Put the events listed below in the correct order:
1. Complementary nucleotides pair up with the free half
of DNA, making two new strands.
II. The new strands twist back into a twisted helix shape.
III. DNA is unzipped.
IV. DNA polymerase starts bringing DNA nucleotides to
the unzipped halves.

Put The Events Listed Below In The Correct Order:1. Complementary Nucleotides Pair Up With The Free Halfof

Answers

Answer 1
The correct order is most likely 3, 4, 1, 2.

Related Questions

1. An is a circulation of a
convection cycle of air.

Answers

Answer:

True

Explanation:

how replacing fossil fuels with biofuels will affect climate change

Answers

Answer: Replacing fossil fuels with biofuels has the potential to reduce some undesirable aspects of fossil fuel production and use.

Explain:

Fuels produced from renewable organic material possibly have the potential to reduce some undesirable aspects of fossil fuel production and use, including conventional and greenhouse gas (GHG) pollutant emissions, exhaustible resource depletion, and dependence on unstable foreign suppliers also. -i hope this helped :)

Use the image on the right to match the following phrases to the correct level of organizational hierarchy.

Answers

Answer:

There is no image Could you please put the image

Explanation:

Thank You

Question 28
Use specific examples to compare and contrast the flow of energy and nutrients.

Answers

Answer:

nn  n

Explanation:

Which of the following is NOT way in which the cell's surface membrane interacts with the exterior environment? The cellular surface mediates attachments other cclls The " cellular surface mediates interactions with extracellular matcrial. The cellular surfacc organizes the interior organclle organization ofthc ccll; The cellular surface controls which substances enter and leavc thc cell; Thc cellular surface rcccivcs Jnd transmits incoming massage

Answers

'The cellular surface organizes the interior organelle organization of the cell'.

What do you mean by organelle?

Organelles are specialized compartments within a cell that perform specific functions. They are like the organs of a human body, performing a specific task within the cell. Examples of organelles include the nucleus, mitochondria, chloroplasts, endoplasmic reticulum, Golgi complex, lysosomes, and peroxisomes.

The cellular surface, or plasma membrane, acts as a barrier between the cytoplasm and the external environment. It also provides structure and organization to the interior of the cell by controlling the movement of molecules, ions, and other particles that enter and exit the cell. The membrane also contains various proteins and lipids that serve as receptors and are involved in signaling pathways that regulate cellular processes. By organizing the interior of the cell, the cellular surface helps to direct the activities of the organelles and ensure that they are located in the right places to function properly.

Hence, option C is correct.

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How many dominant and recessive traits will be produced in the progeny of F2?

Answers

In in the progeny of F2, the genotypic ratio of dominant and recessive traits will be produced is 3:1.

Mendel frequently noted a phenotype ratio of three plants with the dominant phenotype to one plant with the recessive phenotype in the F2 generation, the offspring of monohybrid crossings.

The genotype of the F2 progeny in a monohybrid cross might take on homozygous dominant, heterozygous, or homozygous recessive forms.

Mendel performed a number of crosses on the garden pea plant to gain insight into the inheritance pattern of characteristics. A monohybrid cross, which shows the pattern of inheritance of a single gene with two alleles, controlling a single character with two attributes, is one of these hybrids.

A monohybrid cross examines just one character. Consider the pea plant's height as an example. Tall and dwarf are the two characteristics of height that are displayed. The height-regulating gene is shown as T/t. The mutation "T" causes plants to be tall, whereas the allele "T" causes them to be dwarf.

Purebred or homozygous parents are chosen for the cross depending on the desired features. This indicates that the genotype of the tall parent plant will have both of the T and TT alleles. The genotype of the dwarf parent plant will contain both 't' alleles as 'tt'.

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Guiding Question:

Would this DNA strand function in a living organism? Explain with a CER format.

Legends:

S-Deoxyribose

A, G, C, T-Nitrogen bases

P-Phosphate group

Guiding Question: Would this DNA strand function in a living organism? Explain with a CER format.Legends:S-DeoxyriboseA,

Answers

This DNA strand won't function in a living organism because of the incorrect matching of the base pairs which will distort the structure of  the molecule.

What is DNA?

This is referred to as deoxyribonucleic acid and it is the genetic material of most living organisms.

Claim - A-G , C-T were paired in the example given.

Evidence - Under normal circumstances, the nitrogen-containing bases adenine (A) and thymine (T) pair together, and cytosine (C) and guanine (G) pair together.

Reasoning - Since the base pairs aren't correctly matched then there will be a distort the structure of  the molecule which could cause genetic diseases.

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Respiration can be categorized as either active respiration or passive respiration. True False

Answers

True, respiration can be classified as active and passive

What is active respiration?


Forced breathing is an active mode of breathing which utilises additional muscles to rapidly expand and contract the thoracic cavity volume. It most commonly occurs during exercise.

What is passive expiration?

The process of normal expiration is passive, meaning that energy is not required to push air out of the lungs. Instead, the elasticity of the lung tissue causes the lung to recoil, as the diaphragm and intercostal muscles relax following inspiration.

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How do plants use flowers

Answers

Answer:

I don't know the answer, but it won't let me delete my previous answer.

Explanation:

​Which of the following structures are found in eukaryotes, but not prokaryotes?

Choose 1 answer:

(Choice A) Golgi body

(Choice B) Cytosol

(Choice C) Cilia

(Choice D) Cell membrane

Answers

i’m pretty sure the answer is A

The structures that are found in eukaryotes, but not prokaryotes are:

Golgi bodyCilia. Both prokaryotic and eukaryotic cells contain cytosol and cell membrane structures.

The Golgi apparatus is known as a cellular organelle whose function is to handle the proteins synthesized by the endoplasmic reticulum.

It is found in eukaryotic cells and is responsible for completing the production process of certain proteins.

Cilia are a series of short and numerous mobile extensions of the plasma membrane that line the cell surface of some eukaryotic cells.

Prokaryotic cells form living unicellular organisms, they present their genetic material dispersed in the cytoplasm, because they lack a cell nucleus.

Its cell membrane is responsible for delimiting the organism, which also lacks any type of organelle or cell divisions.

Therefore, we can conclude that the structures that are found in eukaryotes, but not prokaryotes are: Golgi body and Cilia and both prokaryotic and eukaryotic cells contain cytosol and cell membrane structures ..

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____ is the type of inhibition of a metabolic pathway when the final product in an enzyme cascade inhibits the first enzyme in the pathway.

Answers

competitive inhibition

Hurry answer!

All the questions are in the green box

Hurry answer! All the questions are in the green box
Hurry answer! All the questions are in the green box
Hurry answer! All the questions are in the green box

Answers

Answer:I’m pretty sure the first one that they will overcome by camouflage against the color

Explanation:I don’t know the rest

blood pumped from the right side of the heart goes to the _____ via _____.

Answers

The lungs receive blood that the right side of the heart pumps through arteries.

The right side of the heart pumps blood; where does it go?

The lungs are where the blood is oxygenated after being pumped by the right ventricle. Pneumatic veins that enter the left atrium carry oxygenated blood back to the heart. The left ventricle receives blood from the left atrium.

The right side of the heart pumps blood to where?

Blood is pumped by the right side of the heart through the pulmonary circulation, which carries it to the lungs. There, CO2 and O2 are diffused from the lungs into the blood, respectively.

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climate change storys​

Answers

We pollute the environment with greenhouse gasses to the earth's climate is getting warmer

which of the following effectors acts as as feedforward stimulation to the pathway it is produced in when it is in excess?

Answers

The effector that acts as a feedforward stimulation to the pathway it is produced in when it is in excess is the Inhibitory effector.

A feedforward mechanism is a way of regulating a system's output by anticipating disturbances that have not yet occurred. It is a predictive system that functions by taking an action in anticipation of a disturbance or signal, resulting in a pre-emptive response. Feedforward controls are found in a variety of physiological and biochemical systems. They are capable of controlling the sensitivity of a system to stimulation. The inhibitory effector is an effector that serves as a feedforward stimulation to the pathway it is produced in when it is in excess. In a system, it inhibits the rate of the formation of the product of the pathway that produced it. How does an inhibitory effector work? When the concentration of the inhibitory effector in the system is excessive, it activates an inhibitory signal, which results in a decrease in the rate of product formation from the pathway. The inhibitory effector may act to prevent the product from being generated if it becomes too abundant or if it may have a negative impact on the system.

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In the past, some scientists accepted the theory of spontaneous generation. This theory states that organisms can arise from nonliving matter Now scientists generally accept cell theory to explain the origin and growth of


new organisms. Which of these statements is a key idea of cell theory and a rejection of spontaneous generation?

Answers

The key idea of cell theory and a rejection of spontaneous generation is that cells arise only from other cells through the process of cell division.

This implies that new organisms are formed from pre-existing cells that have gone through the cell cycle and the process of mitosis.Cell theory is a fundamental concept of biology that explains the origin and growth of new organisms. This theory states that cells are the basic unit of life and that all living organisms are made up of cells. It was first proposed in the mid-19th century by Matthias Schleiden and Theodor Schwann, and later expanded upon by Rudolf Virchow, who proposed the principle of biogenesis.

Cell theory also states that cells are the basic structural and functional unit of life and that all cells come from pre-existing cells. This means that new cells are formed from the division of existing cells through the process of mitosis. This principle is a key idea of cell theory and a rejection of the theory of spontaneous generation, which proposed that organisms could arise from nonliving matter. The principle of biogenesis, which is a key component of cell theory, states that all living things come from other living things, and this is a fundamental rejection of the theory of spontaneous generation.

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which of the following is the correct order of enzyme according to their action in glycolysis? question 1 options: hexokinase, glucose-6-phosphate isomerase, phosphofructokinase, aldolase, triose phosphate isomerase, glyceraldehyde-3-phophae dehydrogenase, phosphoglycerate kinase, phosphogkycerate mutase, enolase, pyruvate kinase none of the above hexokinase, glucose-6-phosphate isomerase, phosphofructokinase, aldolase, enolase, glyceraldehyde-3-phophae dehydrogenase, phosphoglycerate kinase, phosphogkycerate mutase, triose phosphate isomerase, pyruvate kinase phosphofructokinase, glucose-6-phosphate isomerase, hexokinase, aldolase, triose phosphate isomerase, glyceraldehyde-3-phophae dehydrogenase, phosphoglycerate kinase, phosphogkycerate mutase, enolase, pyruvate kinase hexokinase, triose phosphate isomerase, phosphofructokinase, aldolase, glucose-6-phosphate isomerase, glyceraldehyde-3-phophae dehydrogenase, phosphoglycerate kinase, phosphogkycerate mutase, enolase, pyruvate kinase

Answers

The correct order of enzymes according to their action in glycolysis is given below.

Hexokinase, glucose-6-phosphate isomerase, phosphofructokinase, aldolase, triose phosphate isomerase, glyceraldehyde-3-phosphate dehydrogenase, phosphoglycerate kinase, phosphoglycerate mutase, enolase, and pyruvate kinase. Hexokinase is the enzyme responsible for catalyzing the first step of glycolysis, where glucose is converted into glucose-6-phosphate which is the enzyme that catalyzes the conversion of glucose-6-phosphate into fructose-6-phosphate. Phosphofructokinase is the enzyme that catalyzes the conversion of fructose-6-phosphate into fructose 1, 6-bisphosphate. Aldolase is the enzyme that catalyzes the breaking down of fructose 1, 6-bisphosphate into two molecules of glyceraldehyde 3-phosphate.

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Summary of human nutrition ​

Answers

Answer:

Human nutrition is the process of which substances are Transformed into tissues and energy which are used up to mental and physical activities!

In eukaryotes energy is needed to carry out most of its processes, what is the primary energy source of the cell?
A. ADP
B. Nitrogen
C. ATP
D. C02

Answers

The answer is C. Have a good day!

Which of the following is
an example of a null
hypothesis?
A. Changing the amount of light that a
plant gets has no effect on how tall it
grows.
B. Taking aspirin every day will lower
your chances of having a heart attack.
C. Spending more time studying for a
test will increase your test score.

Answers

Answer:

Which of the following is

an example of a null

hypothesis?

C. Spending more time studying for a

test will increase your test score.

xXxAnimexXx

Happy Labor day!

Candace is wanting to be sure that she is doing what she can to prevent the spread of disease. Which of the following should she sure to do?

Answers

Answer:  She should Avoid Contact with other people's bodily fluids.

Explanation: Hope that helps! (:

Answer:

She should avoid contact with other peoples bodily fluids

Explanation:

I just did the lesson and this is the correct answer.

which statement about n-linked glycosylation is correct (in eukaryotes)? a. n-linked sugars are attached to proteins as a 14 residue oligosaccharide during translation in the endoplasmic reticulum. b. n-linked sugars are attached to proteins as a 14 residue oligosaccharide during translation in the cytoplasm. c. n-linked sugars are attached to proteins as a 14 residue oligosaccharide after translation in the golgi apparatus. d. n-linked oligosaccharides are attached to proteins one sugar at the time in the golgi apparatus.

Answers

The correct statement about n-linked glycosylation in eukaryotes is c. N-linked sugars are attached to proteins as a 14 residue oligosaccharide after translation in the golgi apparatus.

N-linked glycosylation is a process that involves the addition of a sugar molecule, specifically an oligosaccharide, to a protein. This process occurs in eukaryotic cells and is one of the most common post-translational modifications that occur in proteins.

The process of N-linked glycosylation begins with the synthesis of the oligosaccharide chain in the endoplasmic reticulum (ER). This chain is then transferred to a specific amino acid residue (asparagine) on the protein in a process known as "en bloc" transfer. The protein is then transported to the Golgi apparatus where it undergoes further processing and modifications.

Once the protein reaches the Golgi apparatus, the oligosaccharide chain is further modified. It is trimmed down to its final size of 14 residues and then attached to the protein. This process is called "maturation" of the oligosaccharide chain. The final product is a protein with a fully matured, 14 residue oligosaccharide chain attached to it.

Therefore, the correct statement about N-linked glycosylation in eukaryotes is c. N-linked sugars are attached to proteins as a 14 residue oligosaccharide after translation in the Golgi apparatus. Option a is incorrect because the 14 residue oligosaccharide is synthesized in the ER but attached to the protein in the Golgi. Option b is incorrect because the process of N-linked glycosylation occurs in the ER and Golgi, but not in the cytoplasm. Option d is incorrect because the oligosaccharide is not attached to the protein one sugar at a time, but rather as a fully matured, 14 residue chain.


The correct statement about N-linked glycosylation in eukaryotes is: a. N-linked sugars are attached to proteins as a 14 residue oligosaccharide during translation in the endoplasmic reticulum.

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A substance secreted by the vascular endothelial cells that can help to initiate fibrinolysis is:_________

Answers

A substance secreted by the vascular endothelial cells that can help to initiate fibrinolysis is the Tissue plasminogen activator.

Tissue plasminogen activator (tPA), also called alteplase which is a medication made of a protein that can dissolve blood clots. Human tPA is a glycoprotein produced mainly by vascular endothelial cells. It is a thrombolytic agent that will break down blood clots to restore blood flow to the ischemic region of the human brain, and it is the only FDA-approved medication available to treat ischemic stroke.

Fibrinolysis is a normal human body process. It prevents human blood clots, which occur naturally, from the growing and causing problems. A Primary fibrinolysis refers to the normal breakdown of clots.

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What process in the nitrogen cycle converts nitrogen back into its gaseous state?.

Answers

Denitrification is the process in the nitrogen cycle that converts nitrogen back into its gaseous state.

In the nitrogen cycle, a biogeochemical process, nitrogen passes through many phases, interacts with both living and nonliving things, and is transformed into a variety of forms. Although abundant in nature, plants can only utilize nitrogen when it has been transformed from dinitrogen gas to ammonia (leguminous).

Fixation of Nitrogen (Fix the nitrogen with nitrogen-fixing organisms such as rhizobium)

Nitrification (conversion of ammonia to nitrite and nitrite to nitrate) (conversion of ammonia to nitrite and nitrite to nitrate)

Anammox (Anaerobic ammonia oxidation) (Anaerobic ammonia oxidation)

Denitrification is the process of extracting bioavailable nitrogen from the atmosphere and reintroducing it along with inert nitrogen. It is an anaerobic procedure that is crucial in the removal of nitrate. Dinitrogen gas is released as a result of this reaction (gaseous state).

Ammonification (release of inorganic nitrogen back into the biosphere as ammonia) (release of inorganic nitrogen back into the ecosystem as ammonia)

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What is the world's largest surface current?
O The Gulf Stream
O The Humbolt Current
O The EAC (Eastern Australian Current)
o the Coriolis Effect

Answers

Answer:

The Golf Stream

Explanation:

The largest and most powerful surface current in the North Atlantic Ocean is called the Gulf Stream. It moves northward along the east coast of the United States.

Answer:

B.The Humbolt Current

Explanation:

I hope this helps

which statement best describes a common feature of sertoli and granulosa cells?

Answers

A common feature of Sertoli and granulosa cells is their role in supporting and nurturing developing germ cells.

Sertoli cells and granulosa cells are both types of somatic cells found in the reproductive organs of males and females, respectively. While they have distinct locations and functions, they share a common feature in their support and nurturing of developing germ cells.

Sertoli cells are found in the seminiferous tubules of the testes, where they provide physical and nutritional support to developing sperm cells. They create a microenvironment known as the blood-testis barrier, which isolates the developing germ cells from the bloodstream and provides them with necessary nutrients and hormones.

On the other hand, granulosa cells are found in the ovarian follicles of the ovaries. They surround and support the developing oocytes (immature eggs) during folliculogenesis. Granulosa cells play a vital role in the growth and maturation of the oocyte, providing it with essential nutrients and hormonal signals.

Both Sertoli and granulosa cells contribute to the proper development and maturation of germ cells in their respective reproductive systems. Their supportive functions ensure the survival and successful progression of germ cells towards becoming mature sperm or eggs, enabling the reproductive processes in males and females.

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An environment where water flows into a cell and causes it to burst is
A. hypertonic
B. hypotonic
C. isotonic
D. in equilibrium

Answers

The answer is a hypotonic solution

ATP is
Multiple Choice
formed during the hydrolysis of ADP.
used by cells for the storage of energy.
used to transfer energy within a cell.
a protein a molecule with less total energy content than ADP.

Answers

ATP (adenosine triphosphate) is a molecule used by cells to transfer energy within a cell.

ATP is a nucleotide that plays a fundamental role in cellular energy metabolism. It acts as an energy currency within cells, providing the necessary energy for various cellular processes. The given options can be evaluated as follows:

- ATP is formed during the hydrolysis of ADP (adenosine diphosphate). This statement is incorrect since hydrolysis of ATP releases energy and converts it into ADP, not the other way around.

- ATP is used by cells for the storage of energy. This statement is incorrect as ATP is not primarily used for energy storage. Instead, it is involved in the transfer and utilization of energy in cells.

- ATP is used to transfer energy within a cell. This statement is correct. ATP transfers energy through the hydrolysis of its high-energy phosphate bonds. When ATP is hydrolyzed into ADP and inorganic phosphate (Pi), energy is released and can be used for various cellular processes, such as muscle contraction, active transport, and synthesis of macromolecules.

- ATP is not a protein. ATP is a nucleotide, not a protein molecule.

- ATP has more total energy content than ADP. This statement is incorrect. ADP has less energy content than ATP since it lacks one phosphate group.

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This answer is B right? :)

This answer is B right? :)

Answers

Answer:

Yes it's B.

Explanation:

Because we may discover more evidence.

Answer:

yes, you are correct

Explanation:

Help me pleaseeee!!???

Help me pleaseeee!!???

Answers

Answer:

it A

Explanation:

pick A hopefully it right

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Sheena can row a boat at 2.30 mi/h in still water. She needs to cross a river that is 1.20 mi wide with a current flowing at 1.90 mi/h. Not having her calculator ready, she guesses that to go straight across, she should head upstream at an angle of 25.0 from the direction straight across the river.How long does it take to cross the river in minutes?How far upstream or downstream from her starting point will she reach the opposite bank? If upstream, enter a positive value and if downstream, enter a negative value in miles. In order to go straight across, what angle upstream should she have headed? Solve the below homogeneous differential equation:Letu = y / xy' = u + x u'u = du / dxThe solution of the differential equation:(x sec (y/x) -y) dx + xdy = 0, A slab of clay with a mass of 0.16 kg and velocity of 5 m/s hits a stationary toy car of mass 0.51 kg. If the clay hits and sticks to the car, what is the velocity of the clay and car after impact? 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