Question 2 Jarrod is calculating the circumference of a circle. Which number below will give him the BEST approximate value of n? rs A. 3.00 B. 3.14 C. 3.28 D. 3.43

Answer:

Commutative Property of Multiplication

Step-by-step explanation:

Commutative Property of Multiplication

a • b = b • a

4 • d = d • 4

"commute = to get up and move to a new location: switch places"

The reasoning presented lacks explicit explanations and logical connections between the steps, making it difficult to fully understand the intended proof strategy.

The given proof aims to show that the Separation Axioms can be derived from the Replacement Schema using a particular construction involving a formula p(x, y). Let's analyze the proof step by step:

Define the formula p(x, y) as x = yo(x).

This formula states that for each x, y pair, x is equal to the unique object y such that y is obtained by applying the operation o to x.

Define the set F as {(x, x) (x)}.

This set F contains pairs (x, x) where x is the unique object obtained by applying the operation (x) to x.

Claim: F(X) = {y (x = X)p(x, y)} = {y: (x = X)x = y^o(x)} = {x: (3x € X)o(x)} = {x X: (x)}.

This claim asserts that F(X) is equivalent to {y (x = X)p(x, y)}, which is further equivalent to {y: (x = X)x = y^o(x)}, and so on.

The proof states that since (x, y) satisfies the functional formula VaVyVz(p(x, y)^(x, z) y = z), it follows that (x, y) is a functional formula.This step emphasizes that the formula p(x, y) satisfies certain properties that make it a functional formula, which is relevant for the subsequent deductions.

Finally, the proof concludes that the Separation Axioms follow from the Replacement Schema, based on the previous steps.

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Answer:

20

Step-by-step explanation:

She biked an equal amount each day for 8 days to a total of 32 miles. We can write that as 8x = 32. 32/8 = 4 so x = 4. To find how much shell bike in 5 days, we multiply it by x(4). 5*4 = 20.

i think it is 60 because 30 divided by 3-4 equals 2Step-by-step explanation:

Answer: Choice A

Step-by-step explanation:

it increases

Answer: -18

Step-by-step explanation:

The probability and binomial distribution are solved and the selected student will need to attend the math class

Given data ,

Let's denote the probability that a randomly selected student still needs to take another math class as "p".

Given that 72% of all students still need to take another math class, we have p = 0.72.

From the binomial distribution , we get

P(X=k) = C(n, k) * p^k * (1-p)^(n-k)

where:

P(X=k) is the probability of exactly k successes in n trials

C(n, k) is the number of ways to choose k items from n items, also known as "n choose k"

p is the probability of success on a single trial

k is the number of successes

n is the total number of trials

Let's use this formula to solve the questions:

a)

Exactly 29 of them still need to take another math class:

Here, k = 29, n = 38, and p = 0.72

P(X=29) = C(38, 29) * 0.72^29 * (1-0.72)^(38-29)

P ( X = 29 ) = 0.1257

b)

Fewer than 27 of them still need to take another math class:

Here, we need to find the probability of having 0, 1, 2, ..., 26 successes, and then add them together:

P(X<27) = P(X=0) + P(X=1) + P(X=2) + ... + P(X=26)

P ( X < 27 ) = 0.5096

c)

More than 25 of them still need to take another math class:

Here, we need to find the probability of having 26, 27, 28, ..., 38 successes, and then add them together:

P(X>25) = P(X=26) + P(X=27) + P(X=28) + ... + P(X=38)

P ( X > 25 ) = 0.7537

Hence , the binomial distribution is solved

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The complete question is attached below :

Answer the following questions and round your answers to 3 decimal places. 72% of all students at the college still need to take at least another math class. If 38 students are randomly selected, find the probability that

1. Exactly 29 of them still need to take another math class.

2. Fewer than 27 of them still need to take another math class.

3. More than 25 of them still need to take another math class.

The cubic equation that contains the roots 4 and + i 2 is p(x) = x³ - 4 · x² + 4 · x - 16.

In this problem we must derive the expression that has lead coefficient of 1 and the roots 4 and + i 2. According to the statement, the factor form of the cubic equation is introduced below:

p(x) = a · (x - r₁) · (x - r₂) · (x - r₃)

Where:

By quadratic formula, we conclude that quadratic equations with real coefficients can have two conjugate complex roots. Then, the complete set of roots must be 4, + i 2 and - i 2.

If we know that a = 1, r₁ = 4, r₂ = + i 2 and r₃ = - i 2, then the standard form of the cubic equation is:

p(x) = 1 · (x - 4) · (x - i 2) · (x + i 2)

p(x) = (x - 4) · (x² - i² 4)

p(x) = (x - 4) · (x² + 4)

p(x) = x³ - 4 · x² + 4 · x - 16

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The relative frequency of the pitcher throwing exactly 4 pitches in an at-bat is given as follows:

3/20.

A relative frequency is calculated as the division of the number of desired outcomes by the number of total outcomes.

The total number of at bats in this problem is given as follows:

80.

In 12 of them, the pitcher threw exactly four pitches, hence the relative frequency of the pitcher throwing exactly 4 pitches in an at-bat is given as follows:

12/80 = 3/20.

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According to the information provided, 4.5 litres of red paint and 1400 ml of blue paint are required to manufacture the paint mixture.

Red paint requires 3/4 x 6 = 9/2 = 4.5 litres.

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Answer:

The trick for this one is watching for the small indicator lines inside the triangles. When two angles have the same number of lines, they are congruent angles. Now that we know that, we just match them up.

1. ΔUVW ≅ Δ CDB

2. ΔTUV ≅ ΔBCD

3. ΔRST ≅ ΔYZX

4. ΔYXW ≅ ΔJKL

5. ΔXWF ≅ ΔXWV

6. ΔHIJ ≅ ΔRJP

By the way, the file is to show you which ones I have as which number.

Step-by-step explanation:

hope this helps. . .<3

good luck!       UwU

Answer:

5^4

Step-by-step explanation:

Add 18+6

Then add 10+10

Subtract 24-20

Then you get 5^4

Answer: 135,000²

Step-by-step explanation:

5×18=90×30=2,700×50=135,000²

Answer:

\( \frac{x - 9}{2} = 5 \\ x - 9 = 5 \times 2 \\ x = 10 + 9 \\ x = 19\)

well, the profit is clearly just 490 - 350 = 140.

Now, if we take 350(origin amount) to be the 100%, what is 140 off of it in percentage?

\(\begin{array}{ccll} Amount&\%\\ \cline{1-2} 350 & 100\\ 140& x \end{array} \implies \cfrac{350}{140}~~=~~\cfrac{100}{x} \\\\\\ \cfrac{5}{2} ~~=~~ \cfrac{100}{x}\implies 5x=200\implies x=\cfrac{200}{5}\implies x=40\)

Based on the given assumptions and calculations, the net present value (NPV) of the investment in the new piece of equipment is -$27,045.76, indicating that the investment is not favorable.

To calculate the after-tax cash flows for each year and evaluate the investment decision, let's use the following information:

Assumptions:

Tax depreciation is straight-line over five years.

Pre-tax salvage value is $10,000 in Year 5 and $15,000 if the asset is scrapped in Year 4.

Tax on salvage value is 30% of the difference between salvage value and book value of the investment.

The cost of capital is 12%.

Given:

Initial investment cost = $50,000

Useful life of the equipment = 5 years

To calculate the depreciation expense each year, we divide the initial investment by the useful life:

Depreciation expense per year = Initial investment / Useful life

Depreciation expense per year = $50,000 / 5 = $10,000

Now, let's calculate the book value at the end of each year:

Year 1:

Book value = Initial investment - Depreciation expense per year

Book value \(= $50,000 - $10,000 = $40,000\)

Year 2:

Book value = Initial investment - (2 \(\times\) Depreciation expense per year)

Book value \(= $50,000 - (2 \times$10,000) = $30,000\)

Year 3:

Book value = Initial investment - (3 \(\times\) Depreciation expense per year)

Book value = $50,000 - (3 \(\times\) $10,000) = $20,000

Year 4:

Book value = Initial investment - (4 \(\times\) Depreciation expense per year)

Book value \(= $50,000 - (4 \times $10,000) = $10,000\)

Year 5:

Book value = Initial investment - (5 \(\times\) Depreciation expense per year)

Book value \(= $50,000 - (5 \times $10,000) = $0\)

Based on the assumptions, the salvage value is $10,000 in Year 5.

If the asset is scrapped in Year 4, the salvage value is $15,000.

To calculate the tax on salvage value, we need to find the difference between the salvage value and the book value and then multiply it by the tax rate:

Tax on salvage value = Tax rate \(\times\) (Salvage value - Book value)

For Year 5:

Tax on salvage value\(= 0.30 \times ($10,000 - $0) = $3,000\)

For Year 4 (if scrapped):

Tax on salvage value\(= 0.30 \times ($15,000 - $10,000) = $1,500\)

Now, let's calculate the after-tax cash flows for each year:

Year 1:

After-tax cash flow = Depreciation expense per year - Tax on salvage value

After-tax cash flow = $10,000 - $0 = $10,000

Year 2:

After-tax cash flow = Salvage value - Tax on salvage value

After-tax cash flow = $0 - $0 = $0

Year 3:

After-tax cash flow = Salvage value - Tax on salvage value

After-tax cash flow = $0 - $0 = $0

Year 4 (if scrapped):

After-tax cash flow = Salvage value - Tax on salvage value

After-tax cash flow = $15,000 - $1,500 = $13,500

Year 5:

After-tax cash flow = Salvage value - Tax on salvage value

After-tax cash flow = $10,000 - $3,000 = $7,000

Now, let's calculate the net present value (NPV) using the cost of capital of 12%.

We will discount each year's after-tax cash flow to its present value using the formula:

\(PV = CF / (1 + r)^t\)

Where:

PV = Present value

CF = Cash flow

r = Discount rate (cost of capital)

t = Time period (year)

NPV = PV Year 1 + PV Year 2 + PV Year 3 + PV Year 4 + PV Year 5 - Initial investment

Let's calculate the NPV:

PV Year 1 \(= $10,000 / (1 + 0.12)^1 = $8,928.57\)

PV Year 2 \(= $0 / (1 + 0.12)^2 = $0\)

PV Year 3 \(= $0 / (1 + 0.12)^3 = $0\)

PV Year 4 \(= $13,500 / (1 + 0.12)^4 = $9,551.28\)

PV Year 5 \(= $7,000 / (1 + 0.12)^5 = $4,474.39\)

NPV = $8,928.57 + $0 + $0 + $9,551.28 + $4,474.39 - $50,000

NPV = $22,954.24 - $50,000

NPV = -$27,045.76

The NPV is negative, which means that based on the given assumptions and cost of capital, the investment in the new piece of equipment would result in a net loss.

Therefore, the investment may not be favorable.

Please note that the calculations above are based on the given assumptions, and additional factors or considerations specific to the business should also be taken into account when making investment decisions.

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The complete question may be like :

Assumptions: Tax depreciation is straight-line over five years. Pre-tax salvage value is $10,000 in Year 5 and $15,000 if the asset is scrapped in Year 4. Tax on salvage value is 30% of the difference between salvage value and book value of the investment. The cost of capital is 12%.

You are evaluating an investment in a new piece of equipment for your business. The initial investment cost is $50,000. The equipment is expected to have a useful life of five years.

Using the given assumptions, calculate the after-tax cash flows for each year and evaluate the investment decision by calculating the net present value (NPV) using the cost of capital of 12%.

9514 1404 393

Answer:

  no solution

Step-by-step explanation:

The solutions to the equation are ...

  tan(θ/7) +√3 = 0

  tan(θ/7) = -√3

  θ/7 = arctan(-√3) +nπ . . . . . . . for integer n

  θ = 7(-π/3 +nπ) = 7π(n -1/3)

For n=0, θ = -7π/3 -- not in the required interval.

For n=1, θ = 14π/3 -- not in the required interval.

There are no solutions in the required interval.

z = -1/9 , -6/7

Have a nice day!

Answer:

ABD=23

Step-by-step explanation:

9x-22=6x-7

3x= 15

x=5 but wait thats only what X is so

9(5)-22

45-22

ABD=23

Answer:

x=1

Step-by-step explanation:

y=3x so just add 1+3=4 then add veriable y=4x

Answer:

\(3\)

Step-by-step explanation:

\(\mathrm{Let\ the\ age\ of\ Sophia\ be\ }x\mathrm{\ and\ age\ of\ Mohal\ be\ }x+2.\\\mathrm{Given,}\\\mathrm{Product\ of\ their\ ages = 15}\\\mathrm{or,\ }x(x+2)=15\\\mathrm{or,\ }x^2+2x=15\\\mathrm{or,\ }x^2+2x-15=0\\\mathrm{or,\ }x^2+5x-3x-15=0\\\mathrm{or,\ }x(x+5)-3(x+5)=0\\\mathrm{or,\ }(x+5)(x-3)=0\\\mathrm{i.e.}\ x=-5\ \mathrm{or}\ 3.\)

\(x=-5\ \mathrm{is\ disgarded\ because\ age\ cannot\ be\ negative.}\\\mathrm{So\ the\ age\ of\ Shopia,\ }x=3\)

Answer:

f(x) = x^(1/2) + 3

Step-by-step explanation:

Translating to the right 3 units would change these:

0^(1/2) = 0 /// 3 units to the right would be (0,3)

1^(1/2) = 1 //// 3 units to the right would be (1,4)

4^(1/2) = 2 //// 3 units to the right would be (4,5) etc

It will take approximately 349.1 second for the ball with diameter of 10 to deflate.

The formula for a sphere's volume is, V = (4/3)πr³ where V is the sphere's volume, r is its radius, and (pi) is a mathematical constant roughly equal to 3.14. According to this equation, a sphere's volume is equal to four-thirds of the sum of its radius's cube and the value of pi. In geometry and physics, this method is used to determine the volume of spherical objects like planets, balls, and bubbles.

The volume of a sphere is given as:

V = (4/3)πr³

Substituting the values:

V = (4/3)π(5)³ = 523.6 cubic inches

The rate is given as:

V = rt

Solving for t for the given rate we have:

t = V/r = 523.6/1.5 = 349.1 seconds

Hence, it will take approximately 349.1 seconds (or about 5.8 minutes) for the ball to deflate.

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Answer:

16/5=7

Step-by-step explanation:

Use the slope-intercept form to find the slope and y-intercept.

Slope:  0

y-intercept:  ( 0 , 2 )

The cost of each department A, B, C, and D of the Marketing Department would take up is $8,391.17, $4,914.83, $3,356.47, and $2,337.53, respectively.

A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25.

Given the cost of operating the marketing Department for March is $19,000. The total area of operation is,

Total Area = Department A + Department B + Department C + Department D

Total Area = 1400 m² + 820 m² + 560 m² + 390 m² = 3,170 m²

Now, the cost of operating a unit area can be determined as,

Cost of operating = $19,000/3,170m² = $5.99369 per m²

Further the cost of operating the different departments are,

Department A = 1400m²×$5.99 = $8,391.17

Department B = 820m²×$5.99 = $4,914.83

Department C = 560m²×$5.99 = $3,356.47

Department D = 390m² × $5.99 = $2,337.53

Hence, the cost of each department A, B, C, and D of the Marketing Department would take up is $8,391.17, $4,914.83, $3,356.47, and $2,337.53, respectively.

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All the solutions are,

⇒ x = 1/2 (w- v)

⇒ x = (b - 9)/(a - 2)

⇒ x = (4 + w) / (7 - v)

⇒ x = 2 / (v + w)

⇒ x = 7v/(3w - 4)

Given that;

Expressions are,

⇒ 6x + v = 4x + w

⇒ ax + 9 = 2x + b

⇒ 7x - w = vx+4

⇒ 6 - wx = vx + 4

⇒ 3(wx - v) = 4(x + v)

We can simplify as;

⇒ 6x + v = 4x + w

⇒ 6x - 4x = w - v

⇒ 2x = w - v

⇒ x = 1/2 (w- v)

⇒ ax + 9 = 2x + b

⇒ ax - 2x = b - 9

⇒ (a - 2)x = b - 9

⇒ x = (b - 9)/(a - 2)

⇒ 7x - w = vx+4

⇒ 7x - vx = 4 + w

⇒ (7 - v) x = 4 + w

⇒ x = (4 + w) / (7 - v)

⇒ 6 - wx = vx + 4

⇒ vx + wx = 6 - 4

⇒ (v + w)x = 2

⇒ x = 2 / (v + w)

⇒ 3(wx - v) = 4(x + v)

⇒ 3wx - 3v = 4x + 4v

⇒ 3wx - 4x = 7v

⇒ (3w - 4)x = 7v

⇒ x = 7v/(3w - 4)

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Answer:

85cm^3

Step-by-step explanation:

Volume = Base Area * Height

17*5=85

The estimated number of students on the A honor roll who are 8th graders is 126.

Algebra is a branch of mathematics that deals with symbols and the rules for manipulating these symbols. It involves using letters and other symbols to represent numbers and quantities in equations and formulas.

The main goal of algebra is to find the value of an unknown quantity, called a variable, by using known quantities and mathematical operations such as addition, subtraction, multiplication, division, and exponentiation. Algebraic expressions can be solved using various techniques, including simplification, factoring, and solving equations.

The total number of students on the A honor roll is given by adding the number of students in each grade:

Total = 15 (6th grade) + 11 (7th grade) + 14 (8th grade) = 40

To find the proportion of students who are in 8th grade, we can divide the number of 8th graders by the total number of students:

Proportion of 8th graders = 14/40 = 0.35

To estimate the number of students on the A honor roll who are 8th graders, we can multiply the proportion of 8th graders by the total number of students on the A honor roll:

Estimated number of 8th graders = 0.35 x 360 = 126

Therefore, the estimated number of students on the A honor roll who are 8th graders is 126.

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Answer:

Step-by-step explanation: