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The complex ion geometry that has the potential to exhibit cis-trans isomerism is octahedral geometry.

Cis-trans isomerism refers to the phenomenon where two or more ligands in a coordination complex can occupy different positions around a central metal ion, resulting in distinct spatial arrangements.

In the context of complex ion geometry, cis refers to ligands located adjacent to each other on the same side of the coordination complex, while trans refers to ligands located opposite to each other across the coordination complex.

Octahedral geometry is a common coordination geometry for complex ions where the central metal ion is surrounded by six ligands, forming an octahedron shape. In an octahedral complex, there are three possible arrangements of ligands: cis-cis, cis-trans, and trans-trans.

The cis-cis arrangement occurs when two sets of ligands are located adjacent to each other on the same side of the octahedron, while the trans-trans arrangement occurs when two sets of ligands are located opposite to each other across the octahedron.

The cis-trans arrangement, as the name suggests, occurs when there is one set of ligands located adjacent to each other on one side of the octahedron and another set of ligands located opposite to each other on the other side.

The potential for cis-trans isomerism in octahedral complexes arises when the ligands attached to the central metal ion are different. This allows for different spatial arrangements of the ligands, leading to the possibility of cis and trans isomers.

It is important to note that not all octahedral complexes exhibit cis-trans isomerism, as it depends on the specific ligands and their arrangement around the central metal ion.

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1. The limiting reagent is sulfur trioxide, SO₃ and the excess reagent is water, H₂O

2. The mass of the excess reagent leftover is 14.92 g

3. The mass of sulfuric acid, H₂SO₄ is produced is 8.06 g

The limiting and excess reagent can be obtained as follow:

SO₃ + H₂O -> H₂SO₄

From the balanced equation above,

80 g of SO₃ reacted with 18 g of H₂O

Therefore,

6.58 g of SO₃ will react with = (6.58 × 18) / 80 = 1.48 g of H₂O

From the above calculation, we can see that only 1.48 g of H₂O out of 16.4 g is needed to react completely with 6.58 g SO₃.

Thus, the limiting reagent is SO₃ and the excess reagent is H₂O

The mass of the excess reagent leftover can be obtained as follow:

Mass of excess reagent, H₂O leftover = Mass given - mass reacted

Mass of excess reagent, H₂O leftover = 16.4 - 1.48

Mass of excess reagent, H₂O leftover = 14.92 g

The mass of H₂SO₄ produced can be obtained as illustrated below:

SO₃ + H₂O -> H₂SO₄

From the balanced equation above,

80 g of SO₃ reacted to produce 98 g of H₂SO₄

Therefore,

6.58 g of SO₃ will react to produce = (6.58 × 98) / 80 = 8.06 g of H₂SO₄

Thus, the mass of H₂SO₄ produced is 8.06 g

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Answer:

A. equation

B. atoms

C. products

Explanation:

Answer:

A

A chemical equation shows both the reactants and the products of a chemical equation

Answer:

Boron

Explanation:

You can find this by looking at the number of protons in Boron, 5.

Then calculate how many electrons you are given, in this case the 2 core plus the 3 valence equal 5 total electrons

Neutral elements have the same number of protons and electrons, so your answer would be the element with 5 electrons, Boron.

You can also know this by using electron configuration. Since you kow there are 5 electrons then you can use EC to find out where your element is. In this case it is: 1s2 2s2 2p1

For the rocket engine a lean or excessively rich air-fuel ratio will lead to a compromise in the power output and ultimately the altitude the rocket will reach. Hence which ever the ratio the altitude is greatly affected, unless the ideal ratio is archived.

The air-fuel ratio is the ratio of the amount of air need to burn a part of fuel in a combustion cycle, the ratio is basically a compromise between fuel economy and  optimum power output.

For a gasoline engine for example, the ideal air-fuel mixture of 14.7 parts air to 1 part fuel.

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Answer:

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Answer:

1.03 × 10¹

Explanation:

The decimal point is after the first non-zero digit number. The decimal or the number is multiplied by a 10 with an exponent.

Answer:

the volume that the gas occupy at 7.47 atm is  0.1564 liters

Explanation:

The computation of the volume that the gas occupy at 7.47 atm is shown below:

As we know that

P1V1 = P2V2

Now

V2 = P1V1 ÷ P2

= 2.05 atm × 0.570 liters ÷ 7.47 atm

= 0.1564 liters

Hence, the volume that the gas occupy at 7.47 atm is  0.1564 liters

So the same would be considered and relevant

Answer:

10^-7.20 or 1×10^-7.20mol.dm^-3

Explanation:

[H3O^+]= -log[H3O^+]

=antilog(-pH)

=antilog(-7.20)

=10^-7.20 mol.dm^-3

Answer:

1.58 x 10^-7 M

Explanation:

Answer:

4.7 Liters of NO2

Explanation:

mole weight of HNO3  (from periodic table) = ~~ 63 gm/mole

  12 grams of this is   12/63 = .19047 mole

From the equation, you should be able to see that 3 moles of NO2 produces 2 moles of HNO3

  so you need  3/2 * moles HNO3 = .2857 moles of NO2 needed

PV = nR T     n = moles   R = .082057 L-atm/(k-mole)    25 C = 298.15 K

1.6 (V) = .2857 (.082057)(298.15)

  solve for V = 4.37 liters of NO2

Answer:

3.22

Explanation:

The pOH is defined as:

pOH = - log [OH⁻]

From the problem, we have [OH⁻] = 6.0 x 10⁻⁴.

Thus, we introduce the concentration in the equation to calculate the pOH:

pOH = - log [OH⁻] = -log (6.0 x 10⁻⁴) = 3.22

The heat of formation of nitrogen (II) oxide : +91.3 kJ/mol

Given

Reaction

N2(g) + O2(g) + 182.6 kJ → 2 NO(g)

Required

The heat of formation

Solution

In the above reaction, the heat of the reaction is located on the reactant side which indicates that the formation of nitric oxide requires heat (endothermic reaction).

In the above reaction the heat required to form 2 moles of NO, so the heat required for each mole is:

+182.6 kJ : 2 = =+91.3 kJ/mol

O-linked oligosaccharides are commonly attached to the —oh group of amino acids.

Glycosylation is a post-translational modification of proteins in which glyco-linked oligosaccharides are added to proteins. This process is found in eukaryotes, primarily in the endoplasmic reticulum and Golgi apparatus, and involves the enzymatic attachment of sugar units to specific sites on a protein molecule.

These short chains of saccharide sugar residues, called glycosyl sidechains, are examples of glycoconjugates which are covalently attached to hydroxyl groups on the protein.

The most common types of glycosylation sites are the N-linked glycosylation sites, which have an attached sugar group, often an N-acetylglucosamine or N-acetylmannosamine connected to an asparagine sidechain, and the O-linked glycosylation sites, which have a sugar group, usually a galactose or mannose sugar, attached to a hydroxyl group on serine, threonine or hydroxylysine residues.

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The electrolysis of the water is often done with the small amount of the sulfuric acid that is added to the water. The role of the sulfuric acid, H₂SO₄ is to increase the conductance.

The sulfuric acid, with the formula H₂SO₄ is the strong acid and the H₂SO₄ will completely dissociate in to the ions. During the electrolysis of the water, add the sulfuric acid, the number of the ions of the H₂SO₄ will increases and the because of increasing of these ions, the solution conductance increases.

The electrolysis of water is the process by using the electricity to split the water into the hydrogen and the oxygen. The reaction will takes place in the unit and called as an electrolyzer.

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The work done (in J) in compressing a gas at constant temperature is calculated using the formula: W = -PΔV, where W is work done, P is the external pressure and ΔV is the change in volume.

Here, ΔV = Vf - Vi = 2.95 L - 6.63 L = -3.68 L [negative sign because of compression] and P = 735 torr. First, we need to convert the pressure to atm (1 atm = 760 torr):735 torr / 760 torr/atm = 0.967 atm Now, substituting these values in the above formula, we get: W = -(0.967 atm)(-3.68 L) = 3.55256 L atm Converting L atm to J (1 L atm = 101.3 J):W = (3.55256 L atm)(101.3 J/L atm) = 359.52 J

Therefore, the work done in compressing the gas at constant temperature from a volume of 6.63 L to a volume of 2.95 liters by an external pressure of 735 torr is 359.52 J.

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Answer:

the order in which orbitals 4f,5p,5d,and 6s are filled is clacium.

Answer:

covalent bonds............

covalent bonds

Ionic bonds structure when a nonmetal and a steel alternate electrons, while covalent bonds form when electrons are shared between two nonmetals. An ionic bond is a type of chemical bond formed through an electrostatic enchantment between two oppositely charged ions.

The reason for the delay in the EPA proposing greenhouse gas emission limits to Congress in 2013 was a combination of various factors.

Environmental groups had long been advocating for the reduction of greenhouse gases, recognizing their impact on climate change. However, several factors contributed to the delay in the EPA's proposal. One key factor was the complexity of addressing greenhouse gas emissions and developing effective regulations. The EPA needed to gather substantial scientific data and conduct a thorough analysis to determine appropriate emission limits that would have meaningful environmental benefits while considering economic implications.

Another factor was the political landscape and differing opinions on climate change and environmental regulations. The issue of greenhouse gas emissions became highly politicized, leading to debates and disagreements among policymakers and stakeholders. This political polarization hindered the progress in proposing emission limits and slowed down the decision-making process.

Additionally, there were legal challenges and regulatory hurdles that further delayed the EPA's action. The agency had to navigate through legal requirements, potential lawsuits, and stakeholder consultations, which added to the overall time-consuming process.

Despite these challenges, the EPA's proposal in 2013 marked a significant step forward in addressing greenhouse gas emissions on a national level, signaling a commitment to mitigating climate change impacts and protecting the environment.

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Answer:

a jagged black line along the right side of the table separates the metals from the nonmetals. The metals are to the left of the line, the nonmetals are to the right of the line, and the elements immediately next to the line are the metalloids.

Explanation:

The electronic configuration helps to determine if the element is a metal or non-metal.

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.

Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.

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The probability that the batch actually has a chemical defect is 16%. Therefore, option (a) 16% is the correct answer.

To solve this problem, we can use Bayes' theorem. Let's denote the following events:

A: The batch has a chemical defect.

B: The test result is positive for the defect.

We want to find the probability of event A given event B, denoted as P(A|B).

According to the problem statement, we have the following probabilities:

P(A) = 0.02 (2% of the batches have the defect)

P(B|A) = 0.9 (90% of the tests detect the defect, true positive rate)

P(not A) = 1 - P(A) = 0.98 (98% of the batches do not have the defect)

P(B|not A) = 0.096 (9.6% of the tests are false positives, false positive rate)

Now, let's calculate P(A|B) using Bayes' theorem:

P(A|B) = (P(B|A) * P(A)) / (P(B|A) * P(A) + P(B|not A) * P(not A))

P(A|B) = (0.9 * 0.02) / (0.9 * 0.02 + 0.096 * 0.98)

      = 0.018 / (0.018 + 0.09408)

      ≈ 0.018 / 0.11208

      ≈ 0.1606

Therefore, the odds that the batch actually has the chemical defect, given a positive defect result, is approximately 16.06%. Rounding this to the nearest percent, we get the option (a) 16%.

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Answer:

Hartwell's yeast

Explanation: A model organism for studying somatic mutations and cancer."

Treatment of DCS may involve Recompression in a hyperbaric chamber.

Hence, Option (3) is correct answer.

DCS is Decompression Sickness which is followed by recompression in a hyperbaric chamber. They prevent long term effects.  It is also known as generalized barotrauma. It occur mostly in Scuba divers.

The sign and symptoms of DCS are

Thus from the above conclusion we can say that Treatment of DCS may involve Recompression in a hyperbaric chamber.

Hence, Option (3) is correct answer.

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Answer: 0.79

Explanation:

Answer: 0.79

Explanation:

Answer:

a substance capable of becoming superconducting at sufficiently low temperatures.

Explanation:

Answer:

Superconductivity is a set of physical properties observed in certain materials where electrical resistance vanishes and magnetic flux fields are expelled from the material. Any material exhibiting these properties is a superconductor.

Explanation:

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Answer: plastic

Explanation:

The thermal conductivity of a material is highly depending on composition and structure. Generally speaking dense material such as medals and stone are good conductors of heat while load density substances such as gas and porous installations are poor conductors of heat

Answer:

Or plastic

Explanation:

May be useful................

Answer:

When the number of particles, though in this case I think you mean (electrons), changes in an atom....it become an ion. Ions are atoms that were chnaged by losing or gaining an electron. If an atom gains an electron  it will have a negative charge. If an atom loses an electron it will have a positive charge. Hope this was helpful!!

Explanation:

Answer:

Ca(NO3)2

           .................

Ca(NO3)2 is a possible compound formed from Ca²+ and NO3-¹.

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Explanation:

P×V=n×R×T

L×atm / mol×K

n= PV /RT

Description:

So as we know that our Known variables: are P, V, R, T and our unknown variables are n. N= PV / RV. = 6.02 moles.

Answer: 6.02  moles

Hope this helps.

The moles of nitrogen gas present in 135 L at STP have been 6.02 moles.

The nitrogen gas has been assumed to be the ideal gas. For an ideal gas, at STP or standard pressure and temperature, the volume of 1mole of gas has been 22.4 L.

The STP conditions have been 273.15 K temperature, and 1 atm pressure.

Since, moles in 22.4 L gas been 1 mole. The moles in 135 L gas has been:

22.4 L = 1 mole

135 L = \(\rm \dfrac{1}{22.4}\;\times\;135\;moles\)

135 L gas = 6.02 moles.

The moles of nitrogen gas present in 135 L at STP have been 6.02 moles.

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