Q#2 The power flowing in a 3-phase, 400 V, 3 wire balanced load system is measured by two wattmeter method. The reading of wattmeter A is 45 kW and of wattmeter B is 45 kW. Determine: (a) The system power factor (PF), line current, active, and reactive power (b) If the PF is changed to 0.866 lagging calculate the line current and the reading of each device (c) If the PF is changed to 0.866 leading calculate the reading of each device
Answers
In the given scenario, a balanced load system with two wattmeters is used to measure power. The readings of wattmeter A and B are both 45 kW. Let's analyze the situation and calculate the required parameters.
(a) The system power factor (PF) can be determined using the wattmeter readings. In a balanced load system, the total power is given by the sum of the wattmeter readings. Thus, the total power is 45 kW + 45 kW = 90 kW. The power factor (PF) is the ratio of the active power to the apparent power. Since the apparent power in a 3-phase system is given by the product of line current (I) and line voltage (V), we can use the formula: Apparent Power (S) = √3 * V * I. In this case, the line voltage is 400 V. So, 90 kW = √3 * 400 V * I. Solving for I, we find I ≈ 130.9 A. The active power (P) is given by the formula: Active Power (P) = PF * Apparent Power. Since PF = P / S, we can substitute the values to get P = PF * 90 kW. The reactive power (Q) can be found using the formula: Reactive Power (Q) = √(Apparent Power^2 - Active Power^2).
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Related Questions
An AC bridge has 4 arms. In arm AB, a 120 kilo-ohm resistor and a 47 microfarads capacitor are connected in parallel while arm BC has 330 microfarads capacitor. If arm AD has a 330 kilo-ohm resistor, calculate the value of the unknown capacitor and resistor in arm CD connected in series. (AC power is supplied through A and C while the detector is connected across BD)
Answers
The unknown capacitor in arm CD must have a value of 330 microfarads, and the unknown resistor must have a value of 100 kilo-ohms.
To solve the problem, use the following formula:
Cseries = C1 x C2 / (C1 + C2)
Where C1 is the value of the capacitor in arm AB (47 microfarads) and C2 is the value of the capacitor in arm BC (330 microfarads).
Therefore, Cseries = 330 microfarads.
Also, the total resistance of arms CD is the sum of the resistance of the resistor (R) and the reciprocal of the capacitive reactance of the capacitor (1/Xc).
Using the following formula:
Rtotal = R + 1/Xc
Where Xc = 1/2πfC,
f is the frequency and C is the capacitance.
For this problem,
Xc = 1/2π(50)(330 x 10-6)
=> 100 kilo-ohm.
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Some of our modern kitchen cookware is made of ceramic materials. (a) List at least three important characteristics required of a material to be used for this application. (b) Make a comparison of three ceramic materials as to their relative properties and, in addition, to cost. (c) On the basis of this comparison, select the material most suitable for the cookware.
Answers
Answer:
A)
It should be Non- toxic
It should possess high Thermal conductivity
It should have the Required Thermal diffusivity
B)
stoneware : This material has good thermal diffusivity and it is quite affordable and it is used in making pizza stonesporcelain: mostly used for mugs and it is non-toxic Pyrex : posses good thermal conductivity used in ovenC) All the materials are suitable because they serve different purposes when making modern kitchen cookware
Explanation:
A) characteristics required of a ceramic material to be used as a kitchen cookware
It should be Non- toxicIt should possess high Thermal conductivityIt should have the Required Thermal diffusivityB) comparison of three ceramic materials as to their relative properties
stoneware : This material has good thermal diffusivity and it is quite affordable and it is used in making pizza stonesporcelain: mostly used for mugs and it is non-toxic Pyrex : posses good thermal conductivity used in ovensC) material most suitable for the cookware.
All the materials are suitable because they serve different purposes when making modern kitchen cookware
4.11 LAB: Mileage tracker for a runner Given the MileageTrackerNode class, complete main() in the MileageTrackerLinkedList class to insert nodes into a linked list (using the insertAfter() method). The first user-input value is the number of nodes in the linked list. Use the printNodeData() method to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is:
Answers
Using the knowledge of computational language in C++ it is possible to write a code that user-input value is the number of nodes in the linked list
Writting the code:#include "MileageTrackerNode.h"
#include <string>
#include <iostream>
using namespace std;
int main(int argc, char *argv[]) {
// References for MileageTrackerNode objects
MileageTrackerNode *headNode;
MileageTrackerNode *currNode;
MileageTrackerNode *lastNode;
double miles;
string date;
// Front of nodes list
headNode = new MileageTrackerNode();
lastNode = headNode;
// Read in the number of nodes
int no_nodes;
cin >> no_nodes;
// For the read in number of nodes, read in data and insert into the linked list
MileageTrackerNode *tail = headNode;
for (int i = 0; i < no_nodes; ++i) {
double milesInit;
cin >> milesInit;
cin >> date;
MileageTrackerNode *newNode = new MileageTrackerNode(milesInit, date, nullptr);
tail->InsertAfter(newNode);
tail = newNode;
}
// Call the PrintNodeData() method to print the entire linked list
MileageTrackerNode *cur = headNode->GetNext();
while (cur != nullptr) {
cur->PrintNodeData();
cur = cur->GetNext();
}
// MileageTrackerNode Destructor deletes all following nodes
delete headNode;
}
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Which of these was not part of the OBD II implementation?
OA. Common Codes
OB. Readiness Monitors
OC. Digital Processing
OD. Standard Terminologies
Answers
The Digital Processing is not part of the OBD II implementation.
What is an OBD II system?OBD II is known to be a kind of acronym for On-Board Diagnostic II. This is known to be the second generation of on-board self-diagnostic equipment that is needed for light- and medium-duty California vehicles.
The OBD-II is said to be a kind of on-board computer that handles emissions, , speed, etc.
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The gcf method returns the greatest common factor of parameters a and b, as determined by case I and case II. Write the gcf method below. You are encouraged to implement this method recursively.
Answers
The use GCF method is correctly illustrated recursively below
What is GCF (Greatest common factor)The GCF is the greatest common factor that can be used to correctly divide two or more numbers without a reminder.
For example,
The parameters 20 and 30, to know the greatest common factor, write out each factors of 20 and 30
The factors of 20 = 1, 2, 4, 5, 10, and 20
The factors of 30 = 1, 2, 3, 5, 6, 10, 15, and 30
Therefore the GCF = 10
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charging method .Constant current method
Answers
Answer:
There are three common methods of charging a battery; constant voltage, constant current and a combination of constant voltage/constant current with or without a smart charging circuit.
Constant voltage allows the full current of the charger to flow into the battery until the power supply reaches its pre-set voltage. The current will then taper down to a minimum value once that voltage level is reached. The battery can be left connected to the charger until ready for use and will remain at that “float voltage”, trickle charging to compensate for normal battery self-discharge.
Constant current is a simple form of charging batteries, with the current level set at approximately 10% of the maximum battery rating. Charge times are relatively long with the disadvantage that the battery may overheat if it is over-charged, leading to premature battery replacement. This method is suitable for Ni-MH type of batteries. The battery must be disconnected, or a timer function used once charged.
Constant voltage / constant current (CVCC) is a combination of the above two methods. The charger limits the amount of current to a pre-set level until the battery reaches a pre-set voltage level. The current then reduces as the battery becomes fully charged. The lead acid battery uses the constant current constant voltage (CC/CV) charge method. A regulated current raises the terminal voltage until the upper charge voltage limit is reached, at which point the current drops due to saturation.
two technicians are discussing waste spark ignition systems. technician a says that half of the plugs fire toward the ground electrode. technician b says that only half of the negative electrodes will exhibit wear. who is correct?
Answers
Technician A is correct. In a waste spark ignition system, each cylinder has two spark plugs. One spark plug fires during the compression stroke, while the other spark plug fires during the exhaust stroke.
The spark plug firing during the exhaust stroke does not ignite any fuel mixture but instead, it serves to keep the cylinder clean by burning off any unburned fuel. The spark plug firing during the compression stroke ignites the fuel mixture, and in a waste spark ignition system, it fires toward the ground electrode.
Therefore, half of the spark plugs fire toward the ground electrode, as stated by Technician A.
Technician B's statement is not entirely accurate. While it is true that one of the spark plugs in each cylinder will have a negative electrode, wear on the electrodes can vary based on a number of factors, such as driving conditions and the quality of the spark plugs. So, it cannot be assumed that only half of the negative electrodes will exhibit wear.
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The rafter is fastened to the outside wall so that the plumb cut in the birdsmouth is tight to the exterior wall sheathing
Select one:
O True
O False
Answers
what pilot certification and aircraft equipment are required for operating in class c airspace?
Answers
To fly in Class C airspace, no special pilot licence is needed.
What is a pilot known as?A individual who uses an airplane's directional flying instruments is known as an aviation pilot or aviator. Due to their involvement in running the aircraft's guidance and engine systems, some other members of the aircrew, such as navigators as well as flight crew, are also regarded as aviators.
How long does the instruction take to become a pilot?The optimal length of time to train as a pilot is 3–4 years to earn a bachelor of science in commercial flight. It is better to wait until you reach at least 18 years old to start your journey because getting a degree is great for regularity of training.
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6.03 Discussion: Then & Now - Safety
Discussion Topic
I'm Done
In this unit, you have learned about the evolution of the industry’s machines, through both technology and innovation. These improvements have reduced risk and injury to the Operating Engineers.
Choose one innovation or device.
Explain why you think that technology is the most important advancement in Operating Engineers’ safety.
Answers
Answer:
Information technology is important in our lives because it helps to deal with every day's dynamic things. Technology offers various tools to boost development and to exchange information. Both these things are the objective of IT to make tasks easier and to solve many problems.
for reduced voltage start up for an induction motor you would need a(n) _______________.
Answers
Answer:
For reduced voltage start-up of an induction motor, you would need a motor starter or a motor controller with a reduced voltage starting method.
Which of the following is NOT a line used on blueprints?
Answers
Answer: Photo lines
Explanation: made more sense
The cylinder C is being lifted using the cable and pulley system shown.
If point A on the cable is being drawn toward the drum with a speed of 1 m/s , determine the velocity of the cylinder.
Answers
Answer:
sry but it's kinda hard
a load of 12tonnes is put along a horizontal plane by a force at 30°to and above the flat. if the coefficient of sliding friction is 0.2 find the frictional force
Answers
Answer:
20368.917N
Explanation:
Frictional force (F) is the product of the Coefficient of friction and the normal reaction.
F = μN
Coefficient of friction, μ = 0.2
Normal reaction = MgCosθ
Mass, m = 12 tonnes = 12 * 1000 = 12000 kg
N = 12000 * 9.8 * cos30
N = 101844.58
F = 0.2 * 101844.58
F = 20368.917N
the application of engineering to create materials on a molecular or atomic scale is:
Answers
The application of engineering to create materials on a molecular or atomic scale is known as nanotechnology.
Nanotechnology refers to the field of science, engineering, and technology that deals with the manipulation and control of matter at the nanoscale. It involves the study and utilization of materials, devices, and systems with properties and functionalities that emerge at the nanometer scale, typically ranging from 1 to 100 nanometers.
At the nanoscale, the behavior of materials can differ significantly from their macroscopic counterparts due to quantum mechanical effects and increased surface area-to-volume ratios. Nanotechnology aims to understand and harness these unique properties to create new materials, devices, and applications with enhanced performance and novel functionalities.
Nanotechnology finds applications in various fields such as electronics, medicine, energy, materials science, and environmental science. Examples include the development of nanoelectronics for smaller and more efficient electronic devices, nanomedicine for targeted drug delivery and diagnostics, nanomaterials with improved strength and lightweight characteristics, and nanosensors for detecting pollutants and contaminants.
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What is wrong with the following code?
6
print (what is your name?)
Answers
Answer:
pakipic na lang po question nyo para masagot po
Explanation:
please po di ko masyado gets po e
it is simple the title name after all it is just asking your name
in step 5, you demonstrated the circuit functionality by testing different combinations of inputs. what are the potential challenges of testing larger circuits with more inputs using this technique?
Answers
When testing larger circuits with more inputs, using the technique of testing different combinations of inputs, there are several potential challenges that may arise.
Time-consuming: As the number of inputs increases, the number of possible combinations also increases exponentially. Testing all combinations can become time-consuming and impractical. Resource-intensive: Larger circuits with more inputs may require additional resources such as power, memory, and processing capabilities. Testing these circuits may require significant resources and infrastructure. Complexity: The complexity of larger circuits with more inputs increases, making it more challenging to identify and isolate potential faults or errors during testing. This can result in longer debugging and troubleshooting times. Test coverage: Testing all possible combinations of inputs may not guarantee complete test coverage. It is possible to miss certain corner cases or scenarios that may lead to errors in the circuit's functionality. In conclusion, testing larger circuits with more inputs using the technique of testing different combinations of inputs can be time-consuming, resource-intensive, and complex. It may also result in incomplete test coverage. Therefore, alternative testing methods and strategies may be required to overcome these challenges and ensure thorough testing of larger circuits.
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Explain why a hydraulic system would fail to be the best choice in the following scenario.
Henry is an engineer at Verizon. He is developing a tool that can burrow underground and shoot wires up to 50 feet along the yards of individual
houses. The tool needs to create the least amount of ground disturbance possible. He has decided to design a device that uses a hydraulic power
system
Answers
Answer:
The correct answer is that a hydraulic power system is used for large amounts of force.
Explanation:
A pneumatic power system would be much more effective at focusing on a specific area. One person would be able to hold a pneumatic system, as the design can be made small. It can even be designed with a simple on/off switch.
The hydraulic system would fail because hydraulic power system is used for large amounts of force.
What is the hydraulic system?Energy or signals are transported through the static or dynamic forces of liquids in hydraulic power transmission systems. These fluid power systems are a subset of them. The two types of fluid power are hydraulics and pneumatics. The valves aid in controlling the liquid's flow and relieving pressure when necessary.
Pumps are used in hydraulic systems to force hydraulic fluid through the system and generate fluid power. The fluid flows to the cylinder, where the hydraulic energy is converted back into mechanical energy, after passing through the valves.
Therefore, Due to the hydraulic system's need for high levels of force, it would malfunction.
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Describe some typical pairs of entities that you think might be common in business, and describe their relationships, whether many-to-many, one-to-many, many-to-one, or one-to-one. Explain why you think that a particular relationship applies to that pair of entities.
Answers
Answer:
Sole Proprietorship, General Partnership , Limited Partnership, corporation
Explanation:
Business in something that an individual or a group of people do for a living and produce products and services that benefits the society and the people. There are several entities that can be common in business. Some common form of entities are :
Sole Proprietorship : One to one
-- here there is only one owner in the business and he maintains and manages the entire business functions under his control.
Limited Partnership : many to one
-- here two or more than two partners establish business and runs it but only one or more is liable to the amount of the investments.
General Partnership : many to many
-- It is a business partnership where all the partners shares the profits, the assets, legal liabilities and financial liabilities, etc.
Corporation : many to one
It is a business entity where a group of individual or a group of companies run a single business which is generally authorized by the state.
Some of the typical types of the entities that one may think to be common in term of the business entities are about the relationships that are held within many to many and one to many.
The one to one relation is Sole Proprietorship, General Partnership, Limited Partnership, corporation.Learn more about the typical pairs of entities.
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What are some drawbacks of BGP? What is the biggest problem?
Answers
Some drawbacks of BGP (Border Gateway Protocol) include its slow convergence, complexity, and vulnerability to security threats. BGP's slow convergence can result in network instability, as it may take a considerable amount of time for routers to update their routing tables after changes in the network topology.
This delay can lead to packet loss, increased latency, and overall decreased network performance. The complexity of BGP can make configuration and management challenging, especially in large-scale networks. This complexity often requires experienced network administrators who are familiar with BGP's numerous features and options. Misconfigurations can lead to routing loops, suboptimal routing, and even network outages. BGP is also susceptible to security threats such as route hijacking, route leaks, and prefix hijacking. Attackers can exploit BGP's trust-based nature to propagate false routing information, potentially causing traffic to be rerouted, intercepted, or dropped. The biggest problem associated with BGP is arguably its vulnerability to security threats, as these can have severe consequences for the integrity and reliability of the Internet. Mitigating these threats requires both technical and cooperative efforts from network operators and the broader Internet community.
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A 250 kilo ohms and a 750 kilo ohms resistor are connected in series across a 75-volt source. Determine the error in measuring the voltage across each of these resistances when the voltage is read with (a)0-150 volt, 1000 ohms/volt meter
(b)0-75 volt, 20000 ohms/volt meter
(c)voltmeter with an input impedance of 20 megaohms
Answers
Answer:
(a) -55.6%, -31.25 V
(b) -11.1%, -6.25 V
(c) -0.93%, -0.52 V
Explanation:
The open-circuit voltage is (75V)(750/(250+750)) = 56.25 V.
The circuit to which the meter is connected has a Thevenin equivalent impedance of 1/(1/250 +1/750) = 187.5 kΩ. So, the relative error for a given meter impedance of R (in kΩ) is ...
(R/(R +187.5) -1) × 100% = -187.5/(R +187.5) × 100%
(a) For a meter impedance of (1 kΩ/V)×150V = 150 kΩ, the error is ...
-187.5/(150 +187.5) × 100% ≈ -55.6%
The voltage error is (56.25 V)(-55.6%) = -31.25 V.
__
(b) For a meter impedance of (20 kΩ/V)×75V = 1500 kΩ, the error is ...
-187.5/(1500+187.5) × 100% ≈ -11.1%
The voltage error is (56.25 V)(-5.88%) = -6.25 V.
__
(c) For a meter impedance of 20,000 kΩ, the error is ...
-187.5/(20000+187.5) × 100% ≈ -0.93%
The voltage error is (56.25 V)(-0.93%) = -0.52 V.
Sadie is the props manager for a small community theater. Because she does not have a part onstage, Sadie is not part of the Performing Arts pathway of the Arts, AV Technology and Communication cluster.
True
False
Answers
Answer:
I think it is false!
Explanation:
Answer: I think it's true
Explanation:
Because if you were part of a play, you would have a part but if you work on props, you don't have a part onstage.
Environmental engineers monitor the progress of improvement programs by inspecting industrial and municipal facilities for regulation compliance.
True or False?
Answers
true
the answer to this question is true
What is the meaning of beauty and completeness? In relation to these what are the attributes a Muslim should adopt?
Answers
ᴄᴏᴍᴘʟᴇᴛᴇɴᴇꜱꜱ ᴍᴇᴀɴꜱ ᴛʜᴇ ꜱᴛᴀᴛᴇ ᴏꜰ ʙᴇɪɴɢ ᴄᴏᴍᴘʟᴇᴛᴇ ᴀɴᴅ ᴇɴᴛɪʀᴇ; ʜᴀᴠɪɴɢ ᴇᴠᴇʀʏᴛʜɪɴɢ ᴛʜᴀᴛ ɪꜱ ɴᴇᴇᴅᴇᴅ.
ʙᴇᴀᴜᴛʏ ᴍᴇᴀɴꜱ combination of qualities, such as shape, colour, or form, that pleases the aesthetic senses, especially the sight.
Your front lawn measures 60 feet by 25 feet. How many ources of herbicide would be needed if the label rate is expressed as 3.75 pounds/acre? ( pound-16 ounces)
Answers
Approximately 0.006500392 ounces of herbicide would be needed to cover your front lawn, given the label rate of 3.75 pounds/acre.
To determine the number of ounces of herbicide needed for your front lawn, we first need to calculate the area of your lawn in acres. Here are the steps to calculate it:
1. Convert the dimensions of your front lawn from feet to acres:
- Length: 60 feet ÷ 1 acre = 0.015625 acres
- Width: 25 feet ÷ 1 acre = 0.00694444 acres
2. Multiply the length and width to obtain the area in acres:
- Area: 0.015625 acres × 0.00694444 acres = 0.000108506 acres
Now that we have the area in acres, we can calculate the amount of herbicide needed based on the label rate provided, which is expressed as 3.75 pounds per acre.
3. Multiply the label rate (3.75 pounds/acre) by the area of your lawn (0.000108506 acres):
- Amount of herbicide needed: 3.75 pounds/acre × 0.000108506 acres = 0.0004062745 pounds
Finally, we need to convert pounds to ounces since the herbicide is typically measured in pounds and ounces.
4. Convert pounds to ounces:
- 1 pound = 16 ounces
- Amount of herbicide needed: 0.0004062745 pounds × 16 ounces/pound = 0.006500392 ounces
It's important to note that the calculated amount is an estimate based on the given dimensions and label rate. For precise application and safety, please refer to the specific instructions provided by the herbicide manufacturer, as different products may have different application rates and guidelines.
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A fast moving hurricane produces a constant rainfall intensity of 110 mm/h for 45 min. The area consists almost entirely of sandy loam, which typically has a saturated hydraulic conductivity of 9.1 mm/h, average suction head of 110 mm, porosity of 0.45, field capacity of 0.190, wilting point of 0.085, and depression storage of 4 mm. Calculate the cumulative infiltration after 30 min, assuming ponding is continuous from the beginning of the storm. Assume the initial water content is midway between the field capacity and wilting point..
Answers
Answer:
hello some part of your question is missing ( The table ) attached below is the missing detail related to your question
answer: cumulative infiltration after 30 mins = 6.7
Explanation:
Calculate the cumulative infiltration after 30 min
formula for calculating cumulative infiltration
= 11( t - tp + t' ) = F - 34.3 In ( 1 + 0.0291 * F )
Attached below is a detailed solution to the problem
A project ha following time chedule: Activity Time in Week Activity Time in Week 1-2 4 5-7 8 1-3 1 6-8 1 2-4 1 7-8 2 3-4 1 8-9 1 3-5 6 8-10 8 4-9 5 9-10 7 5-6 4 Contruct the network and compute: (1) TE and TL for each event (2) Float for each activity (3) Critical path and it duration
Answers
(1) TE and TL for each event
Event 1: TE=0, TL=0
Event 2: TE=4, TL=4
Event 3: TE=1, TL=5
Event 4: TE=2, TL=6
Event 5: TE=6, TL=12
Event 6: TE=1, TL=2
Event 7: TE=8, TL=16
Event 8: TE=9, TL=17
Event 9: TE=8, TL=18
Event 10: TE=16, TL=23
(2) Float for each activity
Activity 1-2: Float=0
Activity 1-3: Float=3
Activity 2-4: Float=2
Activity 3-4: Float=1
Activity 3-5: Float=0
Activity 4-9: Float=0
Activity 5-6: Float=0
Activity 5-7: Float=0
Activity 6-8: Float=7
Activity 7-8: Float=6
Activity 8-9: Float=5
Activity 8-10: Float=0
Activity 9-10: Float=0
(3) The critical path for this project is: 3-4, 4-9, 5-7, 7-8, 8-10, 9-10, with a total duration of 23 weeks.
THE SOLUTIONTo construct the network and compute the requested information, we first need to create a list of events and activities.From the given schedule, we can identify the following events and activities:Events:1, 2, 3, 4, 5, 6, 7, 8, 9, 10
Activities:1-2: 4 weeks
1-3: 1 week
2-4: 1 week
3-4: 1 week
3-5: 6 weeks
4-9: 5 weeks
5-6: 4 weeks
5-7: 8 weeks
6-8: 1 week
7-8: 2 weeks
8-9: 1 week
8-10: 8 weeks
9-10: 7 weeks
Now we can compute the TE (time when an event is expected to start) and TL (time when an event is expected to be completed) for each event, as well as the float (amount of time that an activity can be delayed without delaying the project completion) for each activity.TE and TL for each event:Event 1: TE=0, TL=0
Event 2: TE=4, TL=4
Event 3: TE=1, TL=5
Event 4: TE=2, TL=6
Event 5: TE=6, TL=12
Event 6: TE=1, TL=2
Event 7: TE=8, TL=16
Event 8: TE=9, TL=17
Event 9: TE=8, TL=18
Event 10: TE=16, TL=23
Float for each activity:Activity 1-2: Float=0
Activity 1-3: Float=3
Activity 2-4: Float=2
Activity 3-4: Float=1
Activity 3-5: Float=0
Activity 4-9: Float=0
Activity 5-6: Float=0
Activity 5-7: Float=0
Activity 6-8: Float=7
Activity 7-8: Float=6
Activity 8-9: Float=5
Activity 8-10: Float=0
Activity 9-10: Float=0
The critical path is the sequence of activities that have zero float, meaning they cannot be delayed without delaying the project completion. The critical path for this project is: 3-4, 4-9, 5-7, 7-8, 8-10, 9-10, with a total duration of 23 weeks.Learn more about Construct Network here:
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Which of the following is NOT a peripheral?
Input devices
Output devices
CPU devices
Input/Output devices
Answers
Answer:
I believe that cpu devices are not considered peripherals
Explanation:
From google: A peripheral or peripheral device is an ancillary device used to put information into and get information out of the computer.
given the standard cell potential for this cell is 0.115 v, and the measured cell potential is 0.0925, what is the concentration of chloride ions in the solution?
Answers
The concentration of chloride ions in the solution can be calculated by using the Nernst equation.
The Nernst equation is used to calculate the potential of an electrochemical cell under non-standard conditions. It relates the electrode potential to the concentrations of the species present in the solution.
The Nernst equation is:E = E° - (RT/nF) ln(Q)where, E is the cell potential under non-standard conditions,E° is the standard electrode potential, R is the gas constant, T is the temperature, n is the number of moles of electrons transferred, F is the Faraday constant, and Q is the reaction quotient.In this case, the standard cell potential (E°) is 0.115 V, and the measured cell potential (E) is 0.0925 V.
The reaction is given as:2AgCl(s) + 2e- → 2Ag(s) + 2Cl-(aq)We can see that n = 2 (two electrons are transferred in the reaction).The Nernst equation can be rearranged to solve for the concentration of chloride ions (Cl-) in the solution:ln(Cl-) = (E° - E)/(0.0592/n)ln(Cl-) = (0.115 - 0.0925)/(0.0592/2)ln(Cl-) = 0.378M[Cl-] = e^0.378M[Cl-] = 1.46 MTherefore, the concentration of chloride ions in the solution is 1.46 M.
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P3. Imagine you are working with an air compressor. The compressor sucks air at atmospheric pressure, P₁ , and Tᵢₙ and provides a pressurized air feed for a system with pressure P₂ and temperature T₂ which P₂ > P₁ and T₂ >T₁ . The velocity of air at inlet and outlet are the same as well as the height of the inlet and outlet. Assume that the compressor body could exchange heat with surroundings (ambient air could be stagnant or circulating) and ignore radiation and no cooling system was designed for the compressor. Sketch the schematic of the system and write the energy balance with all possible heat transfer modes for the compressor.
Answers
The heat generated by the compressor would be transferred to the surroundings through convection and conduction.
The schematic of the system is shown below;
The energy balance with all possible heat transfer modes for the compressor can be written as follows;Q + W = ΔHWhere,Q = heat transfer
W = work transferΔH = change in enthalpy
Since the compressor is assumed to exchange heat with the surroundings, the heat transfer can occur in two ways, which are conduction and convection.
However, radiation heat transfer is ignored. The heat transfer can be represented as;
Q = Q_convection + Q_conductionwhereQ_convection = hA(T_s - T_∞)Q_conduction = kA(T_s - T_∞)/δ
whereh = convection heat transfer coefficientk = thermal conductivity
A = surface areaT_s = surface temperatureT_∞ = surroundings temperatureδ = thickness of insulation As stated, there is no cooling system designed for the compressor;
Learn more about enthalpy:
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