Programmable Array Logic (PAL) has a programmable AND array and a fixed OR array.
Programmable Array Logic (PAL) is a logic device.
It is used to implement a logical function.It is an easy to use device because only AND gates are programmable, but it has a limited programming for AND gate.A PAL consists of a small programmable read-only memory (PROM) and additional output logic used to implement the specific logic function required with limited components.In PAL, a programmable AND gate is followed by a fixed OR gate.A typical PAL IC may have eight inputs, eight outputs, and eight sections, each consisting of eight wide AND-OR arrays.Hence PAL has programmable AND array and a fixed OR array.
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In a 'keep-fit' exercise, a student of mass 45 kg steps 40 times on and off a box of height 0.50 m. How much work does the student do to raise her body each time she steps on the box
Answer:Calculate the work done using:
work done (in joules) = force (in newtons) x distance moved (in metres)
To practice calculations involving force, distance and work done.
Explanation: I hope this helps srry if I'm wrong
What are the standard international (si) units of distance
Answer:
meter
Explanation:
Answer: The International System of Units is a system of measurement based on 7 base units
Explanation: the metre, kilogram, second, ampere, Kelvin, mole, and candela. These base units can be used in combination with each other.
PLEASE HELP IF U CAN
Answer:
what is the help you can tell
Monochromatic light with wavelength 633 nn passes through a narrow slit and a patternappears on a screen 6.0 m away. The distance on the screen between the centers of thefirst minima on either side of the screen is 32 mm. How wide (in mm) is the slit
Answer:
Explanation:
screen distance D = 6 m .
wavelength of light λ = 633 nm.
slit width = d .
Distance between first minima on either side is width of central maxima
= 2 x λD /d
Given
32 x 10⁻³ = 2 x λD /d
d = 2 x λD /32 x 10⁻³
= 2 x 633 x 10⁻⁹ x 6 / 32 x 10⁻³
= 237.37 x 10⁻⁶ m
= .23737 x 10⁻³ m
= .24 mm .
How is the vector arrow representing an acceleration of magnitude 3 m/s2 different from the vector arrow representing a negative acceleration of magnitude 3 m/s2?
Question 11 options:
They point in opposite directions.
They are perpendicular, forming a 270° angle between each other.
They are perpendicular, forming a 90° angle between each other.
They point in the same direction.
The vector arrow representing an acceleration of magnitude 3 m/s² and different from vector arrow representing a negative acceleration of magnitude 3 m/s² so they are perpendicular forming a 90-degree angle between each other. Hence, option C is correct.
What is a Vector?A vector has both magnitude and direction. It is frequently depicted as an arrow with a length proportionate to the magnitude and a direction matching the magnitude of the quantity. A vector lacks position, but possesses magnitude and direction. In other words, if a vector is shifted parallel to itself, its shape remains unchanged as long as its length remains constant.
According to the question,
The acceleration of magnitude 3 m/s² and different form the vector arrow representing a negative acceleration of magnitude 3 m/s².
Hence, they are perpendicular, forming a 90-degree angle between each other.
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A boy pushes a 74kg desk across the floor using a force of 270N. The horizontal floor has a coefficient of friction of 0.36. What is the Net force on the desk? What is the acceleration of desk?
Given data:
* The mass of the desk is m = 74 kg.
* The force applied on the desk is F = 270 N.
* The coefficient of friction between the desk and horizontal floor is,
\(\mu=0.36\text{ }\)Solution:
The diagrammatic representation of the given system is,
The normal force acting on the desk is,
\(N=mg\)where g is the acceleration due to gravity,
Substituting the known values,
\(\begin{gathered} N=74\times9.8 \\ N=725.2\text{ Newton} \end{gathered}\)The frictional force acting on the desk is,
\(\begin{gathered} F_r=\mu N \\ F_r=0.36\times725.2 \\ F_r=261.07\text{ N} \end{gathered}\)The net force acting on the desk is,
\(\begin{gathered} F_{net}=F-F_r \\ F_{\text{net}}=270-261.07 \\ F_{\text{net}}=8.93\text{ N} \end{gathered}\)Thus, the net force acting on the desk is 8.9 N or approximately 9 N.
According to Newton's second law, the acceleration of the desk is,
\(F_{net}=ma\)where a is the acceleration of the desk,
Substituting the known values,
\(\begin{gathered} 8.93=74\times a \\ a=\frac{8.93}{74} \\ a=0.12ms^{-2} \end{gathered}\)Thus, the acceleration of the desk is 0.12 meters per second squared.
A teacher places a warm bottles in a cooler filled with ice. Which statement best explains what happened over time?
A) Thermal energy will move from ice to water bottles
B) Coldness will move from the water bottles to the ice.
C) Coldness will move from the ice to the water bottlers
D) Thermal energy will move from the water bottle to the ice.
Answer:
D) Thermal energy will move from the water bottle to the ice.
Explanation:
Overtime, what happens is that thermal energy will move from the water bottle to the ice.
The water bottle is at a higher temperature compared to the ice. So, thermal energy will move from a place at higher temperature to one with lower temperature.
Thermal energy will stop moving until thermal equilibrium is attained. The water bottle will lose heat to the ice and by so doing it becomes colder. The ice will gain heat and begins to warm upName another way that energy is made
Answer:
The three major categories of energy for electricity generation are fossil fuels (coal, natural gas, and petroleum), nuclear energy, and renewable energy sources. Most electricity is generated with steam turbines using fossil fuels, nuclear, biomass, geothermal, and solar thermal energy.
Explanation:
Solar
Wind
Geothermal
Hydrogen
TidaWave
Hydroelectric
Biomass
hi
How is the mass of a solid measured?
is it By estimating
or
With a beaker
or
With a ruler
or
With a scale?
need ansewer asap!!
Answer:
Scale
Explanation:
this is because mass of a solid is measured with a balance
The substance that is formed in a chemical reaction is called the
Answer:
The substance formed is the product. A chemical reaction is the process in which atoms present in the starting substances rearrange to give new chemical combinations present in the substances formed by the reaction. These starting substances of a chemical reaction are called the reactants, and the new substances that result are called the products.
Answer:
product
Explanation:
educere
There are about 4.7 billion tons of salt in the Great Salt Lake which results in extremely dense water. One weekend, a group of swimmers take a dive into this lake. True or False: As they begin to move around, they find it incredibly easy to stay afloat.
A. True
B. False
Answer:
A. True
Explanation:
Given that there is approx 4.7 billion salt tons in the Great Salt Lake due to which it extremely dense the water.
So if a group of swimmers dives in that so it would be easy to stay afloat as we know that the salt density is greater or more than as if we compared to the water that results into upward buoyant force is large
Therefore as per the situation, the given statement is true
g What is the CD's moment of inertia for rotation about a perpendicular axis through the edge of the disk
Answer:
Explanation:
A CD has an OD of 120 mm and an ID of 15 mm and has a mass between 14 and 33 grams. Let's call it m
Lets call the outer and inner radii R and r respectively
Find the moment of inertia about a line perpendicular to the surface of the disc through its center. We can integrate or look up the result from standard tables
I = ½m(R² + r²)
then use the parallel axis theorem to shift the position of the axis
I = ½m(R² + r²) + md²
where d is the distance of the shift. In this case d = R
I = ½m(R² + r²) + mR²
I = m(1.5R² + 0.5r²)
If we select a mass of say 20 grams
I = 0.020(1.5(0.060²) + 0.5(0.0075²))
I = 0.0001085625 kg•m²
if C is The vector sum of A and B C = A + B What must be true about The directions and magnitudes of A and B if C=A+B? What must be tre about the directions and magnitudes of A and B if C=0?
Check attached photo
Check attached photo
Answer:
Explanation:
1. If C = A + B then the lines A and B may have the same magnitude or they may not. The direction of A for example may be northwest ↖️ and the direction of B must be south ⬇️ because the arrow of A and the point of B must connect. Then C’s direction is west ⬅️ because it shouldn’t be as equilibrium.
2. If C = 0 t means the force is at equilibrium. That means all forces add up to zero. A’s direction for example may be northeast ↗️ and the direction of B may be south ⬇️ and the direction of C must be west if it has to be at equilibrium.
The magnitude of A and B must be equal
True or false? Charges flow from high voltage to low voltage
A 0.360-m-long metal bar is pulled to the left by an applied force F. The bar rides on parallel metal rails connected through a 45.0 ohm resistor, as shown in the diagram, so the apparatus makes a complete circuit. The circuit is in a uniform 0.650-T magnetic field that is directed out of the plane of the figure. At the instant when the bar is moving to the left at 5.90 m s, (a) is the induced current in the circuit clockwise or counterclockwise and (b) what is the rate at which the applied force is doing work on the bar?
(a) The induced current in the circuit is clockwise.
b. To find the power (P) using P = Fd/t or P = Fv (since d/t = v). Here, F = ILB (from the Lorentz force), so P = (ILB)v.
How to solve(a) The induced current in the circuit is clockwise.
This can be determined using the right-hand rule.
As the metal bar moves to the left through the magnetic field directed out of the plane, the generated force on the electrons (Lorentz force) will push them toward the top rail, creating a clockwise current.
(b) To find the rate at which the applied force is doing work on the bar, first calculate the induced EMF (ε) using Faraday's law:
induced EMF (ε) using Faraday's law:
ε = BLv
= (0.65 T) * (0.36 m) * (5.9 m/s)
= 1.389 Tm²/s
= 1.389 V (since 1 Tm²/s = 1 V)
induced current (I) using Ohm's law:
I = ε/R
= 1.389 V / 45 Ω
= 0.03086 A
force (F) from the Lorentz force law, where F = ILB:
F = ILB
= (0.03086 A) * (0.36 m) * (0.65 T)
= 0.00723 N
Finally, we find the power (P) using P = Fv:
P = Fv
= (0.00723 N) * (5.9 m/s)
= 0.04266 W
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On your drive home from school, you travel 1200 m in 80 s, then 400 min 20 s.
What is your average speed in m/s?
Average speed = Total distance/total time taken
\( = \frac{1200 + 400}{80 + 20} \)
\( = \frac{1600}{100} \)
\( = \frac{16}{1} \)
\( = 16 \: ms {}^{ - 1} \)
Please Help Me ~ 50 Points for you
A rock is held steady over a cliff and dropped. 1 seconds later, another rock is thrown straight down at a speed of 11.3 m/s, and hits the first rock. How far have the rocks dropped before they collide? How long is the first rock in the air before it gets hit by the second rock?
What is the displacement of the rocks when they collide? _____ (Hint: be careful of sign -- the rocks drop.)
The first rock is in the air for _____ before it is hit.
Answer:
4.27s
Explanation:
If "t" represents the time traveled from the time rock 2 is dropped until the collision, then the time traveled for rock 1 = t + 1. And, since rock #1 is dropped making its initial velocity = 0, then:
The distance rock 1 travels is
x = (0)(t + 1) + 1/2(-9.8)(t + 1)2 = -4.9(t2 + 2t + 1) = -4.9t2 - 9.8t - 4.9
The distance rock 2 travels
x = -11.3t + 1/2(-9.8)t2 = -11.3t - 4.9t2
For the distances must be equal when the rocks collide:
-4.9t2 - 9.8t - 4.9 = -11.3t - 4.9t2
-9.8t - 4.9 = -11.3t
-4.9 = -1.5t
t = 3.267 s
Now, the distance they traveled can be found by plugging the 3.267 s back into either equation:
x = -11.3(3.267) - 4.9(3.267)2 = -89.2 m or 89.2 m below where they began
The time the first rock was in the air is t + 1 = 3.267 + 1 = 4.267 s = 4.27 s
Let
First rocks time be xSecond rocks time be x+1initial velocity=u=11.3m/sDistance of both rocks be s1 and s2
\(\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2\)
Now
\(\\ \sf\longmapsto s1=11.3x+5x^2\)
\(\\ \sf\longmapsto s2=11.3(x+1)+5(x+1)^2\)
As both collide then
\(\\ \sf\longmapsto s1=s2\)
\(\\ \sf\longmapsto 11.3x+5x^2=11.3x+11.3+5(x+1)^2\)
\(\\ \sf\longmapsto 5x^2=11.3+5x^2+10x+1\)
\(\\ \sf\longmapsto 10x+12.3=0\)
\(\\ \sf\longmapsto x=1.23s\)
Displacement
\(\\ \sf\longmapsto 11.3(1.23)=13.8m\)
A horizontal force is applied to push a 105 N trunk across the floor to the left with an acceleration of 25.1 m/s2. The coefficient of sliding friction between the trunk and the desk is 0.63.
With a 25.1 m/s2 acceleration, 2,946.19 N of horizontal force is required to push the trunk across the floor to the left.
What is the friction coefficient formula?Usually, the Greek letter mu is used to indicate it (). is mathematically equivalent to F/N, where F denotes frictional force and N is normal force. Due to the fact that F and N are both measured in units of force, the coefficient of friction has no dimensions (such as newtons or pounds).
An object's mass times its acceleration equals the object's net force:
F_net = m * a
The applied force less the frictional force equals the net force acting on the trunk:
F_net = F_applied - F_friction
The force of friction is given by:
F_friction = μ * N
As there is no vertical acceleration of the trunk, its weight is equal to the normal force:
N = m * g
where g is the gravitational acceleration.
When you combine everything, you get:
F_net = F_applied - μ * m * g = m * a
With the applied force factored in, we obtain:
F_applied = m * (a + μ * g)
Plugging in the given values, we get:
F_applied = 105 N * (25.1 m/s^2 + 0.63 * 9.81 m/s^2) = 2,946.19 N
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A bubble of air has a diameter of 1 mm when it is 0.5 m under the surface of water ( coefficient of surface tension 0.073 N/m). Find the gauge pressure inside the bubble.
The gauge pressure inside the bubble. is -101310.4 Pa.
The negative sign shows that the pressure inside the bubble is lower than the atmospheric pressure. Hence, the bubble will rise to the surface of the water.
How do we calculate?We apply Laplace's law to find the absolute pressure inside the bubble:
ΔP = 2γ/r
where ΔP is the pressure difference across the curved surface of the bubble, γ is the coefficient of surface tension of water, and r is the radius of curvature of the bubble.
r = 0.5 mm = 0.0005 m
Substituting the given values, we have:
ΔP = 2 × 0.073 N/m ÷ 0.0005 m
ΔP = 14.6 × 10^(-3) Pa
The atmospheric pressure at sea level is approximately 101325 Pa. Therefore, the gauge pressure inside the bubble is:
P_gauge = ΔP - P_atm
P_gauge = 14.6 × 10^(-3) Pa - 101325 Pa
P_gauge = -101310.4 Pa
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1) Determine the magnitude of energy for each of the blanks on the diagram. Give the correct values for 1A, 1B, and 1C.
2)Explain how the energy transformations follow the Law of Conservation of energy throughout the skier's path. Must answer in complete sentences.
3)Explain how the situation shown above would be different if the skier experiences friction while traveling downhill. Include the terms kinetic energy, heat energy, mechanical energy, total energy and friction. Must answer in complete sentences.
Answer:
Explanation: y’all taking the same test as me hahahahah I got the answers but I can’t attach the picture here so hit me up on snap daniela_0789
The total energy at each point in the path of the skier is constant as the
skier travels down the slope.
1) 1A P.E. = 15,000 J, 1B K.E. = 19,000 J, 1C, P.E. = 0 J2) The mechanical energy of the system is constant3) Energy is given off as heat due to friction such that the total energy of the system is not conserved if friction is experiencedReasons:
1) Given that the total mechanical energy, M.E. is constant, we have;
M.E. = Kinetic Energy, K.E. + Potential Energy, P.E. = Constant
M.E. = K.E. + P.E.
At the start, we have;
P.E. = 25,000 J
K.E. = 0 J
Therefore;
M.E. = 25,000 J + 0 J = 25,000 J
At point 1A, we have, K.E = 10,000 J
P.E. = M.E. - K.E.
Therefore;
P.E. = 25,000 - 10,000 = 15,000
The potential energy at point 1A, P.E. = 15,000 J
At point 1B, we have; PE = 6000 J
K.E. = M.E. - P.E.
Therefore;
K.E. = 25,000 J - 6,000 J = 19,000 J
At 1B, K.E. = 19,000 J
At point 1C, we have; K.E. = 25,000 J
Therefore;
P.E. = 25,000 J - 25,000 J = 0 J
At 1C P.E. = 0 J
2) The Law of Conservation of Energy states that the energy in a closed
system is constant.
The energy transformation follows the Law of Conservation of energy
given that the total mechanical energy is constant at all points along the
path.
3) The energy of a system is not conserved when a external force is
applied.
If the skier experiences friction, the force of friction does work to reduce
the speed of the skier, thereby reducing the kinetic energy at a point
downslope, where the potential energy has already been reduced,
resulting in an reduction in the mechanical energy of the system.
Therefore, if the skier experiences friction, the total energy of the system is
not conserved, as energy will be consumed in the work done by friction
which is converted to heat and sound energies.
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A person with a weight of 190 N sits on a box with a weight of 20 N, what is the normal force on the box?
The normal force on the box is 210 N.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Normal force on the box = total Weight of box and person = 210 N.
The normal force on the box is 210 N.
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A plane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. Assume that the plane reaches the required takeoff velocity at the end of the runway. What is the distance dfirst traveled by the plane in the first second of its run?
The distance travelled by the plane in the first second of its run is 5m.
What is Velocity?Velocity is defined as the rate of change of a body’s position with respect to time. Velocity is basically speeding in a specific direction. It is a vector quantity, which means we need both magnitude (speed) and direction to define velocity. If there is a change in magnitude or the direction of velocity of a body, then it is said to be accelerating.
From the question;
velocity (acceleration) = 5m/s2
distance = 1800m
so, to find the distance travelled in the first second;
time = 1 second
using the formula; \(velocity = \frac{displacement}{time}\)
therefore; displacement = velocity x time
displacement = 5 x 1
displacement = 5m
In conclusion, the plane travelled 5m in the first second of its run.
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Find the kinetic energy of a ball of mass 200 grams moving at a speed of 20 m/s
Answer:
40 J
Explanation:
\(KE = \frac{1}{2} mv^{2} \\KE = \frac{1}{2} (0.200 kg)(20 m/s)^{2} \\KE = 40 J\)
Jamaal has done an experiment using a mirror to
investigate how light is reflected.
He measures the angle of incidence and the
angle of reflection. Here are his results plotted
on a graph.
a. Which result or results should be repeated?
b. Why?
C. Where should Jamaal draw a line of best fit?
a. The results should be repeated is 40.
b. because because it's not accurate.
c. Jamaal draw a line of best fit at the middle of the reflection angel and incidence angle.
With an example, what is the angle of incidence?The angle created when a sunlight ray strikes a line that is perpendicular to a surface; for instance, a surface facing the sun directly has an angle of incidence of 0, while a surface parallel to the sun (such as sunlight striking a horizontal rooftop) has an angle of incidence of 90°.
The light ray that reflects off the surface is referred to as the reflected ray, and the angle at which the reflected ray reflects off the surface is referred to as the reflection angle. The law of reflection states that the angle of incidence and angle of reflection are equal.
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1. Two small, identical conducting spheres A and B are a distance R apart; each carries the same charge Q. What is the force sphere B is exerting on sphere A? (2 marks) b. An identical sphere with zero charge, sphere C, makes contact with sphere A and is then moved very far away. What is the net force now acting on sphere A? (3 marks) c. Sphere C next makes contact with sphere A and is then moved far away. What is the force on sphere A in this third case? (2 marks)
Answer:
the same question I want to know
a. Spheres A and B carry the same charge \(\rm \( Q \)\), the force can be written as:
\(\rm \[ F = \frac{k Q^2}{R^2} \]\), b. The net force on sphere A now is the force due to sphere B, which is: \(\rm \[ F = \frac{k \frac{Q}{2} \cdot Q}{R^2} = \frac{k Q^2}{2R^2} \]\), c. The magnitude of the force on sphere A in this third case is \(\rm \( \frac{3}{8} \)\) of the original force.
a) The magnitude of the force (F) sphere B exerts on sphere A can be calculated using Coulomb's law:
\(\rm \[ F = \frac{k Q_1 Q_2}{R^2} \]\)
where:
k is Coulomb's constant \(\rm \( k = \frac{1}{4\pi\epsilon_0} \)\) where \(\rm \( \epsilon_0 \)\) is the vacuum permittivity constant),
\(\rm \( Q_1 \)\) and \(\rm \( Q_2 \)\) are the charges on spheres A and B respectively, and
\(\rm \( R \)\) is the distance between the two spheres.
Since both spheres A and B carry the same charge \(\rm \( Q \)\), the force can be written as:
\(\rm \[ F = \frac{k Q^2}{R^2} \]\)
b) When an identical sphere C makes contact with sphere B, they share the charge equally. Sphere B now carries \(\rm \( \frac{Q}{2} \)\) charge, and sphere C carries \(\rm \( \frac{Q}{2} \)\) charge.
When sphere C is moved far away, it exerts no force on sphere A. So, the net force on sphere A now is the force due to sphere B, which is:
\(\rm \[ F = \frac{k \frac{Q}{2} \cdot Q}{R^2} = \frac{k Q^2}{2R^2} \]\)
c) When sphere C makes contact with sphere A, they both share the charge equally. Each sphere now carries \(\rm \( \frac{Q}{2} \)\) charge.
When sphere C is moved far away, the net force on sphere A now is the force due to the charge on sphere A itself, which is:
\(\rm \[ F = \frac{k \frac{Q}{2} \cdot \frac{Q}{2}}{R^2} \\\\\rm = \frac{3}{8} \frac{k Q^2}{R^2} \]\)
So, the magnitude of the force on sphere A in this third case is \(\rm \( \frac{3}{8} \)\) of the original force.
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A uniform solid cylindrical flywheel has a mass of 50 kg and a radius of 40 cm. The flywheel begins to rotate faster with an acceleration of 1.5 rad/s2. The kinetic energy of the flywheel after 1 minute of rotation is:
A. 16.2 KJ
B. 180 KJ
C. 40.5 KJ
D. 32.4 KJ
The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)
How do I determine the kinetic energy?We'll begin by obtaining the velocity of the flywheel. This is shown below:
Radius (r) = 40 cm = 40 / 100 = 0.4 mAcceleration (a) = 1.5 rad/s² = 1.5 × 0.4 = 0.6 m/s²Time (t) = 1 minute = 1 × 60 = 60 sVelocity (v) = ?v = at
v = 0.6 × 60
v = 36 m/s
Finally, we shall determine the kinetic energy of the flywheel. Details below:
Mass (m) = 50 KgVelocity (v) = 36 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 50 × 36²
KE = 25 × 1296
KE = 32400 J
Divide by 1000 to express in KJ
KE = 32400 / 1000
KE = 32.4 KJ
Thus, the kinetic energy is 32.4 KJ (Option D)
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1. You are part of a new team of colleagues at work and you are trying to remember everyone's
name. What part of the brain would be responsible for making sure you know who everyone is?
a. Hippocampus
b. Hypothalamus
c. Amygdala
d. Thalamus
The part of the brain that would be responsible for making sure you know who everyone is Hippocampus; option A
What is the brain?The brain is the organ in the body which controls the function of other organs in the body.
The brain is made up of cells called neurons.
The brain is divide into three main parts namely:
the cerebrum,the brainstem, andthe cerebellumThe cerebrum consists of two cerebral hemispheres the outer layer called the cortex.
The brainstem consists of the medulla, pons, and midbrain.
The cerebellum consists of three lobes the anterior lobe, the posterior lobe and the flocculonodular lobe.
The hippocampus is part of the temporal lobe which controls recognition and dentification of people.
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If a = (3, 2) and b = (-5, 3), what is a + b ?
(8,-1)
(2,5)
(-2,5)
(8,5)
Answer: a + b = (-2,5)
Explanation: I'm assuming that these are 1-dimensional matrices or vectors.
So,
a + b = [ a(x) + b(x), a(y) + b(y) ]
= [ (3) + (-5) , (2) + (3) ]
= [ (-2) , (5) ]
a +b = (-2,5)
HELP ME ASAPPPPPPPPPPP
A penny sinks to the bottom of a wishing well
What type of frictional force is that?
The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.
A boat strikes an underwater rock that punctures a hole 20 cm^2 in area in its hull 1.5 m below the waterline. At what rate does water enter the hull?
HELP ME PLEASE
Water enters the hull at a rate of 29400 cm^3/s.
What is speed?The distance an object travels in a unit of time is its speed. Speed is a scalar quantity since it has simply magnitude and no direction. SI unit of speed is meter per second.
Given that area of the hole of puncture = 20 cm^2
Depth of the hole: d = 1.5 m.
Then, the speed of the water enter the hull =
acceleration due to gravity × depth
= 9.8 × 1.5 m/s
= 14.7 m/s
= 1470 cm/s.
Hence, the rate of water enter the hull is = the speed of the water × area of the hole
= 1470 cm/s × 20 cm^2
= 29400 cm^3/s.
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https://brainly.com/question/28224010
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