Plzz pls pls pls pls help me I’m stuck

Answer:

False, 82 inches is not greater than 5 feet and 10 inches

Step-by-step explanation:

1 feet = 12 inches

5x12=60+10=70

82 is greater than 70.

Answer:

98 degrees

Step-by-step explanation:

278-82 over 2

196 divided by 2

This will lead to 98, therefor the angle is 98 degrees

Answer: x= a, x=b

Step-by-step explanation:

Solve the equation for x by finding a, b, and c of the quadratic then apply the quadratic formula.

Answer:

In order to find the scale factor of ABCD to EFGH, we need to find the ratio of corresponding side lengths of the two similar figures.

Let's assume that ABCD and EFGH are similar quadrilaterals. We can label the side lengths of ABCD as AB = a, BC = b, CD = c, and DA = d, and the side lengths of EFGH as EF = w, FG = x, GH = y, and HE = z.

The scale factor k is defined as the ratio of corresponding side lengths, such that k = EF/AB = FG/BC = GH/CD = HE/DA.

Therefore, to find the scale factor, we can choose any pair of corresponding sides and divide their lengths. For example, we can choose AB and EF, and get:

k = EF/AB = w/a

Similarly, we can choose other corresponding sides and get:

k = FG/BC = x/b

k = GH/CD = y/c

k = HE/DA = z/d

Since ABCD and EFGH are similar, all four ratios must be equal, so we can set them equal to each other:

w/a = x/b = y/c = z/d

This equation tells us that the scale factor is the same for all corresponding sides of the two quadrilaterals. Therefore, we can find the scale factor by choosing any two corresponding sides and dividing their lengths.

Answer: 6.24

Step-by-step explanation:

To round 6.235 to the nearest hundredth means to round the numbers so you only have two digits in the fractional part (numbers after the decimal)

The last digit in the fractional part of 6.235 is 5 or more and less than 9, so add 1 to the second digit of the fractional part and remove the third digit.

Therefore, the answer is 6.24

Answer:

P': (3, 0)

Q': (4, 2)

R': (3, 4)

S': (2, 2)

Step-by-step explanation:

A rhombus, PQRS, has vertices at the points P(6, 2), Q(7, 4), R(6, 6) and S(5, 4). PQRS is translated 3 squares left and 2 squares down.

Rule: (x - 3, y - 2)

1. Using the given rule, find the new coordinates of the new image:

P': (6, 2) ➺ (6 - 3, 2 - 2) ➺ (3, 0)

Q': (7, 4) ➺ (7 - 3, 4 - 2)  ➺ (4, 2)

R': (6, 6) ➺ (6 - 3, 6 - 2) ➺ (3, 4)

S': (5, 4) ➺ (5 - 3, 4 - 2) ➺ (2, 2)

New coordinates:

P': (3, 0)

Q': (4, 2)

R': (3, 4)

S': (2, 2)

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Answer:x+(-4)=12 the answer is 8

Step-by-step explanation:

Answer:

can you please explain the different way

Step-by-step explanation:

Answer: If you have 10 balls and one of them is defective (either heavier or lighter), you can find the defective ball in a maximum of 3 weighings using a two-pan balance scale.

Here’s how you can do it:

Divide the balls into three groups of three balls each and one group with the remaining ball.

Weigh two groups of three balls against each other. If they balance, the defective ball must be in the third group of three balls or the group with the remaining ball. If they don’t balance, the defective ball must be in one of the two groups being weighed.

Take two balls from the group that contains the defective ball and weigh them against each other. If they balance, the defective ball must be the remaining ball in that group. If they don’t balance, you have found the defective ball.

This method guarantees that you will find the defective ball in a maximum of 3 weighings.

(a) The impulse response is given by: h[n] = {2, 0, 12, −48, −96, 252, …} and (b) The zero-state response is given by: y[n] = (29/15)(2)n + (16/15)(5)n and (c) The total response is: y[n] = (29/15)(2)n + (16/15)(5)n + 2(1) + 12(2)n−2 − 48(2)n−3 + … + {−1/16}[2]n−8.

Given difference equation is:

y[n] = −3y[n −1] + 10y[n −2] + 2x[n] −5x[n −2]

The impulse response of a system is the output of a system when a delta function is the input. A delta function is defined as follows

δ[n] = 1 if n = 0, and δ[n] = 0 if n ≠ 0. If x[n] = δ[n], then the output of the system is the impulse response h[n].

(a) Impulse Response

The input is x[n] = (2)^2n u[n]

Therefore, the impulse response h[n] can be found by setting x[n] = δ[n] in the difference equation. The equation then becomes:

h[n] = −3h[n −1] + 10h[n −2] + 2δ[n] −5δ[n −2]

Initial conditions: y[−1] = 2, y[−2] = 3, and x[n] = δ[n].

The initial conditions determine the values of h[0] and h[1].

For n = 0,h[0] = −3h[−1] + 10h[−2] + 2δ[0] −5δ[−2] = 2

For n = 1,h[1] = −3h[0] + 10h[−1] + 2δ[1] −5δ[−1] = 0

Using the difference equation, we can solve for h[2]:h[2] = −3h[1] + 10h[0] + 2δ[2] −5δ[0] = 12

Using the difference equation, we can solve for h[3]:h[3] = −3h[2] + 10h[1] + 2δ[3] −5δ[1] = −48

Similarly, using the difference equation, we can find h[4], h[5], h[6], … .

The impulse response is given by:

h[n] = {2, 0, 12, −48, −96, 252, …}

(b) Zero-State Response

The zero-state response is the output of the system due to initial conditions only. It is found by setting the input x[n] to zero in the difference equation. The equation then becomes:

y[n] = −3y[n −1] + 10y[n −2] −5x[n −2]

The characteristic equation is:r2 − 3r + 10 = 0(r − 2)(r − 5) = 0

The roots are:

r1 = 2, r2 = 5

The zero-state response is given by:

y[n] = c1(2)n + c2(5)n

We can solve for c1 and c2 using the initial conditions:

y[−1] = 2 = c1(2)−1 + c2(5)−1 ⇒ c1/2 + c2/5 = 2y[−2] = 3 = c1(2)−2 + c2(5)−2 ⇒ c1/4 + c2/25 = 3

Solving these equations simultaneously gives:c1 = 29/15, c2 = 16/15

Therefore, the zero-state response is given by:y[n] = (29/15)(2)n + (16/15)(5)n

(c) Total Response

The total response is the sum of the zero-state response and the zero-input response. Therefore,

y[n] = (29/15)(2)n + (16/15)(5)n + y*[n]where y*[n] is the zero-input response.

The zero-input response is the convolution of the impulse response h[n] and the input x[n]. Therefore,y*[n] = h[n] * x[n]

where * denotes convolution. We can use the definition of convolution:

y*[n] = ∑k=−∞n h[k] x[n − k]Since x[n] = (2)n u[n], we can simplify the expression:

y*[n] = ∑k=0n h[k] (2)n−k

The zero-input response is then:

y*[n] = h[0](2)n + h[1](2)n−1 + h[2](2)n−2 + … + h[n](2)0

Substituting the values of h[n] gives:

y*[n] = 2(1) + 0(2)n−1 + 12(2)n−2 − 48(2)n−3 + … + {−1/16}[2]n−8

Therefore, the total response is given by:

y[n] = (29/15)(2)n + (16/15)(5)n + y*[n]

y[n] = (29/15)(2)n + (16/15)(5)n + 2(1) + 0(2)n−1 + 12(2)n−2 − 48(2)n−3 + … + {−1/16}[2]n−8

The total response is: y[n] = (29/15)(2)n + (16/15)(5)n + 2(1) + 12(2)n−2 − 48(2)n−3 + … + {−1/16}[2]n−8

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The quadratic equation with zeros at -6 and 2 is y² + 4y - 12 = 0. This is in standard form, which is ax² + bx + c = 0, with a = 1, b = 4, and c = -12.

To find the quadratic equation with zeros at -6 and 2, we can start by using the fact that if a quadratic equation has roots x₁ and x₂, then it can be written in the form

(y - x₁)(y - x₂) = 0

where y is the variable in the quadratic equation.

Substituting the given values of the zeros, we get

(y - (-6))(y - 2) = 0

Simplifying this expression, we get

(y + 6)(y - 2) = 0

Expanding this expression, we get

y² - 2y + 6y - 12 = 0

Simplifying this expression further, we get

y² + 4y - 12 = 0

So the quadratic equation with zeros at -6 and 2 is

y² + 4y - 12 = 0

This is the standard form of a quadratic equation, which is

ax² + bx + c = 0

where a, b, and c are constants. In this case, a = 1, b = 4, and c = -12.

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Answer:

6h + 6k

Step-by-step explanation:

3h(2) + 2k(3)

3h * 2 + 2k * 3

6h + 6k  ........this is our final answer.

According to the normal distribution data given the value for x is obtained as 687.5.

What is normal distribution?

One of the families of continuous distributions, the standard normal distribution has a mean of zero and a standard deviation of one. Since most observations are grouped around the mean and mean=median=mode, the distribution is symmetric at the mean zero.

The value for mean is μ = 700.

The value for standard deviation is σ = 50.

The probability value is 0.6.

Use z score formula to solve for value of x -

P (X>x) = 0.6

0.6 = 1 - P (X>x)

0.4 = P[{(X-μ)/σ} ≤ {(x-700)/50}]

z0.4 = (x-700)/50

-0.25 = (x-700)/50

x = (-0.25 × 50) + 700

x = -12.5 + 700

x = 687.5

Therefore, the value for x is 687.5.

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To convert 21.73 m to customary units, we need to use the conversion factors as follows:

meter = 39.37 inches1

inch = 2.54

cm1 foot

= 12 inches

We have:

21.7.

3 m

= 21.73 x 39.37 inches (since 1 mete

r = 39.37 inches)

= 856.301 inches

= 71 feet 4.3 inches (since 1 foot = 12 inches)

The smallest tick mark on

1" = 1' 0"

architect’s scale is 1/16 inch.

This means that there are 16 tick marks in an inch. A fractional ruler was used for scale measurements of a line on the 1/4" = 1'-0" scale. The two ends of the line correspond to 6 2.7/4" and 9 6/8". To get the length of the line in inches, we need to convert the two ends to inches, then subtract them to get the length as follows:

\(6 2.7/4" \\= 6 x 12 + 2.7\\ = 74.7"  (since 1 foot\\ = 12 inches)\\9 6/8" = 9 x 12 + 6 \\= 114" (since 1 foo\\t = 12 inches)\)

Length of the line = 114 - 74.7 = 39.3 inches (rounded off to one decimal place)

Multiplying 3/5 by

\(17/13\\ gives:\\3/5 x 17/13\\= (3 x 17)/(5 x 13)\\= 51/65\)

This is already in its lowest form.

Therefore, the answer is:51/65 (an improper fraction)

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Answer:

D

Step-by-step explanation:

(f - g)(x) = f(x) - g(x), so

f(x) - g(x)

= 3x + 1 - (x² - 6) ← distribute by - 1

= 3x + 1 - x² + 6 ← collect like terms

= - x² + 3x + 7 → D

The distance between points A (3, -5) and A' (2, -3) is 2.4 units.

Given that,

The points A (3, -5) and A' (2, -3).

We have to determine,

The distance between point A and A'.

According  to the question,

The distance between two points is determined by using the distance formula.

\(\rm Distance \ formula = \sqrt{(x_2-x_2) ^2+ (y_2-y_2)^2\)

Then,

The distance between points A (3, -5) and A' (2, -3) is,

\(\rm Distance = \sqrt{(2-3) ^2+ ((-3)-(-5))^2}\\\\ Distance = \sqrt{(-1) ^2+ (2)^2}\\\\ Distance = \sqrt{1+4}\\\\Distance = \sqrt{5}\\\\Distance = 2.4 \ units\)

Hence, The distance between points A (3, -5) and A' (2, -3) is 2.4 units.

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Answer:

13.6 units

Step-by-step explanation:

Edge

Answer:

Option D. \(5989.5\pi\) \(cm^3\)

Step-by-step explanation:

Equation for Volume of a sphere

\(V = \frac{4}{3} \pi r^3\)

The question says to leave your volume on \(\pi\) form, meaning don't use 3.14 or any number to represent pi. Your answer should be (some number) * pi in cubic centimeters.

\(V = \frac{4}{3} \pi (16.5)^3\\V = (4492.125)(\frac{4}{3} )\pi \\\\V = 5989.5\pi\)

So the correct answer is Option D, \(5989.5\pi\) \(cm^3\).

Answer:

25.9 feet

Step-by-step explanation:

If you split a rectangle into 2 pieces with a diagonal, each piece will be a right triangle

Therefore we can use the pythagorean theorem to solve this problem

The two legs of the right triangle will be 23 and 12

The formula is a^2 +b^2=c^2

c^2 is the diagonal squared ( the hypotenuse)

So:

12^2+23^2=c^2

144+529=c^2

673=c^2

To find just c we need to find the square root of 673, rounded to the nearest tenth

(the equation is rounded)

So the diagonal is 25.9

Constant of variation for given quadratic equation is 2/3

Correct option is a.

The ratio between two variables in a direct variation or the product of two variables in an inverse variation.

In the direct variation equations = k and y = k x,

and the inverse variation equations x y = k and

k is the constant of variation.

Given,

quadratic equation,

15y = 10x²

y = (10/15)x²

y = (2/3)x²

Comparing it with general form y = kx²

k = 2/3

Hence, 2/3 is constant of variation for the quadratic equation.

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Answer:

This cannot be solved but it can be simplified

first we open the bracket

so we have

a²- abx/x = 2/3

next we cross multiply so it will be 3(a² - abx) = 2x

we get

3a² - 3abx = 2x

Next we factorise so we can get

3a(a-bx) =2x

I dont know what exactly you where asked but I hop this helps

Step 1: Write out the inequality

Step 2: Rewrite the inequality as shown below

Step 3: Subtract 29 from both sides of the inequality

Step 4: Graph the solution of the inequality

Hence, the correct option is G

Answer:

Step-by-step explanation:

ok

If the statement evaluates to true for all possible truth assignments, then it is a tautology. If there is at least one truth assignment that makes the statement false, then it is not a tautology.

To construct a truth table for the statement (¬(p∧(¬q)))⇒(p∨q), we need to evaluate the statement for all possible truth assignments of the variables p and q.

First, let's create a table with three columns: one for the truth value of p, one for the truth value of q, and one for the truth value of the entire statement.

Next, we can fill in the truth values for p and q. Since there are only two variables, p and q, we have 2^2 = 4 possible truth assignments. We can fill in the values for p and q in the first two columns accordingly.

In the third column, we can calculate the truth value of the statement by following the steps:
1. Evaluate the expression ¬(p∧(¬q)).
2. Evaluate the expression p∨q.
3. Determine the truth value of the entire statement (¬(p∧(¬q)))⇒(p∨q) using the truth values of the previous two expressions.

Once we have filled in the truth values for all possible truth assignments, we can analyze the final column to determine if the statement is a tautology or not.

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Based on the formula of the quadratic function y=-x^2+6x-5, we know that its graph is a downward-facing parabola that opens wide, with a vertex at (3,-14), and an axis of symmetry at x=3.

Based on the formula of the quadratic function y=-x^2+6x-5, we can determine several properties of its graph, including its shape, vertex, and axis of symmetry.

First, the negative coefficient of the x-squared term (-1) tells us that the graph will be a downward-facing parabola. The leading coefficient also tells us whether the parabola is narrow or wide. Since the coefficient is -1, the parabola will be wide.

Next, we can find the vertex using the formula:

Vertex = (-b/2a, f(-b/2a))

where a is the coefficient of the x-squared term, b is the coefficient of the x term, and f(x) is the quadratic function. Plugging in the values for our function, we get:

Vertex = (-b/2a, f(-b/2a))

= (-6/(2*-1), f(6/(2*-1)))

= (3, -14)

So the vertex of the parabola is at the point (3,-14).

Finally, we know that the axis of symmetry is a vertical line passing through the vertex. In this case, it is the line x=3.

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The correct formula for the revenue generated by the item is Revenue = 200p - 5p^2.

The revenue generated by the item can be calculated by multiplying the price (p) by the unit sales (200 - 5p). Therefore, the correct formula for the revenue generated by the item is:

Revenue = Price x Unit Sales
Revenue = p(200 - 5p)
Revenue = 200p - 5p^2

The revenue generated by the item is a quadratic function of the price (p). To find the maximum revenue, we need to differentiate the function with respect to p and set it equal to zero:

dRevenue/dp = 200 - 10p = 0
10p = 200
p = 20

Therefore, the maximum revenue is generated when the price of the item is $20. Substituting p = 20 in the revenue formula, we get:

Revenue = 200(20) - 5(20^2) = $2000

Hence, the correct formula for the revenue generated by the item is Revenue = 200p - 5p^2, and the maximum revenue is achieved when the price of the item is $20, generating a revenue of $2000.

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For this visualization, a bar chart would be the best choice.

A bar chart is an effective way to visually compare different categories or groups. In this case, the data analyst can create a bar chart where each bar represents a city, and the height of the bar corresponds to the population of that city. The analyst can include only the top ten most populous cities in North Carolina and color the bars differently based on whether the population is below or above 250,000 people. By doing so, it becomes easy to identify which cities fall below the threshold, as they will have shorter bars compared to those above the threshold. The clear distinction between the bar heights allows for quick visual comparison and provides a straightforward representation of the population distribution among the top ten cities in North Carolina.

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