

PLEASE HELP
What is the change in internal energy if 80 J of thermal energy is released
from a system, and 30 J of work are done on the system? Use AU = Q-W.

Answers

Answer: Delta U = 30 - 80; -50 jules

Explanation:

The system is losing 80 J, but it is also gaining 30 J because the surroundings are doing work on it. So the net change in energy is -50 J

define scalar quantity​

Answers

Answer:

Scalar quantities are physical quantities which have a magnitude and direction.

e.g. in 5 km, 5 is the magnitude(number) and km is the unit.

some scalar quantities are mass, length, distance, speed, power, energy, temperature etc.

Answer: Values with magnitude but without direction

Explanation:

Majorly there exists two types of quantities, Scalar and Vector.

Vectors: Quantities, with magnitude and direction.

Example: Force, Displacement

Scalars: Quantities, with magnitude but without direction.

Example: Weight, Length, Quantity

we do not need direction to define weight,

it is just 5 kilograms, and NOT 5 kilograms towards east.

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