Question 3 Not yet answered Marked out of 5.00 P Flag question [5 points] Which of the following statements about fopen is incorrect: a. When used with fopen0, the mode " r " allow us to read from a file. b. fopen0 returns EOF if it is unable to open the file. c. fopen0 function is used to open a file to perform operations such as reading, writing etc. d. fopen0 returns NULL if it is unable to open the file. Question 4 Not yet answered Marked out of 5.00 Flag question [5 points] What are the C functions used to read or write text to a file? a. fscanf, fprintf b. fread, fwrite c. readf, writef d. scanf, printf Question 5 Not yet answered Marked out of 5.00 ∇ Flag question [5 points] a list means accessing its elements one by one to process all or some of the elements. a. None of these b. Creating c. Linking d. Traversing Question 6 Not yet answered Marked out of 5.00 P Flag question [5 points] For a non-empty linked list, select the code that should be used to delete a node at the end of the list. lastPtr is a pointer to the current last node, and previousPtr is a pointer to the node that is previous to it. a. lastPtr->next = NULL; free(previousPtr); b. previousPtr −> next = NULL; delete(lastPtr); c. previousPtr −> next = NULL; free(lastPtr) d. lastPtr->next = NULL; delete(previousPtr); Question 8 Not yet answered Marked out of 5.00 P Flag question [5 points] Which one of these operations requires updating the head pointer? a. Deleting the last node, and the list has only one node. b. Multiplying by two all the data fields. c. Inserting at the end (list is not empty) d. Printing all the data fields in the list [5 points] Consider the following linked list: 25−>10−>30−>40−>35−>60−>55. What will the below function print when called with a pointer to the first node of the above list? void fun(Node* head) \{ Node ∗ ptr = head; while (ptr → next ! = NULL ){ printf("\%d", ptr → data ); \} a. 25103040356055 b. Error or no output c. 251030403560 d. 25 an infinity of times

Answer:

  157.38° CCW from +x axis

  67.38° CCW from +y axis

  n = (12/13)i +(5/13)j

Explanation:

The reference angle is ...

  arctan(15/36) ≈ 22.62° . . . . CW from the -x axis

The signs of the component vectors indicate this is a 2nd-quadrant vector, so the angles of interest are ...

  157.38° CCW from +x axis

  67.38° CCW from +y axis

The unit vector will be ...

  n = cos(157.38°)i +sin(157.38°)j

 n = (12/13)i +(5/13)j

The Airline Tariff Publishing Company (ATPCO) is an airline clearing house that is used by airlines to publish and distribute fares and cargo rates to the travel industry.

What is airline?
The structure and size of airlines differ. Others lease the aircraft for a set amount of time while hiring workers from other businesses, while some purchase the aircraft to provide special services. Typically, it is scheduled from one location to another. Worldwide, airlines play a significant role in the travel business. In order to make the route flexible and accessible, they frequently use jets and helicopters. People frequently mistakenly believe that the airline industry and aviation are interchangeable, which is not the case. It's important to note that the aviation industry includes all businesses related to aviation, including aircraft manufacturers, providers of non-commercial flights, regulatory bodies, aerospace firms, and others. The airline industry, on the other hand, refers to businesses that offer air transport services to paying customers or even for cargo services.

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Answer:

b

Explanation:

Trust me. I am not the smartest though...

By early 1818 Karl Friedrich Schinkel had produced a new design for the Altes Museum in berlin to sit atop the old foundations between existing french and german churches.

What do you mean by design template?

Customizable pre-made designs and documents are known as design templates. Templates are frequently created to adhere to strict guidelines or specifications in order to maintain consistency across users and media. You have the option of creating bespoke templates for later use or using pre-design templates from libraries and websites.

Design templates include color palettes, master slides and titles with personalized formatting, and styled fonts created for a specific "look." The slide master and color scheme of the new template is substituted for those of the previous presentation when a design template is applied to a presentation.

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Answer:

do the wam wam

Explanation:

When creating a long table for a report on employee internet use, Yolanda should use clear headings, organize data logically, consider alternating row colors, utilize appropriate formatting, provide a concise summary, consider breaking the table into multiple pages if needed, and test readability.

When creating a long table for a report on employee internet use, Yolanda should follow the following advice:

By following these guidelines, Yolanda can create a well-organized and reader-friendly table in her report on employee internet use, facilitating understanding and interpretation of the data presented.

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Using the knowledge of computational language in C++ it is possible to write a code that user-input value is the number of nodes in the linked list

#include "MileageTrackerNode.h"

#include <string>

#include <iostream>

using namespace std;

int main(int argc, char *argv[]) {

   // References for MileageTrackerNode objects

   MileageTrackerNode *headNode;

   MileageTrackerNode *currNode;

   MileageTrackerNode *lastNode;

   double miles;

   string date;

   // Front of nodes list

   headNode = new MileageTrackerNode();

   lastNode = headNode;

   // Read in the number of nodes

   int no_nodes;

   cin >> no_nodes;

   // For the read in number of nodes, read in data and insert into the linked list

   MileageTrackerNode *tail = headNode;

   for (int i = 0; i < no_nodes; ++i) {

       double milesInit;

       cin >> milesInit;

       cin >> date;

       MileageTrackerNode *newNode = new MileageTrackerNode(milesInit, date, nullptr);

       tail->InsertAfter(newNode);

       tail = newNode;

   }

   // Call the PrintNodeData() method to print the entire linked list

   MileageTrackerNode *cur = headNode->GetNext();

   while (cur != nullptr) {

       cur->PrintNodeData();

       cur = cur->GetNext();

   }

   // MileageTrackerNode Destructor deletes all following nodes

   delete headNode;

}

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Answer:

Mach number = 0.68168

The flow should be treated as compressible.

Explanation:

Given that:

The altitude of a commercial jet = 35000

The properties of air at that given altitude are as follows:

Pressure = 24.577 kPa

Temperature T = 50.78176° C

Temperature T = ( 50.78176 + 273 )K = 328.78176 K

\(\varphi = 0.38428 \ kg/m^3\)

The velocity is also given as: 550 mph = 245.872 m/s

Therefore, the sonic velocity is firstly determined by using the formula:

\(a = \sqrt{ \vartheta \times R \times T\\)

\(a = \sqrt{1.4 \times 287 \times 323.78176\)

\(a = \sqrt{130095.5112\)

a = 360.68755 m/s

Then, we can calculate the Mach number by using the expression:

\({Mach \ number = \dfrac{V}{a}}\)

\(Mach \ number = \dfrac{245.872}{360.68755}\)

Mach number = 0.68168

b) Ideally, all flows are compressible because the Mach number is greater than 0.3, suppose the Mach number is lesser than 0.3, then it is incompressible.

Answer:

<E1, E2>.

Explanation:

So, in the question above we are given that the Two Electric field vectors E1 and E2 are perpendicular to each other. Thus, we are going to have the i and the j components for the two Electric Field that is E1 and E2 respectively. That is to say the addition we give us a resultant E which is an arbitrary vector;

E = |E| cos θi + |E| sin θj. -------------------(1).

Therefore, if we make use of the components division rule we will have something like what we have below;

x = |E2|/ |E| cos θ and y = |E1|/|E| sin θ

​

Therefore, we will now have;

E = x |E2| i + y |E1| j.

The base vectors is then Given as <E1, E2>.

Answer:

The free body diagram of the system is, 558 368 368 508 O ?? O, Consider the equilibrium of horizontal forces. F

Explanation:

I hope this helps you but I think and hope this is the right answer sorry if it’s wrong.

Answer:

C) Prospective Cohort study

Explanation:

prospective cohort study can be regarded as longitudinal cohort study that comes up with periods of time when group of individuals that are different in terms of some factors that are undergoing some study, so that how theses factors influence rates of some particular outcomes can be known.

Answer:

a)  Δh = 2 cm,  b) Δh = 0.4 cm

Explanation:

Let's start by using Bernoulli's equation for the Pitot tube, we define two points 1 for the small entry point and point 2 for the larger diameter entry point.

            P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

Point 1 is called the stagnation point where the fluid velocity is reduced to zero (v₁ = 0), in general pitot tubes are used  in such a way that the height of point 2 of is the same of point 1

           y₁ = y₂

subtitute

           P₁ = P₂ + ½ ρ v₂²

           P₁ -P₂ = ½ ρ v²

where ρ is the density of fluid  

now we measure the pressure on the included beforehand as a pair of communicating tubes filled with mercury, we set our reference system at the point of the mercury bottom surface

           ΔP =ρ_{Hg} g h - ρ g h

           ΔP =  (ρ_{Hg} - ρ) g h

as the static pressure we can equalize the equations

          ΔP = P₁ - P₂

         (ρ_{Hg} - ρ) g h = ½ ρ v²

         v = \(\sqrt{\frac{2 (\rho_{Hg} - \rho) g}{\rho } } \ \sqrt{h}\)

in this expression the densities are constant

        v = A  √h

       A =\(\sqrt{\frac{2(\rho_{Hg} - \rho ) g}{\rho } }\)

They indicate the density of mercury rhohg = 13600 kg / m³, the density of dry air at 20ºC is rho air = 1.29 kg/m³

we look for the constant

        A = \(\sqrt{\frac{2( 13600 - 1.29) \ 9.8}{1.29} }\)

        A = 454.55

we substitute

       v = 454.55 √h

to calculate the uncertainty or error of the velocity

         h = \(\frac{1}{454.55^2} \ v^2\)

       Δh = \(\frac{dh}{dv}\)   Δv

       \(\frac{\Delta h}{h } = 2 \ \frac{\Delta v}{v}\)

Suppose we have a height reading of h = 20 cm = 0.20 m

a) uncertainty 2.5 m / s ( 0.05)

        \(\frac{\delta v}{v} = 0.05\)

       \(\frac{\Delta h}{h}\) = 2 0.05  

       Δh = 0.1 h

       Δh = 0.1  20 cm

       Δh = 2 cm

b) uncertainty 0.5 m / s ( Δv/v= 0.01)

        \(\frac{\Delta h}{h}\) =  2 0.01

        Δh = 0.02 h

        Δh = 0.02 20

        Δh = 0.1 20 cm

        Δh = 0.4 cm = 4 mm

Answer is given below

Explanation:

Agreement is a official contract. It is written form or even in orally form. The Agreement can be written in formal or informal terms or we can use purely verbal language.

Agreement made between two or more party that allow the court to decide.  

The main 6 elements are:  

1. Offer

2. acceptance

3. consideration

4. intention to create legal relation

5. certainty

6. capacity  

1. The first elements of the contract herein are ABC Sanctions Inc., without the offer, as it is not valid under the Contract Act 1950, Contract Act.

2. Once the offer is made in the contract, acceptance must take place. The agreement must be approved by Northern Inc. When Northern Inc is clear with the offer, it will accept it once the terms and conditions of the agreement are clear.

3. Contrarification is the most important aspect of a contract, when considering a contract, the other person will give something in return. It is considered an exchange between ABC Construction Inc and Northern Inc.

4. It is necessary to have these elements in the contract. Contract law 1950 is one of the requirements of a valid contract, although there is silence about the need for a legal relationship.

5. Another important aspect of the contract is of course. The Contract Agreement sets out the terms and conditions that must be clearly understood by both ABC Contracts Inc and Northern Inc.

6. The ability of a contract to have a legal capacity on either side of the contract is more than eighteen years, since the age of 18 years is specified as the age at which the contract is entered into.

The refrigerator uses 8 x 120 x 4 = 3840 watt-hours of electrical energy in 8 hours.

Electrical power is the rate at which electrical energy is transferred or consumed. It is usually measured in watts (W) or kilowatts (kW). Electrical power is the product of voltage and current. Power (P) = Voltage (V) x Current (I).

Calculate the current flowing through the refrigerator:

I = V/R = 120V/120Ω = 4A

Calculate the watt hours of electrical energy used:

Wh = P x t = V x I x t = 120V x 4A x 8h = 3840Wh

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Answer:

To calculate the steady state flux of atomic hydrogen through a steel vessel, we need to use Fick's first law, which states that the flux (J) is equal to the diffusivity (D) multiplied by the concentration gradient (dC/dx).

First, we need to calculate the concentration gradient by dividing the difference in hydrogen concentration between the inside and outside surfaces by the wall thickness of the vessel. The inside surface is kept saturated with hydrogen at a concentration of 4.5 moles/m3, and the outside surface is exposed to the atmosphere, which has a hydrogen concentration of 0 moles/m3. Therefore, the concentration gradient is (4.5 - 0) moles/m3 / (4 mm) = 1.125 moles/m3 mm.

Next, we need to substitute this value into Fick's first law along with the diffusivity of hydrogen in steel, which is given as 0.1 mm2/s. This gives us the steady state flux as J = (-0.1 mm2/s) * (1.125 moles/m3 mm) = -0.01125 moles/s mm2.

Finally, we need to convert the units of the flux from moles/s mm2 to moles/s m2. To do this, we can multiply the flux by 1,000 to convert the units of millimeters to meters, giving us a final steady state flux of -0.01125 moles/s mm2 * 1,000 = -1.125 moles/s m2.

IF THE VESSEL CONTAINS 20 MOLES OF HYDROGEN, CALCULATE THE TIME TAKEN TO DISSIPATE ALL OF THE HYDROGEN OF THAT THE VESSEL HAS A SURFACE AREA OF 3 M2.

To solve this problem, we need to first calculate the flux of atomic hydrogen through the vessel using Fick's first law:

J = -D(dC/dx)

where J is the flux, D is the diffusivity of hydrogen in steel, and dC/dx is the concentration gradient.

Given that the diffusivity of hydrogen in steel is 0.1 mm2/s, the inside concentration is 4.5 moles/m3, and the outside concentration is 0, the concentration gradient is 4.5 moles/m3.

Plugging these values into the equation above, we get:

J = -0.1 mm2/s * 4.5 moles/m3 = -0.45 moles/s-m2

Next, we need to calculate the time it takes to dissipate all 20 moles of hydrogen from the vessel. We can do this by dividing the total number of moles of hydrogen by the flux:

t = 20 moles / (-0.45 moles/s-m2) = 44.44 s

So it would take approximately 44.44 seconds to dissipate all of the hydrogen from the vessel.

Explanation:

SELF EXPLANATORY

The time taken is 44.44 seconds to dissipate all of the hydrogens from the vessel.

To solve this problem, we need to first calculate the flux of atomic hydrogen through the vessel using Fick's first law:

J = -D(dC/dx)

where J is the flux, D is the diffusivity of hydrogen in steel, and dC/dx is the concentration gradient.

Given that the diffusivity of hydrogen in steel is 0.1 mm²/s, the inside concentration is 4.5 moles/m³ and the outside concentration is 0, the concentration gradient is 4.5 moles/m³.

Plugging these values into the equation above, we get:

J = -0.1 mm²/s * 4.5 moles/m³ = -0.45 moles/s-m²

Next, we need to calculate the time it takes to dissipate all 20 moles of hydrogen from the vessel. We can do this by dividing the total number of moles of hydrogen by the flux:

t = 20 moles / (-0.45 moles/s-m2) = 44.44 s

So it would take approximately 44.44 seconds to dissipate all of the hydrogen from the vessel.

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Answer:

Explanation:

We are assuming that there is

a steady state two dimensional conduction

constant properties

uniform volumetric heat generation

From symmetry, we will be determining 6 unknown temperatures.

See attachment for calculation and and tabulation

With T(s) = 300 K, the set of equations were written directly into the IHT work space and solved for nodal temperatures.

The result is seen in the second attachment

Answer:

True!! took the test

Explanation:

Think about a wholesaler and manufacturer of jams and jellies. To prepare for supply delays, they store extra supplies of raw materials like fruit and sugar on hand.

This serves as their backup supply. In the standard formula, buffer stock is determined as the product of the maximum daily usage (the maximum number of units sold in one day) and the maximum lead time (the length of time it has taken your supplier to ship the stock) minus the product of the average daily usage (the average number of units sold in 1 day). A surplus of raw materials is maintained on hand as a buffer stock to protect against any unanticipated inventory shortages prior to production.

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Answer:

I believe that it is E. Write Verilog HDL models for the machine based on the state diagram in (a) and the D flip-flop sequential circuit that you implement in (b).

Engineering controls are an essential element of hazard control in the workplace, providing a means of minimizing or eliminating hazards at their source.

Engineering controls are a type of hazard control that reduces or eliminates the hazard at its source. Engineering controls are used to minimize or eliminate hazards that pose a significant risk of harm or danger to individuals, such as chemical or noise exposure.

These measures are frequently a vital component of an effective occupational health and safety program in the workplace. Examples of engineering controls include the use of ventilation to control fumes, dust, and other airborne hazards, as well as the use of sound barriers to reduce noise levels. In addition, the use of machine guards, interlocks, and other safety devices on equipment and machinery is considered a form of engineering control to safeguard workers from contact with hazardous moving parts.

Other types of engineering controls include changes in the manufacturing process or the substitution of less harmful materials to eliminate the hazard. Engineering controls are an essential element of hazard control in the workplace, providing a means of minimizing or eliminating hazards at their source. These controls, when combined with other forms of hazard control, such as administrative and personal protective equipment, provide a comprehensive approach to worker safety and health.

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Answer:

219

Explanation:

Unsigned binary number (base two) 1101 1011 converted to decimal system (base ten) positive integer = 219.

Answer:219

Explanation:128+64+16+8+2+1

Answer:

The molecular weight of the gas mixture is 35.38 g/mol.

Explanation:

The molecular weight of the gas can be found using the following equation:

\( M = \frac{m}{n} \)

Where:

m: is the mass = 230 g

n: is the number of moles

First, we need to find the number of moles using Ideal Gas Law:

\( PV = nRT \)

Where:

P: is the pressure = 135 psi

V: is the volume = 15 L

R: is the gas constant = 0.082 L*atm/(K*mol)

T: is the temperature = 465 °R (K = R*5/9)

\(n = \frac{PV}{RT} = \frac{135 psi*\frac{1 atm}{14.6959 psi}*15 L}{0.082 L*atm/(K*mol)*465*(5/9) K} = 6.50 moles\)                

Finally, the molecular weight of the gas is:

\( M = \frac{m}{n} = \frac{230 g}{6.50 moles} = 35.38 g/mol \)

Therefore, the molecular weight of the gas mixture is 35.38 g/mol.

I hope it helps you!

A carpentry hammer with a slightly rounded or convex face used to drive the nail head flush without damaging the surface of the work is called a "finishing hammer".

Finishing hammers are specifically designed for final carpentry work, where the appearance of the finished surface is important. The rounded face helps to prevent marring or denting the material while driving nails.

The handle of a finish hammer is typically made of wood or fiberglass, providing a comfortable grip and absorbing some of the shocks from the striking force. These hammers are commonly used in woodworking, cabinetry, and other fine carpentry applications.

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Answer:

See explaination

Explanation:

please kindly see attachment for the step by step solution of the given problem

Installing the operating system on the HDD and making sure that the partition on the HDD is identified as "active" are the best ways to guarantee that the HDD is immediately recognised as the boot drive.

Why Does My Hard Disk Appear in the BIOS But Not Windows. Most causes would result in this mistake. The operating system's driver is probably incompatible with the drive if it is identified in the BIOS but not in the OS. Moreover, it's conceivable for one drive to support AHCI while the other only supports traditional IDE.

In the BIOS, look at the Hard Disk. If not, spend some time checking the BIOS to see if the hard drive is detected, especially if you're installing an operating system from a bootable USB drive or CD/DVD disc. You may access BIOS settings by holding down F2 while pressing. Check to see if the hard drive appears there.

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Answer: hello the diagram related to your question is missing please the third image is the missing part of the question

Fx = 977.76 Ib/ft

Explanation:

Estimate the force that water exerts on the pier

V = 12 ft/s

D( diameter ) = 6 ft

first express the force  on the first half of the cylinder  as

Fx1 =  - \(-2\int\limits^\pi _\frac{\pi }{2} {Ps*cos\beta *a} \, d\beta\)   ---------------- ( 1 )

where ; Fy = 0

Ps = Po + 1/2 Pv^2 ( 1 - 4 sin^2β )  ------------- ( 2 )

Input equation (2)  into equation ( 1 )         (note :  assuming Po = 0 )

attached below is the remaining part of the solution

The relationship between the usage of maritime fuel (termed "bunker" fuel) per container as the size of a container ship increases is explained as follows: Answer: c) Bunker fuel use per container decreases at an increasing rate as container ship size increases.

Container ships are the largest vessels on the seas today, and they consume a large amount of fuel. The size of a container ship is determined by the number of containers it can transport, which is directly related to its carrying capacity. The larger the vessel, the more cargo it can transport, but this does not imply that it consumes more fuel per container. In reality, as the size of a container ship increases, bunker fuel consumption per container decreases at an increasing rate.This is due to the fact that as ships get larger, their hulls become more efficient at slicing through water, resulting in less resistance. A larger vessel's hull shape may be optimized to minimize drag, allowing it to travel through the water more efficiently. The vessel's size has little impact on how much fuel is needed to transport a container, but it does influence how efficiently the vessel consumes fuel while travelling. As a result, the bunker fuel usage per container decreases as the size of a container ship increases.

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Answer:

Efficiency is defined as any performance that uses the fewest number of inputs to produce the greatest number of outputs. Simply put, you're efficient if you get more out of less.

Explanation: