A yellow-gold object has a mass of 57.9 g and its volume is 3 cm³. Could the object be made of gold?
Density of gold: 19.3 g/cm³
Yes, the object is made of gold if the yellow object has a mass of 57.9 g and its volume is 3 \(cm^{3}\).
Mass of object = 57.9 g
Volume of object = 3 \(cm^{3}\)
Also, given density of gold: 19.3 g/\(cm^{3}\)
We know that, Density = Mass/Volume
= 57.9/3
=19.3 g/\(cm^{3}\)
So we calculated the density from the given data in question.
As the density of gold and the given yellow object is same we can conclude that the object is made of Gold.
It is yellow too which is a property of gold and the density is same as well.
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Help ASAP Will mark BRainliest
Answer:
see explanation
Explanation:
beam balance
temperature degree celsius
newton meter per second
weight.
hope I was helpful to tou
A tadpole swims across a pond at 8.50 cm/s. The tail of the tadpole exerts a force of 28.0 mN to overcome drag forces exerted on the tadpole by the water.
What is the power output?
Can someone explain me, please!
Answer:
2.38 mW
Explanation:
Power is work per unit time. Work is the product of force and distance. That means ...
\(\text{power}=\dfrac{\text{force}\times\text{distance}}{\text{time}}=\text{force}\times\dfrac{\text{distance}}{\text{time}}\\\\\text{power}=\text{force}\times\text{velocity}\)
Using the given values of force and velocity, the tadpole's power output is ...
P = (0.028 N)(0.085 m/s) = 0.00238 W = 2.38 mW
The tadpole's power output is about 2.38 mW.
Which statement describes Kepler’s third law of orbital motion?
Answer:
The square of orbital period is proportional to the cube of the semi-major axis.
Explanation:
I just took the quick check
During intercourse, Lydia constantly worries whether her partner thinks she is
attractive enough. Which form of cognitive interference is Lydia experiencing?
discounting
factoring
spectatoring
cognitive reframing
Three cars are driving at 29.0 m/s along the road shown in the figure (Figure 1). Car B is at the bottom of the hill and car C is at the top. Suppose each car suddenly brakes hard and starts to skid. Assume μk=1.00. What is the x-component of the tangential acceleration (i.e., the acceleration parallel to the road) of car A?
Since the car masses are unknown, we are unable to calculate the numerical value of the x-component of Car A's tangential acceleration.
How do kinetic and potential energy compare?The energy that is held in any object or system as a function of its position or component arrangement is known as potential energy. The object or system is unaffected by external factors like air pressure or altitude. Kinetic energy, on the other hand, describes the power of moving particles within a system or an object.
They are being affected by the kinetic frictional force, which is caused by:
f = μk * N
Therefore,
fB = μk * N = μk * mB * g
Car C is at its highest point at the top of the hill, where the normal force acting on it is equal to the force of gravity. Therefore,
fC = μk * N = μk * mC * g
where mC is the mass of Car C.
For Car A, the x-component of the tangential acceleration is given by:
aA = (fB - fC) / mA
where mA is the mass of Car A.
We can substitute the following values and simplify by assuming that the mass of each of the three automobiles is the same:
aA = (μk * mB * g - μk * mC * g) / mA
aA = μk * g * (mB - mC) / mA
Since μk = 1.00 and g = 9.81 m/s², we can plug in the values and get:
aA = (mB - mC) * 9.81 / mA
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When a piece of wood is put in a graduated cylinder containing water the level of water rises from 17.7cm cubic to 18.5cm cubic calculate the total volume of the piece of wood given that it's relative density is 0.60
The total volume of the piece of wood is 1.33\(cm^3\).
To calculate the total volume of the piece of wood, we can use the principle of displacement.
1. First, we need to find the difference in volume between the two water levels. The initial volume is 17.7 \(cm^3\), and the final volume is 18.5 cm^3. The difference is 18.5 \(cm^3\) - 17.7 \(cm^3\) = 0.8 \(cm^3\).
2. Now, we need to find the volume of water displaced by the piece of wood. Since the relative density of the wood is 0.60, it means that the wood is 0.60 times denser than water.
3. The volume of water displaced by the wood is equal to the difference in volume divided by the relative density of the wood. So, the volume of water displaced is 0.8 cm^3 / 0.60 = 1.33 \(cm^3\).
4. Finally, the total volume of the piece of wood is equal to the volume of water displaced. Therefore, the total volume of the piece of wood is 1.33 \(cm^3\).
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Identify the constants that are listed for this experiment. Select all that apply.
A
wool, cotton, and nylon materials
B
feet temperature
C
amount of water
D
cold days in January
E
temperature of water
Answer: C: Amount of Water
Explanation: Because we have the water cycle, the amount of water on the Earth has never changed, it just gets filtered and reused.
Which statement describes S waves? A. They move side to side.B.They arrive betore P waves. C. They travel through liquids D. They occur at Earth's surtace.
Answer: they move side to side
Explanation:
i took the test
person a and b traveling away from each other. It takes person a 2 hours to travel a full circle, and person b 5 hours to travel a full circle. how much time will it take for a and b to meet?
Let the circumference of the circle be 10L.
A moves at 10L/2 = 5L per hour
B moves at 10L/5 = 2L per hour
Therefore it takes 10L/(5L+2L) = 10/7 hours
Kindly please tell me the answer to this question...
Following are the answers:
Pressure = \(force/area = 1.92 N/0.196 m^2 = 9.79 N/m^2\) or 9.79 PaDensity = Pressure/ (acceleration due to gravity x height) =\(9.79 N/m^2 / (9.8 m/s^2 x 0.92 m)\) = 1060 kg/m^3.What is the pressure and density?1. To calculate the pressure exerted by the water column on the surface of the mercury, we can use the formula:
Pressure = force/area
The force is the weight of the water column and the area is the cross-sectional area of the container.
The weight of the water column is given by the mass of the water times the acceleration due to gravity:
mass = density x volume
volume = area x height
So, mass = density x area x height = 1000 kg/m^3 x pi x (0.025 m)^2 x 0.25 m = 0.196 kg
Weight = mass x acceleration due to gravity =\(0.196 kg * 9.8 m/s^2\) = 1.92 N
The cross-sectional area of the container is pi x (0.025 m)^2 =\(0.196 m^2.\)
So, Pressure = force/area = \(1.92 N/0.196 m^2 = 9.79 N/m^2\) or 9.79 Pa
2. To calculate the density of the oil, we can use the formula:
density = mass/volume
Since the height of the oil column is 0.92 m and the cross-sectional area of the container is 0.196 m^2, the volume of the oil column is 0.196 m^2 x 0.92 m = 0.18012 m^3.
We do not know the mass of the oil, but we can calculate it using the pressure exerted by the oil column on the surface of the mercury:
Pressure = force/area = density x acceleration due to gravity x height
So, density = Pressure/ (acceleration due to gravity x height) = 9.79 N/m^2 / (9.8 m/s^2 x 0.92 m) = 1060 kg/m^3.
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A gardener pushes a lawn roller through a distance of 20m if he applies a force of 20kg weight in a direction inclined at 70 degree to ground find the work done by himG=9.8m/s^2
The total force applied to the roller can be obtained as,
\(\begin{gathered} F=(20\text{ kg-wt)(}\frac{9.8\text{ N}}{1\text{ kg-wt}}) \\ =196\text{ N} \end{gathered}\)The work done by the gardner can be given as,
\(W=Fd\cos \theta\)Substitute the known values,
\(\begin{gathered} W=(196N)(20m)(\frac{1\text{ J}}{1\text{ Nm}})cos70^{\circ} \\ =(3920\text{ J)(}0.342) \\ =1340.64\text{ J} \end{gathered}\)Thus, the work done by the gardener is 1340.64 J.
HELPPP!! Thanks!
If you only wanted to increase the particle motion of a gas without increasing any of its other properties, which would the most correct situation?
a. Keep the gas at a constant pressure and keep the temperature constant, but increase the volume of the gas
b. Keep the gas in a fixed container at constant pressure and increase the temperature
c. Keep the gas in a fixed container at constant pressure and decrease the temperature
d. Keep the gas at a constant volume and keep the temperature constant, but decrease the pressure of the gas
Answer:c i think
Explanation: not sure
Which of the following is a hypothesis?
A. The thickness of transparent glass affects how much light passes through.
B. Light may pass through a transparent sheet of glass.
C. A transparent sheet of glass has some effect on light.
D. Light will travel slowly through glass.
The hypothesis is, the thickness of transparent glass affects how much light passes through. Option A is correct.
A hypothesis is a proposed explanation or prediction for a phenomenon or observation that is based on limited evidence and subject to testing and validation through further investigation. It is an essential part of the scientific method, which involves developing a research question, making observations, and forming a hypothesis to explain the observed phenomenon.
The hypothesis should be testable, falsifiable, and based on evidence and reasoning. Testing the hypothesis involves designing experiments and collecting data, which can either support or refute the hypothesis. If the hypothesis is supported by the data, it may be further developed into a scientific theory, which is a widely accepted explanation of a natural phenomenon that has been extensively tested and validated. Option A is correct.
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1) Compute the x and y components of the following vectors, and state them in component form.
a) A 8.0 m South
b) B-15.0 m at 30-East of North
c) C = 12.0 m at 25-South of West -
d) D=10.0 m at 53-West of North-
a) A = 8.0 m South
Since the vector is directly along the South direction, there is no x component.
x component: 0 m
y component: -8.0 m (negative because it's southward)
Component form: A = (0, -8.0)
b) B = -15.0 m at 30° East of North
To find the components, we can use the following relationships:
x component: B_x = B * sin(θ)
y component: B_y = B * cos(θ)
B_x = -15.0 * sin(30°) = -15.0 * 0.5 = -7.5 m
B_y = -15.0 * cos(30°) = -15.0 * (sqrt(3)/2) ≈ -12.99 m
Component form: B ≈ (-7.5, -12.99)
c) C = 12.0 m at 25° South of West
x component: C_x = -C * cos(θ) (negative because it's westward)
y component: C_y = -C * sin(θ) (negative because it's southward)
C_x = -12.0 * cos(25°) ≈ -10.85 m
C_y = -12.0 * sin(25°) ≈ -5.16 m
Component form: C ≈ (-10.85, -5.16)
d) D = 10.0 m at 53° West of North
x component: D_x = -D * sin(θ) (negative because it's westward)
y component: D_y = D * cos(θ)
D_x = -10.0 * sin(53°) ≈ -8.0 m
D_y = 10.0 * cos(53°) ≈ 6.0 m
Component form: D ≈ (-8.0, 6.0)
Suppose you have two point charges of opposite sign. As you move them farther and farther apart, the potential energy of this system relative to infinity:_____________.
(a) stays the same.
(b) Increases.
(c) Decreases.
(d) The answer would depend on the path of motion
Answer:
(b) Increases
Explanation:
The potential energy between two point charges is given as;
\(U = F*r = \frac{kq_1q_2}{r}\)
Where;
k is the coulomb's constant
q₁ ans q₂ are the two point charges
r is the distance between the two point charges
Since the two charges have opposite sign;
let q₁ be negative and q₂ be positive
Substitute in these charges we will have
\(U = \frac{k(-q_1)(q_2)}{r} \\\\U = - \frac{kq_1q_2}{r}\)
The negative sign in the above equation shows that as the distance between the two charges increases, the potential energy increases as well.
Therefore, as you move the point charges farther and farther apart, the potential energy of this system relative to infinity Increases.
In order to get going fast, eagles will use a technique called stooping, in which they dive nearly straight down and tuck in their wings to reduce their surface area. While stooping, a 6- kg golden eagle can reach speeds of up to 53 m/s . While golden eagles are not very vocal, they sometimes make a weak, high-pitched sound. Suppose that while traveling at maximum speed, a golden eagle heads directly towards a pigeon while emitting a sound at 1.1 kHz. The emitted sound has a sound intensity level of 30 dB when heard at a distance of 5 m .A) Model this stooping golden eagle as an object moving at terminal velocity. The eagle’s drag coefficient is 0.5 and the density of air is 1.2 kg/m 3 . What is the effective cross-sectional area of the eagle’s body while stooping?B) What is the doppler-shifted frequency that the pigeon will hear coming from the eagle?C) Consider the moment when the pigeon is 5 m away from the eagle. At the pigeon’s position, what is the intensity (in W/m^2 ) of the sound the eagle makes?D) The golden eagle slams into the 250- g pigeon, which is initially moving at 10 m/s in the opposite direction (toward the eagle). The eagle grabs the pigeon in its talons, and they move off together in a perfectly inelastic collision. How fast do they move after the collision?
Answer:
Check the explanation
Explanation:
Part A
F = CA
this drag force balances the weight = 6X 9.8
so
6X9.8 = 0.5 X A X0.5 X 1.2 X 532
A= 0.069 m2
Part B
here the sorce is moving and the observer is at rest
so f= f(- 1 - 1
f = 1.1X10 343 343 – 53
f' = 1.3 KHz
Part C:
given the intensity = 30 dB
we know that I dB = 10 log (I(W/m2))
so we get I (W/m2) = 1000
Part D : The catch
Given that U1 = 53 M1 = 6 kg
U2 =-10 M2=0.25
V1=V2
now conserving momentum
6 X 53 -0.25 X10 =(6+0.25)V
V= 50.48 m/sec
Calculate the equivalent resistance
Help pls for some reason here’s my problem when I look at my iPad to much and I look at something far away it’s kinda blurry but when I rest my eyes by not looking at the screen it’s kinda gets better this has been happening for a month
Answer: Hello! I believe you might have a condition known as Digital Eye Strain (DES). This is cause by too much screen time, poor posture, bad lighting and viewing distance.
Before you panic, this is not permanent. Here’s some ways to help prevent it :
• Put the screen 20-28 inches away, 4-5 in below eye level and adjust your brightness. (Make sure your screen isn’t too bright)
•Rest your eyes for 15 minutes every 2 hours.
•Try the 20-20-20 rule: look at an object 20 ft away for 20 seconds every 20 minutes.
Please rest your eyes more. If it doesn’t go away after a bit. Please book a appointment with your eye doctor to make sure everything’s alright :)
let me know if you have any questions! :)
PLEASE HELP ANSWER FAST As the vibration of molecules decreases, the _____ of the substance decreases. 1.temperature 2.internal energy 3.kinetic energy 4.all of the above
find the age for a rock for which you determine that 53 % % of the original uranium-238 remains, while the other 47 % % has decayed into lead.
The age of the rock is approximately 2.58 billion years.
The half-life of uranium-238 is approximately 4.47 billion years. This means that after 4.47 billion years, half of the original uranium-238 will have decayed into lead.
We can use this information to determine the age of a rock for which we have measured that 53% of the original uranium-238 remains.
If 53% of the original uranium-238 remains, then 47% has decayed into lead.
Since half of the original uranium-238 decays every 4.47 billion years, the ratio of remaining uranium-238 to original uranium-238 after t years is given by:
\((remaining uranium-238) / (original uranium-238) = 0.53 = e^(-t/4.47E9)\)
Solving for t, we get:
\(t = -4.47E9 * ln(0.53) = 2.58 billion years\)
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Suppose that you cut a sugar cube into smaller and smaller parts. If you
could separate out one molecule, which of these describes what you have?
A. a carbon atom.
B. a molecule without atoms.
C. a molecule with no mass.
D. a molecule of sugar.
Answer:
c
Explanation:
jsjdkksddssddddddmekekwkkwkekeke
视图(V) 30 Q HEAT TRANSFER X Exercise: (H) Solution. 64 /93 64.4% EXXES ↓ a An thick-walled tube of stainless steal (18% Cr, 8% Ni, k=19 W/(m °C)) with 2-cm inner diameter (ID) is covered with a 3-cm layer of asbestos insulation (k=0.2 W/(m-°C)). If the inside wall temperature of the pipe is maintained at 600°C, calculate the heat loss per meter of length. Also calculate the tube-insulation interface temperature.
The tube-insulation interface temperature is 593.4°C.
What is the insulation material's temperature index?Electrical insulating materials (EIMs), which are used in electric machines and apparatus, can be classified according to their temperature using the temperature index (TI), a typical measurement. In most cases, accelerated life testing lasting >7-8 months at accredited labs is used to acquire TI.
we can use the following equation,
q = 2πkL(T1 - T2) / [ln(r2/r1)]
where q = heat transfer rate per unit length
k = thermal conductivity
L = length of the cylinder
T1 = inside temperature of the tube
T2 = outside temperature of the insulation
r1 = inner radius of the tube
r2 = outer radius of the insulation.
we have to calculate the outer radius of the tube,
r1 = 1 cm
r2 = r1 + 3 cm = 4 cm
we can calculate the heat transfer rate per meter of length:
q = 2π(19 W/(m°C))(1 m)(600°C - T2) / [ln(0.04 m/0.01 m)]
We need to solve for T2,
T2 = 450.7 °C
So, the heat loss per meter of length is,
q = 2π(19 W/(m°C))(1 m)(600°C - 450.7°C) / [ln(0.04 m/0.01 m)]
q = 668.6 W/m
Now, we can calculate the tube-insulation interface temperature,
q = 2π(0.2 W/(m°C))(1 m)(T1 - T2) / [ln(0.06 m/0.04 m)]
we get:
T1 = 593.4 °C
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A motorboat, which has a speed of 5 meters per sec-
ond in still water, is headed east as it crosses a river
flowing south at 3.3 meters per second. What is the
magnitude of the boat’s resultant velocity with respect
to the starting point?
1. 3.3 m/s
2. 5.0 m/s
3. 6.0 m/s
4. 8.3 m/s
The magnitude of the boat’s resultant velocity with respect to the starting point is 6.0 m/s. Hence, option (3) is correct.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
The velocity of the boat in still water = 5 meters per second along east.
The velocity of stream = 3.3 meters per second along south.
Hence, the magnitude of the boat’s resultant velocity with respect to the starting point is = √(5² + 3.3²) m/s
=6.0 m/s.
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8:11
GCSE Science - Physics
22 of 25
14 67%
A cat accelerates from rest to 10 m/s
when it sees a dog. This takes 2
the cat?
seconds What is the acceleration of the cat ?
the acceleration of the cat is 5m/s square
An object of mass 10 kg is in a circular orbit of radius 10 m at a velocity of 10 m/s. What is the acceleration of this obiect?
Answer:
The acceleration of the object can be calculated using the formula:
a = v^2 / r
where v is the velocity of the object and r is the radius of the circular orbit.
Substituting the given values, we get:
a = (10 m/s)^2 / 10 m
a = 100 m/s^2
Therefore, the acceleration of the object is 100 m/s^2.
PLEASE HURRY!!!
WILL MARK!!!
Which statement describes a difference between the lower mantle and oceanic crust?
Answer:
Its C on edge
Explanation:
trust me
A kangaroo can jump over an object 2.20 m high with a vertical speed of 6.57 m/s. how long is it in the air
The kangaroo is in the air for approximately 0.667 seconds.
What is the velocity?Velocity is defined as the displacement of the object in a given amount of time and is referred to as velocity.
A kangaroo with a vertical speed of 6.57 m/s may jump over an object 2.20 m high.
To find the time a kangaroo is in the air, we need to calculate the time it takes to reach the peak of its jump and then double that time (to account for both the ascent and descent).
We can use the formula for vertical motion under constant acceleration (g = 9.8 m/s²):
t = √(2h / g)
where h is the height of the jump (2.20 m) and g is the acceleration due to gravity (9.8 m/s²).
Plugging in the values, we get:
t = √(2 × 2.20 m / 9.8 m/s²)
t = √(0.447)
t ≈ 0.667 s
So the kangaroo is in the air for approximately 0.667 seconds.
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How many spoonfuls of water did it take for your sponge to be 100% saturated?
Answer:
19
Explanation:
I legit did this and it took 19.
When 33 volts are connected across a resistor, the current through the resistor is 4.7 amps. What is the resistance of the resistor (in ohms)
Answer:
7.02 ohms
Explanation:
R = V / I