Problem #4
Term Position (n) Term Value (An)
What is the r of this sequence?
1
2. 3 4
5
93312
5
6
7 8
8
9
12
10

Answer:

4/1

Step-by-step explanation:

when you divide 4 by 1 you will get 4 which is your original answer.

Answer:

10

Step-by-step explanation:

by Pythagoras theorem,

PR^2=PQ^2+PR^2

Therefore,PR=√(PQ^2+PR^2)

=√(6^2+8^2)

=√100

=10

Answer:

25quarts of grape juice, 50 quarts of water

Step-by-step explanation:

Do the math

Answer:

You'd need 50 quarts of sparkling water and 25 quarts of grape juice

Step-by-step explanation:

You can make an equation with this.

\(75=4/6x+3/4x\)

When you solve for this, you'll get 100/3.

You can then substitute x for 100/3 and get the numbers.

The number of spanning trees of a connected graph can be proven to be the product of the number of spanning trees of each of its blocks.

Here are the steps-

1. Consider a connected graph G with blocks B1, B2, ..., Bk. Each block is a maximal connected subgraph with no cut-vertex.

2. The number of spanning trees of G can be denoted as T(G), and the number of spanning trees of each block Bi can be denoted as T(Bi).

3. To prove the given statement, we need to show that\(T(G) = T(B1) * T(B2) * ... * T(Bk).\)

4. We can start by considering a single block B1. Since B1 is a maximal connected subgraph with no cut-vertex, it is a connected graph on its own.

5. The number of spanning trees of B1, T(B1), can be calculated using any method such as Kirchhoff's theorem or counting the number of spanning trees directly.

6. Now, consider the original graph G. We can remove block B1 from G, which leaves us with a graph G' that consists of the remaining blocks B2, B3, ..., Bk.

7. G' is still a connected graph, but it may have cut-vertices. However, the removal of B1 does not affect the connectivity between the other blocks, as each block is a maximal connected subgraph.

8. The number of spanning trees of G', denoted as T(G'), can be calculated using the same method as step 5.

9. Since G' is the remaining part of G after removing B1, the number of spanning trees of G can be expressed as T(G) = T(B1) * T(G').

10. We can repeat this process for the remaining blocks B2, B3, ..., Bk. For each block Bi, we remove it from G and calculate the number of spanning trees of the remaining graph.

11. By repeating steps 6-10 for all blocks, we can express the number of spanning trees of G as-

\(T(G) = T(B1) * T(G')\)

\(= T(B1) * T(B2) * T(G'')\)

= ...

\(= T(B1) * T(B2) * ... * T(Bk).\)

12. Therefore, we have proved that the number of spanning trees of a connected graph G is the product of the number of spanning trees of each of its blocks.

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Answer:

i don't know, you need to tell us what we need to do

Step-by-step explanation:

Answer:

Hi! The answer to your question is 0 8/25

Step-by-step explanation:

☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆

☁Brainliest is greatly appreciated!☁

Hope this helps!!

- Brooklynn Deka

The critical value (t₍₃₀,₀.₀₅₎) for a 95% confidence interval, based on a random sample of 30 observations, is t₍₃₀,₀.₀₅₎ = 2.042.

To determine the critical value, we refer to the t-table with degrees of freedom (df) equal to n - 1, where n represents the sample size. In this case, the sample size is 30, so the degrees of freedom is 30 - 1 = 29.

For a 95% confidence interval, we need to consider the two-tailed critical region. Since the area in each tail is 0.025 (0.05/2), we look for the corresponding value in the t-table at a significance level of α/2 = 0.025 for df = 29.

The closest value to 0.025 in the table is 2.042.

Therefore, the critical value (t₍₃₀,₀.₀₅₎) for a 95% confidence interval based on a random sample of 30 observations is t₍₃₀,₀.₀₅₎ = 2.042.

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Answer:

The Properties of parallelogram are

a) Opposite sides are equal

b) All angles are not 90°

The Properties of trapezium are

a) One pair of opposite side is parallel

b) side of adjacent angle and non parallel side

of trapezium is 180°

The Properties of rhombus are

a) All sides are equal

b) All angles are not 90°

Answer:

D

Step-by-step explanation:

Answer:

sinTheta = 24/25

cotTheta = 7/24

cscTheta = 25/24

Step-by-step explanation:

Use pythagorean thm or pythagorean triples to find the missing side of the triangle.

7^2 + x^2 = 25^2

49 + x^2 = 625

x^2 = 576

x = 24

The third side of the triangle is 24. We'll need this in a sec.

The marked angle is called theta. That 0 with a belt is greek letter theta. They could just call it angleA or angleB or whatever. Its name is just theta no big deal.

25 is the hypotenuse (longest side). The side that's 7 units long is one of the pieces that makes up AngleTheta. So the 7 is "adjacent" to theta. The other leg, 24, is "opposite" from theta.

sinTheta is a ratio. It is OPPOSITE/HYPOTENUSE

sinTheta = 24/25

cotTheta is tanTheta flipped over.

tanTheta is OPP/ADJACENT

so...

cotTheta =

ADJ/OPP

=7/24

Last, cscTheta is sinTheta flipped over.

We already found sinTheta, so flip it over.

cscTheta = 25/24

SOH-CAH-TOA is supposed to help you memorize the ratios for sine (opp/hyp), cos (adj/hyp), and tan (opp/adj).

The math word for "flipped over" is reciprocal.

csc is the reciprocal of sin

sec is the reciprocal of cos.

cot is the reciprocal of tan.

Good luck! Hope this helps!

Answer:

It D hope this is right

Step-by-step explanation:

I'm learning this in class right now and I'm pretty good at it so hope you get it right

Answer:

D. a reflection over the y-axis

Step-by-step explanation:

We can see that ΔQRS has been directly translated across the y-axis to form ΔQ'R'S'. (It mirrors across)

Answer:

The length of DB is 8

Step-by-step explanation:

I know it doesn't look EXACTLY like the one in the diagram but I just followed the measurements provided

The expanded form of the number 27.430 is 20 + 7 + 0.400 + 0.30.

A billing statement is a recurring statement that details every transaction made on your credit card account during the billing cycle, including purchases, payments, and other debits and credits. Every month or so, your credit card company will send you a billing statement.

Given that the number is 27.430. The expanded form of the number is written as:-

Expanded form:-

27.430 = 20 + 7 + 0.400 + 0.30.

When we add all the values of the expanded form we will get the previous value.

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correct answer is F - Use a t-sampling distribution because the population is normal, and is unknown.

Since the population is normally distributed and the population standard deviation is unknown.

we should use a t-sampling distribution. Additionally, since the sample size is less than 30 (n < 30), the t-distribution is more appropriate than the normal distribution.

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Since K is the midpoint of JL and we know that JK and KL are separate segments of JL, JK and KL are equal to each other.

6x + 11 = 16x + 1

Subtract 6x and 1 from both sides

10 = 10x

Divide both sides by 10

1 = x

We also know that:

JL = JK + KL = 6(1) + 11 + 16(1) + 1 = 6 + 11 + 16 + 1 = 34

Answer:

1

Step-by-step explanation:

Change 1/2 to 0.5 and then do 0.75-0.25+0.5.

Answer:

1

Step-by-step explanation:

0.75-0.25+1/2

=0.50+0.5

=0.5+0.5

=1

1. The probability of selecting exactly one tank with high-viscosity material is 0.

2. The probability of selecting at least one tank with high-viscosity material is 1.

3. The probability of selecting exactly one tank with high-viscosity material and exactly one tank with high impurities is 0.25.

1. The probability of selecting exactly one tank with high-viscosity material is calculated by the binomial distribution formula, P(X = n) = (nCx)p^x(1-p)^n-x, where n is the number of trials, x is the number of successes, and p is the probability of success. In this case, n = 4, x = 1, and p = 24/24 = 1. Therefore, P(X = 1) = (4C1)1^1(1-1)^4-1 = 0.

2. The probability of selecting at least one tank with high-viscosity material is calculated by the complement rule, P(X > 0) = 1 - P(X = 0). In this case, P(X > 0) = 1 - (4C0)1^0(1-1)^4-0 = 1.

3. The probability of selecting exactly one tank with high-viscosity material and exactly one tank with high impurities is calculated by the binomial distribution formula, P(X = n) = (nCx)p^x(1-p)^n-x, where n is the number of trials, x is the number of successes, and p is the probability of success. In this case, n = 8, x = 2, and p = 24/24 = 1. Therefore, P(X = 2) = (8C2)1^2(1-1)^8-2 = 0.25.

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Since Year 1 is the base year, the Cost per Index(CPI) remains constant at 100 for both Year 1 and Year 2. This means that the prices of apples have not changed relative to the base year.

To compute the Consumer Price Index (CPI) for apples in each year, we need to compare the prices of apples in each year to the prices in the base year (Year 1).

Year 1 (Base Year):

- Price of red apples: $1 each

- Price of green apples: $2 each

- Quantity of red apples purchased: 10

To calculate the CPI for Year 1, we use the formula:

CPI = (Total cost of the consumer basket in the current year / Total cost of the consumer basket in the base year) * 100

The total cost of the consumer basket in Year 1:

= (Price of red apples * Quantity of red apples) + (Price of green apples * Quantity of green apples)

= ($1 * 10) + ($2 * 0)  (since Abby did not buy any green apples in Year 1)

= $10

Therefore, the CPI for apples in Year 1 is:

CPI Year 1 = ($10 / $10) * 100

           = 100

Year 2:

- Price of red apples: $2 each

- Price of green apples: $1 each

- Quantity of green apples purchased: 10

The total cost of the consumer basket in Year 2:

= (Price of red apples * Quantity of red apples) + (Price of green apples * Quantity of green apples)

= ($2 * 0) + ($1 * 10)  (since Abby did not buy any red apples in Year 2)

= $10

Therefore, the CPI for apples in Year 2 is:

CPI Year 2 = ($10 / $10) * 100

           = 100

Since Year 1 is the base year, the CPI remains constant at 100 for both Year 1 and Year 2. This means that the prices of apples have not changed relative to the base year. The index does not change from Year 1 to Year 2, indicating that there is no inflation or deflation specifically related to the price of apples.

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The complete question is:

Abby consumes only apples. In year 1, red apples cost $1 each, green apples cost $2 each, and Abby buys 10 red apples. In year 2, red apples cost $2, green apples cost $1, and Abby buys 10 green apples.

'Compute the cpi for apples for each year. assume that year 1 is the base year in which the consumer basket is fixed. how does your index change from year 1 to year 2?

The number line (d) represents the location of the fraction -3/8 on the number line

A number line is a  vertical or horizontal line that has endpoints and it is used to represent numbers at a constant interval

The fraction is given as

-3/8

The above number is a negative number and it is greater than -1

This means that the location of the number line is between 0 and -1

To plot the number line, we make use of 8 intervals between 0 and -1 ( as represented by the number lines in the options)

The third point to the left of 0 represents -3/8

This means that the number line (d) represents the location of the fraction -3/8 on the number line

Hence, the number line (d) represents the location of the fraction -3/8 on the number line

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Answer:

C. 33

Step-by-step explanation:

36% of 150=54

14% of 150=21

54-21=33

1. Asymptotic slope of the best line for the equation y = 5x⁴ + 3 plotted on a log-log plot is 4. To find this, first note that the dominant term in the equation is 5x⁴. On a log-log plot, the slope corresponds to the exponent of the dominant term. In this case, the exponent is 4.

2. The maximum number of inversions in a list of 100 distinct elements is 4,950. This occurs when the list is sorted in descending order.

To calculate the maximum number of inversions, use the formula n * (n - 1) / 2, where n is the number of elements. In this case, n = 100, so the maximum number of inversions is 100 * 99 / 2 = 4,950.

3. The minimum number of inversions in a list of 100 distinct elements is 0. This occurs when the list is already sorted in ascending order, meaning no inversions are present.

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We have linearized the given ODE to: \(\[ \frac{{dv}}{{dt}} = \frac{5}{2} \]\). This is the linearized equation.

To linearize the given ordinary differential equation (ODE) \(\( \frac{{dy}}{{dt}} = 5 \sqrt{x} \)\), we need to rewrite it in a linear form. One common approach is to introduce a new variable that relates to the derivative of \(\( y \)\).

Let's define a new variable \(\( v = \sqrt{x} \)\). Taking the derivative of both sides with respect to \(\( t \)\), we have:

\(\[ \frac{{dv}}{{dt}} = \frac{{d}}{{dt}} \left( \sqrt{x} \right) \]\)

Using the chain rule, we can express \(\( \frac{{dv}}{{dt}} \)\) in terms of \(\( \frac{{dx}}{{dt}} \)\):

\(\[ \frac{{dv}}{{dt}} = \frac{1}{{2 \sqrt{x}}} \cdot \frac{{dx}}{{dt}} \]\)

Now, we need to substitute \(\( \frac{{dx}}{{dt}} \)\) using the given equation \(\( \frac{{dy}}{{dt}} = 5 \sqrt{x} \)\):

\(\[ \frac{{dv}}{{dt}} = \frac{1}{{2 \sqrt{x}}} \cdot \left( 5 \sqrt{x} \right) \]\)

Simplifying the right-hand side:

\(\[ \frac{{dv}}{{dt}} = \frac{5}{2} \]\)

Thus, we have linearized the given ODE to: \(\[ \frac{{dv}}{{dt}} = \frac{5}{2} \]\)

The linearized equation is much simpler compared to the original non-linear equation.

Note: The complete question is:

Linearize the ODE below;

\(\(\frac{{dy}}{{dt}} = 5\sqrt{x}\)\)

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Answer:

Discrete

Step-by-step explanation:

Given the function:

f(x) = 100x + 300

Where ;

x = number of attendees

At least 4 students but no more than 9 students will attend the fieldtrip due to transportation and chaperone restrictions

Range of attendees :

4 ≤ x ≤ 9

Is this a discrete or continuous situation?

It is a discrete because the number of students who will attend the science weekend are finite and countable.

The number of attendees range from:

4, 5, 6, 7, 8 and 9.

The distance between ping's home to aris's home will be 1 street and 12th avenue.

Arithmetic operators are four basic mathematical operations in which summation, subtraction, division, and multiplication involve.,

Summation = addition of two or more numbers or variable

For example = 2 + 8 + 9

Subtraction = Minus of any two or more numbers with each other called subtraction.

For example = 4 - 8

Division = divide any two numbers or variable called division.

For example 4/8

Multiplication = to multiply any two or more numbers or variables called multiplication.

For example 5 × 7.

Given,

Ping house ⇒ 3rd street and 6th avenue

Ari's home ⇒  21st street and 18th avenue

So, the distance between them

21 - 3 = 18 street

18 - 6 = 12 avenue.

Hence "The distance between ping's home to aris's home will be 1 street and 12th avenue".

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Answer:

2nd answer

Step-by-step explanation:

a triangles area is its height x base x half so 8x4/2 is 16