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Answer:

150   kg-m/s

Explanation:

momentum = m * v

50 * 3 = 150

For the roller coaster on a frictionless track:

a. The speed of the car at Point B can be determined using the principle of conservation of energy. The total mechanical energy (sum of kinetic energy and potential energy) remains constant in the absence of external forces like friction. Therefore, if there is no energy loss, the kinetic energy at Point A is equal to the kinetic energy at Point B.

Given that the speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.

Answer: A. 5.0 m/s

b. To find the height at which kinetic energy equals potential energy, we can set the equations for kinetic energy and potential energy equal to each other.

At Point A, the roller coaster has both kinetic energy and potential energy. The total mechanical energy is the sum of these two:

Initial mechanical energy at Point A = Kinetic energy at Point A + Potential energy at Point A

At Point B, the roller coaster will have kinetic energy and potential energy, but we want to find the height at which kinetic energy equals potential energy. Let's call this height "h."

Mechanical energy at Point B = Kinetic energy at Point B + Potential energy at Point B

Since the speed at Point B is the same as the speed at Point A (5.0 m/s), the kinetic energy at both points is the same.

Equating the mechanical energy at Point A to the mechanical energy at Point B:

Initial mechanical energy at Point A = Mechanical energy at Point B

Kinetic energy at Point A + Potential energy at Point A = Kinetic energy at Point B + Potential energy at Point B

Since the kinetic energy is the same at both points, simplify the equation:

Potential energy at Point A = Potential energy at Point B

The potential energy at any point is given by the formula mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.

Therefore, at the height h between Points A and B, the potential energy equals the potential energy at Point A:

mgh = mghA

Since the mass and acceleration due to gravity are the same, cancel them out:

h = hA

This means that the height where kinetic energy equals potential energy is the same as the height at Point A.

Answer: The height between Points A and B where kinetic energy equals potential energy is 5.0 m.

c. To determine if the car will reach Point C, compare the potential energy at Point B with the potential energy at Point C. If the potential energy at Point B is greater than or equal to the potential energy at Point C, the car will reach Point C.

Potential energy at Point B = mghB

Potential energy at Point C = mghC

Given that the height at Point C is 8.0 m, compare the potential energies:

Potential energy at Point B ≥ Potential energy at Point C

mghB ≥ mghC

Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:

hB ≥ hC

Therefore, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.

d. The minimum speed needed at Point A for the car to reach Point C can be determined by comparing the potential energy at Point A with the potential energy at Point C. If the potential energy at Point A is greater than or equal to the potential energy at Point C, the car will have enough energy to reach Point C.

Potential energy at Point A = mghA

Potential energy at Point C = mghC

Given that the height at Point A is 5.0 m, compare the potential energies:

Potential energy at Point A ≥ Potential energy at Point C

mghA ≥ mghC

Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:

hA ≥ hC

Therefore, for the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.

To summarize, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m, and the height at Point A must also be greater than or equal to 8.0 m.

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Answer: 30 cm.

The situation described is that of two sources of sound waves that are separated by some distance. The two waves interfere with each other constructively at some points and destructively at others. When they interfere constructively, the amplitude (and intensity) of the sound wave is greater than when they interfere destructively.

When the speakers are 40 cm apart, the waves that they produce are in phase at some points on the axis, leading to constructive interference and a maximum in the intensity of the sound. As the distance between the speakers is increased beyond 40 cm, the points of constructive interference move farther apart, and the intensity of the sound decreases. When the speakers are 50 cm apart, the waves that they produce are exactly out of phase at some points on the axis, leading to complete destructive interference and a minimum in the intensity of the sound.

If the separation between the speakers continues to increase, the points of constructive interference will move closer together again, and the intensity of the sound will increase. The separation between the speakers at which the intensity of the sound will again be a maximum can be found using the following equation:

d = λ/2 + nλ

where d is the separation between the speakers, λ is the wavelength of the sound wave, and n is an integer that represents the number of half-wavelengths between the speakers.

At the maximum, the separation is an even multiple of half the wavelength, so we can use the formula above with n = 1. The wavelength can be found from the distance between the speakers at the minimum, which is 50 cm, and the distance at the maximum, which is 40 cm:

λ = 2(d_max - d_min) = 20 cm

Substituting λ and n into the formula gives:

d = λ/2 + nλ = 10 cm + 20 cm = 30 cm

Therefore, the sound intensity will be a maximum again when the separation between the speakers is 30 cm.

Answer:

the answer is the area around a star where a planet can orbit A Star without the harmful effect of radiation

Answer:

STATES OF MATTER The three important states of the matter are (i) Solid state (ii) Liquid state (iii) Gaseous state, which can exist together at a particular temperature and pressure e.g. water has three states in equilibrium at 4.58 mm and 0.0098ºC.

Explanation:

Answer:

N/A

Explanation:

The following formula can be used to compute the power output of a person lifting a lawnmower:

Work (W) / Time (t) = Power (P).

Where:

Work (W) is defined as the force used to lift the lawnmower multiplied by the distance traveled (i.e., work done against gravity).

Time (t) is the amount of time it takes to lift the lawnmower.

To determine the power output, however, we would need to know the force used to lift the lawnmower as well as the distance it was lifted. We won't be able to provide an accurate power output value without this information.

Answer:

The voltage is \(\= DC _v = 2.6 \ V\)

Explanation:

From the question we are told that

  The duty cycle is  p =  65% = 0.65

   The on - state voltage is  \(V = 40 \ volt\)

Generally the average DC voltage is mathematically represented as

        \(\= DC _v = p * V\)

=>      \(\= DC _v = 40 * 0.65\)

=>      \(\= DC _v = 2.6 \ V\)

Answer:The direction a wave propagates is perpendicular to the direction it oscillates for transverse waves. A wave does not move mass in the direction of propagation; it transfers energy.

Explanation:

The picture shown in the figure represents the Milky Way Galaxy. The Galaxy in which the entire solar system is present.

The million and trillion of stars in the universe form Galaxy. The galaxy in which the entire solar system is present is called Milky Way Galaxy. The Milky Way Galaxy is spiral in shape. This Galaxy has four major arms. The major arms have both old and young stars and the minor arms have the gas and star formation activity. This galaxy also has a black hole at its center. Galileo Galilei was the first to see the Galaxy.

The Milky Way Galaxy is made up of a dense cloud of gas that stretches across the sky as seen from the Earth. The age of the Milky Way Galaxy is 13.61 billion years ago and the Andromeda Galaxy is the nearest galaxy to the Milky Way Galaxy.

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Answer:

a) F₁ = F₂,  F₃ = F₄,  b)  the correct answer is 3

Explanation:

a) In this exercise we have several action and reaction forces, which are characterized by having the same magnitude, but different direction and being applied to different bodies

Forces 1 and 2 are action and reaction forces F₁ = F₂

Forces 3 and 4 are action and reaction forces F₃ = F₄

as it indicates that the

b) how the car increases if speed implies that force 1> force3

      F₁ > F₃

therefore the correct answer is 3

Answer:

the resultant wave is the algebraic sum of all the waves reaching that particular point at a given time.

Explanation:

imagine two or three waves reaching a particular particle x at the same time. The particle will vibrate those waves and give out or transmit a resultant wave which is the algebraic sum of the incoming two waves. If both the waves have the same amplitude and phase, the resultant wave will be amplified. However if the waves have the same amplitude and equal but opposite phase then the resultant wave will be a straight line

Answer: Please see the attached image.

Explanation:

A diagram of the Lewis dot structure depicts the valence electrons of the atoms of a molecule. It makes use of dots to represent lone electron pairs and lines to represent atomic bonds.

Valence Electrons are the s and p subshells on the periodic table. You count the total s and p subshells of the corresponding atom to find how much valence electrons it has.

It as dangerous to be hit by the gun as by the bullet because of the following;

(A) The butt distributes the recoil force over an area much larger than that of the bullet.

(B) The rifle has a much lower speed than the bullet.

The principle of conservation of linear momentum states that in an isolated system, the total momentum of the system is conserved.

That is the sum of the initial momentum is equal to the sum of the final momentum.

momentum of the gun = momentum of the bullet

Mu = mU

where;

If the forward momentum of a bullet is the same as the backward momentum of the gun, the speed of the gun will be smaller than the speed of the bullet since the mass of the gun is bigger than mass of the bullet.

We cannot conclude on the kinetic energy, since it depends on both mass and velocity.

Finally, the butt distributes the recoil force over an area much larger than that of the bullet, since the butt has a larger surface area and will hit more surface area than the bullet.

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Answer:

Explanation:

Carbonation. When you think of carbonation, think carbon! ...

Oxidation. Oxygen causes oxidation. ...

Hydration. This isn't the hydration used in your body, but it's similar. ...

Hydrolysis. Water can add to a material to make a new material, or it can dissolve a material to change it. ...

Acidification.

Answer:

electron, lightest stable subatomic particle known. It carries a negative charge of 1.602176634 × 10−19 coulomb, which is considered the basic unit of electric charge. The rest mass of the electron is 9.1093837015 × 10−31 kg, which is only 1/1,836the mass of a proton.

Explanation:

I hope this will be helpful for you.

Given :

Object A is 71 degrees and object B is 75 degrees .

To Find :

How will thermal energy flow.

Solution :

We know, by law of thermodynamics thermal energy will flow from higher temperature to lower temperature.

So, in the given question energy will flow from object B from object A.

Hence, this is the required solution.

Machine 1 has the greatest mechanical advantage among the given machines. To determine the machine with the greatest mechanical advantage, we need to calculate the mechanical advantage for each machine.

Machine 1: Mechanical Advantage = Output Force / Input Force = 50 N / 5 N = 10

Machine 2: Mechanical Advantage = Output Force / Input Force = 50 N / 10 N = 5

Machine 3: Mechanical Advantage = Output Force / Input Force = 50 N / 25 N = 2

Machine 4: Mechanical Advantage = Output Force / Input Force = 50 N / 50 N = 1

Comparing the mechanical advantages, we can see that Machine 1 has the highest mechanical advantage of 10. This means that Machine 1 can multiply the input force by 10 to produce the output force. It provides the greatest amplification of force among the four machines.

Machine 2 has a mechanical advantage of 5, Machine 3 has a mechanical advantage of 2, and Machine 4 has a mechanical advantage of 1. Therefore, Machine 1 has the greatest mechanical advantage among the given machines.

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Velocity is a vector quantity and speed is a scalar quatity. This means that velocity changes with direction and speed does not.

What is speed and velocity?

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.

Three examples were velocity and speed are same:

Three examples were velocity and speed are different:

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Answer:

B. Its virtual and behind the mirror.

Explanation:

Answer:  (B) Virutal, (D) Upright, (E) Smaller.  

Explanation:

Edge Physics B

The time that takes for a small bag of sand to reach the ground after it is released from an ascending hot-air balloon whose upward velocity is 2.25 m/s is 2.94 s.  

We can find the time that takes for the bag to reach the ground with the following equation:

\( y_{f} = y_{i} + v_{i_{y}}t + \frac{1}{2}gt^{2} \)   (1)

Where:            

\( y_{f} \): is the final height = 35.8 m

\( y_{i} \): is the initial height = 0

\( v_{i_{y}} \): is the initial velocity = 2.25 m/s

t: is the time =?

g: is the acceleration due to gravity = 9.81 m/s²

When the bag is released, it will move upward until it reaches a maximum height and then begins to fall. We can find the time that takes for the bag to reach the maximum height as follows:      

\( v_{f} = v_{i} - gt \)  (2)

Where:

\( v_{f} \): is the final velocity = 0 (at the maximum height)

\( v_{i} \): is the initial velocity = 2.25 m/s

The time is:        

\( t = -\frac{v_{f} - v_{i}}{g} = \frac{2.25 m/s}{9.81 m/s^{2}} = 0.23 s \)

This is the rise time it takes for the bag to reach the maximum height, which is equal to the fall time it takes for the bag to reach the same starting point (35.8 m above the ground), so:

\( t = 0.23 s*2 = 0.46 s \)

Now, from equation (1) we have:

\( 35.8 m = 0 + 2.25 m/s*t + \frac{1}{2}9.81 m/s^{2}*t^{2} \)    

By solving the above quadratic equation for t we have:

\( t = 2.48 s \)    

Hence, the total time is:

\( t = 2.48 s + 0.46 s = 2.94 s \)

Therefore, the time that it takes for the bag to reach the ground is 2.94 s.

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The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.

Let's break down the distances and calculate the time for each part of the journey:

Distance from the student to the first cliff: 330 meters

Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second

Distance from the first cliff to the second cliff: 990 meters

Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds

Distance from the second cliff back to the student: 990 meters

Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds

Now, we can calculate the total interval between the first and second echo by adding up the individual times:

Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds

Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.

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Note the complete questions is:

A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?

Answer:

Volume of cube is equal to two times the weight of replaced water \(1000\) Kg

Explanation:

Length of one side of cube is \(1\) meter

Volume of cube \(= 1* 1* 1 = 1\) cubic meter

Half of the wood sank

Hence, the volume of water replaced will be equal to half the volume of cube

Volume of water replaced \(= \frac{1}{2} = 0.5\) cubic meter

Density of water \(1 * 10^3\) kg/m3

Weight of water replaced

\(= 1 * 10^3 * 0.5\\= 500\)Kg

Volume of cube is equal to two times the weight of replaced water

\(= 2* 500 = 1000\) Kg

Answer:

- They need oxygen to burn fuel

- Aerodynamics

- Extreme temperatures

- Radiation

- Pressure issues

Explanation:

A airplane is a heavier-than-air aircraft kept aloft by the upward thrust exerted by the passing air on its fixed wings and driven by propellers, jet propulsion, etc.

Aeroplanes cannot travel in space for several reasons:

They need oxygen to burn fuel - Aeroplane engines rely on the oxygen in the atmosphere to burn fuel and generate thrust. In space, there is no atmosphere so there is no oxygen for the engines to work.

Aerodynamics - Aeroplane wings generate lift by interacting with the air. In space, there is no air so wings would be unable to generate any lift. Aeroplanes rely on aerodynamics to fly which does not work in space.

Extreme temperatures - In space, temperatures can range from -150 degrees Celsius to 150 degrees Celsius. Aeroplanes are designed to operate within a much narrower temperature range. The extreme cold and heat of space could damage aeroplane components.

Radiation - In space, there are high levels of radiation from the Sun and cosmic rays. Aeroplane bodies are not designed to shield against this type of radiation and it could damage electronics and affect aeroplane systems.

Pressure issues - Aeroplanes are designed to withstand air pressures at altitudes up to around 12 kilometers. In low-Earth orbit and beyond, the air pressure is essentially zero. This extreme change in pressure could cause structural damage to the aeroplane.

In summary, while aeroplanes are designed to fly through the Earth's atmosphere, they lack the key features needed to operate in the extreme environment of outer space like spaceships. Aeroplanes require things like oxygen, aerodynamics and being able to withstand changes in pressure - all of which do not exist or work the same way in space.

Explanation:

The wing is pushed up by the air under it. Large planes can only fly as high as about 7.5 miles. The air is too thin above that height. It would not hold the plane up.

A block of wood resting on a steel desk experiences a force of friction that opposes the applied force. The force of friction depends on the coefficients of friction and the normal force acting on the block.

At time t=0, the force applied on the block is 15.8 N. Since the block is at rest, the frictional force must be equal and opposite to the applied force to maintain static equilibrium. Therefore, the force of friction acting on the block at t=0 is:

Ffriction = Fapplied = 15.8 N

Now, when the applied force is greater than the maximum static frictional force (i.e., Fs > μsN), the block will start to move, and the frictional force acting on the block will be the kinetic frictional force. The kinetic frictional force is given by:

Ffriction = μkN

where μk is the coefficient of kinetic friction and N is the normal force acting on the block.

The normal force N acting on the block can be calculated using Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration:

ΣF = ma

Since the block is moving horizontally, its acceleration in the vertical direction is zero, and the normal force N is equal to the weight of the block:

N = mg

where m is the mass of the block and g is the acceleration due to gravity.

Substituting the given values, we get:

N = 5.760 kg × 9.81 m/s^2 = 56.47 N

The maximum static frictional force Fs can be calculated using:

Fs = μsN

Substituting the given values, we get:

Fs = 0.455 × 56.47 N = 25.68 N

Since the applied force is greater than the maximum static frictional force, the block will start to move, and the frictional force acting on the block will be the kinetic frictional force. The kinetic frictional force can be calculated using:

Ffriction = μkN

Substituting the given values, we get:

Ffriction = 0.205 × 56.47 N = 11.56 N

Therefore, the force of friction acting on the block at t=0 is 15.8 N, and the force of friction acting on the block when it starts to move is 11.56 N.

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The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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Given that the distance is d = 39.2 km.

As 1 km = 1000 m, so d =39200 m

The time taken is t = 2 hours 24 minutes and 24 seconds

As 1 minute = 60 seconds and 1 hour = 60 minutes.

So the time will be

The speed can be calculated by the formula

The speed is 4.52 m/s

The vectors can be expressed using unit vectors as follows:

Vector A = 96N i + 96N j + 0N k

Vector B = 76.6N i + 64.3N j + 0N k

Vector C = 64N i + 48N j + 0N k.

In the given diagram, let's consider the vectors as follows:

Vector A with magnitude 120N, Vector B with magnitude 100N, and Vector C with magnitude 80N.

To express these vectors using unit vectors i, j, and k, we need to determine their respective components in the x, y, and z directions.

For Vector A (120N), we have the following information:

Magnitude = 120N

Direction: X-axis (cosine component) with an angle of 37° and Y-axis (sine component) with an angle of 53°.

Using the trigonometric values provided:

cos37° = 0.8 and sin53° = 0.8

Therefore, the components of Vector A are:

Ax = 120N * 0.8 = 96N (in the X-direction)

Ay = 120N * 0.8 = 96N (in the Y-direction)

Az = 0N (no component in the Z-direction)

Thus, Vector A can be written as 96N i + 96N j + 0N k.

Similarly, using the trigonometric values for Vector B and Vector C, we can calculate their components:

For Vector B (100N):

Bx = 100N * cos40° = 100N * 0.766 = 76.6N

By = 100N * sin40° = 100N * 0.643 = 64.3N

Bz = 0N

Vector B can be expressed as 76.6N i + 64.3N j + 0N k.

For Vector C (80N):

Cx = 80N * cos37° = 80N * 0.8 = 64N

Cy = 80N * sin37° = 80N * 0.6 = 48N

Cz = 0N

Vector C can be written as 64N i + 48N j + 0N k.

In summary, the vectors can be expressed using unit vectors as follows:

Vector A = 96N i + 96N j + 0N k

Vector B = 76.6N i + 64.3N j + 0N k

Vector C = 64N i + 48N j + 0N k.

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