Ratio,rates,and proportional test

Answer:

Answer would be 12

Step-by-step explanation:

i'm not always accurate but your welcome!

The type of energy the box have after it is done being pulled is "kinetic energy".

Kinetic energy is the type of energy which an item or particle has as a result of its motion. When work, that transfers energy, is performed on an item by exerting a net force, that object accelerates and obtains kinetic energy.

Now, according to the question;

The box's mass, m = 10 kg

F = 50 N, the force that occurs when the box is pulled

It has been moved 4 meters.

Friction force operating upon that box, f = 20 N

We must determine the box's initial kinetic energy. The box appears to be at rest at first. Because there is no movement in the box at the time.

The formula for box's kinetic energy is as follows:

K.E = (1/2)mv²

As velocity is given zero; v = 0.

Thus, K.E = 0.

The initial velocity of the box is zero.

Therefore, as the box starts moving its zero kinetic energy will start increasing.

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Answer:

3.671%

Step-by-step explanation:

\(\frac{1786}{48650}\) x 100 =3.671

An equation of the plane tangent to the following surface at the given points (5,6, ln(31)) and (-5, -6, ln(31)) is (6/31)(x-5) + (5/31)(y-6) + (z-ln(31)) = 0 and (-6/31)(x+5) + (-5/31)(y+6) + (z-ln(31)) = 0 respectively.

The equation of the plane tangent to the surface z = ln(1+xy) at the given points (5,6, ln(31)) and (-5, -6, ln(31)) can be found using the gradient vector and the point-normal form of a plane equation.

To find the equation of the plane tangent to the surface at the given points, we need to find the normal vector to the surface at those points. The normal vector can be obtained by taking the gradient of the surface function.

The gradient of the surface function z = ln(1+xy) is given by:

∇z = (∂z/∂x, ∂z/∂y) = (y/(1+xy), x/(1+xy))

At the points (5,6, ln(31)) and (-5, -6, ln(31)), we can substitute the respective x and y values into the gradient expression to obtain the normal vectors.

For the point (5,6, ln(31)):

∇z = (6/(1+56), 5/(1+56)) = (6/31, 5/31)

Similarly, for the point (-5, -6, ln(31)):

∇z = (-6/(1-56), -5/(1-56)) = (-6/31, -5/31)

Now, we have the normal vectors to the surface at the given points. We can use the point-normal form of the plane equation to find the equation of the tangent plane.

Using the point-normal form: A(x-x0) + B(y-y0) + C(z-z0) = 0, where (x0, y0, z0) is a point on the plane and (A, B, C) is the normal vector, we can substitute the values from the points and normal vectors:

For the point (5,6, ln(31)):

(6/31)(x-5) + (5/31)(y-6) + (z-ln(31)) = 0

For the point (-5, -6, ln(31)):

(-6/31)(x+5) + (-5/31)(y+6) + (z-ln(31)) = 0

These equations represent the planes tangent to the surface z = ln(1+xy) at the given points.

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Answer:

No offence

Step-by-step explanation:

but have you tried looking it up?

We have two right-angled triangles that share a common side, with side lengths 6 and 10. Let's label the sides of the triangles as follows:

Triangle 1:

Side adjacent to the right angle: 6 (let's call it 'a')

Side opposite to the right angle: x (let's call it 'b')

Triangle 2:

Side adjacent to the right angle: x (let's call it 'c')

Side opposite to the right angle: 10 (let's call it 'd')

Using the Pythagorean theorem, we can write the following equations for each triangle:

Triangle 1:\(a^2 + b^2 = 6^2\)

Triangle 2: \(c^2 + d^2 = 10^2\)

Since the triangles share a common side, we know that b = c. Therefore, we can rewrite the equations as:

\(a^2 + b^2 = 6^2\\b^2 + d^2 = 10^2\)

Substituting b = c, we get:

\(a^2 + c^2 = 6^2\\c^2 + d^2 = 10^2\)

Now, let's add these two equations together:

\(a^2 + c^2 + c^2 + d^2 = 6^2 + 10^2\\a^2 + 2c^2 + d^2 = 36 + 100\\a^2 + 2c^2 + d^2 = 136\)

Since a^2 + 2c^2 + d^2 is equal to 136, we can conclude that x (b or c) is between 11 and 12

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Answer:96

Step-by-step explanation:

uwu yay

The required equation represents the inverse function b(a), which takes the trapezoid's area is B(a) = a/6 - 9.

A trapezoid is a quadrilateral having two parallel bases and one set of other sides called as legs.

We have been given that the trapezoid's base is nine and its height is twelve.

As an outcome, 'b' is the base's parallel side.

The function that represents the trapezoid's area is given by:

A(b) = [12(b + 9)]/2

Let's consider A(b) = a

Then, a =  [12(b + 9)]/2

Now solving for b, we get

2a = 12(b + 9)

a = 6(b + 9)/2

a = 6b + 54

6b = a - 54

b = (a - 54)/6

b = a/6 - 9

Assuming that the length of the side parallel to the base 'b' = B(a), the equation will be:

B(a) = a/6 - 9

Thus, the correct answer would be option A. B(a) = a/6 - 9.

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The value of the coefficient B in the decomposition x-k/x² + 4x = A/x + B/(x+4) is 92.

For the rational function x-k/x² + 4x, the partial fraction decomposition is given by x-k/x² + 4x = A/x + B/(x+4), where A and B are coefficients to be determined. If k = 92, we need to find the value of the coefficient B in this decomposition.

To find the value of the coefficient B, we can use the method of partial fractions. Given the decomposition x-k/x² + 4x = A/x + B/(x+4), we can multiply both sides of the equation by the common denominator (x)(x+4) to eliminate the fractions.

This gives us the equation (x)(x+4)(x-k) = A(x+4) + B(x). Next, we substitute the value of k = 92 into the equation.

(x)(x+4)(x-92) = A(x+4) + B(x).

We can then expand and simplify the equation to solve for the coefficient B. Once we have the simplified equation, we can compare the coefficients of the terms involving x to determine the value of B.

By solving the equation, we find that the coefficient B is equal to 92.

Therefore, when k = 92, the value of the coefficient B in the decomposition x-k/x² + 4x = A/x + B/(x+4) is 92.

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We cannot determine the exact amount of money left in his account without knowing the value of x, but we can express it as Rupees (-x + 35).

Given that,Rohan had Rupees (6x + 25) in his account.If he withdrew Rupees (7x - 10), we have to find how much money is left in his account.Using the given information, we can form an equation. The equation is given by;

Money left in Rohan's account = Rupees (6x + 25) - Rupees (7x - 10)

We can simplify this expression by using the distributive property of multiplication over subtraction. That is;

Money left in Rohan's account = Rupees 6x + Rupees 25 - Rupees 7x + Rupees 10

The next step is to combine the like terms.Money left in Rohan's account = Rupees (6x - 7x) + Rupees (25 + 10)

Money left in Rohan's account = Rupees (-x) + Rupees (35)

Therefore, the money left in Rohan's account is given by Rupees (-x + 35). To answer the question, we can say that the amount of money left in Rohan's account depends on the value of x, and it is given by the expression Rupees (-x + 35). Hence, we cannot determine the exact amount of money left in his account without knowing the value of x, but we can express it as Rupees (-x + 35).

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Answer:

1 solution

Step-by-step explanation:

If you solve for the system of equations you get (0,1) or x=0; y=1. This leads us to select B: One Solution as our answer choice.

If you can please give my answer the brainliest that would be much appreciated. Thanks!

The given expression is now written in the form of ax+b/cx-d where a, b, c, and d are integers, which is as follows:(27x³ - 12x) / (6x² - 28x) = -3x(9x² - 4) / 4(x - 7)

To write the expression in the form of \(ax+b/cx-d,\) we have to perform the given operation to obtain the same denominator.

Explanation: Given expression is: 9x²-4/6x-4 x 3x/x²-5x

First, let's factor the given denominators.6x-4 = 2(3x-2)x²-5x = x(x-5)

Now let's simplify the expression using the above factors.

9x² - 4/6x - 4 x 3x/x² - 5x

= (9x² - 4)/2(3x - 2) * 3x/x(x - 5)

Next, we will perform multiplication of the numerators and denominators of each expression.

9x² - 4/6x - 4 x 3x/x² - 5x

= [(9x² - 4) * 3x] / [2(3x - 2) * x(x - 5)]

Now, let's simplify the given expression by expanding the numerator.

9x² - 4/6x - 4 x 3x/x² - 5x = [(27x³ - 12x) / (6x² - 28x)]

Finally, let's factor out the common factor from both numerator and denominator of the expression.

9x² - 4/6x - 4 x 3x/x² - 5x = [3x(9x² - 4) / 2(3x - 2) * -2(x - 5)]

Thus, the given expression is now written in the form of ax+b/cx-d where a, b, c, and d are integers, which is as follows:(27x³ - 12x) / (6x² - 28x)

= -3x(9x² - 4) / 4(x - 7)

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(a) The signal x[n] = e^(2πn/5) is periodic with a period of 5.

(b) The signal x[n] = sin(19πn) is periodic with a period of 2.

Signal (x[n]) is periodic if there exists a positive integer N such that x[n + N] = x[n] for all n.

In other words, if the signal repeats itself after a certain number of samples, it is periodic. (a) x[n] = e^(2πn/5)

To determine if this signal is periodic, we need to find a positive integer N such that x[n + N] = x[n] for all n.

Let's substitute n + N into the equation: x[n + N] = e^(2π(n + N)/5) To check if this is equal to x[n], we need to simplify it using properties of exponential functions: e^(2π(n + N)/5) = e^(2πn/5) * e^(2πN/5)

Therefore, the period of signal (b) is 2, because x[n] = x[n + 2] for all n.

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The rancher has 5,280 acres left after selling off 5 quarter sections.

There are different ways to approach this problem, but one possible method is to convert all the sections and subsections to acres and then subtract the number of acres sold.

One section is equal to 640 acres (1 mile x 1 mile)

One-half section is equal to 320 acres (1/2 mile x 1 mile)

The one-quarter section is equal to 160 acres (1/2 mile x 1/2 mile)

The rancher owns:

8 full sections x 640 acres/section = 5,120 acres

3 half sections x 320 acres/half section = 960 acres

Total = 6,080 acres

The rancher sells off:

5 quarter sections x 160 acres/quarter section = 800 acres

The number of acres left is:

6,080 acres - 800 acres = 5,280 acres

Therefore, the rancher has 5,280 acres left after selling off 5 quarter sections.

Answer: There are 5,280 acres left.

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Answer:

98

Step-by-step explanation:

Given Information :-

⠀

⠀

To Find :-

⠀

⠀

Solution :-

⠀

We know that, the formula used to calculate distance , when we are provided with time and speed, is :-

⠀

\( ✤ \: \orange{ \underline{ \boxed{ \sf Distance = Speed \times Time}}} \: \star \\ \\ \)

Thus, putting the given values, we will get,

⠀

\( \sf \hookrightarrow Distance = \dfrac{6 \: m}{s} \times 5 \: s \\ \\ \\ \sf \hookrightarrow Distance = \frac{6 \: m}{ \cancel s} \times 5 \: \cancel s \\ \\ \\ \sf \hookrightarrow Distance =6 \: m \times 5 \: \: \: \: \\ \\ \\ \sf \hookrightarrow Distance =30 \: m \: \: \: \: \: \: \: \: \: \: \\ \\ \)

Thus, the distance covered in 5 second by that speed is 30 m.

⠀

\( \underline{\rule{227pt}{1.5pt}} \\ \\ \)

Answer:(x, y) → (x + 8, y – 3)

The answer is C took the test

Answer:

c

Step-by-step explanation:

Step-by-step explanation:

to add 8% the simplest operation is to multiply the basic amount by 1.08.

so,

£9.45 = original price × 1.08

original price = £9.45/1.08 = £8.75

the price before the increase was £8.75.

The least common factor will be equal to x(x - 14 ). The correct option is B.

The least common multiple (LCM) of two or more integers is the smallest positive integer which is a multiple of each of the integers. It is often abbreviated as LCM.

The least common factor is calculated as,

7/x = 5/x-14 +1

[5 / ( x - 14) ] - [ 7 / x] + 1 = 0

[ (5x) -7(x-14) + x (x - 14 )] / [ x(x - 14) ] =0

The lowest common denominator will be  [ x(x - 14) ].

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The value of the angle subtended by sector XY is determined as 137⁰.

The value of the angle subtended by the arc is calculated by applying the formula for length of an arc as shown below;

The formula for the length of an arc is given as;

L = 2πr (θ/360)

where;

The length of the arc is given as 18 in, and the radius of the arc is given as 7.54 in.

L = 2πr (θ/360)

θ/360 = L/2πr

θ = 360 x ( L /2πr)

θ = 360 x ( 18 ) / (2π x 7.54)

θ = ( 360 x 18 ) / (2π x 7.54)

θ = 136.8⁰ ≈ 137⁰

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The complete question is below:

Find the angle subtended by the sector XY.

Answer:

the answer is 180 students.

Step-by-step explanation:

I got this by subtracting 15 by 100 and got 75. This means 75% chose purple. Then you take 75% of 240 and that's your answer

Answer:

204

Step-by-step explanation:

ok

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\(2y+3x=1\implies 2y=-3x+1\implies y=\cfrac{-3x+1}{2} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{3}{2}}x+\cfrac{1}{2}\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill\)

\(\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{ \cfrac{-3}{2}} ~\hfill \stackrel{reciprocal}{\cfrac{2}{-3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{2}{-3} \implies \cfrac{2}{ 3 }}}\)

so we're really looking for an equation whose slope is 2/3

\({\Large \begin{array}{llll} y=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+\cfrac{5}{2} \end{array}} \qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\)

At an angle of 270 degrees (or 3π/2 radians) on a circle with a radius of 2 and center at (0, 0), the x-coordinate is 0 and the y-coordinate is -2.

To find the x and y coordinates at an angle of 270 degrees (or 3π/2 in radian measure) on a circle of radius 2 with center (0, 0), we can use the trigonometric definitions of sine and cosine.

The x-coordinate (x-value) represents the horizontal position on the circle, while the y-coordinate (y-value) represents the vertical position.

For a point on the unit circle (circle with radius 1) at a given angle θ, the x-coordinate is given by cos(θ) and the y-coordinate is given by sin(θ).

In this case, the circle has a radius of 2, so we need to multiply the cosine and sine values by 2 to get the x and y coordinates, respectively.

Using the angle 270 degrees (or 3π/2 in radian measure):

x-coordinate = 2 * cos(3π/2)

y-coordinate = 2 * sin(3π/2)

Evaluating these expressions:

x-coordinate = 2 * cos(3π/2) = 2 * 0 = 0

y-coordinate = 2 * sin(3π/2) = 2 * (-1) = -2

Therefore, at an angle of 270 degrees (or 3π/2 radians) on the circle of radius 2 with center (0, 0), the x-coordinate is 0 and the y-coordinate is -2.

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Answer:

4

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

Write 5% as

5/100

Since, finding the fraction of a number is same as multiplying the fraction with the number, we have

5/100 of 80 = 5/100× 80

Therefore, the answer is 4

If you are using a calculator, simply enter 5÷100×80 which will give you 4 as the answer.

The maximum axle weight for a tandem axle than for a single axle by d) 16,000 lb.

Tandem axles are designed to carry heavier loads than single axles. The maximum axle weight for a tandem axle can be up to 10,000 pounds greater than a single axle.

This means that a tandem axle can carry up to 16,000 pounds, while a single axle can only carry up to 6,000 pounds.

The amount of weight a tandem axle can carry depends on the type of vehicle and the weight of the load it is carrying. If you're looking for extra support, a tandem axle is your best choice.

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geologists unearth a sample of zircon that appears to be a closed system. they find 0.686 micro gram of 206 Pb for 1.000 micro gram of 238U present. approximately  3.7973 × 10⁹ years old is the sample.

The reciprocal of the time period during which the number of atoms in the radioactive element drops to almost A. 50% of its initial number is the decay constant.

According to the radioactive decay law, a nucleus's likelihood of decaying is a constant that is independent of time.

t1/2 of U₂₃₈ is 4.5 × 10⁹ years

moles of U₂₃₈ : (1 × 10⁻⁶ / 238) moles

moles of Pb₂₀₆ : (0.686 × 10⁻⁶ / 206) moles

Now, U₂₃₈ → Pb₂₀₆

As Pb₂₀₆ comes from U₂₃₈ hence,

moles of  U₂₃₈ decayed = moles of  Pb₂₀₆

                                        = (0.686 × 10⁻⁶ / 206) moles

Therefore, initial moles of U₂₃₈:

N₀ = [(1 × 10⁻⁶ / 238) + (0.686 × 10⁻⁶ / 206)] moles

and N = (1 × 10⁻⁶ / 238) moles

Now, λ (decay constant) = 0.693 / (t1/2)

                                        = 0.693 / ( 4.5 × 10⁹ years)

So,

t = 2.303 / λ × log (N₀ / N)

t = 2.303 / [0.693 / ( 4.5 × 10⁹ years)] × log [1 + (0.686/206)/(1/238)]

t = 14.95 × 10⁹ × 0.254

t = 3.7973 × 10⁹ years.

Thus, the sample is: 3.7973 × 10⁹ years old.

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The probability that the mean daily revenue for the next 30 days will exceed $7000 is 47.60%.

The formula for the z score is-

z = (x - μ)/σ

In which,

Put the value in formula

z = (7000 - 7200)/1200

z = - 0.16

Thus,

P(x > $7000) = P(z >  - 0.16)

See the p- value for obtained z from negative z score table.

P(x > $7000) = 0.4760

Thus, the probability that the mean daily revenue for the next 30 days will exceed $7000 is 47.60%.

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Answer:

just know total angle sum is 180°

Step-by-step explanation:

\(52 + (15x + 3) + (3x - 1) = 180 \\ 52 + 3 - 1 + 15x + 3x = 180 \\ 54 + 18x = 180 \\ 18x = 180 - 54 \\ 18x = 126 \\ x = 7\)

but give me a brainliest

Answer:

x = 7

Step-by-step explanation:

→ Find the sum of the angles

52 + 15x + 3 + 3x - 1 = 18x + 54

→ Wquate the expression to 180

18x + 54 = 180

→ Solve for x

x = 7

Answer:

the other 3 sides are 125,55 and 55 - hope this helped :)

Step-by-step explanation:

side 1 = 125

side 2 = 125

side 3 and 4 = ?

360 - 250 = 110

110/2 = 55

side 3 and 4 = 55

The better buy is given by the following brand:

Brand A.

The better buy is obtained applying the proportions in the context of the problem.

A proportion is applied as the cost per ounce is given dividing the total cost by the number of ounces.

Then the better buy is given by the option with the lowest cost per ounce.

The cost per ounce for each brand is given as follows:

$8 per ounce is a lesser cost than $9.3 per ounce, hence the better buy is given by Brand A.

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