Question #2
2. Stan walks 10km west to the grocery store. He shops
then walks back 10 km east back to his house. What
distance did he cover? What was his displacement?

Answer: B

Explanation:

You can use the conservation of momentum, under the assumption that no mass was lost when the collision occurred. The initial momentum of the system must equal the final momentum of the system. Our system is the region including, and only including, the satellite and the space debris. Classical momentum is defined as the product of mass and velocity:

\(p_i=p_f\)

\(m_1v_1_i+m_2v_2_i=m_1v_1_f+m_2v_2_f\)

Due to mass 1 equaling mass 2, we can factor these quantities out:

\(m(v_1_i+v_2_i)=m(v_1_f+v_2_f)\)

Cancel the mass term on both sides to get:

\(v_1_i+v_2_i=v_1_f+v_2_f\)

We have the initial and final velocities for everything besides the final velocity of the satellite. Plug everything in:

\(3700m/s+6000m/s=v_1_f+3700m/s\)

\(v_1_f=6000m/s\)

Answer:Lack of experience.

Explanation:

Research from the CDC points to a few key reasons teen drivers are likely to be involved in car accidents: Lack of experience. Teen drivers have triple the fatal crash risk of older drivers, in part because they do not have the skills to recognize and avoid road hazards.

Answer: 8.0 m/s2

Explanation:

F = ma

a = F/m

F = 12,000 N

m = 1,500 kg

a = 12,000 N / 1,500 kg = 8.0 m/s2

Answer:

Sample Response: If the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will increase because the toy car will have a greater acceleration.

Explanation:

Sample Response: If the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will increase because the toy car will have a greater acceleration.

just in case ur one of the people who like to double-check ur answer before turning it in or before u go onto the next thing u have to work on for the day(if ur doing online school) here u go the person above is 100% correct but here it is again if u like to double-check like I do

The creation of an electric current or magnetic field depends on the movement of electrons  is true about electricity and magnetism.

Option A is correct.

The motion and presence of charged particles constitute the essence of electricity. The force that the magnets exert when they attract or repel one another, on the other hand, is referred to as magnetism. As a result, we can see how distinct they are from one another.

Electromagnetism encompasses a variety of phenomena, one of which is magnetism. Ferromagnetic materials, which can be magnetized into permanent magnets and generate their own magnetic fields by being strongly attracted by magnetic fields, exhibit the most well-known effects. A magnet can also be demagnetized.

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Answer:

170 kg

Explanation:

Let's start by drawing a free body diagram for this problem. Let's call the tension in the left rope \(T_1\) and the tension in the right rope \(T_2\).

Now we can construct a free body diagram using the horizontal and vertical components of the two tension forces.

Let's start with the left tension force:

The right tension force:

In order to see what these forces look like on the diagram, look at the first image attached. (1)

Now, we can create the FBD using the components of the tension forces and the force of gravity pulling on the crate, known as w.

The horizontal components of \(T_1\) and \(T_2\) go on the left and right of the FBD, respectively. The two vertical components go on top, and the weight force is on the bottom. We know that weight = mg.

To see what the free body diagram should look like, see the second image attached. (2)

Now that we have the FBD, we can write a system of equations using the sum of forces in both the x- and y-direction.

Since the crate is not moving in either the horizontal or vertical direction, we can say that the net force acting on the crate is 0.

This means that the sum of x forces and the sum of y forces are both 0. Let's set the top and right to be the positive direction and the bottom and left to be the negative direction. Now we can write the system of equations:

There are many ways to solve this system of equations, but I will be showing the top two ways that I tend to solve these types of problems.

Solve for \(T_1 \cdot sin(30)\) and \(T_1 \cdot cos(30)\) in both equations.

We know that \(\frac{sin\theta}{cos\theta}\) = \(tan\theta\), so we can reorder both equations and divide them.

Note that \(\frac{T_1}{T_1}\) cancels, leaving us with tan(30).

Now that we have this equation, we can plug in known values. We are trying to solve for m, the largest mass of the crate that the ropes can support. We know that:

Let's substitute these values into our equation:

Multiply 1500 * cos(45) to both sides of the equation.

Add 1500 * sin(45) to both sides of the equation.

Divide both sides of the equation by 9.8.

Simplify.

The largest mass the ropes can support is around 170 kg (round down, not up).

We can use the system of equations again.

This time, let's do a little guess and check. Using the first equation, plug in 1500 N for T2 and solve for T1.

Divide both sides of the equation by cos(30).

Simplify.

Now plug in 1500 N for T1 and solve for T2.

Divide both sides by cos(45).

Since the tension cannot exceed 1500 N without the rope breaking, we must use the first substitution, where \(T_1=1224.744871\) and \(T_2=1500 \ \text{N}\).

Now we can use these known values and plug them into the second equation: \(T_1\cdot sin(30) = mg - T_2 \cdot sin(45)\)

Add \(T_2 \cdot sin(45)\) to both sides of the equation.

Divide both sides of the equation by g.

Plug in known values and solve for m.

Simplify.

As you can see, we get the same answer with either method. The largest mass the ropes can support is 170 kg.

Answer:

converts elastic energy to mechanical energy

Explanation:

Answer:

16 m/s^2

Explanation:

acceleration tangential = (v^2)/r

a=400/25

a=16 m/s^2

Side note: next time, be more specific when asking about acceleration in circular motion. There's more than one type! Example:

angular acceleration=acceleration tangential/r

angular acc.=16/25

angular acc.=0.64 rad/s^2

Answer: If you want me to write them for you here they are

Explanation:

Net force causes  change in motion because  a net external force causes a change in motion; thus, we see that a net external force causes acceleration.

Not more likely to be Net force motion because if it doesnt say change then its gonna stay the same so Net force does cause change in a motion because  take for example if you are going to bounce a basketball its gonna change its position from one place to another thats how Net force causes Change in motion.  

Hope this helps :)

Consider that the object experiences two forces at time: gravitational force (which is the weight of the object) and friction force due to air resistance. The net force over the object id then:

F = W - Fr

where,

F: net force

W: weight

Fr: friction force = 100.0N

The net force is equal, by Newton second law, to F = m*a, where m is the mass of the object and a is the acceleration.

Then, you have:

m*a = W - Fr

a = (W - Fr)/m

Consider that the weight of the object is:

W = m*g = (17.0 kg)(9.8 m/s^2) = 166.6 N

Then, by replacing the values of W, Fr and m into the expression for a, you obtain:

a = (166.6N - 100.0N)/(17.0kg)

a = 66.6N/17.0kg

a = 3.9 m/s^2

Hence, the acceleration of the object is approximately 3.9 m/s^2

The speed of the roller coaster at the bottom of the hill is 33.9 m/s.

The conservation of mechanical energy is used to determine the speed of the roller coaster at the bottom of the hill, as there is no friction. According to the law of conservation of energy, mechanical energy is constant at all points in a frictionless environment.Let's look at the equation below:PEg + KE = PEg + KEwhere PEg is gravitational potential energy and KE is kinetic energyThe kinetic energy is maximum and the gravitational potential energy is zero when the roller coaster is at the bottom of the hill. The gravitational potential energy is highest when the roller coaster is at the top of the hill, with its potential energy equal to its kinetic energy when it reaches the bottom of the hill.Initially, the roller coaster is at rest at the top of the hill. The gravitational potential energy of the roller coaster is transformed into kinetic energy as it descends the hill. We can calculate the speed of the roller coaster using the law of conservation of energy.Solution:Given,Height of the hill, h = 59.3 mGravitational acceleration, g = 9.8 m/s²Mass of roller coaster, m = 2000 kgWe need to find the speed of the roller coaster at the bottom of the hill, v.To begin, calculate the potential energy at the top of the hill.Potential energy at the top of the hill = mgh Where m is the mass of the roller coaster, g is the acceleration due to gravity, and h is the height of the hill.

The potential energy at the top of the hill is given by:PEg = mgh= 2000 kg × 9.8 m/s² × 59.3 m= 1.15 × 10⁶ JNow, let's figure out the velocity at the bottom of the hill.Using the conservation of energy, we can write,PEg = KE + KEwhere PEg is gravitational potential energy and KE is kinetic energyThe gravitational potential energy is equal to the kinetic energy.KE = PEg= 1.15 × 10⁶ JKE = 1/2 × mv²Where m is the mass of the roller coaster and v is the velocity of the roller coaster.Substituting the given values in the above equation, we get;1.15 × 10⁶ = 1/2 × 2000 × v²v² = (2 × 1.15 × 10⁶) / 2000v² = 1150v = √1150v = 33.9 m/s.

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Answer:

0.610m/s^2

Explanation:

Acceleration is defined as the ΔV/ΔT. In this case, the change in velocity is 1.43-0.32=1.11 m/s. The change in time is 1.82 seconds. Plugging in what we know, it will result in an acceleration of 0.610 m/s^2.

The researcher did not find strong evidence to support the idea that job applicants with popular names are viewed more favorably than equally qualified applicants with less popular names.

It sounds like the researcher conducted an experiment to investigate whether job applicants with popular names are viewed more favorably than equally qualified applicants with less popular names.

Based on the information provided, the researcher found that the differences in the evaluations of the applicants by the two groups were not significant at the .001 level.

The factors that play an important role in the hiring process for a job:

(1) Qualifications and experience: Employers typically look for candidates who possess the necessary qualifications and experience for the job. This includes education, training, certifications, and work experience.

(2) Skills and abilities: Employers also consider a candidate's skills and abilities related to the job. These may include technical, interpersonal, communication, and problem-solving skills.

(3) Personal characteristics: Personal characteristics, such as motivation, work ethic, and adaptability, can also play a role in the hiring process. Employers may look for candidates who demonstrate a positive attitude, a willingness to learn, and the ability to work well with others.

(4) Fit with company culture: Companies may also consider whether a candidate fits with their company culture, values, and mission. This can include factors such as teamwork, creativity, and innovation.

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Answer:

\(Vf^2=Vo^2+2aS\\(0m/s)^2=(4.67m/s)^2+(2*-10m/s^2)S\\-(4.67)^2 m^2/s^2=-20m/s^2*S\\S=(21.8089/20) m\\S=1.090445 m\\\)

The radius of the Rigel bright blue star and the procyan B is found to be   5.4x10¹⁰m and 5.4x10⁶m

Using the surface radiation formula P (energy per second in Watt) = emissivity constant * surface area * Stefan-boltzmann constant * temperature in kelvin4*.

2.7x10³¹ = 1x5.67x10⁻⁸xAx11000⁴

Making A Formula Subject = 2.7x10³¹/ (5.67*10⁻⁸x1.46x10¹⁶) = 0.3261x10²³m²

The surface area = 4R² since the form is a spherical (radius of the Rigel)

R = √ (0.3261x10²³/ 4π) = 5.1 x 10¹⁰m

The radius of the Rigel star is 5.1 x 10¹⁰m.

B) repeating the previous step

2.1x10²³ = 1xAx5.67x10⁻⁸x1000⁴, where A is the Procyon's surface area.

Creating a formula topic,

A = 2.1x10²³/(5.67x10⁻⁸x10¹⁶)

A = 0.37x10¹⁵

The star is thought to be a spherical;

A = 4R², where R is Procyon's radius.

R = √(0.37x10¹⁵/4π) = 5.4x10⁶m

The radius of the Procyan B is  5.4x10⁶m.

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The force on the larger piston of cross-sectional area 230 cm² is 11500 N.

Force can be defined as the product of mass and acceleration.

To calculate the force on the larger piston, we use the formula below.

Formula:

Where:

From the question,

Given:

Susbtitute these values into equation 1

Hence, the force on the larger piston is 11500 N.

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Determine the magnitude of B-A is 53.68

1.4

Magnitude is a term used to describe size or distance. We can relate the magnitude of the movement to the size and movement speed of the object. The magnitude of a thing or an amount is its size. A car moves at a faster pace than a motorcycle, just in terms of speed.

Magnitude is the relative size of an object (mathematics). The mathematical term for a vector's length or size is the norm. By using the symbol |v|, the magnitude of a vector formula can be utilized to determine the length of a given vector (let's say v). This amount is essentially the distance between the vector's beginning point and ending point.

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It takes the car 13.2 seconds to stop

The car travels 19.2 m while stopping

The coefficient of kinetic friction, μ = 0.224

The initial velocity, u = 28.9 m/s

The final velocity, v = 0 m/s

The force acting in the x-direction is:

The time taken for the car to stop can be calculated using the formula:

The distance travelled

Answer:

3600 N

Explanation:

F=ma

1200*3 = 3600

A hollow glass sphere has a density of 1.3g/cm at 20 C. Glycerine has a density of 1.26 g/cm at 20 C.

To determine the temperature at which the hollow glass sphere begins to float in glycerine, we need to calculate the density of glycerine at various temperatures and compare it to the density of the glass sphere.

The density of glycerine changes with temperature, so we need to use a density-temperature chart or equation to determine the density of glycerine at different temperatures.

Assuming the hollow glass sphere has a uniform wall thickness, we can calculate its volume by subtracting the volume of the hollow interior from the volume of the whole sphere

Volume of sphere = (4/3)π\(r^{3}\)

Volume of hollow interior = (4/3)π\((r-t)^{3}\)

Volume of glass wall = (4/3)π(\(r^{3}\) - \((r-t)^{3}\)), where t is the thickness of the glass wall.

From the density and volume of the glass sphere, we can determine its mass

Mass of glass sphere = Density of glass sphere x Volume of glass sphere

Next, we can use Archimedes' principle to determine the volume of glycerine displaced by the glass sphere when it is submerged in the glycerine

Volume of glycerine displaced = Mass of glass sphere / Density of glycerine at the given temperature

When the glass sphere floats, the volume of glycerine displaced will be equal to the volume of the glass sphere. Thus, we can set the two volumes equal to each other and solve for the temperature at which the density of glycerine matches the density of the glass sphere

Volume of glass sphere = Volume of glycerine displaced

(4/3)π\(r^{3}\) - (4/3)π\((r-t)^{3}\) = Mass of glass sphere / Density of glycerine at the given temperature

Hence, for the temperature requires knowing the radius and thickness of the glass sphere and the mass of the sphere.

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B. The equivalent resistance of the two resistors is 20.0 ohms.

C. The voltmeter will measure the voltage across the 30.0 ohm resistor.

D. The 30.0 ohm resistor will stop working.

B. The total resistance of the circuit is 60.0 ohms. This is because the 30.0 ohm resistor and the 60.0 ohm resistor are in parallel, and the equivalent resistance of two resistors in parallel is equal to the product of the resistors divided by the sum of the resistors.

R_T = 1/(1/R_1 + 1/R_2 + ...)

In this case, the product of the resistors is:

30.0 ohms × 60.0 ohms = 1800 ohms,

and the sum of the resistors is:

30.0 ohms + 60.0 ohms = 90.0 ohms.

Therefore, the equivalent resistance of the two resistors is 1800 ohms / 90.0 ohms = 20.0 ohms.

C. Meter 1 is an ammeter, and it is connected in series with the 30.0 ohm resistor. This means that the ammeter will measure the current flowing through the 30.0 ohm resistor.

Meter 2 is a voltmeter, and it is connected in parallel with the 30.0 ohm resistor. This means that the voltmeter will measure the voltage across the 30.0 ohm resistor.

D. When the switch is opened, the 30.0 ohm resistor will stop working. This is because the switch is in series with the 30.0 ohm resistor, and when the switch is opened, the circuit is broken.

The 60.0 ohm resistor will continue to work, because it is in parallel with the switch, and the current will continue to flow through the 60.0 ohm resistor even when the switch is opened.

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The centripetal force acting on the small piece of dried cement is 0.01 N   when mass 50 g stuck to the inside wall of mixer.

Any force that alters velocity in the direction toward the center of a circular motion is referred to as a centripetal force. The centripetal force is produced by the portion of the force that is perpendicular to the velocity.

The period of the cement mixer can be calculated as:

                                T = 50 sec/rev

                                     = 2πr/v,

where r is the radius of the mixer and

v is the velocity of the piece of dried cement.

Solving for v, we get v = 2πr/T.

Substituting the given values, we get

                               v = 2π(2.5 m)/(50 sec/rev)

                                         = 0.314 m/s.

The centripetal force acting on the piece of dried cement can be calculated using the formula :

                                     F = m v² / r,

where m is the mass of the cement,

v is the velocity, and

r is the radius of the mixer.

Substituting the given values, we get

                                 F = (0.05 kg)(0.314 m/s)²/(2.5 m)

                                                      = 0.01 N.

Therefore, the centripetal force acting on the small piece of dried cement is 0.01 N.

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Answer:

573

Explanation:

totally not stealing previous answer cause I know it's right

The wavelength of the light is 578.45 nm.

Light passing through a double slit with separation is given as

d = 2.42 × 10⁻⁵ m.

Line number m = 2

Angle θ = 2.74°

     The distance between two sound waves i.e., crest and trough is called the wavelength.

To find the wavelength, here we use the formula as,

               sin θ = Line number × λ ÷ ( distance )

By substituting all the given values,

              Sin ( 2.74° ) = 2 × λ ÷ ( 2.42 × 10⁻⁵ )

Rearranging the equation,

                 λ= (Sin ( 2.74° ) ×  ( 2.42 × 10⁻⁵ ) ) ÷ (2)

                  λ = 578.45 nm.

Thus, wavelength λ of the light is 578.45 nm.

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Answer:

The acceleration is \( a = 0.889 \ m/s^2\)

Explanation:

From the question we are told that

The mass of the engine is \(m = 4500 \ kg\)

The mass of each Boxcar is \(m_b = 1500 \ kg\)

The tension between the locomotive and boxcar A is \(T = 4000 \ N\)

Generally the tension between the locomotive and boxcar A is equivalent to the net force propelling the box cars so the tension is mathematically represented as

\(T = F = M* a\)

Here M is the mass of the three box cars

=>       \( 4000=  (3 * 1500)* a\)

=>         \( a =  0.889 \  m/s^2\)

The statement that describes the net force on an object is the sum of all forces acting on an object (option A).

Net force is sum of all forces acting on an object in a single plane.

When a force is applied to a body, not only is the applied force acting, there are many other forces like gravitational force, frictional force and the normal force that balances the other force.

The sum of all these forces acting on the object whether in the same or opposite direction is regarded as the net force.

Therefore, the statement that describes the net force on an object is the sum of all forces acting on an object.

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Answer:

Density=10.50kg/m³

Explanation:

\(Solution,\\Height(h)=0.5m\\Radius(r)=0.4m\\Now, \\Volume=\pi r^{2} h\\\\Volume=\pi *(0.4m)^{2} *0.5m\\\\Volume=0.251327m^{3} \\\\Again,\\\\Density=\frac{mass}{volume} \\\\Density=\frac{2.640kg}{0.251327} \\\\Density=10.50kg/m^{3}\)

The density of the cylindrical rod is 10.516 kg/m³.

To calculate the density of the cylindrical rod, we can use the formula:

\(\rm \[\text{{Density}} = \frac{{\text{{Mass}}}}{{\text{{Volume}}}}\]\)

The mass of the rod is given as 2.640 kg. To find the volume, we can use the formula for the volume of a cylinder:

\(\rm \[\text{{Volume}} = \pi \times \text{{radius}}^2 \times \text{{height}}\]\)

Substituting the given values:

\(\[\text{{Volume}} = \pi \times (0.4 \, \text{{m}})^2 \times 0.5 \, \text{{m}}\]\)

Calculating the volume:

\(\[\text{{Volume}} = \pi \times 0.16 \, \text{{m}}^2 \times 0.5 \, \text{{m}}\]\\\\text{{Volume}} = 0.251 \, \text{{m}}^3\]\)

Now we can substitute the mass and volume values into the density formula:

\(\[\text{{Density}} = \frac{{2.640 \, \text{{kg}}}}{{0.251 \, \text{{m}}^3}}\]\)

Calculating the density:

\(\[\text{{Density}} = 10.516 \, \text{{kg/m}}^3\]\)

Therefore, the density of the cylindrical rod is 10.516 kg/m³.

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