rank the following polyatomic ions from fewest to most oxygen atoms: 1. chlorate 2. chlorite 3. perchlorate

The standard enthalpy change of the explosive reaction is -11408 kJ/mol.

The standard enthalpy change of the reaction can be calculated using the enthalpy of formation values of the reactants and products.

The enthalpy of the formation of ammonium nitrate (NH4NO3) is -393.5 kJ/mol, the enthalpy of the formation of the fuel oil (C10H22) is -249.7 kJ/mol, the enthalpy of the formation of oxygen (O2) is 0 kJ/mol.

The enthalpy of the formation of nitrogen (N2) is 0 kJ/mol, the enthalpy of the formation of water (H2O) is -285.8 kJ/mol, and the enthalpy of the formation of carbon dioxide (CO2) is -393.5 kJ/mol.

The equation for the explosive reaction is 3NH4NO3(s)+C10H22(l)+14O2(g)>3N2(g)+17H2O(g)+10CO2(g). Therefore, the standard enthalpy change of the reaction can be calculated using the following equation:

ΔH = [3(-393.5) + (-249.7) + (14*0) + (3*0) + (17*-285.8) + (10*-393.5)] - [3(-393.5) + (-249.7) + (14*0)]

ΔH = -11408 kJ/mol.

Therefore, the standard enthalpy change of the explosive reaction is -11408 kJ/mol.

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The complete question is attached below.

A significant amount of heat energy is produced when the sulfuric acid combines with the water. Because acid is heavier than water, it should be added to the concentrated sulphuric acid during diluting because acid spurts because the heat from the developed acid is lost in the water.

H2SO4 is diluted by adding acid to water rather than water to acid because the exothermic reaction that occurs when water is added could cause the acid to splash out of the container.

The exothermic reaction that occurs when water is introduced to a concentrated acid might result in burns because of the heat that is produced. On the other hand, because less heat is produced when acid is gently added to water while swirling continuously, the combination won't splash out.

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The correct order of bond polarity is;

H- S < H - O < H- Cl < H -F

Bond polarity refers to the distribution of electrons in a covalent bond between two atoms. In a covalent bond, atoms share one or more pairs of electrons in order to achieve a stable electron configuration.

In some cases, the shared electrons are not equally shared between the two atoms, leading to a bond in which one atom has a greater share of the electrons than the other. This results in a partial negative charge on one end of the bond and a partial positive charge on the other end, creating a separation of charge known as a dipole. The bond is then said to be polar.

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The pH values of the solution after the addition of various amounts of acids are as follows:

(a) When 0.0 mL HCl is added; pH = 11.62

(b) After adding 10.0 mL of 0.100 M HCl; pH = 12.38

(c) After adding 30.0 mL of 0.100 M HCl; pH = 14

(d) After adding 40.0 mL of 0.100 M HCl; pH = 2.70

The equation of the reaction between NH₃ and HCl is:

NH₃ + HCl → NH₄Cl

Before the addition of HCl:

The concentration of NH₃ solution = 0.300 M

The initial concentration of OH- can be calculated from the Kb of NH₃ :

Kb = [NH₄⁺][OH⁻] / [NH₃]

1.8 x 10⁻⁵ = x² / 0.300

x = 0.0024 M

The initial concentration of OH⁻ is 0.0024 M, and the initial pH of the solution ill be:

pH = 14 - pOH

pH = 14 - (-log[OH-])

pH = 11.62

(a) When 0.0 mL HCl is added;

pH = 11.62

(b) After adding 10.0 mL of 0.100 M HCl;

moles of HCl added = (0.100 mol/L) x (0.0100 L)

moles of HCl added = 0.00100 mol

The moles of NH₃ initially present = (0.300 mol/L) x (0.0100 L)

moles of NH₃ initially present = 0.00300 mol

the mole ratio of HCl and NH₃ = 1:1

The remaining moles of NH₃ = 0.00300 mol - 0.00100 mol

remaining moles of NH₃ = 0.00200 mol

The volume of the solution is now 10.0 mL + 10.0 mL = 20.0 mL or 0.0200 L.

The new concentration of NH₃ = 0.00200 mol / 0.0200 L

concentration of NH₃ = 0.100 M

The concentration of OH- can be calculated from the Kb of NH₃ using the new concentration of NH4+:

Kb = [NH4+][OH-] / [NH3]

1.8 x 10⁵ = x² / 0.100

x = 0.0042 M

The new concentration of OH- is 0.0042 M, and the new pH will be:

pH = 14 - (-log[OH-])

pH = 12.38

(c) After adding 30.0 mL of 0.100 M HCl;

the volume of the solution is 40.0 mL or 0.0400 L

The moles of HCl added = (0.100 mol/L) x (0.0300 L)

moles of HCl added = 0.00300 mol

moles NH3 reacted = 0.00300 mol - 0.00300 mol

moles NH3 reacted = 0.00000 mol

[NH₄⁺] remaining [OH⁻] = 0

The concentration of OH- is 0 M, so the pH = 14 - (-log[OH-])

pH = 14

(d) After adding 40.0 mL of 0.100 M HCl;

moles HCl = (0.100 mol/L) x (0.0400 L)

moles HCl = 0.00400 mol

The volume of solution = 0.050 L

All NH₃ has reacted and the remaining moles of HCl = (0.00400 mol - 0.00300 mol) / 0.0500 L

the remaining moles of HCl = 0.00200 M

The concentration of H₃O⁺ can be calculated from the concentration of HCl:

0.00200 M HCl produces 0.00200 M H₃O⁺

pH = -log[H₃O⁺]

pH = -log(0.00200)

pH = 2.70

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A substance that is only made up of carbon and hydrogen has a mass composition of 85.7% c and 14.3% h. The compound's empirical formula is CH₂.

An empirical formula is a chemical formula for a compound that only specifies the proportions of the components present rather than the exact number of atoms.

The empirical formula for molecules is the most straightforward iteration of the molecular formula. To find this, divide each subscript in the formula by its lowest common denominator.

Atomic mass number % is the easiest formula to use to calculate an element's percentage in relation to the number of atoms.

With a density of 85.7 and an atomic mass of 12, carbon has a mass number of 7.141.

Hydrogen has a mass of 14.3 and

an atomic mass of 1 = 14.3 / 1 = 14.3²

As a result, the compound's empirical formula is C₁H₂= CH₂.

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Answer:

Her speed is 6.8m/s.

Explanation:

K.E= 1/2mv²

or, 2543.2= 1/2×110×v²

or, 2543.2 = 55v²

or, 2543.2/55 = v²

or, 46.24 = v²

or, 6.8² = v²

v = 6.8 m/s

answer

6.8

explanation

k.e=1/2v^2

2543.2=55v^2

46.24=v^2

6.8^2=v^2

v=6.8

The molarity of sodium hydroxide involved in the neutralization reaction is 0.251 M.

The molarity of a solution can be calculated using the following expression;

CaVa = CbVb

Where;

According to this, 43.8mL of sodium hydroxide reacts with 15.7 mL of 0.700M phosphoric acid. The molarity of sodium hydroxide can be calculated as follows:

0.700 × 15.7 = 43.8 × Cb

10.99 = 43.8Cb

Cb = 10.99 ÷ 43.8

Cb = 0.251 M

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Answer:

The number of electrons, in turn, determines the chemical properties of the atom.

Protons contribute to the mass of an atom and provide the positive charge to the nucleus. The number of protons also determines the identity of the element.

Electrons have a negative charge. Since the atom is electrically neutral, the number of electrons must equal the number of protons.

The electrons arrange themselves in energy levels around the nucleus. The outermost or valence electrons of an atom are the ones that take part in chemical reactions. An element’s chemical properties depend on its valence electrons.

Explanation:

Answer:

6.336 mg

Explanation:

.4055 x (1/2)^6 = .006336 gm

Plasma is a state of matter that is found in the universe but uncommon on Earth.

Plasma is an ionized gas in which some or all of the atoms have been stripped of their electrons, resulting in a mixture of free electrons and positively charged ions.
Plasma is the most common state of matter in the universe, as stars are composed primarily of plasma. It is also found in other celestial bodies such as nebulas, the solar wind, and lightning.

On Earth, plasma is less common as it requires a lot of energy to create and maintain, and is typically only found in specific conditions such as in lightning bolts, some flames, and in some types of welding.

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Answer:

Mass and Volume

Explanation:

The formula for density is

\(\frac{Mass}{Volume}\)

Answer:

poor access to health care providers

Explanation:

without health care providers you cant get tested.

Answer:

I think it is

1. energy

2. respiration

Answer: 2.5x 10^ 5 m

The statement "You will have enough gas" is true.

The ideal gas law provides a relationship between pressure (P), volume (V), temperature (T), and the number of moles of gas (n). T

he relationship is given by PV = nRT, where R is the gas constant, which has a value of 8.31 L-kPa/mol-K.

To use this equation, the conditions under which the gas is being measured must be specified.The gas in question is given as having a volume of 25.0 L, a pressure of 101.5 kPa, and a temperature of 373 K.

At STP (Standard Temperature and Pressure), the temperature and pressure are 273 K and 101.3 kPa, respectively. To use this information, we need to calculate the number of moles of gas we have, and then compare that value to the number of moles needed for the reaction.

The equation PV = nRT can be rearranged to solve for n. Dividing both sides by RT, we get:n = PV/RTSubstituting the given values, we obtain:n = (101.5 kPa)(25.0 L) / (8.31 L-kPa/mol-K)(373 K)n = 7.55 mol

The volume of gas required for the reaction is 22.4 L at STP.

To convert this to the conditions we have, we must adjust for the pressure and temperature. The pressure ratio is:

101.5 kPa / 101.3 kPa = 1.00197

The volume ratio is:

273 K / 373 K = 0.73193

Multiplying the ratios gives the conversion factor:

1.00197 × 0.73193 = 0.7332

This means that 22.4 L of gas at STP would occupy 0.7332 × 22.4 L = 16.4 L at 101.5 kPa and 373 K.

The number of moles of gas required for the reaction is:

n = PV/RTn = (101.5 kPa)(16.4 L) / (8.31 L-kPa/mol-K)(373 K)n = 4.89 mol

The amount of gas we have is 7.55 mol, which is greater than the 4.89 mol needed for the reaction.

Hence, the statement "You will have an adequate amount of gas" is accurate.

The question should be:

A reaction requires 22.4 L of gas at STP. You have 25.0 L of gas at 101.5 kPa and 373 K. Which of the following statements is true? (Use the ideal gas law: PV = nRT where R = 8.31 L-kPa/mol-K.)

You will have enough gas

You will have excess gas

You do not have enough gas

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Answer:

Chemical Nomenclature?

Explanation:

Based on The Law of Conservation of Mass Lavoisier, the mass of oxygen required is 3,2 g

The two main postulates that was given by Antoine Lavoisier are, oxygen play an important role in combustion and the other is mass of the reactant and product is conserved. Therefore the mass of oxygen is 3.2 g.

According to Law of conservation of mass, mass can neither be created nor be destroyed. Mass can only be transformed from one form to another. The law of conservation of mass was given by Antoine Lavoisier.

Every reaction in nature follow the law given by Antoine Lavoisier that is mass is always conserved. Another postulated that was given by Antoine Lavoisier is the role of oxygen in combustion reaction. Combustion can not happen without presence of oxygen. According to Law of Conservation of Mass Lavoisier, the mass of oxygen required is 3.2 g.

Therefore the mass of oxygen is 3.2 g.

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Answer:

In many parts of the world, water taken directly from wells or public supplies is not safe to drink because it may carry waterborne parasites or other diseases. The water can be sterilized by boiling it, but fuel is needed to do so.

Explanation:

Answer:  Public water supplies are unsafe in some parts of the world because the water may carry bacteria.

Explanation:

Answer:

Liquids take the shape of their container, they are one of the three stages in between a solid and a gas. A liquids particles are not in a fixed position like a solids, nor do they move as freely as a gas.

The symbol [He] represents the electron configuration of a helium (He) atom. Helium has two electrons, and its electron configuration is 1s^2.

The [He] notation is used to indicate that the core electrons of the element being referred to have the same electron configuration as a helium atom.

In the case of [He], it implies that all electrons in the 1s orbital are considered core electrons. Core electrons are the electrons that are closest to the nucleus and are not involved in chemical bonding or interactions with other atoms. They are generally not shown in chemical equations or reactions as they do not participate in the chemical behavior of an element.

So, the symbol [He] implies that the core electrons include the two electrons in the 1s orbital of the element being described.

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The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.

Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.

Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.

According to the given data;

Decomposition of carbon monoxide (CO);

Oxygen produced = 3.36 g

Carbon produced = 2.52 g

We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;

Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol

Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol

Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;

0.21 mol C / (0.21 mol O) = x

Simplifying the equation, we have;

x = 1

Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.

Decomposition of carbon dioxide (CO₂);

Oxygen produced = 9.92 g

Carbon produced = 3.72 g

Following the same calculations as before;

Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol

Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol

Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;

0.31 mol C / (0.62 mol O) = y

Simplifying the equation, we have;

y = 0.5

Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.

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--The given question is incomplete, the complete question is

"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--

The concentration of CO and H2O are decreasing by x, as the forward reaction will proceed to consume CO and H2O and produce CO2 and H until the reaction reaches equilibrium. Option A

The equilibrium constant, Keq, for the reaction CO + H2O ← → CO2 + H is given as 5.1 at 700°C. If 1 mole of each species is mixed in a 1L flask, we can use the given equilibrium constant to predict the direction in which the reaction will proceed.

The reaction quotient, Q, is given by the ratio of the concentrations of the products to reactants, raised to their stoichiometric coefficients. Initially, the concentrations of all the species are equal to 1 M. Therefore, the reaction quotient is:

Q = [CO2][H]/[CO][H2O] = (1 x 1)/(1 x 1) = 1

Comparing Q and Keq, we find that Q < Keq. This means that the reaction is not yet at equilibrium, and the forward reaction will proceed to reach equilibrium.

Therefore, the correct answer is (A) The concentration of CO and H2O are decreasing by x, as the forward reaction will proceed to consume CO and H2O and produce CO2 and H until the reaction reaches equilibrium. Option A

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Answer:

electrolytes yes it is

Explanation:

i'm built different

Answer:

Number of energy levels that the element has.

Explanation:

The period number (n) is the outer energy level that is occupied by electrons. The period number that an element is in, is the number of energy levels that the element has.

Answer: Significant figures in a measurement are all measured digits, and one estimated digit

Significant figures communicate the level of precision in measurements Significant figures are an indicator of the certainty in measurements.

Explanation:

Significant figures : The figures in a number which express the value or the magnitude of a quantity to a specific degree of accuracy or precision is known as significant digits.

The significant figures of a measured quantity are defined as all the digits known with certainty and the first uncertain or estimated digit.

Rules for significant figures:

1. Digits from 1 to 9 are always significant and have infinite number of significant figures.

2. All non-zero numbers are always significant.

3. All zero’s between integers are always significant.

4. All zero’s preceding the first integers are never significant.

5. All zero’s after the decimal point are always significant.

The true statements are

Significant figures in measurement are all measured digits, and one estimated digit

Significant figures communicate the level of precision in measurements Significant figures are an indicator of the certainty in measurements.

The following information should be considered:

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Answer:

choice D. Ionic, because valence electrons are transferred.

Explanation:

Among the given options, C2H6 is the least soluble in water.The answer is option A. Ethane (C2H6) is a nonpolar hydrocarbon composed of two carbon atoms and six hydrogen atoms. Because water molecules are polar, they interact only with polar molecules or ions, not nonpolar ones.

As a result, Ethane (C2H6) lacks polar functional groups like OH, NH2, and COOH, and it is therefore nonpolar. It has no permanent dipole moment as a result of the symmetrical arrangement of the C-H bonds in a tetrahedral geometry, and it is only able to interact with water molecules via Van der Waal forces or London Dispersion Forces. Because water is a polar solvent, nonpolar compounds like C2H6 are poorly soluble in water. Therefore, among the given options, C2H6 is the least soluble in water.In summary, the answer is C2H6. The answer is option A

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Answer:

Control group:

Test section covered with the "Steel Seal" floor wax

Explanation:

In a scientific experiment, the control group is the standard group to which comparison is made, to determine the effect of the experimental agent on the test subjects. In this example, the Steal Seal floor wax is the standard wax being used, and the experimenter wants to see if the "Tough Stuff" wax is better, hence after the treatment with the Tough Stuff wax, the number of scratches observed is compared with the standard wax area and the difference determines if it is a better waxing agent or not.

The compound is basic in nature but the concentration substance is corrosive.

Sodium hydroxide is a compound that is formed from sodium and hydrogen as well as oxygen The compound is basic in nature but the concentration substance is corrosive.

a) The acute health effect of exposure to NaOH is skin burn while the chronic effect of exposure is damage to the lungs.

b) The first aid for the ingestion of NaOH is to take in plenty of water.

c) The compound is not flammable

d) The chemicals that could produce a dangerous reaction with NaOH are acids

e) To handle small spills, irrigate the affected area with plenty water and use lab coats, gloves and eye wear when working with the solution.

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