Reacting quickly to avoid being struck, the diner moves 2.00 m horizontally directly toward the waiter opening the champagne bottle. Determine the horizontal distance, d in meters, between the waiter and the diner at the time the cork reaches where the diner had previously been sitting.
Answers
The horizontal distance d in meters between the waiter and the diner at the time the cork reaches where the diner had previously been sitting is 9.7 m
What is distance?The term distance refers to the quantity of length between two points. it is usually measured in meters but has other units.
Given data
u = 15.6
∅ = 78.5 deg
g = 9.81
solving for time tt = 2 * u * sin ∅ / g
t = 2 * 15.6 * sin 78.5 / 9.81
t = 30.57 / 9.81
t = 3.12 s
Solving for horizontal distance, d in metersd = u * co ∅ * t
d = 15.6 * cos 78.5 * 3.12
d = 9.7 m
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complete question
The cork from a champagne bottle slips through the hands of a waiter opening it, moving with an initial velocity v0 = 15.6 m/s at an angle θ = 78.5° above horizontal. A diner is sitting a horizontal distance d away when this happens. Assume the cork leaves the waiter’s hands at the same vertical level as the diner and that the cork falls back to this vertical level when it reaches the diner. Use a Cartesian coordinate system with the origin at the cork's initial position.
Calculate the time, td in seconds, for the cork to reach the diner.
Reacting quickly to avoid being struck, the diner moves 2.00 m horizontally directly toward the waiter opening the champagne bottle. Determine the horizontal distance, d in meters, between the waiter and the diner at the time the cork reaches where the diner had previously been sitting.
Related Questions
Which two options are homogeneous mixtures?
A. Sand
B. A wet sponge
C. Liquid dishwashing soap
O D. Vinegar
Answers
Answer:
Liquid dishwashing soap
Vinegar
A long straight wire carrying a current of 3A flowing in a direction parallel to the unit vector 1 (i+j+ k) is placed in a √√3 --↑ this is the a magnetic field of (0.75i + 0.4k)T. What is the magnetic force per unit length of the wire? A. (0.69i-0.61j - 1.3k )N/m.. B. (0.39i-0.4j-2.3 k )N/m C.(0.49i-0.51j - 1.37k )N/m D. (0.59-0.71j-0.13k )N/m
Answers
The magnetic force per unit length of the wire is (C) (0.49i - 0.51j - 1.37k) N/m.
To calculate the magnetic force per unit length of the wire, we can use the formula:
F = I * (L x B),
where F is the force, I is the current, L is the length vector of the wire, and B is the magnetic field.
Given:
Current, I = 3A
Length vector, L = √√3 * (i + j + k)
Magnetic field, B = 0.75i + 0.4k
Let's calculate the cross product of L and B:
L x B = | i j k |
|√√3 √√3 √√3|
|0.75 0 0.4|
To evaluate this cross product, we calculate the determinants:
(i) component: (√√3 * 0 - √√3 * 0.4) = -0.4√√3
(j) component: (-√√3 * 0.75 - √√3 * 0) = -0.75√√3
(k) component: (√√3 * 0.75 - √√3 * 0) = 0.75√√3
Now, multiply the cross product by the current:
F = 3A * (-0.4√√3i - 0.75√√3j + 0.75√√3k)
Simplifying this expression gives:
F = (-1.2√√3i - 2.25√√3j + 2.25√√3k) N
Therefore, the magnetic force per unit length of the wire is approximately (-1.2√√3i - 2.25√√3j + 2.25√√3k) N/m.
Comparing the given answer options, the closest match is C. (0.49i - 0.51j - 1.37k) N/m.
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Can you use an adjustable gas lift leg (Similar to office chair) on the moon?
Answers
1. A message signal m(t) has a bandwidth of 5kHz and a peak magnitude of 2V. Estimate the bandwidth of the signal u(t) obtained when m(t) frequency modulates a carrier with a) kf = 10 Hz/V, b) kf = 100 Hz/V, and c) kf = 1000 Hz/V.
Answers
Answer:
3v at 5.3 herts
Explanation:
WILL DO BRAINLIEST A jar contains seven pink, 6 orange, and four blue marbles. If you pick one without looking, what is the probability that the marble you pick will be orange?
6/10
6/17
11/17
7/11
Answers
Answer:
Choice 2: 6/17
Explanation:
4+7=11. 6+11= 17. so it's 6/17
In a DC generator, the generated emf is directly proportional to the
Answers
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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Unit Test
Unit Test Review Active
The diagram shows a position-time graph.
Position (m)
3
2
0
Position vs Time
Mark this and return
1
2
3
Time (s)
4
-2 m
-1 m
3 m
4 m
2
Save and Exit
3
What is the displacement of the object?
4
Next
5
6
7
Submit
8
Answers
The displacement of the object is 2 meters.
To determine the displacement of the object, we need to consider the change in position from the initial position to the final position.
Given:
Initial position = 0 meters
Final position = 2 meters
Calculate the displacement:
Displacement = Final position - Initial position
Displacement = 2 meters - 0 meters
Displacement = 2 meters
Therefore, the displacement of the object is 2 meters.
Explanation:
The position-time graph shows the position of an object over a specific time interval. In this case, the graph shows that the object starts at a position of 0 meters and ends at a position of 2 meters. The displacement of the object is the change in position from the initial point to the final point.
In this context, the displacement of 2 meters indicates that the object has moved 2 meters to the right or in the positive direction from its initial position. The negative and positive signs on the graph indicate the direction of motion, where positive values represent motion in one direction and negative values represent motion in the opposite direction.
The time interval is not directly related to the displacement calculation. It simply represents the duration of the object's motion. To determine the displacement, we only need to consider the initial and final positions, which in this case result in a displacement of 2 meters.
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A 53 g ice cube at −30◦C is dropped into a container of water at 0◦C. How much water freezes onto the ice? The specific heat of ice is 0.5 cal/g · ◦ C and its heat of fusion of is 80 cal/g. Answer in units of g.
Answers
For A 53 g ice cube at −30◦C is dropped into a container of water at 0◦C, the amount of water that freezes onto the ice? is mathematically given as
x = 9.93 g
What is the amount of water that freezes onto the ice?Where
Energy received = energy given out
Generally, the amount of water is mathematically given as
(53)(0.5)(30) = (80)(x)
Therefore
x = (49)(0.5)(16)/(80)
x = 9.93 g
In conclusion, the mass of water
x = 9.93 g
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a suspension bridge cable is connected to its anchor at a 20 degree angle. calculate the vertical component force on the anchor by the cable.
Answers
The question is missing some parts. Here is the complete question.
A suspension bridge cable is connected to its anchor at a 20° angle. Find the vertical and horizontal component of the force on the anchor by the cable.
Answer: \(F_{x}=\) 14095.4 N
\(F_{y}=\) 5130.3 N
Explanation: The force applied to the anchor is not perpendicular to the horizontal plane. So, it can be decomposed into 2 components: a vertical component, which is on the y-axis, and a horizontal component, which is on the x-axis.
The force and its components forms a right triangle, so we can calculate the components by using trigonometric relations:
Horizontal
\(cos(20)=\frac{F_{x}}{F}\)
\(F_{x}=F.cos(20)\)
\(F_{x}=15,000(0.9397)\)
\(F_{x}=\) 14,095.4 N
Vertical
\(sin(20)=\frac{F_{y}}{F}\)
\(F_{y}=Fsin(20)\)
\(F_{y}=\) 15,000(0.3420)
\(F_{y}=\) 5,130.3 N
The vertical and horizontal components of force on the anchor by the cable are 5130.3 N and 14095.4 N, respectively.
The vector sum of the forces acting on the beam is zero, and the sum of the moments about the left end of the beam is zero. (a) Determine the forces and and the couple (b) Determine the sum of the moments about the right end of the beam. (c) If you represent the 600-N force, the 200-N force, and the 30 N-m couple by a force F acting at the left end of the
Answers
This question is incomplete, the complete question is;
The vector sum of the forces acting on the beam is zero, and the sum of the moments about the left end of the beam is zero.
(a) Determine the forces and and the couple
(b) Determine the sum of the moments about the right end of the beam.
(c) If you represent the 600-N force, the 200-N force, and the 30 N-m couple by a force F acting at the left end of the beam and a couple M, what is F and M?
Answer:
a)
the x-component of the force at A is \(A_{x}\) = 0
the y-component of the force at A is \(A_{y}\) = 400 N
the couple acting at A is; \(M_{A}\) = 146 N-m
b)
the sum of the momentum about the right end of the beam is; ∑\(M_{R}\) = 0
c)
the equivalent force acting at the left end is; F = -400J ( N)
the couple acting at the left end is; M = - 146 N-m
Explanation:
Given that;
The sum of the forces acting on the beam is zero ∑f = 0
Sum of the moments about the left end of the beam is also zero ∑\(M_{L}\) = 0
Vector force acting at A, \(F_{A}\) = \(A_{x}i\) + \(A_{y}j\)
Now, From the image, we have;
a)
∑f = 0
\(F_{A}\) - 600j + 200j = 0i + 0j
\(A_{x}i\) + \(A_{y}j\) - 600j + 200j = 0i + 0j
\(A_{x}i\) + (\(A_{y}\) - 400)j = 0i + 0j
now by equating i- coefficients'
\(A_{x}\) = 0
so, the x-component of the force at A is \(A_{x}\) = 0
also by equating j-coefficient
\(A_{y}\) - 400 = 0
\(A_{y}\) = 400 N
hence, the y-component of the force at A is \(A_{y}\) = 400 N
we also have;
∑\(M_{L}\) = 0
\(M_{A}\) - ( 30 N-m ) - ( 0.380 m )( 600 N ) + ( 0.560 m )( 200 N ) = 0
\(M_{A}\) - 30 N-m - 228 N-m + 112 Nm = 0
\(M_{A}\) - 146 N-m = 0
\(M_{A}\) = 146 N-m
Therefore, the couple acting at A is; \(M_{A}\) = 146 N-m
b)
The sum of the moments about right end of the beam is;
∑\(M_{R}\) = (0.180 m)(600N) - (30 N-m) - ( 0.56 m)(\(A_{y}\) ) + \(M_{A}\)
∑\(M_{R}\) = (108 N-m) - (30 N-m) - ( 0.56 m)(400 N ) + 146 N-m
∑\(M_{R}\) = (108 N-m) - (30 N-m) - ( 224 N-m ) + 146 N-m
∑\(M_{R}\) = 0
Therefore, the sum of the momentum about the right end of the beam is; ∑\(M_{R}\) = 0
c)
The 600-N force, the 200-N force and the 30 N-m couple by a force F which is acting at the left end of the beam and a couple M.
The equivalent force at the left end will be;
F = -600j + 200j (N)
F = -400J ( N)
Therefore, the equivalent force acting at the left end is; F = -400J ( N)
Also couple acting at the left end
M = -(30 N-m) + (0.560 m)( 200N) - ( 0.380 m)( 600 N)
M = -(30 N-m) + (112 N-m) - ( 228 N-m))
M = 112 N-m - 258 N-m
M = - 146 N-m
Therefore, the couple acting at the left end is; M = - 146 N-m
how were the outer planets formed?
Answers
Answer:
All planets including the outer larger planets were formed at the same time somewhere around 4.5 Billion years ago.
Explanation:
the young sun drove away most of the gas from the inner solar system, leaving behind the rocky cores also known as the terrestrial planets.
The mass of Jupiter is 1.9 x 10 kg and that of the sun is 2 x 10 kg. If the distance between them is 78 x 10 km, find the gravitational force between them.
Answers
Using the formula F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them, we can calculate the gravitational force between Jupiter and the sun.
Plugging in the values, we get:
F = (6.674 x 10^-11 N * (m^2 / kg^2)) * ((1.9 x 10^27 kg) * (2 x 10^30 kg)) / (78 x 10^6 m)^2
Simplifying this, we get:
F = 1.98 x 10^27 N
Therefore, the gravitational force between Jupiter and the sun is approximately 1.98 x 10^27 Newtons.
The gravitational force between Jupiter and the sun, calculated using Newton's law of gravitation with their masses and distance, is \(1.95 * 10^{22} N.\)
The gravitational force between Jupiter and the sun is determined using Newton's law of gravitation, which states that two masses attract each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Given that the mass of Jupiter is \(1.9 * 10^{27} kg\) and that of the sun is \(2 * 10^{30} kg\), and the distance between them is \(78 * 10^6 km (which is 78 * 10^9 m)\), we can use the formula: Gravitational force = G(m1m2)/r^2where G is the universal gravitational constant, m1, and m2 are the masses of the two bodies, and r is the distance between them. Substituting the values gives Gravitational force \(= (6.67 * 10^{-11} Nm^2/kg^2) * (1.9 * 10^{27} kg) * (2 x 10^{30} kg) / (78 * 10^9 m)^2= 1.95 * 10^{22} N\)Thus, the gravitational force between Jupiter and the sun is \(1.95 * 10^{22} N.\)Summary: The gravitational force between Jupiter and the sun is found using Newton's law of gravitation, which is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Given the mass of Jupiter, the mass of the sun, and the distance between them, we can calculate the gravitational force using the formula. The gravitational force between Jupiter and the sun is \(1.95 * 10^{22} N.\)For more questions on gravitational force
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In order to use a crowbar, you apply 12 N of force. The crow bar applies 38 N of force. What is the mechanical advantage of the crowbar?
Answers
The mechanical advantage of the crowbar is 3.1667.
What is mechanical advantage of inclined plane ?The concept of work, which asserts that work produced through a basic machine (the lever) is equal to the work input, forms the basis for the mechanical advantage of the inclined plane.
The length of the slope divided by the height of the inclined plane represents the inclined plane's mechanical advantage.
Given parameters:
Input force by you= 12 N.
Output force from the crowbar = 38 N.
Then, the mechanical advantage of the crowbar = Output force from the crowbar / input force by you.
= 38N/12N.
=3.1667.
Hence, the mechanical advantage of the crowbar is 3.1667.
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A 20000kg railroad car is traveling at 5 m/s when it collided and coupled with a second, identical car at rest. What is the resulting speed of the combined cans?
Answers
We know that in a collision the momentum of the system is conserved, that is:
\(p_i=p_f\)In this case, since the railroad cars coupled together and have the same mass we have:
\(mv_1+mu_1=2mv\)Now, we know the initial velocity of the cars, one is traveling at 5 m/s and the other is at rest; plugging the values and solving for the final velocity we have:
\(\begin{gathered} 20000(5)+20000(0)=2(20000)v \\ v=\frac{5(20000)}{2(20000)} \\ v=2.5 \end{gathered}\)Therefore, the velocity of the combined cars is 2.5 m/s
You see a boat sitting at the end of a dock. Ten minutes later you see the same boat in a cove to the right of the dock. You did not see the boat move.
However, you know that the boat moved because its
relative to the dock changed.
Answers
The boat must have moved, despite not being seen to move, because its relative position to the dock has changed. This phenomenon is known as relative motion .
Everything is always in motion, but the way we perceive it depends on our frame of reference.
In this scenario, the dock was the frame of reference for the initial position of the boat. When the boat moved to the cove, its position relative to the dock changed, and the dock was no longer an appropriate frame of reference. The boat's motion is now relative to the cove instead.
It is important to note that relative motion depends on the chosen frame of reference. If we were to choose the boat as the frame of reference, then it would be the dock that appears to move, not the boat. This is because motion is always relative to a chosen frame of reference.
In conclusion, the boat must have moved because its position relative to the dock changed. The concept of relative motion reminds us that motion is always relative to a chosen frame of reference, and that the way we perceive motion depends on our chosen frame of reference.
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Hi
Please help on question asap if the answer is correct I'll rate you five stars a thanks and maybe even brainliest!
When two light bulbs are connected in series, the resistance in the circuit is increase compared to that with one lightbulb. The increased resistance opposes the flow of current so far fewer electrons pass per second , transferring less energy. The lightbulbs are therefore not as bright as In a circuit with same voltage but only one bulb.
However, when Two lightbulbs are connected in parallel, each loop behaves like a separate circuit . The resistance in each branch is the same as if there were just one light bulb in the whole circuit.there is the same current in each branch of the circuit ,so the bulbs Will light up with the same brightness as a single bulb circuit. The energy stored in the battery will decrease twice as quickly and battery will run out faster than I series circuit.
6) explain the advantages and disadvantages of arranging components in series or parallel.
Answers
Advantages of Components Arranged in Series:
1. Increased resistance: Connecting components in series increases the overall resistance in the circuit. This can be advantageous in situations where you want to limit the flow of current or control the amount of power being dissipated.
2. Voltage sharing: In a series circuit, the total voltage of the power supply is divided among the components. This can be useful when you want to ensure that each component receives a specific voltage.
3. Current consistency: The current remains the same throughout the series circuit, which can be beneficial when you need to ensure a consistent current flow through multiple components.
Disadvantages of Components Arranged in Series:
1. Reduced brightness or performance: As mentioned in the question, when light bulbs are connected in series, the increased resistance reduces the flow of current, resulting in dimmer bulbs or reduced performance in other electrical devices.
2. Single point of failure: If one component in a series circuit fails, it can disrupt the entire circuit and cause all components to stop functioning.
Advantages of Components Arranged in Parallel:
1. Brightness and performance: When components such as light bulbs are connected in parallel, each component receives the full voltage, resulting in brighter bulbs and better performance in other devices.
2. Redundancy: In a parallel circuit, if one component fails, the other components can continue to function independently. This provides redundancy and ensures that the failure of one component does not affect the others.
3. Increased current capacity: Parallel arrangement allows the circuit to handle higher currents, which can be useful in situations where high power or heavy loads are required.
Disadvantages of Components Arranged in Parallel:
1. Increased complexity: Parallel circuits require more wiring and connections, which can make the circuit more complex and harder to manage.
2. Higher cost: Parallel circuits may require more components and wiring, resulting in higher costs for materials and installation.
It's important to consider the specific requirements and constraints of the application when deciding whether to arrange components in series or parallel. Each configuration has its advantages and disadvantages, and the choice depends on factors such as desired current flow, voltage distribution, and reliability.I
Sam drives 20 miles North, 10 miles East, 20 miles South and 10 miles West.
Distance:
Displacement:
Answers
Sam traveled a total distance of 60 miles, but his displacement is zero, as he ended up back at his starting point after all of his movements.
How to measure the distance?
The distance that Sam has traveled is the total length of the path he took, regardless of the direction. In this case, the distance can be calculated as follows:
Distance = 20 miles (North) + 10 miles (East) + 20 miles (South) + 10 miles (West)
Distance = 60 miles
Therefore, Sam has traveled a total of 60 miles.
The displacement, on the other hand, is the shortest distance between the starting point and the ending point. It is the distance between the initial and final position of an object, measured in a straight line. To calculate the displacement, we need to find the net vector sum of all the individual movements.
Starting from the origin, Sam moved 20 miles to the north and then 20 miles to the south, which means he ended up back at the starting point. Next, he moved 10 miles to the east and then 10 miles to the west, which also means he ended up back at the starting point.
Therefore, the displacement of Sam's journey is zero.
In summary, Sam traveled a total distance of 60 miles, but his displacement is zero, as he ended up back at his starting point after all of his movements.
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1. At t=0s, a particle moving in the x-y plane with constant acceleration has a velocity ofv; = (3î-2)) m/s, and is at the origin. At t=3s, the particle's velocity is f = (91+7j) m/s. Find (a)the acceleration of the particle (b) Its coordinates at t=3s
Answers
Answer:
the particle is at coordinates (18,15/2)
Explanation:
To find the acceleration of the particle, we can use the formula for velocity: v = v0 + at, where v0 is the initial velocity, a is the acceleration, and t is the time. Since we know the initial and final velocities, as well as the time interval, we can solve for the acceleration:
a = (v - v0)/t = [(9i + 7j) - (3i - 2j)]/3 = (6i + 9j)/3 = 2i + 3j
So the acceleration of the particle is a = 2i + 3j m/s².
To find the coordinates of the particle at t=3s, we can use the formula for position: r = r0 + v0t + 1/2at², where r0 is the initial position. Since the particle starts at the origin, r0 = 0. Plugging in the values we have:
r = 0 + (3i - 2j)(3) + 1/2(2i + 3j)(3)² = 9i - 6j + 9i + 27/2 j = 18i + 15/2 j
We can use the kinematic equations of motion to solve this problem.
Let the acceleration of the particle be a = axî + ayj.
(a) Using the equation of motion v = u + at, where u is the initial velocity:
f = v = u + at
Substituting the given values, we get:
(91+7j) = (3î-2j) + a(3î + 3j)
Equating the real and imaginary parts, we get:
91 = 3a + 3a (coefficients of î are equated)
7 = -2a + 3a (coefficients of j are equated)
Solving these equations simultaneously, we get:
a = î(23/6) + j(1/2)
So the acceleration of the particle is a = (23/6)î + (1/2)j.
(b) Using the equation of motion s = ut + (1/2)at^2, where s is the displacement and u is the initial velocity:
At t = 3s, the displacement of the particle is:
s = ut + (1/2)at^2
Substituting the given values, we get:
s = (3î-2j)(3) + (1/2)(23/6)î(3)^2 + (1/2)(1/2)j(3)^2
Simplifying, we get:
s = 9î + (17/2)j
So the coordinates of the particle at t=3s are (9, 17/2).
a converging lens forms a real image four times the size of the objects and 60 cm from the optical centre of the lens.
i) find the focal length of the lens ii)what is the distance between the object and its image when they have the same size?
Answers
i) The focal length of the lens can be determined using the lens formula:
1/f = 1/v - 1/u
Where:
f = focal length of the lens
v = image distance from the optical center of the lens (positive for real image)
u = object distance from the optical center of the lens (positive for object on the same side as the incident light)
Given:
Image distance (v) = 60 cm
Object distance (u) = ?
Magnification (m) = -4 (negative because the image is real and inverted)
The magnification is given by the formula:
m = -v/u
Substituting the given values, we have:
-4 = -60/u
Simplifying the equation, we find:
u = 15 cm
Now we can substitute the values of u and v into the lens formula:
1/f = 1/60 - 1/15
Simplifying the equation, we get:
1/f = (1 - 4)/60
1/f = -3/60
1/f = -1/20
Taking the reciprocal of both sides, we find:
f = -20 cm
ii) The distance between the object and its image when they have the same size can be found using the magnification formula:
m = -v/u
Given:
Magnification (m) = 1 (since the object and image are of the same size)
Image distance (v) = ?
Object distance (u) = ?
Substituting the values into the magnification formula, we have:
1 = -v/u
Since the magnification is positive, the image is virtual and upright. Therefore, the image distance (v) is negative.
We know from part (i) that the object distance (u) is 15 cm. Substituting these values into the equation, we find:
1 = -v/15
Rearranging the equation, we have:
v = -15 cm
Therefore, the distance between the object and its image when they have the same size is 15 cm.
To know more about the i) The focal length of the lens can be determined using the lens formula:
1/f = 1/v - 1/u
Where:
f = focal length of the lens
v = image distance from the optical center of the lens (positive for real image)
u = object distance from the optical center of the lens (positive for object on the same side as the incident light)
Given:
Image distance (v) = 60 cm
Object distance (u) = ?
Magnification (m) = -4 (negative because the image is real and inverted)
The magnification is given by the formula:
m = -v/u
Substituting the given values, we have:
-4 = -60/u
Simplifying the equation, we find:
u = 15 cm
Now we can substitute the values of u and v into the lens formula:
1/f = 1/60 - 1/15
Simplifying the equation, we get:
1/f = (1 - 4)/60
1/f = -3/60
1/f = -1/20
Taking the reciprocal of both sides, we find:
f = -20 cm
ii) The distance between the object and its image when they have the same size can be found using the magnification formula:
m = -v/u
Given:
Magnification (m) = 1 (since the object and image are of the same size)
Image distance (v) = ?
Object distance (u) = ?
Substituting the values into the magnification formula, we have:
1 = -v/u
Since the magnification is positive, the image is virtual and upright. Therefore, the image distance (v) is negative.
We know from part (i) that the object distance (u) is 15 cm. Substituting these values into the equation, we find:
1 = -v/15
Rearranging the equation, we have:
v = -15 cm
Therefore, the distance between the object and its image when they have the same size is 15 cm.
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A windmill captures 700W of wind power for 17h. The kinetic energy is converted to electric energy and stored in a battery, before being used by a 20W light bulb. During the process 68% of the energy is lost.
wind energy captured: ___W h
loss: ___W h
energy delivered to light bulb: ___W h
How long could the light bulb be used? ____hours
Answers
Answer:
this might help
Explanation:
Wind power or wind energy is the use of wind to provide mechanical power through wind turbines to turn electric generators for electrical power. Wind power is a popular sustainable, renewable source of power that has a much smaller impact on the environment compared to burning fossil fuels. Wind farms consist of many individual wind turbines, which are connected to the electric power transmission network. Onshore wind is an inexpensive source of electric power, competitive with or in many places cheaper than coal or gas plants. Onshore wind farms have a greater visual impact on the landscape than other power stations, as they need to be spread over more land and need to be built away from dense population. Offshore wind is steadier and stronger than on land and offshore farms have less visual impact, but construction and maintenance costs are significantly higher. Small onshore wind farms can feed some energy into the grid or provide power to isolated off-grid locations. The wind is an intermittent energy source, which cannot be dispatched on demand. Locally, it gives variable power, which is consistent from year to year but varies greatly over shorter time scales. Therefore, it must be used together with other power sources to give a reliable supply. Power-management techniques such as having dispatchable power sources (often gas-fired power plant or hydroelectric power), excess capacity, geographically distributed turbines, exporting and importing power to neighboring areas, grid storage, reducing demand when wind production is low, and curtailing occasional excess wind power, are used to overcome these problems. As the proportion of wind power in a region increases the grid may need to be upgraded. Weather forecasting permits the electric-power network to be readied for the predictable variations in production that occur. In 2019, wind supplied 1430 TWh of electricity, which was 5.3% of worldwide electrical generation, with the global installed wind power capacity reaching more than 651 G…
Explain using physics vocabulary WHY the volume increases as the temperature increases.
Answers
Answer:
P V = n R T ideal gas equation
V = k T where k = a constant and equals k = n R / P
V is proportional to T when other factors are constant
ONLY answer if you know FOR SURE. if your not 100% on it, DONT FREAKING ANSWER. ONLY IF YOU KNOW FOR SURE!
Which type of graph is best to use with data that shows a comparison of categories?
A. Pie Chart (Circle Graph)
B. Line Graph
C. Bar Graph
D. Frequency Table
Answers
Answer: the answer is (C)
Explanation: Bar graphs show comparisons using number comparisons
How has Physics improved
or affected our society?
Answers
By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life
From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.
The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.
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A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and frictional force between the box and surface is 100 n, calculate the distance covered.
Answers
If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.
To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.
Given:
Mass of the box, m = 210 kg
Tension in the string, T = 1300 N
The angle of inclination, θ = 35°
Frictional force, f = 100 N
Initial speed, u = 0 m/s
Final speed, v = 10 m/s
First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:
T_parallel = T * cos(θ)
Next, let's calculate the net force acting on the box along the incline. The net force is given by:
Net force = T_parallel - f
Now, using Newton's second law, we can calculate the acceleration (a) of the box:
Net force = m * a
From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):
v^2 = u^2 + 2as
Rearranging the equation, we get:
s = (v^2 - u^2) / (2a)
Now, let's plug in the given values and calculate the distance covered:
T_parallel = 1300 N * cos(35°) ≈ 1067.35 N
Net force = 1067.35 N - 100 N = 967.35 N
a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2
s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m
Therefore, the distance covered by the box is approximately 10.89 meters.
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I WILL MARK YOU AS BRAINLIEST IF RIGHT
What is the average velocity of a car that traveled a total of 24 kilometers north in 0.6 hours?
Answers
Answer:
Explanation:
1 km =1000 m
24 km=24/1000
24 km=0.024 m
1 hour= 3600 s
0.6 hours=2160 s
now average velocity=distance/time
v=0.024 m/2160 s
v=1.11*10^-5
another way
v=24 km/0.6 hour
v=40 km/ hour
A 21 kg child is jumping on a trampoline. At her maximum height the child is 2.5 x 10^3 J of gravitational potential energy
Answers
The maximum height of the child is 12.14 m.
What is gravity?We define gravity as: a body is drawn toward the center of the earth or any other physical body with mass by the force known as gravity.
Given parameters:
Mass of the child; m = 21 kg.
Gravitational potential energy at maximum height; E = 2.5 x 10³ J
Let her maximum height is h. Then Gravitational potential energy at maximum height; E = mgh = 21 × 9.8 × h joule.
So, 21 × 9.8 × h = 2.5 x 10³
⇒ h = 12.14 m.
The maximum height of the child is 12.14 m.
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The theoretical efficiency of an Otto cycle is 63%. The ratio of the Cp and Cv heat capacities for the gas in the engine is (a) What is the compression ratio r? (b) If the net work done per cycle is 12.6 kJ, how much heat is rejected and how much is absorbed by the engine during each cycle?
Answers
A spark is used to ignite the fuel-air mixture with in ideal Otto cycle after it is introduced during induction stroke, compressed to a considerably lower compression ratio, and introduced into the engine.
Tell me about the Otto cycle.In order for an engine to operate in the Otto cycle, the piston must make four strokes: one for induction, one for compression, one for ignition, and one for exhaust. In order for combustion to begin with only an electric arc or another method, the air-fuel mixture must first be compressed. bearing the name of German engineer Nikolaus Ott.
Otto cycles come in 2 and 4 stroke varieties.Four engine strokes are required for the Otto Cycle. The term "stroke" refers to a procedure in which the piston of the cylinder goes up or down within the engine.
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please help answering A,B,C in screenshots thank you!
Answers
The slope of the graph is 0.5 m/s² and when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.
To plot the velocity vs. time graph, we'll use the given data points:
Duration, At (s): 2.0, 4.0, 6.0, 8.0, 10.0, 12.0
Velocity, v (m/s): 6.0, 7.0, 8.0, 9.0, 10.0, 11.0
Let's plot these points on a graph:
Time (s) [x-axis] | Velocity (m/s) [y-axis]
--------------------------------------------
2.0 | 6.0
4.0 | 7.0
6.0 | 8.0
8.0 | 9.0
10.0 | 10.0
12.0 | 11.0
After plotting the points, we can connect them with a straight line to represent the motion of the object. This line represents the velocity vs. time relationship.
Now, let's calculate the slope of this line. The slope of a line represents the rate of change of the dependent variable (velocity) with respect to the independent variable (time). In this case, it gives us the acceleration of the object.
Using the formula for calculating the slope of a line:
Slope (k) = (Change in velocity) / (Change in time)
For the first two points:
Change in velocity = 7.0 - 6.0 = 1.0 m/s
Change in time = 4.0 - 2.0 = 2.0 s
Slope (k) = 1.0 m/s / 2.0 s = 0.5 m/s²
Therefore, the slope of the graph is 0.5 m/s².
Now, to answer part B, the physical significance of the slope value is that it represents the object's acceleration. In this case, the constant acceleration experienced by the object is 0.5 m/s².
Moving on to part C, we are given the equation d = kt, where d represents the displacement and t represents time. Since the object is experiencing constant acceleration, the equation can be rewritten as d = 0.5t, where 0.5 is the acceleration (k).
To predict the value of "d" when t = 1.5 s, we can substitute the value of t into the equation:
d = 0.5 * 1.5 = 0.75 meters
Therefore, when t = 1.5 s, the predicted displacement (d) of the object is 0.75 meters.
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The probable question may be:
An object is subjected to a constant acceleration along a frictionless track. A student measures its velocity (v) after specific durations (At). The student uses a graph to analyze the truck's motion.
Duration, At, (s) :- 2.0,4.0,6.0,8.0,10.0,12.0.
Velocity, v, (m/s) :- 6.0,7.0,8.0,9.0,10.0,11.0
A. Plot the velocity (in meters/sec) vs. time (seconds). The velocity is the y-axis and time is the x-axis. Use any graphing software you like or graph this data in pencil on graph paper. Excel has a nice graphing package. Calculate the slope of this graph. You will
B. What is the physical significance of the slope value computed in part A?
C. Having determined the slope of the line, you can now write d = kt. Use this equation to predict a value of "d" when t = 1.5 s.
Which subatomic particles contribute to the mass of an atom
Answers
Answer:
Only protons and neutrons contribute to the mass of an atom.
Explanation:
A race car accelerates from 0 m/s to 30.0 m/s with a displacement of
45.0 m. What is the vehicle's acceleration?
1. O 2.00 m/s2
2. 5.00 m/s2
3. 15.0 m/s2
4. 10.0 m/s2
Answers
Answer:
4. 10.0 m/s²
Explanation:
I) if initial velocity is 'v₀', the final velocity is 'v', the accelaration is 'a', the distance is 'L' and elapsed time if 't', then:
\(1. \ a=\frac{v-v_0}{t};\)
\(2. \ L=\frac{at^2}{2}.\)
II) using these two equations after substitution v₀=0; v=30 and L=45:
\(\left \{{{45 =\frac{at^2}{2}} \atop {a=\frac{30-0}{t} }} \right.\)
\(\left \{ {{at^2=90} \atop {at=30}} \right. \ <=> \ \left \{ {{a=10} \atop {t=3}} \right.\) \(=> \ a=10\frac{m}{s^2}\)