Answers
When the scientists draw conclusions the scientist find out whether the hypothesis was supported.
A hypothesis is a theory put up to explain a phenomenon. A hypothesis cannot be called a scientific hypothesis unless it can be tested using the scientific process.
Once your experiment is complete, you collect your measurements and analyze them to see if they support your hypothesis.
Scientists frequently discover that their hypotheses and predictions were not supported by the results of their experiments. In these circumstances, they will discuss the results of their experiment before reevaluating their initial theories and predictions in light of the fresh information. The scientific method is essentially restarted in this way. Even if they discover that their theory was correct, they could still wish to verify it once more using a different approach.
The correct option is (a).
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Related Questions
Given: g=10 m/s^2
A car moves a distance of 80 m during
a time interval of 10 s. The average
speed v_avg of this car is:
2 m/s
6 m/s
O 10 m/s
O 8 m/s
O 4 m/s
Answers
During a 10-second period, a car travels 80 meters. This car typically travels at a speed of 8 m/s.
An illustration of average velocity.For instance, if it takes a person 40 minutes to travel 20 miles north, 20 miles south, and finally 20 miles in between, their average speed is 40 miles divided by 40 minutes, or 1 mile per minute. Instead of distance, average velocity takes into account total displacement.
How is average velocity calculated?The total displacement must be divided by the total time elapsed in order to determine the average velocity.
average velocity= total displacement/ total time
avg velocity=80/10=8m/s
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What is the chemical formula for magnesium sulfide?
Answers
Answer:
MgS
Explanation:
In Physics lab, a lab team places a cart on one of the horizontal, linear tracks with a fan attached to it. The cart is positioned at one end of the track, and the fan is turned on. Starting from rest, the cart takes 4.34 s to travel a distance of 1.62 m. The mass of the cart plus fan is 354 g. Assume that the cart travels with constant acceleration.
A) What is the net force exerted on the cart-fan combination?B) Mass is added to the cart until the total mass of the cart-fan combination is 762 g, and the experiment is repeated. How long does it take for the cart, starting from rest, to travel 1.62 m now?
Answers
Answer:
A. F = 0.06 N
B. t = 6.37 s
Explanation:
A)
First we need to find the constant acceleration of the cart. For this purpose, we use 2nd equation of motion:
s = (Vi)(t) + (0.5)at²
where,
s = distance traveled = 1.62 m
Vi = 0 m/s (Since, it starts from rest)
t = Time Taken = 4.34 s
a = acceleration = ?
Therefore,
1.62 m = (0 m/s)(4.34 s) + (0.5)(a)(4.34 s)²
1.62 m/9.4178 s² = a
a = 0.172 m/s²
Now, from Newton's Second law, we know that:
F = ma
where,
F = Net Force of the combination = ?
m = Mass pf combination = 354 g = 0.354 kg
Therefore,
F = (0.354 kg)(0.172 m/s²)
F = 0.06 N
B)
Now, for the same force, but changed mass = 762 g = 0.762 kg, we have the acceleration to be:
F = ma
a = F/m
a = 0.06 N/0.762 kg
a = 0.08 m/s²
Now, using 2nd equation of motion:
s = (Vi)(t) + (0.5)at²
1.62 m = (0 m/s)(t) + (0.5)(0.08 m/s²)t²
t² = 1.62 m/(0.04 m/s²)
t = √40.54 s²
t = 6.37 s
Two spheres, 1.00 kg each, whose centers are 2.00 m apart, would have what gravitational force between them? A. 3.14 X 10-17 N
B. 1.67 X 10-11 N
C. 8.17 X 10-6N
D. 5.78 X 10-6 N
Answers
Answer: B
Explanation: the teacher just told us the answer
The gravitational force between the two spheres is \(1.67 \times 10^{-11} \ N\).
The given parameters;
mass of each sphere, m = 1.00 kgdistance between their center mass, r = 2 mThe gravitational force between the two spheres is determined by applying Newton's law of universal gravitation as shown below;
\(F = \frac{Gm_1 m_2 }{r^2} \\\\\)
where;
G is universal gravitation constant = 6.67 x 10⁻¹¹ N/m\(F = \frac{(6.67\times 10^{-11})\times (1\times 1)}{2^2} \\\\F = 1.67 \times 10^{-11} \ N\)
Thus, the gravitational force between the two spheres is \(1.67 \times 10^{-11} \ N\).
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What is the term used when a ball is hit and the batter reaches the following bases safely (without being called out)?
please help me
a) first base
b)second base
c)third base
d) homerun
Answers
Samir is waiting for a slow reaction to finish. What is the best way to make the reaction go faster?
Question 12 options:
Put it in the fridge where it is cold
Cover it with a blanket so it's dark
Warm it up on the stove
There is nothing you can do to change the speed of the reaction
Answers
In general, option c - warming it up on the stove - is often an effective method to increase the reaction rate.
Increasing the temperature of a reaction generally leads to faster reaction rates. This is because higher temperatures provide more thermal energy to the reactant particles, causing them to move faster and collide more frequently. The increased collision frequency and energy lead to more successful collisions and a higher likelihood of effective molecular interactions, which speeds up the reaction. On the other hand, options a and b - putting it in the fridge where it is cold or covering it with a blanket to make it dark - are unlikely to have a significant effect on the reaction rate. While temperature can influence reaction rates, cooling the reaction or making it dark typically reduces the kinetic energy of the particles, resulting in slower reaction rates. Option d - there is nothing you can do to change the speed of the reaction - is not accurate. The reaction rate can be influenced by various factors such as temperature, concentration, catalysts, and surface area, among others. By manipulating these factors, it is often possible to control and change the speed of a reaction. Hence option c, is correct
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In an experiment, a group of students will determine the dielectric constant of paper. They have the following materials available, as well as other materials traditionally available in a high school physics lab. _____ Aluminum foil _____ Sheets of paper _____ Sheets of plastic _____ Multimeters with the ability to measure capacitance(a) Outline an effective experimental procedure to gather the necessary data that can be used to determine the dielectric constant of paper. Place a check mark next to each item above that the students should use. Draw a labeled diagram to represent the setup used for this procedure.The table below shows data from a different experiment in which students measure the capacitance of different setups as they vary the distance between the two plates of the capacitor, the area of the plates, and the material inserted between the plates.Trial Capacitor Dielectric Distance Between the Plates ( m ) Area of the Plates ( m2 ) Capacitance ( F )1 paper 1.00×10−4 0.04 8.1×10−92 paper 1.00×10−4 0.09 18.3×10−93 paper 1.00×10−4 0.16 32.6×10−94 paper 1.00×10−4 0.25 49.8×10−95 paper 2.00×10−4 0.25 23.1×10−96 paper 3.00×10−4 0.25 18.9×10−97 paper 4.00×10−4 0.25 14.9×10−98 paper 5.00×10−4 0.25 9.2×10−99 plastic 1.10×10−4 0.04 11.3×10−910 plastic 1.10×10−4 0.09 25.3×10−911 plastic 1.10×10−4 0.16 45.1×10−912 plastic 1.10×10−4 0.25 70.4×10−913 plastic 2.20×10−4 0.25 35.2×10−914 plastic 3.30×10−4 0.25 23.5×10−915 plastic 4.40×10−4 0.25 17.6×10−916 plastic 5.50×10−4 0.25 14.1×10−9(b)i. What subset of the experimental trials would be most useful in creating a graph to determine the dielectric constant of paper? Explain why the selected trials are most useful.ii. Indicate below which quantities should be graphed to yield a straight line whose slope could be used to calculate a numerical value for the dielectric constant κ of paper.Vertical axis: Horizontal axis:(c) Plot the data points for the quantities indicated in part (b)(ii) on the graph below. Clearly scale and label all axes including units, if appropriate. Draw a straight line that best represents the data.(d) Use the data to determine a value for κ of paper.(e) On the axes below, sketch the Capacitance C as functions of plate separation d, plate area A, and dielectric constant κ.
Answers
(a) The students should use aluminum foil, sheets of paper, sheets of plastic, and multimeters with the ability to measure capacitance for the experiment.
What is dielectric constant?Dielectric constant, also known as relative permittivity, is a measure of a material's ability to store electrical energy in an electric field. It is defined as the ratio of the electric flux density produced by an applied electric field to the electric flux density that would be produced by the same electric field in a vacuum.
An effective experimental procedure to determine the dielectric constant of paper could involve the following steps:
Cut two pieces of aluminum foil and attach them to opposite sides of a sheet of paper using tape, leaving a small area of the foil exposed.
Measure the area of the exposed foil using a ruler and calculate the capacitance of the capacitor using a multimeter with the ability to measure capacitance.
Repeat step 2 for different distances between the plates of the capacitor by adjusting the distance between the foil pieces and measuring the capacitance at each distance.
Plot the capacitance versus distance data on a graph and determine the slope of the best-fit line.
Calculate the dielectric constant of paper using the slope of the best-fit line and the equation C = κεA/d, where C is the capacitance, A is the area of the plates, d is the distance between the plates, ε is the permittivity of free space, and κ is the dielectric constant of paper.
(b)
i. The trials with paper inserted between the plates and varying distances between the plates would be most useful in creating a graph to determine the dielectric constant of paper. Specifically, trials 1-5 would be most useful, as they all use paper as the dielectric material and vary the distance between the plates.
ii. The capacitance C should be graphed on the vertical axis, and the reciprocal of the distance between the plates (1/d) should be graphed on the horizontal axis to yield a straight line whose slope could be used to calculate the dielectric constant κ of paper.
(d) Using the data from trials 1-5 and the graph in part (c), the slope of the best-fit line is 3.77 x 10^-9 F/m. Using the equation C = κεA/d and the measured values of A and d, and ε (permittivity of free space), we can solve for the dielectric constant κ of paper as:
κ = Cd/εA = (3.77 x 10^-9 F/m) / [(8.85 x 10^-12 F/m) x (0.04 m^2)] = 10.7
Therefore, the dielectric constant of paper is approximately 10.7.
(e) See attached image for sketches of Capacitance C as a function of plate separation d, plate area A, and dielectric constant κ. The capacitance rises as the space between the plates gets closer. With a rise in plate area, the capacitance also grows. Last but not least, the capacitance increases as the dielectric constant increases at a certain plate gap and area.
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Newton's Three laws talk about all of the following:
Inertia, Mass, Force, Acceleration, and Velocity.
Which of these five things is involed/relevent to all three laws? Explain why.
Answers
1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point. What is the heat of fusion of the substance?
Answers
1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point , the heat of fusion of the substance is 548 joules .
What is heat of fusion ?Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.
Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.
q = m×∆Hf
q: Total change in heat energy (in Joules)
∆Hf: Heat of fusion of substance (in Joules per gram)
m: Mass of substance (in grams)
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The laboratory exercise for this chapter addresses kinematic motion. You have experienced these motions in everyday life. Instead of a discussion board requiring posts in a forum, this assignment has been modified to accept your response to the following questions in this assignment. Be sure to clearly address each of the points below and show all of your work • What is the difference between a vector and a scalar quantity? • List two examples each of vector and scalar quantities • Write the due date of this assignment: Month and Day (For example, July 15 would be Month - 7. Day = 15) • For a building having a height equal to the quantity you have recorded for Day in meters in our example 15 meters), compute the time required for the ball to fall to the ground while experiencing acceleration due to gravity (g=9.8m/s) • How fast was the ball traveling when it hit the ground? Submit the kinetics Assignment by 11:59 p.m. (ET) on Monday,
Answers
Answer:
A) vectors: veloicty, force
scalar: speed, work
B) t = 1.75 s, C) v = - 17 2 m / s
Explanation:
We answer each part separately
A) A vector magnitude has magnitude and direction instead a scalar magnitude has only magnitude
vector quantities: the speed of a car number is the magnitude and direction is where it goes
Force, the number is the magnitude and above that applies gives direction
Scalar magnitude: how quickly the number of the speedometer of the car
Temperature, work
B) I = 15 m height to the soil and get to calculate time = 0
y = y₀ + v₀ t - ½ g t²
as the ball is loose its initial velocity is zero
0 = 0 +0 - ½ g t²
t = \(\sqrt{2y_o/g}\)
t = \(\sqrt{2 \ 15/ 9.8}\)
t = 1.75 s
C) the velocity to the reach the floor
v = vo - g t
v = 0 - g t
v = - 9.8 1.74
v = - 17 2 m / s
The negative signt iindicates that the speed goes down
Which of the following statements best describes the situation in
which the "constant-acceleration model" appears to fail to describe
the motion of an object (say, a leaf falling from a tree).
In practice, no object's motion is actually very close to the constant acceleration model.
DIf the conditions required for the constant-acceleration model are not present, then the model
may not describe the motion very well.
Any difference between the observed motion and the motion predicted by the constant-
acceleration model must be the result of measurement error.
Answers
We want to see which statements describe the siutuations where "constant-acceleration motion" fails.
We will see that the correct option is the first one.
"In practice, no object's motion is actually very close to the constant acceleration model."
We need to analyze each statement.
1) In practice, no object's motion is actually very close to the constant acceleration model.
This is true, for example, if we return to the leaf example, we usually would say something that "a falling object is only affected due to gravitational acceleration" and we assume that the acceleration is constant, but this is actually false, as there are a lot of other forces like friction or air resistance that also contribute. These forces also depend on the shape of the falling object and the velocity at which it falls, so the contributions to the acceleration are not constants, thus the acceleration is not constant.
2) the conditions required for the constant-acceleration model are not present, then the model may not describe the motion very well.
The conditions are not stated and depend on the particular situation, so this does not fit really well.
3) Any difference between the observed motion and the motion predicted by the constant- acceleration model must be the result of measurement error.
This is false, while yes, obviously, if you have a measurement error the predictions will be wrong, but even in the case where your measures are flawless, the constant-acceleration model ignores some things that contribute to the motion (are kinda small contributions, this is why we ignore them) so a lot of differences will be due to these contributions that we are ignoring.
So the correct statement is the first one.
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A woman stands still holding a 350 Newton bag (about 80 pounds) 2 meters off the ground. How much work does the woman do?
Answers
Answer:
700 Joules
Explanation:
What we know:
Force = 350 Newton
Distance = 2 meters
Work = ?
The formula for work is:
Work = force x distance
Plugging values into equation:
Work = 350 Newtons x 2 meters
Work = 700 Joules
I had the same question on the homework assignment with the answers provided:
a) It depends on how long she holds the bag
b) 350 Joules
c) none
d) 350 Newtons
The final answer would be c) none. The work done is 700 Joules. Hope this helps!
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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Skills Practice
4. Starting from one shore, you swim east across a narrow river to the other shore.
The river is 19.0 m wide. As you swim, the river current moves you north up the
river a distance of 12.0 m. Draw a diagram representing this situation What is you
resultant displacement? Express your answer in components, and then determin
the magnitude.
Answers
Answer:you think i know jesus im in y8 i barley know any g anyway someone asked me something that only albert eientsien knew .
Explanation:
I'm also cluless but i feel good for helpig other people out
The question involves calculating the resultant displacement of swimming across a river while also being carried north by the current. In this scenario, the eastward displacement is 19.0 m, and the northward displacement due to the current is 12.0 m. Using these vectors, the total displacement can be calculated as approximately 22.36 m.
Explanation:The subject of this question is Physics, specifically the concept of calculating displacement, which is a vector quantity. To solve this, we start by setting up a vector diagram. One vector represents your direction of swimming (east), which is 19.0 m long. The other vector represents the direction of the river current (north), which is 12.0 m long. The resultant displacement is the hypotenuse of the right-angled triangle they form. To calculate this magnitude, express your displacement in components: The eastward displacement is (19.0 m, 0) and the northward displacement is (0, 12.0 m). Finally, we can determine the resultant displacement using the Pythagorean theorem (sqrt[(19.0m)^2 + (12.0m)^2]), which gives a magnitude of approximately 22.36 m.
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What method do you use to purify water contaminated with salt and microorganisms
Answers
The water purification procedure, such as filtration, sedimentation, distillation, etc.
Which method of purification disinfect water from microorganisms?Analysis of the reduction in microbes that is enough to protect against the transmission of pathogens in water is debated below. Chlorination is the most widely used method for disinfecting water supplies in the United States.
The most efficient way to desalinize salt water is by using a method called distillation. This is where you boil the water and then assemble the condensation. The steam will provide fresh salt-less water for you to drink.
So we can conclude that Chlorination is the activity of adding chlorine to drinking water to kill parasites bacteria and viruses.
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what i have learned
complete the statements below. write your answers on a separate sheet of paper
even before the advent of the telescope ancient aastronomers were able to observe the following
Answers
Even before the advent of the telescope, ancient astronomers were able to observe the following:
1. Celestial Bodies: Ancient astronomers could observe celestial bodies such as the Sun, Moon, stars, and planets. They could track their movements across the sky and study their patterns and behaviors.
2. Solar and Lunar Eclipses: By carefully observing the positions of the Sun, Moon, and Earth, ancient astronomers could predict and witness solar and lunar eclipses. They noticed that during a solar eclipse, the Moon blocks the Sun's light, creating a temporary darkness on Earth, while during a lunar eclipse, the Earth casts a shadow on the Moon, causing it to appear reddish or darkened.
3. Stellar Positions: Ancient astronomers mapped and observed the positions of stars in the night sky. They recognized patterns and constellations, which helped them navigate and keep track of time.
4. Seasons and Celestial Movements: By observing the changing positions of the Sun and its daily and yearly motions, ancient astronomers could understand the changing seasons. They could determine solstices, equinoxes, and the length of days and nights.
5. Comet Appearances: Ancient astronomers were able to observe and document the appearance of comets in the night sky. They recognized these celestial objects as distinct from stars and noted their unusual and transient nature.
These observations formed the basis of ancient astronomy and laid the groundwork for the development of more advanced astronomical techniques and instruments, including the telescope.
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Electronic flash units for cameras contain a capacitor for storing the energy used to produce the flash. In one such unit, the flash lasts for a time interval of 1.50×10^−3 s with an average light power output of 2.90×10^5 W
a) If the conversion of electrical energy to light has an efficiency of 90.0 % (the rest of the energy goes to thermal energy), how much energy must be stored in the capacitor for one flash?
b) The capacitor has a potential difference between its plates of 125 V when the stored energy equals the value calculated in part A. What is the capacitance?
Answers
Answer:
(a) E = 483.33 J
(b) C = 0.062 F = 62 mF
Explanation:
(a)
First we need to calculate the energy output for one flash. For that purpose we have the formula:
E₀ = Pt
where,
E₀ = Energy output for one flash = ?
P = Light Output Power for one flash= 2.9 x 10⁵ W
t = time interval for one flash = 1.5 x 10⁻³ s
Therefore,
E₀ = (2.9 x 10⁵ W)(1.5 x 10⁻³ s)
E₀ = 435 J
Now, for energy to be stored in capacitor, we use the following formula:
Efficiency = E₀/E
where,
E = Energy required to be stored in capacitor for one flash = ?
Efficiency = 90% = 0.9
Therefore,
0.9 = 435 J/E
E = 435 J/0.9
E = 483.33 J
(b)
The energy stored in the capacitor is given by the formula:
E = (1/2)(CV²)
where,
C = Capacitance = ?
V = Voltage = 125 V
Therefore,
483.33 J = (1/2)(C)(125 V)²
C = (483.33 J)(2)/(125 V)²
C = 0.062 F = 62 mF
When an electromagnetic wave such as light interacts with a solid and polarizes the electron clouds within the atomic structure of that solid, what are the (2) primary consequences of this interaction
Answers
Answer:
1. Absorption or Emission of the light
2. Light induced changes in the matter
Explanation:
When an electromagnetic wave such as light interacts with solid, two consequences are for sure:
1. Absorption or Emission of the light
2. Light induced changes in the matter
When light travels through the solid, the intensity of light decreases as a result of addition of light energy to the body to which it interacts. If the medium or body to which light interacts is low in absorbing due to its atomic structure inside then light passing through it will show it. On the contrary, if a material is high in absorbing, very less intensive light will travel out.
Moreover, there will ionization of the atoms inside the medium to which light interacts. As light carries energy and when it interacts with atoms of the body, atoms gets energy and excited or de-excited accordingly.
Hence, above are the two primary consequences of this interaction.
A 3.8kw elective motor powers an inclined conveyer belt. It is designed to lift heavy boxes from the warehouse floor to loading bay. Answer the following:
a)State the energy conversion performed by the motor
b) Calculate the work done by the motor in 14 s
c) If the conveyer belt takes 14 to lift its load vertically by 5.3m, calculate the maximum mass that can carried by the conveyer belt maximum mass that can be carried by the conveyer belt
d) If a small box were to fall off the conveyer belt and hit the floor, calculate the speed at which it would hit the ground if falls from a vertical height of 4.7m
Answers
Answer:
See the answer below
Explanation:
To solve this problem we must use the definition of power and work in physics.
a)
The function of the conveyor belt is to carry the boxes from an initial point that is at low altitude to an end point that is at high altitude. In this way the conveyor belt prints a speed to the box to be able to raise it to the required vertical distance.
Since we have a velocity at the beginning and then we place the box at a high position, where then the box remains at rest, we can say that it converts kinetic energy to potential energy.
b)
Power is defined as the relationship of work over time. Therefore we have:
\(P=W/t\)
where:
P = power = 3.8 [kW] = 3800 [W]
W = work [J]
t = time = 14 [s]
\(W=P*t\\W=3800*14\\W= 53200[J] = 53.2[kJ]\)
c)
Since the given time is equal to the given time at Point b, we can use the same work calculated.
We know that work is defined as the product of force by the distance traveled.
\(W =F*d\)
So, the force is equal to:
\(F=W/d\\F=53200/5.3\\F=10037.73[N]\)
Now we know that force is defined as the product of mass by gravitation acceleration.
\(F =m*g\)
where:
F = force or weight = 10037.73 [N]
g = gravity acceleration = 9.81 [m/s²]
m = mass [kg]
\(m=F/g\\m = 10037.73/9.81\\m = 1023.2 [kg]\)
d)
This part can be solved by means of the energy conservation theorem, where the potential energy is transformed into kinetic energy or vice versa.
\(E_{pot}=m*g*h = E_{kin}=0.5*m*v^{2}\)
where:
h = elevation = 4.7 [m]
v = velocity [m/s]
\(m*g*h=0.5*m*v^{2}\\g*h=0.5*v^{2} \\v=\sqrt{\frac{g*h}{0.5} } \\v=\sqrt{\frac{9.81*4.7}{0.5} } \\v = 9.6 [m/s]\)
person a and b traveling away from each other. It takes person a 2 hours to travel a full circle, and person b 5 hours to travel a full circle. how much time will it take for a and b to meet?
Answers
Let the circumference of the circle be 10L.
A moves at 10L/2 = 5L per hour
B moves at 10L/5 = 2L per hour
Therefore it takes 10L/(5L+2L) = 10/7 hours
A boat accelerates uniformly from rest to a speed of 10 m/s over a distance of 50 m. (a) Determine the acceleration of the bike. (b) how long will take to do that? ТУЛ in this 34 A boat accelerates uniformly from rest to a speed of 10 m / s over a distance of 50 m . ( a ) Determine the acceleration of the bike . ( b ) how long will take to do that ?
Answers
Answer:
See below
Explanation:
Average speed = (0+ 10)/2 = 5 m/s
then to cover 50 m will take 50 m / 5 m/s = 10 seconds
change in velocity/ change in time = acceleration = 10/10 = 1 m/s^2
can someone help me pleaseenkwnsn
Answers
If a third resistor is added in SERIES, what changes happens to the....
a. Total Voltage - stay the same b. Total Current - decrease c. Total Resistance - increase d. Voltage through resistor 1 - decrease e. Current through resistor 1 - decreaseWhat happens in a circuit?When you add a third resistor in series, the total resistance of the circuit increases. This is because the current has to flow through all three resistors, so it has to overcome more resistance. The total voltage across the circuit stays the same, because the voltage of the battery is constant. However, the current decreases, because the same amount of current is now flowing through a larger resistance.
The voltage across each resistor also decreases, because the total voltage is divided among the three resistors. The current through each resistor also decreases, because the same current is now flowing through a larger resistance.
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A plane flying horizontally at 377 m/s releases a package at an altitude of 15,770 m. How long will the package take to reach the ground?
Answer:
Unit:
Answers
Answer:
An object is called a horizontal projectile if it is launched from a certain height with some initial horizontal velocity only. The initial vertical velocity of such an object is zero. But as the object falls through the atmosphere the horizontal component of velocity remains constant but vertical component increases due to gravitational acceleration.
Explanation:
Find the force between charges of +10.0 C and -50.0 C located 20.0 cm apart.
Answers
Answer: SI
Explanation:
I heat 29.292 g of an unknown metal up to 99.9 °C. While it is heating, I weigh out 27.777 g of water, and find its initial
temperature is 22.1 "C. When I mix the metal and water in an insulated container, the temperature of the mixture rises
to 29.3 °C.
What is the most likely specific heat of the metal?
Select one:
a. 4.8 (104) cal / (g *C)
b. 9.7 (102) cal/(g*C)
c. 7.9 (10³) cal/ (g*C)
Od: 0.13 cal / (g°C)
e. 9.8 (105) cal / (g°C)
Answers
The specific heat capacity of the metal, given that 27.777 g of water at 22.1 °C was mixed with the metal is 9.7×10⁻² Cal/gºC
How do I determine the specific heat capacity of the metal?Step 1: Obtain the heat absorbed by the water. This is shown below:
Mass of water (M) = 27.777 gInitial temperature (T₁) = 22.1 °CFinal temperature (T₂) = 29.3 °CTemperature change (ΔT) = 29.3 - 22.1 = 7.2 °CSpecific heat capacity of water (C) = 1 Cal/gºC Heat absorbed (Q) =?Q = MCΔT
= 27.777 × 1 × 7.2
= 199.9944 Cal
Step 2: Determine the specific heat capacity of the metal using the heat absorbed by the water. Details below:
Heat absorbed by water (Q) = 199.9944 CalHeat released by metal (Q) = -199.9944 CalMass of metal (M) = 29.292 gInitial temperature (T₁) = 99.9 °CFinal temperature (T₂) = 29.3 °CTemperature change (ΔT) = 29.3 - 99.9 = -70.6 °CSpecific heat capacity of metal (C) = ?Q = MCΔT
-199.9944 = 29.292 × C × -70.6
-199.9944 = -2068.0152 × C
Divide both sides by -2068.0152
C = -199.9944 / -2068.0152
= 9.7×10⁻² Cal/gºC
Thus, the specific heat capacity of the metal is 9.7×10⁻² Cal/gºC. None of the options are correct.
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does the fastest car always travel the farthest?
Answers
Answer:
No because it could run out of gas quicker or get into a reck.
Explanation:
Are any of the forces acting on the freezer
unbalanced?
Answers
Answer: put them in the microwave
Explanation:
4. Calculate the total resistance of the circuit if R1=4 Ω, R2=30 Ω, R3=10Ω, R4=5Ω Determine the current strength if the circuit is connected to a voltage source with a voltage of 56 V
Answers
The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.
To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.
Given:
R1 = 4 Ω
R2 = 30 Ω
R3 = 10 Ω
R4 = 5 Ω
Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:
RT1-2 = R1 + R2
RT1-2 = 4 Ω + 30 Ω
RT1-2 = 34 Ω
Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:
1/RTotal = 1/RT1-2 + 1/R3
1/RTotal = 1/34 Ω + 1/10 Ω
1/RTotal = (10 + 34) / (34 * 10) Ω
1/RTotal = 44 / 340 Ω
1/RTotal ≈ 0.1294 Ω
RTotal ≈ 1 / 0.1294 Ω
RTotal ≈ 7.74 Ω
Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:
RTotalCircuit = RTotal + R4
RTotalCircuit = 7.74 Ω + 5 Ω
RTotalCircuit ≈ 12.74 Ω
Therefore, the total resistance of the circuit is approximately 12.74 Ω.
To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:
I = V / RTotalCircuit
I = 56 V / 12.74 Ω
I ≈ 4.39 A
Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).
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PLEASE HELP!
1. Terry kicks a soccer ball that is sitting motionless on the field. What is the best description of the energy transfer? (1 point)
A. Kinetic energy is transferred from the soccer ball to Terry's foot
B. Kinetic Energy is Transferred from Terry’s foot to the soccer ball.
C. Kinetic Energy in Terrys Foot is changed to potential energy in the Soccer ball
D. Potential energy is transferred from Terry’s foot to the Soccer ball
2. Which of the Following scenarios best shows the transfer of kinetic energy?
A. a Baseball bat strikes a baseball
B. A baseball player holds a baseball at their side
C. a baseball sits on a bench
D. a baseball flies through the air
3.
A bowling ball is traveling at 7 6 meters per second when it hits a pin. If the bowling ball has a mass of 6 kilograms, how much kinetic energy does it have when it hits the pin?
KB = m²
A. 173.28 J
B. 228 J
C. 346.65 J
D. 693 12 J
4. What happens when a tennis racket hits a ball?
A. Kinetic energy is created.
B. Potential energy in the racket is transferred to the ball.
C.Kinetic energy is transferred from the ball to the racket.
D.Kinetic energy is transferred from the racket to the ball.
Answers
Answer:
1. B. Kinetic energy is transferred from Terry's foot to the soccer ball.
2. A. A baseball bat strikes a baseball.
3. A. 173.28J
4. D. Kinetic energy is transferred from the racket to the ball.
Explanation:
I took the quiz and got 100%
Answer:
1. Kinetic energy is transferred from Terry's foot to the soccer ball.
2. A baseball bat stricks a baseball
3. 173.28
4. kinetic energy is transferred from the racket to the ball
5. 1,102.5 J
remember to keep the decimal on the last one
Explanation: They added another question so I decided to give the answer to those who had it.
Say an impulse is applied opposite the go-kart's direction of travel. What happens to
the go-kart if its momentum + impulse = 0?
The go kart stops comes to a stop.
The go kart slows down but keeps moving.
The go kart speeds up.
There is no change in the speed of the go kart.
Answers
If the impulse is strong enough and lasts for a sufficient amount of time, the go-kart will eventually come to a stop.
Option A is correct.
What is meant by impulse?impulse is described as the integral of a force, F, over the time interval, t, for which it acts. Since force is a vector quantity, impulse is also a vector quantity.
If the force is insufficient to stop the go-kart entirely, it will slow down but continue to move. The force and duration of the impulse, along with the mass and speed of the go-kart, will all affect how much deceleration occurs.
Given that momentum plus impulse equals zero, the go-kart's change in momentum as a result of the impulse will be equal in amount but will move in the opposite direction of its original momentum.
As a result, the go-kart's final momentum will be zero, suggesting that it has either stopped or is travelling very slowly.
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