Question 1 of 10 What is molarity a measurement of? O A. The volume of liquid containing a dissolved substance B. The grams of a substance dissolved in a liquid O c. The concentration of a substance dissolved in a liquid O D. The number of moles of a dissolved substance
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Answer:

neon sulfur iodine xenon

Answer:

A chemical reaction is usually accompanied by easily observed physical effects, such as the emission of heat and light, the formation of a precipitate, the evolution of gas, or a color change.

In general, the materials termed 'composites' and 'ceramics'have amorphous  arrangement of their atoms.

An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.

The protons are positively charged and neutrons are neutral and hence the nucleus is positively charged. The electrons which revolve around the nucleus are negatively charged and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.

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Your question is incomplete, but mostly probably your full question was,in general, the materials termed 'composites' and 'ceramics' have______ arrangement of their atoms.

A. Orderly

B. Amorphous

C. Lined-up

D. Branched

Answer:

Nitrogen is limiting reactant and 30.4kg of ammonia can be formed

Explanation:

Nitrogen, N₂, reacts with hydrogen, H₂ to produce ammonia, NH₃, as follows:

2N₂ + 3H₂ → 2NH₃

Where 2 moles nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia

To solve this question we must find the moles of each reactant in order to find limiting reactant. With limiting reactant we can find the moles and the mass of ammonia formed as follows:

Moles N2 -Molar mass: 28g/mol-

50000g * (1mol / 28g) = 1786 moles N2

Moles H2 -Molar mass: 2g/mol-

10000g * (1mol / 2g) = 5000 moles H2

For a complete reaction of 5000 moles H2 are needed:

5000 mol H2 * (2mol N2 / 3mol H2) = 3333 moles N2. As there are just 1786 moles, Nitrogen is limiting reactant

The moles of ammonia that can be produced are 1786 moles because 2mol N2 = 2moles NH3.

The mass of ammonia -Molar mass NH3: 17g/mol- is:

1786 moles NH3 * (17g / mol) = 30362g =

30.4kg of ammonia can be formed

The difference in lengths between the steel and copper bars at 41.0°C is 8.729 mm.

The difference in the lengths of the two bars can be calculated using the linear expansion equation;

ΔL = α × L × ΔT

where; ΔL = Difference in length

α = Coefficient of linear expansion

L = Initial length

ΔT = Change in temperature

Given; Initial length (L) = 1.500 m

Change in temperature (ΔT) = 41.0°C - (-12.0°C) = 53.0°C

The coefficient of linear expansion for steel is typically around 11 x 10⁻⁶ /°C, and for copper, it's around 16 x 10⁻⁶ /°C.

For the steel bar;

α (steel) = 11 x 10⁻⁶ /°C

For the copper bar;

α (copper) = 16 x 10⁻⁶ /°C

Now we can calculate the difference in lengths for both bars.

For the steel bar;

ΔL (steel) = α (steel) × L × ΔT

ΔL (steel) = 11 x 10⁻⁶ /°C × 1.500 m × 53.0°C

For the copper bar;

ΔL (copper) = α (copper) × L × ΔT

ΔL (copper) = 16 x 10⁻⁶ /°C × 1.500 m × 53.0°C

Converting the length difference from meters to millimeters (1 m = 1000 mm):

ΔL (steel) = 11 x 10⁻⁶ /°C × 1.500 m × 53.0°C × 1000 mm/m = 8.729 mm (rounded to three decimal places)

ΔL (copper) = 16 x 10⁻⁶ /°C × 1.500 m × 53.0°C × 1000 mm/m = 12.168 mm (rounded to three decimal places)

Therefore, the difference in the lengths of the two bars will be 8.729 mm.

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The mass percent of water in IrBr₃･4 H₂O is  14.4%.

To find the mass percent of water in  IrBr₃･4 H₂O, first determine the mass of water present in the compound and then divide it by the total mass of the compound and multiply by 100 to express the answer as a percentage.

Let's assume that the molecular weight of IrBr3•4 H2O is 500 g/mol. In that case, the mass of water present in the compound would be 4 x 18 g/mol (the molecular weight of water) = 72 g. The total mass of the compound is 500 g, so the mass percent of water in  IrBr₃･4 H₂O can be calculated as follows:

(72 g / 500 g) x 100 = 14.4%

So, the mass percent of water in IrBr₃･4 H₂O is 14.4%.

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Answer:

1.98 M

Explanation:

Step 1: Write the balanced reaction

2 NH₃ + 3 BrO⁻⟶ N₂ + 3 Br⁻ + 3 H₂O

Step 2: Calculate the moles corresponding to 0.325 g of ammonia

The molar mass of NH₃ is 17.03 g/mol.

0.325 g × (1 mol/17.03 g) = 0.0191 mol

Step 3: Calculate the reacting moles of hypobromite

The molar ratio of NH₃ to BrO⁻ is 2:3. The reacting moles of hypobromite are 3/2 × 0.0191 mol = 0.0287 mol

Step 3: Calculate the molar concentration of the hypobromite solution

M = 0.0287 mol / 0.0145 L = 1.98 M

The concentration of the hypobromite solution (BrO⁻) needed for the reaction is 1.97 M

We'll begin by calculating the number of mole in 0.325 g of NH₃. This can be obtained as follow:

Mass of NH₃ = 0.325 g

Molar mass of NH₃ = 17.031 g/mol

Mole = mass / molar mass

Mole of NH₃ = 0.325 / 17.031

Next, we shall determine the number of mole of BrO⁻ needed to react with 0.01908 mole of NH₃. This can be obtained as follow:

2NH₃ + 3BrO⁻ —> N₂ + 3Br⁻ + 3H₂O

From the balanced equation above,

2 moles of NH₃ reacted with 3 moles of BrO⁻.

Therefore,

0.01908 mole of NH₃ will react with = \(\frac{0.01908 * 3 }{2}\\\\\) = 0.02862 mole of BrO⁻.

Finally, we shall determine the concentration of the BrO⁻ solution.

Mole of BrO⁻ = 0.02862 mole

Volume of BrO⁻ solution = 14.5 mL = 14.5 / 1000 = 0.0145 L

Concentration = mole / Volume

Concentration of BrO⁻ = 0.02862 / 0.0145

Therefore, the concentration of the hypobromite solution (BrO⁻) is 1.97 M

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If this diagram represents sugar in water -

temperature of the mixture, this factor affect the solubility.

The maximum quantity of a chemical that will dissolve in a given amount of solvent at a particular temperature is referred to as its solubility. A synonym for solvability is soluble.

If a solute is a solid or liquid, its solubility rises as the temperature rises. In comparison to cold water, hot water can facilitate the dissolution of sugar. A gas-based solute becomes less soluble as temperature rises. For instance, warm water may dissolve carbon dioxide more easily than cold water.

Thus, temperature of the mixture is the factor that affect the solubility.

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Answer:

C

Explanation:

You can't have single atoms of a compound.  By definition, a compound is multiple different atoms bonded together.  The smallest unit you can have for a compound is a molecule.

Answer:

Static electricity is transferred during charging by conduction when electrons from a charged from one object to another object by direct contact. For example, on a carpet, charges are transferred from a person's feet to the rest of his/her body.

The reaction between A and B is reactant favored. This  inference can be drawn from the graph.

Chemical reactions occur all around us, including in our body's digestion of food and the creation of the sunlight's light. Understanding both chemical and physical alterations is crucial before starting any chemical reactions. The best illustration of a chemical and physical alteration is a burning candle. The reaction between A and B is reactant favored. This  inference can be drawn from the graph.

Therefore, the correct option is option A.

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Answer:

10 to the 24 power

Explanation:

Answer:

The final temperature of the copper would be 311.3°C.

I hope this helps you

Answer: ok, its C

Explanation: I used D=26.4* 3 to calculat it

Answer:

Molarity of sucrose = 0.116 M (Approx.)

Explanation:

Given:

Volume of solution = 0.5 liter

Mass of sucrose in gram = 20 gram

Molar mass of sucrose 342.3 g/mol

Find:

Molarity of sucrose

Computation:

Mole of sucrose = Mass of sucrose in gram / Molar mass of sucrose

Mole of sucrose = 20 / 342.3

Mole of sucrose = 0.058 (Approx.)

Molarity of sucrose = Mole of sucrose / Volume of solution

Molarity of sucrose = 0.058 / 0.5

Molarity of sucrose = 0.116 M (Approx.)

Expression of balanced Chemical reaction :

6 HCL (aq) + CrO3 (aq) —------> CrCl3 (aq) + 3 H2O (l) + 3 Cl (g)

What are chemical reactions?

A chemical reaction is a process in which substances (reactants) react and rearrange to form a new substance (product) with different chemical properties.

What are reactants?

Reactants are substances that participate in a chemical reaction and get converted into a new

substance (product) which have different chemical properties.

What are products?

Products are substances that are produced as a result of chemical rearrangement of reactants to produce substances with different chemical properties.

What are chemical properties?

The unique properties of substances that can only be observed while a substance undergoes a chemical reaction are known as Chemical properties. Some chemical properties are: Toxicity, Coordination number, Flammability, Enthalpy of formation, Heat of combustion, Oxidation states, chemical stability etc.

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The best description of a type C tympanogram is Negative peak pressure, lower than normal compliance.

option C

A type C tympanogram indicates negative pressure in the middle ear, which means that the peak of the tympanogram is shifted to the negative pressure side of the graph.

In addition, the compliance, or the ability of the ear to move in response to sound, is lower than normal. This can be caused by conditions such as Eustachian tube dysfunction or blockage, middle ear effusion, or allergies.

Thus, the best description of a type C tympanogram is Negative peak pressure, lower than normal compliance.

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Answer:

  A)  5.0 atm

Explanation:

You want to know the pressure in a 1 L flask at 300 K when 0.03 mol of C₃H₈ reacts completely with O₂.

We suppose the reaction of interest is ...

  C₃H₈(g) +5O₂(g) ⇒ 3CO₂(g) +4H₂O(g)

This shows us there are 3+4 = 7 moles of products for each mole of C₃H₈ in the reaction. That is, there will be 0.03 mole × 7 = 0.21 mole of products.

The gas law equation tells us the final pressure can be computed by ...

  PV = nRT

  P = nRT/V = (0.21 mol)(0.082 L·atm/(mol·K)(300 K)/(1 L) ≈ 5.166 atm

The total pressure in the flask after the reaction is closest to ...

  A) 5.0 atm

The mass of the precipitate, CrPO₄ formed when 45.5 mL of 0.300 M Na₃PO₄ react with 42.5mL of 0.200 M Cr(NO3)₃ is 1.25 g

We'll begin by calculating the number of mole of Na₃PO₄ and Cr(NO3)₃ present in the solution.

Molarity of Na₃PO₄ = 0.3 M

Volume = 45.5 mL = 45.5 / 1000 = 0.0455 L

Mole = Molarity × Volume

Mole of Na₃PO₄ = 0.3 × 0.0455

Molarity of Cr(NO3)₃  = 0.2 M

Volume = 42.5 mL = 42.5 / 1000 = 0.0425 L

Mole = Molarity × Volume

Mole of Cr(NO3)₃ = 0.2 × 0.0425

Next, we shall determine the limiting reactant.

Na₃PO₄(aq) + Cr(NO₃)₃(aq) —> CrPO₄(s) + 3NaNO₃(aq)

1 mole       :      1 mole

0.01365    :      0.0085 mole

Thus, Cr(NO₃)₃ is the limiting reactant.

Next, we shall determine the number of mole of CrPO₄ produced from the reaction.

From the balanced equation above,

1 mole of Cr(NO₃)₃ reacted to produce 1 mole of CrPO₄.

Therefore,

0.0085 mole of Cr(NO₃)₃ will also react to produce 0.0085 mole of CrPO₄.

Finally, we shall determine the mass of 0.0085 mole of CrPO₄.

Mole of CrPO₄ = 0.0085 mole

Molar mass of CrPO₄ = 52 + 31 + (16×4)

= 52 + 31 + 64

= 147 g/mol

Mass = mole × molar mass

Mass of CrPO₄ = 0.0085 × 147

Therefore, the mass of the precipitate, CrPO₄ formed is 1.25 g

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Answer:

Fixed

Explanation:

A solid is the substance that have fixed shape and size. For example: Ice,Wood etc. They have a fixed shape and volume.

Answer:

A. 4Ni(s) + 3O2(g) —> 2Ni2O3(s)

B. Synthesis reaction.

C. 18.31g of O2

Explanation:

A. The equation for the reaction.

Ni(s) + O2(g) —> Ni2O3(s)

The above equation can be balance as follow:

There are 2 atoms of O on the left side and 3 atoms on the right side. It can be balance by putting 2 in front Ni2O3 and 3 in front of O2 as shown below:

Ni(s) + 3O2(g) —> 2Ni2O3(s)

There are 4 atoms of Ni on the right side and 1 atom on the left it can be balance by putting 4 in front of Ni as shown below:

4Ni(s) + 3O2(g) —> 2Ni2O3(s)

Now the equation is balanced

B. From the equation, we can see that two reactants combined to form a single product. Therefore, the reaction is termed synthesis reaction.

C. We'll begin by calculating the mass of Ni and O2 that reacted from the balanced equation. This is illustrated below:

4Ni(s) + 3O2(g) —> 2Ni2O3(s)

Molar mass of Ni = 59g/mol

Mass of Ni from the balanced equation = 4 x 59 = 236g

Molar mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 3 x 32 = 96g

Summary:

From the balanced equation above,

236g of Ni reacted with 96g of O2.

Now, we can obtain the mass of O2 needed to react with 45g of Ni as follow:

From the balanced equation above,

236g of Ni reacted with 96g of O2.

Therefore, 45g of Ni will react with = (45 x 96)/236 = 18.31g of O2.

Therefore, 18.31g of O2 is needed to react with 45g of Ni

The equilibrium constant (Kc) for the given reaction is approximately 16.448. The value of Kc indicates the relative concentrations of reactants and products at equilibrium. In this case, a Kc greater than 1 suggests that the products (H2 and P4) are favored at equilibrium, indicating that the forward reaction is more favorable.

To determine the equilibrium constant (Kc) for the given reaction:

4PH3(g) ↔ 6H2(g) + P4(g)

We can write the equilibrium constant expression based on the stoichiometric coefficients:

Kc = ([H2]^6 * [P4]) / ([PH3]^4)

Substituting the given equilibrium concentrations:

[PH3] = 0.250 M

[H2] = 0.580 M

[P4] = 0.750 M

We can plug in these values into the equilibrium constant expression:

Kc = ([0.580]^6 * [0.750]) / ([0.250]^4)

Kc = (0.0860128 * 0.750) / (0.00390625)

Kc = 16.448

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Limiting reactant in CaCO3 + HCl = CaCl2 + CO2 + H2O is HCl.

HCl is the limiting reactant because HCl has a lower molar ratio than CaCO3 in the balanced equation.

For every 1 mole of CaCO3, 2 moles of HCl are required to react completely.

However, in the given reaction providd, there is only 1 mole of HCl. This means that the HCl will be used up first, and the CaCO3 will be in excess.

The limiting reactant is the one that gets completely consumd first in the chemical reaction, thus determining the maximum amount of product that can be formed.

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The coefficient of oxygen in the following reaction is 5.

During crystallisation, phosphorus pentoxide can exist in at least four different polymorphs or forms. The most popular variety, called a metastable form, is made up of \(P_4O_{10}\) molecules. Weak van der Waals interactions in a hexagonal lattice hold these molecules together.The \(P_4O_{10}\) cage structure is similar to the Td symmetry point group in adamantane. The \(P_4O_{10}\) cage structure is similar to the Td symmetry point group in adamantane.

\(4P + 5 O_2 \rightarrow P_4O_{10}\)

This is because the reaction involves the combination of 1 atom of phosphorus with 5 atoms of oxygen to form 1 molecule of phosphorus pentoxide (\(P_4O_{10}\)). Therefore, the coefficient of oxygen is 5.

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Answer:

Energy

4p ⇵ ⇵ ⇵

3d ⇵ ⇵ ⇵ ⇵ ⇵

4s ⇵

3p ⇵ ⇵ ⇵

3s ⇵

2p ⇵ ⇵ ⇵

2s ⇵

1s  ⇵

Answer:c

Explanation:c