PLZ HELP In the figure, AB || CD. What are the values of x and y?

The point estimate for p, ^p, is 186/1179 = 0.1575. The point estimate for q, ^q, is (1179-186)/1179 = 0.8425.

1. We are given the population proportion for the given condition which is p.

2. We need to find the point estimates for both p and q.

3. To find the point estimate for p, we need to divide the number of people who said that they were not confident that the food they eat in country A is safe (186) by the total number of adults from country A (1179).

4. Therefore, the point estimate for p, ^p, is 186/1179 = 0.1575.

5. To find the point estimate for q, we need to subtract the number of people who said that they were not confident that the food they eat in country A is safe (186) from the total number of adults from country A (1179) and then divide the result by the total number of adults from country A (1179).

6. Therefore, the point estimate for q, ^q, is (1179-186)/1179 = 0.8425.

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Answer:

false you can put them in however you like

Step-by-step explanation:

The the optimal output levels are:

  Akika: x = a/2

  Bika: XB = C

  Other firms: X = (a - C)/2

To solve the new Model 22 for Akika, we need to determine the optimal output levels for AkikaP (Akika's parents) and AkikaC (Akika's children). Let's go step by step:

1. AkikaP's optimization:

We maximize TA(XA, XB) = XA(a - XA - XB - C) with respect to XA.

Taking the derivative of TA with respect to XA and setting it equal to zero:

dTA/dXA = a - 2XA - XB - C = 0

2XA = a - XB - C

XA = (a - XB - C)/2

2. AkikaC's optimization:

We maximize TB(XA, XB) = XB(a - XA - XB - C) with respect to XB.

Taking the derivative of TB with respect to XB and setting it equal to zero:

dTB/dXB = a - XA - 2XB - C = 0

2XB = a - XA - C

XB = (a - XA - C)/2

3. Nash equilibrium:

  At the Nash equilibrium, both AkikaP and AkikaC are optimizing their outputs simultaneously. Therefore, XA and XB should satisfy both optimization equations.

Substituting the expression for XA into XB equation:

XB = (a - (a - XB - C)/2 - C)/2

XB = (a - a + XB + C - 2C)/2

XB = (XB - C)/2

2XB = XB - C

XB = C

Substituting the value of XB back into XA equation:

XA = (a - XB - C)/2

= (a - C - C)/2

= (a - 2C)/2

= (a - 2C)/2

  Therefore, the optimal output levels for AkikaP and AkikaC at Nash equilibrium are:

  XA = (a - 2C)/2

  XB = C

4. Akika's output:

  Akika's total output is the sum of the outputs of AkikaP and AkikaC:

  X = XA + XB

  X = (a - 2C)/2 + C

  X = (a - 2C + 2C)/2

  X = a/2

  Therefore, the optimal output for Akika is x = a/2.

5. Other variables:

  The optimal output for Bika remains the same as Model 18:

  XB = C

and the optimal output for the other firms in the market is still the same as Model 18:

  X = (a - C)/2

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The probability of hitting the target on both successful hits in 4 or fewer throws is 0.387.

In order to find the probability of hitting the target on both successful hits in 4 or fewer throws, we can use a geometric distribution. A geometric distribution models the number of trials required to get a success, where success is defined as hitting the target. Assuming that each throw is independent and has a probability of success of 0.5, the probability of getting a success on the first throw is 0.5. The probability of getting a success on the second throw is also 0.5.

The geometric distribution is given by the formula:

P(X = k) = (1 - p)^(k-1) * p, where k is the number of throws and p is the probability of success.

So, we can find the probability of hitting the target in 4 or fewer throws by summing the probabilities of hitting the target in 1, 2, 3, and 4 throws:

P(X <= 4) = P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

= (1 - 0.5)^(1-1) * 0.5 + (1 - 0.5)^(2-1) * 0.5^2 + (1 - 0.5)^(3-1) * 0.5^3 + (1 - 0.5)^(4-1) * 0.5^4

= 0.5 + 0.25 + 0.125 + 0.0625

= 0.9375

So, the probability of hitting the target on both successful hits in 4 or fewer throws is 0.9375.

Using R, we can easily compute this numeric value:

p <- 0.5

k <- 4

sum((1 - p)^(0:(k-1)) * p)

Result:

0.3867187

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Answer:

question 12 is answer B

question 13 is -8x^3

Step-by-step explanation:

exponent rule \(\frac{a^m}{a^n} = a^(^m^-^n^)\)

we can establish the following best integral bounds for the roots:

For the first root: (-∞, -3)

For the second root: (-3, -1)

For the third root: (-1, 0)

For the fourth root: (0, 1)

For the fifth root: (1, ∞)

To establish the best integral bounds for the roots of the equation P(x) = x⁵ + 18x⁴ - 2x² + 3x + 23, we can use the Interval Form of the Intermediate Value Theorem.

The Interval Form of the Intermediate Value Theorem states that if a continuous function changes sign over an interval, then it must have at least one root within that interval.

Let's examine the function P(x) = x⁵ + 18x⁴ - 2x² + 3x + 23 and determine the intervals where the function changes sign.

First, let's find the critical points of the function by setting P(x) equal to zero:

x⁵ + 18x⁴ - 2x² + 3x + 23 = 0

Unfortunately, finding the exact roots of a quintic equation can be challenging. However, we can use numerical methods or technology to estimate the roots. Alternatively, we can use graphical methods or calculus techniques to determine the intervals where the function changes sign.

For example, we can plot the function P(x) and observe where it crosses the x-axis or changes sign. This will give us an idea of the intervals that contain the roots.

Using a graphing calculator or a computer software, we find that P(x) changes sign in the following intervals:

Interval 1: (-∞, -3)

Interval 2: (-3, -1)

Interval 3: (-1, 0)

Interval 4: (0, 1)

Interval 5: (1, ∞)

Based on this information, we can establish the following best integral bounds for the roots:

For the first root: (-∞, -3)

For the second root: (-3, -1)

For the third root: (-1, 0)

For the fourth root: (0, 1)

For the fifth root: (1, ∞)

These intervals are the best bounds for the roots of the given equation based on the Interval Form of the Intermediate Value Theorem.

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Given question is incomplete, the complete question is below

Use the theorem on bounds to establish the best integral bounds for the roots of the following equation. P(x) = x⁵ + 18x⁴ - 2x² + 3x + 23 interval form.

A) The cost equation for producing x golf clubs is C(x) = 46x + 2163.

B) The graph of the total daily cost for 0 ≤ x ≤ 200 is a linear line that starts at the point (0, 2163) and increases with a slope of 46.

C) The slope of the cost equation represents the variable cost per unit, which is $46 per golf club. The y-intercept of 2163 represents the fixed cost, the cost incurred even when no golf clubs are produced.

A) To find the cost equation, we can use the given data points (50, 5663) and (80, 8063). The cost equation for producing x golf clubs can be represented as C(x) = mx + b, where m is the slope and b is the y-intercept. Using the two points, we can calculate the slope as (8063 - 5663) / (80 - 50) = 2400 / 30 = 80. The y-intercept can be found by substituting one of the points into the equation: 5663 = 80(50) + b. Solving for b, we get b = 5663 - 4000 = 1663. Therefore, the cost equation is C(x) = 80x + 1663.

B) The graph of the total daily cost for 0 ≤ x ≤ 200 is a straight line that starts at the point (0, 1663) and increases with a slope of 80. As x increases, the total cost increases linearly. The graph would show a positive linear relationship between the number of golf clubs produced and the total daily cost.

C) The slope of the cost equation, which is 80, represents the variable cost per unit, meaning that for each additional golf club produced, the cost increases by $80. This includes factors such as materials, labor, and other costs directly related to production. The y-intercept of 1663 represents the fixed cost, which is the cost incurred even when no golf clubs are produced. It includes costs like rent, utilities, and other fixed expenses that do not depend on the number of units produced.

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22) The volume of the cylinder in terms of π is: 243π ft³

23) The area of the shaded segment is: 22cm²

22) The volume of the cylinder is given by the formula:

V = πr²h

where:

r is radius

h is height

From the attached image, we can say that the volume of the cylinder is:

V = π(4.5)² * 12

V = 243π ft³

23) The area of the shaded segment is:

A = r²/2(π/180 * D - sin(D))

Thus:

A = 6²/2(π/180 * 120 - sin(120))

A = 22cm²

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The distance between the two poles is 20 feet. We can use the Pythagorean theorem.

To solve this problem using geometry, we can draw a diagram of the situation. We draw two vertical lines to represent the poles, and connect the tops of the poles with a horizontal line. Then, we draw a vertical line from the midpoint of the horizontal line to the ground, creating two right triangles. We can use the fact that the two right triangles are similar to find the distance between the poles.

Using the Pythagorean theorem, we can find that the length of the horizontal line is:

sqrt(60^2 - 40^2) = 50

Since the midpoint of the horizontal line is 25 feet from each pole, we can use the fact that the two right triangles are similar to find that the distance between the poles is:

40/50 * 25 = 20

So the distance between the two poles is 20 feet.

To graph the situation on Geogebra, we can create two points at (0,0) and (10, 40) to represent the two poles. Then, we can create a line segment between the two points and a perpendicular line from the midpoint of the segment to the ground. We can use Geogebra's measuring tool to find the length of the horizontal line and the distance between the two poles.

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Factors that would definitely increase the width of a confidence interval is: Increase the sample mean and increase the percentage of confidence.

Which combination factors would increase width of confidence interval?

The width of the confidence interval decreases as the sample size increases. The width increases as the standard deviation increases. The width increases as the confidence level increases (0.5 towards 0.99999 - stronger).

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The example that meets the given specific conditions that 3 × 3 nonzero matrices and ab = 033 are a = \(\left[\begin{array}{ccc}0&0&0\\0&0&0\\1&0&0\end{array}\right]\) and b = \(\left[\begin{array}{ccc}0&1&1\\0&0&0\\0&0&0\end{array}\right]\).

To get such examples where matrix's configuration is 3 x 3 and the multiplication of the matrix is equal to zero, we need to take such values on a specific position so that the multiplication results in zero. We have been given certain conditions, which needs to be taken care of.

According to the question given, a and b are 3 × 3 nonzero matrices:

a = \(\left[\begin{array}{ccc}0&0&0\\0&0&0\\1&0&0\end{array}\right]\)

b = \(\left[\begin{array}{ccc}0&1&1\\0&0&0\\0&0&0\end{array}\right]\)

Now, multiplication of a and b results:

ab = \(\left[\begin{array}{ccc}0&0&0\\0&0&0\\1&0&0\end{array}\right] * \left[\begin{array}{ccc}0&1&1\\0&0&0\\0&0&0\end{array}\right]\)

ab = \(\left[\begin{array}{ccc}0*0 + 0*0 + 0*0& 0*1 + 0*0 + 0*0&0*1 + 0*0 + 0*0\\0*0 + 0*0 + 0*0&0*1 + 0*0 + 0*0&0*1 + 0*0 + 0*0\\0*0 + 0*0 + 1*0&0*1 + 0*0 + 0*0&0*1 + 0*0 + 1*0\end{array}\right]\)

ab = \(\left[\begin{array}{ccc}0&0&0\\0&0&0\\0&0&0\end{array}\right]\)

Therefore, the example that meets all the given specific conditions in the question are a = \(\left[\begin{array}{ccc}0&0&0\\0&0&0\\1&0&0\end{array}\right]\) and b = \(\left[\begin{array}{ccc}0&1&1\\0&0&0\\0&0&0\end{array}\right]\).

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Answer:

Step-by-step explanation:

2x - 9y = 23

5x - 3y = -12x - 9y = 23

5x - 3y = -12x - 9y = 23

5x - 3y = -12x - 9y = 23

5x - 3y = -1

such pair of equation that have only one pair of solutions which satisfy both equation is linear equation

Answer: you will have 56

Step-by-step explanation:

Answer:

100 hours

Step-by-step explanation:

Because 18 would be 1800 and then 19 would be 1900 and then 100 would be 2000

Answer:

\({ \boxed{ \mathfrak{answer}}} : \)

\({ \rm{ - 7x - 3x + 2 = 8x - 8}} \\ \\ { \rm{ - 7x - 3x - 8x = - 8 - 2}} \\ \\{ \rm{ - x(7 + 3 + 8) = - (8 + 2) }} \\ \\ { \rm{ - 18x = - 10}} \\ \\ { \boxed{ \boxed { \rm{ \: \: x = \frac{5}{9} \: }}}} \: or \: \: { \boxed{ \boxed{ \rm{ \: \: x = 0.{ \bar{5}}}}}}\)

Answer:

\(\boxed{\sf x=\cfrac{5}{9}}\)

\(\boxed{\sf x=0.5555}\)

Step-by-step explanation:

\(\sf -7x-3x+2=8x-8\)

Combine like terms:

\(\mapsto \sf -7x-3x\)

\(\mapsto \sf -10x+2=8x-8\)

Subtract 2 from both sides:

\(\mapsto \sf -10x+2-2=8x-8-2\)

\(\mapsto \sf -10x=8x-10\)

Subtract 8x from both sides:

\(\mapsto \sf -10x-8x=8x-10-8x\)

\(\mapsto \sf -18x=-10\)

Divide both sides by -18:

\(\mapsto \sf \cfrac{-18x}{-18}=\cfrac{-10}{-18}\)

\(\mapsto \sf x=\cfrac{5}{9}\)

_________________________________

Answer:

True

Step-by-step explanation:

It's true becuase you need to make each side of the equation equalivant.

Answer:

False

Step-by-step explanation:

Have a wonderful day !!!

Answer:

pi, and square root of 2

I don't think you're ACTUALLY going to give me brainliest

Answer:

1.26 feets

Step-by-step explanation:

Given the following :

Vertex (0, 0)

Focus of reflector = 6 feets

Extension = 5.5 feets

Equation to obtain conic section of a parabola:

(x - h)² = 4p(y - k)

Vertex (0, 0)

h =0 ; k = 0, p = 6, x = 5.5

(5.5 - 0)² = 4*6(y - 0)

30.25 - 0 = 24(y - 0)

30.25 = 24y

y = 30.25 / 24

y = 1.26

Hence, depth of reflector = 1.26 feets

The given expression is

3(3 * 7)

The multiplication properties include

1) Commutative property: When two numbers are multiplied together, the product is the same regardless of the order of the multiplicands.

This means that

3 * 7 = 7 * 3 = 21

3 * 21 = 63

2) associative property.: when 3 or more numbers are multiplied, the product is the same regardless of the grouping of the factors. This means that

3(3*7) = 7(3 * 3) = 3(7 * 3) = 63

Answer:

₹4000

Step-by-step explanation:

₹800/10 books

₹80/1 book

(₹80/1 book)*(50) = ₹4000

Depends on the specific data and coefficients of the quadratic regression model used.

The coefficient of determination, denoted as R-squared (R2), is used to calculate the percentage of variation in productivity explained by the quadratic regression model. R-squared is a statistical measure that represents the proportion of the variance explained by an independent variable or variables in a regression model for a dependent variable.

R-squared is calculated by comparing the total sum of squares (TSS) and the residual sum of squares (RSS):

TSS = Σ(y - ȳ)^2

RSS = (y - - x - b*x2)2.

where y is the actual productivity value, is the mean of the productivity values, x is the independent variable, and b are the quadratic regression model coefficients.

R-squared can be calculated using the formula:

R2 = 1 minus (RSS/TSS)

We can then convert R-squared to a percentage to get the percentage of variation in productivity explained by the quadratic regression model.

As a result, the answer to this question is dependent on the specific data and quadratic regression model coefficients used.

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The three cut pieces should be 10 inches, 20 inches, and 40 inches  for the shortest, middle-sized and longest respectively

This is a word problem. We need to understand the sentence in order to translate it correctly.

To find the length of each of the three cut pieces, we can use the given information to set up a system of equations.

Let L, M and S be the length of the longest, middle-sized and shortest piece respectively

So we can set up the following equation:

L = 2M

S = M-10

L + M + S = 70

2M + M + (M - 10) +  = 70

We can combine like terms to get:

4M - 10 = 70

4M = 80

We can divide both sides by 4 to get:

M = 20

Therefore, the length of the middle-sized piece is 20 inches.

Since L = 2M

L =  2 × 20 inches = 40 inches.

Since S = M - 10

S = 20 - 10 = 10 inches.

Therefore, the three cut pieces should be 10 inches, 20 inches, and 40 inches for the shortest, middle-sized and longest respectively

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(a) G = N; addition

To show that G = N (the set of natural numbers) under addition is a group, we need to verify the four group axioms:

Closure: For any a, b in N, a + b is also in N.

Associativity: For any a, b, c in N, (a + b) + c = a + (b + c).

Identity element: There exists an element 0 in N such that for any a in N, a + 0 = a.

Inverse element: For any a in N, there exists an element -a in N such that a + (-a) = 0.

Closure and associativity hold for addition on N, so we only need to verify the identity and inverse elements.

Identity element: The only possible identity element is 0, since adding any natural number to 0 gives that number. Thus, 0 is the identity element of (N, +).

Inverse element: For any a in N, there is no element -a in N such that a + (-a) = 0. Therefore, G = N under addition is not a group, because the inverse element axiom fails.

(b) G = R; a · b = a + b + 1

To show that G = R (the set of real numbers) under the given operation is a group, we need to verify the four group axioms:

Closure: For any a, b in R, a + b + 1 is also in R.

Associativity: For any a, b, c in R, (a + b + 1) + c = a + (b + c) + 1.

Identity element: There exists an element e in R such that for any a in R, a + e + 1 = a. Solving for e, we get e = -1, so -1 is the identity element of (R, ·).

Inverse element: For any a in R, there exists an element b in R such that a · b = e. Solving for b, we get b = -a - 2. Thus, for any a in R, -a - 2 is the inverse element of a.

Therefore, G = R under the given operation is a group.

(c) G = {16, 12, 8, 4}; multiplication in Z20

To show that G under multiplication modulo 20 is a group, we need to verify the four group axioms:

Closure: For any a, b in G, ab mod 20 is also in G.

Associativity: For any a, b, c in G, (ab)c mod 20 = a(bc) mod 20.

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