PLZ HELPPPPP!! i'll give brainliest

PLZ HELPPPPP!! I'll Give Brainliest

Answers

Answer 1

Answer:

12N to the right.

Explanation:

There is a force of 12N upwards and a force of 12N downwards: these cancel out.

Assign a negative value to forces towards the left, and a positive value to the forces towards the right: -3N and +15N

Combine them: -3N+15N = 12N

The net force has a magnitude of 12N, and since our answer was positive, it acts towards the right.


Related Questions

Find the fundamental period (To) and frequency (Wo) of the following signal:

student submitted image, transcription available below

Answers

The fundamental period (To) of a signal is the smallest T for which it repeats. Frequency (Wo) is the reciprocal of To. Example: To = 0.5s, Wo = 2Hz.

The fundamental period (To) of a periodic signal is the smallest positive value of T for which the signal repeats itself exactly. The frequency (Wo) of a periodic signal is the reciprocal of the fundamental period,

Wo = 1/To.

To find the fundamental period and frequency of a signal, we need to analyze its waveform.

First, let's identify the period of the signal. The period is the horizontal distance between two adjacent peaks (or troughs) of the waveform. If the signal repeats itself exactly, it is periodic.

Once we have identified the period, we can calculate the fundamental period (To) by measuring the distance between two adjacent peaks (or troughs) and taking the smallest positive value.

To calculate the frequency (Wo), we can use the formula Wo = 1/To. Here's an example to illustrate this process:

Let's say the signal waveform repeats itself every 2 seconds. This means the period is 2 seconds.

To calculate the fundamental period (To), we measure the distance between two adjacent peaks (or troughs) and find it to be 0.5 seconds.

Therefore, the fundamental period (To) is 0.5 seconds.

To calculate the frequency (Wo), we use the formula Wo = 1/To. In this case, Wo = 1/0.5 = 2 Hz. So, the fundamental period (To) of the signal is 0.5 seconds and the frequency (Wo) is 2 Hz.

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Part A
Which yoga poses did you perform best? Which poses do you still need to improve on?

Answers

Answer:

Knees to Chest

Be consistent. Setting and committing to a regular practice of yoga is absolutely essential if you want to make improvements. ..

Answer: Dog pose was really easy, but tree pose was really difficult because it was hard to balance.

A 2m 3m m of masses m, 3m, and 2m resting on 15. Three blocks frictionless horizontal surface are connected to above. A force of identical ideal springs, as shown F directed to the left is then applied to magnitude thegefttend of spring A: Which spring is stretched the most when the biocks are all moving with the same acceleration? (A) A (B) B (C) C (D) None, because the springs do not stretch. (E) None, because the springs all stretch the same amount:

Answers

Spring (c) C is stretched the most when the blocks are all moving with the same acceleration.

To determine which spring is stretched the most when the blocks are all moving with the same acceleration, we need to consider the forces acting on each block and the resulting spring forces.

Let's analyze the situation:

1. Block of mass m: The force F applied to the left will create a net force of 2F to the right (since there are two masses of m on the right). This net force will accelerate the block to the right. The spring connected to this block (spring A) will experience a force of 2F to the left.

2. Block of mass 3m: This block is pulled to the right by the two blocks of mass m. The net force acting on this block is also 2F to the right. The spring connected to this block (spring B) will experience a force of 2F to the left.

3. Block of mass 2m: This block is being pulled to the right by the block of mass 3m. The net force acting on this block is F to the right. The spring connected to this block (spring C) will experience a force of F to the left.

Based on the analysis, we can conclude that spring C is stretched the most when the blocks are all moving with the same acceleration. This is because it experiences the highest magnitude of force (F) compared to spring A and spring B, which experience forces of 2F.

Therefore, the correct answer is (C) C: spring C.

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What is the potential energy of a 5.0 N weight that is 3 m above the ground

Answers

Answer:

\(15\:\mathrm{J}\)

Explanation:

The potential energy of an object is given by \(PE=mgh\).

Recall that the weight of an object is equal to the force of gravity on the object. From this, we can set up the following equation and solve for the mass of the object:

\(F=mg,\\5=mg,\\m=\frac{5}{9.81}\approx 0.51\:\mathrm{kg}\)

Now we can plug in values to \(PE=mgh\) and solve:

\(PE=0.51\cdot9.81\cdot3=\fbox{$15\:\mathrm{J}$}\).

Answer:

The potential energy of the body is 15J.

Explanation:

What is potential energy?

The energy possessed to a body due to position is called Potential energy.

U=mgh

Given data:weight (mg)=5Nheight (h)=3mPotential energy (U)=?by using formula

U=mgh

U=5×3=15J

Hence, the potential energy of the body is 15J.

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how do we use visible light to detect chemicals in other atmospheres?

Answers

Simply put different aspects of the electromagnetic spectrum reflect differently. Certain chemicals will absorb different frequencies of light while reflecting others.


A student releases a marble from the top of a ramp. The marble increases speed while
on the ramp then continues across the floor. The marble travels a total of 220cm in
5.00s.
What was the marble's final speed?

Answers

Marble's final speed,  Vf = 0.88 m/s

What is displacement and velocity?

Vector difference between the final and initial positions of an object is displacement. It is different from the distance the object has travelled along the way.

Velocity is a vector quantity and is defined as the displacement that an object undergoes with respect to time . Meter per second is the standard unit of velocity.

Given distance= 220cm and

time = 5 sec

We can calculate acceleration of the marble by using 2nd equation of motion:

s = Vi t + (1/2)at²

s = distance covered = 220 cm = 2.2 m

Let Vi = initial Velocity

= 0 m/s (as the marble was initially at rest)

To find acceleration, a  = ?

2.2 m = (0 m/s)(5 s) + (1/2)(a)(5 s)²

a = (2.2 m)(2) / (5 s)²

a = 0.176 m/s²

Using 1st equation of motion for final velocity (Vf)

Vf = Vi + at

Vf = 0 m/s + (0.176 m/s²)(5 s)

Vf = 0.88 m/s

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from the top of a tal cliff of height y, a soccer ball id kicked horizontally so that it leaves the cliff with a velocity v. assuming air friction is negligible, the speed of the ball just before it hits the ground is:

Answers

The speed of the ball just before it hits the ground is: \(\sqrt{v^{2} + 2 g y }\)

Speed gets the symbol v and velocity gets the symbol v . Average values get a bar over the symbol.

Displacement is measured along the shortest path between two points and its magnitude is always less than or equal to the distance.

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4. In a crime scene sketch, there should always be an arrow to show which direction?
a. South
b. North
c. West
d. East

Answers

Answer:

i think it d

Explanation:

NEED HELP A 400 Ω resistor is connected across 200 V. What current will flow?Single choice.
(2 Points)

0.25 A

0.5 A

2.0 A

4.0 A

Answers

Answer: 0.5A

Explanation:

According to Ohm's law, the Voltage(V) when a current flows through a resistor can be calculated by using the formula:

V = IR

where,

V = Voltage = 200V

I = current in amps (A)

R = resistance in ohms (Ω) = 400Ω

Current = Voltage / Resistance

I = V/R

I = 200/400

I = 0.5A

Therefore, the current is 0.5 Ampere

differences between weightlessness in space and weightlessness in earth​

Answers

Answer:

it depends on a person's own weight

Answer:

The gravity is roughly the same. The inverse square law applies to gravity and that means that being 60 miles above Earth is about the same as being on Earth. The thing is, they are going really fast in an orbit and thus falling around the Earth. The weightlessness comes from a sort of cancellation of gravity pulling them down and their going perpendicular to that force. The forces are cancelling and making them relatively “weightless”. It’s not really weightlessness but just an equilibrium reached between the two accelerations of gravity and their motion against the pull of the Earth.

Explanation:

1d. Conservation of energy is demonstrated in this roller coaster example.
The Conservation of Energy is a principle which states that energy cannot be created
or destroyed, but can be altered from one form to another
Friction plays a significant role in the efficiency of the rollercoaster cars. Explain how, even
with friction, the law of conservation of energy still holds true. (2 points)

1d. Conservation of energy is demonstrated in this roller coaster example.The Conservation of Energy

Answers

Answer:

According to the principle of the Conservation of Energy, energy can neither be destroyed or created, energy can be transformed from form to another

The forms of energy the car has at the different stages is given by virtue of either the position of the car, which is the car's potential energy, or the speed of the car, which gives the potential energy of the car

However, due to the frictional forces acting on the car, there is a frictional force which requires work to be done for the car to move between points in the roller coaster

Therefore, based on the Conservation of Energy principle, we have;

The total energy of the roller coaster, M.E. = m·g·\(h_{max}\)

Where;

m = The mass of the roller coaster = 4,500 kg

g = The acceleration due to gravity ≈ 9.81 m/s²

\(h_{max}\) = The maximum height = 30 m

Therefore, M.E.\(_A\) = 4,500 × 9.81 × 30 = 1,324,350 J

The energy at point B, \(M.E._B\) = 4,500×15×9.81 + (1/2) ×4,500×17.15² = 1,323,950.625

The energy at point B, \(M.E._B\) = 1,323,950.625 J

At point C, the total energy, \(M.E._C\) = (1/2)·m·v²

Where;

v = The velocity of the roller coaster at point c = 24.25 m/s

Therefore;

\(M.E._C\) = (1/2) × 4,500 × 24.25² = 1,323,140.625

At point C, the total energy, \(M.E._C\) = 1,323,140.625 J

Therefore, given that the energy at point A, M.E.\(_A\) is larger than the energy at point B, \(M.E._B\), is larger than the energy at point C, \(M.E._C\), the loss in energy can be explained by the presence of the friction which require energy for movement of the roller coaster between the points

Explanation:

a car moves at constant speed along a circular smooth road clock wise. what are the directions of velocity and acceleration vectors at the instant it is at the highest point of the path? a) the velocity is towards the left of the page and the acceleration is towards the top of the page. b) the velocity is towards the right of the page and the acceleration is towards the bottom of the page. c) the velocity is towards the left of the page and the acceleration is towards the bottom right of the page. d) the velocity is towards the right of the page and the acceleration is towards the top right of the page. e) the velocity is towards the left of the page and the acceleration is towards the bottom right of the page.

Answers

The direction of the acceleration vector is towards the top right of the page, at a 90-degree angle to the velocity vector. The correct answer is (d) "the velocity is towards the right of the page and the acceleration is towards the top right of the page".

At the highest point of the circular path, the direction of the velocity vector is tangential to the circle and points to the right of the page, which is the direction of motion. The acceleration vector points towards the center of the circle, which is the direction of centripetal acceleration.

Since the car is moving at a constant speed, there is no component of acceleration in the tangential direction. The magnitude of the centripetal acceleration is given by the formula a = v^2/r, where v is the velocity and r is the radius of the circle.

Therefore, the direction of the acceleration vector is towards the top right of the page, at a 90-degree angle to the velocity vector.

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Which country has more nuclear power stations, the UK or France?

Answers

Answer: FRANCE

Explanation:

Answer:

France

Explanation:

UK has 15 nuclear power plants and 2 under construction whereas France has 56 in operation and 1 under construction  

Find solutions for your homework engineering electrical engineering electrical engineering questions and answers b. a feedback amplifier is to be designed using a feedback loop connected around a two-stage amplifier. the first stage is a directcoupled, small-signal amplifier with a high upper 3-db frequency. the second stage is a power-output stage with a midband gain of 10 v/v and upper and lower 3-db frequencies of 8khz and 80 hz, respectively. the feedback amplifier Question: B. A Feedback Amplifier Is To Be Designed Using A Feedback Loop Connected Around A Two-Stage Amplifier. The First Stage Is A Directcoupled, Small-Signal Amplifier With A High Upper 3-DB Frequency. The Second Stage Is A Power-Output Stage With A Midband Gain Of 10 V/V And Upper And Lower 3-DB Frequencies Of 8kHz And 80 Hz, Respectively. The Feedback Amplifier please help me with this problem,thank you  Show transcribed image text Expert Answer 1st step All steps Final answer Step 1/1  View the full answer  Final answer Transcribed image text: B. A feedback amplifier is to be designed using a feedback loop connected around a two-stage amplifier. The first stage is a directcoupled, small-signal amplifier with a high upper 3-dB frequency. The second stage is a power-output stage with a midband gain of 10 V/V and upper and lower 3-dB frequencies of 8kHz and 80 Hz, respectively. The feedback amplifier should have a midband gain of 100 V/V and an upper 3−dB frequency of 40kHz. What is the required gain of the small-signal amplifier? What value of β should be used? What does the lower 3-dB frequency of the overall amplifier become? (15%)

Answers

Ans - The required gain of the small-signal amplifier is 10 V/V and the value of β should be 1/10 to achieve a feedback amplifier with a midband gain of 100 V/V and an upper 3-dB frequency of 40 kHz.

Solution ;
1. Required gain of the small-signal amplifier:
The feedback amplifier is expected to have a midband gain of 100 V/V. Since the first stage is a direct-coupled, small-signal amplifier, its gain will directly affect the overall gain. Let's denote the gain of the small-signal amplifier as A.
Using the formula for gain in a feedback amplifier (A_f = A / (1 + Aβ)), where A_f is the desired overall gain and β is the feedback factor, we can substitute the given values:
100 V/V = A / (1 + Aβ)
To solve for A, we need to find the value of β.

2. Value of β:
β represents the fraction of the output signal that is fed back to the input. In this case, the feedback loop is connected around the second stage of the amplifier. The midband gain of the second stage is given as 10 V/V. So, the feedback factor β can be calculated as:
β = Gain of the second stage / (1 + Gain of the second stage)
β = 10 / (1 + 10) = 10 / 11

3. Lower 3-dB frequency of the overall amplifier:
The lower 3-dB frequency of the overall amplifier is determined by the lower 3-dB frequency of the second stage. The given lower 3-dB frequency of the second stage is 80 Hz. Since the feedback loop is connected around the second stage, the lower 3-dB frequency of the overall amplifier will remain the same, which is 80 Hz.

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An ideal gas, initially at a volume of 0.777778 L and pressure of 9 kPa, undergoes isothermal expansion until its volume is 7 L and its pressure is 1 kPa. Calculate the work done by the gas during this process. Answer in units of J.

Answers

For an ideal gas, initially at a volume of 0.777778 L,  the work done by the gas during this process is mathematically given as

w=15.380613

What is the work done by the gas during this process.?

Generally, the equation for the work done  is mathematically given as

W=p1v1invfvi

Therefore

v2=p1v1/p2

v2=9*1.0.77778/1

v2=7.00002

In conclusion

w=7.00002ln7/0.777778

w=15.380613

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Sunspots appear dark because they are cooler than the surrounding solar surface. True or false

Answers

Answer:

False, Sunspots appear dark (in visible light) due to their low temperature(cooler) than rest of the sun

Explanation:

Sunspots appear dark because they are much cooler( have low temperature than the rest of the surface contained by Sun. As they appear dark, but still they have very temperature that's why so hot. Sunspots have temperatures ranges  3,500 Celsius (3773 kelvin) and the surrounding surface of the sun has a temperature much higher of about 5,500 Celsius(5773 Kelvin). Even if we see a sunspot alone in space,  it will glow so brightly.

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A ball of mass m falls from height hi to height hf near the surface of the Earth. When the ball passes hf it has speed vf. Ignore air resistance, and assume that any changes in kinetic energy of the Earth are negligible. Also, the starting velocity of the ball is zero. Write an expression for each of the following quantities in terms of the given variables and any physical constants. If any of these are zero, state so explicitly. 1. The change in the kinetic energy of the system (the ball and the earth). 2. The change in potential energy of the system. 3. The net external work by external forces on the system 4. Now write an equation that relates the expressions above and use it to solve for the final speed of the ball.

Answers

1. The change in the kinetic energy of the system is given by the expression ΔKE = 1/2 * m * (vf^2 - 0^2) = 1/2 * m * vf^2, where m is the mass of the ball and vf is its final velocity. The change in potential energy of the system is given by the expression ΔPE = m * g * (hi - hf), where g is the acceleration due to gravity near the surface of the Earth (approximately 9.8 m/s^2).

The net external work by external forces on the system is zero, since the only force acting on the ball is the force of gravity, which is a conservative force and does not do any work on the ball.

Using the conservation of energy principle, we can write the equation ΔKE + ΔPE = 0, which implies that 1/2 * m * vf^2 + m * g * (hi - hf) = 0. Solving for vf, we get vf = √(2gh), where h = hi - hf is the height from which the ball falls. This is the final speed of the ball when it reaches height hf near the surface of the Earth, assuming no air resistance and negligible changes in kinetic energy of the Earth.

Let's write expressions for each quantity using the given terms and physical constants:

1. The change in kinetic energy of the system (the ball and the Earth):
ΔKE = ½mvf² - ½m(0)² = ½mvf²

2. The change in potential energy of the system:
ΔPE = mghf - mghi = mg(hf - hi)

3. The net external work by external forces on the system:
Since there is no air resistance and changes in Earth's kinetic energy are negligible, the net external work is zero.
W_ext = 0

4. Now, let's write an equation that relates the expressions above and use it to solve for the final speed of the ball. We'll use the work-energy theorem:
W_ext = ΔKE + ΔPE

Since W_ext = 0, we can rewrite the equation as:
0 = ½mvf² + mg(hf - hi)

To solve for vf, rearrange the equation:
½mvf² = -mg(hf - hi)
vf² = -2g(hf - hi)
vf = sqrt(-2g(hf - hi))

So, the final speed of the ball is given by the expression:
vf = sqrt(-2g(hf - hi))

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Calculate the energy of a photon released by the n = 5 to n = 2 transition in the hydrogen emission spectrum.
A. 2.76×10^5 J
B. -2.76×10^5 J
C. 4.58×10^-19 J
D. 6.32×10^-19 J
E. -4.58×10^-19 J
^

Answers

The energy of the photon is C. 4.58×10^-19 J

How to calculate the energy of a photon

The energy of a photon released by a transition can be calculated using the formula:

E = hc/λ

where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J*s), c is the speed of light (2.998 x 10^8 m/s), and λ is the wavelength of the photon.

To find the wavelength of the photon released by the n=5 to n=2 transition in hydrogen, we can use the Rydberg formula:

1/λ = R (1/n1^2 - 1/n2^2) where

R is the Rydberg constant (1.097 x 10^7 m^-1), and n1 and n2 are the initial and final energy levels, respectively.

Plugging in the values for n1=5 and n2=2, we get:

1/λ = R (1/5^2 - 1/2^2) 1/λ = R (0.0304) λ = 32.8 nm

Now we can calculate the energy of the photon:

E = hc/λ E = (6.626 x 10^-34 J*s) x (2.998 x 10^8 m/s) / (32.8 x 10^-9 m) E = 4.58 x 10^-19 J

Therefore, the correct answer is C. 4.58 x 10^-19 J.

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The foundation of quantum mechanics is that of wave–particle ________.

Answers

Answer:

Wave-Particle Duality.

an electric blanket is connected to a 220-v outlet and consumes 150 w of power. what is the resistance of the heater wire in the blanket?

Answers

The resistance of the blanket is 3226 Ω

V (Voltage) = 220 V

P (Power) = 150W

Joule’s law of heating gives a direct relation between the applied voltage(V) , the time(T) for which the current(I) passes through the object and the resistance(R) of the object.

Therefore according to the joule's heating law

H (heat dissipated ) = ((voltage)² × time )

                                             resistance (R)

According to the concept of power

P (Power) = heat / time

Substituting the value of heat in the expression of heat removes time and gives a formulae

P = V²/R

P = (220 × 220 )/R

             

R = 220 × 220 / 150

           

R = 3226  Ω

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If a power source provides 54 watts of power to operate a machine that draws 4.5 amps of current when in use, what is the voltage used by the machine?

Answers

Answer:

.V=12v

Explanation:

P=VI

54W=V×4.5A

V=54W/4.5A

V=12V

The waves in the electromagnetic spectrum have a speed that A. Increases in proportion to the frequency of the wave B. Increase in proportion to the wavelength of a wave C. That stays the same

Answers

Answer:

B. Increase in proportion to the wavelength of a wave.

Explanation:

An electromagnetic spectrum refers to a range of frequency and wavelength that an electromagnetic wave is distributed or extends. The electromagnetic spectrum comprises of gamma rays, visible light, ultraviolet radiation, x-rays, radio waves, and infrared radiation.

Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.

Generally, the most commonly used electromagnetic wave technology in telecommunications is radio waves.

Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m. Therefore, radio waves are a series of repetitive valleys and peaks that are typically characterized of having the longest wavelength in the electromagnetic spectrum.

Wavelength is simply the distance from one peak of an electromagnetic wave to the next peak. This distance is also equal to the distance from one trough of a wave to another.

Mathematically, wavelength is calculated using this formula;

\( Wavelength = \frac {speed}{frequency} \)

Hence, the waves in the electromagnetic spectrum have a speed that increase in proportion to the wavelength of a wave.


Hint In the previous sections, you found v² = 2ugd and determined you could
plot v² on the vertical axis and d on the horizontal axis to get a straight line
where the slope is equal to 2µg.

Hint In the previous sections, you found v = 2ugd and determined you couldplot v on the vertical axis

Answers

Answer:

Explanation:

Based on the given hint, it appears that the question is related to the analysis of a physics experiment involving the relationship between velocity, distance, and acceleration due to gravity.

Given that the formula v² = 2ugd is being used, it suggests that the experiment involves dropping an object from a height d and measuring the distance it travels over time, as well as the final velocity it reaches. By plotting the squared velocity (v²) on the vertical axis and distance (d) on the horizontal axis, a straight line can be obtained with a slope of 2ug, where u is the coefficient of friction and g is the acceleration due to gravity.

However, without further information or data from the experiment, it is impossible to determine the specific value of the scale factor used.

a 1 cm wide diffraction grating has 1000 slits. It is illuminated by light of wavelength 550 nm. What are the angles of the first 2 diffraction orders?

Answers

The angles of the first two diffraction orders are 33.08° and 69.24°, respectively.

Find the angles for the first two diffraction orders of a 1 cm wide diffraction grating with 1000 slits and illuminated by 550 nm light

The angles of the first two diffraction orders can be calculated using the equation:

sinθ = mλ/d

Where:

θ is the angle of diffraction

m is the order of the diffraction (m = 1 for the first order, m = 2 for the second order)

λ is the wavelength of the light

d is the distance between the slits (d = 1/1000 cm = 0.0001 cm)

Substituting the given values, we get:

sinθ1 = (1)(550 nm) / (0.0001 cm) = 0.55

θ1 = sin⁻¹(0.55) = 33.08°

sinθ2 = (2)(550 nm) / (0.0001 cm) = 1.10

θ2 = sin⁻¹(1.10) = 69.24°

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the speed of light in sapphire is 1.69 x 10^8 m/s. determine the index of refraction for sapphire.​

Answers

Answer:

1.775 is the answer

Explanation:

We can figure out the index of refraction of the sapphire by using the following equation n = c/v

n  =  index of refraction

c  =  speed of light in a vacuum

v  =  speed of light traveling in medium

Step 1 :

v = 1.69 × 10^8

c = 3 × 10^8

Step2: Substitute values

n = c/v -----> n = 3 × 10^8 / 1.69 × 10^8 = 3/1.69 = 1.775

Index of refraction of sapphire is 1.775

Two small point charges are charged by transferring a number of electrons from Q to q. The charges on the two points are equal and opposite, and the point charges are separated by 12.7 mm in air. Calculate the charge on Q and q if there is an attractive force of 22.5 µN between them. Use k = 8.99 x 10⁹ Nm²c-².​

Answers

899000000000
Cause 8.99•10^9

Which two types of potential energies would be types of mechanical energies? electrical and kinetic nuclear and chemical radiant and thermal elastic and gravitational

Answers

The two types of  potential energies that would be types of mechanical energies are:

thermal elastic energy and gravitational energy.

What is potential energy?

The term potential energy is the energy possessed by a body by virtue of its position. It is different from kinetic energy which is due to the state of motion of a body.

The two types of  potential energies that would be types of mechanical energies are;

thermal elastic and gravitational energy.

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Answer: D - elastic and gravitational

Explanation: Edge 2023

Consider a 84.0 kg ice skater who is spinning on the ice. What is the moment of inertia of the skater, if the skater is approximated to be a solid cylinder that has a 0.150 m radius and is rotating about the center axis of the cylinder.

Answers

The moment of inertia of the ice skater can be calculated using the formula for the moment of inertia of a solid cylinder. The moment of inertia of a solid cylinder rotating about its central axis is given by the equation I = (1/2)MR^2, where I is the moment of inertia, M is the mass, and R is the radius of the cylinder.

(a) To calculate the moment of inertia of the skater, we use the formula I = (1/2)MR^2. Plugging in the values:

I = (1/2) * (84.0 kg) * (0.150 m)^2

I ≈ 0.945 kg·m²

(b) The moment of inertia of the ice skater is approximately 0.945 kg·m².

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Solve for the missing variable for each set. Showing ALL work through GUESS Method. Given, Unknown, Equation, Setup, Solve. 1. P=?, M=20 kg, V=5 m/s 2. P= 3000 kg(m/s), M=?, V=75 m/s

Answers

Answer:

(1) P = 100 kg-m/s (2) M = 40 kg.

Explanation:

We need to solve the missing variable :

1. P=?, M=20 kg, V=5 m/s

If M is mass, V is velocity, then momentum P is given by :

P = MV

P = 20 kg × 5 m/s

P = 100 kg-m/s

(2) P= 3000 kg(m/s), M=?, V=75 m/s

\(M=\dfrac{P}{V}\\\\M=\dfrac{3000}{75}\\\\M = 40\ kg\)

Hence, P = 100 kg-m/s and M = 40 kg.

can someone please answer this, ill give you brainliest and your getting 100 points.

can someone please answer this, ill give you brainliest and your getting 100 points.

Answers

Explanation:

Look at South American and African plates

They are going away from each other

There is a heavy chance of getting youngest rock

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