PLZZ help me wit this I won’t the right answers no facts

A) The Slope is: 2

B) The interpretation of the slope is that there are two races for each number of track meet.

C) The y-intercept from the graph is at: y = 4

D) Equation of the line is: y = 2x + 4

The general form of equation of a line in slope intercept form is:

y = mx + c

where:

m is slope

c is y-intercept

From the given graph, we can see that the slope is gotten from the formula:

A) Slope = (y₂ - y₁)/(x₂ - x₁)

Thus:

Slope = (10 - 4)/(3 - 0)

Slope = 6/3

Slope = 2

B) The interpretation of the slope is that there are two races for each number of track meet.

C) The y-intercept from the graph is at: y = 4

D) Equation of the line is:

y = 2x + 4

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Answer:

Step-by-step explanation:

1/1. The answer is just one. If the answer is a number over itself such as, b/b then it is just b.

Answer:

It doesn't form a right triangle

Step-by-step explanation:

According to the Pythagorean theorem, the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides.

a^2 + b^2 = c^2 by substituting the three values, 10, 15, and 20 you should get an equivalent value of the hypotenuse.

10^2 + 15^2 = 20^2

100 + 225 = 400

325 =/= 400

This is false.

Since this is not equivalent, it is NOT a right triangle.

Hope this helped :)

6/15

you add everything she sells together. ( 3+1+6+5=15) Then you put the amount of ovens she sells above taht number, making it a fraction.

The correct answer is option (a) 001, 002, 003, . .. ,439, 440

The number of individuals or observations included in a study is referred to as the sample size.

Usually, n is used to indicate this number. The size of a sample effects two statistical properties:

1) The accuracy of our estimates, and 2) The ability to draw inferences from the study.

Given:

We must choose an srs of 10 of the 440 retail outlets in new York that sell your company’s products

Sample size, n  = 10

Population size, N = 440

So, we must label the population with numbers 001, 002, 003, . .. ,439, 440.

Thus, each member of the population is correctly identified.

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Answer:

The entire clock measures 360 degrees. As the clock is divided into 12 sections. The distance between each number is equivalent to 30 degrees (360/12)

I hope this helps you!

Answer:

an individual who invested in the market in 2006  has yet to regain the losses incurred in 2008

Step-by-step explanation:

y=-2x+5 is the slope-intercept equation for a line that goes through the point (4,-3) and 5 is the value of b.

The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.

The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.

The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is

m=y₂-y₁/x₂-x₁

We have to find the slope-intercept equation for a line that goes through the point (4,-3)--with a slope of -2

m=-2

Now let us find the y intercept

-3=-2(4)+b

-3=-8+b

-3+8=b

5=b

Hence, y=-2x+5 is the slope-intercept equation for a line that goes through the point (4,-3) and 5 is the value of b.

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Answer:

b

Step-by-step explanation:

just did the test like 20 mins ago good look

Answer:

Parallel

Step-by-step explanation:

Answer:

c) S : {30}

Step-by-step explanation:

a) S : {17}

→ 17 - 3 > 15

→ 14 < 15

So, it is not suitable.

b) S : {18}

→ 18 - 3 > 15

→ 15 = 15

So, it is not suitable.

c) S : {30}

→ 30 - 3 > 15

→ 27 > 15

So, it is correct answer.

d) S : {15}

→ 15 - 3 > 15

→ 12 < 15

So, it is not suitable.

Answer:

Step-by-step explanation:

The domain of any exponential function is "all real numbers."

The value of f(0) is ...

  f(x) = 2^-x

  f(0) = 2^(-0) = 1

_____

Comment on the graph

The free Desmos graphing calculator is an excellent tool for when you "need to see it graphed." It is available in a web browser or as an app for your Android or iOS platform. (I found there to be a little "learning curve", but once you determine the limitations, it is exceptionally useful.) On-line help and tutorials are available, along with some really good examples of use. I can't give you a link, but it is easily found with a search.

Answer:

1 cup glitter i guess

Step-by-step explanation:

Answer:

1 1/2 cups of glitter to each gallon of paint

(a) The errors made by the student are:

Incorrectly expanding 49(2) as 24 instead of 98.

Mistakenly factoring the quadratic equation as (y - 8)(y - 1) instead of

\(y^{2} - 9y + 8.\)

(b) The exact solution to the equation is x = 7/11.

(a) The student made two errors in their solution:

Error 1: In the step \("22x + 49(2) = 0,"\) the student incorrectly expanded 49(2) as 24 instead of 98. The correct expansion should be 49(2) = 98.

Error 2: In the step \("y^{2} - 9y + 8 = 0,"\) the student mistakenly factored the quadratic equation as (y - 8)(y - 1) = 0. The correct factorization should be \((y - 8)(y - 1) = y^{2} - 9y + 8.\)

(b) To find the exact solution to the equation, let's correct the errors made by the student and solve the equation:

Starting with the original equation: \(22x + 4 - 9(2) = 0\)

Simplifying: 22x + 4 - 18 = 0

Combining like terms: 22x - 14 = 0

Adding 14 to both sides: 22x = 14

Dividing both sides by 22: x = 14/22

Simplifying the fraction: x = 7/11

Therefore, the exact solution to the equation is x = 7/11.

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\( \\ \\ \)

\( \\ \\ \)

We know:-

When base and height of triangle is given we use this formula:

\( \bigstar \boxed{ \rm Area \: of \: triangle = \frac{base \times height}{2} }\)

\( \\ \\ \)

So:-

\( \\ \\ \)

\( \dashrightarrow \sf \: Area \: of \: triangle = \dfrac{base \times height}{2} \\ \)

\( \\ \\ \)

\( \dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 10}{2} \\ \)

\( \\ \\ \)

\( \dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times2 }{2} \\ \)

\( \\ \\ \)

\( \dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times\cancel2 }{\cancel2} \\ \)

\( \\ \\ \)

\( \dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times1 }{1} \\ \)

\( \\ \\ \)

\( \dashrightarrow \sf \: Area \: of \: triangle =7 \times 5\)

\( \\ \\ \)

\( \dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2} \\ \)

\( \\ \\ \)

\( \therefore \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} { \red{\bf{yd} }^{ \red2} }}\)

\( \\ \\ \)

\(\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}\)]

The two column proof showing that  ΔWXZ ≅ ΔYXZ is as shown below

From the given triangle, we see that;

Given: WX ≅ XY, XZ bisects WXY

Prove: ΔWXZ ≅ ΔYXZ

The two column proof for the above is as follows;

Statement 1;  WX ≅ XY, XZ bisects 2

Reason 1; Given

Statement 2: ∠WXZ ≅ YXZ

Reason 2; Angle bisector

Statement 3; XZ ≅ XZ

Reason 3: Reflexive property of congruence

Statement 4:  ΔWXZ  ≅ ΔYXZ

Reason 4:  SAS Congruence Postulate

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The expression becomes: p^(1/2) = p^(1/2 * 1) = p^(1/2) Now we can simplify p^(1/2) as p^1/2 which equals the square root of p.

The property of exponents that must be applied to the expression p^(1/2) to derive p as the result is the Power of a Power Property.

The Power of a Power Property states that when a power is raised to another power, the exponents are multiplied.

For instance, consider the expression p^(1/2). We can apply the Power of a Power Property to this expression as follows: p^(1/2) = (p^(1/2))^1 By applying the Power of a Power Property, the exponent (1/2) is multiplied by the exponent 1, giving a result of 1/2.

Therefore, the expression becomes: p^(1/2) = p^(1/2 * 1) = p^(1/2)Now we can simplify p^(1/2) as p^1/2 which equals the square root of p.

So we have derived p as the result using the Power of a Power Property.

In summary, we must apply the Power of a Power Property to the expression p^(1/2) to derive p as the result.

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The correct answer is A. Yes, because the angles are congruent and the sides are proportional.

Two triangles are considered similar if their corresponding angles are congruent and their corresponding sides are proportional. In this case, we are given the triangles ABC and ADEF.

To determine if ABC is similar to ADEF, we need to compare the angles and sides of the two triangles.

If all the angles of one triangle are congruent to the corresponding angles of the other triangle, and the sides of one triangle are proportional to the corresponding sides of the other triangle, then the triangles are similar.

we can say that if the angles of ABC are congruent to the angles of ADEF and the sides of ABC are proportional to the sides of ADEF, then ABC is similar to ADEF.

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Answer:

x = 2

Step-by-step explanation:

Those lines will come together and interact at (2 , 5)

The cost of one dozen of roses as required in the task content is; $11.

It follows from the task content that the cost of one dozen of roses according to the given task content is to be determined.

Let the price of one dozen roses be; x.

Therefore, the price of one dozen of peonies would be; 3x.

Also, since Carnations cost $5 and lilies cost $7;

Hence, the price of the red bouquet is; x + 5.

And, the price of the pink bouquet is; 3x + 7.

Since, it is given that; the cost of five red bouquets is the same as the cost of two pink bouquets; it follows that;

5 ( x + 5 ) = 2 ( 3x + 7 )

5x + 25 = 6x + 14

6x - 5x = 25 - 14

x = 11.

Ultimately, the price of one dozen roses is; $11

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Answer:

No because there are multiple Y values for the same X value. 3 is -1 and 1 at the same time meaning it is not a function.

Step-by-step explanation:

Answer:

10)

Domain: (-∞, ∞)

Range: (∞, 0)

11)

Domain: ( -∞, ∞)

Range: (0, ∞)

I'm not 100% sure this right.

Answer:

y = 3/5x + 12/5

Step-by-step explanation:

y = mx + c

0 = 3/5 ( -4 ) + c

0 = -12/5 + c

12/5 = c

y = 3/5x + 12/5

Answer:

(A)

Step-by-step explanation:

The survey follows of women's height a normal distribution.

The height of 98.51% of women that meet the height requirement are between 58 inches and 80 inches.

The new height requirements would be 57.7 to 68.6 inches

The given parameters are:

\mathbf{\mu = 63.5}μ=63.5 --- mean

\mathbf{\sigma = 2.5}σ=2.5 --- standard deviation

(a) Percentage of women between 58 and 80 inches

This means that: x = 58 and x = 80

When x = 58, the z-score is:

\mathbf{z= \frac{x - \mu}{\sigma}}z=

σ

x−μ

This gives

\mathbf{z_1= \frac{58 - 63.5}{2.5}}z

1

=

2.5

58−63.5

\mathbf{z_1= \frac{-5.5}{2.5}}z

1

=

2.5

−5.5

\mathbf{z_1= -2.2}z

1

=−2.2

When x = 80, the z-score is:

\mathbf{z_2= \frac{80 - 63.5}{2.5}}z

2

=

2.5

80−63.5

\mathbf{z_2= \frac{16.5}{2.5}}z

2

=

2.5

16.5

\mathbf{z_2= 6.6}z

2

=6.6

So, the percentage of women is:

\mathbf{p = P(z < z_2) - P(z < z_1)}p=P(z<z

2

)−P(z<z

1

)

Substitute known values

\mathbf{p = P(z < 6.6) - P(z < -2.2)}p=P(z<6.6)−P(z<−2.2)

Using the p-value table, we have:

\mathbf{p = 0.9999982 - 0.0139034}p=0.9999982−0.0139034

\mathbf{p = 0.9860948}p=0.9860948

Express as percentage

\mathbf{p = 0.9860948 \times 100\%}p=0.9860948×100%

\mathbf{p = 98.60948\%}p=98.60948%

Approximate

\mathbf{p = 98.61\%}p=98.61%

This means that:

The height of 98.51% of women that meet the height requirement are between 58 inches and 80 inches.

So, many women (outside this range) would be denied the opportunity, because they are either too short or too tall.

(b) Change of requirement

Shortest = 1%

Tallest = 2%

If the tallest is 2%, then the upper end of the shortest range is 98% (i.e. 100% - 2%).

So, we have:

Shortest = 1% to 98%

This means that:

The p values are: 1% to 98%

Using the z-score table

When p = 1%, z = -2.32635

When p = 98%, z = 2.05375

Next, we calculate the x values from \mathbf{z= \frac{x - \mu}{\sigma}}z=

σ

x−μ

Substitute \mathbf{z = -2.32635}z=−2.32635

\mathbf{-2.32635 = \frac{x - 63.5}{2.5}}−2.32635=

2.5

x−63.5

Multiply through by 2.5

\mathbf{-2.32635 \times 2.5= x - 63.5}−2.32635×2.5=x−63.5

Make x the subject

\mathbf{x = -2.32635 \times 2.5 + 63.5}x=−2.32635×2.5+63.5

\mathbf{x = 57.684125}x=57.684125

Approximate

\mathbf{x = 57.7}x=57.7

Similarly, substitute \mathbf{z = 2.05375}z=2.05375 in \mathbf{z= \frac{x - \mu}{\sigma}}z=

σ

x−μ

\mathbf{2.05375= \frac{x - 63.5}{2.5}}2.05375=

2.5

x−63.5

Multiply through by 2.5

\mathbf{2.05375\times 2.5= x - 63.5}2.05375×2.5=x−63.5

Make x the subject

\mathbf{x= 2.05375\times 2.5 + 63.5}x=2.05375×2.5+63.5

\mathbf{x= 68.634375}x=68.634375

Approximate

\mathbf{x= 68.6}x=68.6

Hence, the new height requirements would be 57.7 to 68.6 inches

The period of \(f(x)\) is \(\boxed{2\pi}\).

Recall that \(\sin(x)\) and \(\cos(x)\) both have periods of \(2\pi\). This means

\(\sin(x + 2\pi) = \sin(x)\)

\(\cos(x + 2\pi) = \cos(x)\)

Replacing \(x\) with \(3x\), we have

\(\sin(3x + 2\pi) = \sin\left(3 \left(x + \dfrac{2\pi}3\right)\right) = \sin(3x)\)

In other words, if we change \(x\) by some multiple of \(\frac{2\pi}3\), we end up with the same output. So \(\sin(3x)\) has period \(\frac{2\pi}3\).

Similarly, \(\cos(5x)\) has a period of \(\frac{2\pi}5\),

\(\cos(5x + 2\pi) = \cos\left(5 \left(x + \dfrac{2\pi}5\right)\right) = \cos(5x)\)

We want to find the period \(p\) of \(f(x)\), such that

\(f(x + p) = f(x)\)

\( \implies \sin(3x + p) + \cos(5x + p) = \sin(3x) + \cos(5x)\)

On the left side, we have

\(\sin(3x + p) = \sin(3x + 2\pi + p - 2\pi) \\\\ ~~~~~~~~ = \sin(3x+2\pi) \cos(p-2\pi) + \cos(3x+2\pi) \sin(p-2\pi) \\\\ ~~~~~~~~ = \sin(3x) \cos(p-2\pi) + \cos(3x) \sin(p - 2\pi)\)

and

\(\cos(5x + p) = \cos(5x + 2\pi + p - 2\pi) \\\\ ~~~~~~~~ = \cos(5x+2\pi) \cos(p-2\pi) - \sin(5x+2\pi) \sin(p-2\pi) \\\\ ~~~~~~~~ = \cos(5x) \cos(p-2\pi) - \sin(5x) \sin(p-2\pi)\)

So, in terms of its period, we have

\(f(x) = \sin(3x) \cos(p - 2\pi) + \cos(3x) \sin(p - 2\pi) \\\\ ~~~~~~~~ ~~~~+ \cos(5x) \cos(p - 2\pi) - \sin(5x) \sin(p - 2\pi)\)

and we need to find the smallest positive \(p\) such that

\(\begin{cases} \cos(p - 2\pi) = 1 \\ \sin(p - 2\pi) = 0 \end{cases}\)

which points to \(p=2\pi\), since

\(\cos(2\pi-2\pi) = \cos(0) = 1\)

\(\sin(2\pi - 2\pi) = \sin(0) = 0\)

Answer:

Step-by-step explanation:

Claim: if the mean amount of garbage per bin is different from 50.

Null hypothesis: u=50

Alternative hypothesis : u =/ 50

Using the z score formular for a one sample z test - z = (x - u ) / (sd/√n)

Where x = 48.99, u = 50 sd =3.7 and n = 36

z = 48.99 - 50 / (3.7/√36)

z = -1.01 / (3.7/6)

z = -1.01/0.6167

z = -1.6377

To find the p value at a 0.01 level of significant from the -1.6377 z score for a two tailed test the p value using the p value calculator is 0.1016. The result is not significant at 0.01 level of significant thus we will fail to reject the null and conclude that the mean amount of garbage per bin is 50.