Rahul sees a flock of birds. He watches as the flying birds land in neat little rows on several power lines. Which change of state does the motion of the birds most closely model?

melting
vaporization
deposition
sublimation

Answers

Answer 1

Answer:

the answer is sublimation

Answer 2

Answer:

The answer is sublimation


Related Questions

Luis is Is using a treadmill at the gym that monitors his heart rate electronically his target heart rate zone is 128 to 170 bpm rate. But his heart rate is currently measuring at 185 bpm. What should he do to get the best possible work out?

Answers

The best possible workout needed to attain target heart rate zone is 128 to 170 bpm rate from 185 bpm is to decrease his speed and incline which is denoted as option B.

What is Exercise?

This is referred to as a form of physical activity which helps to keep the body fit and improve the general well being of individuals.

High blood pressure is usually cause when the body is performing vigorous exercises which was most likely done by Luis which was the heart rate was  185 bpm, However in other to decrease it, it also necessary to the speed and incline which helps to relax the body a bit.

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The options are:

Increase his speed and inclineDecrease his speed and inclineIncrease his duration and water intakeDecrease his duration and water intake.

You find an old book and decide to estimate the thickness of one of the sheets or leafs. Neglecting the front and back cover, if all the sheets of book are 3 inches thick, and has 1024 marked pages (numbered 1 to 1024), what is the approximate thickness of the sheet in units of mm.

Answers

Explanation:

There are 1024/2 = 512 SHEETS   (each is numbered on two sides)

  3 inches * 25.4 mm/inch / 512 sheet = .1488 mm per sheet

John heats 1 kg of soup from 25 °C to 70 °C for 15 minutes by a heater. How long does the same heater take to heat 1.5 kg of the same kind of soup from 20 °C to 80 °C? The energy output per unit time by the heater is constant.

Answers

Answer:

30 minutes

Explanation:

Energy per time is constant, so:

E₁ / t₁ = E₂ / t₂

m₁C₁ΔT₁ / t₁ = m₂C₂ΔT₂ / t₂

(1 kg) C (70°C − 25°C) / 15 min = (1.5 kg) C (80°C − 20°C) / t

(1 kg) (45°C) / 15 min = (1.5 kg) (60°C) / t

3/min = 90 / t

t = 30 min

A 67 kg high jumper leaves the ground with a
vertical velocity of 6.4 m/s.
How high can he jump? The acceleration
of gravity is 9.8 m/s².
Answer in units of m. Answer in units of m.

Answers

The height of the jump having a mass of 67kg with the vertical velocity of 6.4m/s is 2.089m.

What is Kinetic and Potential energy?

Potential energy is defined as the energy stored in an object or system by virtue of its position or arrangement of parts while kinetic energy is defined as the energy of the moving particles of an object or system.

Potential energy is represented as :

P.E.= mgh

Kinetic energy  is represented as :

\(K.E.= 1/2mv^2\)

where, m = mass of the object

h= height

v= velocity

g= acceleration due to gravity which is \(9.8m/s^2\)

For above given example,

m= 67kg, v= 6.4m/s

we first find out Kinetic energy,

K.E.=\(\frac{1}{2} 67* (6.4)^2\)= 2744.32/2= 1372.16 J

As we know, K.E.= P.E.

So, P.E.= 1372.16J = mgh

1372.16= 67* 9.8* h

height= 2.089 m

Thus, the height of the jump having a mass of 67kg with the vertical velocity of 6.4m/s is 2.089m.

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A 24.4kg dog is running northward at 2.14m/s, while a 5.53kg cat is running eastward at 3.56m/s. Their 78.5kg owner has the same momentum as the two pets taken together. Find the direction of the owner's velocity. Find the magnitude of the owner's velocity.

Answers

The owner's velocity is in the opposite direction of the combined velocity of the dog and the cat, and its magnitude is approximately 0.916 m/s.

To solve the given problem, we can use the principle of conservation of momentum to find the direction and magnitude of the owner's velocity.

Let's denote the velocity of the dog as v1 (northward), the velocity of the cat as v2 (eastward), and the velocity of the owner as v (unknown).

According to the conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction.

The total momentum before the interaction is given by:

Total momentum before = (mass of the dog * velocity of the dog) + (mass of the cat * velocity of the cat) + (mass of the owner * velocity of the owner)

Mass of the dog (m1) = 24.4 kg

Velocity of the dog (v1) = 2.14 m/s

Mass of the cat (m2) = 5.53 kg

Velocity of the cat (v2) = 3.56 m/s

Mass of the owner (m3) = 78.5 kg

Velocity of the owner (v) = unknown

Total momentum before = (24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v)

The total momentum after the interaction is zero since the owner has the same momentum as the pets taken together.

Total momentum after = 0

Equating the two expressions:

(24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v) = 0

Simplifying the equation:

(52.216 kg·m/s) + (19.6488 kg·m/s) + (78.5 kg * v) = 0

71.8648 kg·m/s + (78.5 kg * v) = 0

Solving for v:

78.5 kg * v = -71.8648 kg·m/s

v = -71.8648 kg·m/s / 78.5 kg

v ≈ -0.916 m/s

Therefore, the direction of the owner's velocity is opposite to the combined velocity of the dog and the cat, and the magnitude of the owner's velocity is approximately 0.916 m/s.

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A cannon ball is shot horizontally off a 37.0 m cliff and lands a distance of 18.5 m
from the base of the cliff. Whall was the initial horizontal velocity of the cannon ball?

Answers

Answer:

vₓ = 6.73 m/s

Explanation:

Assuming no other external influences than gravity, in the horizontal direction (which we make to coincide with the x- axis) , speed is constant, so, applying the definition of average velocity, we can write the following equation:

       \(v_{x} = \frac{\Delta x}{\Delta t} (1)\)

Now, in the vertical direction (coincident with the y- axis) , as both movements are independent each other, initial velocity is zero, so we can write the following equation for the vertical displacement:

       \(\Delta h = \frac{1}{2} * g * t^{2} (2)\)

where Δh = -37.0 m , g = -9.8 m/s2Solving (2) for t, we get:

       \(t = \sqrt{\frac{2*\Delta h}{g} } =\sqrt{\frac{2*37.0m}{9.8m/s2}} = 2.75 s (3)\)    

Taking t₀ = 0, ⇒ Δt = tReplacing (3) in (1), we get:

       \(v_{x} = \frac{\Delta x}{\Delta t} = \frac{x}{t} = \frac{18.5m}{2.75s} = 6.73 m/s\)

As the horizontal velocity is constant, the initial horizontal velocity is just the average one, i.e., 6.73 m/s.

What force pushes the plane upwards

Answers

Answer: The force that pushes a plane upwards is the lift generated by the wings as the plane moves through the air. The lift force is created by the difference in air pressure above and below the wings, which creates an upward force that opposes the weight of the plane.

what is kinematics ;-;
explain.​

Answers

Answer:

the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion.

Explanation:

you take a running leap, leaving the ground with a speed 6.00 m/s at an anglle 40.0 degrees above horizontal.

Answers

The maximum height reached while running is calculated to be 0.75m.

The formula for the maximum height of the projectile motion is given by

H = u² (sin θ)²/2g

where, θ is the angle made with the horizontal

H is the maximum height reached

g is the acceleration due to gravity

u is the initial velocity

Given that, u = 6 m/s

g = 10 m/s²

θ = 40°

Substituting the above values, we have,

H = u² (sin θ)²/2g = 6² * (sin 40°)² / 2 * 10 = 36* 0.414/20 = 0.75 m

Thus, the maximum height reached while running is 0.75m.

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What does newton first law states ​

Answers

Answer:

Newton's first law, also known as the law of inertia, states that an object will remain at rest or in motion at a constant velocity unless acted upon by an external force. In other words, an object will not change its velocity on its own, it will only do so if something else pushes or pulls on it. This law is a fundamental principle of classical mechanics, and it helps to explain the behavior of objects under various conditions.

Explanation:

Answer: Newton first law states that an object at rest tends to stay at rest. an object in motion tends to stay in motion in a straight line at a constant speed until another force acts on the object.  It is also called the law of inertia

Explanation: Newton’s first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

Hope this was helful

How far did the object travel from time = 0 to time =15 s 120 m. 180 m 90 m 45 m

How far did the object travel from time = 0 to time =15 s 120 m. 180 m 90 m 45 m

Answers

Answer:Position is an object’s location in relation to a reference point.

Yes. As in the movie theater example, an object can be one unit positive from the reference point and a different object can be one unit negative from the reference point. Both objects are one unit away (the same distance), but they occupy different locations in space because they are in different directions.

Distance is the total amount an object has traveled, while displacement is the shortest distance between the object’s starting and finishing point.

Distance does not have direction. Objects can be one unit away from a point in every direction. However, displacement does have a direction. Displacement is defined as a specific distance in a specific direction.

Explanation: hope it helped

How to find force if mass time and distance is given?

Answers

Answer:

For example, speed is a length divided by time. Force is mass times acceleration, and is therefore a mass times a distance divided by the square of a time. We therefore say that [Force] = MLT−2.

A projectile is fired straight up with an initial velocity of 40.0 m/s . Approximately how high will the projectile ?

Answers

Answer:

it depends on the wind and any other conditions but if you have a controlled environment it should take 1 second to get 40 meters but it could go higher in which it could take about 5 seconds to go 200 meters

Explanation:

hope it helped

:)

A box with a mass of 30kg accelerates at a rate of 3m/s. If the force of friction on the box is 20N, how much force did you exert in order to move it?

Answers

The force exerted in order to move the box is 404 N.

What is force?

Force is a pull or push effect on a body.

The force on a body is related to the mass and the acceleration of the body.

The acceleration of a body is inversely related to the mass of of the body and directly related to the force acting on it.

Force = mass * acceleration.

Net force = Force applied - (weight of the body + frictional force)

Force applied = Net force + weight of the body  + frictional force

Weight of the body = 30 * 9.8 m/s = 294 N

Net Force = 30 * 3 = 90 N

Force applied = 90 N + 294 N + 20 N

Force applied = 404 N

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What is a Cuticle?

20 POINTS

Answers

Answer:

a protective and waxy or hard layer covering the epidermis of a plant, invertebrate, or shell.

Answer:

The cuticles for animals are a thin layer of clear dead skin around the nail bed on fingers and toes. As the nail grows, it naturally pushes and damages the underside of the skin around the base of the nails, called the eponychium. The space between the eponychium and the bottom of the nail is where the cuticle is located.  

The cuticle definition related to plants is a protective and waxy or hard layer covering the epidermis. The plant cuticle is an extracellular hydrophobic layer that covers the aerial epidermis.

Explanation:

a construction crew is lengthening a road that originally measured miles. the crew is adding one mile to the road each day. the length, (in miles), after days of construction is given by the following function.

Answers

As the crew is adding one mile to the road each day, so the length of the road after 27 days is 79 miles.

A collection of skilled workers, including a supervisor, a construction manager, a distinct maintenance staff, and a team of specialist labourers, make up an efficient construction crew. Employees must actively participate in the prevention of hazardous situations as they have a significant role to play.

A road construction crew assists with new road and sidewalk creation, repairs to or improvements to current roads, and the burying of wires underneath the local roads. They are also known as vehicle restraining operators and highway maintenance operators.

The question is incomplete, find the complete question here

A construction crew is lengthening a road that originally measured 52 miles. The crew is adding one mile to the road each day. The length, L (in miles), after d days of construction is given by the following function. L = 52 + d. what is the length of the road after 27 days?

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Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.40 cm. If the potential difference across the plates was 23.0 kV, find the magnitude of the electric field (in V/m) in the region between the plates.

Answers

Answer:

E =  1.64 x 10⁶ V/m

Explanation:

The electric field in the region between the plates can be given by the following formula:

\(E = \frac{\Delta V}{d}\)

where,

E = Electric Field = ?

ΔV = Poetential Difference across the plates = 23 KV = 23000 V

d = distance between plates = 1.4 cm = 0.014 m

Therefore, using these values in the equation, we get:

\(E = \frac{23000\ V}{0.014\ m}\)

E =  1.64 x 10⁶ V/m

Each value measured in nature has a number value, called its magnitude, and
a dimension, or
Answer here

Answers

Answer:

yassssssssssssssssssssssssssssssssssssss

Explanation:

what would happen if gravity were to stop everywhere?

Answers

Answer:

everything will float up and go up to space and die

Explanation:

gravity keeps us down and once it stops everything will float up. And if it were to stop everywhere everything and everyone will die and everything will be destroyed.

How would you go about answering this question?

How would you go about answering this question?

Answers

The new angular velocity becomes  0.286 rev/s.

Given parameters:

Mass of the marry go round: M = 120 kg.

Radius of the marry go round: r = 1.80 m.

Mass of the boy: m = 27 kg.

Initial angular velocity of the marry go round: ω₁ = 0.350 rev/s.

Final angular velocity of the marry go round: ω₂ = ?

From the principle of conservation of angular momentum;

Initial angular momentum = final angular momentum

⇒ 1/2 Mr²ω₁ = 1/2( M+m)r²ω₂

⇒ ω₂ = Mω₁/(m+M)

= 120×0.35/(120+27) rev/s

= 0.286 rev/s.

So, final angular velocity of the marry go round: ω₂ = 0.286 rev/s.

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a bulb rated 100 watt 120 volt is connected across a 120 volt source find the current in the bulb and power consumed by it ​

Answers

As it mentioned

100W/120V

So

power is 100W

Now

Current be I

\(\\ \rm\rightarrowtail I=\dfrac{P}{V}=\dfrac{100}{120}=\dfrac{5}{6}=0.8A\)

They believes studying behavior, the mind and circumstances leads to
understanding people
gestalt
functionalism
structuralism
behaviorism

Answers

the answer is behaviorism !! <3

the answer is behaviorism=3

miniature spring-loaded, radio-controlled gun is mounted on an air puck. The gun's bullet has a mass of 5.00 g, and the gun and puck have a combined mass of 120 g. With the system initially at rest, the radio controlled trigger releases the bullet causing the puck and empty gun to move with a speed of 0.500 m/s. What is the bullet's speed

Answers

Answer:

12 m/s

Explanation:

From the question,

Applying the law of conservation of momentum,

total momentum before collision = Total momentum after collision

mu+Mu' = mv+Mv'........................... Equation 1

Where m = mass of the bullet, u = initial velocity of the bullet, M = combined mass of the gun and the puck, u' = initial velocity of the gun and the puck, v = final velocity of the bullet, v' = final velocity of the gun and the puck

make v the subeject of the equation

v = [(mu+Mu')-Mv']/m................. Equation 2

Given: m = 5.00 g = 0.005  kg, M = 120 g = 0.12 kg, u = u' = 0 m/s (at rest), v' = 0.5 m/s

Substitute these values into equation 2

v = [0-(0.12×0.5)]/0.005

v = -0.06/0.005

v = -12 m/s

The negative sign  can be ignored since we are looking for the speed, which has only magnitude.

Hence the speed of the bullet is 12 m/s

What do mammoths and tigers need energy for

Answers

Muscles
.............

What kind of object are the light rays interacting with in the model below?

Convex mirror
Convex lens
Concave mirror
Concave lens

What kind of object are the light rays interacting with in the model below?Convex mirrorConvex lensConcave

Answers

Answer:

Concave lens

.............

Mark weighs 375 N and is carrying a full-sized cello as he climbs the stairs to a height of 4 m. It takes him 3 seconds to do this.
How does the amount of work he does change if he were to climb the same flight of stairs again in the same amount of time, but this time without the cello?

A) It depends on the weight of the cello.

B) It remains the same.

C) It increases

D) It decreases.

Answers

Mark's work decreases when he climbs the same flight of stairs again in the same amount of time without the cello.

The correct answer is option D.

The amount of work Mark does depends on the weight of the cello, as well as the distance he climbs and the time it takes. Work is calculated using the formula :

Work = Force × Distance.
In the given scenario, Mark is carrying a full-sized cello while climbing the stairs. The weight of the cello adds to the force he exerts. So, the total force Mark exerts is the weight of the cello plus his own weight (375 N).

When Mark climbs the stairs with the cello, he is doing work against the force of gravity.

The work done is equal to the force exerted multiplied by the distance climbed (375 N + weight of cello) × 4 m.

Now, if Mark were to climb the same flight of stairs again in the same amount of time (3 seconds), but this time without the cello, the amount of work he does would decrease. This is because without the cello, the force exerted would only be Mark's weight (375 N), which is less than the total force exerted with the cello.

Therefore, mark's work decreases.

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A footballer kicks a ball from rest. The foot is in contact with the ball for 0.30s and the final velocity of the ball is 15ms-1 .What is the average acceleration of the ball?​

Answers

Answer:

50m/s^2

Explanation:

Step one:

given data

initial velocity u= 0m/s since the ball is at rest

time of contact t= 0.3s

final velocity v=15m/s

Required

acceleration a

from the first law of motion

v=u+at

substitute our given data

15=0+a*0.3

15=0.3a

divide both sides by 0.3

a=15/0.3

a=50m/s

The average acceleration is 50m/s^2

The value of q1 and q2 will be 3.0 x 10^-9 C respectively. Because to be at equilibrium, both of the charges must have equal but opposite charge in them is -6 x 10^-9 C. So we will divide this value into equal and opposite types

Answers

Answer:

Yes, you are correct. In order to be in equilibrium, two charges must have equal but opposite charges. So, if the total charge is -6 x 10^-9 C, dividing it into equal and opposite charges would give each charge a value of 3 x 10^-9 C. This is because (-6 x 10^-9 C) / 2 = 3 x 10^-9 C.

Two bodies separated from
each other at a certain distance
started moving simultaneously
to meet each other - one with ar
acceleration of 2.4 m/s, and the
other with an acceleration of 4.8
m/s2. Determine the ratio of the
displacement module of the first
body to the displacement
module of the second body at
the moment of their meeting.

Answers

The result of the ratio of the displacement module of the second body at the point of meeting is 0.5.

How to find displacement ratio?

To determine the ratio of the displacement of the first body to the displacement of the second body at the moment of their meeting, use the equation of motion:

d = vt + 1/2at²

where d is the displacement, v is the initial velocity, t is the time, and a is the acceleration.

Since the bodies are moving simultaneously towards each other, then assume that their initial velocities are zero. Also, at the moment of their meeting, their displacement will be the same, d₁ = d₂.

Assume that the time at which they meet is t, then:

d₁ = 1/2 * 2.4t²

And the equation for the displacement of the second body:

d₂ = 1/2 * 4.8t²

If d₁ = d₂

then, 1/2 * 2.4t² = 1/2 * 4.8t²

Solving this equation for t and substituting it into the equation for d₁ or d₂, the ratio of the displacement of the first body to the displacement of the second body: d₁/d₂ = 2.4/4.8 = 0.5 or 1/2

So, at the moment of their meeting, the displacement of the first body is half of the displacement of the second body.

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When a condenser discharges electricity, the instantaneous rate of change of the voltage is proportional to the voltage in the condenser. Suppose you have a discharging condenser and the instantaneous rate of change of the voltage is -0.01 of the voltage (in volts per second). How many seconds does it take for the voltage to decrease by 90 %?

Answers

Answer:

460.52 s

Explanation:

Since the instantaneous rate of change of the voltage is proportional to the voltage in the condenser, we have that

dV/dt ∝ V

dV/dt = kV

separating the variables, we have

dV/V = kdt

integrating both sides, we have

∫dV/V = ∫kdt

㏑(V/V₀) = kt

V/V₀ = \(e^{kt}\)

Since the instantaneous rate of change of the voltage is -0.01 of the voltage dV/dt = -0.01V

Since dV/dt = kV

-0.01V = kV

k = -0.01

So, V/V₀ = \(e^{-0.01t}\)

V = V₀\(e^{-0.01t}\)

Given that the voltage decreases by 90 %, we have that the remaining voltage (100 % - 90%)V₀ = 10%V₀ = 0.1V₀

So, V = 0.1V₀

Thus

V = V₀\(e^{-0.01t}\)

0.1V₀ = V₀\(e^{-0.01t}\)

0.1V₀/V₀ = \(e^{-0.01t}\)

0.1 = \(e^{-0.01t}\)

to find the time, t it takes the voltage to decrease by 90%, we taking natural logarithm of both sides, we have

㏑(0.01) = -0.01t

So, t = ㏑(0.01)/-0.01

t = -4.6052/-0.01

t = 460.52 s

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