Red shift and light spectra

Answers

Answer 1

Answer:

what I do not understand :(


Related Questions

The perimeter of parallelogram pqsr is 74 cm. What is qs?.

Answers

qs is 37 - y cm.

Let the two parallel sides of the parallelogram PQRS be PQ and SR respectively.

Also, let the two adjacent sides of the parallelogram be PQ and QS. Let the length of PQ be x cm and that of QS be y cm.

Thus, the length of SR would also be x cm.

Therefore, the perimeter of the parallelogram is 2(x + y) cm = 74 cm. Hence,x + y = 37 cm

Again, we know that the opposite sides of the parallelogram are equal. So, QS = PQ = x cm. QS = x = 37 - y

Therefore, qs is 37 - y cm.

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In a car engine, what type of energy is released at a high level, leading to inefficiency?

A. Mechanical
B. Electrical
C. Chemical
D. Thermal

Answers

Thermal energy is the answer

What is the conversion of 210 c to f ?

Answers

The conversion from 210 Celsius to Fahrenheit is 410 degrees Fahrenheit. To convert Celsius to Fahrenheit, you can use the formula (Celsius x 9/5) + 32 = Fahrenheit.

The equation F = 9/5C + 32 relates temperature measured in degrees Celsius (C) to degrees Fahrenheit (F). The formula is used to convert temperatures from Celsius to Fahrenheit , and vice versa. To use the formula, you simply plug in the known temperature in Celsius (or Fahrenheit), and then solve for the unknown temperature in Fahrenheit (or Celsius).

To convert Celsius to Fahrenheit, you would use the formula F = 9/5C + 32, where C is the temperature in Celsius and F is the temperature in Fahrenheit. Thus, 210 Celsius to Fahrenheit is 410 degrees Fahrenheit.

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A 40-mc charge is positioned on the x axis at x = 4.0 cm. where should a -60-mc charge be placed to produce a net electric field of zero at the origin?

Answers

To create a net electric field of zero at the origin, a -60-microcoulomb charge should be placed at a position on the x-axis that is symmetrically opposite to the 40-microcoulomb charge, specifically at x = -4.0 cm.

The net electric field at a point is the vector sum of the individual electric fields created by each charge present. In this scenario, a 40-microcoulomb charge is positioned at x = 4.0 cm on the x-axis.

To produce a net electric field of zero at the origin (x = 0), a -60-microcoulomb charge needs to be placed at a location that cancels out the electric field produced by the 40-microcoulomb charge.

Since electric fields follow the inverse square law, the -60-microcoulomb charge should be positioned at a symmetrically opposite point on the x-axis, specifically at x = -4.0 cm. This way, the electric field vectors generated by the charges will cancel each other out, resulting in a net electric field of zero at the origin.

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what is the difference between copernicus and kepler description of planetary orbits?

Answers

Answer:

Kepler refined the Copernican model. Orbits are not circles along which planets move at a constant speed, but ellipses, in the central focus of which is the Sun. The planet moves in an ellipse with a variable speed depending on the distance to the Sun. On this basis, Kepler significantly simplified the Copernican model and formulated the laws of planetary motion in their orbits.


what is friction? effect of force​

Answers

Answer:

Force

Explanation:

Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. Dry friction is a force that opposes the relative motion of two solid surface in contact.


In an element's square on the periodic table, the number with the greatest numerical value represents the
number of neutrons.
number of electrons.
atomic number.
atomic mass.

Answers

Answer: Atomic mass

Explanation:

I took the test!

your welcome

Answer:

Atomic Mass on edge2020

Explanation:

Just did it. And got it correct.

The public is not yet able to purchase cars powered by hydrogen fuel cells because engineers have to determine how
the cars perform based on which scenario?
O on racetracks
O in real-world conditions
O in flooded environments
O on closed courses
Next
Submit
Save and Exit
return

Answers

Probably in real world conditions

Answer:

B on EDGE

Explanation:

What is the level of institutional care available if the imposters could go undetected for a
period of days and, in some cases, weeks?

Answers

Answer:

Dissociative fugue A memory loss for anything having to do with personal memory.

Explanation:

For which of the following properties does the Moon have the largest value compared to the other planetary satellites (not moons of dwarf planets) in the Solar System?

Answers

The moon is a natural satellite that orbits Earth. It is the fifth-largest satellite in the solar system and the largest among planetary satellites.

What are the properties of the moon?

The following properties are the ones where the Moon has the largest value compared to other planetary satellites:

Size: The moon is the fifth-largest satellite in the solar system, with a diameter of 3474 km. No other planetary satellite is as large as the moon. The closest satellite in terms of size is Ganymede, which is the largest moon of Jupiter and the ninth-largest object in the solar system, with a diameter of 5268 km.

Mass: The moon has a mass of 7.342 × 1022 kg, which is about 1.2% of Earth's mass. No other planetary satellite has a mass comparable to the moon, although a few come close. Ganymede has a mass of 1.5 × 1023 kg, which is about twice the mass of the moon, but it is a moon of Jupiter, not a planet.

Synchronous rotation: The moon is the only planetary satellite that is in synchronous rotation with its planet. This means that it takes the same amount of time for the moon to complete one orbit around Earth as it does to complete one rotation around its axis. As a result, the same side of the moon always faces Earth. No other planetary satellite has this property.

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what two elements are highlighted on group 3 of the periodic table​

Answers

Answer:

hello! Jaesuk~Sakai here!

Explanation:

The four group 3 elements are scandium, yttrium, lanthanum and actinium. “lanthanide” refers to the elements between lanthanum and lutetium. That term does not encompass scandium and yttrium. Scandium and yttrium act pretty much identically to lanthanides.

happy to help!!

Remember to always stay happy no matter what happens! ^^

Is there an inverse relationship between wavelength and frequency?

Answers

Wavelength and frequency are inversely proportional to one another.The wavelength of a wave that has a high frequency is also its shortest.

Does the link between wavelength and frequency have an opposite? Wavelength and frequency have an inverse relationship.The wavelength of the wave with the highest frequency is the smallest.Half the wavelength is equivalent to twice the frequency.Because of this, the wavelength ratio is the opposite of the frequency ratio.Frequency and wavelength are inversely related to one another, as shown by the equation v = f.The link between a wavelength and its frequency is inverse because when one changes, the other does too, which changes the wave's total energy.Frequency, or the quantity of wave cycles per second, and wavelength have an inverse relationship.The wavelength of the signal decreases with increasing frequency.

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0.042 kg … ________________grams

Answers

Answer:

42 grams

Explanation:

you multiply the value by 1000 to get your answer

0.042 kg is equal to 42 grams. To convert Kg to g, multiply by 10^3 power

a refrigerator has a coefficient of performance equal to 5.00. the refrigerator takes in 120j of energy from a cold reservoir in each cycle. find (a) the work required in each cycle and (b) the energy expelled to the hot reservoir

Answers

The work required in each cycle is 24 joule

The Coefficient of performance (COP) of a refrigerator is defined as the ratio of the heat removed from the cold reservoir to the work input required. In this case, the COP is given as 5.00, which means that for every 1 joule of work input, the refrigerator removes 5 joules of heat from the cold reservoir.

To find the work required in each cycle, we can use the equation:

COP = heat removed / work input

We know that COP = 5.00 and heat removed = 120 J, so we can solve for work input:

5.00 = 120 J / work input

work input = 24 J

Therefore, the work required in each cycle is 24 joule

The energy expelled to the hot reservoir can be found using the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added minus the work done by the system. In this case, the internal energy of the refrigerator remains constant, so we can simplify the equation to:

heat added = work done

We know that the work required in each cycle is 24 J, so the heat added to the hot reservoir must also be 24 J. Therefore, the energy expelled to the hot reservoir in each cycle is 24 joules.

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Currently, the world population is about:
A. 7 billion
B. 450 million
C. 1.2 trillion
D. 700 million

Answers

A. 7 billion, I looked it up on Google and it said 7.8 billion
The answer is A 7 billion

if 20 boys can sweep the school compound in 8 minutes, how many boys can sweep it in 10minutes​

Answers

Answer:

So this is just a ratio/proportion problem

so lets say its in boys:minutes

so in the first scenario

20:8

and we want to find

x:10

So proportion really

20/8=x/10

cross multiply

25

25 boys can sweep it in 10 minutes

Cyclist 1 pedals 40 kilometers east in 2 hours. Cyclist 2 pedals 10 kilometers west in half an hour. Based on this information, which statement about cyclists is correct?

Answers

Answer:

See Explanation

Explanation:

Given

Cyclist 1:

\(Distance = 40km\)

\(Time = 2hr\)

\(Direction = East\)

Cyclist 2:

\(Distance = 10km\)

\(Time = 0.5hr\)

\(Direction = West\)

The question requires options. Since none is given,  I'll answer on a general term.

First, calculate the speed of both cyclists

\(Speed = \frac{Distance}{Time}\)

Cyclist 1:

\(Distance = 40km\)

\(Time = 2hr\)

\(Speed = \frac{40km}{2hr}\)

\(Speed = 20km/hr\)

Cyclist 2:

\(Distance = 10km\)

\(Time = 0.5hr\)

\(Speed = \frac{10km}{0.5hr}\)

\(Speed = 20km/hr\)

The following can be deduced from above:

Both cyclists travel at the same speed of 20km/hrBoth cyclists travel in opposite directions

Define the types of friction and give FOUR examples of each
Static Friction
Rolling Friction
Sliding Friction
Fluid Friction

Answers

Static Friction is the force that keeps an object at rest
example: pushing against a heavy box but it isnt moving due to the weight of the box and gravity pulling it down

Rolling friction is a resistive force that slows down something thats rolling such as a ball or a wheel
example: a rolling soccer being slowed down from grass

Sliding Friction is the friction created from two object sliding against eachother, just like kinetic friction. It is intended to make the object stop
example: A sled sliding down a hill against snow

Fluid Friction is the force that resist motion in fluid or something moving around a fluid.
example: water pushing against a swimmer when swimming through it

Amplitude measures
O the length of the wave
O the height of the wave
O how many waves past a certain point in a certain amount of time
O the distance the wave travels

Answers

Explanation:

the distance the wave travel

A baboon steals an apple and runs to a nearby boulder 10.0\,\text m10.0m10, point, 0, start text, m, end text to its left. The baboon reaches the boulder in 1.0\,\text s1.0s1, point, 0, start text, s, end text with a constant acceleration of 20.0\,\dfrac{\text m}{\text s^2}20.0 s 2 m ​ 20, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction leftward. What was the baboon's initial velocity when it started running to the boulder?

Answers

Given that,

Distance = 10 m

Time = 1.0 sec

Acceleration a =20 m/s²

We need to calculate the baboon's initial velocity

Using equation of motion

\(s=ut+\dfrac{1}{2}at^2\)

Where, s = distance

t = time

a = acceleration

Put the value in to the formula

\(10=u\times1+\dfrac{1}{2}\times20\times1^2\)

\(u=10-10\)

\(u=0\ m/s\)

Hence, The baboon's initial velocity is zero.

Microbial food infections are usually not seen until ______ after eating contaminated food.

Answers

Answer:

2 to 4 hours

Explanation:

Given that,

Microbial food infections

We know that,

Food infection :

When we eat old food, uncooked, fermented food, more junk food and contaminated food then 2 to 4 hours after eating we started vomiting, headache then we affected by food infections.

So, we can say that microbial food infections are usually not seen until 2 to 4 hours after eating contaminated food.

A 0. 25 kg baseball is in contact with a bat for 0. 0075 s and exerts a force of 18,500 N. What impulse is delivered to the ball? 33 kg • 140 kg • 4600 kg • 74,000 kg •.

Answers

The Impulse delivered to the ball is 138.75 Ns or 138.75 kgm/s.

Impulse: This is the product of force and time.

Formula:

I = Ft................. Equation 1

Where:

I = Impulse on the baseballF = Force exerted on the baseballt = time of contact

From the question,

Given:

F = 18500 Nt = 0.0075 s

Substitute these values into equation 1

I = 18500(0.0075)I = 138.75 Ns or 138.75 kgm/s

Hence, The Impulse delivered to the ball is 138.75 Ns or 138.75 kgm/s

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It is advisable to place room heater at the ground level for effective heating

Answers

Answer:

yes

Explanation:

The heater is placed near the floor because the air currents move upwards so the hot air fills up the whole room. Whereas, an air conditioner is placed near the ceiling because the cold breeze tends to settle down. If it is placed near the floor then it will fill just the bottom of the room with cool air.

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it in 45mins please, i will defina
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In the Newton's ring experiment, the diameter of 4 and 10% dark ring are 0.30 cm and 0.62 cm, respectively. a) What is the diameter of 15th dark ring? b) Calculate the wavelength of the light, if the

Answers

Answer: In the Newton's ring experiment, the diameter of the 4th dark ring is 0.30 cm and the diameter of the 10th dark ring is 0.62 cm. We can use this information to find the diameter of the 15th dark ring and calculate the wavelength of the light.

Explanation:

In the Newton's ring experiment, the diameter of the 4th dark ring is 0.30 cm and the diameter of the 10th dark ring is 0.62 cm. We can use this information to find the diameter of the 15th dark ring and calculate the wavelength of the light.

a) To find the diameter of the 15th dark ring, we can use the formula for the diameter of the nth dark ring:

d_n = sqrt(n * λ * R)

where d_n is the diameter of the nth dark ring, n is the order of the ring, λ is the wavelength of the light, and R is the radius of curvature of the lens.

Since we want to find the diameter of the 15th dark ring, we can substitute n = 15 into the formula and solve for d_15:

d_15 = sqrt(15 * λ * R)

b) To calculate the wavelength of the light, we can use the formula:

λ = (\(d_10^2 - d_4^2\)) / (\(10^2 - 4^2\))

where d_10 is the diameter of the 10th dark ring and d_4 is the diameter of the 4th dark ring.

Substituting the given values, we have:

λ = (\(0.62^2 - 0.30^2\)) / (\(10^2 - 4^2\))

Simplifying this expression will give us the value of the wavelength of the light used in the experiment.

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Which section from the article BEST explains why wavelength and frequency are dependent on each other? (A) "Amplitude And Height" (B) "Wavelength And Cycle" (C) "Frequency And Period" (D) "Speed"

Answers

C! Bejxjxksjxjcu u jkdmskxckc

A 16 kg object and a 25 kg object are connected by a massless compressed spring and rest on a frictionless table. After the spring is released, the object with the smaller mass has a velocity of 4 m/s to the left. What is the velocity of the object with the larger mass?
Answer in units of m/s.

Answers

The velocity of the object with the larger mass is 2.56 m/s.

The given parameters:

Mass of the first object, m₁ = 16 kgMass of the second object, m₂ = 25 kgSpeed of the smaller object, v₁ = 4 m/sSpeed of the larger object, v₂ = ?

The speed of the larger mass is determined by applying the principle of conservation of linear momentum as follows;

\(m_1v_1 = m_2v_2\\\\v_2 = \frac{m_1v_1}{m_2} \\\\v_2 = \frac{16\times 4}{25} \\\\v_2 = 2.56 \ m/s\)

Thus, the velocity of the object with the larger mass is 2.56 m/s.

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A 12,000 kg object is being pushed by a 25 N force. What is the acceleration?

Answers

480 is the acceleration

7. From the choices below, select ALL that are results of radioactive decay.
-the nuclear ejection of electrons
-nuclear fission
-radiation emission
-the nuclear capture of electrons
-nuclear fusion

Answers

the nuclear capture of electrons

(13%) Problem 5: A solid sphere of mass M and radius R rolls without slipping down rough incline that makes an angle € with the horizontal Otheexpertta.COm Find thc magnitudc of thc lincar accclcration a of thc sphcrc _ (Frade Summary Deductions Polenlial [uu% a = 5 g sine 5 a = 9 sine a = cose Submissions Atterrpts remnaining: 5 (2040 per attetupt) detailed vicw a = 9 C = g sine a = 9 cose Submil Hint Feedback give up'

Answers

The magnitude of the linear acceleration a of the sphere is 5/7gsinθ whose mass is M and radius is R.

Given the radius of sphere = R

The mass of sphere = M

The angle of inclination = θ

Let the linear acceleration = a

The horizontal force component = F x = Mgcosθ

The vertical force component = Fy = Mgsinθ

The magnitude of linear acceleration of the sphere can be determined using the equation of motion for a body rolling without slipping.

The friction will be acting opposite to the force such that:

Mgsinθ = Ma + Ff

Mgsinθ = Ma + Iα/R

The moment of inertia of solid sphere I = 2/5MR^2

gsinθ = a + 2/5a

gsinθ = a( 1 + 2/5)

a = 5/7gsinθ

Therefore, the magnitude of the linear acceleration of the sphere is equal to 5/7gsinθ.

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(13%) Problem 5: A solid sphere of mass M and radius R rolls without slipping down rough incline that

A car is traveling at 15. 5 m/s, and the driver sees a traffic light turn red. After 0. 321 s (the reaction time), the driver applies the brakes, and the car decelerates at 6. 2 m/s2. What is the stopping distance of the car, as measured from the point where the driver first sees the red light?

Answers

Stopping distance of the car, as measured from the point where the driver first sees the red light, is 43.95 meters We can use distance-time formula.

To calculate the stopping distance of the car, we need to determine the distance traveled during the driver's reaction time and the distance traveled while the car is decelerating.

During the driver's reaction time, the car will continue to move forward at its initial speed of 15.5 m/s. The distance traveled during this time is:

\(d_reaction = v_initial * t_reaction = 15.5 m/s * 0.321 s = 4.98 m\)

After the driver reacts, the car begins to decelerate at a rate of \(6.2 m/s^2\). Use equation:

d =\(v_initial * t + (1/2) * a * t^2\)

where d: distance traveled, v_initial: initial velocity, t: time, a: acceleration, and final velocity = 0 (since car stops).

We need to find the distance traveled during the deceleration period, so we can rearrange the equation to solve for d:

d = \((v_initial^2) / (2a)\)

Put values:

\(d_deceleration = (15.5 m/s)^2 / (2 * -6.2 m/s^2) = 38.97 m\)

Note that we used a negative value for acceleration, since the car is decelerating (slowing down) rather than accelerating (speeding up).

The total stopping distance is the sum of the distance traveled during the driver's reaction time and the distance traveled while decelerating:

\(d_total = d_reaction + d_deceleration = 4.98 m + 38.97 m = 43.95 m\)

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