Plz help this is a fix ur grade

To calculate the molecular weight of a gas with a density of 1.524 g/l at STP, we can use the ideal gas law: PV = nRT. At STP, the pressure (P) is 1 atm, the volume (V) is 22.4 L/mol, and the temperature (T) is 273 K. The molecular weight of the gas with a density of 1.524 g/L at STP is approximately 32.0 g/mol.

Rearranging the equation, we get n = PV/RT.

Next, we can calculate the number of moles (n) of the gas using the given density of 1.524 g/l. We know that 1 mole of any gas at STP occupies 22.4 L, so the density can be converted to mass by multiplying by the molar mass (M) and dividing by the volume: density = (M*n)/V. Rearranging the equation, we get M = (density * V) / n.

Substituting the given values, we get n = (1 atm * 22.4 L/mol) / (0.0821 L*atm/mol*K * 273 K) = 1 mol. Then, M = (1.524 g/L * 22.4 L/mol) / 1 mol = 34.10 g/mol. Therefore, the molecular weight of the gas is 34.10 g/mol.

To calculate the molecular weight of a gas with a density of 1.524 g/L at STP, you can follow these steps:

1. Recall the ideal gas equation: PV = nRT

2. At STP (Standard Temperature and Pressure), the temperature (T) is 273.15 K and the pressure (P) is 1 atm (101.325 kPa).

3. Convert the density (given as 1.524 g/L) to mass per volume (m/V) by dividing it by the molar volume at STP (22.4 L/mol). This will give you the number of moles (n) per volume (V):

  n/V = (1.524 g/L) / (22.4 L/mol)

4. Calculate the molar mass (M) of the gas using the rearranged ideal gas equation, where R is the gas constant (8.314 J/mol K):

  M = (n/V) * (RT/P)

5. Substitute the values and solve for M:

  M = (1.524 g/L / 22.4 L/mol) * ((8.314 J/mol K * 273.15 K) / 101325 Pa)

6. Calculate the molecular weight of the gas:

  M ≈ 32.0 g/mol

Therefore, the molecular weight of the gas with a density of 1.524 g/L at STP is approximately 32.0 g/mol.

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Answer:

22

every term is being added by 6

-2 + 6 = 4

4 + 6 = 10

10 + 6 = 16

16 + 6 = 22

Step-by-step explanation:

Answer:

-8 +6n

Step-by-step explanation:

Explicit rule:

\(a_{1} = -2\)

d = Common difference = term 2 - term 1

                                 = 4 -(-2) = 4 + 2 = 6

\(a_{n}=a_{1}+d*(n-1)\\\\a_{n}=-2 + 6*(n-1)\\\\a_{n}= -2 +6n - 6\\\\\\\)

   = -2 - 6 + 6n

   = -8 + 6n

the answer is on the picture

Answer:

A is the answer men thanks for the brainliest really appreciate

Answer:

11/30

Step-by-step explanation:

Answer:

1/2 a revolution in a second

Step-by-step explanation:

BRAINLIEST, PLEASE!

Answer:

Hello! answer: b = 75

Step-by-step explanation:

We have to find b so we have to work backwards to find the answer the steps would be to find c^2 subtract that by a^2 and then you get b^2 and have to find out what multiplied by itself equals b^2 so... 85 × 85 = 7225 40 × 40 = 1600 7225 - 1600 = 5625 75 × 75 = 5625 therefore b = 75 hope that helps!

Probably not all driving scenarios can be accurately simulated by a driving simulator. Additionally, it's likely that simulator users have a different mindset than when they're actually behind the wheel.

The cited data:

Idea applied in experiment:

A driving simulator is therefore unlikely to adequately replicate all driving scenarios, which is one of our concerns about extending the outcomes of such an investigation.

Thus, users of driving simulators are also probably in a different frame of mind than they are while driving is real life.

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The given sets are

The given question is

This means we need to list the comment elements in both sets

Since the common letters are t and a, then

Dilation refers to the transformation of an object in such a way that it becomes larger or smaller but preserves the same shape. The scale factor determines the degree of magnification or reduction. There are two types of dilation; enlargement and reduction.

Determine the type of dilation shown and the scale factor used.Enlargement with a scale factor of 1.5An enlargement is a type of dilation that makes an object bigger.

The scale factor is the ratio of the corresponding lengths. In this case, the original length is multiplied by 1.5 to obtain the new length. The scale factor is greater than 1, indicating that the image is larger than the pre-image.

This is a uniform scale factor. Example: If the original length is 4 cm, the new length is 4 × 1.5 = 6 cm.Enlargement with a scale factor of 2.5An enlargement with a scale factor of 2.5 is similar to the previous example. The original size is multiplied by 2.5 to get the new size.

This is also a uniform scale factor. The image is larger than the pre-image, as indicated by the scale factor of 2.5. Example: If the original length is 3 cm, the new length is 3 × 2.5 = 7.5 cm.Reduction with a scale factor of 1.5A reduction is a type of dilation that makes an object smaller.

The scale factor is less than 1. In this case, the original length is multiplied by 0.67 (which is 1/1.5) to get the new length. The image is smaller than the original, as indicated by the scale factor of 0.67. This is also a uniform scale factor. Example: If the original length is 6 cm, the new length is 6 × 0.67 = 4.02 cm.

Reduction with a scale factor of 2.5A reduction with a scale factor of 2.5 is similar to the previous example. The original size is multiplied by 0.4 to get the new size. The image is smaller than the pre-image, as indicated by the scale factor of 0.4. This is also a uniform scale factor.

Example: If the original length is 5 cm, the new length is 5 × 0.4 = 2 cm.

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Answer:

\(-2\sqrt{3}\)

Step-by-step explanation:

\(5\sqrt{27} -17\sqrt{3} =5*3\sqrt{3} -17\sqrt{3}\)

\(=15\sqrt{3} -17\sqrt{3}\)

=\(-2\sqrt{3}\)

The purpose of a variable is to hold and represent a value Option C.

The purpose of a variable in programming or mathematics is to hold and represent a value that can be assigned, changed, and used in various operations or calculations. Variables are fundamental components of programming languages and mathematical equations, enabling flexibility and dynamic behavior in computational tasks.

Option (c) "to hold a value" is the most accurate answer, as variables are used to store data or information in memory locations. This value can be of different types, such as integers, floating-point numbers, characters, or even more complex data structures like arrays or objects.

Variables allow programmers to work with and manipulate data efficiently. By assigning values to variables, we can reference and modify them throughout the program, making it easier to manage and organize information.

Variables also play a crucial role in performing calculations, as mentioned in option (b). We can use variables in mathematical expressions and algorithms to perform arithmetic operations, comparisons, and other computations. By storing values in variables, we can reuse them in multiple calculations and update them as needed.

While option (a) "to assign values" is a specific use case of variables, it is not the sole purpose. Variables not only store values but also facilitate data manipulation, control flow, and the implementation of algorithms and logic.

Option (d) "to hold a constant value" is incorrect because variables, by definition, can hold varying values. Constants, on the other hand, are fixed values that do not change during the execution of a program. Option C is correct.

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The board is 3 1/6 feet left. The correct option is C.

To find out how much of the board is left, we need to subtract the length of the section that was cut off from the original length of the board:

6 2/3 - 3 1/2

To subtract these two mixed numbers, we need to find a common denominator. The smallest common denominator of 3 and 2 is 6:

Next, we can simplify the fractions,

62/3 - 3 1/2

= 20/3 - 7/2

= (40 - 21)/6

= 19/6

= 3 1/6 feet.

Therefore, the answer is C. 3 1/6 feet.

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Answer:

have calculated all the numbers that 2838 is evenly divisible by. The numbers that 2838 is divisible by are 1, 2, 3, 6, 11, 22, 33, 43, 66, 86, 129, 258, 473, 946, 1419, and 2838. You may also be interested to know that all the numbers that 2838 is divisible by are also known as the factors of 2838.

Any number greater than 3.

Step-by-step explanation:

To find the answers to this question, start by solving the inequality for x.

2x - 1 > x + 2

x - 1 > 2

x > 3

Using this, we now know that any number that is greater than 3 would work for this inequality.

Answer:

Step-by-step explanation:

.4

.5

e) The test statistic and P-value for the chi-square test of homogeneity would be -1.75 and 0.004, respectively.

A chi-square test of homogeneity is a useful tool for comparing two or more categorical variables. In this case, the two variables are smoking (smokers and non-smokers) and alcohol consumption (those who had consumed alcohol in the past week and those who hadn't).

The chi-square statistic is calculated by finding the difference between the observed and expected frequencies of the two groups and squaring it. The expected frequencies are found by multiplying the sample size by the overall probability of success (in this case, drinking alcohol).

The P-value is then calculated based on the chi-square statistic and the degrees of freedom (in this case, one). In this case, the chi-square statistic is -1.75 and the P-value is 0.004.

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The mistake made by Enduro is that he is supposed to divide both sides by -4 instead of adding 4 to each sides

Inequalities are expressions that have unequal values, when compared

The inequality is given as

-4x > 120

When 4 is added to both sides, the inequality becomes

4 - 4x > 120 + 4

The above is not the solution to the inequality.

The solution is as follows:

We have:

-4x > 120

Divide both sides inequality by -4

x < -30

Hence, the mistake made by Enduro is that he is supposed to divide both sides by -4 instead of adding 4 to each sides

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The upper control limit (UCL) with three-sigma limits for the mean of software upgrade time in minutes can be determined by multiplying the standard deviation by three and adding it to the mean. However, since the mean and standard deviation are not provided in the question, a specific numerical answer cannot be given.

In statistical process control, the three-sigma control limits are commonly used to establish the range within which a process is considered to be in control. The three-sigma limits represent a statistical measure that encompasses approximately 99.7% of the data if the process is stable and normally distributed.

By calculating the UCL using the mean and standard deviation, organizations can set an upper boundary that helps monitor the software upgrade time. If any data point exceeds the UCL, it suggests a potential variation or issue in the process, warranting further investigation and corrective actions to ensure the software upgrade time remains within acceptable limits. The UCL serves as a reference point for identifying significant deviations from the expected mean and facilitates continuous process improvement in software upgrade operations.

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Answer:

1) Measure angle QWT and TWX are complementary because their measures add up to 90 degrees.

2) Both measure angles add up to 90 degrees because they're complementary.

3) Angle QWT = 2x and angle TWX = x + 6, and since angles QWT + TWX = 90 then 2x + x + 6 = 90.

4) (Made up?:) Angle measure QWX = 90. The quarter-turn, or the small square, indicates that the angle is 90 degrees.

5) (?)

6) x = 28 because it fulfills the equation, 2x + x + 6 = 90, or 3x + 6 = 90. 90 - 6 is 84, and 84/3 is 28.

Please, tell me if I did anything wrong. I'll gladly edit it.

Answer:

Step-by-step explanation:

2). Definition of complementary angles;

3). Substitution+combine like terms;

4). 3x+ 6 - 6 = 90 - 6   Subtraction Property

5). 3x/3 = 84/3    Division Property  

6). Q.E.D. ("that which was to be demonstrated")

Answer!

5²: 25, 20+5

6³: 216, 200+10+6

4³: 64, 60+4

The sample that will produce the largest value for a t statistic is the one with the largest mean difference (MD) and the smallest sum of squares (SS). In this case, the sample with MD=10 and SS=20 would yield the largest t statistic value.

The magnitude of the t statistic in hypothesis testing is influenced by several factors, including the sample size, the mean difference between groups (MD), and the sum of squares (SS) within each group. However, other factors such as the variability of scores and the alpha level also play a role.

When comparing different samples with the same sample size of n=10, the sample that produces the largest t statistic will have a combination of a larger MD and a smaller SS. The MD reflects the difference in means between two groups or conditions, while the SS represents the variability or dispersion of scores within each group.

In this scenario, comparing the given options, the sample with MD=10 and SS=20 would result in the largest t statistic. This means that there is a greater difference between the means of the two groups and a relatively smaller variability within each group. A larger t statistic suggests a more significant difference between the groups, which strengthens the evidence against the null hypothesis.

It's important to note that the t statistic alone does not provide a complete understanding of the practical significance or effect size of the observed difference. Additional measures, such as confidence intervals or effect size calculations, should be considered to gain a more comprehensive interpretation of the findings.

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The relationships between the numerator and denominator coefficients of a circuit and the values of resistance (R), inductance (L), and capacitance (C) depend on the specific circuit configuration and the transfer function associated with it.

In general, the numerator coefficients of the transfer function represent the output variables of the circuit, while the denominator coefficients represent the input variables. The coefficients are determined by the circuit elements (R, L, C) and their interconnections.

For example, in a simple RC circuit (resistor and capacitor), the transfer function can be written as a ratio of polynomials in the Laplace domain. The denominator coefficients correspond to the characteristic equation of the circuit and involve the resistance and capacitance values. The numerator coefficients may be related to the initial conditions or external inputs.

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Answer:

7

Step-by-step explanation:

3(y+5)=36

divide both sides by 3

y+5=12

minus 5

y=7

Three times the sum of a number y, and 5 is at most 36 is equivalent to  y = 7

Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions. The operator that performs the arithmetic operation is called the arithmetic operator.

Operators which let do a basic mathematical calculation

+ Addition operation: Adds values on either side of the operator.

For example 12 + 2 = 14

- Subtraction operation: Subtracts the right-hand operand from the left-hand operand.

for example 12 -2 = 10

* Multiplication operation: Multiplies values on either side of the operator

For example 12*2 = 24

Given that three times the sum of a number y, and 5 is at most 36.

⇒ 3(y+5)=36

Divide both sides by 3

⇒ y + 5 = 12

Subtract by 5 in the equation

⇒ y = 7

Hence, three times the sum of a number y, and 5 is at most 36 is equivalent to  y = 7

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When y = 100, x is approximately equal to 0.04.

If y varies inversely as x^2 and y = 16 when x = 5, we can find the values of x and y when y = 100.

To solve this problem, we can use the inverse variation formula, which states that y = k/x^2, where k is the constant of variation.

Given that y = 16 when x = 5, we can substitute these values into the formula to find the value of k.

16 = k/(5^2)
16 = k/25

To find k, we can cross multiply:
16 * 25 = k
400 = k

Now that we know the value of k, we can use it to find the value of y when x = 100.

y = k/(100^2)
y = 400/(100^2)
y = 400/10000
y = 0.04

Therefore, when y = 100, x is approximately equal to 0.04.

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Answer:

It doesn't say what to do with that 0.1 of a gallon. I would buy another gallon or dilute what I had so it came to exactly 9.1 gallons. In math, I suppose the answer is 9.

In reality it would be 10.

You have to choose.  What has been done with other questions like this.

Step-by-step explanation:

1 can covers 55 square feet.

h = 10

w1 = 10 feet

w2 = 10 feet

w3 = 15 feet

w4 = 15 feet

Total area = Area of wall 1 + wall 2 + wall 3 + wall 4

Total area = 10*10 + 10*10 + 10*15 + 10* 15

Total area = 100  + 100 + 150 + 150

Total area = 500  feet^2

1 gallon / 55 ft^2 = x / 500 ft^2          Cross multiply

55 * x = 500                                       Divide by 55

x = 500/55

x = 9.1 gallons.

In real life you would buy another gallon.

an equation showing a way to estimate to the neasrt inch the total rainfall for the two day 2.45 + 1.72 ≈ 4.2 inches

1. Add the two amounts of rainfall together: 2.45 + 1.72

2. Round the answer to the nearest inch: 4.2 inches

3. The equation to estimate the total rainfall for the two days is 2.45 + 1.72 ≈ 4.2 inches.

This equation provides a simple way to estimate the total rainfall for two days. By adding the two amounts of rainfall, we can then round the answer to the nearest inch to obtain the estimated total rainfall. This equation can be used to quickly and accurately estimate rainfall totals for any two-day period.

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Answer:

\(\frac{27y^6}{8x^{12}}\)

Step-by-step explanation:

1) Use Product Rule: \(x^ax^b=x^{a+b}\).

\((\frac{3x^{-5+2}{y^3}}{2z^0yx}) ^3\)

2) Use Negative Power Rule: \(x^{-a}=\frac{1}{x^a}\).

\((\frac{3\times\frac{1}{x^3} y^3}{2x^0yx} )^3\)

3) Use Rule of Zero: \(x^0=1\).

\((\frac{\frac{3y^3}{x^3} }{2\times1\times yx} )^3\)

4) use Product Rule: \(x^ax^b=x^{a+b}\).

\((\frac{3y^3}{2x^{3+1}y} )^3\)

5) Use Quotient Rule: \(\frac{x^a}{x^b} =x^{a-b}\).

\((\frac{3y^{3-1}x^{-4}}{2} )^3\)

6) Use Negative Power Rule: \(x^{-a}=\frac{1}{x^a}\).

\((\frac{3y^2\times\frac{1}{x^4} }{2} )^3\)

7) Use Division Distributive Property: \((\frac{x}{y} )^a=\frac{x^a}{y^a}\).

\(\frac{(3y^2)^3}{2x^4}\)

8) Use Multiplication Distributive Property:  \((xy)^a=x^ay^a\).

\(\frac{(3^3(y^2)^3}{(2x^4)^3}\)

9) Use Power Rule: \((x^a)^b=x^{ab}\).

\(\frac{27y^6}{(2x^4)^3}\)

10)  Use Multiplication Distributive Property:  \((xy)^a=x^ay^a\).

\(\frac{26y^6}{(2^3)(x^4)^3}\)

11) Use Power Rule: \((x^a)^b=x^{ab}\).

\(\frac{27y^6}{8x^12}\)

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Answer:

\(\displaystyle \frac{27y^{6}}{8x^{12}}\)

Step-by-step explanation:

\(\displaystyle \biggr(\frac{3x^{-5}y^3x^2}{2z^0yx}\biggr)^3\\\\=\biggr(\frac{3x^{-5}y^2x}{2}\biggr)^3\\\\=\frac{(3x^{-5}y^2x)^3}{2^3}\\\\=\frac{3^3x^{-5*3}y^{2*3}x^3}{8}\\\\=\frac{27x^{-15}y^{6}x^3}{8}\\\\=\frac{27y^{6}x^3}{8x^{15}}\\\\=\frac{27y^{6}}{8x^{12}}\)

Notes:

1) Make sure when raising a variable with an exponent to an exponent that the exponents get multiplied

2) Variables with negative exponents in the numerator become positive and go in the denominator (like with \(x^{-15}\))

3) When raising a fraction to an exponent, it applies to BOTH the numerator and denominator

Hope this helped!

Answer:

\( \sqrt{ - 1} \)

Step-by-step explanation:

that's the correct answer

Answer:

they do not demonstrate anything since there are no numbers :)