In the word problem , the number of days were in the "13-18" category is C)4.
What is word problem?
Word problems are often described verbally as instances where a problem exists and one or more questions are posed, the solutions to which can be found by applying mathematical operations to the numerical information provided in the problem statement. Determining whether two provided statements are equal with respect to a collection of rewritings is known as a word problem in computational mathematics.
Here the given data represent the numbers of loaves sold in the last 10 days is 5, 12, 8, 15, 18, 20, 3, 17, 14, 21.
Now number of loaves sold in last 10 days between from 13-18 is
=> 15,18,17,14
Hence the number of days were in the "13-18" category is C)4.
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5/4 as a percentage
;-;
Answer:
125%
Step-by-step explanation:
If 25 individuals were alive in 1955 and 500 existed in 2013, what is r?a) 475b) 2.99c) 0.052d) 0.029
It seems that you are referring to the exponential growth formula which is:
N(t) = N₀ * (1 + r)^t
Where:
N(t) is the number of individuals at time t
N₀ is the initial number of individuals (in this case, 25 alive in 1955)
r is the growth rate
t is the time period (in years)
In this problem, we have:
N₀ = 25 individuals (alive in 1955)
N(t) = 500 individuals (existed in 2013)
t = 2013 - 1955 = 58 years
We need to solve for r. To do that, rearrange the formula:
r = [(N(t) / N₀)^(1/t)] - 1
Plug in the given values:
r = [(500 / 25)^(1/58)] - 1
r ≈ 0.029
So, the answer is (d) 0.029.
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A deck of standard playing cards holds 52 unique cards.
36 of these cards are numbered cards (numbered 2-9), 4
of these cards are aces, and 12 of these cards are face
cards (jack, queen, and king). If you play a card game and
draw half of the face cards, one ace, and one fourth of the
numbered cards, how many cards do you have? How
many of each card type of card do you have? Cite
evidence from the problem.
Answer:
Based on the information in the problem, you would have a total of 16 cards, with 6 being face cards, 1 being an ace, and 9 being numbered cards.
Step-by-step explanation:
According to the issue:
The deck contains 52 distinct cards.
There are 36 numbered cards ranging from 2 to 9.
There are four aces in the deck.
There are 12 face cards (including the jack, queen, and king).
If you draw half of the face cards, one ace, and one-fourth of the numbered cards, you will get the following:
Face cards in half: 1/2 * 12 = 6 face cards
1 ace: 1 ace
One-fourth of a deck of numbered cards: 1/4 * 36 = 9 decks of numbered cards
When you add these up, you get a total of 6 + 1 + 9 = 16 cards.
Based on the information in the problem, you would have a total of 16 cards, with 6 being face cards, 1 being an ace, and 9 being numbered cards.
A complex point of the form a 3i has a distance of 29 units from –9 24i. What is the value of a? –1 5 11 19. 8.
The value of a in the complex point a + 3i is 11. it has a distance of 29 units from -9 + 24i, we can use the distance formula in the complex plane.
To find the value of a in the complex point of the form a + 3i, given that it has a distance of 29 units from -9 + 24i, we can use the distance formula in the complex plane.
The distance between two complex numbers, z1 = x1 + y1i and z2 = x2 + y2i, is given by the formula:
distance = √[(x2 - x1)^2 + (y2 - y1)^2]
Let's apply this formula to the given information:
distance = √[(-9 - a)^2 + (24 - 3)^2]
Simplifying further:
distance = √[(-9 - a)^2 + 21^2]
Since the given distance is 29 units, we can set up the equation:
29 = √[(-9 - a)^2 + 21^2]
Now, we can square both sides of the equation to eliminate the square root:
29^2 = (-9 - a)^2 + 21^2
Expanding and simplifying:
841 = 81 + 18a + a^2 + 441
Rearranging the terms:
a^2 + 18a - 319 = 0
Now, we have a quadratic equation. To solve for the value of a, we can factor or use the quadratic formula. Factoring is not straightforward in this case, so let's apply the quadratic formula:
a = (-b ± √(b^2 - 4ac)) / (2a)
In our case, a = 1, b = 18, and c = -319. Substituting these values into the quadratic formula:
a = (-18 ± √(18^2 - 4(1)(-319))) / (2(1))
Simplifying:
a = (-18 ± √(324 + 1276)) / 2
a = (-18 ± √(1600)) / 2
a = (-18 ± 40) / 2
We have two possible solutions for a:
a = (-18 + 40) / 2 = 11
a = (-18 - 40) / 2 = -29
However, among the given answer choices, the only value that matches one of the solutions is a = 11. Therefore, the value of a in the complex point a + 3i is 11.
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Problem 2 A local girls soccer team decides to sell chocolate bars to raise some money for new uniforms. The girls are to receive 10% of all the sales they make. Once the bars arrive the girls see that they have to sell each bar for $2.50. They think this price is too high. Are the girls being altruistic or is there something else going on? (Assume the girls face a downward sloping demand curve).
The girls' reluctance to sell the chocolate bars at $2.50 per bar may not be purely altruistic but instead driven by their understanding of market demand and the potential impact of pricing on sales volume.
The girls' perception that the selling price of $2.50 per chocolate bar is too high may not necessarily indicate altruism but rather a response to market demand. When faced with a downward sloping demand curve, higher prices can lead to lower sales volume.
The girls' concern may be rooted in their understanding that a higher price could potentially deter potential buyers from purchasing the chocolate bars, resulting in lower overall sales and potentially lower earnings for themselves.
By considering the demand curve, the girls are likely taking into account the price elasticity of demand. Elastic demand implies that a change in price will have a relatively larger impact on the quantity demanded. If the girls perceive the demand for chocolate bars to be elastic, they might believe that a lower price would attract more customers and lead to increased sales volume.
Their concerns could also be motivated by their desire to achieve a balance between maximizing their sales and ensuring a reasonable profit margin. They might be aware that setting the price too high could lead to reduced demand and lower overall revenue, thereby limiting their earnings.
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Ignacio is going on vacation. He needs to drive 520 miles in 8 hours. What is his average speed in miles per hour?
Answer:
65 miles per hour
Step-by-step explanation:
520 divided by 8
Answer:
His average speed is 65 miles per hour.
Step-by-step explanation:
The answer is 65 because 520 divided by 8 is 65.
P.S Can I have brainliest?
Please help this is algebra!
Answer:
7 nickels
20 dimes
5 quarters
Step-by-step explanation:
n=nickels. d=dimes. q=quarters
n+d+q=32
0.05n+0.1d+0.25q=3.60
d=8+n+q
Solve for number of dimes:
d-8=8-8+n+q
d-8=n+q
d-d-8=n+q-d
-8=n+q-d
32=n+q+d
- (-8=n+q-d)
32 - (-8) = n-n + q-q + d-(-d)
32 + 8 = d + d
40 = 2d
d = 20 => simplify
20=8+n+q ==> substitute 20 for d (d=8+n+q)
20-8 = 8-8+n+q
n+q = 12
0.05n+0.1(20)+0.25q=3.60 ==> substitute 20 for d
0.05n + 2 + 0.25q = 3.60
(0.05n + 2 + 0.25q = 3.60)*100 ->remove the decimals by multiplying by 100
5n + 200 + 25q = 360
5n + 200 - 200 + 25q = 360 - 200
5n + 25q = 160
Solve for number of quarters:
(5n + 25q)/5 = 160/5 ==> simplify the equation
n + 5q = 32
- (n + q = 12)
n-n + 5q-q = 32-12
0 + 4q = 20
4q = 20
q = 5 ==> simplify
Solve for number of nickels:
n+20+5=32 ==> plug in 20 for d and 5 for q (n+d+q=32)
n+25=32
n+25-25=32-25 ==> solve for n
n=7 ==> simplify
n=7: 7 nickels
d = 20: 20 dimes
q = 5: 5 quarters
SOLVE THIS PROBLEM ASAP
Answer:
6,6
There are 8 spaces in bettween point a and b so 8/2 = 4 so 4 up from point a is 6,6
Step-by-step explanation:
a-If given that we were tasked to evaluate the model, between MAPE and R2 which of these parameters do we use?
b-If given that model A has a higher MAPE than model B but model B has a higher R2 than model A, then how do we choose among the two?
c-Between the MAPE , MAD and MSD, which of these parameters shall we use for accuracy measures and why?
a. When evaluating a model, we use R2 as a parameter for performance assessment.
b. If model A has a higher MAPE but model B has a higher R2, we choose the model with the higher R2 for better overall performance.
c. For accuracy measures, we typically use MAPE (Mean Absolute Percentage Error) due to its interpretability and ability to capture relative errors.
When evaluating a model's performance, it is crucial to choose the appropriate parameters to assess its accuracy and reliability. In the case of MAPE (Mean Absolute Percentage Error) and R2 (Coefficient of Determination), the choice between them depends on the specific evaluation goals.
The R2 parameter is commonly used for evaluating models because it measures the proportion of the dependent variable's variance that can be explained by the independent variables. R2 provides insights into how well the model fits the data and captures the relationship between the input features and the target variable. Therefore, R2 is a suitable parameter to use when evaluating a model.
When comparing two models, if model A has a higher MAPE but model B has a higher R2, it is advisable to choose the model with the higher R2 value. This is because R2 indicates the proportion of variance explained, suggesting that model B performs better in capturing the underlying patterns and predicting the target variable.
Although model A may have a lower relative error (MAPE), it is crucial to prioritize the model's ability to explain and predict the target variable accurately.
Among MAPE, MAD (Mean Absolute Deviation), and MSD (Mean Squared Deviation), MAPE is commonly preferred as a parameter for accuracy measures. MAPE calculates the average percentage difference between the predicted and actual values, making it interpretable and easily understandable.
It captures relative errors and enables comparisons across different scales and datasets. MAD and MSD, on the other hand, measure absolute and squared errors, respectively, but they do not account for the relative magnitude of the errors. Hence, MAPE is a more suitable parameter for accuracy measures.
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what is the equation of the line that has a slope of -3 and a y-intercept of -1
Answer:
y=4x+2
Step-by-step explanation:
need help right now asap??!?!?!??!?!??!
A) The person that has a greater probability of selecting a quadrilateral is Robert.
B) The person that has a greater probability of selecting a polygon is; Robert.
C) The event that is more likely to happen is the Probability of Sandy selecting a polygon with at least 2 sides parallel.
How to Identify Polygons?Sandy has; Square, Rhombus, Equilateral Triangle, Regular Hexagon
Robert has Scalene Triangle, Kite, Right Isosceles Triangle, Isosceles Trapezoid, Quadrilateral.
A) Sandy's probability of selecting a quadrilateral = 2/4 = 0.5
Robert's probability of selecting a quadrilateral = 3/5 = 0.6
The person that has a greater probability of selecting a quadrilateral is Robert
B) The person that has a greater probability of selecting a polygon is; Robert because he has more.
C) Probability of Sandy selecting a polygon with at least 2 sides parallel is; 3/4 = 0.75
The Probability of Robert selecting a polygon with at least 2 sides parallel is; 2/5 = 0.4
The event that is more likely to happen is the Probability of Sandy selecting a polygon with at least 2 sides parallel.
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y=(x+4)^2-3 , y+=2x=5 FIND THE SOLUTION OF EACH SYSTEM
Answer:
5
Step-by-step explanation:
Find the value of x.
Answer:
12
Step-by-step explanation:
This triangle is equalateral, so all the sides and all the angles are the same. Since in every triangle all angles add up to 180, they would be evenly distributed. (so 180/3, which is 60) 60/5= 12, so the value of x is 12
Express the radical using the Imaginary unit, i.Express your answer in simplified form.#v-20 = +
Using imaginary unit i:
Recall i² = -1
-20 = -1 × 20 = i² × 20
\(\begin{gathered} \pm\sqrt[]{-20}\text{ = }\pm\sqrt[]{i^{2}\times20} \\ \sqrt[]{20}\text{ = }\sqrt[]{4\times5}\text{ = 2}\sqrt[]{5} \end{gathered}\)\(\begin{gathered} \pm\sqrt[]{i^2\times20}\text{ = }\pm\sqrt[]{i^2}\times\sqrt[]{20} \\ =\pm(i\times2\sqrt[]{5)}\text{ = }\pm2i\sqrt[]{5} \\ \text{the answer in the box = }2i\sqrt[]{5} \end{gathered}\)There are four students named A,B,C, and D. All four of them are loss averse over money, with the same value function for money: v(x dollars )={√x x ≥ 0
{-2√-x x < 0
All three of them are also loss averse over mugs, with the same value function for mugs:
v(y mugs)={3y y ≥ 0
{4y y < 0
Total utility is the sum of the gain/loss utility for mugs and the gain/loss utility for money. The reference point is the status quo, that is, a person's initial endowment. Student A owns a mug and is willing to sell it for a price of a dollars or more. Student B does not own a mug and is willing to pay up to b dollars for buying it. Student C does not own a mug and is indifferent between getting a mug and getting c dollars. Student D is indifferent between losing a mug and losing d dollars.
1. Solve for a,b,c, and d.
2. Instead, suppose A, B, C, and D are only loss averse over mugs, but not over money. That is, their value function for money is instead:
v(x dollars)={√x x ≥ 0
{-√-x x < 0
and their value function for mugs remains:
v(y mugs)={3y y ≥ 0
{4y y < 0
Solve for a,b,c, and d.
3. Instead, suppose A,B,C, and D are not loss averse:
v(x dollars)={√x x ≥ 0
{-√-x x < 0
and v(y mugs)=3y
Solve for a,b,c, and d.
4. Suppose A, B, C, and D are not loss averse (as in the previous question), but their value for a mug varies with ownership. Specifically, the value of the mug is 3 for someone who does not currently own the mug, and 4 for someone who currently owns a mug. Solve for a,b,c, and d.
As per the question, All four students A, B, C, and D are loss-averse over money and have the same value function as below:v(x dollars)={√x x ≥ 0 {-2√-x x < 0They are also loss averse over mugs and have the same value function.
v(y mugs)={3y y ≥ 0
{4y y < 0
Now, we have to find the values of a, b, c and d as below:
- Student A owns a mug and is willing to sell it for a price of a dollars or more. i.e v(a) = v(0) + v(a-A), where A is the initial endowment of A. According to the given function, v(0) = 0, v(a-A) = 3, and v(A) = 4.
So, a ≥ A+3/2
- Student B does not own a mug and is willing to pay up to b dollars for buying it. i.e v(B-b) = v(B) - v(0), where B is the initial endowment of B. According to the given function, v(0) = 0, v(B-b) = -4, and v(B) = -3.
So, b ≤ B+1/2
- Student C does not own a mug and is indifferent between getting a mug and getting c dollars. i.e v(c) = v(0) + v(c), where C is the initial endowment of C. According to the given function, v(0) = 0, v(c) = 3.
So, c = C/2
- Student D is indifferent between losing a mug and losing d dollars. i.e v(D-d) = v(D) - v(0), where D is the initial endowment of D. According to the given function, v(0) = 0, v(D-d) = -3.
So, d = D/2
2) In this case, value function for money changes to:v(x dollars)={√x x ≥ 0
{-√-x x < 0
However, the value function for mugs remains the same:v(y mugs)={3y y ≥ 0
{4y y < 0
Therefore, values for a, b, c, and d will remain the same as calculated in part (1).
3) In this case, students are not loss-averse. Value function for money:v(x dollars)={√x x ≥ 0
{-√-x x < 0
Value function for mugs:v(y mugs)={3y y ≥ 0
The reference point is the status quo, i.e initial endowment. So,
- Student A owns a mug and is willing to sell it for a price of a dollars or more. The value of mug for A is 3 initially and he would sell it for 3 or more.
So, a ≥ A+3/2
- Student B does not own a mug and is willing to pay up to b dollars for buying it. The value of mug for B is 3 initially and he would buy it for 3 or less.
So, b ≤ B+3/2
- Student C does not own a mug and is indifferent between getting a mug and getting c dollars. The value of the mug for C is 3 initially.
So, c = 3
- Student D is indifferent between losing a mug and losing d dollars. The value of the mug for D is 3 initially.
So, d = 3
4) In this case, value function for money:v(x dollars)={√x x ≥ 0
{-√-x x < 0
Value function for mugs: Mug will have a value of 4 for someone who owns it and 3 for someone who does not own it.
The reference point is the status quo, i.e initial endowment. So,
- Student A owns a mug and is willing to sell it for a price of a dollars or more. The value of mug for A is 4 initially and he would sell it for 4 or more.
So, a ≥ A+2
- Student B does not own a mug and is willing to pay up to b dollars for buying it. The value of mug for B is 3 initially and he would buy it for 3 or less.
So, b ≤ B+3/2
- Student C does not own a mug and is indifferent between getting a mug and getting c dollars. The value of the mug for C is 3 initially and he would like to buy it for 3.
So, c = 3
- Student D is indifferent between losing a mug and losing d dollars. The value of the mug for D is 3 initially.
So, d = 3.
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Solve for the value of m
Answer:
m = 7
Step-by-step explanation:
The 3 given angles lie on a straight line, thus sum to 180° , then
8m - 4 + 90 + 5m + 3 = 180, that is
13m + 89 = 180 ( subtract 89 from both sides )
13m = 91 ( divide both sides by 13 )
m = 7
you watch a roulette wheel spin 7 consecutive times and the ball lands on a red slot each time. what is the probability that the ball will land on a red slot on the next spin?
The probability that the ball will fall into a red slot during the following spin is 0.14.
To calculate the probability of an occurrence, divide the total number of outcomes by the total number of possible outcomes. The concepts of probability and odds are distinct. Odds are determined by dividing the probability of a situation happening by the probability that it won't happen. Probability is a metric used to determine how likely an event is to occur. When we toss the coin in the air, the probability that it will land with the heads side up is calculated. Here is a practical use of probability that you are probably already familiar with. We always check the weather forecast before a significant outing.
\(\frac{1}{7}=0.142857\)
The probability is 0.14
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The probability of the ball landing on a red slot in a single spin of a fair roulette wheel is 1/2, as there are an equal number of red and black slots.
The outcome of each spin is independent, meaning that the outcome of one spin does not affect the outcome of another. Therefore, the probability that the ball will land on a red slot in the next spin is still 1/2, regardless of the results of the previous seven spins.
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6 ︎︎≤︎ 2x, Solve for what x is
Answer:
x = 3
Hope that helps!
Step-by-step explanation:
Answer:
\(x \geqslant 3\)
Step-by-step explanation:
\(6 \leqslant 2x\)
\(2x \geqslant 6\)
\(x \geqslant 3\)
a set of x and y scores has b = 4, mx = 12, and my = 51. what is the y-intercept (a) for the regression equation?
The y-intercept for the regression equation is 3, given that b = 4, Mx = 12, and My = 51. So, the correct option is C).
The formula for the y-intercept of the regression equation is
a = My - b(Mx)
where My is the mean of the dependent variable (y), b is the slope, and Mx is the mean of the independent variable (x).
Given that b = 4, Mx = 12, and My = 51, we can substitute these values in the formula to find the y-intercept
a = 51 - 4(12)
a = 51 - 48
a = 3
Therefore, the y-intercept (a) for the regression equation is 3.
The correct Answer is C) 3.
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--The given question is incomplete, the complete question is given
" A set of X and Y scores has b = 4, Mx = 12, and My = 51. What is the y-intercept (a) for the regression equation? O 9.75 17.36 3.00 8.25 "--
4. (10 points) Show whether the series is absolutely convergent, conditionally convergent, or di- vergent. k Σ(-1)*, K3/2 + 3 k=1
The given series Σ((-1)^k) / (k^(3/2) + 3) for k=1 to ∞ is absolutely convergent.
To determine if the given series is absolutely convergent, conditionally convergent, or divergent:
The series is:
Σ((-1)^k) / (k^(3/2) + 3) for k=1 to ∞
Step 1: Test for absolute convergence
To check for absolute convergence, we consider the absolute value of the series' terms:
Σ|((-1)^k) / (k^(3/2) + 3)| for k=1 to ∞
This simplifies to:
Σ(1) / (k^(3/2) + 3) for k=1 to ∞
Step 2: Apply the Comparison Test
We can compare our series with a known convergent series, 1/k^(3/2), since k^(3/2) ≤ (k^(3/2) + 3) for all k.
Therefore, we have:
(1) / (k^(3/2)) ≥ (1) / (k^(3/2) + 3)
Since the series Σ(1) / (k^(3/2)) converges (it's a p-series with p = 3/2 > 1),
by the Comparison Test, our series Σ(1) / (k^(3/2) + 3) also converges.
This means the original series is absolutely convergent.
The given series Σ((-1)^k) / (k^(3/2) + 3) for k=1 to ∞ is absolutely convergent.
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By writing each number correct to 1 significant figure, find an estimate for the value of
2.8 × 82.6
27.8-13.9
The value of the phrase to one significant figure is estimated to be 17.
To find an estimate for the value of the expression (2.8 × 82.6)/(27.8-13.9),
we can first perform the calculations using the given values to obtain a more precise answer, and then round the final result to one significant figure.
Using a calculator, we have:
(2.8 × 82.6)/(27.8-13.9) ≈ 16.63
Rounding this to one significant figure, we get:
(2.8 × 82.6)/(27.8-13.9) ≈ 17
Therefore, an estimate for the value of the expression to one significant figure is 17.
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8. Given : triangle PQR and triangle TSR are right triangles , R is the midpoint of overline PT , overline PQ cong overline TS Prove : Delta PQR cong Delta TSR
By using the ASA Congruence Theorem, Delta PQR is congruent to Delta TSR.
We can prove this by using the fact that triangle PQR and triangle TSR are both right triangles and that R is the midpoint of overline PT and overline PQ is congruent to overline TS. Since R is the midpoint of overline PT, it follows that overline PR is congruent to overline TR (by the midpoint theorem).
Since PQR is a right triangle, and R is the right angle, it follows that angle PQR is congruent to angle TSR (by the definition of a right angle). Since overline PQ is congruent to overline TS, it follows that angle PQS is congruent to angle TSR (by the definition of congruence). Together, these congruences imply that triangle PQR is congruent to triangle TSR by the ASA congruence theorem.
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Definition of a derivative (limit of the difference quotient)
The derivative of a function f(x) at a point x = a is defined as the limit of the difference quotient as h approaches zero:
f'(a) = lim (h → 0) [f(a + h) - f(a)] / h
What is derivative?
The derivative of a function in calculus measures the function's sensitivity to changes in its input variable. Specifically, at a particular point, it represents the function's rate of change with respect to its input variable at that moment.
The derivative of a function f(x) at a point x = a is defined as the limit of the difference quotient as h approaches zero:
f'(a) = lim (h → 0) [f(a + h) - f(a)] / h
This limit represents the instantaneous rate of change or slope of the function at the point x = a. The difference quotient is the change in the function value divided by the change in the input variable (or the distance between two points on the graph of the function).
The derivative is a fundamental concept in calculus, and it has many applications in various fields of science, engineering, and economics. It allows us to calculate important quantities such as velocity, acceleration, and marginal cost, and it is used to optimize functions and solve many real-world problems.
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Exactly 50% of the area under the normal curve lies to the left of the mean.
True or False
The statement "Exactly 50% of the area under the normal curve lies to the left of the mean" is a true statement.
In a normal distribution, the mean, median, and mode all coincide, and the distribution is symmetrical.
The mean is the balance point of the distribution, with 50% of the area to the left and 50% to the right of it. Exactly 50% of the area under the normal curve lies to the left of the mean.
This implies that the distribution is symmetrical, and the mean, mode, and median are the same.
Therefore, the statement "Exactly 50% of the area under the normal curve lies to the left of the mean" is a true statement.
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Maggie makes a scale drawing of a deck. The scale for the actual deck to the scale
drawing is 7 ft to 1 in. The dimensions of the deck are 28 ft by 17.5 ft. What are the
dimensions of the deck in the drawing?
Answer:
4 inches by 2.5 inches
Step-by-step explanation:
can someone please help me.
Answer:
D = (-4,4)
E = (-4,-4)
the length from d to e is 4
Answer:
It is 3
It is 3
it is 3
it is 3
Which r–value represents the strongest negative correlation?
a.–0.7
b.–0.22
c.0.38
d.0.9
The strongest negative correlation is represented by the r-value that is closest to -1. In this case, option a, -0.7, represents the strongest negative correlation.
The answer is a. –0.7. A correlation coefficient (r-value) ranges from –1 to +1, where –1 represents a perfect negative correlation, +1 represents a perfect positive correlation, and 0 represents no correlation. The closer the r-value is to –1 or +1, the stronger the correlation. Therefore, –0.7 represents a stronger negative correlation than –0.22 or 0.38, and is not a positive correlation like 0.9.
The strongest negative correlation is represented by the r-value that is closest to -1. In this case, option a, -0.7, represents the strongest negative correlation.
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23. You decide that you don't like to use ϕ in spherical coordinates, so you will instead define a coordinate system (rho,θ,α), where α is the angle up or down from the xy-plane (rho and θ are the same as in spherical coordinates). So −π/2≤α≤π/2. (a) Obtain formulas for x,y and z in terms of rho,θ and α. (You probably want to draw some triangles.) (b) Use our method of general change of variables to determine what the rule would be for converting a triple integral into an iterated integral over rho,θ and α.
In the (rho, θ, α) coordinate system, the formulas for x, y, and z in terms of rho, θ, and α can be obtained by using trigonometric relationships and considering the geometry of the coordinate system.
To derive the formulas for x, y, and z in the (rho, θ, α) coordinate system, we can visualize a point in three-dimensional space and consider its position relative to the coordinate axes. Starting with the spherical coordinates (ρ, θ, ϕ), we can first express x, y, and z in terms of ρ, θ, and ϕ using the standard formulas. Next, we can consider the relationship between ϕ and α, which involves a rotation about the x-axis. By applying the appropriate trigonometric functions and considering the angles involved, we can establish the formulas for x, y, and z in terms of ρ, θ, and α.
Using the method of general change of variables, we can determine the rule for converting a triple integral over (ρ, θ, ϕ) into an iterated integral over ρ, θ, and α in the (ρ, θ, α) coordinate system. This involves expressing the differential volume element in terms of the new variables and adjusting the limits of integration accordingly. The Jacobian determinant plays a crucial role in this transformation, accounting for the scaling factor and orientation changes associated with the coordinate system conversion.
Understanding the formulas for x, y, and z in the (ρ, θ, α) coordinate system and the procedure for converting triple integrals provides a mathematical framework for working with this alternative coordinate system and solving problems involving volume calculations and coordinate transformations.
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Answer: Top right
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This is substituting into point-slope form.
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