plssssssssss help because i need to go to basketball practice

Answer:

Step-by-step explanation:

\(8(j-6) +2 (5j-6)\\\\\mathrm{Expand}\:8\left(j-6\right):\quad 8j-48\\\\=8j-48+2\left(5j-6\right)\\\\\mathrm{Expand}\:2\left(5j-6\right):\quad 10j-12\\\\=8j-48+10j-12\\\\\mathrm{Simplify}\:8j-48+10j-12:\\\quad 18j-60\)

Answer:

220 adults and 250 children

Step-by-step explanation:

we require to set up 2 equations and solve simultaneously.

let a be the number of adults and c the number of children , then

a + c = 470 → (1) based on number of people

3a + c = 910 → (2) based on ticket sales

subtract (1) from (2) term by term to eliminate c

(3a - a) + (c - c) = 910 - 470

2a + 0 = 440

2a = 440 ( divide both sides by 2 )

a = 220

substitute a = 220 into (1) and solve for c

220 + c = 470 ( subtract 220 from both sides )

c = 250

that is 220 adults and 250 children attended

According to the graph, the value of the function g(-3) is 4 and g(10) is out of view

Graphs are graphical representations of equations, ordered pairs, tables of a relation

From the question, the function is represented by the attached graph

Also from the question, the function to calculate is given as g(10) and g(-3)

This means that we calculate the values of the function, when x = 10 and -3

i.e.

We calculate g(x), when x = -3

We calculate g(x), when x = 10

So, we look at the graph for this function value

From the graph of values, we have

When x = -3, g(x) = 4

When x = 10, g(x) = not visible

This means that

g(-3) = 4

g(10) = out of view

Hence, the function g(-3) has a value of 4 and g(10) is out of view

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Answer:

Quadrilateral: 20.5 units

Triangle: 8.6 units

Step-by-step explanation:

Quadrilateral:
We can use the following formula to find the perimeter of a quadrilateral.

Perimeter = AB + BC + CD + DA

where AB, BC, CD, and DA are the lengths of the four sides of the quadrilateral.

In your case, the coordinates of the vertices of the quadrilateral are A(-3,-1), B(-3,3), C(2,3), and D(4,-1).

Using the distance formula, we can find the lengths of the four sides of the quadrilateral as follows:

\(AB = \sqrt{(-3 - (-3))^2 + ((-1) - 3)^2} = \sqrt{16} = 4\)

\(BC = \sqrt{(-3 - 2)^2 + ((3) - 3)^2} = \sqrt{25}= 5\)

\(CD = \sqrt{(2 - 4)^2 + ((3) - (-1))^2} = \sqrt{4+16} = 2\sqrt{5}\)

\(DA = \sqrt{(4 - (-3))^2 + ((-1) - 1)^2} = \sqrt{49} =7\)

Therefore, the perimeter of the quadrilateral is:

Perimeter = AB + BC + CD + DA

= \(4+5+2\sqrt5+7=20.5\) units

Triangle

The perimeter of a triangle is the total length of all three sides of the triangle. To find the perimeter of a triangle, we can use the following formula:

Perimeter = AB + BC + CA

where AB, BC, and CA are the lengths of the three sides of the triangle.

In your case, the coordinates of the vertices of the triangle are

E(-4,1), F(-2,3), and G(-2,4). Using the distance formula, we can find the lengths of the three sides of the triangle as follows:

\(EF = \sqrt{(-4 - (-2))^2 + ((1) - (3))^2} = 2\sqrt{2}\)

\(FG = \sqrt{(-2 - (-2))^2 + ((3) - (4))^2} = 1\)

\(EG = \sqrt{(-4 - (-2))^2 + ((1) - (4))^2} = \sqrt{4 + 9} = \sqrt{13}\)

Therefore, the perimeter of the triangle is:

Perimeter = EF + FG + EG

= 4 + 1 + \(\sqrt{13}\)

=8.6 units

Therefore, the perimeter of the quadrilateral is 20.5 units and the perimeter of the triangle is 8.6 units

The final result of the integral is:

∫ (log(1 + x²) / (x + 1)²) dx = log(x + 1) - 2 (log(x + 1) / x) - 2Li(x) + C,

where Li(x) is the logarithmic integral function and C is the constant of integration.

We have,

To solve the integral ∫ (log(1 + x²) / (x + 1)²) dx, we can use the method of substitution.

Let's substitute u = x + 1, which implies du = dx. Making this substitution, the integral becomes:

∫ (log(1 + (u-1)²) / u²) du.

Expanding the numerator, we have:

∫ (log(1 + u² - 2u + 1) / u²) du

= ∫ (log(u² - 2u + 2) / u²) du.

Now, let's split the logarithm using the properties of logarithms:

∫ (log(u² - 2u + 2) - log(u²)) / u² du

= ∫ (log(u² - 2u + 2) / u²) du - ∫ (log(u²) / u²) du.

We can simplify the second integral:

∫ (log(u²) / u²) du = ∫ (2 log(u) / u²) du.

Using the power rule for integration, we can integrate both terms:

∫ (log(u² - 2u + 2) / u²) du = log(u² - 2u + 2) / u - 2 ∫ (log(u) / u³) du.

Now, let's focus on the second integral:

∫ (log(u) / u³) du.

This integral does not have a simple closed-form solution in terms of elementary functions.

It can be expressed in terms of a special function called the logarithmic integral, denoted as Li(x).

Therefore,

The final result of the integral is:

∫ (log(1 + x²) / (x + 1)²) dx = log(x + 1) - 2 (log(x + 1) / x) - 2Li(x) + C,

where Li(x) is the logarithmic integral function and C is the constant of integration.

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Answer:

\(6p+4q=r\\\\4q = r-6p\)

\(q = \frac{r}{4} -\frac{6}{4}p \\\\q = \frac{r}{4} -\frac{3}{2}p\)

The completion of the ratios, resulting from the square feet occupied by Departments A and B, and the amounts of allocated overhead costs to the two departments are as follows:

                           Ratio      Amount

Department A     0.25       $15,000

Department B     0.75      $45,000

The ratio is the proportion of the whole shared by two or more numbers.

Ratios are fractional values like proportions.

Ratios, depicted in fractions, decimals, and percentages, show how much a value or variable is contained in another.

Total distributable overhead = $60,000

Ratios = 10,000:30,000

= 1:3

Sum of Ratios = 4

OR

= 0.25:0.75

Sum of Ratios = 1

Department   Square Feet  Ratio    Amount of Overhead Allocated

Dept. A            10,000         A = 1      B = $15,000 ($60,000 x 0.25)

Dept. B            30,000        C = 3     D = $45,000 ($60,000 x 0.75)

Thus, based on the cost driver ratios, Department A bears $15,000, while Department B will be allocated $45,000 of the distributable overheads.

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The correct options that could be constructed by Brian using his straightedge to draw some chords of circle C are:

Equilateral triangle MNQ inscribed in circle C

Regular hexagon AMNBPQ inscribed in circle C

Brian is constructing figures inscribed in circle C.

Equilateral triangle MNQ inscribed in circle C:

This option is possible since the points M, N, and Q are labeled and they lie on circle C.

Equilateral triangle ANP inscribed in circle C:

This option is not possible. The points A and P are labeled, but the third vertex of the equilateral triangle is not specified.

Regular hexagon AMNBPQ inscribed in circle C:

This option is possible since the points A, M, N, B, P, and Q are labeled and they lie on circle C.

Square MNPQ inscribed in circle C:

This option is not possible based on the given information. The label points do not form a square.

Square ANBQ inscribed in circle C:

This option is not possible . The points A, N, B, and Q are labeled, but they do not form a square.

The correct options that could be constructed by Brian using his straightedge to draw some chords of circle C are:

Equilateral triangle MNQ inscribed in circle C

Regular hexagon AMNBPQ inscribed in circle C

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The vertical displacement is of 2 units down, the correct option is B.

Remember that for a function f(x), a vertical displacement of N units is written in general form as:

g(x) = f(x) + N

If N > 0, the translation is upwards.

if N < 0, the translation is downwards.

Here we assume that we start with the parent cosine function:

y = cos(x)

And the transformed function is:

y = -2 - cos(x - π)

So we have some transformations, but the vertical translation is of 2 units down. So the correct option is B.

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The general solution for the equation 5tan(θ) - 6cos(θ) = 0 is:

θ = sin⁻¹(2/3) + nπ, where n is an integer.

To determine the general solution of the trigonometric equation 5tan(θ) - 6cos(θ) = 0, we can use algebraic manipulation and trigonometric identities to simplify and solve for θ.

Starting with the given equation:

5tan(θ) - 6cos(θ) = 0

First, we can rewrite the tangent function in terms of sine and cosine:

5(sin(θ)/cos(θ)) - 6cos(θ) = 0

Next, multiply through by cos(θ) to eliminate the denominator:

5sin(θ) - 6cos²(θ) = 0

Using the identity sin²(θ) + cos²(θ) = 1, we can express cos²(θ) as 1 - sin²(θ):

5sin(θ) - 6(1 - sin²(θ)) = 0

Expanding and rearranging terms:

5sin(θ) - 6 + 6sin²(θ) = 0

Rearranging the equation:

6sin²(θ) + 5sin(θ) - 6 = 0

Now, we have a quadratic equation in terms of sin(θ).

We can solve this quadratic equation by factoring or using the quadratic formula.

However, since this equation is not easily factorable, we will use the quadratic formula:

sin(θ) = (-b ± √(b² - 4ac)) / 2a

For our equation:

a = 6, b = 5, c = -6

Plugging these values into the quadratic formula and simplifying, we get:

sin(θ) = (-5 ± √(5² - 4(6)(-6))) / (2(6))

sin(θ) = (-5 ± √(25 + 144)) / 12

sin(θ) = (-5 ± √169) / 12

sin(θ) = (-5 ± 13) / 12.

This gives us two possible solutions for sin(θ):

sin(θ) = (13 - 5) / 12 = 8/12 = 2/3

sin(θ) = (-13 - 5) / 12 = -18/12 = -3/2

Since the range of the sine function is -1 to 1, the second solution (-3/2) is not valid.

Now, to find the values of θ, we can use the inverse sine function (sin⁻¹) to solve for θ:

θ = sin⁻¹(2/3)

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Answer:

A =625 ft^2

Step-by-step explanation:

The perimeter of a square is

P = 4s where s is the side length

100 =4s

Divide each side by 4

100/4 = 4s/4

25 = s

A = s^2 for a square

A = 25^2

A =625

Answer:

Step-by-step explanation:

If you add up all the male and female categories, the total is 400

the number of females between 22 and 39 is 51

P(22 - 39)  = 51 / 400

P(22 - 39) = 0.1275

I think the answer you want is 51/400

The graph of the system of the inequalities is attached.

To graph the inequalities y < -x - 4 and y ≥ (3/5)x + 4, we can start by graphing the corresponding equations and then shade the appropriate regions based on the inequality signs.

Let's begin with the equation y = -x - 4:

Choose a range of x-values to plot.

For simplicity, let's use x-values from -10 to 10.

Substitute different x-values into the equation to find corresponding y-values.

For example:

When x = -10, y = -(-10) - 4 = 10 - 4 = 6.

When x = 0, y = -(0) - 4 = -4.

When x = 10, y = -(10) - 4 = -10 - 4 = -14.

Plot these points on the coordinate plane and draw a straight line passing through them.

This line represents the equation y = -x - 4.

Next, let's graph the equation y = (3/5)x + 4:

Again, choose a range of x-values to plot. Let's use the same range of -10 to 10.

Substitute different x-values into the equation to find corresponding y-values. For example:

When x = -10, y = (3/5)(-10) + 4 = -6 + 4 = -2.

When x = 0, y = (3/5)(0) + 4 = 0 + 4 = 4.

When x = 10, y = (3/5)(10) + 4 = 6 + 4 = 10.

Plot these points on the coordinate plane and draw a straight line passing through them.

This line represents the equation y = (3/5)x + 4.

Now, let's shade the regions based on the inequalities:

For y < -x - 4, we need to shade the region below the line y = -x - 4.

For y ≥ (3/5)x + 4, we need to shade the region above or on the line y = (3/5)x + 4.

Hence, the region where the shaded regions overlap represents the solution to both inequalities.

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The function represented by the graph given is equivalent to -

g(x) = (x - 4)².

The function plotted represents a quadratic equation. A quadratic equation has a degree of 2. The given function is shifted to the left by 4 units. This means that the following transformation will take place on the x - coordinate of each and every point lying on the graph -

f(x, y) → f(x - 4, y)

So, we can write the function as -

g(x) = (x - 4)²

So, the function represented by the graph given is equivalent to -

g(x) = (x - 4)²

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Answer:

3.1

Step-by-step explanation:

23.5-6.8x

x=3

first put 3 in for x

23.5-6.8(3)

now solve the expression

23.5-20.4

3.1

The population increased by 18 million at the end of one year at the rate of 1.8%.

The Latin word "per centum," which means "by the hundred," is where the word "percentage" originally came from. With 100 as the denominator, percentages are fractions. Alternatively put, it is the relationship between a component and a whole in which the value of "whole" is always assumed to be 100.

For instance, if a student receives 15 out of 50 in math, one can determine the relevant percentage by expressing "marks earned" as a fraction of "total marks" and multiplying the result by 100. i.e., the percentage of marks is equal to 15 / 50 100, or 30%.

Given that, population of India is one billion.

The rate of increase is 1.8%.

After one year the population will be:

P = (1000000000)(1.8/100)

P = 18000000

Hence, the population increased by 18 million at the end of one year at the rate of 1.8%.

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To accumulate $400,000 for retirement in 35 years with a 6% interest rate, you would need to save approximately $2,090.77 per year.

We can use the formula for calculating the future value of an ordinary annuity.

The formula for the future value of an ordinary annuity is:

FV = P * ((1 + r)^n - 1) / r

In this scenario:

FV = $400,000

r = 6% = 0.06

n = 35 years

Let's substitute the values into the formula and solve for P:

\($400,000 = P * ((1 + 0.06)^35 - 1) / 0.06\)

Solving for the annual payment (P) required:

\(P = ($400,000 * 0.06) / ((1 + 0.06)^{35} - 1)\)

Using a calculator, we can evaluate this expression:

P ≈ $2,090.77

Therefore, to accumulate $400,000 for retirement in 35 years with a 6% interest rate, you would need to save approximately $2,090.77 per year.

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Answer:The inequality represented by the equation y = -11/7x - 4 can be written as:

y ≤ -11/7x - 4

This represents a less than or equal to inequality, indicating that the values of y are less than or equal to the expression -11/7x - 4.

Step-by-step explanation: .

Answer:

(3.70 - 2.92) / 2.92 = about 0.27%.

The method is: Find the increase and find the ratio of the increase and the old price.

The percentage increase is 20%

A percentage is defined as the ratio that can be expressed as a fraction of 100.

The method below shows how you would calculate the % increase.

First step: Find the increase:

increase = 480 - 400 = $80

Second step: Find the ratio of the increase and the old price and multiply by 100 to express in percentage:

80/400 * 100 = 20%

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Answer:

$28.80 per hour

Step-by-step explanation:

60 ÷ 5 = 12

4 × 12 = 4.8

He makes $00.48 per minute.

.48 × 60 = 28.80

Answer:

It is 12

Step-by-step explanation:

Hope this helped have an amazing day!

Answer:

See below.

Step-by-step explanation:

A

To find the inverse of f(x), we start by replacing f(x) with y

y = 3/(7x+1)

Next, we swap the positions of x and y

x = 3/(7y+1)

Now we solve for y

7yx + x = 3

7yx = 3 - x

y = (3 - x) / 7x

Therefore, the inverse of f(x) is f^-1(x) = (3 - x) / (7x).

B

To verify that g(x) = f^-1(x), we need to show that f(g(x)) = x.

We know that g(x) = f^-1(x) = (3 - x) / (7x).

So, we can substitute g(x) into f(x) and simplify

f(g(x)) = 3 / (7(g(x)) + 1)

= 3 / (7((3 - x) / (7x)) + 1)

= 3 / ((3 - x) / x + 1)

= 3x / (3 - x + x)

= 3x / 3

= x

Therefore, we have shown that f(g(x)) = x, which means that g(x) is indeed the inverse of f(x).

Answer:

x=-1, y=4. (-1, 4).

Step-by-step explanation:

-6x-y=2

-7x-4y=-9

----------------

y=-6x-2

-7x-4(-6x-2)=-9

-7x+24x+8=-9

17x=-9-8

17x=-17

x=-17/17

x=-1

-6(-1)-y=2

6-y=2

y=6-2=4

Answer:

56

Step-by-step explanation:

Each step of this theorem is proved below.

Given that,

S is finite,

Now enumerate all of its elements as x₁, x₂,..., x\(_{n}\).

According to the cancellation rule,

This product is independent of the order of the factors.

As a result, we can define the identity element e as this product.

It is simple to demonstrate that e meets the criteria of an identity element.

Now, let's show that every element of S has an inverse.

Let a be any element of S. Consider the set {a, a, a, ...}.

Since S is finite,

There exist positive integers m and n such that

am = an   for some m > n.

By the cancellation law,

We can cancel a power of a from both sides to get a\({(m-n)}\) = e.

This means that a has an inverse, and we can conclude that S is a group.

Consider the set of all positive integers under addition, except 1, as an example of an infinite semigroup in which the cancellation laws hold but which is not a group.

This set clearly meets the cancellation laws, but it does not have an inverse for every element, because the inverse of 2, for example, is not an integer.

As a result, this is not a group.

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Answer:

the other ones can be 100, 80 & 80

Step-by-step explanation:

Step 1: Isolate the Sin Operator

\(8 sin(\frac{\pi }{6} x)=2\\sin(\frac{\pi }{6} x)=0.25\\\\\)

Step 2: Use Inverse Sin(arcsin) to isolate the term with the x variable

Note that since trig functions have 2 general solutions, this will give us one of our general solutions.

\(x=\frac{6 arcsin(0.25)}{\pi } =0.48\)

x₁= 0.48

Solving for x₂

Use the period identity for Sin Functions

\(sin(x)=sin(\pi -x)\)

X in this case is arcsin(0.25)

\(\frac{\pi }{6} x=\pi -arcsin(0.25) = 5.52\)

So our two general solutions are 0.48 and 5.52

Step 3: Period

Trig Functions have periodic behavior and this function period is

\(\frac{2\pi }{1} (\frac{6}{\pi } )= 12\)

So our general solutions are

0.48±12k, where k is an integer

5.52±12k, where k is an integer

Let k=1, and we get our next set of solutions:

12.48 and 17.52

So our answer is 0.48,5.52,12.48,17.52

Answer:

the point is in Quadrant 4 and the best match in the options is;

Point D

Explanation:

Given the polar coordinates;

To simplify, let us convert it to rectangular coordinates;

so, we have;

The rectangular coordinate of the given point is;

Therefore, the point is in Quadrant 4 and the best match in the options is;

Point D

Answer:

Effective output = 224

Capacity Utilization = 80%

Step-by-step explanation:

Given the maximum output = 280

The actual output = 195

The efficiency = 80%

Below is the formula to calculate the efficiency.

Efficiency in percentage  = (Effective output /  Maximum output) x 100

Insert the given values in the formula.

80 =( Effective output / 280 ) x 100

Effective output = 280 x 0.8

Effective output = 224

Now the Capacity utilization ( %) = Actual output / Maximum output x 100

Capacity utilization in percentage  = 224 / 280   x   100

Capacity Utilization = 80%