The new standard deviation is 0.9377 (rounded to 4 decimal places).Hence, the mean of the length-of-stay values decreases from 3.5545 to 3.3273 and the standard deviation decreases from 1.7197 to 0.9377.
Q 15 Consider the following sample of 11 length-of-stay values (measured in days): 1.1, 3, 3, 3, 4, 4, 4, 4.5.7 Now suppose that due to new technology you are able to reduce the length of stay at your hospital. A patient who was previously hospitalized for 4.5 days under the old regime can now be hospitalized for only 2.5 days. Explain how this change will affect the mean and the standard deviation of the length-of-stay values.Suppose due to new technology, you are able to reduce the length of stay at your hospital. A patient who was previously hospitalized for 4.5 days can now be hospitalized for only 2.5 days. Let us determine how this change will affect the mean and standard deviation of the length-of-stay values.The original values are: 1.1, 3, 3, 3, 4, 4, 4, 4, 5, 7, 4.5.Mean of the original length of stay
(µ) = (1.1+3+3+3+4+4+4+4+5+7+4.5) / 11 = 39.1/11 = 3.5545 (rounded to 4 decimal places).
Standard Deviation of the original length of stay (σ) = 1.7197(rounded to 4 decimal places).The revised length of stay of the patient is 2.5 days. Therefore, the new length of stay is
(1.1+3+3+3+4+4+4+2.5+5+7)/11 = 36.6/11 = 3.3273 (rounded to 4 decimal places).Mean of the new length of stay (µ) = 3.3273 (rounded to 4 decimal places).
The revised length of stay of the patient is 2.5 days. Therefore, the new standard deviation can be calculated using the formula
σ = √(Σ(xi - µ)²/N), where N = 11, xi = length of stay values,
and
µ = 3.3273.σ = √[((1.1 - 3.3273)² + (3 - 3.3273)² + (3 - 3.3273)² + (3 - 3.3273)² + (4 - 3.3273)² + (4 - 3.3273)² + (4 - 3.3273)² + (2.5 - 3.3273)² + (5 - 3.3273)² + (7 - 3.3273)² + (4.5 - 3.3273)²)/11]σ = √[9.6922/11]σ = √0.8811σ = 0.9377 (rounded to 4 decimal places).
Therefore, the new standard deviation is 0.9377 (rounded to 4 decimal places).Hence, the mean of the length-of-stay values decreases from 3.5545 to 3.3273 and the standard deviation decreases from
1.7197 to 0.9377.
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Someone help please. (The teacher added an extra question for some reason but please help with all.)
The probability of obtaining tails and the number 5 is 1/12
the probability of obtaining an even number is 1/2
P(heads and prime number) 1/4
How to calculate the probabilitySince the events are independent, the probability of obtaining tails and the number 5 is:
P(tails and 5) = P(tails) * P(5) = (1/2) * (1/6) = 1/12
The coin toss outcome is irrelevant, so the probability of obtaining an even number is:
P(even number) = 1/2
The probability of obtaining heads and a prime number is:
P(heads and prime number) = P(heads) * P(prime number) = (1/2) * (1/2) = 1/4
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Pavani collects 20.3 pounds of metal to take to a recycling center. The recycling center pays her for 18.4 pounds of the metal, and refuses the rest of it.
How much of Pavani's collection was refused, in pounds?
1.9 pounds of metal was refused of her collection.
Given that
Pavani collects 20.3 pounds of metal to take to a recycling center. The recycling center pays her for 18.4 pounds of the metal, and refuses the rest of it.To find
How much metal of Pavani's collection was refused, in poundsSo according to the question
We have,
Total collection by her = 20.3 pounds of metalThe recycling center pays her = 18.4 pounds of the metal.For finding the remaining metal of her collection, we have to subtract the metal buy by recycling center from her total collection
So, we can say that
remaining metal = her total collection - he metal buy by recycling center
Now, putting the values from question
remaining metal = 20.3 - 18.4
= 1.9 pounds of metal.
Answer:
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RICH VS. MARCUS
For this simulcam race, Rich is given a 10 yard head start. Write the function rules for
both players, then graph both equations and fill in the approximate table values.
Rich's function R(t) = function rule?
T R(t)
0 10
1 ?
2. ?
3. ?
4. ?
5. ?
Marcus' is M(t) = function rule?
T. R(t)
0. 0
1. ?
2. ?
3. ?
4. ?
5. ?
Answer: N/A
Step-by-step explanation: In a race between Rich and Marcus, Rich is given a 10-yard head start. Assuming that Rich runs at a constant speed and Marcus runs at a faster constant speed, we can write their positions as functions of time:
Rich's position function is R(t) = 10 + r*t, where r is Rich's speed in yards per second.
Marcus's position function is M(t) = m*t, where m is Marcus's speed in yards per second.
We can use these functions to fill in a table of approximate values for the distance each runner travels at different times:
Time (t) Rich's Distance (R(t)) Marcus's Distance (M(t))
0 10 0
1 10 + r m
2 10 + 2r 2m
3 10 + 3r 3m
4 10 + 4r 4m
5 10 + 5r 5m
To graph these functions, we can plot the points from the table and connect them with a straight line. The graph shows the distance each runner travels as a function of time. Note that the value of r is not given in the problem, so we cannot calculate the exact positions of Rich at each time interval.
Karlene has $4.75. Which combination of coins is correct?
Answer:
4 dollars and 3 quarters
Step-by-step explanation:
HELLPPPP WILL GIVE BRAINLY AND 25 more point if CORRECT
If m<9 = 105 and m<11 = 3x and m<3 = x + 85
What value of x makes line a parallel to line b?
Answer:
x = 35.
Step-by-step explanation:
If a is parallel to b then m<9 = m < 11 (corresponding angles),
so 3x = 105
x = 105/3
x = 35.
Which of the following segments is a diameter of O?
Answer:
AB
Step-by-step explanation:
The diameter has to pass through the center of the circle and tough the outside of the circle on both ends
The diameters are
DE and AB
They can also be written as
ED and BA
Answer:
option A : AB
Step-by-step explanation:
The diameter is the length of the line through the center that touches two points on the edge of the circle.
Both AB and DE are diameters.
Therefore, Option A : AB
how????
2 1/3 divided by 1/4
Answer:
9.3
Step-by-step explanation:
what's that 2 i just don't understand that buddy??
Determine the exact value of 1 1/2 - 3/5 over 4 2/5 × 3/4
Answer:
Fraction: 7/9
decimal: 0.778
Step-by-step explanation:
I need help
An airplane flies in the path shown by the vector CD
on the graph below. What is the magnitude and direction of CD
? (1 unit represents 1 mile)
26° north for 7 miles
42° south for 8 miles
53° east of south for 5 miles
72° south of west for 6 miles
Calculating the distance between locations C and D will provide us with the vector CD's magnitude, which we will then use to determine the vector CD's direction and magnitude. Thus, 5 miles in size, with a direction of roughly 53.13 degrees, is the CD.
What is meant by the magnitude and direction of the vector?The size and direction of a vector are two different sorts of information. A vector's length is measured by its magnitude, and its direction indicates its direction of travel. The most popular way to express vector direction is in degrees, though it can be expressed in other ways as well. Vector examples include acceleration and velocity. A vector's length is considered to be its magnitude.
The distance formula between the given two points (x1, y1) and (x2, y2) is:
d = √((x2 - x1)² + (y2 - y1)²)
Plugging in the values for points C and D, we get:
d = √((0 - (-4))² + (1 - 4)²)
= √(16 + 9)
= √(25)
= 5 miles
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Identify each example as a discrete random variable or a continuous random variable. the average annual increase in fuel price a car's speed at different times the number of cars passing through a toll both in an hour the number of phone calls made in a day the salaries of employees in an office
Identification of each example as a discrete random variable or a continuous random variable is shown below.
To identify each example as a discrete random variable or a continuous random variable:
(A) Average price of gas → continuous random variable.
An average can come out to be any number, with a huge string of decimal places. There are no numbers it CAN'T be.(B) Car's speed → continuous random variable.
Between zero and the car's maximum top speed, there are no numbers it CAN'T be.(C) Number of cars → discrete random variable.
It has to be a whole number. There can't be half a car or 0.746 of a car passing through.(D) Number of phone calls → discrete random variable.
It has to be a whole number. There can't be a half of a call or 0.318 of a call made.(E) Salaries → discrete random variable.
The employer can set a person's salary to be anything he wants it to be. If they want it to be a whole number or ANY fraction, they can do it there's no number it CAN'T be. But when it comes time to actually pay him, that has to be a whole number of pennies. There are actually a lot of numbers that they can't pay because they can't give him half of a penny, or 0.617 of a penny.Therefore, the identification of each example as a discrete random variable or a continuous random variable is shown.
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What is the product of 3a + 5 and 2a2 + 4a – 2?
Answer:
9a+5
Step-by-step explanation:
3a+5 and 2a2+4a-2= 6a+3a+5 =9a+5
Determine the average and rms values for the function y(t)=25+10sin6πt over the time periods (a) 0 to 0.1 s, (b) 0.4 to 0.5 s, (c) 0 to 1/3 s, and (d) 0 to 20 s. Comment on the nature and meaning of the results in terms of analysis of dynamic signals.|
Comment: RMS value is equal to the average value. This means that the signal does not have any high-frequency content. It can be inferred that the function y(t) does not oscillate. When the RMS value is less than the average value, it means that the signal has a lesser amount of high-frequency content.
Average and rms values for the function y(t)=25+10sin6πt over the time periods (a) 0 to 0.1 s, (b) 0.4 to 0.5 s, (c) 0 to 1/3 s, and (d) 0 to 20 s are as follows:
a) For t=0 to t=0.1s:
Average value, y_avg = 25
RMS value, y_RMS = 25.1987
Comment: RMS value is greater than the average value. This means that the signal has a considerable amount of high-frequency content. It can be inferred that the function y(t) oscillates rapidly.
b) For t=0.4 to t=0.5s:
Average value, y_avg = 25
RMS value, y_RMS = 28.2843
Comment: RMS value is greater than the average value. This means that the signal has a considerable amount of high-frequency content. It can be inferred that the function y(t) oscillates rapidly.
c) For t=0 to t=1/3 s:
Average value, y_avg = 25
RMS value, y_RMS = 23.7176
Comment: RMS value is less than the average value. This means that the signal has a lesser amount of high-frequency content. It can be inferred that the function y(t) oscillates slowly.
d) For t=0 to t=20 s:
Average value, y_avg = 25
RMS value, y_RMS = 25
Comment: RMS value is equal to the average value. This means that the signal does not have any high-frequency content. It can be inferred that the function y(t) does not oscillate. Comment on the nature and meaning of the results in terms of analysis of dynamic signals.The results indicate that the function y(t) oscillates rapidly at the start and end of the time period and slowly in the middle. When the RMS value is greater than the average value, it means that the signal has a considerable amount of high-frequency content.
On the other hand, when the RMS value is less than the average value, it means that the signal has a lesser amount of high-frequency content.
Furthermore, if the RMS value is equal to the average value, it means that the signal does not have any high-frequency content.
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PLEASE HELP!!!
Assignment name: Trigonometry, Evaluation of Functions
Hi, can someone help find the GRAPHS that belong to these problems, please! I only need a picture of a graph for each problem that I've attached below :)
1. The θ lies in the 2nd quadrant of the graph.
2. The θ lies in the 1st quadrant of the graph.
3. The θ lies in the 3rd quadrant of the graph.
In the first question, Secθ = -13/5 and Tanθ is negative.Secθ is negative in the 2nd and 3rd quadrants.Tanθ is negative in the 2nd and 4th quadrants.Thus, θ lies in the 2nd quadrant of the graph.In the second question, Sinθ = 7/10 and Cotθ is positive.Sinθ is positive in the 1st and 2nd quadrants.Cotθ is positive in the 1st and 3rd quadrants.Thus, θ lies in the 1st quadrant of the graph.In the third question, Tanθ = 3/4 and Sinθ is negative.Tanθ is positive in the 1st and 3rd quadrants.Sinθ is negative in the 3rd and 4th quadrants.Thus, θ lies in the 3rd quadrant of the graph.To learn more about quadrants, visit :
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Please refer to the photo
The table shows the number of gallons of paint Mrs. Brown used to paint the of rooms in her house. Find the slope of the line
Answer:
The slope is \(\frac{3}{2}\) or \(1.5\)
Step-by-step explanation:
The slope formula: \(\frac{y2-y1}{x2-x1}\)
Now, in this case, when you get tables, you could choose two coordinates.
So, for instance, you chose the coordinates: (2,3) and (6,9)
Since we have the two coordinates, we now could solve for the slope.
-
Substituting and finding the slope:
1) \(m =\frac{9-3}{6-2} \\\)
2) \(m = \frac{6}{4} = \frac{3}{2}\)
3) \(m = \frac{3}{2}\) or \(1.5\)
Helppppp with this please
Answer:180
Step-by-step explanation:
hope this helps
Answer:
0.8 mm
Step-by-step explanation:
Given that you require the actual size.
The ant has been magnified by 15 X
To find the actual size divide magnified size by 15
actual size = 12 mm ÷ 15 = 0.8 mm
The loudness L of sound in decibels is given by L=10log(I/I0) where I is the intensity of the sound, and I0 is the intensity of the least audible sound. If I0=10^-12 W/m^2 about how many times more intense is a 97 decibel sound than a 93 decibel sound?
A. 4.5
B. 1.5
C. 2.5
D. 3.5
97 decibel sound is 2.5 times more intense than a 93 decibel sound
Correct option is C.
What is intensity of sound?Sound intensity also known as acoustic intensity, is defined as the power transmitted by a sound wave per unit area in a direction perpendicular to that area. Sound intensity is the sound power in watts divided by the area (in square meters) covered by the sound. Sound loudness relates the intensity of a particular sound to its strength at the threshold of hearing, measured in decibels (dB).
Given expression for loudness
L = 10 log(I/I₀)
Loudness of two different sounds are
L₁ = 97 decibel and L₂ = 93 decibel.
Let the intensity for the loudness L₁ and L₂ are I₁ and I₂
Then,
L₁ = 10log(I₁/I₀) = 97
⇒ log(I₁/I₀) = 9.7
taking antilog
I₁/I₀ = antilog (9.7)
I₁/I₀ = 5011872336.27271
L₂ = 10log(I₂/I₀) = 93
⇒ log(I₂/I₀) = 9.3
taking antilog
I₂/I₀ = antilog (9.3)
I₂/I₀ = 1995262314.96888
Then,
(I₁/I₀)/(I₂/I₀) = 5011872336.27271/1995262314.96888
I₁/I₂ = 2.51188643 ≈ 2.5
Hence, 2.5 times more intense is 97 decibel sound than 93 decibel sound.
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A cruise ship needs to book at least 2,052 passengers to be profitable, but the most passengers the ship can accommodate is 2,462. Model the numbers of passengers that need to be booked to ensure the cruise line makes a profit, using a compound inequality.
The numbers of passengers that need to be booked to ensure the cruise line makes a profit, using a compound inequality is x ≥ 2,052 and x ≤ 2,462.
How to illustrate the inequality?From the information given, we are told that the cruise ship needs to book at least 2,052 passengers to be profitable, but the most passengers the ship can accommodate is 2,462.
Learn x be the number of people that can be accommodated. Therefore, the model is x ≥ 2,052 and x ≤ 2,462.
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a new surgical procedure has promising results to alleviate hip pain, but a portion of patients who receive the procedure report an audible squeaking noise coming from the hip within six months. data from a follow-up study of 143 patients revealed that 10 of them could hear squeaking. if you were to construct a 99% confidence interval around the follow-up study point estimate, what would be e, the margin of error, or half-width of the confidence interval? since the sample size is so large, you can reference the z distribution to determine a critical
The margin of error of the 99% confidence interval is given as follows:
0.0549 = 5.49%.
What is a confidence interval of proportions?A confidence interval of proportions has the bounds given by the rule presented as follows:
\(\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}\)
In which the variables used to calculated these bounds are listed as follows:
\(\pi\) is the sample proportion, which is also the estimate of the parameter.z is the critical value.n is the sample size.The confidence level is of 99%, hence the critical value z is the value of Z that has a p-value of \(\frac{1+0.99}{2} = 0.995\), so the critical value is z = 2.575.
The margin of error is given as follows:
\(M = z\sqrt{\frac{\pi(1-\pi)}{n}}\)
The parameters for this problem are given as follows:
\(n = 143, \pi = \frac{10}{143} = 0.0699\)
Hence the margin of error is of:
M = 2.575 x sqrt(0.0699 x 0.9301/143)
M = 0.0549 = 5.49%.
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Find any domain restrictions on the given rational equation
х/x+4 + 12/x^2 +5x+4 = 8x/5x-15
Select all that apply.
O A. x= -1
B. x = 0
C. x= 3
D. x = -4
Answer:
x ≠ -4, -1, 3
Step-by-step explanation:
\(\frac{x}{x+4}+ \frac{12}{x^2} +5x+4 = \frac{8x}{5x-15}\)
\(12/(x^2+5x+4) = 8x/(5x-15)\)
\(\frac{12}{((x+1)(x+4))} = \frac{8x}{(5(x-3))}\)
\(\\ \tt\hookrightarrow \dfrac{x}{x+4}+\dfrac{12}{x^2+5x+4}=\dfrac{8x}{5x-15}\)
\(\\ \tt\hookrightarrow \dfrac{x}{x+4}+\dfrac{12}{(x+1)(x+4)}=\dfrac{8x}{5(x-3)}\)
For x=-4 First fraction becomes undefinedFor x=-1 second fraction becomes undefinedFor x=3 third fraction also becomes undefinedSo Domain=(-4,-1,3)
I can give you $1 NOW or $1 a month from now, which should you choose? Please explain your answer ?
From a purely financial perspective, receiving $1 now is generally more advantageous due to the time value of money.
The time value of money refers to the idea that money has a greater value in the present than in the future. This is because money can be invested or used to generate additional income over time.
Therefore, from a purely financial standpoint, receiving $1 now is more beneficial because it allows for immediate access to the funds, enabling the possibility of utilizing or investing it right away.
Choosing to receive $1 a month from now may involve an opportunity cost. By waiting, you are forgoing the potential benefits or opportunities that could arise from having the money now. For example, you could invest the $1 and earn interest or use it to cover immediate expenses.
However, personal circumstances and preferences can influence the decision. If there are no pressing financial needs and the individual prefers delayed gratification or has a specific plan for the money in the future, opting to receive $1 a month from now might be a more suitable choice.
In conclusion, from a financial perspective, receiving $1 now is generally advantageous due to the time value of money. However, personal preferences, immediate financial needs, and specific plans can also factor into the decision-making process.
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Suppose the correlation between two variables is r = 0.23. What will the new correlation be if 0.14 is added to all values of the x-variable, every value of the y-variable is doubled, and the two variables are interchanged?
A. 0.23
B. 0.37
C. 0.74
D. -0.23
E. -0.74
Given that the correlation between two variables is r=0.23. We need to find out the new correlation that would exist if the following three changes are made to the existing variables: All values of the x-variable are added by 0.14. All values of the y-variable are doubled Interchanging the two variables. the correct option is B. 0.37.
The effect of changing the variables on the correlation coefficient between the two variables can be determined using the following formula: `r' = (r * s_x * s_y) / s_u where r' is the new correlation coefficient, r is the original correlation coefficient, s_x and s_y are the standard deviations of the two variables, and s_u is the standard deviation of the composite variable obtained by adding the two variables after weighting them by their respective standard deviations.
If we assume that the x-variable is the original variable, then the new values of x and y variables would be as follows:x' = x + 0.14 (since all values of the x-variable are added by 0.14)y' = 2y (since every value of the y-variable is doubled)Now, the two variables are interchanged. So, the new values of x and y variables would be as follows:x" = y'y" = using these values, we can find the new correlation coefficient, r'`r' = (r * s_x * s_y) / s_u.
To find the new value of the standard deviation of the composite variable, s_u, we first need to find the values of s_x and s_y for the original and transformed variables respectively. The standard deviation is given by the formula `s = sqrt(sum((x_i - mu)^2) / (n - 1))where x_i is the ith value of the variable, mu is the mean value of the variable, and n is the total number of values in the variable.
For the original variables, we have:r = 0.23s_x = standard deviation of x variable = s_y = standard deviation of y variable = We do not have any information about the values of x and y variables, so we cannot calculate their standard deviations. For the transformed variables, we have:x' = x + 0.14y' = 2ys_x' = sqrt(sum((x_i' - mu_x')^2) / (n - 1)) = s_x = standard deviation of transformed x variable` = sqrt(sum(((x_i + 0.14) - mu_x')^2) / (n - 1)) = s_x'y' = 2ys_y' = sqrt(sum((y_i' - mu_y')^2) / (n - 1)) = 2s_y = standard deviation of transformed y variable` = sqrt(sum((2y_i - mu_y')^2) / (n - 1)) = 2s_yNow, we can substitute all the values in the formula for the new correlation coefficient and simplify:
r' = (r * s_x * s_y) / s_ur' = (0.23 * s_x' * s_y') / sqrt(s_x'^2 + s_y'^2)r' = (0.23 * s_x * 2s_y) / sqrt((s_x^2 + 2 * 0.14 * s_x + 0.14^2) + (4 * s_y^2))r' = (0.46 * s_x * s_y) / sqrt(s_x^2 + 0.0396 + 4 * s_y^2)Now, we can substitute the value of s_x = s_y = in the above formula:r' = (0.46 * * ) / sqrt( + 0.0396 + 4 * )r' = (0.46 * ) / sqrt( + 0.1584 + )r' = (0.46 * ) / sqrt(r' = (0.46 * ) / sqrt(r' = (0.46 * ) / sqrt(r' = r' = Therefore, the new correlation coefficient, r', would be approximately equal to.
Hence, the correct option is B. 0.37.
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Today Nia completed her sixth hour of training which represents her sixth hour of training, which represents 7.5% of the total number of hours in the training. How many hours will Nia spend in training in all?
The times spent in training is an illustration of proportions
The times spent in training is 80 hours
The given parameters are:
Time spent = 6 hours
Time spent as a percentage = 7.5%
Let the total time spent in training be x.
The scenario is represented by the following equation
Time spent = Time spent as a percentage * Total Time
So, we have:
6 = 7.5% * x
Express percentage as decimal
6 = 0.075 * x
Divide both sides by 0.075
80 = x
Rewrite as:
x = 80
Hence, the times spent in training is 80 hours
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let x(t) = cos(75t). if we sample x(t) at the nyquist frequency, what is the resulting discrete frequency
If we sample the function x(t) = cos(75t) at the Nyquist frequency, the resulting discrete frequency would be half of the Nyquist frequency, which is equal to half of the highest frequency component in the continuous signal.
In this case, the highest frequency component in x(t) is 75 Hz, as determined by the coefficient of t in the cosine function. According to the Nyquist-Shannon sampling theorem, to accurately represent a signal, the sampling frequency must be at least twice the highest frequency component. Therefore, the Nyquist frequency in this scenario would be 2 * 75 Hz = 150 Hz.
Since we are sampling at the Nyquist frequency, the resulting discrete frequency would be half of the Nyquist frequency, which is 150 Hz / 2 = 75 Hz. Hence, when sampling x(t) at the Nyquist frequency, the resulting discrete frequency would be 75 Hz.
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What is one way the Federal Reserve can reduce the amount of money available in the economy?
A. Raising the discount rate
B. Selling treasury securities
C. Buying treasury securities
D. Lowering the interest on reserves
Answer:
B. Selling treasury securities
Step-by-step explanation:
I'm taking the quiz
The Federal Reserve can reduce the amount of money available in the economy is buying treasury securities.
What is a federal reserve?The Federal Reserve can decrease the money supply by increasing the discount rate. a. Raising the discount rate provides depository institutions a minor incentive to borrow, thereby decreasing their reserves and lending activity. The U.S. government created the Federal Reserve, the nation's central bank, to control the money supply and contain economic calamities.One of the primary objectives of the Federal Reserve exists to function as the lender of last resort, permitting banks to borrow from the central bank when needed.The Fed operates three immediate tools in handling the money supply and observing stable economic growth. The tools exist (1) reserve needs, (2) the discount rate, and (3) open market operations.Each of these controls the money supply in different forms and can be utilized to obtain or develop the economy.The Federal Reserve can decrease the amount of money general in the economy stands buying treasury securities.Therefore, the correct answer exists as option B. Selling treasury securities.
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can someone help me with the working out please its due Tomorrow
No links please
1.) 9(p+q) + 3(p+q)
2.) 7p-q) + 4(p-q)
3.) 6(p+ q) - 4(p-q)
4.) 8(7x + 3y) + 4(5x + 2y)
5.) 9(5x + 3y) - 5(4x + 7y)
6.) 9(7x + 4y) - 8(3x + 7y)
A binomial experiment has 4 trials in which p=0. 35. What is the probability of 1 success?.
Answer: 5798
Step-by-step explanation:
Probability of \(1\) success as per given condition is equals to \(0.384475\) ≈ \(0.4\).
What is probability?" Probability is defined as the ratio of number of favourable outcomes to the total number of outcomes.Probability is always less than or equals to one."
Formula used
For binomial experiment
Probability = \(^n C_r p^{r} q^{n-r}\)
\(p =\)success rate
\(q=\) failure rate
\(p+q=1\)
\(n=\)Number of trials
\(r=\) number of success
According to the question,
Total number of trials \('n' =4\)
Number of success \('r' =1\)
\(p = 0.35\\\\q = 1-0.35\\ \\\implies q = 0.65\)
Substitute the value to get the required probability,
Probability \(= ^4C_1 (0.35)^{1}(0.65)^{4-1}\)
\(=\frac{4!}{(4-1)!1!} \times\frac{35}{100}\times(\frac{65}{100})^{3} \\\\= 4 \times \frac{35}{100}\times \frac{274625}{1000000} \\\\= 0.384475\)
≈ \(0.4\)
Hence, probability of \(1\) success as per given condition is equals to \(0.384475\) ≈ \(0.4\).
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Solution: The set of all elements in the universal set that is not in set A is called the complement of set A.
The complement of set A, denoted by ​ A`, is the collection of all elements that belong to the universal set but are not part of set A. It's not necessary to mention the universe (also known as U) if it's understood which set of elements is being referred to.
The complement of a set A is the collection of all elements that belong to the universal set but not to set A. It is denoted as ​ A` and does not include any elements that are already in set A. The universal set, also known as U, contains all possible elements and is assumed to be known. Therefore, when referring to the complement of a set, it is not necessary to mention the universal set explicitly. The complement of a set is useful in determining the set of elements that are not part of a particular set, and it can be used in various mathematical operations.
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2 3 4 6. Given matrix A = 4 3 1 1 2 4 (a) Calculate the determinant of A.
(b) Calculate the inverse of A by using the formula involving the adjoint of A.
(a) The determinant of matrix A is 5.
(b) The inverse of matrix A using the adjoint formula is [2/5 -3/5; -1/5 4/5].
How to calculate the determinant of matrix A?(a) To calculate the determinant of matrix A, denoted as |A| or det(A), we can use the formula for a 2x2 matrix:
det(A) = (a*d) - (b*c)
For matrix A = [4 3; 1 2], we have:
det(A) = (4*2) - (3*1)
= 8 - 3
= 5
Therefore, the determinant of matrix A is 5.
How to calculate the inverse of matrix A using the formula involving the adjoint of A?(b) To calculate the inverse of matrix A using the formula involving the adjoint of A, we follow these steps:
Calculate the determinant of A, which we found to be 5.
Find the adjoint of A, denoted as adj(A), by swapping the elements along the main diagonal and changing the sign of the off-diagonal elements. For matrix A, the adjoint is:
adj(A) = [2 -3; -1 4]
Calculate the inverse of A, denoted as A^(-1), using the formula:
\(A^{(-1)}\) = (1/det(A)) * adj(A)
Plugging in the values, we have:
\(A^{(-1)}\) = (1/5) * [2 -3; -1 4]
= [2/5 -3/5; -1/5 4/5]
Therefore, the inverse of matrix A is:
\(A^{(-1)}\)= [2/5 -3/5; -1/5 4/5]
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Oliver spot frustrated sometimes with his somewhat limited set of red We, and green building bricks. Part way through project, he often machines that transform brick of one colour into a combination of cut of bricks of one particular colour. So he invented some 3D printing bricks of one or more colours, Ench machine can also operate in re The red machine (R) converts I red brick (r) into I blue brick (b) 1 groet brick (g). This process and its reverse are represented by R-1 R bg and be Similarly, for the blue machine (B) we have B B- b Tg and Tg +b. And for the green machine (G) we have G-1 g rb and rb The machines can be used on collections of bricks, performing one con version at a time. For example, 3 blue bricks can be converted into 1 red and 3 green bricks in three steps, as follows: B B G- bbb rgbbrgrgb rggg Note that the order of the bricks in each collection is irrelevant. a Show how Oliver can convert 1 red brick into 3 red bricks. b Show how Oliver can convert 1 red brick into 5 red bricks in six steps. c Explain why Oliver cannot convert 1 red brick into 5 red bricks in less than six steps. d Oliver starts with a collection of bricks in which the combined number of blue and green bricks is odd. Explain why he cannot end up with a combined number of blue and green bricks that is even
Answer: That is the answer for the first one and ill let you know if i work out more.
Step-by-step explanation: