Question 3

What is an area that is claimed by one or more

individuals?


A. Population

B. Carrying Capacity

C. Dispersion

D. Territory


Answer is D

Answer:

a. The Zn and HCl both retained their identity.

Answer:

Number of students-this has nothing to do with the question, its called a distractor.

The variable that would most likely not affect the time it takes the ice to melt is the Number of students. The correct option is C.

Variables are the different substances or objects that participate in the experiment directly or indirectly. They are substances that together form the experiment. These variables impact the result of the experiment.

There are two types of variables. They are Dependent and independent variables. Dependent variables can be controlled in the experiment, but independent variables can't be controlled.

Students are performing the experiment, so they cannot be the variables because their presence or absence would be to impact the experiment.

Thus, the correct option is C. Number of students.

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Oxygen is a molecule that is essential for life. It is a colorless, odorless gas that makes up about 20% of the air we breathe.

A molecule is a group of two or more atoms that are held together by chemical bonds. They are the basic building blocks of all matter, and are composed of protons, neutrons, and electrons.

When oxygen is dissolved in water, it can be absorbed by aquatic organisms such as fish. These aquatic organisms use the oxygen to help them with their metabolic processes. When the levels of oxygen in the water are too low, the organisms are not able to survive and may die. Low oxygen levels can occur naturally due to environmental factors like temperature or seasonality, or they can be caused by human activities such as pollution. It is important to keep oxygen levels in the water high to ensure the health of aquatic ecosystems.

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The capacity of an object is measured by its volume. For instance, a cup's capacity is stated to be 100 ml if it can hold 100 ml of water in its brim. Here ice cube has particles that can be drawn closer to occupy smaller volume. The correct option is D.

Due to the strong intermolecular interactions, the solid molecules are very near to one another. Solids have a low volume and a high density as a result. Additionally, the solid molecules cannot be easily crushed due to the narrow intermolecular distance.

So here ice cube has small volume.

Thus the correct option is D.

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Answer:

To find out the number of atoms: MULTIPLY all the SUBSCRIPTS in the molecule by the COEFFICIENT. (This will give you the number of atoms of each element.)

Explanation:

hi hope it helps

306.178 liters is the volume of O2 at STP, required for the complete combustion of 125g octane (\(C_{8}H_{18}\)) to \(CO_{2}\) and H20

To calculate the volume of \(O_{2}\) required for the complete combustion of octane (\(C_{8}H_{18}\)) to \(CO_{2}\) and \(H_{2}O\) at STP (Standard Temperature and Pressure), we need to consider the stoichiometry of the balanced chemical equation.

The balanced equation for the combustion of octane is:

\(C_{8}H_{18}\) + 12.5\(O_{2}\) -> 8\(CO_{2}\) + 9\(H_{2}O\)

From the equation, we can see that 1 mole of octane requires 12.5 moles of \(O_{2}\) to completely combust. The molar mass of octane (\(C_{3}H_{18}\)) is approximately 114.22 g/mol.

To calculate the moles of octane, we divide the given mass by the molar mass:

Moles of octane = 125 g / 114.22 g/mol ≈ 1.093 mol

Since the molar ratio between octane and \(O_{2}\) is 1:12.5, the moles of \(O_{2}\)required can be calculated as:

Moles of \(O_{2}\) = 1.093 mol * 12.5 ≈ 13.663 mol

Now, we can use the ideal gas law, PV = nRT, to calculate the volume of \(O_{2}\) at STP. At STP, the temperature is 273 K, and the pressure is 1 atm.

Using the molar volume of an ideal gas at STP (22.4 L/mol), the volume of \(O_{2}\) required is:

Volume of \(O_{2}\) = Moles of \(O_{2}\) * Molar volume = 13.663 mol * 22.4 L/mol ≈ 306.178 L

Therefore, approximately 306.178 liters of \(O_{2}\) at STP would be required for the complete combustion of 125 grams of octane (\(C_{8}H_{18}\)) to \(CO_{2}\) and \(H_{2}O\)

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B. Hydrogen bonding with polar molecules is the  inter molecular interactions will water participate commonly with polar molecules.

Polarity causes the water molecules to attract each other. Water is polar despite possessing a zero net charge because of the structure of its molecules. The molecule's hydrogen ends are positive, and its oxygen ends are negative. Water molecules are attracted to other polar molecules and to one another as a result.

The polarity of water enables hydrogen bonds to form whenever adjacent water molecules are drawn to each other by their opposing charges. Other polar molecules and ions, such as many biomolecules including sugars, nucleic acids, and certain amino acids, are also attracted to or attracted by water.

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Answer:

1.897 km

Explanation:

1897÷1000=1.897km

you would convert it in to 0.019 km

The number of moles of NaCl that can be produced from 2.5 moles of BaCl₂ is 5.

To determine the number of moles of NaCl that can be produced from 2.5 moles of BaCl2, we first need to balance the chemical equation for the reaction between BaCl₂ and Na₂SO₄:

BaCl₂ + Na₂SO₄  ->  2NaCl + BaSO₄

From the balanced equation, we can see that 1 mole of BaCl₂ reacts with 2 moles of NaCl.

Therefore, we can use a mole ratio to calculate the number of moles of NaCl that can be produced from 2.5 moles of BaCl₂:

2.5 moles BaCl₂ × (2 moles NaCl / 1 mole BaCl₂) = 5 moles NaCl

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The complete question is below:

How many moles of NaCl can be produced from 2.5 moles of BaCl2, when  BaCl₂ reacts with Na₂SO₄?

Answer:

3.48 x 1013 N2 molecules

step-by-step explanation:

Lets set up our equation first

P = 1.00 x 10-6 mm Hg T = 0.0° C + 273 = 273 K

We are given the V = 985 mL ,

R = 0.0821 L·atm/mol·K

Now use the ldeal gas law, but we are solving n, amount of substanvce

PV = nRT, we will change this equation to ;

n = PV/RT

n = 1.00 x 10-6 mm x 1 atm/760 mm x 985 mL x 1 L/103

mL/

(0.0821 L·atm/mol·K x 273 K) = 5.78 x 10-11 moles N2

nmolecules = 5.78 x 10-11 moles N2 x 6.02 x 1023 N2 molecules/1 mol N2

736.84g is the mass of a sample of "impure" ore if it is 47.5 %by mass CuCO3 and produces 350.0 grams of Cu.

Copper(II) carbonate or cupric carbonate is a chemical compound with formula CuCO ₃. At ambient temperatures, it is an ionic solid consisting of copper(II) cations Cu²⁺ and carbonate anions CO²⁻ ₃.

Ore is a naturally occurring rock or silt that has precious minerals in it that may be extracted, processed, and sold for a profit. These minerals are usually metals. Mined ore is then processed or refined, frequently by smelting, to remove the valuable metals or minerals.

To find the total mass of CuCO3 follow the given steps:

Given:

Mass percent=47.5% by mass

Mass of Cu =305.0 g

mass percent = (mass of chemical ÷ total mass of compound) x 100.

Rearranging the above eq.

Total mass of compound= mass of chemical /mass percent*100

Total mass of compound =350/47.5*100=736.84g

Hence, 736.84g is the mass of a sample of "impure" ore if it is 47.5 %by mass CuCO3 and produces 350.0 grams of Cu.

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Answer:

Silicon atoms have 14 protons.

Silicon atoms will react with other atoms in order to gain stability.

Silicon atoms have 14 electrons.

Answer:

my answer is i dont know  to be honest this is hard and i have the same question to thanks

Explanation:

Answer:

Half-life of 150 years are those year that a radioactive element take to disintegrate to a half of it's original value.

I don't have graphical software

Sinve CH3NH2 is weak base and its salt is CH3NH3Cl, mixing 125.0 mL of CH3NH2 and 120.0 mL of CH3NH3Cl so produce a buffer.

A buffer is a solution which resists changes to its pH when a small quantity of strong acid or base is added to it..

A buffer is made from a weak acid and its salt or a weak base and its salt.

From the given options, CH3NH2 is weak base and its salt is CH3NH3Cl.

Therefore, mixing 125.0 mL of CH3NH2 and 120.0 mL of CH3NH3Cl so produce a buffer.

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The number of moles of carbondioxide that can fill the sealed container is 0.261moles.

The number of moles of an ideal gas can be calculated using the ideal gas law equation as follows:

PV = nRT

Where;

According to this question, a sealed container can hold 6.28L carbondioxide at 1.00 atm and 293 K. The number of moles of the gas can be calculated as follows:

1 × 6.28 = n × 0.0821 × 293

6.28 = 24.0553n

n = 6.28 ÷ 24.0553

n = 0.261moles

Therefore, 0.261moles is the number of moles of the gas that can fill the container.

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Answer &

Explanation:

eukaryotic: Having complex cells in which the genetic material is contained within membrane-bound nuclei. cell: The basic unit of a living organism, consisting of a quantity of protoplasm surrounded by a cell membrane, which is able to synthesize proteins and replicate itself.

therefore it is cell

Based on dilution methods, the dilution given is a serial dilution with dilution factor of 1/10.

A serial dilution is the stepwise dilution of a substance in solution usually using a constant dilution factor at each step of dilution.

The above dilution step is a serial dilution.

Therefire, the dilution factor of the dilution above is:

initial volume = 10 mL

final volume = 100 mL

Dilution factor = 10/100

Dilution factor = 1/10

Therefore, the dilution given is a serial dilution with dilution factor of 1/10.

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The jumbled word "gzeysktqix" can be unscrambled to form the word "skyzigtext."

Here are possible words that can be made from this jumbled word:

Sky: Referring to the atmosphere above the Earth.

Zig: Describing a series of sharp turns or angles.

Text: Referring to written or printed words.

Six: The number following five and preceding seven.

It seems that the jumbled word has provided a mix of letters that can be rearranged to form these words. This exercise is likely intended to enhance the student's vocabulary skills, spelling ability, and problem-solving skills. By unscrambling the letters, the student is encouraged to explore different word possibilities and apply their knowledge of language. It also promotes critical thinking and creativity as they find valid words from the given set of letters.

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Answer:

1.67

Explanation:

Mass÷mr=moles

3÷18=1.67

The ideal gas relationships among the variables are PV = nRT

An ideal gas is a theoretical gas composed of many randomly transferring factor particles that aren't difficult to interparticle interactions. the best gasoline idea is beneficial because it obeys the precise gas law, a simplified equation of country, and is amenable to evaluation under statistical mechanics.

Volume is a degree of occupied three-dimensional space. it's far more frequently quantified numerically the usage of SI-derived gadgets or by way of diverse imperial gadgets. The definition of length is interrelated with the extent.

An ideal gas is described as one for which both the extent of molecules and forces between the molecules are so small that they have got no effect on the behavior of the gas. The real gas that acts almost like a really perfect gasoline is helium. that is due to the fact helium, in contrast to maximum gases, exists as an unmarried atom, which makes the van der Waals dispersion forces as low as viable

relation

PV = nRT

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Answer:

hence the correct answer is 52.94 or 53g H2O approx.

A good example of equilibrium would be the mixing of oil and water in a closed container.

Chemical equilibrium is a condition in which the concentrations of components of a chemical reaction remain unchanged and have no tendency to change.

Of all the options, the only one where the concentrations of the component reactants cannot change is a mixture containing oil and water in a closed container.

Oil and water are immiscible and thus, their concentrations remain constant.

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Answer:

Hence, there are approximately $1.686\times {{10}^{22}}$ molecules in 2.3 grams of $N{{H}_{4}}S{{O}_{2}}$.

The freezing point of the solution containing 0.867 m glycerin is -1.61442 °C. Option C is correct

The mass of glucose in 505 mL of 10.5% glucose solution is 53.01 g or 5.30 x 10^2 g.

Option C is correct

To find the freezing point depression of the solution containing 0.867 m glycerin:

ΔTf = Kf * molality

ΔTf = (1.86°C/m) * 0.867 m

ΔTf = 1.61442 °C

The freezing point depression is 1.61442 °C.

The freezing point of the solution is:

Freezing point = 0.0 °C - ΔTf

Freezing point = 0.0 °C - 1.61442 °C

Freezing point = -1.61442 °C

To find the mass of glucose in 505 mL of 10.5% glucose solution:

Mass of glucose = Volume of solution * Density of solution * % mass

Mass of glucose = 505 mL * 1.04 g/mL * 10.5%

Mass of glucose = 53.01 g

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The mass of chlorine (from sodium chloride) in the sample, given that the sample contains 98% sodium chloride is 32.05 grams

First, we shall determine the mass of sodium chloride, NaCl in the sample. Details below:

Mass of NaCl = Percentage of NaCl × Mass of sea water

Mass of NaCl = 98% × 53.9

Mass of NaCl = (98/100) × 53.9

Mass of NaCl = 52.822 g

Finally, we shall determine the mass of chlorine. Details below:

Mass of chlorine, Cl = (Molar mass of Cl / molar mass of NaCl) × Mass of NaCl

Mass of chlorine, Cl = (35.5 / 58.5) × 52.822

Mass of chlorine, Cl = 32.05 grams

Thus, the mass of chlorine in the sample is 32.05 grams

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I would have to go with option

A. Energy must be added, particles must slow down

Hope this helps