Plz help, and it's easy, 3D shapes ASAP

During the month of May, there were 130 births, of which the newborn death rate is 38.4615.

According to the question,

There were 130 births, of which 127 were full-term births and three were premature births. There were five newborn deaths.

In order to find the newborn death rate we have the formula:

=  \(\frac{number of death under 28 days of age }{Total live births in the same year}\)  × 1000

= \(\frac{5}{130}\) × 1000

=\(\frac{5000}{130}\)

=38.4615

Hence, the new born death rate is 38.4615.

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Answer:

a. The total charge for first restaurant (in dollars) = 16x + 8

The total charge for the second restaurant (in dollars) = 18x

b. 16x+8=18x models the equation when the charge would be same for both restaurants.

Step-by-step explanation:

Given that:

Delivery charges of first restaurant = $8

Price per pizza = $16

Let,

x be the number of pizzas bought

Total cost = 16x + 8

There are no delivery charges for the second restaurant.

Price per pizza = $18

Total cost = 18x

The charge will be the same when

Total cost of first restaurant = Total cost of second restaurant

16x + 8 = 18x

Hence,

a. The total charge for first restaurant (in dollars) = 16x + 8

The total charge for the second restaurant (in dollars) = 18x

b. 16x+8=18x models the equation when the charge would be same for both restaurants.

The total probability of a girl having a "K-name" is 3/8. The total probability of there being a girl in the club is 5/8.

Therefore, the conditional probability of having a girl with a "K-name" given that there is a girl in the club can be calculated as follows:

P (Girl | K-name) = P (K-name | Girl) × P (Girl) / P (K-name) = 2/5 * 5/8 / 3/8 = 2/3

Therefore, the probability of a girl with a K-name given that there is a girl in the club is 2/3.

In a club consisting of 5 girls (Kirsten, Sarah, Suzie, Monica, and Katie) and 3 boys (Kevin, Steve, and Samuel), we are asked to find P(Girl | K-name).

We can use Bayes' theorem to calculate the conditional probability of this event. This theorem states that the probability of an event given another event can be calculated as the product of the probability of the second event Therefore, the probability of a girl having a "K-name" given that there is a girl in the club is 2/3.

The conditional probability of there being a girl in the club given that a girl has a K-name is 2/3.

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Answer:

B: -1/4

Step-by-step explanation:

Answer = 320.05 (to 2 d.p)

The answers, rounded to the appropriate number of significant figures, are as follows:

(a) 1.088 ×\(10^2\)

(b) 2.132

(c) 1.3331 ×\(10^1\) and

(d) 1.05.

Let's calculate the answers to the given operations using the appropriate number of significant figures.

(a) 8.370×1.3×10

To perform this multiplication, we multiply the decimal numbers and add the exponents of 10:

8.370 × 1.3 × 10 = 10.881 × 10 = 1.0881 × \(10^2\)

Since the original numbers have four significant figures, we round the final answer to four significant figures:

1.088 × \(10^2\)

(b) 4.265/2.0

For division, we divide the decimal numbers:

4.265 ÷ 2.0 = 2.1325

Since both numbers have four significant figures, the answer should be rounded to four significant figures:

2.132

(c) (1.2588×\(10^3\))×(1.06×\(10^-^2\))

To multiply these numbers, we multiply the decimal numbers and add the exponents:

(1.2588 × \(10^3\)) × (1.06 × \(10^-^2\)) = 1.333128 × \(10^1\)

Since the original numbers have five significant figures, we round the final answer to five significant figures:

1.3331 × \(10^1\)

(d) \((1.11)^(^1^/^2^)\)

To calculate the square root, we raise the number to the power of 1/2:

\((1.11)^(^1^/^2^)\)= 1.0524

Since the original number has three significant figures, the answer should be rounded to three significant figures:

1.05

It's important to note that the significant figures in a result are determined by the original data and the operations performed. The final answers provided above reflect the appropriate number of significant figures based on the given information and the rules for significant figures.

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Yellow shirt probability is 1/4, 0.25 and 25%

Answer:

Think proportion and ratio.

The ball bounced twice and travelled 12ft.

The first bounce is twice the distance of the second bounce so the second bounce must be equal to two of the first.

2:1 of a total 12.

You now have three parts 12/3 =4

The first bounce is 2 times this amount which is 8 ft the second bounce was 4 ft as it was only one part.

To display formulas, one way is to press the key combination [Ctrl]+[] (grave accent).

The key combination [Ctrl]+[] is used to display formulas.

This is a useful feature for checking and editing formulas without altering the calculated values.

By pressing [Ctrl]+[], users can easily view the underlying formulas and ensure their accuracy.

This key combination provides a convenient way to switch between the formula view and the results view, enabling efficient editing and troubleshooting of complex calculations.

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Answer:

9+6

Step-by-step explanation:

6 + 9 is similar to 9+6 because they both equal 15

Answer:

\(15\)

Step-by-step explanation:

\(6 + 9 = 15\)

For and example ,u have 6 apples with you and your friend gave more 9 apples to you. Now think how many apples are there with you. there are 15 apples.

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

14x+12

Step-by-step explanation:

6 + 2(7x + 3)

= 6+14x+6

= 14x+12

Answer:

L=25

W=10

Step-by-step explanation:

Answer:

Use the perimeter to find x:

\(x + x + 6x + 6x = 70\\14x=70\\x=5\)

Therefore,

The UCL-X for the average diameter is 0.564374 inches.
The LCL-X for the average diameter is 0.555626 inches.
Using a sample size of 6, the A2 value is 0.729.

The UCL-X (Upper Control Limit for the average) and LCL-X (Lower Control Limit for the average) can be determined using the formula:

UCL-X = Average diameter + (A2 * R)
LCL-X = Average diameter - (A2 * R)
1. Calculate A2 value using a control chart constants table. For a sample size of 6, A2 value is 0.729.
2. Plug in the values into the formulas:
  UCL-X = 0.56 + (0.729 * 0.006)
  LCL-X = 0.56 - (0.729 * 0.006)
3. Simplify the calculations:
  UCL-X = 0.56 + 0.004374 = 0.564374 inches
  LCL-X = 0.56 - 0.004374 = 0.555626 inches

Therefore, the UCL-X for the average diameter is 0.564374 inches.
The LCL-X for the average diameter is 0.555626 inches.
Using a sample size of 6, the A2 value is 0.729.

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Answer:144 in.

Step-by-step explanation:

A critical value, z subscript alpha (zα), denotes the boundary or cutoff point for a statistical test where the level of significance, also known as alpha (α), is set.

A critical value, z subscript alpha (zα), denotes the value at which the probability of observing a test statistic in the tail(s) of the sampling distribution equals the pre-determined significance level (alpha).

The critical value can be defined as the value that is compared with the parameter value in the hypothesis test to determine whether the null hypothesis will be rejected. If the value of the parameter is less than the critical value, the null hypothesis is rejected.

However, if the measured value is higher than the critical value, reject the null hypothesis and accept the alternative hypothesis. In other words, cropping divides the image into acceptable and unacceptable areas. If the value of the index falls within the rejection range, the rejection of the fact is rejected, otherwise the negative hypothesis is rejected.

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Answer:

c=125 dollars

Step-by-step explanation:

c=25p

p(people)=5

c=25*5

c=125

Answer:

\(\textsf{B.} \quad 3.14, \; \pi, \; \dfrac{22}{7}, \;\sqrt{10}\)

Step-by-step explanation:

The given set of numbers (in any order) is:

\(\pi, \;\sqrt{10}, \; 3.14, \; \dfrac{22}{7}\)

Convert each number to its decimal equivalent to 4 decimal places:

\(\implies \pi=3.1416\;(\sf 4\;d.p.)\)

\(\implies \sqrt{10}=3.1623\;(\sf 4\;d.p.)\)

\(\implies 3.14 = 3.1400\;(\sf 4\;d.p.)\)

\(\implies \dfrac{22}{7}=3.1429\;(\sf 4\;d.p.)\)

Each number has 3 units and 1 tenth.

Comparing the hundredths, all the numbers have 4 hundredths except √10 which has 6 hundredths.  Therefore, √10 is the largest number since 6 > 4.

Comparing the thousandths of the other three numbers, 3.14 is the smallest number as it has zero thousandths.

π is the next smallest as it has a one thousandth.

Therefore, the given set of numbers in increasing order is:

\(3.14, \; \pi, \; \dfrac{22}{7}, \;\sqrt{10}\)

The maximum angle of the incline for the car to be at rest using only friction is 38.7° if, for the car on the incline, the coefficient of static friction is 0.8 and the coefficient of kinetic friction is 0.6.

If the car is at rest on the incline, the force of gravity acting on the car down the incline is balanced by the force of static friction acting up the incline. The maximum angle \($\theta$\) of the incline is the angle at which the force of static friction is at its maximum, which is given by the product of the coefficient of static friction and the normal force.

Let's assume that the mass of the car is m and the incline makes an angle of \($\theta$\) with the horizontal. Then, the force of gravity acting on the car down the incline is given by \($mg\sin(\theta)$\), where g is the acceleration due to gravity. The normal force acting on the car perpendicular to the incline is given by \($mg\cos(\theta)$\).

For the car to be at rest on the incline, the force of static friction acting up the incline must be equal in magnitude to the force of gravity down the incline. Therefore, we have:

\($$\mu_s mg\cos(\theta) = mg\sin(\theta)$$\)

here \($\mu_s$\) is the coefficient of static friction. Simplifying this equation,

we get:

\($$\tan(\theta) \leq \mu_s$$\)

Therefore, the maximum angle \($\theta$\) of the incline is:

\($$\theta \leq \tan^{-1}(\mu_s)$$\)

Substituting the value of \($\mu_s = 0.8$\), we get:

\($$\theta \leq \tan^{-1}(0.8) \approx 38.7^{\circ}$$\)

Therefore, the maximum angle of the incline for the car to be at rest using only friction is approximately 38.7°.

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Answer:

Yearly fee of $48 is better

Step-by-step explanation:

It is obvious. We know that a year have 12 months so if we compare between the $30 per months deal (which is $360 a year when we multiple it with 12) and the $48 a year deal, the difference is $312 which is a lott.

If Maria only want to use it for a month then its fine but if she want to use it more than 1 month, she definitely should choose the no 2 deal because if she even only rent it for 2 months using the no 1 deal ($30+$30=$60), the no 2 deal ($48) is far more better with a $12 difference.

Part A: Just like the top we know that its costs $34 per month and we need to know how much it would costs for 12 months/a year. So we just have to multiple it with 12=$408. Now which is better $495 or $408? Of course its $408 right? Maria could save $87 with renting the trombone than buying the trombone.

Answer:

number of men = 30

Step-by-step explanation:

18 men takes 15 days to dig 6 hectares of land.

18 men will take 12 days to dig ? hectares of land

cross multiply

hectares of land = 12 × 6/15  

hectares of land = 72/15

hectares of land = 4.8 hectares

18 men will take 12 days to dig 4.8 hectares of land

? number of men will take 12 days to dig 8 hectares

cross multiply

number of men = 18 × 8/4.8

number of men = 144/4.8

number of men = 30

Answer:

x = 3, y = 7

Step-by-step explanation:

Given the 2 equations

y - x = 4 → (1)

3x + y = 16 → (2) ← rearrange

y + 3x = 16 → (2)

Multiplying (1) by - 1 and adding to (2) will eliminate the y- term

- y + x = - 4 → (3)

Add (2) and (3) term by term to eliminate y

4x = 12 ( divide both sides by 4 )

x = 3

Substitute x = 3 into either of the 2 equations and solve for y

Substituting into (1)

y - 3 = 4 ( add 3 to both sides )

y = 7

The population in this scenario is option D) The SAT scores from all recent applicants.

The admission committee at the university was interested in the average SAT score of the recent high school graduates who had applied to the university. Therefore, the population of interest is the SAT scores of all recent applicants. However, since the number of applicants was very large, the committee chose to sample 50 applicants randomly and evaluate the average of the 50 scores. This sample was used to estimate the population mean SAT score. It is important to note that the sample of 50 applicants is not the population in this scenario. Instead, it is a subset of the population that was selected to estimate the population mean. The statistician will use this sample mean to make inferences about the population mean SAT score.

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Answer:

Part a.

An angle bisector divides the angle into two congruent angles.

m<FGH = m<HGI

2x - 4 = 3x - 22

Subtract 2x from both sides. Add 22 to both sides.

18 = x

x = 18

Now that we know x = 18,

m<FGH = 2x - 4 = 2(18) - 4 = 36 - 4 = 32

m<FGH = 32

Part b.

m<HGI = 3x - 22 = 3(18) - 22 = 54 - 22 = 32

m<HGI = 32

Part c.

m<FGI = m<FGH + m<HGI = 32 + 32 = 64

m<FGI = 64

Step-by-step explanation:

The correct answer is C. The Mode.

Data is the collection of data term that is organized and formatted in a specific way it's typically contains fact observation or statistics that are collected through a process of measurement or research data set can be used to answer question and help make informed decision they can be used in a variety of ways such as to identify trends on cover patterns and make prediction.

This measure of centre is most meaningful when the data is qualitative because it shows the value that appears most frequently in the data set. The mode can be used to identify the most popular item or most commonly occurring outcome. It is the only measure of centre that can be used for qualitative data, as the other measures (mean, median, and range) require numerical data.

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Answer:

2 x 3 = 6 cups

Step-by-step explanation:

Answer: x=-8

Step-by-step explanation:

X+5=1-4

X+5=-3

Now subtract 5 from both sides

X=-8

The group that would be the most stable based on size would be 10 people. So, the correct answer is c. 10 people.

A group is a set of people or objects that are deemed to be equivalent or share a common feature. Group members may collaborate and share knowledge to achieve a common goal. The group's performance is frequently greater than the sum of its members' individual efforts, and this is known as the group effect.

Group stability is defined as the ability of a group to remain together and keep working toward its objective over time. It is essential for a group to achieve its objectives and is typically linked to the group's size and objective. A stable group can withstand external pressures and is less susceptible to breaking up or being disbanded.

A group's size has a significant influence on its stability. Small groups are often more cohesive and productive than large groups. On the other hand, as a group's size grows, it becomes more challenging to sustain cohesion and productivity. A group of 10 people would be the most stable since it's not too large or too small. Thus, the correct option is c. 10 people.

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(a) Using the fact that the tank is empty after 50 minutes, we can set up a differential equation to describe the rate of change of salt in the tank. (b) The maximum amount of salt will occur at one of these critical points,  the maximum amount of salt in the tank.

(a) To find the amount of salt in the tank after t minutes, we need to consider the rate at which salt enters and leaves the tank. Since brine enters at a rate of 2 gallons per minute and contains 2 lb of salt per gallon, the rate of salt entering the tank is 2 * 2 = 4 lb per minute. Meanwhile, the solution leaves the tank at a rate of 3 gallons per minute, so the rate of salt leaving the tank is 3 * (x / t), where x is the amount of salt in the tank at time t. Using the fact that the tank is empty after 50 minutes, we can set up a differential equation to describe the rate of change of salt in the tank and solve it to find the amount of salt as a function of time.

(b) The maximum amount of salt ever in the tank can be found by determining the time at which the amount of salt reaches its maximum value. To do this, we can take the derivative of the amount of salt function and set it equal to zero to find the critical points. The maximum amount of salt will occur at one of these critical points, and we can evaluate the function at that point to find the maximum amount of salt in the tank.

In summary, we can determine the amount of salt in the tank at any given time using a differential equation based on the rates of inflow and outflow of salt. By solving this equation, we can find the amount of salt after t minutes. Additionally, by finding the critical points of the amount of salt function and evaluating it at those points, we can determine the maximum amount of salt ever in the tank.

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Answer:

y=\(\sqrt[3]{x-1}\)

Step-by-step explanation:

y=x^3-1

Switch y and x

x=y^3-1

Solve for y

x-1=y^3

y=\(\sqrt[3]{x-1}\)