Quickly please! Which is a group of tissues that work together to carry out a common function?

cell
organ
organelle
organ system

Answers

Answer 1

Answer:

organ system

Explanation:

Answer 2

Answer:

B) organ

Explanation:


Related Questions

What is the volume of a 12.2 g piece of metal with a density of 9.43 g/cm??

What is the volume of a 12.2 g piece of metal with a density of 9.43 g/cm??

Answers

Answer:

1.29

Explanation:

You have to find the equation which is d=m/v. d is 9.43=12.2/v. You have to solve for v which you get 1.29

1.29 \(cm^3\) is the volume of a 12.2 g piece of metal with a density of 9.43 g/cm.

What is density?

Density is the measurement of how tightly a material is packed together.

Density =Mass ÷ volume

9.43=12.2 ÷  V

V = 1.29 \(cm^3\)

Hence, 1.29 \(cm^3\) is the volume of a 12.2 g piece of metal with a density of 9.43 g/cm.

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calculate the area of a book which has length 30cm and breadth 20cm

Answers

30cm*20cm= 600cm^2
You have to multiply the length(30cm) times the breadth(20cm), in order to get your answer(600cm^2).
Area = length by width(breadth)
Area = 30cm x 20cm
Area = 600 cm^2

In a science demonstration, a teacher mixed zinc (Zn) with hydrogen chloride (HCl) in a flask and quickly attached a balloon over the mouth of the flask. Bubbles formed in the solution and the balloon inflated.
What most likely occurred during this demonstration?

a.The Zn and HCl both retained their identity.
b.Either Zn or HCl, but not both, retained its identity.
c.Evaporation of one of the substances occurred.
d.One or more new substances formed.

Answers

Answer:

a. The Zn and HCl both retained their identity.

Draw the Lewis electron dot
structure for COCI2.
What is the VSEPR shape of this
particle? PLS HELP

Answers

Answer:

Idon't know if this helps but I think it is a linear structure and if I am wrong I am so sorry

What is the number of Li atoms in 4.5 mol of Li?

2.7 x 1024 atoms

27 x 1024 atoms

2.2 x 1023 atoms

2.0 x 1023 atoms

Answers

The number of lithium, Li atoms in 4.5 moles of lithium, Li is 2.7×10²⁴ atoms

Data obtained from the question Number of mole of Li = 4 moles Number of atoms =?

Avogadro's hypothesis

1 mole of Li = 6.02×10²³ atoms

How to determine the number of atoms

From Avogadro's hypothesis given above,

1 mole of Li = 6.02×10²³ atoms

Therefore,

4.5 moles of Li = 4.5 × 6.02×10²³

4.5 moles of Li = 2.7×10²⁴ atoms

Thus, we can conclude that 2.7×10²⁴ atoms are present in 4.5 moles of lithium.

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How can you make an item that is made of magnetic material become a permanent magnet instead of a temporary magnet? *
1.You can put it in a very strong magnetic field. 2.You can heat it while it is being influenced by a magnetic field. 3. You can leave it in the magnetic field of an actual magnet for a long time. 4. You can do any of the above.​

Answers

You can put it in a very strong magnetic field.

what is the formula of water​

Answers

Answer:

H2O is the formula of water

Answer:

H²O is formula of water

Explanation:

2 molecule of hydrogen and 1 molecule of oxygen

What would happen to the measured cell potentials if 30 mL solution was used in each half-cell instead of 25 mL

Answers

Answer:

The answer is "\(\bold{\log \frac{[0] mole}{[R]mole}}\)"

Explanation:

\(E_{cell} =E_{cell}^{\circ} - \frac{0.0591}{n}= \log\frac{[0]}{[R]}\\\)

In the above-given equation, we can see from \(E_{ceu}\), of both oxidant \(conc^n\)as well as the reactant were connected. however, weight decreases oxidant and reduction component concentration only with volume and the both of the half cells by the very same factor  and each other suspend

\(\to \log \frac{\frac{\text{oxidating moles}}{25 \ ml}}{\frac{\text{moles of reduction}}{25 ml}} \ \ = \ \ \log \frac{\frac{\text{oxidating moles}}{30 \ ml}}{\frac{\text{moles of reduction}}{30 ml}} \\\\\\\)

\(\to {\log \frac{[0] mole}{[R]mole}}\)

The cell potential of the electrochemical reaction has been the same when the volume has been reduced from 30 mL to 25 mL in each half cells.

The cell potential has been given as the difference in the potential of the two half cells in the electrochemical reaction.

The two cells has been set with the concentration of solutions in the oxidation and reduction half cells.

Cell potential change

The cell potential has been changed when there has been a change in the potential of the half cells.

The volume of 30 mL to the solution has been, resulting in the cell potential difference of x.

With the volume of 25 mL, there has been the difference in the potential being similar to the 30 mL solution, i.e. x.

Thus, the cell potential of the electrochemical reaction has been the same when the volume has been reduced from 30 mL to 25 mL in each half cells.

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A piece of lumber is 7.60cm long. What is it’s length in millimetres and in inches?

Answers

Explanation:

Since 10mm is 1cm

Therefore 7.60cm is 760mm

Since 1 inch is 2.54cm

Therefore 7.60cm is 3.10 inches

A thermometer reads -111.1 °F. What is the temperature in °C?

Answers

The temperature is -79.5
To find C, the formula is
K-273.15=C

The first five ionization energies of an unknown element are listed in the table above. which of the following statements correctly identifies the element and cites the evidence supporting the identification?

Answers

B) Al because the large difference between the third and forth ionization energies.

What is ionization energy?

Ionization energy (also called ionization potential) is the amount of energy required to remove an electron from an isolated atom or molecule in chemistry and physics. There is an ionization energy for each successively removed electron. However, the ionization energy associated with the removal of the first (most loosely held) electron is most commonly used.

The ionization energy of a chemical element, expressed in joules or electron volts, is usually measured in a discharge tube in which rapidly moving electrons produced by an electric current collide with gas atoms of the element, releasing one of them will be electronic.

B) Al because the large difference between the third and forth ionization energies.

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How many molecules are there in a candle wax

How many molecules are there in a candle wax

Answers

Answer:

6

Explanation:

0. Calculate the amount of heat absorbed when 5.50 g of aluminum is heated from
25.0°C to 95.0°C. The specific heat of aluminum is 0.897 J/g °C).

Answers

Answer:

34.5J

Explanation:

Amount of Heat(Q) = mc∆T

where m (mass of aluminum) = 5.50g

c (specific heat capacity of aluminum) = 0.897J/g°C and ∆T = 95.0°C - 25.0°C = 70.0°C

Q = 5.50x 0.897x 70.0

= 34.5354J = 34.5J

The amount of heat absorbed when 5.50 g of aluminum is heated from 25.0°C to 95.0°C is 34.5 J.

What is heat?

Heat is defined as a form of the energy transmitted from one body to another as a result of a temperature difference.

It can also be defined as the potential energy stored in the bonds that hold the object's particles together.

Heat absorption is defined as absorption of heat without increasing the temperature at the certain point.

Amount of heat = mcΔT

Where m = 5.50g

           c = 0.897 J/g °C

           ΔT =  95.0°C - 25.0°C

                 = 70.0°C

So, amount of heat = 5.50 x 0.897 x 70.0

                                = 34.5354 J = 34.5 J

Thus, the amount of heat absorbed when 5.50 g of aluminum is heated from 25.0°C to 95.0°C is 34.5 J.

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An amateur entomologist captures a particularly excellent ladybug specimen in a plastic jar. The internal volume of the jar is 0.5L, and the air within the jar is initially at 1 atın. The bug-lover is so excited by the catch that he squeezes the jar fervently in his sweaty palm, compressing it such that the final pressure within the jar is 1.25 atm. What is the final volume of the ladybug's prison? ​

Answers

The final volume of the ladybug's prison is approximately 0.4 liters.

To determine the final volume of the ladybug's prison, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature. The equation for Boyle's Law is:

P1 * V1 = P2 * V2

Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively.

In this scenario, the initial volume (V1) is given as 0.5 L, and the initial pressure (P1) is 1 atm. The final pressure (P2) is 1.25 atm. We need to find the final volume (V2).

Plugging the given values into the equation, we have:

1 atm * 0.5 L = 1.25 atm * V2

Simplifying the equation, we find:

0.5 L = 1.25 atm * V2

Dividing both sides of the equation by 1.25 atm, we get:

0.5 L / 1.25 atm = V2

V2 ≈ 0.4 L

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Consider the following reaction: 2N2O5(g) → 4NO2(g) + O2(g) Calculate the volume N2O5 that must decompose completely to produce 9.64 L nitrogen dioxide.​

Answers

The volume of \(N_2O_5\) needed to produce 9.64 L of \(NO_2\) is 4.97 L, calculated using stoichiometry and the ideal gas equation.

The given chemical equation is \(2N_2O_5(g) \rightarrow 4NO_2(g) + O_2(g)\) .The volume of \(N_2O_5\) that decomposes completely to form 9.64 L of \(NO_2\) is to be calculated. For this, we can use the concept of stoichiometry. Stoichiometry is a branch of chemistry that deals with the quantitative relationships between reactants and products in a balanced chemical equation.To calculate the volume of \(N_2O_5\) that is needed to produce 9.64 L of \(NO_2\), we will first determine the number of moles of NO2 produced in the reaction. For this, we can use the ideal gas equation, PV = nRT. Here, we have the volume of NO2 and we can assume the pressure and temperature to be constant. Thus, we have PV = nRT, where P = pressure, V = volume, n = number of moles, R = ideal gas constant, and T = temperature. Substituting the given values in the ideal gas equation, we get,n = PV/RT = (1 atm × 9.64 L)/(0.0821 L atm K-1 mol-1 × 300 K) = 0.404 molFrom the chemical equation, we see that 2 moles of \(N_2O_5\) give 4 moles of \(NO_2\). Thus, 0.404 mol of \(NO_2\) must have been produced from (0.404/2) = 0.202 mol of \(N_2O_5\). Using the ideal gas equation, we can also find the volume of 0.202 mol of \(N_2O_5\) at the given conditions. Thus, V = nRT/P = (0.202 mol × 0.0821 L atm K-1 mol-1 × 300 K)/1 atm = 4.97 L. Thus, the volume of \(N_2O_5\) that must decompose completely to produce 9.64 L nitrogen dioxide is 4.97 L.

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Please if you know the answer put it thanks

Please if you know the answer put it thanks

Answers

The diagram shows a picture of a compound.

What is a compound?

A compound is a substance that is made up of two or more different elements that are chemically bonded together in a specific ratio.

This means that the elements are combined in a way that creates a new substance with different physical and chemical properties than the individual elements.

Compounds can be formed through a variety of chemical reactions, such as combining elements through a chemical bond or through a reaction between an acid and a base.

So for the given diagram, we can see that it represents two or more elements chemically combined.

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Pls help !
What happens to the speed of a tsunami wave as it approaches the shore?

It increases and then decreases.

It increases.

It remains at a constant speed.

It decreases.

Which term represents when a tsunami wave slows down as it reaches shore?

surfing

waving

sinking

shoaling

Answers

Answer: It decreases.

Explanation:

Calculate the molar solubility, S , of CuS if it has a Ksp value of 6×10−37.

Answers

The molar solubility of CuS is 7.8 x 10⁻¹⁹ M.

The solubility product expression for CuS is:

Ksp = [Cu²⁺][S²⁻]

Since CuS dissociates to form one Cu²⁺ ion and one S²⁻ ion, the molar solubility of CuS can be represented as x. Therefore, at equilibrium:

[Cu²⁺] = x[S²⁻] = x

Substituting these values in the Ksp expression:

Ksp = x²

Solving for x, we get:

x = √(Ksp) = √(6 x 10⁻³⁷) = 7.8 x 10⁻¹⁹ M

Therefore, the molar solubility of CuS is 7.8 x 10⁻¹⁹ M.

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The complete question is:

Calculate the molar solubility, S , of CuS if it has a Ksp value of 6×10⁻³⁷.

Describe how adaptations can help survival

Answers

Adaptions can help survival by an organism making modifications to their body, behavior. For an example humans have chopped down a forest. For the animals they have to adapt by migration or blend in with their environment

An empty weighing dish has a mass of 1.0041 ± 0.0002 g. After you add dried sodium chloride to the dish, the mass is 3.2933 ± 0.0002 g. You quantitatively transfer the sodium chloride into a 500.00 ± 0.05 mL volumetric flask and dilute to the mark with deionized water. The molar mass of sodium chloride is 58.440 g/mol. What is the absolute error in the concentration of the resulting solution? Report your answer normally to the correct number of significant figures with the correct unit.

Answers

Answer:

The correct answer to the following question will be "0.0013%".

Explanation:

The given values are:

Weight of an empty dish = 1.0041 ± 0.0002 g

Weight of dish + sodium chloride (NaCl) = 3.2933 ± 0.0002 g

Weight of NaCl = 2.2892 ± 0.0002 g

Now,

Volume of the solution = 500.00 ± 0.05 ± 0.0002

                                      = 500.00 ± 0.0502 ml

So,

Molarity = \(\frac{W \ NaCl}{M \ NaCl} \times \frac{1000}{Volumes \ of \ solution}\)

On putting the values in the above formula, we get

             = \(\frac{(2.2892\addeq +0.0002)}{58.440}\times \frac{1050}{(500.00+0.0502)}\)

             = (\(3.917\) ± \(0.0002\)) × (\(2\) ± \(0.0502\))

             = (\(0.7834\) ± \(.00001004\))

Now,

Absolute error = \(\frac{0.00001004}{0.7834}\times 100\)

                         = \(0.0013\)%

If 315 days have passed how many grams of iodine-125 will remain undecayed

Answers

Mass of Iodine-125 remaining undecayed after 315 days is 8.28 g.

What mass of iodine-125 will remain undecayed if 315 days have passed?

The mass of iodine-125 which will remain undecayed if 315 days have passed is determined as follows:

Half-life of Iodine-125 = 60 days

Number of half lives in 315 days is to be determined.

315 days = 300 days + 15 days

Number of half lives in 300 days = 300 / 600

Number of half lives in 300 days = 5 half lives

Number of half lives in 15 days = 15 / 60

Number of half lives in 15 days = 1/4 half lives

After 5.25 half lives, amount remaining = (0.5)⁵°²⁵ = 0.02628

Mass remaining undecayed = 0.02628 * 315

Mass remaining undecayed = 8.28 g

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Complete question:

The half-life of iodine-125 is 60 days and an initial mass of 300 g is present.. If 315 days have passed how many grams of iodine-125 will remain undecayed

Given a 64.2-g
sample of this substance with a specific heat of 50.6 J/(kg·°C),
how much heat is required to change its temperature from 180.0 °C
to 244.0 °C?

Answers

The total amount of heat generated is 207.5 J, under the condition that the given sample possess 64.2-g sample of this substance with a specific heat of 50.6 J/(kg•°C).

The heat needed to change the temperature of a substance can be evaluated applying the given formula

q = m × c × ΔT

Here

q = energy added,

m = mass of the substance,

c = specific heat capacity of the substance

ΔT = change in temperature.

Then we can proceed by calculating the heat required to change its temperature from 180.0 °C to 244.0 °C by converting the mass of the substance from grams to kilograms

m = 64.2 g = 0.0642 kg

Then, we can evaluate the change in temperature

ΔT = (244.0 °C - 180.0 °C)

= 64.0 °C

Lastly, we can apply the formula above to evaluate the heat required

q = m × c × ΔT

= (0.0642 kg) × (50.6 J/(kg•°C)) × (64.0 °C)

= 207.5 J

Hence, 207.5 J of heat is required to change the temperature of this substance from 180.0 °C to 244.0 °C.

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2 Na + 2 H20 = 2 NaOH + H2 is this equation balanced

Answers

Answer: yes it it balanced you have 2 atoms on both sides of the equation

Explanation:

3. A light bulb containing argon gas is switched on,
and after 30 minutes its temperature is 418 K
What Celsius temperature is equal to 418 K?

Answers

Answer:

The assumption is quite reasonable.........

A lightbulb contains Ar gas at a temperature of 295K and at a pressure of 75kPa. The light bulb is switched on, and after 30 minutes its temperature is 418 K. What is a numerical setup for calculating the pressure of the gas inside the light bulb at 418K?

Explanation:

P

1

T

1

=

P

2

T

2

given constant

n

, and constant

V

, conditions that certainly obtain with a fixed volume light bulb.

And so

P

2

=

P

1

T

1

×

T

2

=

75

k

P

a

295

K

×

418

K

100

k

P

a

.

Had the light bulb been sealed at normal pressure during its manufacture, what do you think might occur when it is operated?

you have two solutions of sodium chloride. one is a 2.00 m solution, the other is a 4.00 m solution. you have much more of the 4.00 m solution and you add the solutions together. which of the following could be the concentration of the final solution?

Answers

When two solutions are mixed, the concentration of the resulting solution will depend on the volumes and concentrations of the two original solutions.

The final concentration can be calculated using the following formula:

Cfinal = (C1V1 + C2V2) / (V1 + V2)

where C1 and C2 are the concentrations of the two solutions, V1 and V2 are their volumes, and Cfinal is the concentration of the final solution.

In this case, one solution has a concentration of 2.00 M, and the other has a concentration of 4.00 M. Let's assume that we have much more of the 4.00 M solution, and that we mix 100 mL of the 2.00 M solution with 400 mL of the 4.00 M solution. We can calculate the resulting concentration of the mixed solution as follows:

Cfinal = (2.00 M x 100 mL + 4.00 M x 400 mL) / (100 mL + 400 mL) = 3.20 M

Therefore, a possible concentration of the final solution is 3.20 M. The actual concentration of the mixed solution will depend on the volumes and concentrations of the original solutions used.

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Photosynthesis cannot happen without:
O light
O chlorophyll
O carbon dioxide
O all of the above
O none of the above

Answers

All of the above — plants need light, chlorophyll, and carbon dioxide to perform photosynthesis, a chemical reaction producing glucose (which provides energy for the plant.)

budding in yeast is it physics chemistry or biology ?

Answers

Answer:

Budding in yeast is primarily a biological process

Which unit of measurement would best be used to measure the volume of a points a DROP of water? .​

Which unit of measurement would best be used to measure the volume of a points a DROP of water? .

Answers

Answer:

milliliter

Explanation:

smallest form of measuring volume from all the available choices

……….is strong due to the ……………..between positive ions and negative delocalized electrons

Answers

Answer:

atom &bond

Explanation:

atom is strong due to the bond

The orbit of a planet is an ellipse with the sunat one of the foci.. This is Kepler's........ second law third law first law​

Answers

Answer:

its keplers first law

Explanation:

answer from gauth math

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