Point M is the midpoint of the line segment LN. LM=8x+2 and MN=10x-4 solve for x and find the length is segment LM

Answer:

(5, 4)

Step-by-step explanation:

(x + 2, y + 3)

(3  + 2, 1 + 3)

(5, 4)

Answer:

B' (5, 4 )

Step-by-step explanation:

the translation rule (x, y ) → (x + 2, y + 3 )

means add 2 to the original x- coordinate and add 3 to the original y- coordinate , then

B (3, 1 ) → B' (3 + 2, 1 + 3 ) → B' (5, 4 )

2 sin²(x) + 3 sin(x) + 1 = 0

(2 sin(x) + 1) (sin(x) + 1) = 0

2 sin(x) + 1 = 0   OR   sin(x) + 1 = 0

sin(x) = -1/2   OR   sin(x) = -1

The first equation gives two solution sets,

x = sin⁻¹(-1/2) + 2nπ = -π/6 + 2nπ

x = π - sin⁻¹(-1/2) + 2nπ = 5π/6 + 2nπ

(where n is any integer), while the second equation gives

x = sin⁻¹(-1) + 2nπ = -π/2 + 2nπ

2 cot(x) sec(x) + 2 sec(x) + cot(x) + 1 = 0

2 sec(x) (cot(x) + 1) + cot(x) + 1 = 0

(2 sec(x) + 1) (cot(x) + 1) = 0

2 sec(x) + 1 = 0   OR   cot(x) + 1 = 0

sec(x) = -1/2   OR   cot(x) = -1

cos(x) = -2   OR   tan(x) = -1

The first equation has no (real) solutions, since -1 ≤ cos(x) ≤ 1 for all (real) x. The second equation gives

x = tan⁻¹(-1) + nπ = -π/4 + nπ

sin(x) cos²(x) = sin(x)

sin(x) cos²(x) - sin(x) = 0

sin(x) (cos²(x) - 1) = 0

sin(x) (-sin²(x)) = 0

sin³(x) = 0

sin(x) = 0

x = sin⁻¹(0) + 2nπ = 2nπ

2 cos²(x) + 2 sin(x) - 12 = 0

2 (1 - sin²(x)) + 2 sin(x) - 12 = 0

-2 sin²(x) + 2 sin(x) - 10 = 0

sin²(x) - sin(x) + 5 = 0

Using the quadratic formula, we get

sin(x) = (1 ± √(1 - 20)) / 2 = (1 ± √(-19)) / 2

but the square root contains a negative number, which means there is no real solution.

2 csc²(x) + cot²(x) - 3 = 0

2 (cot²(x) + 1) + cot²(x) - 3 = 0

3 cot²(x) - 1 = 0

cot²(x) = 1/3

tan²(x) = 3

tan(x) = ± √3

x = tan⁻¹(√3) + nπ  OR   x = tan⁻¹(-√3) + nπ

x = π/3 + nπ   OR   x = -π/3 + nπ

Answer:

\(\frac{6}{x-5}\)

Step-by-step explanation:

Helping in the name of Jesus.

Answer:

The length of s is 5.1 inches to the nearest tenth of an inch

Step-by-step explanation:

In Δ RST

∵ t is the opposite side to ∠T

∵ r is the opposite side to ∠R

∵ s is the opposite side to ∠S

→ To find s let us use the cosine rule

∴ s² = t² + r² - 2 × t × r × cos∠S

∵ t = 4.1 inches, r = 7.1 inches, and m∠S = 45°

→ Substitute them in the rule above

∴ s² = (4.1)² + (7.1)² - 2 × 4.1 × 7.1 × cos(45°)

∴ s² = 16.81 + 50.41 - 41.1677568

∴ s² = 26.0522432

→ Take √ for both sides

∴ s = 5.10413981

→ Round it to the nearest tenth

∴ s = 5.1 inches

∴ The length of s is 5.1 inches to the nearest tenth of an inch

Answer:

5.1

Step-by-step explanation:

delta math

Answer:

in this figure B: 32 square units

Answer:

Step-by-step explanation:

surface area of the given image

= 1/2 (24) 35 (2 sides)  = 840 cm²

= 44 x 37 (2 sides)       = 3256 cm²

= 24 x 44 (bot base)   = 1053 cm²  

total                             = 5152 cm²          

Both expressions equal 5 when substituting 2 for x because the expressions are equivalent.

Algebra is the branch of mathematics that deals with numbers and values which are represented with letters and symbols.

Sometimes, we do not want to mention a particular number, we can represent the number by a letter or a suitable symbol. This approach is algebraic.

For example, d + d = 2d

This is an example of an algebraic expressionns.

Given the algebraic expressions,

\(\frac{1}{2}x + 4 \\ x + 6 - \frac{1}{2}x - 2\)

Substituting 2 for x in the first expression gives:

(1/2 × 2) + 4

1 + 4

5

Substituting 2 for x in the second expression gives:

2 + 6 - (1/2 ×2) - 2

8 - 1 - 2

8 - 3

5

Both expressions equal 5 when substituting 2 for x because the expressions are equivalent.

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Based on the volume of the solid, the value of K is 8960.

The volume of the solid = volume of the cone + volume of the hemisphere

The volume of the cone = ¹/₃hπr²

The volume of the hemisphere = ²/₃πr³

where;

r is radius = 20 cm

h is the height of the cone = ?

The curved surface area of the cone = πrl

The curved surface area of the cone = 580π cm²

πrl =  580π

l = 580/20

l = 29 cm

h = √(29² - 10²)

h = 27.2 cm

The volume of cone = ¹/₃ * 27.2 * 20² * π

The volume of the cone = 3626.7π cm³

The volume of the hemisphere = ²/₃ * π * 20³

The volume of the hemisphere = 5333.3 cm³

The volume of the solid = 5333.3π cm³ + 3626.7π cm³

The volume of the solid = 8960π cm³

The volume of the solid is kπcm³ = 8960π cm³

K =  8960

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1. The x - intercepts of the parabola are

2. The meaning of the x-intercepts are the plane takes of at x = 2.5 s and lands at x = 7.5 s

3. The vertex of the parabola is at (5, 80).

A parabola is a curved shape

1. Given the parabola above, to find the x - intercepts, we proceed as follows.

The x-intercepts are the points at which the graph cuts the x-axis.

They are

2. The meaning of the x-intercepts in this problem are the points where the plane takes off and lands on the ground.

The plane takes of at x = 2.5 s and lands at x = 7.5 s

3. The vertex is the maximum point on the graph.

So, we see that the vertex is at x = 5 s and y = 80 ft

So, the vertex is at (5, 80).

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Answer:

27 feet

Step-by-step explanation:

Two walls have same area

Area of first wall(square) = 18*18 = 324

Area of second wall = 12 * x = 324

324/12 = 27

27 feet

Let that be x

Now

Answer:

  2∛3 units

Step-by-step explanation:

The volume is the cube of the edge length, so the edge length is the cube root of the volume:

  s = ∛V

  s = ∛24 = ∛(2³·3)

  s = 2∛3

The edge length is 2∛3 ≈ 2.8845 units.

the trader sell 36 mangos.

so she has 44 mangos with her.

44÷88=0.55

0.55×100%=55%

Answer:

4m-2

Step-by-step explanation:

4m-2

4 times the number of maple trees and subtracting 2 afterwards due to wording order.

10. Based on the chord theorem, x ≈ 12.5

11. Using the hint given, x = 60

According to the chord theorem, when a radius of a circle is perpendicular to a chord within the circle, the radius divides the chord into two equal parts.

10. Based on the chord theorem, the radius bisects the segment that measures 23 units into two segments, each measuring 23/2 = 11.5. Apply the Pythagorean theorem to find x.

x = √(11.5² + 5²)

x ≈ 12.5

11. Using the hint, we have:

(BC)(AB + BC) = (CD)(x + CD)

Substitute:

(14)(36 + 14) = (10)(x + 10)

700 = 10x + 100

700 - 100 = 10x

600 = 10x

600/10 = x

x = 60

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Maria’s vegetable garden measures 5⅔ feet by 6⅚ feet. 38.72 feet² is the area of the garden. This can be solved using the concept of the area of rectangle.

A rectangle is a sort of quadrilateral with parallel sides that are equal to one another and four vertices that are all 90 degrees apart. Because of this, it is also known as an equiangular quadrilateral. Because the opposing sides of a rectangle are equal and parallel, it can also be referred to as a parallelogram.

Each and every square is a rectangle since it is a quadrilateral with right angles on all four sides. But not all rectangles are squares; for a shape to be a square, all of its sides must have the same length.

So a square is also a rectangle and a rhombus. There is no square shape in the rectangle or rhombus. The trapezium shape is a parallelogram.

Maria’s vegetable garden measures 5⅔ feet by 6⅚ feet.

So, it is a rectangular garden.

Now, area = 5⅔ feet × 6⅚ feet

or, area = 17/3 feet × 41/6 feet

or, area = 697 /18 feet²

or, area = 38.72 feet²

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Answer:

203

Step-by-step explanation:

Sample size, n = 9

Mean weight, m = 203

Standard deviation = 25

Point estimate for the population mean weight of all black bears that are tagged `

The point estimate of the population mean ;

ΣX / n

Sum of sample / sample size ;

This is the mean value formula for the sample.

However, since it has been given in the question that, sample mean weight value = 203 ; then the point estimate of the population mean weight = 203

Option d: 203 is a point estimate for the population mean weight of all female black bears that are tagged.

Point estimate of population mean weight of female black bears that are tagged.

Point estimation of population mean is calculated by calculating the mean of the sample drawn from that population. This estimate is considered best guess of population mean.

The sample mean is obtained by:

\(\overline{x} = \dfrac{\sum \text{sample observations}}{\text{sample size}}\)

Since it is given that the sample mean is 203, thus we have the point estimate of the population mean as 203 too.

Thus, 203 is a point estimate for the population mean weight of all female black bears that are tagged.

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The number of cups for small pitchers = 2

The number of cups for large pitchers = 4.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

Two small pitchers and three large pitchers can hold a total of 16 cups of water.

And, The large pitcher holds 2 more cups of water than the small pitcher.

Now,

Let number of cups for small pitchers = x

And, The number of cups for large pitchers = y

Here, Two small pitchers and three large pitchers can hold a total of 16 cups of water.

So, We can formulate;

⇒ 2x + 3y = 16  .. (i)

And, The large pitcher holds 2 more cups of water than the small pitcher.

So, We get;

⇒ y = 2 + x  .. (ii)

Substitute the value of y from (ii) in (i), we get;

⇒ 2x + 3 (2 + x) = 16

Solve for x as;

⇒ 2x + 6 + 3x = 16

⇒ 5x = 16 - 6

⇒ 5x = 10

⇒ x = 2

And, From (ii);

⇒ y = 2 + x

⇒ y = 2 + 2

⇒ y = 4

Thus, The number of cups for small pitchers is 2

The number of cups for large pitchers is 4.

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Objects commonly found in a locality include residential buildings, commercial establishments, public facilities, transportation infrastructure, landmarks, natural features, utilities, street furniture, and vehicles.

The type of objects that can be found in a locality can vary greatly depending on the specific location and its surroundings. Here are some common types of objects that can be found in a locality:

Residential Buildings: Houses, apartments, condominiums, and other types of residential structures are commonly found in localities where people live.

Commercial Establishments: Localities often have various types of commercial establishments such as stores, shops, restaurants, cafes, banks, offices, and shopping centers.

Public Facilities: Localities typically have public facilities such as schools, libraries, hospitals, community centers, parks, playgrounds, and sports facilities.

Transportation Infrastructure: Localities usually have roads, sidewalks, bridges, and public transportation systems like bus stops or train stations.

Landmarks and Monuments: Some localities may have landmarks, historical sites, monuments, or cultural attractions that represent the area's heritage or significance.

Natural Features: Depending on the locality's geographical characteristics, natural features like parks, lakes, rivers, mountains, forests, or beaches can be present.

Utilities: Localities have infrastructure for utilities such as water supply systems, electrical grids, sewage systems, and telecommunications networks.

Street Furniture: Localities often have street furniture like benches, streetlights, waste bins, traffic signs, and public art installations.

Vehicles: Various types of vehicles can be found in a locality, including cars, bicycles, motorcycles, buses, trucks, and possibly other modes of transportation.

It's important to note that the objects present in a locality can significantly differ based on factors such as urban or rural setting, cultural context, economic development, and geographical location.

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Answer:

1200 centimeters

Step-by-step explanation:

Hello!

1meter=100centimeters

12meter = ?

\(thus \: \frac{12m \times 100cm}{1m} = 1200cm\)

Answer:

1200cm

Step-by-step explanation:

1m=100cm

12m=xcm

by multiplying cris cross

x=12*100

x=1200cm

12m=1200cm

Answer:

\( P'\cap Q' = \{1\}\)

Step-by-step explanation:

E = {1, 3, 7, 9, 11, 13, 15}

P= {3, 9, 11, 13} and Q = {3,7,9,15}

P' = {1, 7, 15} and Q = {1, 11, 13}

\( P'\cap Q' = \{1\}\)

The joint relative frequency for school children who plan to attend camp and have swimming lesson is 44%.

The correct option to the given question is option d.

We are required to find the joint relative frequency for school children who plan to attend camp and have swimming lessons, rounded to the nearest percent.

To find the joint relative frequency, we use the formula as follows:

Joint relative frequency = frequency of interest / total frequency

Joint relative frequency for school children who plan to attend camp and have swimming lessons = 42 / 96

(As we are looking for the students who plan to attend camp and have swimming lessons, we are interested in the first column of the table and the entry at the intersection of the first row and second column.)

Joint relative frequency for school children who plan to attend camp and have swimming lessons = 0.4375

Joint relative frequency for school children who plan to attend camp and have swimming lessons (rounded to the nearest percent) = 44%(option d).

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We have the expression:

In order to solve to get only one logarithm, we proceed as follows:

That, since:

and:

Answer:

x = -8 1/3

Step-by-step explanation:

Answer:

the answer is 2

Step-by-step explanation:

Answer:

Step-by-step explanation:

It is 2, because it is the only factor that can go with both of the numbers.

Answer:

46 boxes

Step-by-step explanation:

1012 / 22 = 46

Answer:

Step-by-step explanation:

-4(7-1) = (-4)7 + (-4)(-1) = -24

\(-21x^{2}-588\)

let me know if anything is unclear, I'm happy to help!