Question 2 of 10
What charge does an ion have if it has more protons than electrons?
O A. Neutral, since protons are inside the nucleus
B. A net positive charge
C. A net negative charge
O D. No charge
SUBMIT

Answers

Answer 1
B. A net positive charge
Answer 2

Answer:

B. A net positive charge

Explanation:

a p e x 2021!


Related Questions

What is the mass (in grams) of 3.03 × 1024 molecules of carbon dioxide molecules?

Answers

1 mole of CO2 has 6.02 x 10^23 molecules of CO2. Say x moles of CO2 has 3.0x10^23 molecules of CO2. Therefore x = 3/6.02 = 0.50. M = 0.50 * (12 + 2x16) = 0.50 * 44 = 22g

We have that for the Question "" it can be said that the mass (in grams) of 3.03 × 1024 molecules of carbon dioxide molecules is

Amount of CO_2(g)=221.35g

From the question we are told

What is the mass (in grams) of 3.03 × 1024 molecules of carbon dioxide molecules?

Generally the equation for the   is mathematically given as

\(No moles in 3*02*10^{24}=\frac{3.03*10^{24}}{6.023*10^-{23}}\)

No moles in 3*02*10^{24}=5.03moles

Amount of CO_2(g)=5.03moles *44g/mol

Amount of CO_2(g)=221.35g

Hence

the mass (in grams) of 3.03 × 1024 molecules of carbon dioxide molecules is

Amount of CO_2(g)=221.35g

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See photo please!! I only have 10 mins

See photo please!! I only have 10 mins

Answers

Answer:

0.30 ug of U-235

Explanation:

N = N0 * (1/2)^(1/2)

0.15 ug = N0 * (1/2)^(1/2)

N0 = 0.15 ug / (1/2)^(1/2)

N0 = 0.30 ug

Answer:

B

Explanation:

The decay of U-235 follows an exponential decay model, which can be described by the equation:

N = N0 * (1/2)^(t/T)

where N is the amount of U-235 at a given time t, N0 is the initial amount of U-235, t is the elapsed time, and T is the half-life of U-235.

In this case, we know that the sample has undergone two half-lives, which means that the elapsed time is:

t = 2 * T

We also know that the amount of U-235 in the sample is 0.15 ug. We can use this information to solve for the initial amount of U-235 (N0):

N = N0 * (1/2)^(t/T)

0.15 = N0 * (1/2)^(2)

0.15 = N0 * (1/4)

N0 = 0.15 / (1/4)

N0 = 0.60 ug

Therefore, the amount of U-235 that was originally present in the sample before it decayed was 0.60 ug. The answer is B) 0.60 ug.

Even more:

It's not A) 0.30 ug because if the sample originally contained 0.30 ug of U-235 and underwent two half-lives, the amount of U-235 remaining would be:N = N0 * (1/2)^(t/T)

N = 0.30 * (1/2)^(2)

N = 0.30 * (1/4)

N = 0.075 ug

This means that the amount of U-235 in the sample after two half-lives would be 0.075 ug, which is not consistent with the given information that the sample contains 0.15 ug of U-235.

Therefore, the correct answer is B) 0.60 ug, which is the initial amount of U-235 that would have been present in the sample before it decayed.

you need to make 700 ml of 5.0% (w/v) naoh solution. you have a bottle of 10.0% (w/v) naoh solution, which you must dilute to the correct concentration. what volume of the 10.0% solution should you use, and how much water must you add to it?

Answers

M1: Nook's necessary concentration is 5.0% (w/v).

V1 = final volume of solution, 400 mL

M2 = 10.0% (w/v) of the present NaOH concentration

V12 equals the initial volume of the solution.

Due to the fact that w/v% = weight of solute / volume of solution * 100

and the solute's mass will always be the same.

Mass of NaOH in solution is given by M1 X V1.

By the Mass Conservation Law: According to the law of conservation of mass or principle of mass conservation, any system that is closed to all transfers of matter and energy must maintain a constant mass over time since the system's mass cannot vary and neither more nor less amount can be added or subtracted.

M2 X V2 = M, X V1

M., M2, and 1/2's slow values in the equation above

500 x 400 ML = 10.0% x V2

V₂ = 200 mL

10.0 volume. utilized solution = 2.0 x 10 mL x 200 M L

Volume of goods added is calculated as [Y1 - V2 = 400-200=200ML = 2.0 = 2.0 x 102m/]

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Why does the human eye see different colors?

Answers

Answer:

Light receptors within the eye transmit messages to the brain, which produces the familiar sensations of color. Newton observed that color is not inherent in objects. Rather, the surface of an object reflects some colors and absorbs all the others. We perceive only the reflected colors.

enough of a monoprotic acid is dissolved in water to produce a 1.48 m solution. the ph of the resulting solution is 2.80 . calculate the ka for the acid.

Answers

The Ka value for the monoprotic acid on dissociation is found to be 16.44.

The dissociation of monoprotic acid HA is as,

HA = H⁺ + A⁻

So, the Ka value is defined as,

Ka = [H⁺][A⁻]/[HA]

The pH of a compound is given as,

log([H⁺]) = pH

The given pH is 2.8, so,

log([H⁺]) = 2.8

[H⁺] = 16.44 M.

Now,  as we can see from the equation,

[H⁺] = [A⁻] = [HA]

So, putting the values for Ka,

Ka = [H⁺][A⁻]/[HA]

Ka = 16.44×16.44/16.44

Ka= 16.44

So, the value of Ka for this acid is 16.44.

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Iron(III) hydroxide undergoes thermal decomposition to form iron(III) oxide and
water.
Calculate the mass of Fe₂O3 formed from the decomposition of 17.2g of Fe(OH)3,
assuming a 40% yield. Give your answer to 3 significant figures.
2Fe(OH)3(s)
Fe₂O3(s)
+
3H₂O(g)
[4 marks]

Answers

The mass of Fe₂O₃ formed from the  decomposition of 17.2g of Fe(OH)₃ , with yield assuming to be 40% is 5.14 g (upto three significant figures).

The reaction in which one reactant breaks down to form two or more different products is known as decomposition reaction.

The decomposition reaction of Fe(OH)₃ takes place as:

2Fe(OH)₃  (s) →   Fe₂O₃(s) + 3H₂O(g)

Firstly, we will find out the relative formula mass of Fe(OH)₃ and  Fe₂O₃.

The sum of the relative atomic masses of atoms present in a molecule is known as the relative formula mass of that molecule.

Relative formula mass of Fe(OH)₃

= ( 56+ 16×3+1×3)g

=(56+48+3)g

=107g

Relative formula mass of Fe₂O₃

=(56×2+16×3)g

=(112+48)g

=160g

From the equation we get,

2 × 107g  Fe(OH)₃ gives= 160g Fe₂O₃

∴ 17.2g Fe(OH)₃  will give

= (160×17.2)/(2×107) g  Fe₂O₃

=12.85 g Fe₂O₃

And, 40% yield

= 40/100 × 12.85

=5.14 g

Hence, assuming 40% yield, the mass of Fe₂O₃ formed from the decomposition of 17.2g of Fe(OH)₃ is 5.14 g

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Phospholipid molecules that prevent the alveoli from collapsing are known as ______. A) laryngitis. B) surfactant. C) mucus. D) plasma.

Answers

B) Surfactant is a phospholipid molecule that prevents alveoli from collapsing. It reduces surface tension in the lungs, allowing the alveoli to remain open and facilitating efficient breathing.

Phospholipid molecules that prevent the alveoli from collapsing are known as surfactants. Surfactant is a substance composed of phospholipids, proteins, and other components. It is produced by specialized cells in the lungs called type II alveolar cells.

The primary function of surfactant is to reduce the surface tension within the alveoli, which are tiny air sacs in the lungs where gas exchange takes place. Without surfactant, the surface tension would be too high, causing the alveoli to collapse during exhalation. Surfactant molecules disrupt the cohesive forces between water molecules on the alveolar surface, allowing the alveoli to remain open and preventing them from sticking together. The presence of surfactant is crucial for efficient breathing and maintaining lung function. In conditions where surfactant production is reduced or absent, such as in premature infants or certain lung diseases, respiratory distress syndrome and other breathing difficulties can occur.

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Which of these most likely occurs to result in the formation of these mountains?

Which of these most likely occurs to result in the formation of these mountains?

Answers

You already answered the question?

Answer:

thanks

Explanation:

youre awesome

How do I convert 3.221×10^−3 mm to standard notation

Answers

Answer:

0.003221

Explanation:

When we multiply anything by 10 times a power, we follow the base 10 decimal system.

To convert 3.221 × 10⁻³ from scientific notation to standard notation, simply move the decimal place 3 places to the left:

3.221 × 10⁻³ = 0.003221

The answer is 0.003221

A hydrogen atom is excited from its ground state to the n= 4 state. The atom subsequently emits three photons, one of which has a wavelength of 1882 nm. What are the wavelengths of the other two photons?

Answers

The wavelength of the first line (n=4 to n=3) in the Balmer series is 656.3 nm. The wavelength of the second line (n=4 to n=2) in the Balmer series is 486.1 nm. The wavelength of the third photon, calculated above, is 594.1 nm.

The hydrogen atom has a single electron in its shell. Electrons in a hydrogen atom have a set of allowed energy levels. The ground state has the lowest energy level, and n represents the electron's energy level in the hydrogen atom.

Electrons gain energy and rise to a higher energy level when they are stimulated by energy from an external source such as an electric current or a photon beam.The hydrogen atom is said to be excited when its electron absorbs energy and rises to a higher energy level.

The excited atom then emits the energy in the form of electromagnetic radiation, which includes visible light and other wavelengths.The hydrogen atom has a characteristic spectrum due to the transitions between its energy levels. The wavelengths of photons absorbed or emitted when electrons in a hydrogen atom move between energy levels are determined by the following equation:

E=(hc)/λ whereE = energy of the photonh = Planck's constanctc = speed of lightλ = wavelength of the photonLet us now determine the wavelengths of the other two photons. When a hydrogen atom is excited from its ground state to the n=4 state, it emits a series of spectral lines known as the Balmer series.

The Balmer series is a series of lines in the visible light region of the spectrum. The wavelength of the first line (n=4 to n=3) in the Balmer series is 656.3 nm. The wavelength of the second line (n=4 to n=2) in the Balmer series is 486.1 nm.The third photon's wavelength can be calculated as follows

:Energy of the photon = (hc)/λEnergy of the photon = (6.626 x 10^-34 J s) x (2.998 x 10^8 m/s) / (1882 x 10^-9 m) = 3.328 x 10^-19 JThe wavelength of the third photon is calculated as follows: Energy of the photon = (hc)/λ3.328 x 10^-19 J = (6.626 x 10^-34 J s) x (2.998 x 10^8 m/s) / λλ = (6.626 x 10^-34 J s) x (2.998 x 10^8 m/s) / (3.328 x 10^-19 J)λ = 594.1 nmThe first two wavelengths are given by the Balmer series.

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How does carbon dioxide gas in the atmosphere cause climate change?

Answers

carbon dioxide controls temperature because the carbon dioxide molecules in the air absorb infrared radiation. The carbon dioxide and other gases in the atmosphere are virtually transparent to the visible radiation that delivers the sun's energy to the earth. carbon dioxide is released through natural processes such as respiration and volcano eruptions and through human activities such as deforestation, land use changes, and burning fossil fuels.


Can someone do a True or false for these

Can someone do a True or false for these

Answers

Answer:

all i can accurately say is that 2 and 4 are both true

In addition to the name of the chemical, and all special warnings, what else must be on the label of all stock solutions prepared in the lab?

Answers

In addition to the name of the chemical and any special warnings, there are several other important pieces of information that should be included on the label of stock solutions prepared in the lab. These include:

1. Concentration: The concentration of the stock solution should be clearly indicated. This can be expressed as molarity (M), percentage (%), or other appropriate units.

2. Date of Preparation: It is important to include the date when the stock solution was prepared. This helps in tracking the age and shelf life of the solution.

3. Storage Conditions: The recommended storage conditions should be provided, such as temperature, light sensitivity, or any other specific requirements to maintain the stability and integrity of the solution.

4. Hazard Symbols or Codes: If the chemical is hazardous, it is important to include the appropriate hazard symbols or codes, such as GHS (Globally Harmonized System) pictograms, to indicate the potential risks associated with the solution.

5. Safety Precautions: Any necessary safety precautions or handling instructions should be clearly stated, including the use of personal protective equipment (PPE), ventilation requirements, and handling procedures.

6. Batch or Lot Number: If applicable, a batch or lot number can be included to help with traceability and quality control.

It is essential to ensure that all information on the label is accurate, up-to-date, and compliant with local regulations and safety standards. Properly labeled stock solutions help to minimize the risks associated with handling and using chemicals in the laboratory.

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Explain the concept law of diminishing marginal rate of substitution. What is/are the reason/s why the law of diminishing marginal rate of substitution suggest/s that isoquant must be bent toward the origin?

Answers

The law of diminishing marginal rate of substitution indicates that the rate at which one input can be substituted for another decreases as the quantity of one input increases, leading to isoquants being bent toward the origin.


In other words, as the quantity of one good increases, the individual is willing to sacrifice fewer units of the other good to obtain an additional unit of the first good. This reflects a diminishing rate of substitution between the two goods.

The reason why the law of diminishing marginal rate of substitution suggests that isoquants must be bent toward the origin is rooted in the concept of diminishing marginal utility. As more units of a particular input (e.g., labor or capital) are added while holding other inputs constant, the additional output gained from each additional unit of the input will decrease. This diminishing marginal productivity leads to a decreasing MRS.

When isoquants (which represent different combinations of inputs that produce the same level of output) are bent toward the origin, it reflects the fact that as more of one input is used, the amount of the other input that needs to be substituted decreases. This bending signifies the diminishing MRS and captures the idea that a larger quantity of one input can be substituted for a smaller quantity of the other input to maintain the same level of output.

Overall, the law of diminishing marginal rate of substitution indicates that the rate at which one input can be substituted for another decreases as the quantity of one input increases, leading to isoquants being bent toward the origin.


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calculate the equilibrium constant at 25°c for a reaction for which ∆g° = -4.22 kcal/mol.

Answers

The equilibrium constant (K) for the reaction at 25°C is approximately 1203.56.

To calculate the equilibrium constant (K) at 25°C for a reaction with a given standard Gibbs free energy change (ΔG°), you can use the following equation:

ΔG° = -RT ln(K)

where ΔG° = -4.22 kcal/mol, R is the gas constant (in kcal/mol·K), and T is the temperature in Kelvin.

1. Convert the temperature to Kelvin: T = 25°C + 273.15 = 298.15 K
2. Convert R to kcal/mol·K: R = 0.001987 kcal/mol·K
3. Rearrange the equation to solve for K: ln(K) = -ΔG° / (RT)
4. Substitute the values: ln(K) = -(-4.22 kcal/mol) / (0.001987 kcal/mol·K × 298.15 K)
5. Calculate ln(K) ≈ 7.094
6. Find K by taking the exponent: K = e^(7.094) ≈ 1203.56

The equilibrium constant (K) for the reaction at 25°C is approximately 1203.56.

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how many molecules are there in 360cm3 of nitrogen as r.t.p

Answers

Answer:

9.68x10^21 molecules of nitrogen

Explanation:

I will assume that r.t.p. is supposed to be STP, Standard Temperature and Pressure.  rtp might refer to room temperature and pressue, but no value is given for room temperature, so let's assume standard temperature (0 degrees Celsius).  Here is a marvelous, and useful, property of gasses at STP:  One mole of gas at STP occupies 22.4 liters.  Let's make that a conversion factor:  (1 mole/22.4 liters).

We have the volume of gas at STP:  360 cm^3.  Convert that into liters:

(360cm^3)*(1 ml/cm^3)*(1 liter/1000 ml) = 0.360 liters(L)

Now use the conversion factor from above to convert the volume of gas into moles of gas:

 (0.360L)*(1 mole/22.4 liters) = 0.0161 moles of gas

By definition, 1 mole is 6.02x10^23 particles, or molecules of the gas.

Convert moles of the gas to molecules:

(0.0161 moles)*((6.02x10^23 molecules)/mole) = 9.68x10^21 molecules of nitrogen.

How many grams is 40.48 moles of cobalt?

Answers

Answer:

2385.49 grams of cobalt.

Explanation:

1. Convert 40.48 moles of Co (cobalt) into grams (mass):

The molar mass of cobalt is 58.933195 g/mol.

\(40.48 mol Co = \frac{58.93 g/mol}{1 mol Co} = 2385.49 g\)

How many grams of sodium iodide must be used to produce 44.8 grams of iodine in the following reaction? NaI+Cl2→I2+NaCl

Answers

26.4 grams of sodium iodide must be used to produce 44.8 grams of iodine in the given reaction : NaI+Cl₂→I₂+NaCl

The amount of sodium iodide (NaI) required to produce 44.8 grams of iodine (I₂) in the given reaction, we need to consider the balanced chemical equation and the molar masses of the substances involved.

The balanced equation shows that 1 mole of sodium iodide (NaI) reacts to produce 1 mole of iodine (I₂).

The molar mass of iodine (I₂) is 253.8 grams/mol.

Using these values, we can set up a proportion to calculate the amount of sodium iodide needed:

(44.8 g I₂) / (253.8 g/mol I₂) = (x g NaI) / (149.9 g/mol NaI)

Solving for x, the amount of sodium iodide needed, we have:

x = (44.8 g I₂) × (149.9 g/mol NaI) / (253.8 g/mol I₂)

x ≈ 26.4 grams

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The image below shows two types of plant cells under a microscope.

root cells and leaf cells

Which statement explains the difference in chloroplasts between the two types of plant cells?

Answers

Unlike the leaf cells, the root cells have no chloroplasts because root cells do not need to produce or use energy. Option A

What is the cell?

We have to note that the cell is the smallest part of an organism that can have independent existence. We know that the microscope is the device that we can be able to use to view the cells.

Now, we know that the cell is composed of the organelles of the cell. The organelles of the cell include the chloroplast of the cell as well as the cell wall of the cell.

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Missing parts;

The image below shows two types of plant cells under a microscope.

root cells and leaf cells

Which statement explains the difference in chloroplasts between the two types of plant cells?

A.

Unlike the leaf cells, the root cells have no chloroplasts because root cells do not need to produce or use energy.

B.

Unlike the root cells, the leaf cells have many chloroplasts because leaf cells produce sugars for the plant.

C.

The root cells have smaller chloroplasts because root cells do not need to store food and water.

D.

The leaf cells have larger chloroplasts because leaf cells need more support and a stronger structure.

What is the outcome of hotspots? Question 13 options: Formation of islands Constant volcanic eruptions Divergent boundary interaction Convergent boundary interaction.

Answers

Answer:

Constant volcanic eruptions Hope this helps!

Express the measurement 0.530060 g three significant figures

Answers

Answer:

0.530 g.

Explanation:

The express the measurement 0.530060 g we need to remember first that:

- The zeros to the left of the amount do not count as significant figures

- All non-zero numbers count as significant figures

- The zeros that are between digits significants are significant figures

Hence, the three significant figures of the measurement 0.530060 g are:

0.530060 g = 0.530 g            

Therefore, the three significant figures of the measurement 0.530060 g are 0.530 g.

I hope it helps you!

Does the diagram below demonstrate an endothermic or an exothermic reaction? Explain your reasoning.

PLEASE BE ACCURATE!!! Thank you so much!!:))

Does the diagram below demonstrate an endothermic or an exothermic reaction? Explain your reasoning.PLEASE

Answers

Answer:

Endothermic reaction.

Explanation:

The reactants are at a lower energy rate than the products. Because delta H is positive, energy is absorbed from the surroundings.

using only polarizing lters (the second element under the polarization section) create a con guration such that the detector only detects 6% of the initial photons. what is the minimum number of polarizing lters required to achieve this?

Answers

The minimum number of polarizing filters required to achieve a configuration such that the detector only detects 6% of the initial photons would be two.

Polarizing filters are used to transmit light waves that are polarized in a specific direction and block light waves that are polarized in a perpendicular direction. When two polarizing filters are placed in series, the intensity of the light that passes through both filters is proportional to the product of the transmissions of each filter.

Let's assume that the transmission of each polarizing filter is represented by T. If we want the detector to only detect 6% of the initial photons, we can write the equation as follows:

0.06 = T₁ × T₂

Since T represents the transmission of each polarizing filter, it must be a value between 0 and 1. To minimize the number of polarizing filters required, we want T₁ and T₂ to be as close to 1 as possible. So, we can choose T₁ and T₂ to be equal to 0.2:

0.06 = 0.2 × 0.2

Therefore, the minimum number of polarizing filters required to achieve a configuration such that the detector only detects 6% of the initial photons is two.

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--The given question is incomplete, the complete question is

"Using only polarizing filters (the second element under the polarization section) create a configuration such that the detector only detects 6% of the initial photons. what is the minimum number of polarizing filters required to achieve this?"--

Can someone help
Me out pls if your good at chemistry

Can someone helpMe out pls if your good at chemistry

Answers

No lo sé dímelo tú jsjsjsjs

What was the second most used type of material during the 1960 s? Select one:a) Semiconductors b)Composites c) Metals d) Polymers and Elastomers e) Ceramics and glasses

Answers

The correct answer to the given question is option c) Metals.

What were the materials used during the 1960s?

The materials used during the 1960s included metals, ceramics, glasses, semiconductors, polymers, and elastomers.

The 1960s were a period of significant technological advances.

A number of new and innovative materials emerged during this time that would shape the world for decades to com. Metals were the second most used material during the 1960s. During this time, there was significant demand for materials that could withstand high temperatures and pressures, as well as resist wear and tear and corrosion .Metals were used for a wide range of applications, including the construction of aircraft, automobiles, and other machinery.

They were also used in the production of electronic components, such as resistors and capacitors, and for the manufacture of a wide range of consumer goods, from kitchen utensils to jewellery. Metals remain a critical material in today's world, with a wide range of applications in industries ranging from aerospace and automotive to electronics and construction.

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Which of the following polysaccharides can people eat and digest?
animals
plants
plant fibers
none of the above

Answers

Answer:

animals

plants

Explanation:

Polysaccharides are complex organic sugars formed from simple sugars called monosaccharides.

Human beings can digest the polasaccharides found in many plants and animals without qualms.

However, human beings lack the enzymes required for the digestion of plant fibers. As such human beings can not digest plant fibers. The excrete them out in feces.

Thus the polysaccharide that can not be digested by people are plant fibers.

which statement(s) regarding metal ion indicators in edta titrations is/are true? metal ion indicators are compounds that change color when they bind to a metal ion. useful indicators must bind the metal ion less strongly than edta does. metal ion indicators are also acid-base indicators.

Answers

Metal ion indicators are compounds that change color when they bind to a metal ion. They are commonly used in EDTA (ethylene diamine tetraacetic acid) titrations, where EDTA acts as a chelating agent, binding to the metal ion to form a stable complex.

One important characteristic of a useful metal ion indicator is that it must bind the metal ion less strongly than EDTA does. This is because EDTA is typically added in excess to ensure complete complexation of the metal ion, and a strong metal ion indicator would compete with EDTA for the metal ion and interfere with the accuracy of the titration.

Metal ion indicators are not necessarily also acid-base indicators, but some can be both. In EDTA titrations, pH plays an important role in determining the stability of the metal-EDTA complex, so an indicator that can monitor pH changes as well as metal ion binding can be useful.

In summary, metal ion indicators are compounds that change color when they bind to a metal ion, and useful indicators must bind the metal ion less strongly than EDTA does.

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which of the following solutions has a greater concentration of hydronium ions? solution a has a ph of 8.0. solution b has a ph of 13.5.

Answers

Solution A with pH of 8 has greater concentration of hydronium ions as compared to solution B with pH of 13.5.

pH = -log [H3O+]. By using the opposite mathematical procedure from that used to determine the pH, the hydronium ion concentration can be calculated from the pH.

The pH lowers as the hydronium content rises, making the fluid more acidic. When an acid is introduced, this happens. The solution's hydronium concentration rises when H+ ions separate from the acid and join with water to produce hydronium ions.

Any time an acid dissolves in water, the hydronium ion is created. The nearest water molecule is always where the acid's H+ moves to produce H3O+. Take the perspective of the proton (H+) to see the hydronium ion from a different angle. Hydration refers to the addition of water to anything.

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Calculate the mass in grams, in 2.28 mol of SO3 .

Answers

The mass of 2.28 mol of SO₃ is 182.4 g.

What is mass?

Mass can be defined as the quantity of matter a body contains.

The S.I unit of mass is kilogram (kg). other units of mass include grams (g), milligram (mg), microgram (μg) etc.

What is a matter?

A matter is anything that has mass and occupies space. Matter exist in three states.

Solid stateLiquid stateGaseous state

To calculate the mass of 2.28 mol of SO₃, we use the formula below.

Formula:

m = nM............. Equation 1

⇒ Where:

m = mass of SO₃n = number of mole of SO₃M = molar mass of SO₃

From the question,

Given:

n = 2.28 molM = 80 g/mol

Substitute these values into equation 1

m = 2.28×80m = 182.4 g

Hence, the mass of 2.28 mol of SO₃ is 182.4 g.

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to the best of your knowledge, classify each of the following as an element, compound, or mixture. explain how your everyday experiences influenced your response. a. silver coin b. air c. coffee d. soil

Answers

a. Silver coin - Element (Silver is a pure element and is not chemically combined with any other element in a silver coin)

b. Air - Mixture (Air is a mixture of gases, primarily nitrogen and oxygen, with trace amounts of other gases and particles)

c. Coffee - Mixture (Coffee is a mixture of various compounds such as water, caffeine, and organic compounds that give it its flavour and aroma)

d. Soil - Mixture (Soil is a mixture of various substances such as minerals, organic matter, water, and air)

My everyday experiences influenced my response because I have come across these examples in my daily life and have been taught about them in science classes. For example, I know that air is composed of different gases and particles, and that soil is made up of a mixture of substances, including minerals and organic matter. Similarly, I know that a silver coin is made of pure silver and that coffee is made of various compounds.

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