QUESTION 7
Which of the following statements is true regarding the keyword search feature in TIS?
Select the correct option and click NEXT.
O Finds results based on the documents that other users have found helpful
O Can only be used in conjunction with Service Category and Section
O Can only be used in conjunction with vehicle model and year
Finds the word or phase you're searching for plus alternate spellings and synonym
Which of the following statements is true regarding the keyword search in TIS

The numerical values for the mesh currents that we have in the question are given as:

We first have to write the KVL

2 - 1(i₁ - i₂) + 3 - 5(i₁ - i₃) = 0

We have to expand the equation that we have above

2 - i₁ + i₂ + 3 - 5i₁ + 5i₃ = 0

take like terms

-i₁ - 5i₁  i₂ + 5i₃ = 5

=  6i₁ - i₂ - 5i₃ = 5

-1(i₂ - i₁) - 6 i₂ - 9(i₃ - i2) = 0

after expanding we would have

i₁ - 16i₂ + 9i₃ = 0------- equation 2

-5 (i3 - i1) - 3 - 9(i3 - i2) - 7i3 = 0

5i1 + 9i2 - 2i3 = 3 ------ equation 3

From the equations that we have in 1, 2 and 3, we would solve the system of equations to get

1i = 0.9892 = 0.9892 ampere

i2 = 0.1501 ampere

i3 = 0.1570 ampere

These are the mesh current that are in the labeled diagram.

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When it comes to combining multiple documents, an important word processing skill to know that ensures the final result is organized and easy to use is pagination.

Pagination is a page numbering technique that is done sequentially. These page numbers are usually located at the top or bottom of the web page. In most cases, it is used for main pages and partitions in corporate websites. This kind of design can generally make the user experience simpler on the site. They can also feel more comfortable when it comes to distributing and navigating products within the website.

For example, like this, imagine an e-commerce site that consists of hundreds of product catalogs from various categories. Of course, these products will not be found easily if only placed on one page. As a solution, UI developers and designers can take advantage of pagination to make product placement more structured.

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Answer:

The answer is D

Explanation:

The characteristic of an application is it helps the user perform an activity they want to do. The correct option is D.

An application program is a computer program that is designed to perform a specific activity that is not related to the operation of the computer itself and is typically utilized by end users. Examples include word processors, media players, and accounting software.

The different types of applications: are web, native, cross-platform, hybrid, etc. Scalability, portability, robustness, and agility are four fundamental features and functionalities that modern applications must have. Scalability: Today, we require apps that can scale to millions of people worldwide on demand.

Therefore, the correct option is D, it helps the user perform an activity they want to do.

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True is the answer.....

Answer:

Information

Explanation:

A student who wants to work with computers but does not have a strong aptitude for math might find a good fit by persuing a(n) Information systems degree.

The 'marking menu' opened up ways for me to access the most commonly used commands and tools with a flick of the wrist. What's more impressive is that its dependent on workspace, so you can use it in all parts of the design!

HOPE IT HELPS:)

PLS FOLLOW:)

#BRAINLIEST:)

As aircraft engines became more powerful and pilots became more skilled, the structural integrity of the aircraft became the limiting factor in aviation advances. Here's a detailed explanation:

1. Engine Power: With the advancement of technology, aircraft engines have become more powerful, providing increased thrust and improved performance. More powerful engines allow for higher speeds, greater altitude capabilities, and improved maneuverability. As a result, the focus shifted from engine power limitations to other factors that could restrict further advancements.

2. Pilot Skills: As pilots gained more experience and expertise, they became capable of pushing the boundaries of aircraft performance. Skilled pilots were able to extract the maximum potential from the engines and maneuver the aircraft in more demanding flight regimes. However, this increased capability also highlighted the importance of aircraft structural integrity in handling the stresses and loads associated with high-speed flight, tight maneuvers, and increased forces.

3. Structural Limitations: The structural integrity of an aircraft refers to its ability to withstand the various forces and stresses encountered during flight. These forces include aerodynamic loads, such as lift, drag, and the loads resulting from maneuvers, turbulence, and high-speed flight. As aircraft engines became more powerful and pilots pushed the limits of performance, the structural components of the aircraft, including the airframe, wings, fuselage, and control surfaces, needed to be robust enough to handle these increased forces.

4. Material Strength and Design: To overcome the limitations of structural integrity, advancements in materials science and aircraft design became crucial. Stronger and lighter materials, such as advanced alloys, composites, and carbon fiber reinforced polymers, were developed to enhance the structural strength while reducing weight. Innovative design techniques, including computer-aided design (CAD) and finite element analysis (FEA), allowed for more efficient distribution of stresses and optimized structural configurations.

5. Safety and Certification: Ensuring the structural integrity of aircraft became a critical aspect of aviation safety. Regulatory bodies and certification agencies imposed strict standards and requirements to ensure that aircraft designs met the necessary safety criteria. Extensive testing, including stress testing, fatigue analysis, and load simulations, became necessary to obtain airworthiness certifications.

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By using a histogram to check for normality, you contrast the histogram of the data set with the normal probability curve. You can presume that the data set is regularly distributed if the histogram is roughly bell-shaped.

The magic number, or the 95% probability mass in a normal distribution, is 1.96. This means that 95% of the probability mass falls within 1.96 standard deviations on each side of it.

For a number of reasons, we transform normal distributions into the standard normal distribution. to determine the likelihood that a distribution's observations will fall above or below a certain value.

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The electrode from which electrons are taken acquires a positive charge, whereas the electrode from which they are supplied acquires a negative charge and an excess of electrons.

decreasing agent The electrode at which reduction takes place in any electrochemical cell (electrolytic or galvanic) is referred to as the cathode. The positive electrode, on the other hand, will draw anions, or negative ions, to it. As a result of its ability to take electrons from those negative ions or other species in the solution, this electrode acts as an oxidizing agent. The anode is the electrode in any electrochemical cell where oxidation takes place. The fact that anode, oxidation, and reduction all start with vowels whereas cathode, reduction, and other electrodes do not, makes it simple to remember which electrode is which.

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  ┌─[0]─┐

┌──┴──┐  │

│  q0  │  │

│      │  │

│  q1  │  │

└──┬──┘  │

  └─────┘

The finite-state automaton (FSA) has two states, q0 and q1. The initial state is q0, and the accepting state is q1. The transition is as follows:

From q0:

On input 0, remain in q0.

On input 1, transition to q1.

From q1:

On input 0 or 1, remain in q1.

The FSA recognizes binary strings that start with two or more 0s. If the input begins with 0, the machine stays in state q0 until it encounters a non-zero digit, at which point it transitions to state q1. Once in state q1, the machine will stay there regardless of subsequent inputs. Therefore, if the machine reaches state q1, it means that the input string started with two or more 0s.

The FSA effectively captures the requirement of recognizing binary strings that start with two or more 0s using two states and transitions based on the input symbols. It provides a clear visual representation of the machine's behavior, making it easier to understand and analyze its functionality.

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A chain fall locks it’s elevated load is place using an automatic brake.

A chain fall locks it’s elevated load is place using an automatic brake.

Automatic emergency braking (AEB) is a safety feature that may detect when a collision is likely to happen and automatically apply the brakes to either slow down the vehicle before impact or stop it altogether to prevent a collision.

Additionally, it found that injuries from these incidents decreased by 56%. Reverse automated braking systems have been associated with a 78% reduction in crashes when compared to vehicles that merely have a reverse camera.

In general, automatic emergency braking is intended to engage at highway speeds, provided the front collision warning sensors can identify the car in front of them. In towns, newer systems operate at slower rates.

Thus, an automatic brake.

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The area of the gutter is therefore equal to the area of the rectangle plus the area of the triangles.

A = rectangle + 2 * triangle

= 10h + 2 * (1/2 hw)

Using trig work out h and w.

h = 10 sin ?

w = 10 cos ?

A = 10h + hw

= 100sin? + 100sin?cos?

Differentiate the expression (either use the product rule for sin? cos?, or write 100sin?cos? as 50sin2? using the double angle formula)

A = 100sin? + 50sin2?

dA/dt = 100cos? + 100cos2?

For A to be a max or min the derivative must equal zero

100cos? + 100cos2? = 0

cos? + cos2? = 0

Use the double angle formula to write cos2? as 2cos^2 ? - 1

cos? + 2cos^2 ? - 1 = 0

2cos^2 ? + cos? - 1 = 0

This quadratic factorizes:

(2cos? - 1)(cos? + 1) = 0

This means that

cos ? = 1/2 or cos ? = 1

giving:

? = pi/3 or ? = pi

Which means that to achieve the maximum area ? should be pi/3 = 60 degrees

You can check that this is the max by substituting in these values of theta and the two end points (theta = 0, theta = pi), and seeing that pi/3 gives the maximum.

The maximum area is therefore

A = 100sin? + 100sin?cos?

= 100sin(pi/3) + 100sin(pi/3)cos(pi/3)

= 100 sqrt(3) / 2 + 100 sqrt(3)/2 * 1/2

= 100 * 3/2 * sqrt(3) / 2

= 3 * 25 * sqrt(3)

= 75 sqrt(3)

= 129.9...

= 130 cm^3

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I inferred you want literal editing of the text above.

Explanation:

Here's a correction of the sentences:

1. The author, an expert in cybersecurity will speak via Zoom on Wednesday.

In this sentence, punctuation mark ( , ) was added and the word  'this' was replaced with 'on'.

2. Williams' book contains many illustrations, which makes it easy to read.

Added punctuation and made a revision of the sentence.

3. Based on the available evidence, the university administrators have opted for a hybrid format for the fall, which begins September 20.

Mainly added punctuations to make the senstence clarer.

4. (Thesis statement) I believe Free laptops should be offered to all students who need them.

Made a few additions.

The goal of Boeing, Inc is to determine whether an existing machine can mill an engine part that has a design specification of 5.0mm +- 0.10 mm. The process has a standard deviation of σ = 0.02 mm.

Given that the standard deviation of the process is σ = 0.02 mm. Now, we need to determine if the existing machine can produce a part that meets the design specification using the given standard deviation (σ).The tolerance limit (T.L) can be calculated as;

T.L = (Upper Limit – Lower Limit) / 2 where;

Upper Limit = 5.0 + 0.10 = 5.10 mm

Lower Limit = 5.0 – 0.10 = 4.90 mm

T.L = (5.10 – 4.90) / 2 = 0.10 / 2 = 0.05 mm

The value of T.L = 0.05 mm

The process standard deviation (σ) = 0.02 mm

Using the formula;

P = 0.6827, approximately 68.27% of the parts produced by the existing machine fall within the tolerance limit (5.0 ± 0.10)

With a process standard deviation of σ = 0.02 mm and a tolerance limit of 0.05 mm, approximately 68.27% of the parts produced by the existing machine fall within the tolerance limit (5.0 ± 0.10). It can, therefore, be concluded that the existing machine can produce parts that meet the design specification.

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Bay Oll produces regular and super fuels by mixing three ingredients. The distinguishing feature of the two products is the octane level required.

Octane rating is a measure of a fuel's ability to resist "knocking" or "pinging" during combustion, caused by the air-fuel mixture detonating prematurely in the engine. A higher octane rating means that the fuel is more resistant to knocking.
Regular fuel must have a minimum octane rating of 87, whereas super fuel must have a minimum octane rating of 91. This means that super fuel is more resistant to knocking than regular fuel. The ingredients used in the production of regular and super fuels may be the same, but the proportions and processing techniques are different to achieve the desired octane level.
Octane level is an important consideration when choosing the type of fuel to use in your vehicle. If your vehicle requires high-octane fuel and you use regular fuel instead, it may result in engine knocking and decreased performance. On the other hand, using high-octane fuel in a vehicle that only requires regular fuel may not provide any significant benefits.
In conclusion, Bay Oll produces regular and super fuels by mixing three ingredients and adjusting the proportions and processing techniques to achieve the desired octane level. The higher the octane rating, the more resistant the fuel is to knocking during combustion. It is important to use the appropriate fuel for your vehicle's octane requirement to ensure optimal performance.

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When electric power is transferred over a long distance then, line loss can be reduced by high voltage and low current. Thus, option A is correct.

The complete question is attached to the image below.

The electric circuit transfers the electric current then it is called electric power. The loss in the line over a larger distance is reduced by transferring AC instead of DC voltage.

The AC transmitted is of high voltage, and the power is low. The equation for current is given,

P = VI

The increase in the voltage causes the decrease in the current and in turn the resistance also reduces resulting in the loss of the power of the circuit to decrease.

Therefore, the loss is reduced by transferring high voltage and, low current AC.

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Assessing the promises made about new cities built from scratch requires a critical evaluation of their potential benefits and challenges. While such cities may offer solutions to existing urban problems, there are several factors of concern that need to be considered:

1. Implementation Challenges: Building a city from scratch is a complex and challenging task. It involves extensive planning, coordination, and financial investment. Delays and cost overruns can be common, impacting the realization of promised benefits.

2. Sustainability and Environmental Impact: New cities often promote sustainability and eco-friendly practices. However, there is a need to ensure that these cities truly deliver on their environmental promises throughout their lifespan. Issues such as resource consumption, waste management, and carbon emissions must be carefully addressed.

3. Social and Economic Equity: Scratch cities may claim to address social inequalities and provide affordable housing. However, ensuring equitable access to housing, education, healthcare, and employment opportunities for diverse socio-economic groups is crucial. Care must be taken to avoid creating new forms of exclusion and segregation.

4. Community Engagement and Identity: Creating a sense of community and fostering a unique city identity takes time and effort. It is essential to involve residents and stakeholders in the planning process to ensure their needs, preferences, and cultural aspects are considered.

5. Long-Term Viability: The long-term sustainability and success of new cities depend on various factors, including economic diversification, job creation, attracting investments, and adapting to changing demographics and technological advancements. Ongoing governance and management strategies are essential for their continued growth and development.

6. Infrastructure and Connectivity: Adequate infrastructure, transportation networks, and connectivity are vital for the smooth functioning and accessibility of new cities. Planning for efficient transportation systems, public spaces, and connectivity with existing urban areas is critical to avoid isolation and promote integration.

7. Economic Development and Job Opportunities: Scratch cities often promise economic growth and employment opportunities. However, the transition from initial development to a self-sustaining economy can be challenging. Ensuring a diversified and resilient economy with sustainable job opportunities is crucial for the long-term prosperity of the city.

8. Cultural and Social Vibrancy: Creating vibrant cultural and social spaces is important for the quality of life in new cities. Encouraging artistic expression, cultural events, and social interactions can contribute to the overall livability and attractiveness of the city.

In assessing promises made about scratch cities, it is important to critically analyze these factors and ensure that realistic expectations, proper planning, community engagement, and ongoing monitoring and evaluation are integral parts of the development process. This can help address concerns and increase the likelihood of achieving the envisioned benefits for residents and the wider community.

Assessing the promises made about new cities from scratch requires a critical evaluation of their potential benefits and potential concerns. While these cities hold the promise of addressing existing urban challenges, there are several aspects to consider:

Promises:

Urban Planning: New cities from scratch provide an opportunity for deliberate urban planning, allowing for the creation of well-designed and efficient infrastructure, transportation systems, and public spaces. This can lead to improved quality of life and a more sustainable environment.

Innovation and Technology: Many new cities aim to leverage advanced technologies and smart solutions to create efficient, connected, and sustainable urban environments. This includes the integration of renewable energy, smart grids, intelligent transportation systems, and data-driven management.

Social Equity: Scratch cities often promise to address social issues such as poverty and inequality. They may offer affordable housing, access to quality education and healthcare, and inclusive community spaces, aiming to create more equitable societies.

Economic Opportunities: New cities can attract investments, industries, and businesses, potentially creating new job opportunities and economic growth. They may offer a favorable environment for innovation, entrepreneurship, and the development of new industries.

Concerns:

Realization Challenges: Implementing a new city from scratch involves complex and long-term processes. Delays, budget overruns, and changing political priorities can hinder the realization of promised benefits, leaving residents and stakeholders disappointed.

Social Displacement: The creation of new cities may involve displacing existing communities or disrupting established social networks. This raises concerns about the potential marginalization of vulnerable populations and the loss of cultural heritage.

Sustainability and Environmental Impact: While new cities often aim to be sustainable, the actual environmental impact depends on factors such as resource consumption, waste management, and carbon emissions. The ecological footprint of construction, transportation, and ongoing operations must be carefully considered.

Affordability and Accessibility: Ensuring affordable housing, inclusive amenities, and accessible public services in new cities is crucial for addressing social equity. High costs, exclusionary practices, or limited accessibility can lead to socioeconomic disparities and exclusion.

Long-Term Viability: The long-term viability of new cities depends on various factors such as economic diversification, governance structures, citizen engagement, and adaptability to changing social, economic, and environmental conditions. Failure to anticipate and address these challenges can impact the sustainability and success of the new city.

Assessing the promises made about scratch cities requires a comprehensive evaluation of these factors, considering the specific context, governance frameworks, stakeholder engagement, and long-term planning. It is essential to carefully balance the potential benefits with the concerns to ensure the development of successful and inclusive new cities.

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Any Voltage used on board a ship if less than 1kV (1000 V) then it is called as LV (Low Voltage) system and any voltage above 1kV is termed as High Voltage. Typical Marine HV systems operate usually at 3.3kV or 6.6kV.

Explanation:

trust

Answer:

D) AND gate.

Explanation:

Given that:

A certain printer requires that all of the following conditions be satisfied before it will send a HIGH to la microprocessor acknowledging that it is ready to print

These conditions are:

1. The printer's electronic circuits must be energized.

2. Paper must be loaded and ready to advance.

3. The printer must be "on line" with the microprocessor.

Now; if these conditions are met  the logic gate produces a HIGH output indicating readiness to print.

The objective here is to determine the basic logic gate used in this circuit.

Now;

For NOR gate;

NOR gate gives HIGH only when all the inputs are low. but the question states it that "a HIGH is generated and applied to a 3-input logic gate". This already falsify NOR gate to be the right answer.

For NOT gate.

NOT gate operates with only one input and one output device but here; we are dealing with 3-input logic gate.

Similarly, OR gate gives output as a high if any one of the input signals is high but we need "a HIGH that is generated and applied to a 3-input logic gate".

Finally, AND gate output is HIGH only when all the input signal is HIGH and vice versa, i.e AND gate output is LOW only when all the input signal is LOW. So AND gate satisfies the given criteria that; all the three conditions must be true for the final signal to be HIGH.

Answer:

F = Qa*K

Explanation:

The force on the dipole is expressed as the negative gradient of the potential energy.

Thus;

Force; F = -dU/dx

Now, the potential energy is given as;

U = -pE

So, dU/dx = -pdE/dx

Since F = -dU/dx

Then, F = p*dE/dx

We are given p = Qa

Then;

F = Qa(dE/dx)

We are given that dE/dx = K

Thus;

F = Qa*K

The Airline Tariff Publishing Company (ATPCO) is an airline clearing house that is used by airlines to publish and distribute fares and cargo rates to the travel industry.

What is airline?
The structure and size of airlines differ. Others lease the aircraft for a set amount of time while hiring workers from other businesses, while some purchase the aircraft to provide special services. Typically, it is scheduled from one location to another. Worldwide, airlines play a significant role in the travel business. In order to make the route flexible and accessible, they frequently use jets and helicopters. People frequently mistakenly believe that the airline industry and aviation are interchangeable, which is not the case. It's important to note that the aviation industry includes all businesses related to aviation, including aircraft manufacturers, providers of non-commercial flights, regulatory bodies, aerospace firms, and others. The airline industry, on the other hand, refers to businesses that offer air transport services to paying customers or even for cargo services.

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The maximum transverse shear stress is 25.46 psi.

The maximum transverse shear stress, in psi, of a 1/4-8 lead screw with a shear force of 10 lbs can be calculated using the following equation:

Shear Stress (psi) = Shear Force (lbs) x 0.323 x (Threads per Inch).

The maximum transverse shear stress can also be determined by using the formula of \(\tau_{max} = (F_s * r) / I,\)

where \(F_s\) is the shear force, r is the radius, and I is the moment of inertia of the shaft.

The moment of inertia of a solid circular shaft can be determined by the formula of \(I = (\pi * r^{4} ) / 4\).

Here, the diameter of the lead screw is 1/4-8, which means the radius is 1/8 inches. The shear force is given to be 10 lbs.

\(\tau_{max} = (F_s * r) / I,\)

\(\tau_{max} = (10 * \frac{1}{8} ) / (\pi* \frac{1}{8})\)

\(\tau_{max} = 25.46\ psi\)

Therefore, the maximum transverse shear stress in psi of a 1/4-8 lead screw with a shear force of 10 lbs is 25.46 psi.

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Answer:  0.765 m kg / s

Explanation:

Momentum = (mass) x (speed)

INSIDE JOIN

When using this join method, the records that have matching values in both tables are returned. All the tuples with matching values in both tables will be output if you perform an INNER join operation between the Employee table and the Projects table.

If the criteria is met, the INNER JOIN keyword selects all rows from both tables. This keyword will combine all rows from both tables where the criterion is met to create the result set.

SQL supports a total of four join types. types include left outer join, right outer, and inner join.

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An extremum is a point where the function has its highest or lowest value, and at which the slope is zero.

The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum is as follows;

Reason:

The given parameters are;

Form of silo = Cylinder surmounted by a hemisphere

Cost of construction of hemisphere per square unit = 2 × The cost of of construction of the cylindrical side wall

Required:

The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum

Solution:

The fixed volume of the silo, V, can be expressed as follows;

\(V = \pi \cdot r^2 \cdot h + \dfrac{2}{3} \cdot \pi \cdot r^3\)

Where;

h = The height of the cylinder

r = The radius of the cylinder

The surface area is, Surface Area = 2·π·r·h + 2·π·r²

The cost, C = 2·π·r·h + 2×2·π·r² = 2·π·r·h + 4·π·r²

Therefore;

\(C = 2 \times \pi \times r\times \dfrac{V - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } + 4 \cdot \pi \cdot r^2 = \dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r}\)

At the minimum value, we have;

Which gives;

16·π·r³ = 6·V

Which gives;

\(h = \dfrac{\dfrac{8 \cdot \pi \cdot r^3}{3} - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } = 2 \cdot r\)

h = 2·r

The height of the silo, h = 2 × The radius, 2

Therefore, the dimensions to be used if the volume is fixed and the cost is to be kept to a minimum is, height, h = 2 times the radius

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Answer:

Cross pattern, according to the internet

A) The solid length is 5.9 in. B) The force required to close the spring solid is 0.063 psi. C) The factor of safety is 2543.

The solid length of a helical compression spring is calculated using the equation
Ls = Nd + 0.25Dn + 0.5Lf,

where Nd is the total number of active coils, Dn is the wire diameter and Lf is the free length of the spring.

For this spring, the solid length is calculated as follows:
Ls = 12 * 0.2 + 0.25 * 0.2 + 0.5 * 5 = 5.9 in.

(b) The force required to close the spring solid is calculated using the equation
F = k * (Ls – Lf), where k is the spring rate and Ls is the solid length.

The spring rate is calculated as follows:
k = G * d4 / 8D3, where G is the modulus, d is the mean coil diameter and D is the wire diameter.

For this spring, the spring rate is calculated as follows:
k = 11.6 * (2 / 8) * (0.2)3 = 0.069 mpsi.

The force required to close the spring solid is then calculated as follows:
F = 0.069 * (5.9 – 5) = 0.063 psi.

(c) The factor of safety at solidity is calculated using the equation
FS = Fmax / F, where Fmax is the maximum operating force and F is the force required to close the spring solid.

For this spring, the factor of safety is calculated as follows:
FS = 160 / 0.063 = 2543.

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Answer:

the proper diameter at its base so as to maintain the same volume flow rate is 1.6034 cm

Explanation:

Given the data in the question ;

flowrate Q = 400 cm³/s

cross section of the sprue is round

Diameter of sprue at the top d_top = 3.4 cm

Height of sprue = 20 cm = 0.2 m³

the proper diameter at its base so as to maintain the same volume flow rate = ?

first we determine the velocity at the sprue base

V_base = √2gh = √( 2×9.81×0.2) = √3.924 = 1.980908 m = 198.0908 cm

so, diameter of the sprue at the bottom  will be

Q = AV = [ (( πd²_bottom)/4) × V_bottom ]

d_bottom =  √(4Q/πV_bottom)

we substitute

d_bottom =  √((4×400)/(π×198.0908 ))

d_bottom =  √( 1600/622.3206)

d_bottom =  √2.571022

d_bottom =  1.6034 cm

Therefore, the proper diameter at its base so as to maintain the same volume flow rate is 1.6034 cm

Answer:

hello some part of your question is missing ( The table ) attached below is the missing detail related to your question

answer: cumulative infiltration after 30 mins = 6.7

Explanation:

Calculate the cumulative infiltration after 30 min

formula for calculating  cumulative infiltration

= 11( t - tp + t' ) = F - 34.3 In ( 1 + 0.0291 * F )

Attached below is a detailed solution to the problem