Plzzz help again!!!!!! Plz plz plz 15 points

ответ на картинке !!!!

The smallest value of the other number will be 3 ×5× 11 =165

In the given statement is :

When the least common multiple of two positive integers is divided by their greatest common divisor, the result is 33. If one integer is 45.

To find what is the smallest possible value of the other integer

Now, According to the question

One of the numbers 3 ×3× 5 = 45

The lowest common multiple has to be a multiple of 45 i.e.,

3 ×3× 5 something when LCM is divided by the greatest common divisor

then the answer is 33 = 3 x 11 .

So the other number will have to be a multiple of 11

3 ×3× 5× 11 × ?/ some factor of 4 = 33

(3 ×5) ×3× 11 × 1 /3 × 5 = 33

So if the greatest common divisor is 3× 5 the given number is 3 ×3× 5

Hence, The smallest value of the other number will be 3 ×5× 11 =165  

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Answer:

\(13- 0.75 * (12) + 8 * (\frac{1}{2} ) = 13-9+4\\\\13-5=8\)

Step-by-step explanation:

Evaluate 13-0.75w+8x13−0.75w+8x13, minus, 0, point, 75, w, plus, 8, x when w=12w=12w, equals, 12 and x=\dfrac12x= 2 1 ​ x, equals, start fraction, 1, divided by, 2, end fraction.

For this case we have the following expression:

 \(13-0.75w + 8x\)

Evaluate for the following values:

 w = 12

 x = 1/2

 We Substituting the values we have:

\(13- 0.75 * (12) + 8 * (\frac{1}{2} ) = 13-9+4\\\\13-5=8\)

The relationship of those who attend religious services regularly are less likely to consume alcohol regularly.

Yes, there can be a relationship between attendance at religious services and alcohol consumption. In the given random sample of 1000 adults, both their attendance at religious services and daily alcohol consumption were recorded.

To analyze the relationship, you can follow these steps:

1. Organize the data: Create a contingency table that displays the frequency of each combination of attendance at religious services and alcohol consumption.

2. Calculate percentages: Determine the percentage of adults who attend religious services and drink alcohol daily, as well as the percentages for the other categories (e.g., attend services and don't drink daily, don't attend services and drink daily, etc.).

3. Identify trends or patterns: Compare the percentages to see if there is a relationship between attendance at religious services and daily alcohol consumption.

For example,

If the percentage of adults who attend religious services and drink daily is significantly lower than the percentage of those who don't attend services and drink daily, this suggests a relationship.

4. Statistical testing: Perform a chi-square test to determine if the observed relationship is statistically significant.

This test compares the observed frequencies in the contingency table to the frequencies that would be expected if there was no relationship between attendance at religious services and alcohol consumption.

5. Interpret the results: If the chi-square test shows that the relationship is statistically significant, this supports the hypothesis that there is a relationship between attendance at religious services and alcohol consumption in the sample of 1000 adults.

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Answer:

\(area = length \times width \\ length = \frac{area}{width } \\ length = \frac{(56 {x}^{2} + 108x + 36) {m}^{2} }{(14x + 6)m} \\ length = (4x + 6)m\)

The present value of the sequence of annual payments of Rs 25000 each, the first being made at the end of the 5th year and the last being paid at the end of the 12th year, if money is worth 6% is Rs. 158620.39.

1: We can use the formula to calculate the present value of the annuity:

P = A x [1 - (1+i)^-n] / i

Where

P = Present Value

A = Annuity

i = Interest Raten = Number of payments

2: Calculate the present value of each payment using the formula:

P1 = 25000 / (1.06)⁵

P2 = 25000 / (1.06)⁶

P3 = 25000 / (1.06)⁷

P4 = 25000 / (1.06)⁸

P5 = 25000 / (1.06)⁹

P6 = 25000 / (1.06)¹⁰

P7 = 25000 / (1.06)¹¹

P8 = 25000 / (1.06)¹²

3: Substitute the values into the formula to find the present value:

P = P1 + P2 + P3 + P4 + P5 + P6 + P7 + P8

P = (25000 / (1.06)⁵) + (25000 / (1.06)⁶) + (25000 / (1.06)⁷) + (25000 / (1.06)⁸) + (25000 / (1.06)⁹) + (25000 / (1.06)¹⁰) + (25000 / (1.06)¹¹) + (25000 / (1.06)¹²)

P = 158620.39

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Answer:

It’s still 11.9

Step-by-step explanation:

Answer:

200

Step-by-step explanation:

1/5m-2/3y=30

1/5m-2/3(15)=30

1/5m-30/3=30

1/5m-10=30

1/5m=30+10

1/5m=40

m=40/(1/5)

m=(40/1)(5/1)

m=200/1

m=200

Answer:

y=3x+2

Step-by-step explanation:

For a the equation is y=3x+2 because he makes 3 every hour (3x) and he already has 2 (+2).

For the graph you replace x with any number and solve. Plot the point.

Then you do it again but with a different x.

Finally you draw a straight line trough the 2 points.

Given dataAn element with mass 310 grams decays by 5.7% per minute. We need to find how much of the element is remaining after 9 minutes, to the nearest 10th of a gram.Solution

Let P be the amount of the element remaining after 9 minutes. Then, the amount of the element that decayed in 9 minutes is:Q = 310(1 - 0.057)^9= 310(0.943)^9≈ 174.24 gramsTherefore, the amount of the element remaining after 9 minutes is:P = 310 - Q≈ 135.76 grams.So, the amount of the element remaining after 9 minutes is approximately 135.76 grams, rounded to the nearest 10th of a gram.

Let x be the number of ounces of the 40% alloy Dr. Hamilton used.Then (80 - x) would be the number of ounces of the 60% alloy he used. Therefore, the equation is:0.4x + 0.6(80 - x) = 0.45(80)Simplify this equation to solve for x as follows:0.4x + 48 - 0.6x = 36Add like terms:-0.2x + 48 = 36Subtract 48 from both sides of the equation:-0.2x = -12Solve for x by dividing both sides of the equation by -0.2:x = 60Therefore, Dr. Hamilton used 60 ounces of the 40% alloy.

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Answer:

EXPLANATION BELOW

Step-by-step explanation:

7 | 0, 4, 8

8 | 0, 8, 9

9 | 5

10 | 1, 9

11 | 6, 7

hope this helps!! you basically just divide the number into two-

Answer:

2 nonreal solutions

Step-by-step explanation:

given a quadratic equation in standard form

ax² + bx + c = 0 (a ≠ 0 )

then the nature of the roots are determined by the discriminant

b² - 4ac

• if b² - 4ac > 0 then 2 real and irrational solutions

• if b² - 4ac > 0 and a perfect square then 2 real and rational solutions

• if b² - 4ac = 0 then 2 real and equal solutions

• if b² - 4ac < 0 then no real solutions

5x² - 2x + 6 = 0 ← in standard form

with a = 5 , b = - 2 , c = 6

b² - 4ac

= (- 2)² - (4 × 5 × 6)

= 4 - 120

= - 116

since b² - 4ac < 0

then there are 2 nonreal solutions to the equation

Answer:

(a) 6

(b) 14

Step-by-step explanation:

Answer:  (a) 6

               (b) 14

Step-by-step explanation:

Let a represent the unknown digit for Chinese --> 70 + a

Let b represent the unknown digit for Mathematics --> 80 + b

Total scores ÷ Total number of tests = Average

\(\dfrac{78 + (70 + a) + (80 + b) + 62}{4}=76\\\\\\\dfrac{290 + a + b}{4}=76\\\\\\290 + a + b=304\\\\\\a+b=14\)

The two digits must add up to 14.

The only options are: (9,5), (8,6), (7,7), (6,8), and (5,9),

            Mathematics   -   Chinese  

(9, 5)          89              -         75       =      14       LARGEST Difference

(8, 6)          88              -         76       =      12

(7, 7)          87              -          77       =      10

(6, 8)          86              -         78       =       8

(5, 9)          85              -         79       =       6      SMALLEST Difference

\(S_\square = 8 * 8 = 64\\S_\triangle = \frac{ah}{2} = \frac{8*3}{2} = 4 * 3 = 12\\S = S_\square - S_\triangle = 64 - 12 = 52\)

Answer: 52.

Answer:

(.25)(.30) = .075 probability that both children will get the flu

The probability that both a youngster in New York and a kid in Los Angeles will get this season's virus can be determined by duplicating the singular probabilities. Consequently, the likelihood that both will get influenza is 0.075.

To find the probability of the two occasions happening, we duplicate the probabilities of every occasion. Considering that the probability of a kid in New York getting this season's virus is 0.25 (or 25%) and the probability of a youngster in Los Angeles getting influenza is 0.30 (or 30%), we multiply these probabilities: 0.25 * 0.30 = 0.075. This implies there is a 0.075 probability, or 7.5%, that both a youngster in New York and a kid in Los Angeles will get influenza.

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The distance from Southville to Westfield is 95 miles.

How to find the distance?

Let's say that Portland is the origin of the coordinate axis, East is the positive x-axis and North is the positive y-axis.

Westfield is 76 mi due west of Portland, then Westfield's position is:

(76mi, 0mi).

Southville is 57 mi due south of Portland, then its position is:

(0mi, 76mi)

The distance between these two points is given by:

\(D=\sqrt{(76mi-0mi)^2+(0mi-(-57mi)^2}\) = 95 miles.

So the distance from Southville to Westfield is 95 miles.

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Answer:

2198.9 cm³

Step-by-step explanation:

Volume of flower vase = volume of cuboid - voume of cone

Volume of cuboid = lbh (length×breath×height) = 12 × 10 × 20 = 2400 cm³

Volume of cone = ⅓ × base area × height

Base area = area of circle = pi radius² = pi 4² = 16 pi

(the diameter of the circle is 8 so to find the radius you just divide it by 2 and you'll get 4)

So,

vol of cone = ⅓ × 16 pi × 12 = 64 pi = 201.06192

Volume of flower vase = 2400 - 201.06192 = 2198.93808 = 2198.9

The statement is false.

The expression to which the distance Kane run in a training session after w week is {3+(1÷4)w}...

Kane is training for a marathon. He start running 3 miles during every training session. Each week he plan to increase the distance of his running by 1/4 miles. Let 'w' be the number of week.

Let w be the number of week.

So the expression is formed  as that in 1st week if he sart running 3 miles and after every week 1/4 miles added ,it's mean 1 by forth part of one mile is added after every week so if;

we suppose that we have to calculate it for "w" weeks then these weeks will be multiply with 1/4 and then added to the starting miles which are 3 miles

So the expression will be:

{3+(1÷4)w}

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Your question is may be misspelled it will be...(Kane is training for a marathon. He start running 3 miles during every training session. Each week he plan to increase the distance of his running by 1/4 miles. Let 'w' be the number of week. Write an expression to how the distance Kane run in a training session after 'w' weeks?

Let x be the amount invested at 9% and y the amount invested at 6%.

Then we have:

I) x + y = $14,929

II) 0.09x - 0.06y = $1,139.91

First, we multiply equation II by 100:

9x - 6y = $113,991

Now, we add to it 6 times equation I:

15x = $203,565

x = $13,571

Now, we replace x in equation I to find y:

$13,571 + y = 14,929

y = $1,358

Answer:

the anser is b great job

Step-by-step explanation:

Answer:

2x^2 - 8x + 6

Step-by-step explanation:

2x*x+(-3x*2x)+(x*(-2))+6=

2x^2-8x+6

To find the equation of the line, we will use the formula below;

x₁=-6 y₁=6 x₂=4 y₂=6

substitute the values into the formula

y - 6 = 0

y = 6

The values of the variables and numbers in radical form are presented as follows;

43a) x > -5

40a) a > 0

44b) x < 0

47e) x > 0

43b) x = The set of all real numbers

44a) The set of all numbers

45 a) x = 14

45 b) x = 0

45 c) x = -1

45 d) x = -4

45 e) x = 1

42 d)x = 5/196

9 e) x = 4

9 f) x = 8

9 a) √(0.6/36) ≈ 0.13

9 h) √((4 - 10)/(0.01)) = i·10·√6

A radical also known as a root is represented using the square root or nth root symbol and is the opposite of an exponent.

43 a) \(\sqrt{x + 5}\)

x + 5 > 0

Therefore, x > -5

40a) ∛a

a > 0

44b) √(-5·x)³

-5·x < 0

x < 0

47e) √(13 - (13 - 2·x))

(13 - (13 - 2·x)) > 0

13 > (13 - 2·x)

0 > -2·x

x > 0

43b) √|x| + 1

x = All real numbers

44 a) √(-2·x)²

√(-2·x)² = -2·x

x = Set of all numbers

45 a) √(x - 5) = 3

(x - 5) = 3² = 9

x = 9 + 5 = 14

45b) √(2·x + 4) = 2

2·x + 4 = 2²

2·x = 2² - 4 = 0

x = 0/2 = 0

45c) √(x·(x + 1)) = 0

(x·(x + 1)) = 0

(x + 1) = 0

x = -1

45 d) √(x + 5) = -1

(x + 5) = (-1)²

x + 5 = 1

x + 5 = 1

x = 1 - 5 = -4

x = -4

45e) √x + x² = 0

√x = -x²

(√x)² = (-x²)² = x⁴

x  = x⁴

1 = x⁴ ÷ x = x³

x = ∛1 = 1

x = 1

42d) \(\sqrt{\dfrac{5}{x} } +3= 17\)

\(\sqrt{\dfrac{5}{x} }= 17-3 =14\)

\(\dfrac{5}{x} }=14^2=196\)

\(x = \dfrac{5}{196}\)

9e) \(\sqrt{\dfrac{4}{x} } = 1\)

\(\dfrac{4}{x} } = 1^2\)

x × 1² = 4

x = 4

19f) ∛x - 2 = 0

∛x = 2

x = 2³ = 8

9a) \(\sqrt{\dfrac{0.6}{36} }\)

\(\sqrt{\dfrac{0.6}{36} }\) = \(\sqrt{\dfrac{1}{60} }= \dfrac{\sqrt{15}}{30} \approx 0.13\)

9h) \(\sqrt{\dfrac{4-10}{0.01} }\)

\(\sqrt{\dfrac{4-10}{0.01} }\)= √(-600) = √(-1)·√(600) = i·10·√6

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Answer:

-6 or 5

Step-by-step explanation:

3x^2+3x-90=0 Simplified to x^2+x-30=0;

Using cross multiplication (x+6)*(x-5) = 0;

so x=-6 or 5

it is proportional

cause it is trust me

Answer: it's proportional

Step-by-step explanation:

Answer:

0 = 2f + 3g + 4f + -4g + 8

Step-by-step explanation:

The probability that the student will fail, given that he guesses the answers, is 0.227.

Since there are only two possible outcomes for each question (true or false),

the probability of guessing a correct answer is 1/2 = 0.5.

Likewise, the probability of guessing a wrong answer is also 1/2 = 0.5.

To find the probability of failing the exam,

we need to find the probability of answering less than 11 questions correctly.

Using the binomial probability formula,

the probability of getting k successes (correct answers) in n trials (questions) is given by:

P(k) = (n C k) * p^k * q^(n-k)

where p is the probability of success (getting a correct answer),

q is the probability of failure (getting a wrong answer), and (n C k) is the number of combinations of n things taken k at a time.

In this case,

n = 17, p = 0.5, and

q = 0.5.

The number of ways to get less than 11 correct answers is:

P(X < 11) = P(X = 0) + P(X = 1) + ... + P(X = 10)P(X = k) = (n C k) * p^k * q^(n-k)

Substituting the values:

P(X < 11) = P(X = 0) + P(X = 1) + ... + P(X = 10)

P(X = 0) = (17 C 0) * (0.5)^0 * (0.5)^17 = 0.0015

P(X = 1) = (17 C 1) * (0.5)^1 * (0.5)^16 = 0.0146

P(X = 2) = (17 C 2) * (0.5)^2 * (0.5)^15 = 0.0586

P(X = 3) = (17 C 3) * (0.5)^3 * (0.5)^14 = 0.1558

P(X = 4) = (17 C 4) * (0.5)^4 * (0.5)^13 = 0.268

P(X = 5) = (17 C 5) * (0.5)^5 * (0.5)^12 = 0.327

P(X = 6) = (17 C 6) * (0.5)^6 * (0.5)^11 = 0.2732

P(X = 7) = (17 C 7) * (0.5)^7 * (0.5)^10 = 0.1537

P(X = 8) = (17 C 8) * (0.5)^8 * (0.5)^9 = 0.0573

P(X = 9) = (17 C 9) * (0.5)^9 * (0.5)^8 = 0.013

P(X = 10) = (17 C 10) * (0.5)^10 * (0.5)^7 = 0.0015

Therefore, P(X < 11) = 0.0015 + 0.0146 + 0.0586 + 0.1558 + 0.268 + 0.327 + 0.2732 + 0.1537 + 0.0573 + 0.013 + 0.0015P(X < 11) = 0.8857

Thus, the probability of failing is: P(fail) = P(X < 11) = 0.8857

The probability that the student will fail, given that he guesses the answers, is 0.227 (rounded to three decimal places).

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The equation is a shorthand method for writing a mathematical rule.

The answer to your question is b.equation. An equation is a shorthand method for writing a mathematical rule. It represents a relationship between two or more variables using mathematical symbols and operations. Equations are commonly used in algebra, calculus, and other areas of mathematics to solve problems and make predictions. They are written using an equal sign (=) to show that the expression on the left is equal to the expression on the right. Equations are an important tool in mathematics because they allow us to express complex ideas in a concise and precise way. By using equations, we can simplify calculations and solve problems more efficiently.
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