Question 4
What are some factors that influence flexibility
O Being Tall
O Weightlifting PR
O Heredity
O Sex and Age

Answer:

Food accounts for 10-30% of a household's carbon footprint, typically a higher portion in lower-income households. Production accounts for 68% of food emissions, while transportation accounts for 5%.

Explanation:

Answer: Food accounts for 10-30% of a household's carbon footprint, typically a higher portion in lower-income households.

Explanation:

We shall consider two properties to illustrate the experiment:

1. Temperature difference

2. Thermal conductivity of the material

Use a steel or other suitable material cylindrical rod that has insulation all the way around it.

The rod is submerged in water at 40 degrees Celsius and a large reservoir of water at 100 degrees Celsius on opposite ends. The cold water is kept in a cylinder that is completely insulated. A thermometer measures the cold water's temperature over time.

This experiment will show that

(a) heat flows from a region of high temperature to a region of lower temperature.

(b) The thermal energy of a body increases when heat is added to it, and its temperature will rise.

(c) The thermal conductivity of water determines how quickly its temperature will rise. If mercury replaces water in the cold cylinder, its temperature will rise at a different rate because its thermal conductivity is different

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Answer:

wait what do you mean? And why is this in physics?

Is this about the iron dome or something biblical?

Explanation:

Answer:

the story of Israel is part of the Bible that's what what you're your lesson is

Explanation:

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the answer for the question is D. all of the above

The overall resistance of the combination is 1.53 Ω.

When resistors are connected in parallel, the total resistance is calculated using the formula:1/R_total = 1/R1 + 1/R2 + 1/R3 + ...In this case, the three resistors have values of 3.00 Ω, 7.00 Ω, and 15.0 Ω. Plugging these values into the formula, we get:
1/R_total = 1/3.00 + 1/7.00 + 1/15.0.Calculating the sum on the right-hand side gives us:1/R_total = 0.3333 + 0.1429 + 0.0667 = 0.5429. To find the overall resistance, we take the reciprocal of the sum:R_total = 1/0.5429 = 1.53 Ω.
Therefore, the overall resistance of the combination is 1.53 Ω.

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Answer:

E" =  Q/4πε₀√[(x² + R²)]³(x - (L - x)/√[(L - 2x)L/(x² + R²) + 1]³})

Explanation:

The electric field due to a charged ring of radius R at a distance x from the center of the ring when the axis of the ring is located on the x - axis is

E = Qx/4πε₀[√(x² + R²)]³

Since the rings are separated by a distance L, the electric field at point x due to the second ring is E' = -Q(L - x)/4πε₀[√((L - x)² + R²)]³. It is negative since it points in the negative x - direction.

So, the resultant electric field at x is E" = E + E' = Qx/4πε₀[√(x² + R²)]³ + {-Q(L - x)/4πε₀[√((L - x)² + R²)]³}

E" =  Qx/4πε₀√[(x² + R²)]³ - Q(L - x)/4πε₀√[((L - x)² + R²)]³

E" =  Q/4πε₀(x/√[(x² + R²)]³ - (L - x)/√[((L - x)² + R²)]³})

E" =  Q/4πε₀(x/√[(x² + R²)]³ - (L - x)/√[(L² - 2Lx + x² + R²)]³})

E" =  Q/4πε₀(x/√[(x² + R²)]³ - (L - x)/√[(L - 2x)L + (x² + R²)]³})

E" =  Q/4πε₀√[(x² + R²)]³(x - (L - x)/√[(L - 2x)L/(x² + R²) + 1]³})

So, the electric field at points along the x axis is

E" =  Q/4πε₀√[(x² + R²)]³(x - {(L - x)/√[(L - 2x)L/(x² + R²) + 1]³})

Answer:

A. wind blows from the land toward the sea.

B. that this happens because the land cools faster than the sea, and, as a result, the air over land cools faster, which creates an area of higher pressure on land and lower pressure over the sea.

Explanation:

bc I am smrt

PLZ thank five star

and brainliest would be appreciated:-)

When aiming at a marble at the bottom of a fish tank filled with water (n2=1.33) and an incident angle of 80 degrees, the angle of refraction can be calculated using Snell's law. The angle of refraction is approximately 58.2 degrees.

To determine the angle of refraction when aiming at a marble in a fish tank filled with water, Snell's law can be applied. Snell's law relates the incident angle, the angle of refraction, and the refractive indices of the two media involved. Snell's law is given by:

n1 * sin(θ1) = n2 * sin(θ2)

where n1 and n2 are the refractive indices of the initial medium (in this case, air) and the final medium (water), respectively, θ1 is the angle of incidence, and θ2 is the angle of refraction.

Given:

Refractive index of water (n2) = 1.33

Angle of incidence (θ1) = 80 degrees

First, we need to convert the angle of incidence from degrees to radians:

θ1 (in radians) = θ1 (in degrees) * (π / 180)

θ1 (in radians) = 80 * (π / 180)

θ1 (in radians) ≈ 1.3963 radians

Using Snell's law, we can calculate the angle of refraction (θ2):

n1 * sin(θ1) = n2 * sin(θ2)

Substituting the values:

sin(θ2) = (n1 / n2) * sin(θ1)

sin(θ2) = (1 / 1.33) * sin(1.3963)

Now, we can find the value of sin(θ2) using a scientific calculator and take the inverse sine to find the angle θ2.

θ2 ≈ arcsin[(1 / 1.33) * sin(1.3963)]

Calculating the value, we find that the angle of refraction (θ2) is approximately 58.2 degrees.

Therefore, when aiming at the marble in the fish tank with an incident angle of 80 degrees, the angle of refraction is approximately 58.2 degrees.

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In the game of volleyball, low intensity is often used during warm-up exercises or cool-down sessions.

These exercises are designed to help players get their bodies warmed up and ready to play, or to help them cool down after a game or practice. There are several low-intensity exercises that are commonly used in volleyball, including stretching, jogging, and light calisthenics.Stretching is a key part of any volleyball warm-up routine. This helps to get the blood flowing to the muscles and prepares them for the more intense exercises that are to follow. Some of the most common stretching exercises include hamstring stretches, quad stretches, and shoulder stretches. These exercises help to improve flexibility and range of motion, which can reduce the risk of injury during the game.Jogging is another common low-intensity exercise that is used in volleyball.

This helps to get the heart rate up and prepare the body for more intense activities. Jogging can also help players to develop endurance and stamina, which can be critical in the later stages of a game or tournament.Light calisthenics, such as jumping jacks, sit-ups, and push-ups, can also be used to warm up or cool down. These exercises are designed to help improve strength and endurance while also promoting flexibility and range of motion. Players can choose from a variety of different exercises to create a customized workout routine that meets their specific needs and goals.Overall, low-intensity exercises are an important part of any volleyball training program. They help to prepare the body for more intense activities while also promoting flexibility, endurance, and strength. By incorporating these exercises into their training routine, volleyball players can improve their overall fitness and performance on the court.

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Answer:

a = 32^2 / 56 = 2.29 m/s^2.

Explanation:

To find the car's centripetal acceleration, we need to use the formula a = v^2 / r, where a is the centripetal acceleration, v is the speed of the car, and r is the radius of the curve.

In this case, the car's speed is 32 m/s and the radius of the curve is 56 m, so the centripetal acceleration would be a = 32^2 / 56 = 2.29 m/s^2.

Answer:

The final velocity is 5.24 m/s

The initial speed is 65.5 m/s

Explanation:

Horizontal Motion

When an object is launched horizontally with an initial speed v from a height h, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.

The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:

\(v_x=v_o\)

The vertical component of the velocity changes in time t because gravity makes the object fall at increasing speed given by:

\(v_y=g.t\)

The maximum horizontal distance traveled by the object can be calculated as follows:

\(\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}\)

Another useful formula allows us to calculate the distance traveled by the object in terms of time t:

\(\displaystyle y=\frac{g.t^2}{2}\)

a.

The time taken for the arrow to reach the ground can be calculated by solving the above equation for t:

\(\displaystyle t=\sqrt{\frac{2y}{g}}\)

Since y=1.40 m:

\(\displaystyle t=\sqrt{0.2857}\)

t = 0.53 s

The final vertical speed is:

\(v_y=9.8.(0.53)=5.24\ m/s\)

The final velocity is 5.24 m/s

b)

The initial speed can be calculated by solving the following equation for v:

\(\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}\)

\(\displaystyle v=d\cdot\sqrt{\frac {g}{2h}}\)

\(\displaystyle v=35\cdot\sqrt{\frac {9.8}{2(1.40)}}\)

v = 65.5 m/s

The initial speed is 65.5 m/s

Earth's magnetic field is generated in the core, which is composed of molten iron and nickel that is constantly in motion.

The Earth's magnetic field is generated in the core, which is located at the center of our planet. The core is composed of molten iron and nickel, and it is in constant motion. This motion creates a phenomenon known as the geodynamo, which generates Earth's magnetic field.

The geodynamo works through a process called convection. The intense heat from the core causes the molten iron and nickel to become buoyant, leading to a continuous circulation of the materials. This motion generates electric currents, which, in turn, produce a magnetic field. The Earth's rotation further amplifies this field, creating the complex and dynamic magnetic field we observe.

The magnetic field generated by the core extends from the Earth's interior to its surrounding space, creating a protective shield called the magnetosphere. This shield plays a crucial role in shielding the planet from harmful solar radiation and charged particles emitted by the Sun. Additionally, Earth's magnetic field enables navigation by acting as a compass for birds, animals, and even some microorganisms.

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The wavelength of light absorbed by the copper complex when an electron is promoted from a lower energy d orbital to a higher energy d orbital is 231 nm.

To determine the wavelength of light absorbed by a copper complex when an electron is promoted from a lower energy d orbital to a higher energy d orbital, we need to use the formula:
ΔE = hc/λ
Where ΔE is the energy difference between the two orbitals, h is Planck's constant, c is the speed of light, and λ is the wavelength of the absorbed light.
We know that the energy change (ΔE) is equal to the energy of the higher orbital minus the energy of the lower orbital. Since the question states that the energy change is 0.256 aj, we can assume that this is the value of ΔE.
We also know that the energy of an electron is related to its wavelength by the equation:
E = hc/λ
Therefore, we can rearrange this equation to solve for the wavelength:
λ = hc/E
Substituting the value of ΔE into this equation, we get:
λ = hc/ΔE
Plugging in the values of h, c, and ΔE, we get:
λ = (6.626 x 10^-34 J.s) x (2.998 x 10^8 m/s) / (0.256 x 1.602 x 10^-19 J)
Simplifying this equation, we get:
λ = 2.31 x 10^-7 m = 231 nm
Therefore, the wavelength of light absorbed by the copper complex when an electron is promoted from a lower energy d orbital to a higher energy d orbital is 231 nm.

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The force of friction between the losing player’s feet and the grass is 692 N.

The force of friction between the losing player’s feet and the grass is calculated by applying Newton's second law of motion as shown below.

F(net) = ma

where;

F - Ff = ma

where;

800 - Ff = 90 x 1.2

800 - Ff = 108

Ff = 800 - 108

Ff = 692 N

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Given that copper's electron mobility is 3 10-3 m2/v-s, there are 1.20 × 10⁷ conducting electrons per cubic meter in copper.

The mobility of holes and electrons in semiconductors and metals is the subject of this essay. See Electrical mobility for a broad explanation. The electron mobility in solid-state physics refers to how quickly an electron may move through with a metal or semiconductors when being drawn by an electric field. Hole mobility is the corresponding quantity for holes. Both electron / hole mobility are collectively referred to as carrier mobility. The electrical mobility if charge particles in a fluid under such an applied electric field includes electron / hole mobility as specific examples.

The equation =VdE allows us to mathematically demonstrate electron mobility. The SI symbol for electron mobility when subject to an external electric field is m2V1s1. We can see that [M1T2A] is its dimensional form when the SI unit's dimensions are calculated.

resistivity of the copper (p) = 1.73 × 10⁸ Ωm

η = σ/μe

Here, σ = electrical conductivity

σ = 1/ρ

e = charge on electrons = 1.6 × 10⁻¹⁹

μ = mobilty of electrons

n = σ/μe

n = 1/ρμe

n = 1/8.304 × 10⁻⁸

n = 10⁸/8.304

n = 1.20 × 10⁷ electrons/ m³

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Answer:

300 kg x cm/s / 100 = 3 kg x m/s.

Answer:

Aim: To investigate which material of pot will cook food quicker.

Hypothesis: The (aluminum/enamel) pots will cook the food quicker than the (aluminum/enamel) pots.

Apparatus:

- Aluminum pots

- Enamel pots

- Stove top

Variables:

Independent variable (What will be changed) - Material of pot

Dependent variable (What's being measured) - Time taken for food to cook

Controlled variables (What's staying the same) - Size of pot, type of food being cooked, quantity of food being cooked, stove top

Method:

Results: (I don't have results because i never conducted this experiment)

Conclusion: This experiment showed that (aluminum/enamel) pots cooked the food quicker than (aluminum/enamel pots). These results (supported/rejected) my hypothesis.

Evaluation: (Never did the experiment, so there's nothing to evaluate)

Explanation:

I hope this helps :)

Answer:nvm

Explanation:

Answer:

A furry and they cant spell god

Explanation:

The height of each bob rebound is 0.66m.

Height is the measurement of someone or something.

The velocity with which the 75g bob collides with the 95g bob is u = sqrt(2gl) = 4.12m/s Now th given collsion is headon and elastic therefore the  energy and linear momentum of both will be conserves and from the law of conservationists of linear momentum and laws of conservationists of energy we get for lighter (75g) bob

v1 = (m_1 -m_2 \over m_1 +m_2 )u_1 +( 2m_2 \over m_1 +m_2 )u_2

= 0.075-0.095

\over 0.075+ 0.095 ×4.12 + 0

= -0.485 m/s ( -ve sign shows that the bob will move in opp. dir. to its initial dir.)

and v2 = (m_2 -m_1 \over m_1 +m_2 )u_2 +( 2m_1 \over m_1 +m_2 )u_1 = 0 + 2×0.075 \over 0.075+ 0.095 × 4.12 = 3.63 m/s

as at max hieght both the bob will come to rest for a moment then applying v2 - u2 = 2as we get for bob of 95g 0 - 13.21 = -2×10h or h = 13.21/20 = 0.66m for bob height.

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Answer:

To find the lateral area of a pyramid, we need to calculate the area of each triangular face and then add them together. The lateral area does not include the area of the base.

Explanation: Given the width and length of the base of the pyramid, we can calculate the height using the Pythagorean theorem. The height of the pyramid is the same as the height of each triangular face.

Using the Pythagorean theorem:

height² = slant² - (1/2 × width)²

height² = 40² - (1/2 × 60)²

height² = 1600 - 1800

height = √200

height = 10√2

The area of each triangular face can be calculated as:

area of triangle = (1/2 × base × height)

area of triangle = (1/2 × 60 × 10√2)

area of triangle = 300√2

Since the pyramid has four triangular faces, the total lateral area is:

lateral area = 4 × area of triangle

lateral area = 4 × 300√2

lateral area ≈ 1,695

Therefore, the lateral area of the pyramid is approximately 1,695 square meters, to the nearest whole number.

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A divergent plate boundary is a location on Earth's surface where two tectonic plates are moving away from each other. This movement causes the crust to crack and form a rift, which can lead to the formation of magma.

The process begins with the Earth's mantle, the layer of rock below the crust. The mantle is made up of solid rock that is heated by the Earth's core and is in a constant state of convection. As the rock in the mantle rises, it begins to melt and form magma. This magma is less dense than the surrounding rock, so it begins to rise towards the surface.

As the magma rises, it pushes against the crust, causing it to crack and form a rift. The rift is a deep crack in the Earth's surface, and as the tectonic plates continue to move apart, it becomes wider and wider. The magma continues to rise and fill the rift, forming a volcano.

As the divergent plate boundary continues to move apart, the volcano continues to erupt and build up layers of lava and ash. Over time, these layers can build up to form a volcano. This process can continue for millions of years, forming a chain of volcanoes along the divergent plate boundary.

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Explanation:

what is it of? I maybe able to help.

The diffraction grating affects the light from a hydrogen lamp as it produces the separation of the colors of the white light. The spectrum can be viewed through the grating,

The distance from the axis of the force applied is 2.05 m.

The distance from the axis of the force applied is calculated as follows;

The formula for torque;

τ = Fr

where;

Another formula for torque is given as;

τ = Iα

where;

τ = (mr²)α

τ = (25 kg x (0.925 m)²) x (1.84 rad/s²)

τ = 39.36 Nm

The distance is calculated as;

r = τ/F

r = ( 39.36 Nm ) / (19.2 N)

r = 2.05 m

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To find the value of t when the cart is first located at x = 8.47 cm, we need to set the given equation equal to 8.47 cm and solve for t. Therefore, we have:

8.47 cm = (12.4 cm) cos[(6.35 s^-1)t]

Dividing both sides by 12.4 cm, we get:

cos[(6.35 s^-1)t] = 0.6835

Taking the inverse cosine (cos^-1) of both sides, we get:

(6.35 s^-1)t = 46.13°

Multiplying both sides by (1 rad/57.3°) to convert degrees to radians, we get:

(6.35 s^-1)t = 0.805 rad

Finally, solving for t, we get:

t = (0.805 rad)/(6.35 s^-1) = 0.127 s

Therefore, the cart is first located at x = 8.47 cm at a time of t = 0.127 s after t = 0.00 s.
The position of an air-track cart oscillating on a spring is given by the equation x = (12.4 cm) cos[(6.35 s-1)t]. To find the value of t when the cart is first located at x = 8.47 cm, we can set the equation equal to 8.47 cm:

8.47 cm = (12.4 cm) cos[(6.35 s-1)t]

Now, we need to solve for t:

(8.47 cm) / (12.4 cm) = cos[(6.35 s-1)t]
0.6831 = cos[(6.35 s-1)t]

Next, take the inverse cosine (arccos) of both sides:

t = arccos(0.6831) / (6.35 s-1)

Calculating the value of t, we get:

t ≈ 0.3069 s

So, the cart is first located at x = 8.47 cm after approximately t = 0.3069 seconds.

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