Question 5

1 pts

Chloroethene,C2H3C1, reacts with oxygen according to the equation below.

2 C2H2Cl (9) + 5O2(g) + 4CO2 (g) + 2 H20 g) + 2 HCl (9)

What is the amount, in mol, of H2O produced when 10.0 mol of C2H3Cl and 10.0 mol of

O2 are mixed together, and the above reaction goes to completion?

08.00

10.0

04.00

20.0

Lo

Answer:

"The last digit in any number is referred to as the estimated digit."

Explanation:

So it should be 2

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The gas exerts a pressure of 133.33 kPa on the walls of the 3 liter which is calculated by using the expression of Boyle’s law.

A fixed amount of a gas occupies a volume of 1l and exerts a pressure of 400 kPa on the walls of its container.

Initial volume (V1) is 1L

Initial pressure (P1) is 400 kPa

Final volume (V2) is 3L

Boyle's law explains the absolute pressure and volume of a given mass of confined gas are inversely proportional while the temperature remains unchanged within a closed system.

According to the Boyle’s law,

        P1V1 = P2V2

        ⇒ P2 = (P1V1)/V2

Putting all tte values we get,

            P2 = (1L * 400 kPa / 3L )

                 = 133.33 kPa

So we get the gas exerts a pressure of 133.33 kPa on the walls of the 3 liter.

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a. In a solution that is 0.010 M in Ba²⁺ and 0.020 M in Ca²⁺, when sodium sulfate (Na₂SO₄) is used to selectively precipitate one of the cations, the cation that will precipitate first is Ba²⁺. The minimum concentration of Na₂SO₄ that trigger the precipitation of the cation that precipitates first is 5.5 x 10^-9 M Na₂SO₄.

b. The remaining concentration of the cation that precipitates first, when the other cation begins to precipitate is 2.0 x 10^-2 M.

Let us discuss this in detail.

a. To determine which cation will precipitate first, we need to compare the solubility product constants (Ksp) of their respective sulfates. The Ksp for BaSO₄ is 1.1 x 10^-10 and the Ksp for CaSO₄ is 2.4 x 10^-5. Since the Ksp for CaSO₄ is much larger, it means that CaSO₄ is more soluble than BaSO₄. Therefore, Ba²⁺ will precipitate first.

To calculate the minimum concentration of Na₂SO₄ needed to trigger the precipitation of Ba²⁺, we need to use the common ion effect. This means that we need to add enough sulfate ions to the solution to exceed the solubility product constant of BaSO₄. The equation for the dissociation of Na₂SO₄ is:

Na₂SO₄(s) → 2 Na⁺(aq) + SO₄²⁻(aq)

Since we have 0.010 M Ba²⁺ in the solution, we need to add enough SO₄²⁻ ions to exceed the Ksp of BaSO₄. This can be calculated using the equation:

Ksp = [Ba²⁺][SO₄²⁻]

1.1 x 10^-10 = (0.010 M)(x)

x = 1.1 x 10^-8 M

This means that we need to add at least 1.1 x 10^-8 M SO₄²⁻ ions to trigger the precipitation of Ba²⁺. Since Na₂SO₄ dissociates to give 2 SO₄²⁻ ions for every formula unit, we need to add:

(1.1 x 10^-8 M) / 2 = 5.5 x 10^-9 M Na₂SO₄

b. Once Ba²⁺ starts to precipitate, the concentration of Ba²⁺ ions in the solution will decrease until it reaches a new equilibrium. At this point, the concentration of Ca²⁺ will still be 0.020 M. To calculate the new concentration of Ba²⁺ at this equilibrium, we need to use the equation:

Ksp = [Ba²⁺][SO₄²⁻]
1.1 x 10^-10 = (x)(5.5 x 10^-9 M)

x = 2.0 x 10^-2 M

Therefore, the remaining concentration of Ba²⁺ at equilibrium will be 2.0 x 10^-2 M.

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Total heat generated by 2 mole of TiO2(s) is 4.963kJ.

The amount of heat released in the reaction of 2.89 mol of TiO2(s) can be calculated using the following equation: q = nCΔT, where n is the number of moles, C is the specific heat capacity of TiO2, and ΔT is the change in temperature.

The specific heat capacity of TiO2 is 683. 697. J/kgK. and the change in temperature is is 25k. By plugging in the values and converting J to kJ,

q = 2.89 * 25 * 683.697

=> 4963.35

In brief, the amount of heat released by 2.89 mol of TiO2(s) is 4.963kJ.

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Complete question :

determine how much heat (in kj) of 2.89 mol of tio2(s) with a temperature difference of 25k

Answer:

False

Explanation:

The ideas were not proposed

Answer:

false

Explanation:

The pH dependence of the protonation state of glu487 is most likely responsible for the change in MP activity.

As the Glu487 have deprotonation, the pH becomes high. According to the pH-dependence of MP activity, activity reduces at both low and high pH levels. The main reason for decreased activity at low pH and high pH is the protonation of functional groups, respectively, and deprotonation of functional groups. According to the question, before being attacked by a nucleophile the substrate is protonated by Glu487 . The pKa of the side chain is always much greater in the enzyme active site than it is in solution to act as a Bronsted acid during catalysis ; otherwise, it would exist in the deprotonated form in the active site. If the pH elevated enough than there occurs the change in the protonation.

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We can see here that when compared to sulfuric acid, carboxylic acids are weaker acids.

Sulfuric acid is a strong, highly corrosive acid with the chemical formula \(H_{2} SO_{4}\). It is one of the most important and widely used industrial chemicals. Sulfuric acid is known for its strong acidic properties and is often referred to as the "king of chemicals" due to its widespread applications in various industries.

Sulfuric acid is a dense, oily liquid that is colorless when pure. It is soluble in water, and when dissolved, it releases hydrogen ions (H+) to make the solution highly acidic.

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Answer:

3.5%

Explanation:

To find the percentage that $13.13 represents of $375.00, we can use the following formula:

Percentage = (Part / Whole) x 100%

where "Part" is the amount we're trying to find the percentage of (in this case, $13.13), "Whole" is the total amount ($375.00), and we multiply the result by 100% to convert it to a percentage.

So, we have:

Percentage = ($13.13 / $375.00) x 100%

Percentage = 0.035 x 100%

Percentage = 3.5%

Therefore, $13.13 is approximately 3.5% of $375.00.

Answer:

856.0548362529

Explanation:

Answer:

False

Explanation:

The correct statements which are true for the reactions in the Sun are that are fusion reactions and reactions occur because of very high temperatures.

Nuclear fusion reactions are those reactions in which two species reacts with each other for the formation of new specie.

In the core of the sun, nuclear fusion of hydrogen atoms occur for the formation of helium molecules in the presence of high temperature.

Hence, the correct statements are they are fusion reactions and reactions occur because of very high temperatures.

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The type of reaction that must involve an increase in dispersal of matter is c. decomposition reactions

Decomposition reactions involve the breakdown of a single compound into two or more simpler substances. In these reactions, the reactant molecule is usually more complex and has higher molecular order compared to the products, resulting in an increase in dispersal of matter.

When a compound decomposes, the bonds within the molecule are broken, leading to the formation of multiple products.

As a result, the individual particles become more dispersed in space, increasing the entropy (disorder) of the system. This increased dispersal of matter is a characteristic feature of decomposition reactions.

On the other hand, single replacement reactions involve the replacement of one element in a compound with another element, and formation reactions involve the synthesis of a compound from its constituent elements.

These types of reactions do not typically result in an increase in the dispersal of matter.

Therefore, the type of reaction that must involve an increase in dispersal of matter is c. decomposition reactions.

Decomposition reactions are the type of reaction that result in an increase in the dispersal of matter. In these reactions, a compound breaks down into simpler substances, leading to an increase in entropy or disorder within the system.

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There are 1.81 × 10²⁴ molecules of sucrose in the given sample.

To calculate the number of molecules of sucrose in the given sample, we need to first determine the number of moles of carbon atoms present in the sample, and then use the molecular formula of sucrose to calculate the number of molecules.

Calculate the number of moles of carbon atoms in the sample:

We know that the sample contains 3.6 × 10²⁴ atoms of carbon. The molar mass of carbon is approximately 12 g/mol.

Therefore, the mass of carbon in the sample can be calculated as follows:

mass of carbon = number of atoms of carbon × molar mass of carbon

= 3.6 × 10²⁴ × 12 g/mol

= 4.32 × 10²⁵ g

To calculate the number of moles of carbon in the sample, we divide the mass of carbon by the molar mass of carbon:

number of moles of carbon = mass of carbon / molar mass of carbon

= 4.32 × 10²⁵ g / 12 g/mol

= 3.6 × 10²⁴ mol

Calculate the number of molecules of sucrose in the sample:

To calculate the number of molecules of sucrose in the sample, we can use the following formula:

number of molecules of sucrose = (number of moles of carbon / 12) × Avogadro's number

where;

Substituting the values, we get:

number of molecules of sucrose = (3.6 × 10²⁴ mol / 12) × 6.02 × 10²³ molecules/mol

= 1.81 × 10²⁴ molecules

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To ensure safety while carrying out her experiment, Maria should follow proper laboratory protocols and take necessary precautions like handle equipment and glassware carefully,wear appropriate personal protective equipment (PPE),read safety data sheets (SDS) to understand the proper handling,never work alone in the laboratory,etc.

Here are some recommendations:

1.Wear appropriate personal protective equipment (PPE), including safety goggles, lab coat, and gloves, to protect her eyes, body, and hands from potential hazards.

2.Familiarize herself with the properties and potential risks associated with the chemicals she will be working with. Read safety data sheets (SDS) to understand the proper handling, storage, and disposal procedures.

3.Work in a well-ventilated area or use a fume hood to minimize exposure to any fumes or gases that may be generated during the experiment.

4.Handle equipment and glassware carefully to prevent accidents or breakages. Ensure that all equipment is in good condition and appropriate for the experiment.

5.Follow proper techniques for measuring, mixing, and transferring chemicals to prevent spills or splashes. Use appropriate containers and labels to clearly identify and store chemicals.

6.Be aware of emergency procedures, including the location of safety equipment such as fire extinguishers, eyewash stations, and emergency showers.

7.Never work alone in the laboratory. Inform a supervisor or lab mate about the experiment and maintain communication throughout the process.

By following these safety measures, Maria can minimize risks and ensure a safe working environment during her experiment.

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Answer:

The heat of vaporization is typically larger than the heat of fusion

Next question answer:

The liquid water absorbs heat from the skin surface and is transferred to the air when the water evaporates.

Explanation:

Answer:

First answer

B. The heat of vaporization is typically larger than the heat of fusion

Second answer:

A. The liquid water absorbs heat from the skin surface and is transferred to the air when the water evaporates.

Explanation:

Answer: the answer is a

Explanation:

you should always keep lab coat on when in lab

Answer:

its  A. chemistry labs have a lot of things that can hurt you, even with just a few drops . its one of the most dangerous experiment types you do in science. even if your not doing an experiment  but your in the room you should have on protection in case of a spill or something.  it is always impotent  to have safety  gear on. even more so in chemistry

Answer: There is 0.8 liters (L) of water required to be added to prepare 4800mL of 0.5M NaCl from a 3M NaCl stock solution.

Explanation:

Given: \(M_{1}\) = 0.5 M        

\(V_{1}\) = 4800 mL

Convert mL into L as follows.

\(1 mL = 0.001 L\\4800 mL = 4800 mL \times \frac{0.001 L}{1 mL}\\= 4.8 L\)

\(M_{2}\) = 3 M

Formula used to calculate the volume of water required as follows.

\(M_{1}V_{1} = M_{2}V_{2}\)

Substitute the values into above formula.

\(M_{1}V_{1} = M_{2}V_{2}\\0.5 M \times 4.8 L = 3 M \times V_{2}\\V_{2} = \frac{0.5 M \times 4.8 L}{3 M}\\= 0.8 L\)

Thus, we can conclude that 0.8 liters (L) of water need to be added to prepare 4800mL of 0.5M NaCl from a 3M NaCl stock solution.

The mass of precipitate formed if a solution containing 2.34 g of cesium hydroxide is added to a solution containing a large excess of tiso4 is 0.6387 g

Mass of CsOH = 2.34 g

Number of moles of CsOH = 149.9 g / mol

Molar mass of CsOH =  Mass of CsOH / Number of moles of CsOH

                                    = 2.34 / 149.9

Molar mass of CsOH is 0.0156 mol

2 CsOH + TiSO4 → Ti(OH)2 + CsSO4

In this reaction 2 moles of CsOH gives 1 mole of Ti(OH)2

0.0156 mol of CsOH will produce, 0.0156 / 2 = 0.0078 mol

0.0156 mol of CsOH will produce 0.0078 mol of Ti(OH)2

Mass of Ti(OH)2 =  Molar mass of Ti(OH)2 / Number of moles of Ti(OH)2

                            = 0.0078 * 81.88

                            = 0.6387 g

Mass of Ti(OH)2 formed is 0.6387 g

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The mass of precipitate formed is 0.90441 g

cesium hydroxide is added to a solution containing a large excess of TiSo4

The chemical reaction is

2CsOH + TiSo4  →  Ti(OH)2 + CsSo4

The above reaction the Ti(OH)2 is a precipitate formed

Molar mass = mass of a substance / mass of one mole

Mass of CsOH = 2.34 / 149.912

Mass of CsOH = 0.0156 mol

The above reaction 2 mol of cesium hydroxide yield 1 mol of titanium hydroxide

Then, 0.0156 mol of CsOH yield 0.0156 / 2 = 0.0078 mol of Ti(OH)2

The mass of Ti(OH)2 is 115.95

0.0078 mol of Ti(OH)2 = 115.95 X 0.0078

                                      = 0.90441

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Answer:

Option c) The measurement of how much solute can be dissolved in a liter of solvent.

Explanation:

The concentration of a solution can be defined as the amount of solute in 1 litre of the solvent i.e how much of the solute that can dissolve in a litre of the solvent. Mathematically, it can be written as:

Concentration = mole of solute / Volume of solvent

Thus, the unit for the concentration is mole per litre (mol/L)

From the above illustration, we thus say that the concentration of a solution is a measure of how much solute can be dissolved in a liter of solvent.

Answer: A) Increase the amount of solute.

              C) Decrease the amount of solvent.

Specific heat is the amount, like the other brainly answer said, of heat per unit mass required.

The signs of δsuniv, δssurr, and δssys for water freezing at −10°C are ΔSsys: Negative, ΔSsurr: Positive and ΔSuniv: Positive.

When water freezes at -10°C, the signs of ΔSuniv, ΔSsurr, and ΔSsys are as follows:

1. ΔSsys (Change in entropy of the system): Since water is freezing, the molecules become more ordered, resulting in a decrease in entropy. So, ΔSsys is negative.

2. ΔSsurr (Change in entropy of the surroundings): When water freezes, it releases heat to the surroundings. This heat dispersal increases the entropy of the surroundings. Therefore, ΔSsurr is positive.

3. ΔSuniv (Change in entropy of the universe): This is the sum of ΔSsys and ΔSsurr. Since the process of freezing is spontaneous at -10°C, the overall entropy change in the universe must be positive. So, ΔSuniv is positive.

In summary, for water freezing at -10°C:
ΔSsys: Negative
ΔSsurr: Positive
ΔSuniv: Positive

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To determine the number of moles of F2 needed to form 2.8 moles of PF3, we need to first balance the chemical equation for the reaction and then use stoichiometry.

Given the chemical equation for the reaction:PF3 + F2 → PF5Firstly, we balance the equation by ensuring that the number of each type of atom is the same on both sides of the equation:PF3 + 2F2 → PF5Now, we know that 1 mole of PF3 reacts with 2 moles of F2 to produce 1 mole of PF5.

The molar ratio of PF3 to F2 is 1:2.Thus, we can use the following stoichiometric relationship to determine the number of moles of F2 required to form 2.8 moles of PF3:moles of F2 = (moles of PF3) x (2 moles of F2/1 mole of PF3)moles of F2 = 2.8 x 2 = 5.6 moles of F2Therefore, 5.6 moles of F2 are required to form 2.8 moles of PF3.

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Answer:

13

Explanation:

The mass number of an atom is the sum of the number of protons and neutrons.

27 = protons + 14

protons = 13

The number of protons is equal to the atomic number.

Answer: 41 or Niobium

Explanation: To get the number of Protons or Electrons given the number of Neutrons and Mass, you have to add the given numbers. This gives the number of Protons and Electrons which is the same number as the Atomic number. So, 14 Neutrons plus the mass of 27 is equal to 41, which gives the element Niobium

Answer:

Nylon, Cabon Fibre, High-Density Polythene.

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The three synthetic fibers or plastics used by the canoeist are:

Synthetic fibers are defined as man-made textile fibers that are generated from chemical substances. Some of these man-made fibers are also derived from natural substances such as cellulose or protein.

Based on the given question, the three synthetic fibers or plastics used by the canoeist are:

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Answer:

option A it has equal numbers of electrons and protons

Explanation:

electrons are negatively charged and protons are positively charged, so if the numbers of each are equal, then the atom will be neutral.

Answer:

A. it has equal numbers of electrons and protons

Explanation:

The overall charge of every atoms is neutral because the number of electrons and protons is the same. Protons are positively charged while electrons are negatively charged and so they cancel out.

Answer:

A. True

Explanation: