Question 3
This law states that every particle attracts every other particle in the universe with a force that
is directly proportional to the product of their masses and inversely proportional to the square of the
distance between their centers
O Theory of General Relativity
O Hubble's Law of Cosmic Expansion
O Law of Universal Gravitation
O Archimede's Bouoyancy Principle
3 pts
Question 4
3 pts

If Half- life of an isotope is 30 days and it was assumed that the person ate 100 Bq of isotope, there are 50 transformations in the stomach.

The radioactive decay of a sample of an isotope can be characterized by the half-life of that isotope. When a radioisotope undergoes decay, its nucleus becomes unstable, and it emits particles or energy to become more stable. The half-life of an isotope is the time it takes for half of the original sample to decay. The question states that the half-life of an isotope is 30 days, and the person ingested 100 Bq of isotope. It also says to calculate the number of transformations in the stomach using GI track model information .

Since the isotope has a half-life of 30 days, we can use the following formula to find the number of transformations in the stomach:` N = N₀ (1/2)^(t/T₁/₂)`where: N₀ = initial number of nuclei N = final number of nuclei (after time t)T₁/₂ = half-life of the isotope The isotope has a half-life of 30 days, so T₁/₂ = 30 days. The question doesn't specify how long the person has had the isotope in their stomach, so we'll assume it's been there for one half-life, or 30 days. Therefore, t = 30 days.

Substituting into the formula:` N = 100 (1/2)^(30/30)`Simplifying:` N = 100 (1/2)^1`Evaluating:`N = 50`So after 30 days in the stomach, the person would have 50 Bq of the isotope left. Therefore, the number of transformations in the stomach is the difference between the initial number of transformations (100 Bq) and the final number of transformations (50 Bq):`Number of transformations in stomach = 100 - 50 = 50 transformations. Therefore, there are 50 transformations in the stomach.

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Answer:

the answer is over water D

Answer:

First determine the lever arm and then multiply it times the applied force.

The equation τ = m(r^2)α is the rotational analog of Newton's second law (F=ma)

Hope this helps.

Sucrose; C12H22O11

C9H8O4; acetyl salicylic acid

H2O2; hydrogen peroxide,

NaOH; sodium hydroxideExplanation:

1) The VSEPR number for T-shaped molecular geometry is 5.

2) The geometry is octahedral

3) The geometry is Trigonal pyramidal

The VSEPR (Valence Shell Electron Pair Repulsion) theory is used to predict the molecular geometry of a molecule based on the arrangement of electron pairs around the central atom.

For a T-shaped molecular geometry, there are three bonding pairs of electrons and two non-bonding pairs of electrons around the central atom. Therefore, the VSEPR number for T-shaped molecular geometry is 5.

The VSEPR number is the sum of the number of atoms bonded to the central atom and the number of lone pairs of electrons on the central atom.

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Answer:

So A covalent bond consists of the mutual sharing of one or more pairs of electrons between two atoms. These electrons are simultaneously attracted by the two atomic nuclei. A covalent bond forms when the difference between the electronegativities of two atoms is too small for an electron transfer to occur to form ions.

Explanation:

words to know: covalent bond, electronegativities, and simultaneously

Covalent Bond: A chemical bond formed when electrons are shared between two atoms. Usually each atom contributes one electron to form a pair of electrons that are shared by both atoms.

Electronegativities: the degree to which an element tends to gain electrons and form negative ions in chemical reactions.

Simultaneously: at the same time.

hope this helps!

H₂ receptor antagonists reduce the secretion of acids by blocking the H₂ receptors on parietal cells in the stomach, thereby inhibiting the action of histamine and decreasing the production of gastric acid.

H₂ receptor antagonists, also known as H₂ blockers, are medications commonly used to treat conditions related to excessive gastric acid production, such as gastroesophageal reflux disease (GERD) and peptic ulcers. These drugs work by selectively binding to H₂ receptors present on parietal cells in the stomach.

When histamine, a naturally occurring chemical in the body, binds to H₂ receptors, it stimulates the parietal cells to produce and release gastric acid into the stomach. However, H₂ receptor antagonists competitively bind to the H₂ receptors, preventing histamine from binding and inhibiting its stimulatory effect.

By blocking the H₂ receptors and inhibiting histamine's action, H₂ receptor antagonists reduce the activation of parietal cells and subsequently decrease the secretion of gastric acid. This helps in alleviating symptoms associated with conditions caused by excess acid production, such as heartburn, acid reflux, and ulcers.

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Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

From the question

volume of ethanol = 423 cm³

density = 0.789 g/cm³

So we have

mass = 0.789 × 423 = 333.747

We have the final answer as

Hope this helps you

Answer:

The equation for wave speed can be used to calculate the speed of a wave when both wavelength and wave frequency are known. Consider an ocean wave with a wavelength of 3 meters and a frequency of 1 hertz. The speed of the wave is: Speed = 3 m x 1 wave/s = 3 m/s.

SO... take your meters and hezert and do tha same

Explanation:

Plz mark me as brainlyist

Answer:

Volume occupied by oxygen gas at 15 degree centigrade​ is equal to \(316.5\) centimeter cube

Explanation:

Assuming Pressure is constant.

\(\frac{V_1}{T_1} = \frac{V_2}{T_2}\)

where T1 and T2 are temperature in Kelvin

Substituting the give values we get-

\(\frac{300}{273} = \frac{V_2}{288}\)

\(V_2 = \frac{288*300}{273} \\V_2 = 316.5\)

Volume occupied by oxygen gas at 15 degree centigrade​ is equal to \(316.5\) centimeter cube

In the context of atomic orbital (AO) wavefunctions, the terms "radial node" and "nodal plane" refer to different aspects of the wavefunction's behavior.

A radial node is a region in the AO wavefunction where the probability of finding an electron is zero along the radial direction. In other words, it represents a spherical shell where the electron is unlikely to be found. The number of radial nodes is determined by the principal quantum number (n) of the orbital. For example, the 2s orbital has one radial node, while the 2p orbital has no radial nodes.

On the other hand, a nodal plane is a flat plane within the AO wavefunction where the probability of finding an electron is zero along a particular direction. It represents a surface that divides the orbital into two regions of opposite phases. The number of nodal planes is determined by the angular quantum numbers (l and m) of the orbital. For example, the 2s orbital has no nodal planes, while the 2p orbital has one nodal plane (the xz or yz plane).

Radial nodes arise from the radial part of the wavefunction because they depend on the distance from the nucleus. The radial part determines the distribution of the electron density as a function of distance, and the nodes correspond to regions where the density drops to zero.

On the other hand, nodal planes arise from the angular part of the wavefunction because they depend on the orientation and shape of the orbital. The angular part describes the angular distribution of the electron density around the nucleus, and the nodal planes correspond to regions where the phase of the wavefunction changes sign.

In summary, radial nodes are related to the distance from the nucleus and arise from the radial part of the wavefunction, while nodal planes are related to the orientation and shape of the orbital and arise from the angular part of the wavefunction. The 2s orbital has one radial node and no nodal planes, while the 2p orbital has no radial nodes and one nodal plane.

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Answer:

Subconscious - psychic activity just below the level of awareness

Election - the act of electing someone

Explanation:

I hope this helped enough, good luck in chemistry!

Answer:

I did this but I dont remember

Explanation:

kk

To calculate the weight of Y that would be removed from the water solution with each extraction, we need to use the following steps:

Determine the initial concentration of Y in the water solution. The initial concentration can be calculated using the total mass of Y in the solution, the volume of the solution, and the number of moles of Y per mole of solution.

Determine the amount of Y removed during each extraction. The amount of Y removed can be calculated using the volume of the extraction solvent (in this case, methylene chloride) and the molar mass of Y.

Calculate the final concentration of Y in the water solution after each extraction. The final concentration can be calculated using the initial concentration, the amount of Y removed during each extraction, and the volume of the solution.

Here is the calculation:

The initial concentration of Y in the water solution can be calculated using the total mass of Y in the solution (m), the volume of the solution (V), and the number of moles of Y per mole of solution (n).

Y initial concentration = m / n

For example, if the total mass of Y in the solution is 1.0 g, the volume of the solution is 100 mL, and the number of moles of Y per mole of solution is 1, then the initial concentration of Y in the solution would be 1.0 g / 1 mol/100 mL = 1 g/mL.

The amount of Y removed during each extraction can be calculated using the volume of the extraction solvent (mL) and the molar mass of Y (M).

Y removed per extraction = mL * M

For example, if the volume of the extraction solvent is 70 mL and the molar mass of Y is 120 g/mol, then the amount of Y removed per extraction would be 70 mL * 120 g/mol = 8400 g.

The final concentration of Y in the water solution after each extraction can be calculated using the initial concentration, the amount of Y removed during each extraction, and the volume of the solution.

Final Y concentration after extraction = (initial Y concentration - Y removed per extraction) / V

For example, if the initial concentration of Y in the solution is 1 g/mL, the amount of Y removed per extraction is 8400 g, and the volume of the solution is 100 mL, then the final Y concentration after extraction would be (1 - 8400 g/mL) / 100 mL = 0.1 g/mL.

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Answer:

\(\boxed {\boxed {\sf v \approx0.295 \ mL}}\)

Explanation:

We are asked to find the volume of a metal cylinder. We are given the mass and the density.

We know that density is the mass per unit volume of a substance. It is found using the following formula.

\(\rho= \frac {m}{v}\)

We know the density is 21.0 grams per milliliter and the mass is 6.20 grams. We substitute these values into the formula.

\(21.0 \ g/mL = \frac{6.20 \ g}{v}\)

We are solving for the volume, so we must isolate the variable v. First, cross multiply. Multiply the first numerator by the second denominator, then the first denominator and the second numerator.

\(\frac {21.0 \ g/mL}{1} = \frac{6.20 \ g}{v}\)

\(21.0 \ g/ mL *v= 6.20 \ g * 1\)

\(21.0 \ g/ mL *v= 6.20 \ g\)

v is being multiplied by 21.0 grams per milliliter. The inverse operation of multiplication is division. Divide both sides of the equation by 21.0 g/mL.

\(\frac {21.0 \ g/ mL *v}{21.0 \ g/mL}= \frac{6.20 \ g }{21.0 \ g/mL}\)

\(v= \frac{6.20 \ g }{21.0 \ g/mL}\)

The units of grams cancel.

\(v= \frac{6.20 }{21.0 mL}\)

\(v=0.2952380952\)

The original measurements of density and mass both have 3 significant figures, so our answer must have the same. For this number, 3 sig fig is the thousandth place. The 2 in the ten-thousandth place tells us to leave the 5.

\(v \approx0.295 \ mL\)

The volume of the metal cylinder is approximately 0.295 milliliters.

Answer:

B. gas state at room temperature

Explanation:

The substance combined with germanium that will cause the germanium to emit free electrons is the aluminum. Correct answer: letter D.

Adding aluminum to germanium will cause the germanium to emit free electrons. This is because aluminum has one more electron in its outermost shell than germanium does. When the two atoms are combined, the extra electron from the aluminum will fill the outermost shell of the germanium atom, and the germanium atom will then become unstable and emit an electron.

Aluminum and germanium are elements of the periodic table. Some similarities between the two are:

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To calculate the experimental mass percent of barium in the sample, we need to use the following formula:
Experimental Mass Percent = (Mass of Barium / Mass of Sample) x 100

Given that the mass of the barium collected was 0.844 g and the mass of the sample was 1.52 g, we can substitute these values into the formula to calculate the experimental mass percent:
Experimental Mass Percent = (0.844 g / 1.52 g) x 100
Simplifying the equation:
Experimental Mass Percent = 0.555 x 100
Calculating the value:
Experimental Mass Percent = 55.5%
So, the experimental mass percent of barium in the sample is 55.5%. The experimental mass percent of barium in the sample is 55.5%. To calculate the experimental mass percent, we divided the mass of barium collected by the mass of the sample and multiplied the result by 100. This gives us the proportion of barium in the sample, expressed as a percentage. To calculate the experimental mass percent of barium in the sample, we used the formula (Mass of Barium / Mass of Sample) x 100. Given that the mass of barium collected was 0.844 g and the mass of the sample was 1.52 g, we substituted these values into the formula to calculate the experimental mass percent. By dividing 0.844 g by 1.52 g, we obtained the proportion of barium in the sample. Multiplying the result by 100, we converted this proportion into a percentage. The final result, 55.5%, represents the experimental mass percent of barium in the sample. This calculation allows us to quantify the amount of barium present in relation to the total sample mass.

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Answer:

Explanation:

Let us take our minds back to the kinetic theory of matter. Recall that the particles that compose matter are in constant random motion and the solids are arranged in a definite pattern while the particles of a gas are in random motion.

As such, the zinc has its atoms in a fixed pattern while the hydrogen atoms are roaming freely in the gaseous state.

Given that;

Amount of the acid = 10.95 g/36.5 g/mol = 0.3 moles

Amount of the zinc = 1g/65 g/mol = 0.015 moles

Given the reaction equation; \(Zn(s) + 2HCl(aq) ------ > ZnCl_{2} (aq) + H_{2}(g)\)

1 mole of Zn reacts with 2 moles of acid

0.015 moles of zinc reacts with x moles of acid

x =0.015 moles * 2 moles / 1 mole

= 0.03 moles

Thus, the zinc is the limiting reactant.

1 moles of the zinc produces 1 mole of the hydrogen

The amount of the hydrogen produced =  0.03 moles * 2 g/mol

= 0.06 moles of hydrogen

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Explanation:

Crystallography. an arrangement in space of isolated points (lattice points ) in a regular pattern, showing the positions of atoms, molecules, or ions in the structure of a crystal.

If an atom experiences sufficient thermal activation, it can move to a neighboring lattice position.4 If the vibration frequency of the atom is v and the atom has Z nearest neighbors, the total number of jump attempts is vZ. However, only a small fraction of the attempts will be successful, with a probability depending on the ratio between the necessary activation energy for a single jump QD and the thermal activation kBT. The effective jump frequency ΓD is then

(5.6)

With each successful jump, the atom travels one atomic distance λ and the total traveling distance in unit time is thus ΓDλ. Substituting the jump frequency ΓD into the expression for the root mean square displacement of a random walker [equation (5.5)] and using the spatial coordinate r leads to

For the sample of n sludge specimens is selected and the conclusion and the pH of each one is determined.

A) The null hypothesis is rejected. Sufficient evidence is present for the fact that the true average pH is less than 7.0.

B) The null hypothesis is rejected. Sufficient evidence is present for the fact that the true average pH is less than 7.0.

C) The null hypothesis is rejected. Sufficient evidence is present for the fact that the true average pH is less than 7.0.

D) The null hypothesis is rejected. Sufficient evidence is present for the fact that the true average pH is less than 7.0.

E) The null hypothesis is rejected. Sufficient evidence is present for the fact that the true average pH is less than 7.0.

The null hypothesis in inferential statistics is that two possibilities are always equal. It shows that the underlying assumption is that the observed difference is just the result of chance. It is possible to estimate the probability of the null hypothesis is correct using statistical tests.

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No, none of the gases listed in the table above have molar masses larger than Xe.

Unfortunately, the table you are referring to is not visible.

However, Xenon (Xe) is a heavy noble gas with a molar mass of 131.29 g/mol.

For comparison purposes, you would need to check the molar masses of the gases in your table to determine if any of them have larger molar masses.

Summary: Without access to the table, it is not possible to definitively answer your question, but it is important to compare the molar masses of the gases listed to that of Xenon (131.29 g/mol) to find out if any have larger molar masses.

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Answer:

im just gonna explain how a speaker works and how it can make a window move. So a speaker has a crystal in it that when hit with and electric charge moves like a diaphragm that makes sound waves. the more electricity the slower it moves yet the slower it moves the bigger the movement. Anyway when that crystal moves it also moves the cardboard pice in front of it making a louder sound. The best way to think about it is a sound wave is like wind, its just moving air. so that moving air can push and pull something like a window pane. Cool Huh?

Explanation:

Answer:

Polar molecules occur when there is an electronegativity difference between the bonded atoms. Nonpolar molecules occur when electrons are shared equal between atoms of a diatomic molecule or when polar bonds in a larger molecule cancel each other out

Explanation:

Correct answer is Each orbit has a specific energy level.

Therefore, Correct statement is Each orbit has a specific energy level.

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The complete question is mentioned below:

Which statement about Niels Bohr’s atomic model is true?

a) Higher orbits have lower energies.

b) Each orbit has a specific energy level. c) Electrons can exist in any energy level. d) Orbits close to the nucleus have no energy.

Answer:

yes

Explanation:

Answer:

Yes it can

Explanation:

Answer: No

Explanation:

Answer:

Explanation:

sunlight

soil

water

sugar

carbon dioxide

minerals

leaves

vitamins