Answers
The pressure needed to raise the boiling point of water to 200.0°C can be gotten from the graph of temperature versus saturation pressure of water
Checking from the graph:
The water pressure necessary to raise the boiling point to 200.0°C = 1554900 Pa
\(P=1.55\times10^6Pa\)b) To calculate the gauge pressure, follow the steps below
\(\begin{gathered} P_g=P-P_{atm} \\ \\ P_g=(1.55\times10^6)-(1.01\times10^5) \\ \\ P_g=1.45\times10^6Pa \\ \\ P_g=\frac{1.45\times10^6}{1.01\times10^5} \\ \\ P_g=14.4\text{ atm} \end{gathered}\)Related Questions
Hint: sin2θ + cos2θ = 1 .
Consider the 692 N weight held by two
cables shown below. The left-hand cable had
tension 570 N and makes an angle of θ2 with
the ceiling. The right-hand cable had tension
530 N and makes an angle of θ1 with the
ceiling. a) What is the angle θ1 which the righthand cable makes with respect to the ceiling?
Answer in units of ◦.
b) What is the angle θ2 which the left-hand
cable makes with respect to the ceiling?
Answer in units of ◦.
Answers
a) The angle θ1 which the righthand cable makes with respect to the ceiling is sin^(-1)(692 N / 530 N).
b) The angle θ2 which the left-hand cable makes with respect to the ceiling is sin^(-1)(692 N / 570 N).
We may utilise the tension of the right-hand cable as well as its vertical and horizontal components to determine the angle 1. θ2 = sin^(-1)(692 N / 570 N).
We may apply the ideas of trigonometry and vector addition to address this issue.
a) The tension of the right-hand wire as well as its vertical and horizontal components can be used to determine the angle 1.
T1sin(1) calculates the vertical component of the right-hand cable's tension, which is equal to the object's weight (692 N).
T1sin(θ1) = 692 N
We may rearrange the equation to find 1:
θ1 = sin^(-1)(692 N / T1)
We can find 1 by substituting the given tension value, T1 = 530 N:
θ1 = sin^(-1)(692 N / 530 N)
b) Similarly, we can use the formula to determine the angle 2 the left-hand cable's tension and its vertical and horizontal components.
The vertical component of the left-hand cable's tension is given by T2sin(θ2), and it should also be equal to the weight of the object (692 N).
T2sin(θ2) = 692 N
To find θ2, we can rearrange the equation:
θ2 = sin^(-1)(692 N / T2)
Substituting the given tension value T2 = 570 N, we can solve for θ2:
θ2 = sin^(-1)(692 N / 570 N)
Calculating these angles using the given tension values will provide the answers in degrees.
For more question on tension
https://brainly.com/question/24994188
#SPJ11
5. The mechanical advantage of a jaw when it is used as a second-class lever is 1.4.
a. If the input force is 100 newtons, what is the output force?
b. How does the input lever arm compare to the output lever arm when the jaw is used as a
second-class lever? Draw a diagram to illustrate your answer.
Answers
Answer: a. It would be 140 N
I don’t know, I just got it right
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
Answers
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
Know more about potential energy here:
https://brainly.com/question/21175118
#SPJ8
A unit used to measure force is a
a. newton.
b. newton-meter.
c. joule.
d. watt.
Answers
Answer:
Newton
Explanation:
Newton's are the standard unit of force.
which of the following describes the net force on an object?
A. The sum of all forces acting on an object
B. The Gravitational force minus any contact forces on an object.
C. The difference between the normal force and the Gravitational force acting on an object.
D. the sum of all forces acting on an object in the same direction.
Answers
The statement that describes the net force on an object is the sum of all forces acting on an object (option A).
What is net force?Net force is sum of all forces acting on an object in a single plane.
When a force is applied to a body, not only is the applied force acting, there are many other forces like gravitational force, frictional force and the normal force that balances the other force.
The sum of all these forces acting on the object whether in the same or opposite direction is regarded as the net force.
Therefore, the statement that describes the net force on an object is the sum of all forces acting on an object.
Learn more about net force at: https://brainly.com/question/18031889
#SPJ1
A uniform electric field is directed upward and has a magnitude of 24 N/C. A charge of -6 C is placed in this
field.
The direction of the force on the charge placed in the electric field is upward.
True or False
Answers
The statement" The direction of the force on the charge placed in the electric field is upward" is false because the direction of the force on a negative charge (-6 C) placed in an upward-directed uniform electric field of magnitude 24 N/C would be downward.
The direction of the force on a charged particle placed in an electric field is determined by the charge of the particle and the direction of the electric field. In this case, a charge of -6 C is placed in an electric field directed upward with a magnitude of 24 N/C.
The force on a charged particle in an electric field can be calculated using the formula:
F = q * E
Where F is the force, q is the charge of the particle, and E is the electric field.
Since the charge q in this case is negative (-6 C) and the electric field E is directed upward, we can substitute the values into the formula:
F = (-6 C) * (24 N/C)
F = -144 N
The negative sign in the force value indicates that the force is in the opposite direction to the electric field. Therefore, the force on the charge placed in the electric field is downward, not upward.
The force on a negative charge is always opposite to the direction of the electric field. This is because negative charges experience an attractive force towards positive charges, and electric fields are directed from positive charges to negative charges.
Therefore, the statement "The direction of the force on the charge placed in the electric field is upward." is false.
For more such information on: force
https://brainly.com/question/12785175
#SPJ8
The ruminant stomach has four compartments including the rumen, reticulum, omasum and large intestine,
O True
O False
Answers
Answer:
FalseIt has four compartments just not including all of those
Explanation:
Ruminant stomachs have four compartments: the rumen, the reticulum, the omasum and the abomasum.Anatomy of the ruminant digestive system includes the mouth, tongue, salivary glands (producing saliva for buffering rumen pH), esophagus, four-compartment stomach (rumen, reticulum, omasum, and abomasum), pancreas, gall bladder, small intestine (duodenum, jejunum, and ileum), and large intestine (cecum, colon, and rectum).in a typical cop movie we see the hero pulling a gun firing that gun straight up into the air and shouting
Answers
It is not recommended to fire a gun straight up into the air.
When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.
Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.
To know more about the Gun, here
https://brainly.com/question/16568407
#SPJ1
Which scenario is best illustrates the concept of illusory correlation?
A. A person insists that there is no way to determine whether or not
any two events are actually correlated.
B. A person believes crossing his fingers brings good luck despite
studies demonstrating that it does not.
O C. A person argues that the mood swings he often has on rainy days
prove that weather affects human emotions.
O D. A person criticizes a scientific study for reaching a definitive
conclusion about data based on a weak correlation.
Answers
Answer:
A person believes crossing his fingers brings good luck despite studies demonstrating that it does not.
Explanation:
Hope it helps!
How are both electromagnetic and mechanical waves used when people communicate with each other?
Answers
If a 9851.6 kg vw van is moving at a speed of 16.7 m/s, what is the momentum? Round answer to the nearest hundredth
Answers
Answer:
the momentum is 164500 kg m/s
Explanation:
The computation of the momentum is shown below:
As we know that
Momentum is
= mass × velocity
= 9851.6 kg × 16.7 m/s
= 164522 kg·m/s
= 164500 kg m/s
hence, the momentum is 164500 kg m/s
A man runs 300 m West in 60 seconds. He then runs 100 m
North-west in 20 seconds.
What is his average velocity in metres per second?
Answers
Answer:
5 m/s
Explanation:
Total distance = 300 + 100 = 400m
Total time = 60 + 20 = 80s
Velocity = 400/80 = 5m/s
Average velocity of man is 5 meter per second.
To find the average speed of an object we divide the total distance travelled by the total time time taken by object.
Total distance travelled by man = 300 + 100 = 400 m
Total time taken by man = 60 + 20 = 80 seconds
Average velocity,\(=\frac{400}{80} =5m/s\)
Thus, Average velocity of man is 5 meter per second.
Learn more:
https://brainly.com/question/23856383
A satellite is to be launched into an orbit of radius,r Show that v = 2gr, where V is the
launch speed
Answers
Explanation:
We start by using the conservation law of energy:
\(\Delta{K} + \Delta{U} = 0\)
or
\(\dfrac{1}{2}mv^2 - G\dfrac{mM}{r} = 0\)
Simplifying the above equation, we get
\(v^2 = 2G\dfrac{M}{r}\)
We can rewrite this as
\(v^2 = 2\left(G\dfrac{M}{r^2}\right)r\)
Note that the expression inside the parenthesis is simply the acceleration due to gravity \(g\) so we can write
\( v^2 = 2gr\)
where \(v\) is the launch velocity.
8. What is the difference between mechanical waves and
electromagnetic waves?
Answers
A car rounds a banked curve as we will discuss in class on Tuesday. The radius of curvature of the road is R and the banking angle is θ. (a) In the absence of friction, what is the safe speed for the car to take this curve? (b) Now assume the coefficient of friction between the car’s tires and the road is µs. Determine the range of speeds the car can have without slipping up or down the road. (c) What is the minimum value of µs that makes the minimum speed zero? (d) If θ = 25.0 ◦ , for what values of µs can the curve be taken at any speed? Note: The upper limit of µs you will find is practically impossible to achieve for the car’s tires and the road.
Answers
Answer:
A) v = √[(rg(tan θ - µ_s))/(1 + (µ_s•tan θ))]
B)√[(rg(tan θ - µ_s))/(1 + (µ_s•tan θ))] ≤ v ≤ v = √[(rg(tan θ + µ_s))/(1 - (µ_s•tan θ))]
C) µ_s = tan θ
D) µ_s = 0.4663
Explanation:
A) The forces acting on the car will be;
Force due to friction; F_f
Force due to Gravity; F_g
Normal Force; F_n
Now, let us take the vertical direction to be j^ and the direction approaching the centre to be i^ downwards and parallel to the road surface by k^.
Also, we will assume that initially, F_n is in the negative k^ direction and that it will have a maximum possible value of; F_f = µ_s × F_n
Thus, sum of forces about the vertical j^ direction gives;
ΣF_j^ = F_n•cos θ − mg + F_f•sin θ = 0
Since F_f = µ_s × F_n ;
F_n•cos θ − mg + (µ_s × F_n × sin θ) =0
F_n = mg/[cos θ + (µ_s•sin θ)]
Also, sum of forces about the centre i^ direction gives;
ΣF_i^ = F_n(sin θ + (µ_s•cos θ)) = mv²/r
Plugging in formula for F_n gives;
ΣF_i^ = [mg/[cos θ + (µ_s•sin θ)]] × (sin θ + (µ_s•cos θ)) = mv²/r
Making v the subject gives;
v = √[(rg(tan θ - µ_s))/(1 + (µ_s•tan θ))]
B) What we got in a above is the minimum speed the car can have while going round the turn.
The maximum speed will be gotten by making the frictional force(F_f) to point in the positive k^ direction. This means that F_f will be negative.
Now, if we change the sign in front of F_f in the equation in part a that led to the minimum velocity, we will have the maximum as;
v = √[(rg(tan θ + µ_s))/(1 - (µ_s•tan θ))]
Thus the range is;
√[(rg(tan θ - µ_s))/(1 + (µ_s•tan θ))] ≤ v ≤ v = √[(rg(tan θ + µ_s))/(1 - (µ_s•tan θ))]
C) For the minimum speed to be 0, it implies that F_f will be in the negative k^ direction. Thus, Sum of the forces in the k^ direction gives;
ΣF_k^ = mg(sin θ - µ_s•cos θ) = 0
Thus;
mg(sin θ - µ_s•cos θ) = 0
Making µ_s the subject gives;
µ_s = sin θ/cos θ
µ_s = tan θ
D) If θ = 25.0°;
Thus;
µ_s = tan 25
µ_s = 0.4663
2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
Answers
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
For more such information on; volume
https://brainly.com/question/14197390
#SPJ8
How could human activities affect natural resources like air, trees, and soil?
Answers
Gold forms a solid solution with silver. Since the densities of pure gold and silver are 19.32 g/cm³ and 10.49 g/cm³, respectively, calculate the number of gold atoms per cubic centimeter for a silver-gold alloy containing 10% Au and 90% Ag by weight.
Answers
There are 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.
The density of a binary alloy can be calculated using the following equation:
ρ = w1ρ1 + w2ρ2
where,
ρ = density of the alloy
w1 and w2 = weight fractions of the two components (in this case, gold and silver)
ρ1 and ρ2 = densities of the pure components.
We are given that the alloy contains 10% gold and 90% silver by weight, so we can calculate the weight fractions as:
\(w_{Au}\) = 0.10
\(w_{Ag}\) = 0.90
We are also given the densities of pure gold and silver as:
ρ_Au = 19.32 g/\(cm^{3}\)
ρ_Ag = 10.49 g/\(cm^{3}\)
Now we can substitute these values into the density equation to find the density of the alloy:
ρ = \(w_{Au}\)ρ_Au +\(w_{Ag}\)ρ_Ag
ρ = (0.10)(19.32 g/\(cm^{3}\)) + (0.90)(10.49 g/\(cm^{3}\))
ρ = 11.08 g/\(cm^{3}\)
Next, we need to calculate the number of gold atoms per cubic centimeter in the alloy.
To do this, we can use Avogadro's number and the atomic weights of gold and silver:
\(N_A\) = 6.022 × \(10^{23}\) atoms/mol
Aum = 196.97 g/mol
Agm = 107.87 g/mol
The number of gold atoms:
\(n_{Au}\) = (\(w_{Au}\)ρ/ Aum) × \(N_{A}\)
Substituting the values, we get:
\(n_{Au}\) = (0.10 × 11.08 g/\(cm^{3}\)/ 196.97 g/mol) × 6.022 × \(10^{23}\) atoms/mol
\(n_{Au}\) ≈ 3.37 × \(10^{22}\) atoms/\(cm^{3}\)
Therefore, there are approximately 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.
know more about weight fractions here:
https://brainly.com/question/29078616
#SPJ11
(4x)。
(2x+6)。
I need to solve x for these angles
Answers
Answer: x=14
Explanation:
there is 90° in a right angle so
(4x)+(2x+6) =90
collect like terms
6x+6=90
-6 from both sides
6x=84
÷6
x=14
An ideal massless spring, inclined plane, that makes an angle theta with the horizontal, and mass arrangement is given. A block of mass m is released from rest at the top of a frictionless incline. The block comes to rest momentarily after it has compressed this spring by ∆x. Initially, distance between the block and the spring is d.
Find ∆x.
Answers
Compression is Δx = √(2mgd·sinθ/k).
Given parameters:
Mass of the block = m.
Distance between the spring and the block is = d
The spring constant = k.
And, angle of inclination = θ.
And, The block comes to rest momentarily after it has compressed this spring by ∆x.
Now, loss of potential energy of the block = mgd sinθ.
And, gain in potential energy of the spring due to compression = 1/2k(Δx)²
From principle of conservation of energy,
1/2k(Δx)² = mgd sinθ.
⇒ Δx = √(2mgd·sinθ/k)
So, amount of compression is Δx = √(2mgd·sinθ/k).
Learn more about potential energy here:
https://brainly.com/question/24284560
#SPJ1
What are the two types of precipitation?
In precipitation, rainwater can fall as either
Answers
In precipitation, Rainwater can fall as either Liquid or Solid.
Precipitation is a part of the water cycle. Precipitation falls to the floor as snow and rain. It subsequently evaporates and rises back into the surroundings as a gas. In clouds, it turns back into a liquid or stable water, and it falls to Earth again
The water cycle shows the non-stop motion of water within the Earth and its surroundings. it's miles a complex system that consists of many one-of-a-kind techniques. Liquid water evaporates into water vapor and condenses.
There are four fundamental ranges in the water cycle. they are evaporation, condensation, precipitation, and collection. permit's examined every one of these ranges. Evaporation: that is whilst warm temperature from the sun causes water from oceans, lakes, streams, ice, and soils to upward push into the air and grow to be water vapor.
Disclaimer: your question is incomplete, please see below for the complete question.
Liquid
Steam cloud
2nd half
Steam
Solid
Cloud
Learn more about precipitation here:-https://brainly.com/question/1783904
#SPJ9
An especially violent lightning bolt has an average current of 1.16 x 103 A lasting 0.139 s. How much charge is delivered to the ground by the lightning bolt
Answers
Charge is current times time :
Q = I × t
Q = 1.16 × 10³ × 0.139
Q = 161.24 C
what is the acceleration of an 18 kg mass pushed by a 9 N force
Answers
Answer:
0.5 m/s2 or 1/2 m/s2
Explanation:
f=ma
f= 9 N
m= 18 kg
a= f/m
9/18= 0.5 or 1/2 m/s2
Two ropes are attached to a heavy object. The ropes are given to two strong physics students (is there any other kind?) with instructions for each to pull with 1000 N of force. Determine the resultant force if the two students pull: a) in the same direction east.
Answers
write down the value of
920 kg in g
Answers
Answer:
920000
Explanation:
Each kg contains 1,000 grams
A car has a mass of 1200 kg and an acceleration of 4 m/s^2. If the friction on the car is 200 N, how much force is the thrust providing?
Answers
Answer:
5000N
Explanation:
According to Newton's second law of motion, the net force (∑F) acting on a body is the product of the mass (m) of the body and the acceleration (a) of the body caused by the force. i.e
∑F = m x a -------------(i)
From the question, the net force is the combined effect of the thrust (F) and the friction force (Fₓ). i.e
∑F = F + Fₓ -------------(ii)
Where;
Fₓ = -200N [negative sign because the friction force opposes motion]
Combine equations(i) and (ii) together to get;
F + Fₓ = m x a
F = ma - Fₓ -------------(iii)
Where;
m = mass of car = 1200kg
a = acceleration of the car = 4m/s²
Now substitute the values of m, a and Fₓ into equation (iii) as follows;
F = (1200 x 4) - (-200)
F = 4800 + 200
F = 5000N
Therefore, the force the thrust is providing is 5000N
1. Refer to Exercise 1.1: Discuss in everyday language what the numeric value of the
car washing inefficiency index tells you about each team.
(Hint: Think about what the number means if the team has only 1 person, or,
alternatively, what would it take to wash a car in 1 minute?)
Answers
Find the magnitude of u × v and the unit vector parrallel to u × v in the direction of u × v. u = 2i + 2j - k, v = -i + k
Answers
Answer:
magnitude = 3
unit vector = \(\frac{2i}{3} - \frac{j}{3} - \frac{2k}{3}\)
Explanation:
Given vectors:
u = 2i + 2j - k
v = -i + k = -i + 0j + k
(a) u x v is the cross product of u and v, and is given by;
\(u X v = \left[\begin{array}{ccc}i&j&k\\2&2&-1\\-1&0&1\end{array}\right]\)
u x v = i(2+0) - j(2 - 1) + k(0 - 2)
u x v = 2i - j - 2k
Now the magnitude of u x v is calculated as follows:
| u x v | = \(\sqrt{2^2 + (-1)^2 + (-2)^2}\)
| u x v | = \(\sqrt{4 + 1 + 4}\)
| u x v | = \(\sqrt{9}\)
| u x v | = 3
Therefore, the magnitude of u x v is 3
(b) The unit vector û parallel to u x v in the direction of u x v is given by the ratio of u x v and the magnitude of u x v. i.e
û = \(\frac{u X v}{|u X v|}\)
u x v = 2i - j - 2k [calculated in (a) above]
|u x v| = 3 [calculated in (a) above]
∴ û = \(\frac{2i - j - 2k}{3}\)
∴ û = \(\frac{2i}{3} - \frac{j}{3} - \frac{2k}{3}\)
2 point
A circuit has a current of 3.6 A and a resistance of 5.0 2. What is the
voltage applied to the circuit?
Answers
Answer:
Explanation:
Comment
The voltage is governed by Ohm's Law which is E = I * R
Givens
I = 3.6 amperes
R = 5.0 ohms
E = ?
Solution
E = I * R
E = 3.6 * 5
E = 18
Answer: Voltage = 18 Volts.
⦁ A 18 kg rock starting from rest free falls through a distance of 7.0 m with no air resistance. Find the momentum change of the rock caused by its fall and the resulting change in the magnitude of earth’s velocity. Earth’s mass is 6.0 × 1024 kg. Show all your work, assuming the rock-earth system is closed.
Answers
Answer:
First, we can find the velocity of the rock just before it hits the ground using the equation:
v^2 = 2gh
where v is the final velocity, g is the acceleration due to gravity (9.81 m/s^2), and h is the height the rock falls from (7.0 m).
v^2 = 2(9.81 m/s^2)(7.0 m) = 136.89 m^2/s^2
v = √136.89 m^2/s^2 = 11.7 m/s
The momentum change of the rock caused by its fall is:
Δp = mv = (18 kg)(11.7 m/s) = 211.2 kg m/s
The resulting change in the magnitude of earth's velocity can be found using the conservation of momentum equation:
m1v1 + m2v2 = (m1 + m2)v'
where m1 and v1 are the mass and velocity of the rock before it falls, m2 and v2 are the mass and velocity of the earth before the rock falls (which we can assume is negligible), and v' is the velocity of the rock-earth system after the rock falls.
We can rearrange this equation to solve for v':
v' = (m1v1)/(m1 + m2)
v' = (18 kg)(11.7 m/s)/(18 kg + 6.0 × 10^24 kg)
v' = 1.95 × 10^-24 m/s
This means that the change in the magnitude of earth's velocity is essentially zero (which makes sense, since the mass of the earth is so much greater than the mass of the rock).
The momentum change of the rock caused by its fall is 211.2 kg·m/s, and the resulting change in the magnitude of earth’s velocity is 3.5 × 10⁻²³ m/s.
What is Momentum?
Momentum is a physics concept that describes the amount of motion an object has. The units of momentum are kg m/s. In a closed system, the total momentum before an event or interaction is equal to the total momentum after the event or interaction.
To solve this problem, we need to use the law of conservation of momentum, which states that the momentum of an isolated system remains constant.
The momentum change of the rock is given by the formula:
Δp = mv
where m is the mass of the rock, and v is the change in velocity.
First, we need to find the final velocity of the rock. We can use the formula for the velocity of a falling object:
v² = 2gh
where g is the acceleration due to gravity, and h is the height of the fall.
Plugging in the given values, we get:
v² = 2 × 9.8 m/s² × 7.0 m
v² = 137.2
v = √137.2
v = 11.7 m/s
The change in the magnitude of Earth's Velocity can be found using the formula:
Δv = Δp / M
where M is the mass of the earth.
The mass of the earth is given as 6.0 × 10²⁴ kg.
Δp = mΔv
Δp = 18 kg × 11.7 m/s
Δp = 211.2 kg·m/s
Δv = Δp / M
Δv = 211.2 kg·m/s / 6.0 × 10²⁴ kg
Δv = 3.5 × 10⁻²³ m/s
Therefore, the momentum change of the rock caused by its fall is 211.2 kg·m/s, and the resulting change in the magnitude of earth’s velocity is 3.5 × 10⁻²³ m/s.
Learn more about Momentum from given link
https://brainly.com/question/1042017
#SPJ1