plz help as soon as you can

Oil of Vitriol is a substance that humankind has used for thousands of years! Today the substance is known by its scientific name sulfuric acid and has the molecular formula H2SO4. What is the molar mass of H2SO4?

Question 2 options:

49.067 g/mol


73.29 g/mol


98.08 g/mol


148.72 g/mol

Answer:

Answer is D, None of the above :)

Explanation:

Answer:

As you move across a period the electrons are being added to the same shell. But, protons are being added as well. This makes the nucleus more positively charged and, increasing protons has a greater effect than electrons. So, there is a greater nuclear attraction and, because the electrons are being added to the same shell that shell gets pulled in more. This causes a decrease in atomic radius.

Explanation:

The primary reason that atomic radius decreases as you move from left to right across the periodic table is; Due to the increase in electrostatic attraction between the positively charged nucleus and the negatively charged electrons.

The number of shells in elements located in the same period are equal.

However, with successive increase in the atomic number, the number of electrons and protons increases.

Consequently, the electrostatic attraction between the positively charged nucleus and negatively charged electrons increases and the radius reduces accordingly.

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Answer:

The new volume will be 808 L

Explanation:

Charles's law is a law that says that the volume of gas at constant pressure is directly proportional to its absolute temperature (in degrees Kelvin), that is, when the amount of gas and pressure are kept constant, the quotient between volume and temperature will always have the same value:

\(\frac{V}{T}=k\)

Having a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment, by varying the volume of gas to a new value V2, the temperature will change to T2 and the following will be fulfilled:

\(\frac{V1}{T1} =\frac{V2}{T2}\)

In this case:

Replacing:

\(\frac{625 L}{273 K} =\frac{V2}{353 K}\)

Solving:

\(V2=353 K*\frac{625 L}{273 K}\)

V2= 808 L

The new volume will be 808 L

Answer:

A, Vapor pressure is very high

Answer:

vapor pressure is very high

To answer this question, we need to know the concentration of the RbOH solution. Without this information, we cannot determine the amount of RbOH present in the 28.3 mL sample.
However, if we assume that the concentration of the RbOH solution is known, we can use the formula:
moles of solute = concentration x volume

To find the number of moles of RbOH in the 28.3 mL sample. From there, we can use the molar mass of RbOH (102.47 g/mol) to calculate the mass of RbOH in the sample.
For example, if the concentration of the RbOH solution is 0.1 M, then:
moles of RbOH = 0.1 M x 0.0283 L = 0.00283 moles
mass of RbOH = 0.00283 moles x 102.47 g/mol = 0.290 g
So, a 28.3 mL sample of a 0.1 M RbOH solution would contain 0.290 g of RbOH.
In summary, the amount of RbOH present in a 28.3 mL sample of a solution depends on the concentration of the solution. Without knowing the concentration, we cannot determine the amount of RbOH in the sample.

complete question not found in the search engine.

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Answer:

477 °C

Explanation:

Step 1: Given data

Step 2: Convert 27 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 27 + 273.15 = 300 K

Step 3: Calculate the final temperature (T₂)

If we assume constant volume (before the can explodes) and ideal behavior, we can calculate the final temperature using Gay-Lussac's law.

T₁/P₁ = T₂/P₂

T₂ = T₁ × P₂/P₁

T₂ = 300 K × 2.5 atm/1.0 atm = 750 K

In Celsius,

°C = K - 273.15 = 750 - 273.15 = 477 °C

Answer:

E) C₂H₄(g) + H₂(g) ⇒ C₂H₆(g)

Explanation:

Which ONE of the following is an oxidation–reduction reaction?

A) PbCO₃(s) + 2 HNO₃(aq) ⇒ Pb(NO₃)₂(aq) + CO₂(g) + H₂O(l). NO. All the elements keep the same oxidation numbers.

B) Na₂O(s) + H₂O(l) ⇒ 2 NaOH(aq). NO. All the elements keep the same oxidation numbers.

C) SO₃(g) + H₂O(l) ⇒ H₂SO₄(aq). NO. All the elements keep the same oxidation numbers.

D) CO₂(g) + H₂O(l) ⇒ H₂CO₃(aq). NO. All the elements keep the same oxidation numbers.

E) C₂H₄(g) + H₂(g) ⇒ C₂H₆(g). YES. C is reduced and H is oxidized.

The name of the salt tells us that:

a) there is just one other element combined with the metal by looking at the suffix of the salt's name.

b) the presence of oxygen in a salt can be indicated by the name of the salt.

a) The name of a salt can tell us that there is just one other element combined with the metal by looking at the suffix of the salt's name. If the salt name ends in "-ide," it indicates that the salt is composed of a metal and a single non-metal element.
For example, sodium chloride (NaCl) and potassium bromide (KBr) are salts where the metal (sodium and potassium) is combined with a single non-metal element (chlorine and bromine, respectively). The "-ide" suffix suggests the presence of only one other element in the salt.

b) The presence of oxygen in a salt can be indicated by the name of the salt. If the salt name includes the element oxygen, it suggests that oxygen is present in the salt compound.
For example, sodium carbonate (Na₂CO₃) and calcium sulfate (CaSO₄) contain the element oxygen in their chemical formulas. The presence of oxygen in the salt is implied by the name and the combination of elements in the compound.

Therefore, the name of salt tells us that there is just one other element combined with the metal and there is oxygen present in the salt

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Answer:

d) The object falls towards the ground

Explanation:

Answer: In the Western United States and Canada, open range is rangeland where cattle roam freely regardless of land ownership. ... Land in open range that is designated as part of a "herd district" reverses liabilities, requiring an animal's owner to fence it in or otherwise keep it on the person's own property.

Explanation: Mark me as brainliest

The sample of nitrogen gas will occupy 236.54 mL of volume at 1.05 atm pressure.

Boyle's law is the ideal law that defines the relationship between pressure and volume of gases. A law is given if the temperature is kept constant. Pressure and volume exhibit an inverse relationship.

The Boyle's Law is given as:

P₁V₁ = P₂V₂

Given,

Initial pressure (P₁) = 0.974 atm

Initial volume (V₁) = 255 mL

Final pressure (P₂) = 1.05 atm

Final volume = V₂

The final volume at 1.05 atm is calculated by substituting values in Boyle's Law as:

P₁V₁ = P₂V₂

0.974 × 255 = 1.05 V₂

V₂ =  248.37 ÷ 1.05

= 236.54 mL

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Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

Answer:

gguhg

Explanation:

no te es caso drama me están muy una las y y que las te

The correct statement is one person performs the work in less time than the other.

Power is a measure of the rate at which work is done. It is calculated by dividing the amount of work done by the time taken to do the work.

P = E/t

where;

Therefore, if two people are moving boxes into a moving truck, the person who moves more boxes in a shorter amount of time has more power than the other person.

Thus, the correct statement will be "One person performs the work in less time than the other" which best explains how one can have more power than the other.

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The temperatures describing the value of C is 100 °C, because it is the boiling point of water.Hence, The correct answer is Option (B)

A phase change is when matter changes to from one state (solid, liquid, gas, plasma) to another.

These changes occur when sufficient energy is supplied to the b(or a sufficient amount is lost), and also occur when the pressure on the system is changed.

The given heating curve has two flat lines (Or plateaus) ;

(Image is attached for reference)

In the given problem, C is the second flat line, so it is boiling point.

Therefore , The temperatures describing the value of C is 100 °C, because it is the boiling point of water.Hence, The correct bis Option (B)

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Answer:a

Explanation:

Answer:

Answervis A.

Explanation:

Because,so that other scientists can validate the results.

I hope it's helpful!

Answer: A. An element with the valence electron configuration 5s1 would form a monatomic ion with a charge of  Answer: +1. In order to form this ion, the element will Answer:  lose electron(s) from/into the 5s subshell(s).

Explanation:

Based on the given reactions, the compounds are as follows:

A: The specific product formed from the reaction between prop-1-yne and either 2HBr or H2O2.

B: The product formed when compound A reacts with 2H2O.

C: The product formed when compound B reacts with K2CO3(aq).

D: The product formed from the heat-induced reaction of compound C.

E: The product formed when compound D reacts with HBr.

Based on the given reactions, let's analyze the compounds involved:

Reaction 1: prop-1-yne + 2HBr/H2O2 = A

The reactant prop-1-yne reacts with either 2HBr or H2O2 to form compound A. The specific product formed will depend on the reaction conditions.

Reaction 2: A + 2H2O = B

Compound A reacts with 2H2O (water) to form compound B.

Reaction 3: B + K2CO3(aq) = C

Compound B reacts with K2CO3(aq) (potassium carbonate dissolved in water) to form compound C.

Reaction 4: C + heat = D

Compound C undergoes a heat-induced reaction to form compound D.

Reaction 5: D + HBr = E

Compound D reacts with HBr (hydrobromic acid) to form compound E.

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H2O as an oxidant only

Given

Reaction

2 Na + 2 H2O → 2 NaOH + H2

Required

The function of water in the equation

Solution

Water : oxidizing agent

Na : reducing agent

Na⁰ → Na⁺ (oxidation)

H⁺- → H⁰ (reduction)

Acids and bases according to Bronsted-Lowry

Acid = donor (donor) proton (H⁺ ion)

Base = proton (receiver) acceptor (H⁺ ion)

If water is acting as an acid it should only give 1 H +, so that becomes:

H₂O (l) ⇔ OH⁻ (aq) not H₂

When the equilibrium constant is higher than one, it indicates that the reaction prefers to produce products, whereas if the equilibrium constant is less than one, it indicates that the reaction prefers to produce reactants. If the equilibrium constant is equal to one, the reaction proceeds in both directions equally.

In a chemical reaction, exothermic reactions are defined as reactions that release heat into their environment. It implies that heat is given off when reactants are converted to products. At equilibrium, an exothermic reaction continues to be exothermic, meaning that heat is given off even after the reaction reaches a state of equilibrium.There are two types of reactions: exothermic and endothermic.

A reaction is classified as exothermic if it releases heat, and endothermic if it absorbs heat. The direction of the reaction is determined by whether it is exothermic or endothermic. At equilibrium, the reaction is no longer moving forwards or backwards. It's also worth noting that reactions can be exothermic in one direction and endothermic in the other.

The equilibrium constant (K) is defined as the ratio of the concentration of products to the concentration of reactants in the chemical reaction equation. It is used to express how much of the products is generated by the reaction in comparison to the reactants.  the equilibrium constant aids in the identification of the direction in which the reaction will proceed at equilibrium.

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Answer:

letter: B

Explanation:

thats is the true answer.

pleas heart my heart my answer

The unknown gas : N₂

Given

Volume : 23.1 L

Mass : 28.85 g

Required

The identity of the unknown gas

Solution

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol

So mol for The unknown gas :

= 23.1 L : 22.4 L

= 1.0313

The molar mass of unknown gas :

= mass : mol

= 28.85 g : 1.0313

= 27.974 g/mol≈ 28 g/mol

23.1 L of nitrogen has a mass of 28.85 g at STP.

An unknown gas occupies 23.1 L at STP. We will calculate the moles of the gas, considering that 1 mole of an ideal gas occupies 22.4 L at STP.

\(23.1 L \times \frac{1mol}{22.4L} = 1.03 mol\)

1.03 moles of the unknown gas have a mass of 28.85 g. The molar mass of the gas is:

\(M = \frac{28.85 g}{1.03 mol} = 28.0 g/mol\)

A gas with a molar mass of 28.0 g/mol is likely to be nitrogen gas.

23.1 L of nitrogen has a mass of 28.85 g at STP.

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Answer: True

Explanation:

Phosphagens are high energy storage compounds that are usually found in the tissue of animals.

Based on the question, the molecules have similar functions in different organisms such as the fact that they can accept phosphoryl groups from ATP in a situation where the ATP is in excess. Also, they donate phosphoryl groups to ADP in order for the regeneration of ATP.

The standard reduction potential of the Cr³+/Cr electrode is -0.46V. None of the option is correct.

To determine the standard reduction potential of the Cr³+/Cr electrode, we can use the Nernst equation, which relates the standard reduction potential to the cell potential under non-standard conditions. The Nernst equation is given by:

E = E° - (0.0592/n) * log(Q)

where E is the cell potential, E° is the standard reduction potential, n is the number of electrons transferred in the half-reaction, and Q is the reaction quotient.

In this case, we have the standard potential of the cell as −0.60V. We know that the standard reduction potential of the Sn/Sn²+ electrode is -0.14V. Therefore, the reduction potential of the Cr³+/Cr electrode can be calculated as:

E = -0.60V - (-0.14V)

E = -0.60V + 0.14V

E = -0.46V

Therefore, the standard reduction potential of the Cr³+/Cr electrode is -0.46V.

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Answer:

When dry ammonia is passed over heated sodium in absence of air, the product formed is sodium amide. - When dry ammonia is passed over heated sodium in absence of air, sodium amide is produced. - Sodium amide aka sodamide is mainly used as a strong base in organic chemistry.

Explanation:

Answer: 55.5 oC is 0.014 atm (3rd decimal point)

Explanation:

The Clausius-Clapeyron equation is given as:

ln(P2/P1) = -(ΔH_vap/R) * (1/T2 - 1/T1)

where:

P1 = vapor pressure at temperature T1

P2 = vapor pressure at temperature T2

ΔH_vap = enthalpy of vaporization

R = gas constant = 8.314 J/(mol*K)

Converting the enthalpy of vaporization to J/mol:

ΔH_vap = 35.2 kJ/mol = 35,200 J/mol

Converting temperatures to Kelvin:

T1 = 64.7 + 273.15 = 337.85 K

T2 = 55.5 + 273.15 = 328.65 K

Substituting the values into the equation and solving for P2:

ln(P2/1 atm) = -(35,200 J/mol / 8.314 J/(mol*K)) * (1/328.65 K - 1/337.85 K)

ln(P2/1 atm) = -4.231

P2/1 atm = e^(-4.231)

P2 = 0.014 atm

Therefore, the vapor pressure for methanol at 55.5 oC is 0.014 atm, to the third decimal point.

Answer:

Hydrogen, lithium, sodium, and potassium all have 1 valence electron ( an electron in the outermost energy level is a valence electron).