Potential energy can be described as situations?

Answers

Answer 1
Potential energy is the energy of an object stored when it is kept from a high distance

Related Questions

ASAP DUE TO DAY PLS HELP MEEEEEE

1. Kinetic energy is the energy of:
A. potential
B. objects at rest
C. objects in motion
D. accelerating objects
--------------------------------------------------------------------------------------------

Answers

i believe it is c, objects in motion. i apologize i’m im wrong.

John recently suffered a gunshot wound to the abdomen and has undergone surgery. He is 37 years old, 6’ 0”, and weighs 200 lbs. John is currently on a medical ventilator to help him breathe.

1. Describe the metabolic response to injury (ebb phase and flow phase

Answers

Answer:

The flow phase is the "all or nothing" phase. it is trying to prevent bleeding and infection. It is compensating for the trauma and volume replacement.

Explanation:

hope it helps ;-;

What is the momentum of a 3 kg bowling ball moving at 3 m/s?
.
O 1 kg. m/s
O 3 kg. m/s
O 6 kg. m/s
O 9 kg • m/s

Answers

Explanation:

p = mv

p denotes momentumm denotes massv denotes velocity

→ p = 3 kg × 3 m/s

p = 9 kg.m/s

Option D is correct.

Which term is most applicable to a discussion of angular momentum in the context of black holes?
A. photon
B. curvature
C. spin
D. time

Answers

Answer:

Curvature

Explanation:

energy saving can be known as energy production.​

Answers

Saved energy is generated energy We can not continue to produce resources including gas, diesel and electricity which are not sustainable

To demonstrate the ideas of electric current and resistivity the following experiment was conducted using a 10.0 m long 1.00 m diameter pipe. The pipe is connected to an air pump which produces high air pressure at one end. The other end of the pipe is open to the surrounding air, and the pump maintains a constant difference in air pressure between the two ends. Six hundred electrically charged ping pong balls are injected into the pipe with velocities that have random magnitudes and directions. Due to the difference in air pressure, the balls drift from the high pressure end of the pipe to the low pressure end at a speed of 2.00 cm/s. What quantity in this demonstration is analogous to electric potential in a wire connected to a battery

Answers

The air pressure is analogous to electric potential in a wire connected to a battery.

This is because an electric potential difference causes charges to move from a point of higher electric potential to point of lower electric potential.

Similarly, since the six hundred electrically charged ping pong balls move from a point in which the air pressure is higher to a point in which the air pressure is lower, this is due to the difference in pressure between the two points.

So, the air pressure is analogous to the electric potential in a wire connected to a battery.

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Suppose a bar magnet is oriented horizontally with its north end to the right and its south end to the leftAt which of the following locations does the magnetic field NOT point to the right ? (1 point )

A.in the center of the magnet between the two poles
B.Directly above the center of the magnet
C.to the right of the north pole
D.to the left of the South Pole

Answers

Answer:

B. Directly above the center of the magnet.

Explanation:

The magnetic field lines of a bar magnet emerge from the magnet's north pole and re-enter the magnet at the south pole. Therefore, the magnetic field lines point from north to south within the magnet. Based on this, we can determine that:

A. In the center of the magnet between the two poles, the magnetic field lines point from north to south and are therefore not pointing to the right.

B. Directly above the center of the magnet, the magnetic field lines point downward and to the south, so they are not pointing to the right.

C. To the right of the north pole, the magnetic field lines point to the right.

D. To the left of the south pole, the magnetic field lines also point to the right.

Therefore, the location where the magnetic field does NOT point to the right is B, directly above the center of the magnet.

A physics book slides off a horizontal tabletop with a speed
of 1.10 m/s. It strikes the floor in 0.480 s. Ignore air resistance.
What is the height of the tabletop above the floor in meters.

Answers

A physics book slides off a horizontal tabletop with a speed of 1.10 m/s. It strikes the floor in 0.480 s. The height of the tabletop above the floor is 0.264 m.

Given data:

Speed = 1.10 m/s

Time taken to strike the floor = 0.480 s

We are supposed to find the height of the tabletop above the floor in meters.

We can use the formula of distance to calculate the height of the tabletop above the floor.

We also need to make use of kinematic equations to find out the distance fallen by the book.

Let us first calculate the distance fallen by the book.

Let the height of the table be ‘h’.

From the kinematic equations of motion, we know thats = ut + 1/2 at²Here, u = 1.10 m/s, a = acceleration due to gravity = 9.8 m/s², t = 0.480 s

Putting these values in the above equation, we get:s = 1.10 × 0.480 + 1/2 × 9.8 × (0.480)² = 0.264 m

Now, we can find the height of the tabletop using the formula of distance.d = h + sHere, d = distance fallen by the book = h, s = 0.264 m

Putting these values in the above equation, we get: h = d = s = 0.264 m

Therefore, the height of the tabletop above the floor is 0.264 m.

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Perform an experiment in which you flip a switch 2,300,000 times. Write this
number in scientific notation.
O A. 23 x 10-6
O B. 2.3 x 106
O C. 0.23 x 105
O D. 0.23 x 106

Answers

Answer:

B. 2.3 x 10⁶

Explanation:

To calculate scientific notation for the number 2,300,000, we have to follow this notation

a × 10^b

Step 1 :

To find a we have to write the non-zero digits placing a decimal after the first non-zero digit.

2,300,000 to 2.300000

Step 2 :

Now, to find b count how many numbers of digits are there to the right of the decimal.

2.300000

Hence, there are 6 digits to the right of the decimal.

Step 3 :

Since, we had found the value of a and b, we can now reconstruct the number into scientific notation.

a = 2.3

b = 6

2.3 × 10

Therefore, option b is correct.

By flowing back across the membrane, protons (H+) seek to
find electrons they can combine with
become antiprotons (H-)
equalize their concentration of both sides of the membrane
transfer their energy to other protons

Answers

By flowing back across the membrane, protons (H+) seek to equalize their concentration of both sides of the membrane.

The third option is correct.

What is the process called?

The  process by which Protons (H+) flowing back across a membrane seek to equalize their concentration on both sides of the membrane is known as proton gradient equilibration or proton motive force equilibration.

During cellular respiration, protons are pumped across a membrane to create a gradient. This gradient is then used to generate ATP, the energy currency of the cell. Protons flow back across the membrane through a channel called ATP synthase, which generates ATP as the protons flow through it.

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A transformer has a primary coil with 400 turns of wire and a secondary coil with 1,600 turns. An AC generator connected across the primary coil has a voltage given by the function Δv = (180 V)sin(t).
What rms voltage (in V) is measured across the secondary coil?

Answers

The voltage across the secondary coil is related to the voltage across the primary coil by the turns ratio of the transformer. The turns ratio is defined as the ratio of the number of turns in the secondary coil to the number of turns in the primary coil. In this case, the turns ratio is 1600 turns / 400 turns = 4.

The rms voltage across the secondary coil is given by the following formula:

V_secondary_rms = V_primary_rms * turns ratio

where V_primary_rms is the rms voltage across the primary coil.

The rms voltage across the primary coil is given by the following formula:

V_primary_rms = Δv / (2^0.5) = Δv / 1.41

where Δv is the peak voltage of the AC generator.

Substituting Δv = 180 V and evaluating the above formula, we get:

V_primary_rms = 180 V / 1.41 = 127.46 V

Substituting the value of V_primary_rms into the equation for the secondary coil, we get:

V_secondary_rms = 127.46 V * 4 = 509.84 V

So, the rms voltage measured across the secondary coil is 509.84 V.

You do 32 joules of work using a pair of scissors. The scissors do 25 joules of
work cutting a piece of fabric. What is the efficiency of the scissors?

Answers

Answer:

Efficiency = 65%

Explanation:

The formula of Efficiency applied to any circumstance is:

Efficiency = Useful Energy / Energy applied

Then replacing the values given its:

Efficiency = 25 J / 32 J

Efficiency = 0.65

0.65 written as percentage is 65%, then:

Efficiency = 65%

As you do 32 joules of work using a pair of scissors and the scissors do 25 joules of work cutting a piece of fabric, the efficiency of the scissors is 78.125%.

What is efficiency?

Efficiency is the proportion of work done by a machine or throughout a process to the overall amount of energy or heat used.

The ratio of usable output to total input can be used to objectively measure efficiency. The efficiency of the device is defined as the ratio of energy converted to a useable form to the original amount of energy supplied.

Mathematically,

efficiency of a machine = (work output/work input)×100%

Given parameters:

Input work to the pair of scissors= 32 joules.

Output work from the pair of scissors= 25 joules.

Hence,

The efficiency of a machine = (work output/work input)×100%

= ( 25 joule/32joule)×100%

= 78.125%

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2. The following diagram shows a metal ball and ring apparatus. The ring and ball are both made of brass. At room temperature, the ball is just the right size to pass through the ring. When the ball is heated, it is unable to pass through the ring. Which of the following is NOT true? A The volume of the ball increased. B The mass of the ball increased. C. The speed at which the particles move increased. D The spaces between the particles increased. Not True

Answers

The statement that is NOT true is "the spaces between the particles increased.

option D.

What is effect of temperature on volume?

If we consider the solids and liquids, when the temperature increases the molecules gain energy and start moving in all directions. This expands the substance and the volume of the substance increases.

Similar, when the ball is heated, the volume of the ball increases due to thermal expansion.

As the temperature increases, the average kinetic energy of the particles within the ball also increases, causing them to move faster.

However, the spaces between the particles do not necessarily increase. In fact, the expansion of the ball occurs due to the particles themselves moving farther apart, but the intermolecular spacing within the ball remains relatively constant.

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The mass of a moving object appears to be 3.11% greater than its rest mass. What is it speed?

Answers

The apparent mass m is related to the actual mass m_0 by:

\(m=\frac{m_0}{\sqrt{1-\frac{v^2}{c^2}}}\)

Isolate v:

\(v=c\sqrt{1-\left(\frac{m_0}{m}\right)^2}\)

Replace m=1.0311m_0:

\(v=c\sqrt{1-\left(\frac{m_0}{1.0311m_0}\right)^2}=0.24375...c\approx7.3\times10^6\frac{m}{s}\)

Therefore, the speed of the object is approximately 7.3*10^6 m/s.

Hellllllpppppp what happens

Hellllllpppppp what happens

Answers

Answer:

u can write ur answer and submit it

its a test

How does the ionosphere affect radio frequencies

Answers

Answer:

This is what gives the Ionosphere its name and it is the free electrons that cause the reflection and absorption of radio waves. ... The high frequency waves pass through the ionosphere and escape into space while the low frequency waves reflect off the ionosphere and essentially "skip" around the earth.

Explanation:

A radio is rated as 50 W. Calculate the energy transferred in Joules by the radio when it has been switched on for 2 minutes?

Answers

The energy transferred in Joules by the radio when it has been switched on for 2 minutes would be 6000 Joules.

Energy transfer

Power is defined as the rate of energy transfer or the rate at which work is done, and is given by the equation:

Power = Energy transferred / Time

Rearranging the equation to solve for energy transferred, we get:

Energy transferred = Power x Time

We are given:

Power = 50 W

Time = 2 minutes = 120 seconds

Therefore, the energy transferred by the radio when it has been switched on for 2 minutes is:

Energy transferred = Power x Time = 50 W x 120 s = 6000 J

In other words, the energy transferred by the radio is 6000 Joules.

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Differentiate between velocity, acceleration, and deceleration. (I'm getting really desperate) help!!!!!!!!!!!!!!!!!!!!!!

(This is for my cyber physical education, i don't have physics yet but i couldn't find physical education in the pick a subject :/)

Answers

Velocity is the rate of change of displacement with time while acceleration refers to the rate of change of velocity with time.

Deceleration means the amount a speed or velocity decreases.

Velocity = displacement / time

Velocity is measured in m/s ( meters per second)

Acceleration = velocity / time and is measured in m/s2 ( meters per second square )

This also means that velocity differ from acceleration in that they have different unit as velocity is measured in m/s and acceleration is measured in m/s2

What is velocity?

Velocity can simply be defined defined as the rate of change of velocity with time. It is a derived quantity. That is, a quantity which is obtained from the combination of one or more fundamental quantities. The units of derived quantities are called derived units.

So therefore, velocity is the rate of change of displacement with time while acceleration refers to the rate of change of velocity with time. Deceleration means the amount a speed or velocity decreases.

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what is the potential energy the greatest in a roller coaster​

Answers

Answer:

Gravitational potential energy is the greatest

Explanation

It is the highest point of a roller coaster.

What energy store is in the human
BEFORE he/she lifts the hammer?​

Answers

I believe the answer would be protentional because they have the potential energy in them to lift the hammer.

Answer #49 please and thank you

Answer #49 please and thank you

Answers

when Force (N) is 10.0 Length (m) is 0.60

when Force (N) is 8.0 Length (m) is 0.40

when Force (N) is 4.0 Length (m) is 0.20

when Force (N) is 4.0 Length (m) is 0.20

when Force (N) is 2.0 Length (m) is 0.10

chatgpt

49. To find the length of a pendulum that has a period of 2.3 seconds on the Moon, where the gravitational acceleration (g) is 1.6 N/kg, we can use the formula:

Period (T) = 2π√(Length (L) / g)

Substituting the given values:

2.3 = 2π√(L / 1.6)

To solve for L, we can rearrange the formula:

L = (2.3 / (2π))^2 * 1.6

L ≈ 0.781 meters (or 78.1 centimeters)

So, the pendulum must be approximately 0.781 meters (or 78.1 centimeters) long to have a period of 2.3 seconds on the Moon.

50. Ranking Task:

To rank the pendulums according to their periods, we need to consider both the length and mass of each pendulum.

Ranking from least to greatest period:

1. A: 10 cm long, mass = 0.25 kg

2. C: 20 cm long, mass = 0.25 kg

3. B: 10 cm long, mass = 0.35 kg

There is a tie between pendulums A and C, as they have the same length but different masses.

Question:why do some liquids flow really fast and other flow really slow?does temperature affect the rate of flow?

If the thickness of the liquid affects its flow rate
Then————


Figure out the then part by the question

Answers

Answer:

Some liquids flow really fast and some flow really slow.

Explanation:

This is because of a liquids viscosity , If the liquids viscosity is high it will flow really slow like syrup. But if it has high viscosity it will flow really fast much like water.

Hope this helped!!   :)

A 50gram bracelet is suspected of not being pure gold. It is dropped into a glass of water and 4 cm3of water overflows. Is the bracelet pure gold? How do you know?

Answers

Since, density of the bracelet is not equal to the density of gold, then, the bracelet is not pure gold.

To know if the bracelet is pure gold, we calculate the density of the bracelet and compare it to the density of pure gold (19.3 g/cm³).

That is, for the bracelet to pure gold,

Density of bracelet ≈ 19.3 g/cm³

What is Density?

Density can be defined as the ratio of the mass and the volume of a substance.

The formula of Density is give as

D = m/v................... Equation 1

⇒ Where:

D = Density of the braceletm = mass of the braceletv = volume of the bracelet

From the question,

⇒ Given:

m = 50 gv = 4 cm³ (an object displace an amount of water equal to it's own volume)

⇒ Substitute these values into equation 1

D = 50/4D = 12.5 g/cm³

Hence, since the density of the bracelet is not equal to the density of gold, then, the bracelet is not pure gold.

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Can we pretend that airplanes in the night sky are like shootin' stars
I could really use a wish right now, wish right now, wish right now
Can we pretend that airplanes in the night sky are like shootin' stars
I could really use a wish right now, wish right now, wish right now

Answers

Answer:

Ok

Explanation:

Ggggrvvvvvdssssccccdddhhhh

why did the ball not reach its original height after bouncing once

Answers

huh.... what.... i...

Answer:

it slows down after every bounce

why aeroplanes cannot travel in space

Answers

Answer:

- They need oxygen to burn fuel

- Aerodynamics

- Extreme temperatures

- Radiation

- Pressure issues

Explanation:

A airplane is a heavier-than-air aircraft kept aloft by the upward thrust exerted by the passing air on its fixed wings and driven by propellers, jet propulsion, etc.

Aeroplanes cannot travel in space for several reasons:

They need oxygen to burn fuel - Aeroplane engines rely on the oxygen in the atmosphere to burn fuel and generate thrust. In space, there is no atmosphere so there is no oxygen for the engines to work.

Aerodynamics - Aeroplane wings generate lift by interacting with the air. In space, there is no air so wings would be unable to generate any lift. Aeroplanes rely on aerodynamics to fly which does not work in space.

Extreme temperatures - In space, temperatures can range from -150 degrees Celsius to 150 degrees Celsius. Aeroplanes are designed to operate within a much narrower temperature range. The extreme cold and heat of space could damage aeroplane components.

Radiation - In space, there are high levels of radiation from the Sun and cosmic rays. Aeroplane bodies are not designed to shield against this type of radiation and it could damage electronics and affect aeroplane systems.

Pressure issues - Aeroplanes are designed to withstand air pressures at altitudes up to around 12 kilometers. In low-Earth orbit and beyond, the air pressure is essentially zero. This extreme change in pressure could cause structural damage to the aeroplane.

In summary, while aeroplanes are designed to fly through the Earth's atmosphere, they lack the key features needed to operate in the extreme environment of outer space like spaceships. Aeroplanes require things like oxygen, aerodynamics and being able to withstand changes in pressure - all of which do not exist or work the same way in space.

Explanation:

The wing is pushed up by the air under it. Large planes can only fly as high as about 7.5 miles. The air is too thin above that height. It would not hold the plane up.

A 50-gram sample of water is initially at a temperature of 22 °C. The sample is heated until the temperature is 32 °C The specific heat of water is 1.00 cal/g °C. How much heat is absorbed by the water in calories? Enter your answer without a decimal​

Answers

Answer:

500cal

Explanation:

Given parameters:

Mass of water  = 50g

Initial temperature  = 22°C

Final temperature  = 32°C

Specific heat of water  = 1cal/g

Unknown:

Amount of heat absorbed by the water in calories  = ?

Solution:

To solve this problem, we use the expression below:

       H  = m c Ф

H is the amount of heat absorbed

m is the mass

c is the specific heat capacity

Ф is the temperature change

       H  = 50 x 1 x (32  - 22)  = 500cal

can someone help me pleaseenkwnsn​

can someone help me pleaseenkwnsn

Answers

If a third resistor is added in SERIES, what changes happens to the....

a. Total Voltage - stay the same b. Total Current - decrease c. Total Resistance - increase d. Voltage through resistor 1 - decrease e. Current through resistor 1 - decrease

What happens in a circuit?

When you add a third resistor in series, the total resistance of the circuit increases. This is because the current has to flow through all three resistors, so it has to overcome more resistance. The total voltage across the circuit stays the same, because the voltage of the battery is constant. However, the current decreases, because the same amount of current is now flowing through a larger resistance.

The voltage across each resistor also decreases, because the total voltage is divided among the three resistors. The current through each resistor also decreases, because the same current is now flowing through a larger resistance.

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An object of charge +2.0 x10^-3 C is located at the Cartesian origin, (0m,0m). A second object, of charge -4.0x10^-3 C, is located at a position (50m, 0m). Find the full magnitude and direction of the Electric force present on a test charge of +1C, located at a position (0m, 50m).

Answers

Explanation:

We can represent the situation with the following figure

Therefore, we need to calculate the magnitude of F1 and F2.

The magnitude of electric force between two charges is equal to

\(F=k\frac{q_1q_2}{r^2}\)

Where k = 8.98 x 10^9, q1 and q2 are the charges and r is the distance between the charges. The distance between the object of charge -4 x 10^(-3) C and the object of charge +1C can be calculated using the Pythagorean theorem as

\(\begin{gathered} \text{ Pythagorean Theorem: c=}\sqrt{a^2+b^2} \\ \\ \text{ Replacing a = 50 and b = 50} \\ c=\sqrt{50^2+50^2} \\ c=\sqrt{2500+2500} \\ c=\sqrt{5000} \\ c=70.71\text{ m} \end{gathered}\)

Therefore, the distance between the charges is 70.71 m.

Then, replacing q1 = -4 x 10^(-3) C, q2 = +1C and r = 70.71 m, on the initial equation, we get:

\(\begin{gathered} F1=(8.98\times10^9)\frac{(-4\times10^{-3})(+1)}{70.71^2} \\ \\ F1=7184\text{ N} \end{gathered}\)

To calculate F2, we need to replace q1 = +2 x 10^(-3) C, q2 = +1C, and r = 50 m, so

\(\begin{gathered} F2=(8.98\times10^9)\frac{(2\times10^{-3})(1)}{50^2} \\ \\ F2=7184\text{ N} \end{gathered}\)

Now, we need to calculate the resultant force, so we need to identify the x and y coordinates of each force and add them

\(\begin{gathered} F1x=F1\cos(45)=7184\cos45=5079.86 \\ F1y=F1\sin(45)=7184\sin45=-5079.86 \\ F2x=0 \\ F2y=F2=7184 \\ \\ \text{ Resultant force} \\ Fx=F1x+F2x \\ Fx=5079.86+0=5079.86\text{ N} \\ \\ Fy=F1y+F2y \\ Fy=-5079.86+7184=2104.14\text{ N} \end{gathered}\)

Finally, we can calculate the magnitude and direction of the force as follows

\(\begin{gathered} \text{ magnitude } \\ F=\sqrt{(Fx)^2+(Fy)^2} \\ F=\sqrt{(5079.86)^2+(2104.14)^2} \\ F=5498.40\text{ N} \\ \\ \text{ Direction} \\ \theta=\tan^{-1}(\frac{Fy}{Fx}) \\ \\ \theta=\tan^{-1}(\frac{2104.14}{5079.86}) \\ \\ \theta=\tan^{-1}(0.41) \\ \theta=22.5° \end{gathered}\)

Therefore, the magnitude of the electric force is 5498.40 N and the direction is 22.5 degrees.

An object of charge +2.0 x10^-3 C is located at the Cartesian origin, (0m,0m). A second object, of charge

In a bizarre but harmless accident, a watermelon fell from the top of the Eiffel Tower. How fast was the watermelon traveling when it hit the ground 6.40 seconds after falling?

Answers

Answer:

v = 62.7 m/s

Explanation:

Assuming no air resistance, the only force acting on the watermelon while it was falling, was the one due to the gravity.This means that the object fell down with a constant acceleration which magnitude is equal to 9.8 m/s2.Applying the definition of acceleration, and assuming that the watermelon was dropped, so initial velocity is just zero, we can find the speed when it hit the ground as follows:

        \(v_{f} = a*t = -g*t = -9.8 m/s2*6.4 m/s = -62.7 m/s (1)\)

The watermelon was traveling at a speed of 62.7 m/s when it hit the ground.
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