(Plzzzz help!!!) (50 points!!!)
1. Write the following quantities in scientific notation:
(1) 10130 Pa to 2 decimal places
(2) 978,15 m·s−2
to one decimal place
(3) 0,000001256 A to 3 decimal places

Answers

Answer 1

Answer:

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THEM BRAINLIST


Related Questions

Physics has brought us many important inventions over the centuries. What do you believe is the most important invention in the last 100 years? Why?


Your response should be 3-5 sentences long

Answers

One of the most important inventions of the last century is the transistor, which was invented in 1947 by John Bardeen, Walter Brattain, and William Shockley at Bell Labs.

What is transistor?

Transistor revolutionized electronics and enabled the development of modern computer. Transistors are tiny semiconductor devices that can amplify and switch electronic signals, and they have been essential components in development of almost all electronic devices, from radios and televisions to smartphones and laptops. According to their design, transistors can be divided into two categories: bipolar junction transistors (BJT) and field effect transistors. (FET).

The basis of a transistor's operation is the ability to modulate the intensity of a smaller current that is flowing through a second channel, which controls the flow of current through one channel.

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A force Ě = F, î + Fy h acts on a particle
that undergoes a displacement of g = s, it
Sy Ĵ where F, = 10 N, F, = -1 N, 8z = 4 m,
and sy=1 m.
Find the work done by the force on the
particle.
Answer in units of J.

A force = F, + Fy h acts on a particlethat undergoes a displacement of g = s, itSy where F, = 10 N, F,

Answers

Answer:

Pt 1: \(W=39J\)

Pt 2: θ = \(19.7\)

Explanation:

Part 1:

\(W=FS\)

\(W=F_{_xs_x}+F{_ys_y}\)

imagine the "i"and the "j" with the hat

\(W=(10i-1j)(4i+3j)\)

\(W=(10*4)-(1*1)\)

\(W=40-1\)

\(W=39J\)

Part 2:

\(|F|=\sqrt{10^2+(-1)^2}\)

\(|F|=\sqrt{101}\)

\(|S|=\sqrt{4^2+1^2}\)

\(|S|=\sqrt{17}\)

\(W=|F||S|cos\)θ

\(39=(\sqrt{101})(\sqrt{17} )cos\)θ

θ = \(19.7\)

Hope it helps

8. Molecular gastronomy was created by two scientists from Oxford University.
True or false

Answers

True,

molecular gastronomy was created by two scientists from Oxford University. Molecular gastronomy is a sub-discipline of food science that investigates the physical and chemical transformations of ingredients during cooking. It was first established by physicist Nicholas Kurti and chemist Hervé This, both from Oxford University. The term "molecular gastronomy" was coined in 1988 during a workshop on the science of cooking, which aimed to bridge the gap between scientific research and culinary arts.

Molecular gastronomy explores various aspects of food, such as flavor, texture, and presentation, and combines scientific knowledge with culinary techniques. This innovative approach to cooking has led to the creation of many unique and modern dishes, often featuring unexpected combinations of ingredients and visually appealing presentations.
The objective of molecular gastronomy is not only to create innovative dishes but also to understand and improve traditional cooking methods. This has led to advancements in food technology, as well as a deeper understanding of the science behind cooking processes. As a result, molecular gastronomy has become a popular and influential trend in the culinary world, inspiring chefs and home cooks alike to experiment with new techniques and ingredients.

In summary, molecular gastronomy was created by two scientists from Oxford University, Nicholas Kurti and Hervé This. Their groundbreaking work has had a significant impact on the culinary world and has led to many exciting innovations in food preparation and presentation.

How is the amplitude related to the energy of a wave?

Answers

Answer:

The higher the amplitude, the higher the energy.

A gyroscope slows from an initial rate of 34 rad/s at a rate of 0.619 rad/s2. The angular displacement when it stops moving is _

Answers

Answer: \(933.76\ rad\)

Explanation:

Given

The initial rate of gyroscope is \(\omega_o=34\ rad/s\)

Angular deceleration \(\alpha =0.619\ rad/s^2\)

Using angular equation of motion

\(\Rightarrow \omega^2-\omega_o^2=2\alpha \theta\)

Insert the values

\(\Rightarrow 0-34^2=2(-0.619)\theta \\\\\Rightarrow \theta =\dfrac{34^2}{2\times 0.619}\\\\\Rightarrow \theta =933.76\ rad\)

Thus, the angular displacement is \(933.76\ rad\)

An 80 N box of clothes is pulled 20m up a 30° ramp by a force of 115 N that points along the ramp. If the

Answers

The box's kinetic energy is 845.2J when an 80.0 N box is pulled 20.0 m up a 30.0-degree ramp by a force of 115 N if the coefficient of kinetic friction between the box and the ramp is 0.22.

We know that,

the theorem states the relationship between work and energy. This theorem states that the change in kinetic energy is equal to the work

W = ΔKE = Force × displacement

Now given that,

Weight of the box, w = 80N

Length of the ramp, l = 20m

Angle, θ = 30⁰

Applied force on the box, F = 115N and

coefficient of the kinetic friction, μ = 0.22

first, we find the net force acting on the box

ΣF = Fsinθ - f

here, f is the frictional force

ΣF = Fsinθ - μwcosθ

or ΣF = 115(sin30°) - 0.22(80)cos30° = 115(0.5) - 17.6(0.86)

or ΣF = 42.26N

Now, by applying the work-energy theorem

W = ΣF×d = (42.26N)(20m) = 845.2J

Kinetic energy = 845.2J

Therefore, The box's kinetic energy is 845.2J when an 80.0 N box is pulled 20.0 m up a 30.0-degree ramp by a force of 115 N if the coefficient of kinetic friction between the box and the ramp is 0.22.

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The complete question is:

An 80.0 N box is pulled 20.0 m up a 30.0-degree ramp by a force of 115 N. If the coefficient of kinetic friction between the box and the ramp is 0.22, what is the box's kinetic energy?

how does mass relates to latent heat?​

Answers

The mass of a substance is not directly related to latent heat. Instead, latent heat is a parameter that describes the amount of energy required or released during a phase shift of a substance.

What is latent heat?​

Latent heat can be thought of as hidden energy that is supplied or extracted to change the state of a substance without changing its temperature or pressure.

Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process—typically a first-order phase transition.

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A ball is in free fall after being dropped. What willthe speed of the ball be after 2 seconds of free fall?

Answers

So, the speed of the ball after 2 seconds after free fall is 20 m/s.

Introduction

Hi ! I'm Deva from Brainly Indonesia. In this material, we can call this event "Free Fall Motion". There are two conditions for free fall motion, namely falling (from top to bottom) and free (without initial velocity). Because the question only asks for the final velocity of the ball, in fact, we may use the formula for the relationship between acceleration and change in velocity and time. In general, this relationship can be expressed in the following equation :

\( \boxed{\sf{\bold{a = \frac{v_2 - v_1}{t}}}} \)

With the following conditions :

a = acceleration (m/s²)\( \sf{v_2} \) = speed after some time (m/s)\( \sf{v_1} \) = initial speed (m/s)t = interval of time (s)

Problem Solving

We know that :

a = acceleration = 9,8 m/s² >> because the acceleration of a falling object is following the acceleration of gravity (g).\( \sf{v_1} \) = initial speed = 0 m/s >> the keyword is free fallt = interval of time = 2 s

What was asked :

\( \sf{v_2} \) = speed after some time = ... m/s

Step by step :

\( \sf{a = \frac{v_2 - v_1}{t}} \)

\( \sf{(a \times t) + v_1 = v_2} \)

\( \sf{(10 \times 2) + 0 = v_2} \)

\( \boxed{\sf{v_2 = 20 \: m/s}} \)

So, the speed of the ball after 2 seconds after free fall is 20 m/s.

compare the times of all sunsets during the same period what do you observe​

Answers

Answer:

Theres no given?

Explanation:

Well, whatever.

I observed the shift of their sunset time.

Examples like:

January to June = their sunset time increased while

July to December = their sunset time decreased

Which of the following is NOT a part of the respiratory system?
a. pharynx
b. trachea
c. pancreas
d. larynx

Answers

Answer:

trachea

Explanation:

The trachea is one part of the respiratory tree that is a conduit for air to pass through on its way to or from the alveoli of the lungs. This transmits oxygen to the body and removes carbon dioxide.

if you wanted to increase the energy of a wave but you had to leave the wavelength the same what might you do ​

Answers

Answer:

Increase the amplitude

Explanation:

The energy conveyed by a wave is directly proportional to the square of its amplitude. Thus; E ∝ A²

This means that increasing the amplitude will lead to an increase in the energy.

Now, the amplitude of a wave is the height of a wave from it's highest point known as the peak, to the lowest point on the wave known as the trough whereas wavelength refers to the length of a wave from one peak to the next.

This means that increasing the amplitude has no effect on the wavelength.

A well-coated structure is defined as A) 95% or better B) 90% or better C) 99% or better D) 93% or better

Answers

Answer and Explanation:

A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing. Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body.

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A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing.

Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body

A 15000N crane pivots around a friction-free axle at its base and is supported by a cable making a 25 degree angle with the crane. The crane is 16m long and is not uniform, its center of gravity being 7m from the axle as measured along the crane. The cable is attached 3m from the upper end of the crane. (a) When the crane is raised to 55 degrees above the horizontal holding an 11000N pallet of bricks by a 2.2m very light cord, find the tension in the cable.

Answers

The quadratic equation of this equals up to 999

The table below shows the right ascensions of two stars at a location.


Name of star Right ascension
Star 1 2 hours
Star 2 4 hours 20 minutes

HELP ME PLS

What is the degree difference between the two stars that rise at the location?
20 degrees
30 degrees
35 degrees
60 degrees

Answers

Answer:

Star 1 2 hours

35

Explanation:

Answer:

the answer would be 35 degrees :))))

Explanation:

it was the correct on the quiz,,, good luckk :3!!


A race car accelerates from rest with a displacement of 25.0 m. If the
acceleration is 1.2 m/s2, what is the car's final velocity?

Answers

Answer:

Vf = Vi + at

t = Vf - Vi = 0.0m/s - 1.75 m/s

    --------- = ------------------------- = 8.8s

         a              -0.20 m/s(squared)

Explanation:

This is what I got I am pretty sure it's correct but correct me if I'm wrong : )

toy car A drives with a steady force of 35N and covers 2000 m with fully charged battery. toy car B drives with a steady force of 80 N. how far would it be able to drive using the same fully charged battery as car A.​

Answers

The distance travelled by toy car B using the same fully charged battery as car A is 875 m

How to determine the energy of car AForce (F) = 35 NDistance of car A (d) = 2000 mEnergy (E) = ?

E = fd

E = 35 × 2000

E = 70000 J

How to determine the distance travelled by car BEnergy (E) = 70000 JForce (F) = 80 NDistance of car B =?

E = fd

70000 = 80 × Distance of car B

Divide both sides by 80

Distance of car B = 70000 / 80

Distance of car B = 875 m

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A car accelerates from rest. It reaches a velocity of 25m/s in 10 seconds. What was the cars acceleration?

Answers

Answer:

We are Given:

initial velocity (u) = 0m/s

final velocity (v) = 25 m/s

time (t) = 10 seconds

acceleration (a)  = a m/s/s

From the first equation of motion, we know that:

v = u + at

solving for a, we get:

a = (v-u) / t

now, plugging the given values in this equation

a = (25 - 0) / 10

a = 25 / 10

a = 2.5 m/s/s

Therefore, the acceleration of the car is 2.5 m/s/s

24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.

Answers

The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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Give examples of stochastic and non-stochastic effects of radiation and explain why this information is essential in our field of study

Answers

Stochastic impacts of radiation allude to those that happen arbitrarily and are not reliant upon the portion got. These impacts are related to the likelihood of events and incorporate disease and hereditary changes. Non-stochastic impacts, then again, have a limit, and their seriousness increments with expanding portions.

Models incorporate radiation consumption and intense radiation conditions. Understanding the qualification among stochastic and non-stochastic impacts of radiation is significant in fields like radiation security, atomic medication, and radiobiology.

It assists in setting radiation with dosing limits, creating well-being rules, and carrying out suitable radiation safeguarding measures. By separating these impacts, experts can evaluate and deal with the dangers related to openness to ionizing radiation all the more successfully.

This information guides choices in regard to radiation wellbeing conventions, word-related openness limits, and the improvement of radiation therapy systems in medication.

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A space probe is sent (from the surface of the Earth) to intercept a comet when it is at a distance
of 3 × 10^11 m from the Sun. Find the minimum energy required to move a 100-kg payload to
that location. [MEarth = 6 × 10^24 kg; REarth = 6.37 × 10^6 m; MSun = 2.0 × 10^30 kg; radius of
Earth’s orbit = 1.5 × 10^11 m.]

Answers

The energy that is required by the space probe is 2.94 * 10^14 J.

What is the energy required?

Let us recall that the gravitational potential energy is the energy that is possessed by a body by virtue of the position of the body in space. We know that the energy that is possessed by the space probe is the gravitational potential energy and we have to obtain the energy required.

Recall that energy required = Work done = mgh

m = mass of the object

g = acceleration due to gravity

h = distance covered

Then;

100-kg * 9.8 m/s^2 *  3 × 10^11 m

= 2.94 * 10^14 J

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(b) The block takes time tup to slide up the ramp a distance x The block then takes time down to slide back down to the bottom of the ramp, where it has speed up. Is flows greater than equal to
or less tup?
tdown >tup -tdown = tup .tdown In a clear, coherent paragraph-length response that may also contain figures and/or equations, explain your reasoning. If you need to draw anything other than what you have shown in part (a) to
assist in your response, use the space below. Do NOT add anything to the figures in part (a).

Answers

Newton's second law allows finding the result for the comparison of the rise and fall times of the block on the ramp is:

The acceleration of the two processes is the same, if the initial velocity is equal, the times are equal.

Newton's second law establishes a relationship between the net force, the masses and the acceleration of the bodies.  

         ∑ F = m a

Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.

The reference system is a coordinate system with respect to which the forces are drawn, in the attached we can see a free body diagram of the block going up and down the ramp, in this case the x axis is parallel to the ramp and the y axis it is perpendicular.

Let's use trigonometry to find the components of weight.

         sin θ = \(\frac{W_x}{W}\)  

         cos θ = \(\frac{W_y}{W}\)  

         Wₓ = W sin θ

          \(W_y\) = W cos θ

Let's write Newton's second law for each axis.

Case 1. block slides down.

x- axis

         Wₓ = ma

         mg sin θ = ma

         a = g sin θ

Case 2. block rises

X axis

         - Wₓ = m a

         - m gsin θ = a

          a = - g sin θ

We can see that the acceleration is the same in two two cases, if the block has the same initial speed, the rise and fall time is the same.

           y = v₀ t - ½ a t²

            y = ½ a t²

In conclusion using Newton's second law we can find the result for the comparison of the rise and fall times of the block on the ramp is:

The acceleration is the same, if the initial velocity is the same, the times of going up and down are the same.

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(b) The block takes time tup to slide up the ramp a distance x The block then takes time down to slide

A science teacher asks her class to compare the way in which heat is transferred to water in a pond as opposed to soil at the edge of the pond. Which of the following investigations will help them make this comparison?

Answers

The investigation" Place soil in the bottom of a container and water on top, place it in the sun, and measure the temperature of the container" will help them make this comparison.

How to carryout this investigation?

A starting point for conducting a comparative analysis is to fill a container with soil followed by pouring water on top.

The next step involves placing it under sun rays while simultaneously recording its temperature. Post that, we need to separate the sand from water to rapidly gauge any change in temperature.

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Complete question:

A science teacher asks her class to compare the way in which heat is transferred to water in a pond as opposed to the soil at the edge of the pond. Which of the following investigations will help them make this comparison?

a. Mix water and soil in a container, place it in the sun, and measure the temperature of the container.

b. Place soil and water in separate containers, place them indoors, and monitor the temperature of the containers.

c. Place soil and water in separate containers, place them in the sun, and monitor the temperatures of each container.

d. Place soil in the bottom of a container and water on top, place it in the sun, and measure the temperature of the container.

An experiment is set up to determine the speed of charged particles as they move through a region that is traversed by a constant electric and a constant magnetic field. The particles are moving toward the right of the page when they encounter the region. The electric field points toward the top of the page, and the magnetic field points out of the page. Required:
Predict how the positively and negatively charged particles of various speeds will behave in this experiment

Answers

The deflection will be toward the backside for bad cost and closer to the pinnacle of the spread page for the high-quality charge.

What are charged particles?

Charged particles are simply defined as particles with an electric charge on them. This may sometimes result in being an ion, as a molecule with excess or a reduced amount of electrons relative to protons.

Generally, the Magnetic area points internal the airplane so through fleming left hand rule is

F = q ( V x B). Ie

hence

qVB = qE

V= E/B then no deflection.

V > E/B then magnetic pressure is dominant over electric powered force.

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Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was stopped in her lane 30 feet ahead, Kara rear-ended Lisa's rented Taurus. Kara's 1100-kg car was moving at 10.9 m/s and stopped in 0.159 seconds.

Answers

The change in momentum of Kara's car is -1.43 × 10⁴ kg.m/s, the magnitude of force is -1.021 × 10⁵ N.

What is Force?

Force is the external agent which causes the motion of an object or it is the resistant which makes the object come at rest from motion. It is a vector quantity, because it has both the magnitude and direction.

Mass of Kara's car = 1300 Kg

moving with speed = 11 m/s

time taken to stop = 0.14 s

final velocity = 0 m/s

distance between Lisa ford and Kara's car = 30 m

a) change in momentum of Kara's car

Δ P = m Δ v          

Δ P = m(vf - vi)

Δ P = 1300 (0 - 11)

Δ P = -1.43 × 10⁴ kg.m/s

The impulse is equal to the change in momentum of the car

I = -1.43 × 10⁴ kg.m/s

Magnitude of the force experienced by Kara

I = F × t

where, I is impulse acting on the car

t is time

- 1.43 × 10⁴ = F × 0.14

F = -1.021 × 10⁵ N

Negative sign represents the direction of the force.

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Your question is incomplete, most probably the complete question is:

Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was stopped in her lane 30 feet ahead, Kara rear-ended Lisa's rented Taurus. Kara's 1300-kg car was moving at 11 m/s and stopped in 0.14 seconds.

a. Determine the momentum change of Kara's car.

b. Determine the impulse experienced by Kara's car.

c. Determine the magnitude of the force experienced by Kara's car.

Clearing forests for oil palm plantations is an example of large-scale agriculture. Oil palms are also plants. However, it is not desirable to have large areas of forest plants replaced by oil palms. Why is that so?

Answers

It is not desirable to have large areas of forest plants replaced by oil palms because animals and plants may be affected in regions of fragmented habitat, which is an important issue in ecosystem disturbance and loss of biodiversity.

What are ecosystem disturbances and loss of biodiversity?

Ecosystem disturbance is an ecological concept that makes reference to the different human activities and natural processes (such as earthquake catastrophes) that are to break the delicate internal homeostatic equilibrium of the ecosystems. Moreover, loss of biodiversity refers to the loss of variation due to the extinction of populations and even species.

Therefore, with this data, we can see that ecosystem disturbance and loss of biodiversity are fundamental processes and they have been associated with the process of replacement of native trees in natural forests with oil palms, which have negative outcomes for the surrounding environment.

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what 2 things keep windows from shattering?
video- Mechanical Universe: Resonance

Answers

Two things that keep windows from shattering are the strength of the glass and the ability of the window frame to dampen vibrations.

What is the shattering of windows?

The strength of the glass is important because it determines how much force the glass can withstand before it breaks. Modern windows are typically made of tempered glass, which is treated with heat to make it stronger and more resistant to shattering.

The ability of the window frame to dampen vibrations is also crucial because glass is prone to resonance, which is a phenomenon that occurs when an object is subjected to vibration at its natural frequency.

If the frequency of the vibration matches the natural frequency of the glass, the glass can begin to vibrate and eventually shatter. To prevent this, window frames are designed to be sturdy and to dampen vibrations, which helps to prevent the glass from vibrating and shattering.

In summary, both the strength of the glass and the ability of the window frame to dampen vibrations are important factors that help to prevent windows from shattering.

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The results in a science text

describe details involved in completing the experiment.

share the data found after an experiment is concluded.

give the background and purpose of an experiment.

interpret the results of a completed experiment.

Answers

Answer:

The answer is B since no one answered it :)

Explanation:

The results in a science textdescribe details involved in completing the experiment.share the data found

Answer:

b

Explanation:

i took the test

How does technology help science?

a)Technology teaches scientists how to do math.
b)Technology helps scientists study things that are very small, far away, or hard to reach.
c)New inventions are based on scientific principles.
d)Computers figure out answers so scientists don’t have to think.

Answers

Answer:

the answer to this is letter b

Answer:

B) Technology helps scientists study things that are very small, far away, or hard to reach.

What will be the temperature reading in Fahrenheit scale whe eading is 310 k?​

Answers

The temperature reading in Fahrenheit scale when reading 310 K is  98.6F

What is temperature?

Temperature is the degree of hotness or coldness of the object.

Given is a temperature in Kelvin scale = 310 K

Temperature on centigrade scale = 310 -273 = 37°C

Temperature conversion from Centigrade to Fahrenheit is

C/5 = F -32/9

Plug the value, we get

37/5 = F-32/9

66.6 = F -32

F = 32+66.6 =

F = 98.6

Thus, the temperature of 310 K in Fahrenheit is 98.6F.

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A 68 kg
man's arm, including the hand, can be modeled as a 79-cm
-long uniform cylinder with a mass of 3.3 kg. In raising both his arms, from hanging down to straight up, by how much does he raise his center of gravity?

Answers

Answer:

Explanation:

We can calculate the change in the man's center of gravity by considering the initial and final positions of the center of gravity of his arms.

Assuming the man's arms are initially hanging down by his sides, the center of gravity of his arms is located at the midpoint of the cylinder, which is at a distance of L/2 = 79/2 = 39.5 cm from the shoulder joint.

When the man raises his arms straight up, the center of gravity of his arms is located at the top of the cylinder, which is at a distance of L = 79 cm from the shoulder joint.

The change in the man's center of gravity is therefore:

Δh = h_final - h_initial

= L - L/2

= 79 cm - 39.5 cm

= 39.5 cm

Therefore, the man raises his center of gravity by 39.5 cm when he raises both his arms from hanging down to straight up.

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