Predict how the total pressure varies during the gas-phase reaction 2 ICl(g)+H2 (g)→I 2 (g)+2 HCl(g) in a constant-volume container.

Answers

Answer 1

Answer:

Explanation:

First thing we should note, is remember Avogadro's law, which states that "equal no of moles of gas occupy equal volume". And thus, the number of moles on both the sides of above are the same, this means that the number of particles that are colliding with wall due to which pressure will be present. Also, if the number of moles are the same, which they are, then the pressure will also be the same.

The Initial number of moles is(see first attachment), without ammonia.

At a point in the reaction, α is the amount or number of N2 that has reacted. Therefore, the total number of gas moles is get by is(see second attachment)

The first two terms represents a change in number of moles of reactant while the last one stands for the number of ammonia produced.

Predict How The Total Pressure Varies During The Gas-phase Reaction 2 ICl(g)+H2 (g)I 2 (g)+2 HCl(g) In
Predict How The Total Pressure Varies During The Gas-phase Reaction 2 ICl(g)+H2 (g)I 2 (g)+2 HCl(g) In

Related Questions

The coefficient of static friction between a rubber tire and dry pavement is about 0.800. Assume that a car’s engine only turns the two rear wheels and that the weight of the car is uniformly distributed over all four wheels.

What limit does the coefficient of static friction place on the time min required for a car to accelerate from rest to 60.0 mph (26.8 m/s)?

Answers

The coefficient of static friction places a limit of approximately 3.42 seconds on the minimum time required for the car to accelerate from rest to 60.0 mph (26.8 m/s).

To find the limit that the coefficient of static friction places on the minimum time required for a car to accelerate from rest to 60.0 mph (26.8 m/s), we need to consider the maximum acceleration the car can achieve due to the friction between the rear tires and the pavement.

The maximum acceleration can be determined using the formula:

a_max = μs * g

where μs is the coefficient of static friction and g is the acceleration due to gravity (approximately 9.8 m/s²).

In this case, since the car's engine only turns the two rear wheels, the maximum acceleration is limited by the friction force between the rear tires and the pavement.

Now, to calculate the minimum time required to accelerate to 60.0 mph (26.8 m/s), we can use the following kinematic equation:

v = u + a * t

where v is the final velocity (26.8 m/s), u is the initial velocity (0 m/s), a is the acceleration, and t is the time.

Rearranging the equation, we have:

t = (v - u) / a

Plugging in the values, we get:

t = (26.8 m/s - 0 m/s) / a_max

t = 26.8 m/s / (μs * g)

Substituting the given value for the coefficient of static friction (μs ≈ 0.800) and the acceleration due to gravity (g ≈ 9.8 m/s²), we can solve for the minimum time required:

t = 26.8 m/s / (0.800 * 9.8 m/s²)

t ≈ 3.42 seconds

Therefore, the coefficient of static friction places a limit of approximately 3.42 seconds on the minimum time required for the car to accelerate from rest to 60.0 mph (26.8 m/s).

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A playground merry-go-round has a mass of 120 kg and a radius of 1.80 m and it is rotating with an angular velocity of 0.400 rev/s. What is its angular velocity (in rev/s) after a 22.0 kg child gets onto it by grabbing its outer edge

Answers

Answer:

The final angular velocity is rev/s is 0.293 rev/s.

Explanation:

Given;

mass of the merry-go-round, m₁ = 120 kg

radius of the merry-go-round, r = 1.8 m

initial angular velocity, ω = 0.4 rev/s

mass of the child, m₂ = 22 kg

Apply the principle of conservation angular momentum to determine the final angular velocity;

\(I_i= I_f\\\\\frac{1}{2} m_1r^2 \omega _i = \frac{1}{2} m_1r^2 \omega _f + m_2r^2 \omega _f\\\\ \frac{1}{2} m_1r^2 \omega _i =( \frac{1}{2} m_1r^2 + m_2r^2 )\omega _f\\\\\omega _f = \frac{ \frac{1}{2} m_1r^2 \omega _i}{\frac{1}{2} m_1r^2 + m_2r^2} \\\\\omega _f = \frac{ \frac{1}{2} m_1 \omega _i}{\frac{1}{2} m_1 + m_2}\\\\\omega _f = \frac{0.5 \ \times \ 120\ kg \ \times \ 0.4\ rev/s}{0.5 \ \times 120\ kg \ \ + \ \ 22 \ kg} \\\\\omega _f = 0.293 \ rev/s\\\)

Therefore, the final angular velocity is rev/s is 0.293 rev/s.

You stand near the edge of a swimming pooland observe through the water an object lying on the bottom of thepool. Which of the following statements correctly describes whatyou see?
a. The apparent depth of the object is less than thereal depth.
b. The apparent depth of the object is greater thanthe real depth.
c. There is no difference between the apparent depth and the actual depth of the object.

Answers

Answer:

a

Explanation:

The correct answer would be that the apparent depth of the object is less than the real depth.

The refractive property of light as it passes from air to water would make the depth of the pool appear less shallow than the actual depth to an observed. Hence, an object placed at the bottom of the pool will have an apparent depth that is shallower than its actual depth.

Due to the difference in the density of air and that of water, as the ray of light from an observer standing at the edge of a swimming pool travels from air into the water, it becomes refracted by bending away from the original traveling angle.

The same refraction occurs when light rays from an object inside the pool travel from water into the air. Hence, due to the refraction of the ray of light coming from the object at the bottom of the pool, the depth appears shallower than the actual depth.

Correct option: a

Write a paragraph about the cartoon. Tell what he is trying to do. Will it work and why? What do you think will happen? Use the following words, static electricity, lightning, electrons, positive and negative charges.

Write a paragraph about the cartoon. Tell what he is trying to do. Will it work and why? What do you

Answers

Answer:

They are trying to jump-start a car using a kite and lightning connected to the battery. This will not work because there is no positive or negative charged side to the circuit.

Explanation:

How does the Doppler effect explain why a siren's pitch increases as it approaches you?
A. The siren moves away from sound waves it has already produced, increasing their wavelength.
B. The siren moves closer to sound waves it has already produced) decreasing their wavelength
C. The siren moves away from sound waves it has already produced decreasing their wavelength,
D. The siren moves closer to sound waves it has already produced, increasing their wavelength​

Answers

Answer:a

Explanation:I just took the quiz and got it right lol

The Doppler effect explains why a siren's pitch increases as it approaches you as it infers that the siren moves away from sound waves it has already produced, increasing its wavelength. This is further explained below.

What is Doppler effect?

Generally, The Doppler effect is simply the apparent variation between the frequency via which waves leave an origin and how they reach an observer.

In conclusion,  increasing its wavelength is the wave property that causes the effect.

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Object A attracts object B with a gravitational force of 10 newtons from a given distance. If the distance between the two objects is doubled, what is
the new force of attraction between them?
OA 2.5 newtons
B.
OC.
D.
5 newtons
20 newtons
100 newtons

Answers

Given that the original force is 10 newtons, the new force when the distance is doubled would be 2.5 newtons. Option A

What does Newton's law say?

Based on Newton's law of  gravitation, the force of gravity between two objects is inversely proportional to the square of the distance between them.

What this means is that if the distance between two objects is doubled, the force of gravity between them is reduced by a factor of four.

In this case, the distance between the two objects is doubled, so the force of gravity between them is reduced from 10 newtons to 2.5 newtons.

We can calculate it by saying 10 N / 4 = 2.5 N.

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Answer: A.

2.5 newtons

Explanation: edmentum

Object A attracts object B with a gravitational force of 10 newtons from a given distance. If the distance

Which type of force is used by your legs to pedal a bicycle?

Answers

Answer:

kinetic energy

Explanation:

2. Which process is used by plants to cycle water from the ground, through the roots, and out the leaves as water vapor?
sublimation
O perspiration
O transpiration
O runoff

Answers

Answer:

The answer is transpiration

Perspiration is the answer

Can someone please solve these 6 questions and explain briefly? I really do not understand them. Thank you

Can someone please solve these 6 questions and explain briefly? I really do not understand them. Thank
Can someone please solve these 6 questions and explain briefly? I really do not understand them. Thank

Answers

Explanation:

Use SOH-CAH-TOA.

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tangent = Opposite / Adjacent

For example, in 2(a), we are given an angle and the hypotenuse.  We want to find the side adjacent to the angle.  Therefore, we should use cosine.

cos 58° = y / 32.3

y = 32.3 cos 58°

y ≈ 17.1

In 3(a), we are given the adjacent side and opposite side.  We want to find the angle.  So use tangent.

tan θ = 3.6 / 6.2

θ = tan⁻¹(3.6/6.2)

θ = 30.1°

In 4(a), we are given an angle and the hypotenuse.  We want to find the side opposite of the angle.  Therefore, we should use sine.

sin 47° = x / 29

x = 29 sin 47°

x ≈ 21.2

New evidence increasingly emphasizes that __________.

Answers

Penissssssssssssssssssssssssssssssssssssssssssssssssss

which toy car had the greatest applied force?

Answers

what are the choices

Answer:

d

Explanation:

If a balloon with a weight of 3000 N (306kg) is lifted by an air force of 3300 N, in what will be its acceleration?

Answers

Answer:

See below

Explanation:

F = ma       net force is 300 N upward

300 = 306  * a         a = .980 m/s^2

what is the angle between 3i-2j-3k and the negative x axis

Answers

Answer:

Um its the vbuck card on the 3 thrid level

Explanation:

Bc its a vbuck card you know sihdg;aig

a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!​

Answers

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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A woman stands still holding a 350 Newton bag (about 80 pounds) 2 meters off the ground. How much work does the woman do?

Answers

Answer:

700 Joules

Explanation:

What we know:

Force = 350 Newton

Distance = 2 meters

Work = ?

The formula for work is:

Work = force x distance

Plugging values into equation:

Work = 350 Newtons x 2 meters

Work = 700 Joules

I had the same question on the homework assignment with the answers provided:

a) It depends on how long she holds the bag

b) 350 Joules

c) none

d) 350 Newtons

The final answer would be c) none. The work done is 700 Joules. Hope this helps!

6. A picture of weight, w is hanging from a steel nail as shown in the figure below. The nail has a diameter of 1.50 mm and an original length, Lo = 5.0 mm. Useful Information: The shear modulus, G for steel is 80 x 10° N.m². (a) (b) (c) 1.50 mm 3 Ax = 1.80 μm W Lo = 5.00 mm M What kind of deformation occurs in this case? How are stress and strain in this deformation related to each other? [3] When the picture is hung from the nail, the head of the nail displaces vertically downwards by an amount Ax = 1.80 µm. Find the mass of the picture. Neglect the weight of the nail. [6] What angle does the nail make with the horizontal after the picture is hung from it? [2]​

Answers

The mass of the picture is approximately 5.19 kilograms.

How to solve for the problem

The deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).

The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:

τ = G * γ

To find the weight of the picture, we need to calculate the shear stress first:

The cross-sectional area A of the nail is given by the formula for the area of a circle:

A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².

The shear strain γ is given by:

γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.

The shear stress τ can now be calculated by rearranging the formula:

τ = G * γ

=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²

The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:

τ = F / A

=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.

Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:

m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.

So, the mass of the picture is approximately 5.19 kilograms.

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Problem
THE FLIGHT OF A BALL A ball is launched at 5.5 m/s at 76° above
the horizontal. It starts and lands at the same distance from the
ground. What are the maximum height above its launch level and the
flight time of the ball?

Answers

1. The maximum height above its launch level is 1.45 m

2. The time of flight of the ball is 1.1 s

1. How do I determine the maximum height?

From the question given above, the following data were obtained:

Initial velocity (u) = 5.5 m/sAngle of projection (θ) = 76 °Acceleration due to gravity (g) = 9.8 m/s²Maximum height (H) =?

The maximum height can be obatianed as follow:

H = u²Sine²θ / 2g

H = [5.5² × (Sine 76)²] / (2 × 9.8)

Maximum height = 1.45 m

How do I determine the time of flight?

The time of flight of the ball can be obtained as follow:

Initial velocity (u) = 5.5 m/sAngle of projection (θ) = 76 °Acceleration due to gravity (g) = 9.8 m/s²Time of flight (T) = ?

T = 2uSineθ / g

T = [2 × 5.5 × Sine 76] / 9.8

Time of flight = 1.1 s

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which theory says dreaming is an unimportant by-product of neural firing during sleep

A. latent content theory
B. activation-synthesis
C. Freudian theory
D. information- processing

Answers

Answer:

B. Activation-Synthesis

Explanation:

Apex

Determine the type of reaction (S, D, SD, or DD) and balance the chemical equation. (Hint: Please place a coefficient of 1 in front of any formula
that does not need its atoms to increase.)
Type of reaction
НІ
--
H2
+
12
Blank 1: 1
Blank 2:
Blank 3:
Blank 4:​

Answers

Answer and Explanation: The types of reaction represented in the question are the following: S is Synthesis; D is Decomposition; SD is Single Displacement; and DD is Double Displacement.

The reaction showed is: HI ⇄ H₂ + I₂

This reaction's type is Decomposition, because it is a reaction in which a compund breaks down into 2 or more simpler compounds. Most of them requires energy that could be in form of heat, light or electricity.

To balance a chemical equation, remember that, according to the Conservation of Mass Law, matter can not be created or destroyed just transformed. Then, the amount of reagents that enters the reaction has to be same amount that reacts to become the products, i.e.:

For the decomposition reaction, there are 2 atoms of hydrogen and 2 atoms of iodine being produced while only 1 atom of each element enters the reaction.

The balanced reaction will be: 2HI ⇄ H₂ + I₂

How much force is needed to accelerate an object of mass 90 kg at a rate of 1.2 m/s²

Answers

Answer:

108 N

Explanation:

Use Newton's second law.

F = ma

F = (90 kg) (1.2 m/s²)

F = 108 N

in the circuit at right, the bulbs are identical, and the battery is ideal. rank the brightness of the bulbs in the ircuit at right

Answers

Brightest resistor is the one with the most current. The current via bulb C is the highest since it receives the same amount of current as the battery.

What is an example of a resistor?

Digital potentiometers and rheostats are variable resistors. Electrical parts called rheostats are constructed from resistive thin wire around for a ceramic core. They were once employed to regulate the quantity of power utilized by ovens, heaters, and motors.

How do resistors function?

By decreasing the voltage and obstructing the passage of electricity, the resistance absorbs the electrical energy, which is then released as heat. The heat dissipation in electronic circuits today is typically a few hundredths of a watt.

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Kindly Answer

Physics​

Kindly AnswerPhysics

Answers

Answer:

1. d 2. a 3. a 4. a 5. a

Explanation:

Sorry if this is wrong

How have humans
changed the area and how might this affect recovery after the flood?

Answers

Answer:

Explanation:

Loss of lives and property: Immediate impacts of flooding include loss of human life, damage to property, destruction of crops, loss of livestock, non-functioning of infrastructure facilities and deterioration of health condition owing to waterborne diseases. Flash floods, with little or no warning time, cause more deaths than slow-rising riverine floods.

Loss of livelihoods: As communication links and infrastructure such as power plants, roads and bridges are damaged and disrupted, economic activities come to a standstill, resulting in dislocation and the dysfunction of normal life for a period much beyond the duration of the flooding. Similarly, the direct effect on production assets, be it in agriculture or industry, can inhibit regularly activity and lead to loss of livelihoods. The spill over effects of the loss of livelihoods can be felt in business and commercial activities even in adjacent non-flooded areas.

Decreased purchasing and production power: Damage to infrastructure also causes long-term impacts, such as disruptions to clean water and electricity, transport, communication, education and health care. Loss of livelihoods, reduction in purchasing power and loss of land value in the flood plains lead to increased vulnerabilities of ties living in the area. The additional cost of rehabilitation, relocation of people and removal of property from flood-affected areas can divert the capital required for maintaining production.

Mass migration: Frequent flooding, resulting in loss of livelihoods, production and other prolonged economic impacts and types of suffering can trigger mass migration or population displacement. Migration to developed urban areas contributes to the overcrowding in the cities. These migrants swell the ranks of the urban poor and end up living in marginal lands in cities that are prone to floods or other risks. Selective out-migration of the workforce sometimes creates complex social problems.

Psychosocial effects: The huge psycho-social effects on flood victims and their families can traumatize them for long periods of time. The loss of loved ones can generate deep impacts, especially on children. Displacement from one’s home, loss of property and livelihoods and disruption to business and social affairs can cause continuing stress. The stress of overcoming these losses can be overwhelming and produce lasting psychological impacts.

Hindering economic growth and development: The high cost of relief and recovery may adversely impact investment in infrastructure and other development activities in the area and in certain cases may cripple the frail economy of the region. Recurrent flooding in a region may discourage long-term investments by the government and private sector alike. Lack of livelihoods, combined with migration of skilled labour and inflation may have a negative impact on a region’s economic growth. Loss of resources can lead to high costs of goods and services, delaying its development programmes.

Political implications: Ineffective response to relief operations during major flood events may lead to public discontent or loss of trust in the authorities or the state and national governments. Lack of development in flood-prone areas may cause social inequity and even social unrest posing threat to peace and stability in the region.

A box of mass m is pushed up a frictionless ramp. The ramp has an angle 0 .

What is the acceleration ?

A box of mass m is pushed up a frictionless ramp. The ramp has an angle 0 .What is the acceleration ?

Answers

Answer: C

Explanation: khan academy

A box of mass m is pushed on a frictionless ramp. The ramp has an angle θ.

What is the acceleration?

Answer: -F/m + g sin θ

Clothes dryer spins to angular speed 7.2 rad/s starting from angular speed 0 rad/s
Average angular acceleration is 1.88rad/s^2
Takes dryer 3.82 s to reach 7.2 rad/s
How many revolutions does the dryer make during this time

Answers

Answer:

Explanation:

initial angular speed ω₀ = 0

final angular speed = ω

time = t

angular acceleration α = 1.88 rad /s ² , θ = angle of rotation in radian

ω² = ω₀² +2 α θ

7.2² = 0 + 2 x 1.88 x  θ

θ = 13.79 rad

let n be no of rotation

2πn = 13.79

2 x 3.14 x n = 13.79

n = 2.2

A disrupted circuit in which the current bypasses its proper path is a(n) ________ circuit.

Answers

Answer:

short circuit

Explanation:

A disrupted circuit in which the current bypasses its proper path is a short circuit.

What is a Short circuit?

A short circuit is an electrical circuit which allows the electric current to travel along an unintended and uninterrupted path with no or very low electrical impedance in the circuit. This results in an excessive current flow through the electric circuit.

A short circuit is a situation in which there is  faulty connection or damaged wire that causes electric current to travel along the wrong route in the circuit with low or no resistance and damage an electrical device. This may cause serious damage, fire, or even small-scale explosions.

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Match the following wave to the correct wave type. **You may use some answers more than once and some not at all*

Match the following wave to the correct wave type. **You may use some answers more than once and some

Answers

The following are the correct matches for the waves in Column A and the wave types in Column B:

A - d. mechanical wave - longitudinalB - b. electromagnetic waveC - a. mechanical wave - transverseD - e. spring wave

What are the wave types?

A mechanical wave is a wave that requires a medium to travel through. The two types of mechanical waves are transverse waves and longitudinal waves. A transverse wave is a wave in which the particles of the medium move perpendicular to the direction of the wave. A longitudinal wave is a wave in which the particles of the medium move parallel to the direction of the wave.

An electromagnetic wave is a wave that does not require a medium to travel through. Electromagnetic waves are made up of electric and magnetic fields that oscillate perpendicular to each other.

A matter wave is a wave that describes the probability of finding a particle at a given location. Matter waves are associated with all particles, including electrons, protons, and neutrons.

A spring wave is a type of mechanical wave that travels through a spring. The particles of the spring move back and forth along the length of the spring.

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A 80 Kg monkey climbs a 15 meter tree in half a minute. What is the magnitude of power the monkey demonstrated?
a. 13.1 J/S
b. 392 J/S
c. 784 J/s
d. 11760 J/s​

Answers

Answer:

Power = Work / Time

P = m g h / t = 80 kg * 9.8 m/s^2 * 15 m / 39 s = 320 N m/ s = 392 J / s

= 392 Watts

The magnitude of power the monkey demonstrated is equal to 392 J/S.

Power calculation

To measure the power of a given body, one must relate its weight, the displacement performed and the time in which the movement was performed, in such a way:

                                              \(P = \frac{m\times g\times d}{t}\)

Thus, applying the values ​​given by the statement we have:

                                          \(P = \frac{80 \times 9.8 \times 15}{30}\)

                                           \(P = 392 J/s\)

So, the power performed by the monkey climbing 15 meters is equal to 392J/s.

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Explan the advantage of accuracy​

Answers

Answer:

Reduction of order delivery times.

More efficient order fulfilment.

Lower number of incomplete orders.

Improved service in emergency situations.

Reduction of errors in the composition of orders and deliveries.

Better management of internal quality levels.

Greater flexibility (wider range of services on offer to the client)

Explanation:

Accuracy benefits
Reduction of order delivery times.
More efficient order fulfilment.
Lower number of incomplete orders.
Improved service in emergency situations.
Reduction of errors in the composition of orders and deliveries.
Better management of internal quality levels.
Greater flexibility (wider range of services on offer to the client)

A long jumper with a speed of 120m/s at an angle of 30 degrees with respect to the horizontal. how far did he land in the sand from his jump spot?

Answers

Given data:

* The initial velocity of the jumper is,

\(u=120ms^{-1}\)

* The angle between the initial velocity and the horizontal line is,

\(\theta=30^{\circ}\)

Solution:

The horizontal range of the projectile motion by the jumper is,

\(H=\frac{u^2\sin (2\theta)}{g}\)

where g is the accleration due to gravity, and H is the horizontal range.

Substituting the known values,

\(\begin{gathered} H=\frac{120^2\times\sin (2\times30^{\circ})}{9.8} \\ H=1272.53\text{ m} \end{gathered}\)

Thus, the distance of the jump from its spot is 1272.53 m.

Other Questions
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