Question 12: P(Y < 4.168) for a Chi-squared distribution with 9 degrees of freedom is approximately 0.0259.
Question 13: P(5.229 < Y < 14.067) for a Chi-squared distribution with 7 degrees of freedom is approximately 0.95.
Question 12: To find P(Y < 4.168) where Y follows a Chi-squared distribution with 9 degrees of freedom, we need to calculate the cumulative probability up to the value 4.168 using the Chi-square distribution table or a statistical software.
Question 13: To find P(5.229 < Y < 11.07) where Y follows a Chi-squared distribution with 6 degrees of freedom, we need to calculate the cumulative probability up to the upper value 11.07 and subtract the cumulative probability up to the lower value 5.229. This will give us the probability of Y falling between those two values.
Question 14: To find the value y such that P(Y > y) = 0.05, where Y follows a Chi-squared distribution with 7 degrees of freedom, we need to find the critical value that corresponds to a cumulative probability of 0.95 (1 - 0.05).
This critical value will be the minimum value of Y for which the tail probability is 0.05
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Ms. Rodas has a class with 26 students. 14 of the students are boys. The department chair asks her to send 3 students to help take inventory of the math textbooks. What is the probability that she sends 2 boys and 1 girl? *
14/25
77/600
539/3900
77/676
Answer: 7/50
Step-by-step explanation:
Answer:
7/50, none of the answer choicesStep-by-step explanation:
Total number = 26Number of boys = 14Number of girls = 12There are three ways of choosing 2 boys and a girl:
P(bbg) = 14/26*13/25*12/24 = 7/50P(bgb) = 14/26*12/25*13/24 = 7/50P(gbb) = 12/26*14/25*13/24 = 7/50As we see the answer is 7/50 and all the answer choices are different from this
Let u=In(x) and v=ln(y), for x>0 and y>0.. Write In (x³ Wy) in terms of u and v. Find the domain, the x-intercept and asymptotes. Then sketch the graph for f(x)=In(x-3).
To find ln(x³y) in terms of u and v, we can use the properties of logarithms. ln(x³y) can be rewritten as ln(x³) + ln(y), and using the property ln(a^b) = bˣ ln(a), we have 3ln(x) + ln(y) = 3u + v.
How can ln(x³y) be written in terms of u and v, where u = ln(x) and v = ln(y)?To find ln(x³y) in terms of u and v, we can use the properties of logarithms. ln(x³y) can be rewritten as ln(x³) + ln(y), and using the property ln(a^b) = bˣ ln(a), we have 3ln(x) + ln(y) = 3u + v.
The domain of the function f(x) = ln(x-3) is x > 3, since the natural logarithm is undefined for non-positive values. The x-intercept occurs when f(x) = 0, so ln(x-3) = 0, which implies x - 3 = 1. Solving for x gives x = 4 as the x-intercept.
There are no vertical asymptotes for the function f(x) = ln(x-3) since the natural logarithm is defined for all positive values. However, the graph approaches negative infinity as x approaches 3 from the right, indicating a vertical asymptote at x = 3.
To sketch the graph of f(x) = ln(x-3), we start with the x-intercept at (4, 0). We can plot a few more points by choosing values of x greater than 4 and evaluating f(x) using a calculator.
As x approaches 3 from the right, the graph approaches the vertical asymptote at x = 3. The graph will have a horizontal shape, increasing slowly as x increases. Remember to label the axes and indicate the asymptote on the graph.
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Abby earned $56 in 7 hours at her job today. She wants to know how much she could earn tomorrow if she works 34 hours at the same hourly rate.
How much will Rachel earn in 34 hours? please help me !!!
Answer:
It will be $85, 34÷ 4
will give you 8.5 then you multiply it by 10,× 10=85
Answer:
272
Step-by-step explanation:
56:7=8 (she earns 8$ in 1 hour)
8×34=272
please help, if correct I’ll give brainlist..
Answer:
I believe the answer is B
Step-by-step explanation:
Learn with an example
Find the perimeter. Simplify your answer.
y-6
y-5
y-5
y-6
Answer:
P = 22
Step-by-step explanation:
P= l(2) + w(2)
5(2) + 6(2)
10 + `12
22
Evaluate 11.5p+10.9r when p=6 and r-7
Step-by-step explanation:
11.5 (6) + 10.9 (7)
= 69+ 76.3
= 145.3
Step-by-step explanation:
11.5(6) + 10.9 (7)
69 + 76.3
145.3
numeric prefixes are used to name select one compounds. they are not used for select one compounds, but the charges must select one .
Greek number prefixes are employed in the naming of molecular (covalent) substances.
Greek number prefixes are employed in the naming of molecular (covalent) substances. Prefixes are always combined in order of size (left-to-right in the table below). For instance, "heptadecatetracta" (7 + 10 + 400) would be the prefix for the number 417.
We utilise prefixes (mono-, di-, tri-, etc.) at the beginning of each element in molecular compounds to denote the element's subscript, but we only use the prefix mono- for the compound's second element.
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Deandre wants to measure the height of a tree. He sights the top of the tree, using a mirror that is lying flat on the ground. The mirror is 33 ft from the tree, and Deandre is standing 10.2 ft from the mirror, as shown in the figure. His eyes are 6 ft above the ground. How tall is the tree? Round your answer to the nearest foot.
What is the volume of the rectangular prism?
Answer:
i think its 256 lol my disc is Andreww#6506 if u want to add me lol
Step-by-step explanation:
Volume of a pentagonal prism is 360 inches cubed. The height of prism is 3 inches. What is the area of the pentagon base?
The pentagonal prism with volume 360 in³ and height of 3 inches have a base area of 120 in²
What is a pentagonal prism?A pentagonal prism is a prism that has two pentagonal bases like top and bottom and five rectangular sides.
Given that, the volume of a pentagonal prism is 360 in³, with a height of 3 inches,
We need to find the area of the base,
We know that, the volume of a pentagonal prism is =
V = 1/4 √(5(5+2√5)·a²h
Where a is the base edge and h is the height,
360 = 1/4·3 √(5(5+2√5)·a²
1/4·√(5(5+2√5)·a² = 120
Since, the base of a pentagonal prism is a pentagon, and the area of a pentagon = 1/4 √(5(5+2√5)·a²
And we have,
1/4 √(5(5+2√5)·a² = 120
Therefore, the base area is 120 in²
Hence, the pentagonal prism with volume 360 in³ and height of 3 inches have a base area of 120 in²
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The scale of a map is 1 in. = mi. Find each length on the map
The question gives the relationship to be
\(1in=21mi\)We will interpolate to solve the question.
First Question: 147 mi
\(\begin{gathered} \text{If 1 in = 21 mi} \\ x\text{ in = 147 mi} \end{gathered}\)Cross multiplying,
\(undefined\)the price of an item has dropped to 63$ today yesterday it was 105$ find the percentage decrease
Answer:
40%
Step-by-step explanation:
Answer:
it decreased by 40% percent.
Step-by-step explanation:
help plz anyone :( will mark
Answer:
area of square - area of circle
s² - pie r²
3² - 3.14 x1 x1
9 - 3.14 cm²
your answer is 5.86cm²
this is area of shaded region
nearest hundered is 6cm²
plz brainlist me bro I need it plz
her answer is wrong brainlist me
Answer:
The area of the shaded region is
Step-by-step explanation:
we know that
The area of the shaded region is equal to the area of the rectangle minus the area of the circle
The rectangle is a square
So.... Plz check rest in the pic!
Hope it helped u if yes mark me BRAINLIEST!
Tysm!
Hbbbbbbbbmmmmmhhehsjsdjs
Diinineinnneeeeeeeeeeeeeeeeeeeee
a bagel store sells 6 different types of bagels. in how many ways can you buy 20 bagels with at least one bagel of each kind?
The number of ways to buy 20 bagels with at least one bagel of each kind from a bagel store that sells 6 different types of bagels is 3060.
To calculate the number of ways to buy 20 bagels with at least one bagel of each kind from a bagel store that sells 6 different types of bagels, we can use the concept of stars and bars.
First, we need to ensure that we have at least one of each type of bagel. So, we take one bagel of each type, which leaves us with 14 bagels to buy.
Now, we can use stars and bars to distribute the remaining 14 bagels among the 6 types of bagels. We represent the 14 bagels as stars and the 5 possible locations between the types of bagels as bars.
Using this method, we need to distribute 14 stars among 5 bars, which can be done in
(14+5-1) choose (5-1) = 18 choose 4 = 3060 ways.
Therefore, the number of ways to buy 20 bagels with at least one bagel of each kind from a bagel store that sells 6 different types of bagels is 3060.
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What is the slope of the line that passes through the points (−3,−9) and (22, -4) ? Write your answer in simplest form.
Answer:
1/5
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-4-(-9))/(22-(-3))
m=(-4+9)/(22+3)
m=5/25
m=1/5
Suppose f(2) is analytic in a deleted neighborhood of infinity (cf: Sec. 2.44) , with Laurent expansion of the form f(z) =...c/z+..._c-1/z+co+c1z+......+cnz^n..... (R Then the point morc exactly A removable singular point if the serics (39) contains no positive powers of 2; A pole of order m if (39) contains only & finite number of positive powers of 2, the highest positive power being An essential singular point if (39) contains infinitely many positive powers of z.
Based on the given information, we can conclude that f(2) is an analytic function in a deleted neighborhood of infinity. This means that f(z) has a Laurent expansion in the form of
\(f(z) = ..._c-2/z^2 + _c-1/z + c0 + c1z + ... + cnz^n + ...,\)
where the coefficients
\(_c-2, _c-1, c0, c1, ...,\)
cn are constants.
The point morc is a singular point of f(z) that can be either removable, a pole of order m, or an essential singular point. The type of singular point depends on the behavior of the Laurent expansion of f(z).
If the Laurent expansion of f(z) contains no positive powers of z, then the point morc is a removable singular point. This means that the singularity can be "filled in" or removed, and the function can be defined at that point.
If the Laurent expansion of f(z) contains only a finite number of positive powers of z, with the highest positive power being m, then the point morc is a pole of order m. This means that the singularity is a simple pole, double pole, triple pole, or higher order pole, depending on the value of m.
If the Laurent expansion of f(z) contains infinitely many positive powers of z, then the point morc is an essential singular point. This means that the singularity cannot be removed or "filled in", and the behavior of the function at that point is very complex.
In summary, the type of singular point at the point morc depends on the behavior of the Laurent expansion of f(z) at that point.
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Mrs. Figueroa made a spaghetti dinner for the cheerleaders after practice. She purchased four and three fourths pounds of beef for $3.99 per pound. How much money did she spend on the beef for the spaghetti?
$7.25
$8.87
$9.98
$18.95
The cost of four and three-fourths pounds of beef is $18.95.
Given,
Amount of beef purchased = 4 and 3/4th pounds.
Cost of beef per pound = $3.99
We need to find how much four and three-fourths pounds of beef cost.
Find the cost of 1 pound of beef.
1 pound = $3.99
We can write four and three-fourths as:
= 4 3/4
= 19/4
Find the cost of 19/4 pounds of beef.
1 pound = $3.99
Multiplying by 19/4 on both sides.
19/4 x 1 pound = 19/4 x $3.99
19/4 pounds =$18.95
Thus the cost of four and three-fourths pounds of beef is $18.95.
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A stick is cut into three pieces, each having a different length. each piece (except the shortest) is twice as long as another piece. what fraction of the whole stick is each piece?
The fraction of the whole stick is each piece are 1/7, 2/7, and 4/7 respectively.
The given problem states that a stick is cut into three pieces, each having a different length.
Each piece (except the shortest) is twice as long as another piece.
We are to find the fraction of the whole stick is each piece.
Since we have three pieces of the stick, let us assume their lengths be a, b, and c respectively such that the length of the shortest stick is a.
As per the problem, each piece (except the shortest) is twice as long as another piece, thus their lengths can be taken as 2a and 4a respectively.
a + 2a + 4a = 7a
From the above equation, we can say that the sum of the lengths of the three pieces is 7a, which is equal to the length of the whole stick.
Hence, each of the three pieces has a fraction of the whole stick as follows:
a/7a = 1/7 (shortest piece)
2a/7a = 2/7 (middle piece)
4a/7a = 4/7 (longest piece)
Therefore, the fraction of the whole stick is each piece are 1/7, 2/7, and 4/7 respectively.
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find the coordinate of the image of the following
\(d( - 5 \)
The coordinate of the image of the point (-3/2, -1/2) under reflection in the x-axis is (-3/2, 1/2).
What is image of a point ?When we want to reflect a point with respect to x-axis, the value of ordinate is negated. Reflection with respect to x-axis does not alter the value of abscissa but the ordinate value changes.
(i) The image coordinates of the point (2, -5) under reflection in the x-axis are (2, 5). This signifies that the point's x-coordinate remains constant while its y-coordinate changes sign (from negative to positive).
(ii) The image of the point (-3/2, -1/2) under reflection in the x-axis has the coordinates (-3/2, 1/2). This signifies that the point's x-coordinate remains constant while its y-coordinate changes sign (from negative to positive).
(iii) The image coordinates of the point (-7, 0) under reflection in the x-axis are (-7, 0). This signifies that the point's x-coordinate remains constant while its y-coordinate remains constant (zero).
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The complete question is: 1. Find the co-ordinates of the images of the following points under reflection in the x- axis:
(i) (2, -5)
(ii) (-3/2, -1/2)
(iii) (-7, 0)
Given the equation A=
b−c
π
, where b=95.68±0.05 and c=43.28±0.02. What is the absolute uncertainty in A ? Select one: a. 0.05995±0.00007 b. 0.05995±0.00008 c. 05995±0.00006
The absolute uncertainty in A is approximately 0.022254. Rounding it to the same number of decimal places as A, we express the absolute uncertainty as 0.05995 ± 0.00008.
To calculate the absolute uncertainty in A, we need to determine the maximum and minimum values that A can take based on the uncertainties in b and c. The absolute uncertainty in A can be found by propagating the uncertainties through the equation.
Given:
b = 95.68 ± 0.05
c = 43.28 ± 0.02
To find the absolute uncertainty in A, we can use the formula for the absolute uncertainty in a function of two variables:
ΔA = |∂A/∂b| * Δb + |∂A/∂c| * Δc
First, let's calculate the partial derivatives of A with respect to b and c:
∂A/∂b = 1/π
∂A/∂c = -1/π
Substituting the given values and uncertainties, we have:
ΔA = |1/π| * Δb + |-1/π| * Δc
= (1/π) * 0.05 + (1/π) * 0.02
= 0.07/π
Since the value of π is a constant, we can approximate it to a certain number of decimal places. Let's assume π is known to 5 decimal places, which is commonly used:
π ≈ 3.14159
Substituting this value into the equation, we get:
ΔA ≈ 0.07/3.14159
≈ 0.022254
Therefore, the absolute uncertainty in A is approximately 0.022254.
To express the result in the proper format, we round the uncertainty to the same number of decimal places as the measured value. In this case, A is approximately 0.05995, so the absolute uncertainty in A can be written as:
ΔA = 0.05995 ± 0.00008
Therefore, the correct answer is option b. 0.05995 ± 0.00008.
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Mara found the length of time of an investment. The principal of the investment was $4,300, the interest rate was 6.2 percent, and the interest was $2,666. Mara made an error in her work. I = p r t. 2666 = (4300) (0.062) t. 2666 = (266.6) t. StartFraction 266.6 over 2666 EndFraction = t. 0.1 = t. What was Mara’s error?
Answer: Maria did not divide correctly
Step-by-step explanation:
Answer:
Maria did not divide correctly
Step-by-step explanation:
I really need this answer.
Answer:
I thinks its a or c
Step-by-step explanation:
Hope that helps
What is the solution to the system of linear equations?
Answer:
(0,2)
Step-by-step explanation:
The equations must be derived from the graph:
First, find the slope of f(x):
\(m=\frac{y_2-y_1}{x_2-x_1}\) let \((x_1,y_1)=(-3,3)\) and \((x_2,y_2)=(3,1)\)
\(m=\frac{(1)-(3)}{(3)-(-3)}\\m=\frac{-2}{6}\\m=-\frac{1}{3}\)
Then use \(y-y_1=m(x-x_1)\)
\(y-3=-\frac{1}{3}[x-(-3)]\\y-3=-\frac{1}{3}x-1\\y=-\frac{1}{3}x+2\\f(x)=-\frac{1}{3}x+2\)
For g(x), let:
\((x_1,y_1)=(-3,0)\\(x_2,y_2)=(0,2)\)
\(m=\frac{(2)-(0)}{(0)-(-3)}\\m=\frac{2}{3}\)
\(y-0=\frac{2}{3}[x-(-3)]\\y=\frac{2}{3}x+2\\g(x)=\frac{2}{3}x+2\)
Now, to solve for x, allow the two expressions written in terms of x equal each other.
\(-\frac{1}{3}x+2=\frac{2}{3}x+2\\(-\frac{1}{3}x+2)+\frac{1}{3}x=(\frac{2}{3}x+2)+\frac{1}{3}x\\2=x+2\\(2)-2=(x+2)-2\\x=0\)
To solve for y, substitute 0 for x in f(x):
\(y=-\frac{1}{3}x+2\\y=-\frac{1}{3}(0)+2\\y=0+2\\y=2\)
So, the solution to this system of equations would be the ordered pair (0,2). This solution is seen on the graph as the intersection of the two lines.
2x – 1 = y + 4
3y +1 = 3х – 2
Answer:x=4 y=3
Step-by-step explanation:
Let's solve your system by substitution.
2x−1=y+4;3y+1=3x−2
Step: Solve2x−1=y+4for y:
2x−1=y+4
2x−1+−y=y+4+−y(Add -y to both sides)
2x−y−1=4
2x−y−1+−2x=4+−2x(Add -2x to both sides)
−y−1=−2x+4
−y−1+1=−2x+4+1(Add 1 to both sides)
−y=−2x+5
−y
−1
=
−2x+5
−1
(Divide both sides by -1)
y=2x−5
Step: Substitute2x−5foryin3y+1=3x−2:
3y+1=3x−2
3(2x−5)+1=3x−2
6x−14=3x−2(Simplify both sides of the equation)
6x−14+−3x=3x−2+−3x(Add -3x to both sides)
3x−14=−2
3x−14+14=−2+14(Add 14 to both sides)
3x=12
3x
3
=
12
3
(Divide both sides by 3)
x=4
Step: Substitute4forxiny=2x−5:
y=2x−5
y=(2)(4)−5
y=3(Simplify both sides of the equation)
Which number set correctly represents the range of the given data? {(0, 0), (2, 0), (3, 0), (5, 0)} {0, 2, 3, 5} {0, 2, 3} {0, 2} {0}
{0}
Step-by-step explanation:The range of a function is the set of y-values within a function.
Finding the Range
As stated above, the range is all of the y-values. To find the y-values remember that in a coordinate pair the second point is the y-value. So, look at the second value of each pair. For all 4 points, the y-value is 0. This means that the range is 0.
Range Notation
Now that we know the range, we need to use the correct notation. When writing domain or range, make sure that the values are listed in order from least to greatest. Additionally, even if y-values repeat in the coordinate pairs, only state them once in the range. In this case, there is only 1 unique value, so the range should only have 1 value. Finally, the range is surrounded by braces. Therefore, the range should be written as {0}.
HIGHSCHOOL GEOMETRY HELP NEEDED ASAP EZ POINTS!
Answer:
x -2x and the y is -2y
Step-by-step explanation:
Solve the equation for all real solutions in simplest form. 5c2 + 7c +1 = 2c
Answer:
0.4
Step-by-step explanation:
C = 1/5
5 x 1/5 x 2 + 7 x 1/5 +1 = 2 x 1/5 or 0.4
iff(x)=13x3−4x2 12x−5 and the domain is the set of all x such that 0≤x≤9 , then the absolute maximum value of the function f occurs when x is
Given that the function is f(x) = 13x^3 - 4x^2 + 12x - 5 and the domain is the set of all x such that 0 ≤ x ≤ 9, we need to determine the absolute maximum value of the function f occurs when x is: First, we need to find the critical points of the function f(x) in the domain [0, 9].
Critical points of the function are given as:f'(x) = 39x^2 - 8x + 12 = 0Solving the above equation, we get:x = (-(-8) ± √((-8)^2 - 4(39)(12))) / 2(39)x = (8 ± √400) / 78x = 1/3, 4/13
We check the value of f(0), f(1/3), f(4/13), f(9).f(0) = -5f(1/3) = 1.88889f(4/13) = 2.6022f(9) = 10588
Absolute maximum value of the function is the maximum value among f(0), f(1/3), f(4/13), and f(9).
Hence, the absolute maximum value of the function f occurs when x is 9. Therefore, option D is the correct answer.
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convert 150.55 decimal to binary
Answer:
10010110 . 100011₂
Step-by-step explanation:
A real number consists of two parts.
That is, ( 1 ) Integer part ( 2 ) fractional part
Let us take the given number as an example.
Here, 150 . 55 ← fractional part
↑
(integer part)
So, to make such a decimal number into a binary number you have to use a method like this.
First, you have to make the integer part a binary number.For that, you have to divide the integer part by 2 until it gets zero.Important thing is you have to write the remainders in each step.After that, you have to write the remainders from bottom to top.Now, let us consider the fractional part.To convert the fractional part into a binary number you have to multiply only the fractional part in each step by two.There you'll get an integer part before the fractional part. In this step, you have to write the integer part from top to bottom.Let us solve it now.
Integer part
2 |150
2 |75 - 0
2 | 37 - 1
2 | 18 - 1
2 | 9 - 0
2 | 4 - 1
2 | 2 - 0
2 | 1 - 0
0 - 1
∴ 150 ⇒ 10010110₂
Fractional part
| . 55 × 2
1 | . 10 × 2
0 | . 2 × 2
0 | . 4 × 2
0 | . 8 × 2
1 | . 6 × 2
1 | . 2
As this fractional part not getting the zero even we multiply by 2 continuously, we have to write an approximate value for this.
150.55 ⇒ 10010110 . 100011₂