Question 7 A short needle, length 5.5 cm, stands on its end on the axis of a spherical mirror. It is a distance 22 cm from the mirror. Part A What is the length of the image of the needle if the focal

Answer:

i think its  Russia, USA, Germany.

Answer:

The independent variable is what you, the scientist, changes, and it causes the dependent variable to change.

Explanation:

The distance between the two cars each have the distance of 1050 kg is 17.99 x 10⁴ m

The mass of two cars = 1050 kg

The gravitational force between the two cars = 2.27 x 10⁻⁷ N

The distance between the two cars can be found using the formula,

           F = g m₁m₂/r²

where F is the gravitational force

          g is the gravitational constant

          m₁,m₂ is the masses of the two cars

          r is the distance between the two cars

Let us rearrange the above equation,

          r² = g m₁m₂/F

Let us substitute the known values in the above equation, we get

        r² = 6.67 x 10⁻¹¹ x 1050 x 1050 / 2.27 x  10⁻⁷

            = 7353675 x 10⁻¹¹ / 2.27 x  10⁻⁷

            = 3239504.41 x 10⁴

        r = √3239504.41 x 10⁴

           = 1799.86233 x 10²

           = 17.99 x 10⁴ m

Therefore, the distance between the two cars is 17.99 x 10⁴ m

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The collision between the electron and the atom resulted in an excitation of the atom from its ground state to a state with an energy of 102.5 eV.

When an electron with a speed of \(6.00\times 10^6 m/s\) collides with an atom, it can excite the atom to a higher energy state. In this case, the collision excites the atom from its ground state (0 eV) to a state with an energy of 3.70 eV.

To calculate the change in energy of the atom due to the collision, we can use the formula:

ΔE = \(1/2 * m * v^2\)

Where ΔE is the change in energy, m is the mass of the electron, and v is its velocity.

Since the mass of an electron is constant, we can calculate the change in energy by substituting the given values into the formula:

ΔE = 1/2 * \((9.11\times10^{-31 kg}) * (6.00\times10^6 m/s)^2\)

Simplifying this expression, we get:
ΔE =\(1/2 * 9.11\times10^{-31 }kg * 3.6\times10^{13 m^2}/s^2\)
ΔE \(= 1.64\times10^{-17 J\)

To convert this energy into electron volts (eV), we can use the conversion factor:
\(1 eV = 1.6\times10^{-19 J\)

Therefore, the change in energy of the atom due to the collision is:

ΔE = \((1.64\times10^{-17} J) / (1.6\times10^{-19}J/eV) = 102.5 eV\)

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Complete Question:

The density of the unknown sample is 0.67 g/ml.

To calculate the density, we use the formula:

Density = Mass / Volume

Mass = 38.00 g

Volume = 56.39 ml

Substituting the values into the formula:

Density = 38.00 g / 56.39 ml

Dividing the mass by the volume, we find:

Density = 0.674 g/ml

Rounding to two decimal places, the density of the unknown sample is 0.67 g/ml.

Density is a measure of how much mass is contained within a given volume. In this case, we are given the mass of the unknown sample as 38.00 g and its volume as 56.39 ml. To find the density, we divide the mass by the volume. By performing the calculation, we obtain a density of 0.674 g/ml.

When rounding the value to two decimal places, the density of the unknown sample is 0.67 g/ml. This means that for every milliliter of the sample, there is 0.67 grams of mass. Density is an important property in chemistry and materials science as it can help identify substances and determine their behavior in various applications.

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The question is incomplete, however \(1/2\kappa (\mu^2 m^2g^2/k)\) is  the potential energy stored in the spring.

of spring F=−kx

coefficient of kinetic friction F=μmg

At equilibrium, the mass and spring will both revert to their average positions.

so,−kx=μmg \(x=-\mu mg/k\)

the potential energy stored the spring is

\(1/2kx^2=1/2k-\mu mg/k^2=1/2k(\mu^2m^2g^2/k)\)

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To calculate show window branch-circuit loads using one of the two methods, you can multiply each receptacle by 180 volt-amperes.

Branch circuit loads in an electrical distribution system are the electrical equipment and appliances linked to a particular branch circuit. A branch circuit is a conduit through which electricity is sent from the main electrical panel to certain outlets, lights or pieces of equipment inside a building or other structure. The total amount of electrical load that each branch circuit can safely take is determined by its maximum capacity, or the circuit's ampere rating. Lighting fixtures, outlets, kitchen appliances, HVAC systems, and electronic gadgets are just a few examples of the many electrical components that might be branch circuit loads. The safe and effective operation of electrical systems in residential, commercial, and industrial settings depends on the proper sizing and distribution of branch circuits.

1. Identify the number of receptacles in the circuit.
2. Multiply the number of receptacles by 180 volt-amperes.
3. The result will give you the total load in volt-amperes for the show window branch-circuit.

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Answer:

oxygen and carbon dioxide

Explanation:

are soluble in water animal and plants can utilize these dissolved gases for resporation and photosynthesis and hence can survived in water

Answer:

Mass = 1450kg

Explanation:

P = M * V (where p is momentum, m is mass and v is velocity)

29000 = 20 * M

M = 29000 / 20

M= 1450 kg

Formula: \(d=vt\)

We're given:

\(d=vt\\\\t=\dfrac{d}{v}\)

⇒ Plug in the given values:

\(t=\dfrac{4.0}{2.0}\\\\t=2.0\)

Therefore, it took 2.0 seconds for the ball to reach the second player.

The organs of the circulatory system and the respiratory system are protected by the cutaneous system, the thoracic cage, and the immune system.

The cutaneous system is mainly made up of the skin. The skin is made of multiple layers of ectodermal tissue. It protects the body from UV radiations and also cold climatic conditions. The thoracic cage is also called as the rib cage. It is one of the main system that protects the vital organs.

The immune system protects the organs against infections from viruses, bacteria, fungi etc. The immune system is not like the other systems. Because it is made up of cells and not tissues. These cells are sterile.  

Therefore, the the three ways in which they are protected are by

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For (a), the minimum value of n for a hydrogen atom to be ionized by a photon with an energy of 1.99 eV is not possible. For (b), speed of the electron released from the state is 8.366 × 10^5 km/s.

(a) The minimum n for a hydrogen atom to be ionized by a photon can be found using the formula: E = -13.6 eV / n^2

where E is the energy of the absorbed photon. Rearranging the equation to solve for n, we have:

n = sqrt(-13.6 eV / E)

Substituting the values E = 1.99 eV into the equation, we get:

n = sqrt(-13.6 eV / 1.99 eV) ≈ sqrt(-6.834)

Since the value under the square root is negative, it implies that there is no integer solution for n. Therefore, there is no minimum value of n for a hydrogen atom to be ionized by a photon with an energy of 1.99 eV.

(b) When the electron is far from the nucleus, it can be considered to have escaped from the atom's influence and its energy can be approximated as kinetic energy. The kinetic energy of the electron can be calculated using the equation:

KE = E - |E_final|

where E is the energy of the absorbed photon and E_final is the energy of the electron when it is far from the nucleus.

Substituting the values E = 1.99 eV into the equation, we have:

KE = 1.99 eV - 0 eV = 1.99 eV

To find the speed of the electron, we can use the equation:

KE = (1/2)mv^2

where m is the mass of the electron and v is its velocity. Rearranging the equation to solve for v, we have:

v = sqrt((2KE) / m)

Substituting the values KE = 1.99 eV and the mass of the electron m = 9.10938356 × 10^-31 kg, we can calculate the speed of the electron.

that is, v = 8.366 × 10^5 km/s

The minimum value of n for a hydrogen atom to be ionized by a photon with an energy of 1.99 eV is not possible. The speed of the electron released from the atom when it is far from the nucleus can be calculated using the given energy of the photon and the mass of the electron.

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To achieve an outlet temperature of 125°C, needed a heat flux of 6919 W/m².

To solve this problem, we need to use the energy balance equation, which relates the heat transfer rate, mass flow rate, specific heat capacity, and temperature difference.

Q = mdot × cp × (Tout - Tin)

Where,

Q = heat transfer rate (W)

mdot = mass flow rate (kg/s)

cp = specific heat capacity of air (J/kg.K)

Tout = outlet temperature (K)

Tin = inlet temperature (K)

We can assume that the air is incompressible, and thus the specific heat capacity of air at constant pressure (cp) can be taken as a constant value of 1005 J/kg.K.

Next, we can use the Reynolds number to determine the flow regime in the tube.

Re = (ρ × D × V) / μ

Where,

ρ = density of air (kg/m³)

D = diameter of the tube (m)

V = velocity of air (m/s)

μ  = viscosity of air (Pa.s)

Assuming atmospheric pressure and using the properties of air at 20°C, we get:

ρ = 1.2041 kg/m³ and μ = 1.81 x 10^-5 Pa.s

Re = (1.2041 kg/m³ × 0.05 m × (0.005 kg/s / (π×(0.025 m)² / 4))) / (1.81 x 10^-5 Pa.s) = 26197

Since the Reynolds number is greater than 4000, we can assume that the flow is turbulent and fully developed.

Next, we can use the Dittus-Boelter equation to calculate the heat transfer coefficient (h).

ν = 0.023 × Re^(4/5) × Pr^(0.4)

Where,

Pr = Prandtl number of air (unitless)

Pr = (cp × μ) / k, where k is thermal conductivity of air at 20°C, k=0.0263 W/m.K

Pr = (1005 J/kg.K × 1.81 x 10^-5 Pa.s) / 0.0263 W/m.K = 0.706

ν = 0.023 × (26197)^(4/5) × (0.706)^(0.4) = 119.23

h = (ν × k) / D = (119.23 × 0.0263 W/m.K) / 0.05 m = 62.25 W/m².K

Now we can calculate the required heat flux using the energy balance equation.

Q = mdot × cp × (Tout - Tin) = h × pi × D × (Tout - Tin)

We can rearrange the equation to get the heat flux (q).

q = Q / (π × D × (Tout - Tin)) = h × (Tout - Tin)

Substituting the values, we get:

q = 62.25 W/m².K × (125°C - 20°C) = 6919 W/m²

Therefore, to achieve an outlet temperature of 125°C, we need a heat flux of 6919 W/m².

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A) Formulate policies to protect wetlands and ensure that the policies are enforced.

B) Wetlands hold important biodiversity. They are a source of foods, medicines, and raw materials. They help with stabilizing the climate.

As a governor of my state, the two most important steps to protect wetlands include:

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To protect the wetlands, I will ensure a strict enforcement of all existing state laws on the conservation of wetlands.

The wetlands are those areas that consists of marshes and swamps. They are of great important to the ecosystem and biodiversity.

a) The two things that I will do to protect wetlands are;

b) Wetlands are very important because;

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The Sun does not expand or contract because it is in a state of hydrostatic equilibrium. That is to say, the inward force of gravity is balanced by the outward pressure from nuclear fusion. The correct answer is option C.

Hydrostatic equilibrium refers to the balancing of the inward force of gravity and the outward force of radiation pressure (or thermal pressure) in stars. The energy emitted by a star comes from the nuclear reactions that occur in its core. These reactions create an enormous amount of energy in the form of light and heat, which is carried outward to the star's surface. The heat and light create a pressure that acts to push outward on the star's matter. At the same time, the star's mass creates a force of gravity that pulls inward. The balance between these two forces is called hydrostatic equilibrium.

Hydrostatic equilibrium is essential for stars to maintain a stable size and shape. When a star is in hydrostatic equilibrium, the inward force of gravity is balanced by the outward pressure from nuclear fusion. If this balance were upset, the star would either collapse under its own gravity or expand outwards, both of which would lead to catastrophic consequences.

Therefore, the concept of hydrostatic equilibrium is critical to our understanding of how stars evolve and the role they play in shaping our universe.

Therefore, the correct answer is option C.

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Answer:

B

Explanation:

Therefore, while increasing ground clearance alone does not inherently increase the risk of an accident, it is crucial to ensure that any modifications made to a vehicle are done properly and in accordance with safety standards to maintain optimal handling and stability.

Increasing ground clearance on a vehicle does not inherently increase the risk of an accident. True.

Increasing ground clearance can have certain advantages, such as improving off-road capability, allowing for better clearance over obstacles, and reducing the likelihood of scraping the bottom of the vehicle on rough terrain. However, it's important to consider that altering the ground clearance can affect the vehicle's handling and stability.

While increasing ground clearance itself does not directly lead to an increased risk of an accident, it can indirectly impact vehicle dynamics. A higher center of gravity resulting from increased ground clearance may affect the vehicle's stability, especially during sharp turns or sudden maneuvers. This could potentially increase the risk of rollovers or loss of control if the vehicle is not properly designed or modified to accommodate the changes in clearance.

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Frank is correct because light travels through diamond at  the slowest speed, and speed and frequency have an inverse  relationship .

Lisa is correct because  light travels through air at the fastest speed of ,and speed and frequency have a direct relationship .

Neither  Frank nor Lisa  is correct because light  does not change frequency when it travels through different media .

Both Frank and Lisa are correct because light has both inverse and a direct relationship with frequency ,depending on the type of media .

Neither of the two is correct because light does not change frequency when it travels through different media .

Disclaimer :The question given on the portal is incomplete .Here is the complete question .

Question :Frank and Lisa are analyzing the chart, which shows the speed at which light travels through different media. Frank says that light travels through diamond with the greatest frequency. Lisa says that light travels through air with the greatest frequency. Which best describes the accuracy of these statements?

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Answer:

A

Explanation:

Put A, It will help you.

Answer:

Transverse waves are always characterized by particle motion being perpendicular to wave motion. A longitudinal wave is a wave in which particles of the medium move in a direction parallel to the direction that the wave moves.

Explanation:

The movement of the medium is different. In the longitudinal wave, the medium moves left to right, while in thee transverse wave, the medium moves vertically up and down. Longitudinal waves have a compression and rarefaction, while the transverse wave has a crest and a trough. Longitudinal waves have a pressure variation, transverse waves don't have pressure variation. Longitudinal waves can be propagated in solids, liquids and gases, transverse waves can only be propagated in solids and on the surfaces of liquids. Longitudinal waves have a change in density throughout the medium, transverse waves don't.

Complete question

A cannon with a muzzle velocity of 500. meters per second fires a cannonball at an angle of 30.° above the horizontal. What is the vertical component of the cannonball's velocity as it leaves the cannon?

A   0.0 m/s

B    250. m/s

C   433 m/s

D    500. m/s

Answer:

The correct option is  C

Explanation:

From the question we are told that

   The velocity is  \(v = 500 \ m/s\)

    The angle is  \(\theta = 30^o\)

Generally the vertical component of the canon ball is mathematically represented as  

          \(v_y = v * cos (30 )\)

=>       \(v_y = 500 * cos (30 )\)

=>       \(v_y = 433 \ m/s\)

Answer:

250. m/s

Explanation:

It is vertical component so you do: 500mSin(30°) = 250m/s

(a) The heating load that can be met can be determined by calculating the heat transfer rate in the evaporator of the vapor-compression cycle. The heat transfer rate is given by the product of the mass flow rate and the enthalpy change of the refrigerant during the process:

Q_in = m_dot * (h_2 - h_1)

where m_dot is the mass flow rate, h_1 is the enthalpy at the evaporator inlet, and h_2 is the enthalpy at the evaporator outlet.

(b) The power input required for the system can be calculated using the compressor work, which is given by:

W_in = m_dot * (h_2 - h_3)

where h_3 is the enthalpy at the compressor outlet.

(c) The coefficient of performance (COP) is the ratio of the desired heating output to the required power input:

COP = Q_in / W_in

(d) The warmest outside temperature at which this particular cycle is unable to operate is determined by the condenser temperature. If the condenser temperature exceeds the highest ambient temperature, the system will not be able to reject heat effectively and will not operate efficiently.

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Answer:

I don't know what you mean about which changes occurred in this process but if its why the dough starts rising then its caused by the carbon dioxide in baking soda and yeast which is a fungus

Answer:

When baking,flour is mixed with water,the other ingredients and yeast to form a paste called a dough.what happens is that the zymase enzyme from the yeast acts on the sugars to form carbon dioxide and alcohol.the carbon dioxide begins to form bubbles in the dough causing it to rise..

I hope this helps

The statement that best describes the relative motions of the Pacific and Nazca plates is as follows:

Thus, the correct option for this question is C.

The Relative motion may be defined as the process that significantly involves the motion or speed of any object with respect to a particular point.

According to the context of this question, a mid-ocean ridge separates the Pacific plate and the Nazca plate off the western coast of South America. The relative motion of both these two plates with respect to South America possesses in a bidirectional manner. As the Pacific plate is moving to the west, and the Nazca plate is moving to the east.

Therefore, the correct option for this question is C.

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The largest compartment for carbon in Earth's system is the deep ocean, specifically the deep-sea sediments.

These sediments contain vast amounts of organic and inorganic carbon that has accumulated over millions of years.

The amount of carbon stored in these sediments is estimated to be on the order of 40,000 billion metric tons, which is several times more than the amount of carbon stored in the atmosphere, land plants, and soils combined.

The deep ocean plays an important role in the global carbon cycle, as it serves as a long-term storage reservoir for carbon and helps to regulate the concentration of carbon dioxide in the atmosphere over long timescales.

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1. Electron

2. Neutron

3. Nucleus

4. Atom

5. Molecule

Answer:

\(5,480\:\text{N}\)

Explanation:

The formula for work is given by \(W=F\Delta x\), where \(F\) is the force applied over a distance of \(\Delta x\).

Plugging in given values, we get:

\(16,700=F\cdot 3.05,\\F=\frac{16,700}{3.05},\\F\approx \boxed{5,480\:\text{N}}\)(three significant figures).

The amount of work that the force do on the block during the displacement is 4950 Joules.

The work done by a body is given by

W = F.S

Where,

W is the work done,

F is the force applied,

S is the displacement.

Work done is a scalar quantity that is found by the dot product of the force and the displacement of the body.

The force applied by the rushing water is given to be exerted is (210N)i-(150N)j

The displacement is given to be (15m)I - (12m)j.

Now, putting all the values,

W = (210i-150j)(15i-12j)

W = 4950 Joules.

So, the work done by the force to move the ice block is 4950 Joules.

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Complete question - A floating ice block is pushed through a displacement vector d= (15 m)i - (12 m)j along a straight embankment by rushing water, which exerts a force vector F = (210 N)i - (150 N)j on the block. How much work does the force do on the block during the displacement?

Answer:

1.) Experiments

2.) Mass, occupies space

3.) Potential energy

Explanation: