Question 9 of 16
What is the reactant(s) in the chemical equation below?

3CO(g)+Fe₂ O₃(s) → 2 {Fe}(s)+3CO₂(g)

A. Fe₂ O₃(s)
B. 2 Fe(s)+3CO₂(g)
C. 2 Fe(s)
D. 3 CO(g)+Fe₂ O₃(s)

The mass of nitrogen, N₂ that contains 1.81×10²³ molecules is 8.42 g

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole of nitrogen, N₂

But

1 mole of nitrogen, N₂ = 28.02 g

Thus,

6.02×10²³ molecules = 28.02 g of nitrogen, N₂

With the above information, we can obtain the mass of nitrogen, N₂ that contains 1.81×10²³ molecules as follow:

6.02×10²³ molecules = 28.02 g of nitrogen, N₂

Therefore,

1.81×10²³ molecules = (1.81×10²³ × 28.02) / 6.02×10²³

1.81×10²³ molecules = 8.42 g of nitrogen, N₂

Thus, we can conclude that the mass of nitrogen, N₂ is 8.42 g

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The event which is most likely occurring in this scenario is effusion because there is a movement of a gas through a small opening into a larger volume and is denoted as option C.

This is referred to as the process in which a gas or a substance escapes from a container through a hole of diameter which is usually smaller.

The type of event which is most likely occurring is effusion because of the presence of the small holes in which the balls are made to pass through the center which is why option C was chosen.

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The options are:

When dissolved in water, most Group 1 metal salts can be described as strong electrolytes.

When Group 1 metal salts are dissolved in water, they can be described as strong electrolytes. This is because Group 1 metals, such as lithium (Li), sodium (Na), potassium (K), and so on, readily lose their outermost valence electron to form positive ions (cations). These cations then dissociate completely in water, separating from the anions to which they were originally bonded.

The dissociation of Group 1 metal salts in water results in the formation of positively charged metal ions and negatively charged non-metal ions (anions). These ions are free to move and conduct electric current, making the solution a good conductor of electricity. The complete dissociation of Group 1 metal salts in water and the presence of freely moving ions make them strong electrolytes.

Strong electrolytes are substances that ionize completely or almost completely in solution, producing a high concentration of ions. This is in contrast to weak electrolytes, which only partially ionize and produce a lower concentration of ions.

In summary, when Group 1 metal salts are dissolved in water, they form strong electrolytes due to their ability to dissociate completely into ions, leading to a high concentration of freely moving ions in the solution, thus enabling efficient electrical conductivity.

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Answer:

1.80 g (grams) of glucose.

Explanation:

First, we dissolve 20.0 g of glucose in a volume of water of 100 mL (0.1 L), so let's calculate the concentration of glucose in g/L, like this:

Now, we take 45 mL (0.045 L) of this solution that contains a concentration of glucose of 200 g/L to create a new solution with 0.500 L.

From this new solution, we have to find the mass of glucose if we took 100 mL (0.1 L) of this solution, so we have to use the following equation:

Where C is concentration, V is volume, and subindex 1 and 2 indicate the initial solution, which in this case, is C1 = 200 g/L, V1 = 0.045 L, and the final solution with unknown concentration (C2) and a volume of V2 = 0.500 L.

Let's solve for C2 and replace the given data to obtain the new concentration (final concentration) of the new solution of 0.500 L, like this:

The final concentration of glucose in 0.500 L would be 18.0 g/L.

The next and final step is to calculate the total mass using the volume that we took from the 0.500 L solution, which is 100.0 mL (0.1 L). To do this, we have to do a dimensional analysis to obtain the answer in units of grams, so the calculation will look like this:

The answer would be that we have 1.80 g (grams) of glucose in 100 mL from the 0.500 L solution.

Answer: the answer is C

Explanation:

Ocean water contains dissolved salts, like halite and gypsum. The correct option is C.

The ocean is the salty water that covers an area of 70.08% of the total surface. It is a large body of water that covers the entire earth. There are seven oceans present with different names, and they are connected with each other. The ocean is one of the traveling routes for traveling and exporting and import of products.

The average salinity of the ocean is 3.5%. It contains salts, halite, and gypsum-like minerals and substances.

Thus, the correct option is C. contains dissolved salts, like halite and gypsum.

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The wavelength of the radiation emitted by the argon ion laser is \(4.854 * 10^-7 m\).

Wavelength is a property of any type of wave that refers to the distance between two adjacent points on the wave that is in phase, i.e., at the same point in their respective cycles. It is usually denoted by the Greek letter lambda (λ) and is measured in units of length, such as meters or nanometers.

The energy carried by the photon (E) is related to the wavelength (\(\lambda\)) through the following equation:

\(E=hc/\lambda\); where 'h' is the Plank's Constant and 'c' is the speed of light which is \(3* 10^{-7} m/s\).

We can say that

\(\lambda - hc/E\)

Now after substituting the given values, we get:

\(\lambda = (6.626 * 10^{-34} J.s * 3.00 * 10^8 m/s) / (4.071 * 10^{-19} J)\\\lambda = 4.854 * 10^-7 m\)

Therefore the wavelength of the radiation emitted by the argon ion laser is \(4.854 * 10^-7 m\).

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Answer:

The density of the liquid is \(808\ kg/m^3\).

Explanation:

It is given that,

The density of liquid is 0.808 g/cm³

We need to convert the density into kg/m³

We know that,

1 kg = 1000 g

And 1 m = 100 cm

So,

\(d=0.808\ \dfrac{g}{cm^3}\\\\=0.808 \dfrac{(1/1000)\ kg}{(1//100\ cm)^3}\\\\d=808\ kg/m^3\)

So, the density of the liquid is \(808\ kg/m^3\).

The density of the liquid nitrogen in Kg/m³ is 808 Kg/m³

From the question given above, the following data were obtained:

Density (g/cm³) = 0.808 g/cm³

1 g/cm³ = 0.001 Kg/cm³

Therefore,

0.808 g/cm³ = 0.808 × 0.001

1 Kg/cm³ = 10⁶ Kg/m³

Therefore,

0.000808 Kg/cm³ = 0.000808 × 10⁶

Thus, 0.808 g/cm³ is equivalent to 808 Kg/m³

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Answer:

This apparent change in the pitch (or frequency) of sound is called Doppler shift. ... You see these stretched-out light waves as having a lower frequency. Since red is at the low-frequency end of the visible spectrum, we say that light from a receding star is shifted toward red, or red shifted.

Explanation:

Answer:

\(Molarity\,\,of\,\,the\,\,solution\,\,is\,\,S=0.039M\)

Explanation:

\(W=2.18 g\\M=322g\\V=175mL=0.175L\\\\S=\frac{W}{MV} \\=>S=\frac{2.18}{322*0.175} \\So,S=0.039M\)

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B < Na < Al < K

The size of elements in the periodic table increases from right to left and top to bottom down the group.

For the given question, we will arrange the elements based on atomic size.

For the given elements

• Aluminum has an atomic number of 13

• Boron has an atomic number of 5

• Potassium has an atomic number of 19

• Sodium has an atomic number of 11.

The increasing size will be based on their increasing atomic number and position in the periodic table.

The required increasing size will be B < Na < Al < K

0.0956 grams of helium will occupy a volume of 575 mL at 760 mmHg and 20°C

To calculate the mass of helium that will occupy a given volume at a specific temperature and pressure, we need to use the ideal gas law equation: PV = nRT. Here's how you can solve the problem:

Convert the volume to liters: 575 mL = 575/1000 = 0.575 L.

Convert the pressure to atmospheres: 760 mmHg = 760/760 = 1 atm.

Convert the temperature to Kelvin: 20°C = 20 + 273.15 = 293.15 K.

Plug the values into the ideal gas law equation: (1 atm) * (0.575 L) = n * (0.0821 L·atm/(mol·K)) * (293.15 K).

Rearrange the equation to solve for n (the number of moles): n = (1 atm * 0.575 L) / (0.0821 L·atm/(mol·K) * 293.15 K).

Calculate the value of n: n = 0.0239 moles.

To find the mass, we need to know the molar mass of helium, which is approximately 4 grams per mole.

Multiply the molar mass by the number of moles: 4 g/mol * 0.0239 moles = 0.0956 grams.

Therefore, approximately 0.0956 grams of helium will occupy a volume of 575 mL at 760 mmHg and 20°C.

Note: The ideal gas law assumes ideal gas behavior, and the calculated result may not be accurate under extreme conditions or for gases that deviate significantly from ideal behavior.

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Explanation:

the otion correct is H2S

Considering the definition of percent yield, the percent yield is 76%.

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

\(percent yield=\frac{actual yield}{theorical yield}x100\)

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

In this case, you know:

Replacing in the definition of percent yield:

\(percent yield=\frac{0.532 moles}{0.700 moles}x100\)

Solving:

percent yield= 76%

Finally, the percent yield is 76%.

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The number of moles of C₃H₈ that must be consumed via the given reaction is 0.168 mole

We'll begin by obtaining the mole of CO₂ produced. Details below:

PV = nRT

3.68 × 4 = n × 0.0821 × 355

Divide both sides by (0.0821 × 355)

n = (3.68 × 4) / (0.0821 × 355)

n = 0.505 mole

Finally, we shall determine the mole of C₃H₈ consumed by the reaction. This is illustrated below:

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

From the balanced equation above,

3 moles of CO₂ were obtained from 1 mole of C₃H₈

Therefore,

0.505 mole of CO₂ will be obtained from = (0.505 × 1) / 3 = 0.168 mole of C₃H₈

Thus, number of mole of C₃H₈ consumed is 0.168 mole

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Answer:

A. Alternating single and double bonds

Explanation:

Hydrocarbons i.e. hydrogen and carbon containing compounds, are grouped into two namely: aliphatic and aromatic hydrocarbons. Aliphatic hydrocarbons contains straight or branched chains of carbon and hydrogen atoms in their structure e.g. alkanes, alkenes etc.

On the other hand, aromatic hydrocarbons are cyclic hydrocarbons containing one or more cyclic rings. The benzene ring is the basis of all aromatic hydrocarbons and one characteristics of benzene is that it possesses an alternating single (-) and double bonds (=) in their structure.

Since benzene is a building constituent of aromatic hydrocarbons, an "alternating single and double bond" is a characteristics of aromatic hydrocarbons.

Answer:

The total energy absorbed is 32.171 kilojoules.

Explanation:

The total energy absorbed by the ice is the sum of the sensible heat of ice and water and the latent heat of fusion of the water, that is:

\(Q = m\cdot [c_{i}\cdot (T_{2}-T_{1})+L_{f} + c_{w}\cdot (T_{3}-T_{2})]\) (1)

Where:

\(m\) - Mass of the ice, in kilograms.

\(c_{i}\) - Specific heat of ice, in kilojoules per kilogram-degree Celsius.

\(c_{w}\) - Specific heat of water, in kilojoules per kilogram-degree Celsius.

\(L_{f}\) - Latent heat of fusion, in kilojoules per degree Celsius.

\(T_{1}\) - Initial temperature of water, in degrees Celsius.

\(T_{2}\) - Fusion point of water, in degrees Celsius.

\(T_{3}\) - Final temperature of water, in degree Celsius.

\(Q\) - Total energy absorbed, in kilojoules.

If we know that \(m = 50.5\times 10^{-3}\,kg\), \(c_{i} = 2.090 \,\frac{kJ}{kg\cdot^{\circ}C}\), \(c_{w} = 4.180\,\frac{J}{kg\cdot ^{\circ}C}\), \(L_{f} = 334\,\frac{kJ}{kg}\), \(T_{1} = -15\,^{\circ}C\), \(T_{2} = 0\,^{\circ}C\) and \(T_{3} = 65\,^{\circ}C\), then the total energy absorbed is:

\(Q= (50.5\times 10^{-3}\,kg)\cdot \left[\left(2.090\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (15\,^{\circ}C) + 334\,\frac{kJ}{kg}+ \left(4.180\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (65\,^{\circ}C)\right]\)\(Q = 32.171\,kJ\)

The total energy absorbed is 32.171 kilojoules.

Answer:

B i think

Explanation:

Answer:When a single compound breaks down into two or more compounds or elements in a chemical reaction then it is known as decomposition reaction.

The chemical symbol for sodium carbonate is .

The decomposition of sodium carbonate is:

The decomposition of sodium bicarbonate,  will result in the formation of sodium oxide,  and carbon dioxide, .

Hence, carbon dioxide,  will produce with sodium oxide,  on decomposition of .

Explanation:Na2CO3 Na2O +CO2   CO2 is the answer

The correct answer is "C.

The type of exercise that Mei is doing is the "Machine exercise."

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Taking into account the definition of entropy, the entropy increases (option B).

Entropy can be interpreted as a measure of the random distribution of a system. In other words, the entropy S is a state function that measures the degree of molecular disorder of systems.

In this way, the change in entropy shows the change in molecular order that occurs in a chemical reaction. If the increase in entropy is positive, the products have a higher molecular disorder (higher entropy) than the reactants. On the other hand, when the increase is negative, the products are more ordered.

So, the entropy increases in the reaction if the total number of product molecules are greater than the total number of reactant molecules.

In this case, there are 12 moles of gaseous product, and 11 moles of gaseous reactant in the equation. This is, there are more moles in the products than in the reactants.

Therefore, the entropy increases (option B).

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Answer: 0.725g

Explanation: mass = (5.83*10^21/6.02214076*10^23)*74.92 g = 0.725 g

Answer:

0.583 kilojoules

Explanation:

The amount of heat required to pop a single kernel can be calculated using the formula as follows:

Q = m × c × ∆T

Where;

Q = amount of heat (J)

m = mass of water (g)

c = specific heat capacity of water (4.184 J/g°C)

∆T = change in temperature

From the given information, m = 0.905 g, initial temperature (room temperature) = 21°C , final temperature = 175°C, Q = ?

Q = m × c × ∆T

Q = 0.905 × 4.184 × (175°C - 21°C)

Q = 3.786 × 154

Q = 583.044 Joules

In kilojoules i.e. we divide by 1000, the amount of heat is:

= 583.04/1000

= 0.583 kilojoules

The IUPAC name for the compound given in the question is 2,3-dibromo-5-methylheptane

The IUPAC name for compound can be obtained by using the following steps:

Thus, the IUPAC name for the compound is: 2,3-dibromo-5-methylheptane

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There are differences in the observed solubility of calcium iodate (Ca(IO3)2) in different types of solvent due to its unique composition.

There differences in the observed solubility of Ca(IO3)2 into each of these solvents because calcium iodate (Ca(IO3)2) is not soluble in all types of solvent. In some solvents, it is fully soluble whereas in other solvents it is insoluble or slightly soluble.

For example, calcium iodate (Ca(IO3)2) is soluble in nitric acid but insoluble in alcohol due to its unique structure and composition so we can conclude that there are differences in the observed solubility of calcium iodate (Ca(IO3)2) in different types of solvent due to its unique composition.

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Answer:

no animals have cells

Explanation:

cells are a theory made up by old scientists

The compound to have a dipole moment, the correct statement about the dipole moment is 4) The molecule has no dipole moment.

The molecule is  CF₄, carbon tetrafluoride. The bond between the C - F is the polar covalent bond because of the greater electronegativity difference between the C and the F atoms. Even though it has no dipole moment because of the geometry that is tetrahedral geometry. The all the C - F bonds are arrange in  such a manner that the dipole moment will cancel out each other.

Thus, the  CF₄ molecule has no dipole moment. The molecule is the non - polar molecule.

This question is in complete , the complete question is :

Would you expect the following compound to have a dipole moment? if the molecule has a dipole moment, specify its direction. select the single best answer.           CF₄

1) The dipole moment is oriented from the fluorine atom towards the carbon atom.

2)  The dipole moment is oriented from the carbon atom towards the fluorine atom.

3) The orientation cannot be determined.

4) The molecule has no dipole moment.

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