Refer to the Introduction section where the identity of the rate- determining reaction was discussed. Suppose that the rate constant for reaction (1a) increases by 2% for each increase of 1 degree C, and the Q. What would be the percent decrease in the observed elapsed time when the temperature increases by 1 degree c ? a)2% b)20% c)2+20= 22% d)0.02 X 20 = 0.4%
Answers
To determine the percent decrease in the observed elapsed time when the temperature increases by 1 degree Celsius, we need to consider the relationship between the rate constant and the temperature.
k = k₀ * e^(Ea / (R * T))
Δk / k = 2% = 0.02
The rate constant (k) for reaction (1a) is temperature-dependent and can be expressed as:
k = k₀ * e^(Ea / (R * T))
where k₀ is the rate constant at a reference temperature, Ea is the activation energy, R is the gas constant, and T is the absolute temperature.
Given that the rate constant increases by 2% for each increase of 1 degree Celsius, we can express this as:
Δk / k = 2% = 0.02
Now, we can calculate the percent decrease in the observed elapsed time by considering the relationship between the rate constant and the reaction rate:
Rate = k * [reactant]
Since the reaction rate is inversely proportional to the elapsed time, we can say:
Elapsed time ∝ 1 / Rate
Therefore, the percent decrease in the observed elapsed time would be the same as the percent decrease in the rate constant, which is 2%.
So, the correct answer is option (a) 2%.
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Related Questions
Which event in a solar cell uses the photoelectric effect?
Answers
Answer:
Electromagnetic waves strike a semiconductor, removing some of
its electrons, which form a current.
Answer:Electromagnetic waves strike a semiconductor, removing some of its electrons, which form a current.
Explanation:
which is an example of interdependence between species?
A. Sea turtles lay their eggs in the sand
B. Animals eat seeds, then those seeds are spread by animals
C. Trees make carbohydrates from solar energy
D. Polar bears eat seals on ice floes
Answers
B. Animals eat seeds, then those seeds are spread by animals
step-by-step explanation:
interdependence is the dependence of two or more living things on each other
Animals eat seeds, then those seeds are spread by animals.
In interdependence if the population of an organism rises and falls, then they can affect the rest of the ecosystem.Here plants are dependent on animals for depression of seeds and animals are dependent on plants for foodWhat is interdependence?Interdependence means dependence of living beings on each other for their survival.All organisms from tiny microbes to huge predators, depend upon each other to obtain energy and other basic resources.To know more on interdependence here
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A spherical ball of lead has a diameter of 7. 0 cm. What is the mass of the sphere if lead has a density of 11. 34 g/cm3 ? (the volume of a sphere is 43πr3 where r is the radius. )
Answers
A spherical ball of lead has a diameter of 7. 0 cm. Therefore, the mass of the lead sphere is approximately 2036.37 grams. To find the mass of the lead sphere, one need to calculate its volume first using the formula for the volume of a sphere.
Volume = (4/3) × π × \(r^3\)
Given that the diameter of the sphere is 7.0 cm, one can find the radius (r) by dividing the diameter by 2:
Radius (r) = Diameter / 2 = 7.0 cm / 2 = 3.5 cm
Now one can substitute the radius value into the volume formula:
Volume = (4/3) ×π ×(3.5 cm\()^3\)
Volume ≈ 179.594 c\(m^3\)
Next, one can calculate the mass using the density of lead. The formula for mass is:
Mass = Density × Volume
Given that the density of lead is 11.34 g/c\(m^3\), one can substitute the values into the formula:
Mass = 11.34 g/c\(m^3\) × 179.594 c\(m^3\)
Mass ≈ 2036.367 g or approximately 2036.37 g
Therefore, the mass of the lead sphere is approximately 2036.37 grams.
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A box sits on the horizontal bed of a truck accelerating to the left. Static friction between the box and the truck keeps the box from sliding around as the truck accelerates. The work done on the box by the static friction force as the accelerating truck moves a distance D to the left is:a. positiveb. zeroc. negatived. dependent on the speed of the truck
Answers
The work done on the box by the static friction force is zero.
What is work done ?Work is a measure of the energy transferred to or from an object by a force when the object is displaced. The amount of work done is defined as the product of the magnitude of the force and the distance over which the force is applied. It could be written as
Work (W) = Force (F) x Distance (d) x cos(theta)
where theta is the angle between the force and the displacement.
When a force is applied to an object, work is done if there is displacement in the direction of the force. If there is no displacement, no work is done. If the force is perpendicular to the displacement, no work is done, as the cosine of 90 degrees is zero.
Work is a scalar quantity and is measured in joules (J) in the SI system. One joule of work is done when a force of one newton (N) is applied over a distance of one meter (m) in the direction of the force.
Work can be either positive or negative, depending on the direction of the force and the displacement. When the force and displacement are in the same direction, the work is positive. When the force and displacement are in opposite directions, the work is negative.
The work done on the box by the static friction force is zero.
This is because the static friction force acts perpendicular to the displacement of the box. Therefore, the angle between the static friction force and the displacement of the box is 90 degrees. In this case, the work done by the static friction force is given by the dot product of the force and the displacement, which is equal to Fdcos(theta), where theta is the angle between the force and the displacement. Since cos(90) = 0, the work done by the static friction force is zero.
Note that although the static friction force does no work on the box, it does provide the necessary force to keep the box in place and prevent it from sliding around as the truck accelerates.
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what happens to the brightness of bulb b if bulb a is removed from the circuit? construct the correct explanation. drag the terms on the left to the appropriate blanks on the right to complete the sentences. resethelp if bulb b is removed, the potential difference across bulb a blank.target 1 of 4 since the power dissipated by the resistance of the bulb is given by blank and its resistance blank, the brightness of bulb a blank.
Answers
Removing bulb A from the circuit does not have any effect on the brightness of bulb B.
If bulb A is removed from the circuit, the potential difference across bulb B remains the same. Since the power dissipated by the resistance of the bulb is given by P = \(V^{2}\)/R and its resistance remains unchanged, the brightness of bulb B will stay the same.
When bulbs are connected in parallel, they experience the same potential difference across them. Therefore, removing bulb A does not affect the potential difference across bulb B.
The power dissipated by a resistance is given by the equation P = \(V^{2}\)/R, where P is the power, V is the potential difference, and R is the resistance. Since the resistance of bulb B remains the same, the power dissipated by bulb B remains constant. The brightness of a bulb is directly proportional to the power dissipated, so if the power remains constant, the brightness of bulb B will also remain unchanged.
Therefore, removing bulb A from the circuit does not have any effect on the brightness of bulb B.
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two spheres of mass m and a third sphere of mass m form an equilateral triangle, and a fourth sphere of mass m4 is at the center of the triangle. the net gravitational force on that central sphere from the three other spheres is zero. what is m in terms of m?
Answers
The mass m in terms of m4 is equal to the square root of 3 times the mass m4.
Let's assume that the equilateral triangle formed by the three spheres with mass m has side length s.
Then, the distance between the center of any of the three spheres and the center of the central sphere is s/2.
Using the formula for the gravitational force between two masses, the magnitude of the gravitational force between each of the three spheres with mass m and the central sphere with mass m4 is:
\(F = G * (m * m4) / ((s/2)^2)\)
where G is the gravitational constant.
Since the net gravitational force on the central sphere from the three other spheres is zero, the magnitudes of the gravitational forces from the three spheres must be equal and opposite in direction, so:
\(F = G * (m * m4) / ((s/2)^2) = G * (m * m4) / ((s/2)^2)\)
Simplifying this equation, we get:
\(m = sqrt(3) * m4\)
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How much heat is absorbed by 17 grams of water that is heated from 50°C to 120°C? (Specific heat capacity of water is 1.0 cal/gºC) SHOW YOUR WORK *
Answers
Answer:
Q = 1190 [cal]
Explanation:
In order to solve this problem, we must use the following equation of thermal energy.
\(Q=m*C_{p}*(T_{final}-T_{initial})\)
where:
Q = heat energy [cal]
Cp = specific heat = 1 [cal/g*°C]
T_final = final temperature = 120 [°C]
T_initial = initial temperature = 50 [°C]
m = mass of the substance = 17 [g]
Now replacing:
\(Q=17*1*(120-50)\\Q=1190[cal]\)
if anhydrous methanol is used, how is water getting into the system?
Answers
Water can enter the system from different sources such as air, moisture, or impurities in the materials used.
Even if anhydrous methanol is used, water can still get into the system from various sources. One source is the air, which can carry moisture. The moisture can condense in the system as the air cools, especially in colder environments, such as when refrigeration is used in the system. Another source is impurities in the materials used in the system, such as equipment and piping, which can contain water and release it into the system.
It is essential to prevent water from getting into the system as it can lead to various problems such as corrosion, damage to equipment, and changes in the process conditions, which can affect the product quality. The system should be designed, operated, and maintained to minimize the ingress of water. This can be done by using high-quality materials, controlling the environment, using appropriate procedures, and regularly monitoring and testing the system for water content.
Water can enter the system even if anhydrous methanol is used. Therefore, it is important to prevent water ingress by using appropriate materials, procedures, and monitoring techniques to ensure the quality and safety of the process.
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Television is an integral part of our daily entertainment. For which of these processes has the television not used any form of energy?
Answers
The Question does not contain any option, the question is incomplete.
I think the Question may be :
Television is an integral part of our daily entertainment. for which of these processes has the television not used any form of energy?
A. manufacturing
B. packaging
C. storage
D.none of the above
The operation of televisions requires the use of energy throughout its entire lifecycle, from the manufacturing process, packaging, storage, transportation, and its use by consumers. The correct option is D.
During the manufacturing process, the television components need to be assembled and tested, which requires the use of energy to power the machinery and tools used in the process.
Packaging and storage also require energy to produce and maintain suitable conditions for the television until it is sold to consumers.
Transportation of televisions from the manufacturing facility to retailers or directly to consumers requires the use of energy for shipping and logistics. Finally, the use of televisions by consumers requires energy to power the device and produce the images and sounds on the screen.
Therefore, The correct answer is D i.e none of the above
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Determine the condition of the airplane:
Pilot and copilot = 400 lb
Passengers -- aft position = 240 lb
Baggage = 20 lb
Fuel = 75 gal
Answers
The condition of the airplane, considering the weights of the pilot, copilot, passengers, baggage, and fuel, is important for ensuring safe flight operations and determining the aircraft's center of gravity.
To assess the condition of the airplane, we need to calculate the total weight and the location of its center of gravity (CG). Let's break down the given weights:
- Pilot and copilot: 400 lb
- Passengers (aft position): 240 lb
- Baggage: 20 lb
- Fuel: 75 gal
To determine the total weight, we sum up the weights of the pilot, copilot, passengers, baggage, and fuel. Assuming the average weight of fuel is approximately 6 lb/gal, the total weight would be:
400 lb + 240 lb + 20 lb + (75 gal * 6 lb/gal) ≈ 1,110 lb.
To calculate the CG location, we need to know the arm (distance) from a reference point. Without that information, it is difficult to provide a precise assessment. The CG position affects the aircraft's stability and control. It is crucial to ensure the CG is within specified limits to maintain safe flight characteristics.
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name two situations in which light behaves like a wave and two situations in which light behaves like a particle.
Answers
Two situations in which light behaves like a wave are diffraction and interference. The two situations in which light behaves like a particle photoelectric effect and Compton scattering.
What are two examples of situations in which light exhibits wave-like behavior and two examples of situations in which it exhibits particle-like behavior?Two situations in which light behaves like a wave are:
Diffraction: When light waves pass through an opening or around an obstacle, they bend and spread out, creating a pattern of bright and dark regions. This phenomenon is known as diffraction and is a characteristic property of waves.
Interference: When two or more light waves overlap, they can reinforce or cancel each other out, producing a pattern of bright and dark regions. This phenomenon is known as interference and is also a characteristic property of waves.
Two situations in which light behaves like a particle are:
Photoelectric effect: When light shines on a metal surface, electrons can be ejected from the surface. This phenomenon is known as the photoelectric effect and can be explained by the particle-like behavior of light, where light is considered to consist of discrete packets of energy called photons.
Compton scattering: When X-rays or gamma rays collide with matter, they can scatter off the particles in the matter, causing a decrease in energy and a change in the direction of the radiation. This phenomenon is known as Compton scattering and can also be explained by the particle-like behavior of light, where photons are considered to collide with the particles in the matter and transfer some of their energy to them.
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ACTIVITY 3: THE CHOICE IS YOURS!
Directions: Read each item carefully. Choose the letter of the best answer.
____1. What is the advantage of an electromagnet compared to a permanent magnet?
A. Electromagnet is lighter.
B. Electromagnet can be turned on and off.
C. Permanent magnet cannot be used to pick up metals.
D. Electromagnet can be used for attracting more metals.
____2. What are the factors that affect the strength of an electromagnet?
A. Battery, magnet, and core
B. Dry cells, nail, and magnet
C. Number of coil, number of magnets, and wire
D. Number of coils/wire, number of batteries/dry cells, and properties of the core
____3. What could make an electromagnet stronger?
A. Use a weaker battery.
B. Reverse the poles of the magnet.
C. Remove all the coils and the nail.
D. Add more coils of wire to the nail.
____4. Complete this sentence:
"In order to form an electromagnet, a/an _______ current should flow through a coil of
______ covered around a/an ______ core. "
A. Electric, wire, iron C. Iron, electric, wire
B. Iron, wire, electric D. Wire, iron electric
_____5. You conducted an experiment using a very strong electromagnet. How can
you make it weaker?
A. Add more loops. C. Add more batteries.
B. Use a thicker wire. D. Wrap the wire loosely.
(LAS)-Science week 6 QR-3
Answers
Answer:
1 B 2 D 3 D 4 DC wire ferrite 5 D
Explanation:
what mass of tree sap could be raised from 19.0°c to its boiling point and then evaporated by this energy, assuming sap has the same thermal characteristics as water?
Answers
The mass of tree sap could be raised from 19.0°c to its boiling point and then evaporated by this energy is 2.97g.
The mass of tree sap that could be raised from 19.0°C to its boiling point and then evaporated by this energy can be calculated using the heat capacity of water.
Heat capacity is defined as the amount of energy required to increase the temperature of a substance by one degree Celsius.
For water, the heat capacity is 4.186 J/g°C. This means that for every gram of water heated by one degree Celsius, 4.186 Joules of energy is required.
To calculate the mass of tree sap that can be raised from 19.0°C to its boiling point, we can use the following equation:
Mass of tree sap = Energy / (Heat capacity x Change in temperature)
Where Energy is the total energy available, Heat capacity is 4.186 J/g°C and Change in temperature is the difference between the initial and final temperatures (i.e. 100°C - 19.0°C = 81.0°C).
Therefore, the mass of tree sap that can be raised from 19.0°C to its boiling point is:
Mass of tree sap = \(Energy / (4.186 J/gC * 81.0C)\)
mass = Energy / (335.746 J/g)
Assuming we have a total energy of 1,000 Joules, the mass of tree sap that can be raised from 19.0°C to its boiling point is:
Mass of tree sap =\(1,000 J / (335.746 J/g)\)
m = 2.97 g
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A scientist is examining an unknown solid. Which procedure would most likely help determine a chemical property of the substance?
heating it to find the temperature at which it melts
exposing it to a flame to see if it catches on fire
hitting it with a hammer to determine if it breaks or bends
placing it in water to find out whether or not it dissolves
Answers
Answer:
hitting it with a hammer to determine if it breaks or bends
Answer:
exposing it to a flame to see if it catches on fire
Explanation:
A chemical property is when the matter changes into a different substance. This is true when you expose it to a flame because if a substance is burned, it will change into a new substance. All the other options are examples of physical changes.
-I also took the quiz and got 100%
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most waves approach shore at an angle. why do they break almost parallel to shore?
Answers
Waves break almost parallel to shore due to a process called wave refraction, which causes the wave fronts to gradually align themselves parallel to the coastline as they approach shore. This ensures the energy of the waves is distributed evenly along the shore.
When waves are generated in the open ocean, they typically approach the coastline at various angles. As the waves come closer to the shore, the depth of the water decreases and the speed of the waves is affected. The portion of the wave that encounters shallower water first starts to slow down, while the part of the wave that is still in deeper water continues at a faster speed. This causes the wave to bend and its crests to become more parallel to the shoreline.
Wave refraction helps to distribute the energy of the waves along the entire coastline, minimizing the erosive impact on any single point of the shore. By breaking parallel to the shore, waves are also able to deposit sediments more evenly along the coastline, which contributes to the formation and maintenance of various coastal landforms, such as beaches and sandbars. Overall, the process of wave refraction plays a crucial role in shaping the appearance and stability of coastal areas.
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Un tubo metálico tiene 100 metros de longitud cuando está a 0 oC y 100,13 metros cuando se calienta hasta 100 oC. ¿Cuál es el coeficiente de dilatación del material?
Answers
Answer:
α= 1.3 10-5 ºC⁻¹
Explanation:
La dilatación termica de los cuerpos esta dada por la relación
ΔL = L₀ α ( T -T₀)
en este caso nos piden el coeficiente de dilatación térmica
α =DL/L₀ DT
calculemos
α = ( 100,13 -100)/[100 (100 – 0)]
α = 1,3 10-5 ºC⁻¹
Traduction
The thermal expansion of bodies is given by the relationship
ΔL = L₀ α (T -T₀)
in this case they ask us for the coefficient of thermal expansion
α = ΔL / L₀ ΔT
let's calculate
α = (100,13 -100) / [100 (100 - 0)]
α= 1.3 10-5 ºC⁻¹
Types of Spectra 5) Stars like our Sun have low-density, gaseous atmospheres surrounding their hot, dense cores. If you were looking at the spectra of light coming from the Sun (or any star), which of the three types of spectrum would be observed? Explain your reasoning.
Answers
The spectrum observed from the Sun (or any star) would exhibit an absorption spectrum. This is because the outer gaseous atmosphere of the star absorbs specific wavelengths of light, resulting in dark absorption lines in the spectrum.
In the cooler, lower-density outer atmosphere, where white light from the star travels, some atoms or molecules in the atmosphere absorb photons with particular energy. In the spectrum, these absorptions show up as black lines at specific wavelengths. The specific set of absorption lines that each element or molecule generates results in a distinctive pattern that can be used to identify the elements that are present in the star's atmosphere.
The absorption spectrum offers insightful data on the chemical make-up and physical characteristics of the star. Astronomers can ascertain the elements present, their abundances, and other characteristics like the temperature, pressure, and velocity of the star's atmosphere by examining the absorption lines.
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listen as marisela describes her new fitness program. then indicate which activity she plans to do each day.
Answers
Marisela's fitness program may vary based on her personal preferences and goals. Additionally, the duration and intensity of each activity may differ depending on her fitness level and schedule. The key is to find a well-rounded program that includes cardiovascular exercise, strength training, flexibility work, and rest days for recovery.
Based on Marisela's description of her new fitness program, she plans to do the following activities each day:
1. Monday: Jogging - Marisela mentions that she starts her week with a morning run. Jogging is a cardiovascular exercise that can help improve endurance and burn calories.
2. Tuesday: Strength training - Marisela says that on Tuesdays, she focuses on strengthening her muscles. Strength training typically involves exercises like weightlifting, resistance training, or bodyweight exercises to build and tone muscles.
3. Wednesday: Yoga - Marisela mentions that she incorporates yoga into her routine on Wednesdays. Yoga is a mind-body practice that combines physical postures, breathing exercises, and meditation. It helps improve flexibility, strength, and relaxation.
4. Thursday: High-intensity interval training (HIIT) - Marisela states that she does HIIT workouts on Thursdays. HIIT involves short bursts of intense exercise followed by brief recovery periods. It is known for its effectiveness in burning calories and improving cardiovascular fitness.
5. Friday: Swimming - Marisela mentions that she enjoys swimming on Fridays. Swimming is a low-impact, full-body workout that improves cardiovascular fitness, builds muscle strength, and increases flexibility.
It's important to note that Marisela's fitness program may vary based on her personal preferences and goals. Additionally, the duration and intensity of each activity may differ depending on her fitness level and schedule. The key is to find a well-rounded program that includes cardiovascular exercise, strength training, flexibility work, and rest days for recovery.
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1. The thin top layer of the crust is called the Crust. What are the two types of
crust?
O Magma and Nickel
O Inner Core and Outer Core
O Oceanic and Continental
O Lithosphere and Mantle
Answers
Describe the properties of waves and explain how they can be measured.
Why is a sound wave considered a mechanical wave?
Answers
The properties of waves are: wavelength, time period.
Sound wave is considered a mechanical wave because it requires medium to travel.
What is mechanical wave?A mechanical wave is one whose energy cannot be transmitted via a vacuum. To transfer their energy from one place to another, mechanical waves need a medium.
A mechanical wave is something like a sound wave. A vacuum can not be traversed by sound waves.
Units of time and space can be used to measure the fundamental characteristics of waves. The length between wave crests, or wavelength (L), and the time it takes a wave to pass a fixed point, or period (T), are two characteristics that can be measured directly.
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how would sunspots appear if you could magically remove them from the sun?
Answers
If we could magically remove sunspots from the sun, it would appear smoother and more uniform in its brightness. Sunspots are darker, cooler regions on the sun's surface caused by magnetic activity, which creates areas of intense magnetic fields that suppress the movement of heat and gas.
Removing sunspots would affect the sun's overall magnetic field, which could potentially impact the sun's activity and influence space weather. Sunspots are closely related to solar flares and coronal mass ejections, which can cause disruptions in communication and navigation systems on Earth.
However, it is important to note that sunspots are a natural occurrence of the sun and play a significant role in regulating the sun's temperature and energy output. Removing them could have unintended consequences and may not be a practical solution.
Instead, scientists study sunspots to better understand the sun's behavior and predict potential space weather events. They use tools such as the Solar Dynamics Observatory to monitor the sun's activity and gather data that can inform space weather forecasts and help protect our technological infrastructure.
In conclusion, while removing sunspots may seem like a solution, it is important to consider the potential consequences and the valuable role they play in our understanding and management of the sun's behavior.
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definition of motion?
Answers
Answer: The action of something moving or being moved
Explanation:
Answer:
The act or process of changing position or place.
Example:
Wind.
A ball being thrown.
Someone running.
A fish swimming.
Example in a sentence:
Raindrops fell as if in slow motion, and lightning stayed, brighter than the midday sun.
The highest involuntary deceleration survived by a human is 1762 m/s2. Formula-1 racecar driver David Purley crashed into a wall going 110 mph. How much distance in meters was covered during this massive deceleration? Report answer with two significant digits and do not forget units.
Answers
The kinematics can be found that for the stopping distance the answer is:
x = 0.686 m
Kinematics studies the motion of bodies, giving relationships between position, velocity and acceleration, let's use the relationship.
v² = v₀² - 2 a x
Where v is the velocity, v₀ the initial velocity, at the acceleration x the distance traveled
The reference system of units are coordinate systems selected by convention to exchange magnitudes with precision and reliability, the most used system is the international system of measurements (SI), let's reduce the magnitudes
v₀ = 110 mi / h (1609.34 m / 1 mi) (1h / 3600s) = 49.17 m /s
This case as the car stops its final speed is zero
0 = v₀² - 2a x
x = v₀² / 2a
We calculate
x = 49.17² / 2 1762
x = 0.686 m
In conclusion using kinematics we can find that for the braking distance the answer is:
x = 0.686 m
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Help! Plssssss 30 points!
Answers
What an objects movement is slowing down it is called ____acceleration
Answers
Explanation:
When an object slows down, its acceleration is opposite to the direction of its motion. This is known as deceleration.
Answer: deceleration
Explanation:
How are faults that occur in the middle of tectonic plates different from plate boundaries?
Answers
Divergent boundaries – where two plates are moving apart.
Transform boundaries – where plates slide passed each other.
:)
Causes of Earthquake
An earthquake is caused by a sudden slip on a fault. The tectonic plates are always slowly moving, but they get stuck at their edges due to friction.
Five causes of earthquake?
1. Volcanic Eruptions. The main cause of the earthquake is volcanic eruptions.
2. Tectonic Movements. The surface of the earth consists of some plates, comprising of the upper mantle
3. Geological Faults
4. Groundwater extraction – decrease in pore pressure.
5. Groundwater – increase in pore pressure.
6. Heavy rain.
7. Pore fluid flow.
8. High CO2 pressure.
9. Building dams.
Explanation:
Now, Boundaries between tectonic plates are made up of faults. which are associated with the various types of fault, normal, reverse and strike-slip faults
More so, Plate boundaries are always faults, but not all faults are plate boundaries.
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A large pendulum swings in the lobby of the United Nations building in New York City. The pendulum has a 91-kg gold-plated bob and a length of 22.9 m. Assume g = 9.81 m/s2.
Part A
How much time does it take for the bob to swing from its maximum displacement to its equilibrium position?
Express your answer to three significant figures and include the appropriate units.
Answers
Answer:
t = 2.40 s
Explanation:
It just told me
Car AMass: 1,500 kgVelocity: 10 m/sCar BMass: 1,500 kgVelocity: 25 m/sCar CMass: 1,000 kgVelocity: 10 m/sWhich order shows decreasing momentum?A, B, CB, A, CC, B, A
Answers
Answer:
B, A, C
Explanation:
The momentum is equal to the mass times the velocity, so for each car the momentum is equal to
Car A
Momentum = Mass x Velocity
Momentum = 1,500 kg x 10 m/s
Momentum = 15,000 kg m/s
Car B
Momentum = Mass x Velocity
Momentum = 1,500 kg x 25 m/s
Momentum = 37,500 kg m/s
Car C
Momentum = Mass x Velocity
Momentum = 1,000 kg x 10 m/s
Momentum = 10,000 kg m/s
Then, the decreasing momentum is B, A, C because
37,500 is greater than 15,000 and 15,000 is greater than 10,000
So, the answer:
B, A, C
Calculate the angular momentum of a 265 kg motorcycle traveling at 25 m/s. Traveling around a circular curve 500 m in radius
Answers
The angular momentum of a 265 kg motorcycle traveling at 25 m/s around a circular curve with a radius of 500 m is \(3,312,500 \;kg.m^2/s.\)
To calculate the angular momentum of the motorcycle, we need to first find its angular velocity. Since the motorcycle is traveling around a circular curve, we can use the formula:
\(v = r\omega\)
where v is the velocity of the motorcycle, r is the radius of the curve, and ω is the angular velocity.
Rearranging this formula to solve for ω, we get:
\(\omega = v/r\)
Substituting the values given, we get:
\(\omega = 25 \;m/s \;/ \;500 m = 0.05 \;rad/s\)
Next, we can use the formula for angular momentum:
\(L = I\omega\)
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
For a point mass moving in a circular path, the moment of inertia is simply mr², where m is the mass of the motorcycle and r is the radius of the curve.
Substituting the values given, we get:
\(L = (265 \;kg)(500 \;m)^2(0.05 \;rad/s)\)
\(L = 3,312,500 \;kg.m^2/s\)
Therefore, the angular momentum of the motorcycle is \(3,312,500 \;kg.m^2/s.\)
In summary, the angular momentum of a 265 kg motorcycle traveling at 25 m/s around a circular curve with a radius of 500 m is \(3,312,500 \;kg.m^2/s.\)
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a cylinder with , and a diameter is being pulled by a string with a force . the cylinder rolls on a surface with a coefficient of friction of horizontally: a cable reel on a flat surface is pulled by a force at its center. friction exists between the reel and the surface. determine r, and the acceleration. is the cylinder slipping?
Answers
The radius of the cylinder is approximately 2.19 m, and the cylinder is experiencing a deceleration of approximately 1.86 m/s². Since the cylinder is decelerating and the force applied is less than the friction force, it is not slipping.
From the given information:
Mass of the cylinder, m = 5 kg
Moment of inertia of the cylinder, I = 12 kg·m²
Diameter of the cylinder, D = 0.5 m
Force applied, F = 25 N
Coefficient of friction, μ = 0.7
Radius of the cylinder, r = ?
To determine the radius (r) of the cylinder, we can use the relationship between moment of inertia (I) and mass (m) for a solid cylinder:
I = (1/2) * m * r²
Given I = 12 kg·m² and m = 5 kg, we can solve for r:
12 = (1/2) * 5 * r²
r² = 12 / (1/2) * 5
r² = 12 / 2.5
r² = 4.8
r ≈ √4.8
r ≈ 2.19 m
So, the radius of the cylinder is approximately 2.19 m.
Now, let's determine the acceleration of the cylinder. The force applied is given as F = 25 N. The friction force can be calculated using the equation:
Friction force = μ * Normal force
Since the cylinder is being pulled by the string, the normal force is equal to the weight of the cylinder, which is given by:
Weight = mass * acceleration due to gravity
Weight = m * g
Assuming a standard acceleration due to gravity of 9.8 m/s²:
Weight = 5 kg * 9.8 m/s² = 49 N
Friction force = μ * Normal force = μ * Weight = 0.7 * 49 N = 34.3 N
Now, we can calculate the net force acting on the cylinder:
Net force = Force applied - Friction force
Net force = 25 N - 34.3 N
Net force = -9.3 N
Since the net force is negative, indicating that the force applied is less than the friction force, the cylinder will experience a deceleration rather than acceleration. The magnitude of the deceleration can be calculated using Newton's second law:
Net force = mass * acceleration
-9.3 N = 5 kg * acceleration
acceleration = -9.3 N / 5 kg
acceleration = -1.86 m/s²
The negative sign indicates that the deceleration is in the opposite direction to the force applied, which means the cylinder is moving in the direction opposite to the applied force.
Hence, the radius of the cylinder is approximately 2.19 m, and the cylinder is experiencing a deceleration of approximately 1.86 m/s². Since the cylinder is decelerating and the force applied is less than the friction force, it is not slipping.
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