PLSSSS HELP IN HURRY Wilton drives a taxicab. He charges $40 per hour. One passenger gave Wilton a tip of $30.

How much would Wilton earn if he drove another passenger for 5.5 hours and received the same tip?

Question 3 options:

$250


$2,500


$225


$150

The scale factor of the quadrilaterals is equal to 3 / 4.

In this problem we find the case of two similar quadrilaterals, two quadrilaterals are similar when their internal angles are congruent and sides are not congruent though proportional. Then, both figures can be related by proportion formula:

JN / JP = HN / LP = EH / KL = EJ / KJ

From which we can determine the scale factor. If we know that JN = 36, JP = 48, HN = 18, LP = 24, then the proportion formula is:

k = 36 / 48 = 18 / 24

k = 3 / 4 = 3 / 4

The two quadrilaterals have a scale factor of 3 / 4.

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Answer:

One piece of fabric: 10 x 6, or 60.

If one triangle is 15, she can cut 4 triangles from each piece of fabric.

If she has 24 pieces  of fabric, she can cut 4 x 24, or 96 triangle patches.

Let me know if this helps!

To design a simulation for this situation, one can generate a set of four numbers by using the number generator with numbers 0 to 5 representing those who prefer watching a movie at a theatre and 6 to 9 representing those who do not.

From the information given about the probability, the goal here is to design a simulation for this situation.

In this case, to design a simulation for this situation, one can generate a set of four numbers by using the number generator.

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Answer:

π(70)(√(70^2 + 50^2)) = π(700√74) m^3

= 18,918 m^3

Answer:

9,149.10

Step-by-step explanation:

To get the average you take all the values and add them up then divide by 5.

767,542 divided by 5 = 153,508.40

Now to get the percentage take 5.96 and divide by 100 = 0.0596

With this you can multiple the average by the percent in decimal form.

153,508.40 * 0.0596 = 9,149.10

Answer: The distance is about 5.39 units

Step-by-step explanation:

To find the distance between the two points find the difference in the x and y coordinates and square them to add them and find their square root.

4-(-1) = 5

-1 -1 = -2

5^2 + -2^2 = d^2  where d is the distance

25 + 4 = d^2

29 = d^2

d = \(\sqrt{29}\)

d= 5.39

Answer:

91

Step-by-step explanation:

P>J and P>M

269 -> split into 3 parts

Approx is 90

IF Peter's score is 90, then the other 2 scores could be 90 and 89

+ 1 to Peter's score

Hence Peter's least possible score could be 91.

Answer:

D

Step-by-step explanation:

multiplying 35.22 with r since this amount is charged for every repair and then adding 62 since that is the additional fee

The length of the arc that subtends a central angle of 5 radians in a circle with a radius of 7 feet is 35 feet × radians.

Arc Length = Radius × Central Angle

In this case, the radius is 7 feet and the central angle is 5 radians. Plugging these values into the formula, we get:

Arc Length = 7 feet × 5 radians

Arc Length = 35 feet × radians

Therefore, the length of the arc that subtends a central angle of 5 radians in a circle with a radius of 7 feet is 35 feet × radians.

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the radius of the larger circle is $\sqrt{3} - 1$.

The radius of the larger circle can be determined by considering the centers of the smaller circles and the points of tangency. Let's denote the radius of the larger circle as R.

Since the three smaller circles are externally tangent to each other, the centers of the smaller circles form an equilateral triangle with side length equal to the sum of their radii, which is $2 + 2 + 2 = 6$. The larger circle is tangent to the sides of this equilateral triangle.

To find the radius of the larger circle, we can draw an altitude from the center of the larger circle to one of the sides of the equilateral triangle. This altitude splits the equilateral triangle into two congruent 30-60-90 triangles. The altitude is equal to the radius of the larger circle plus the radius of one of the smaller circles, which is $R + 1$.

In a 30-60-90 triangle, the length of the hypotenuse (R + 1) is twice the length of the shorter leg (1). Therefore, we have:

$2 = (R + 1) \cdot \frac{1}{\sqrt{3}}$

Solving for R, we get:

$R = \sqrt{3} - 1$

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The answers to the questions involving trigonometry are: 90, BC/AB ÷ BC/AB = 1, g = 6.5, <I = 62 degrees, h= 13.8, 12.0, x = 6.8, x = 66.4, 160.6, The pole = 6.7

Trigonometric ratios are special measurements of a right triangle, defined as the ratios of the sides of a right-angled triangle.  There are three common trigonometric ratios: sine, cosine, and tangent

For page 3 question 3,

a) <A + <B = 90 since <C = right angle

b) SinA = BC/AB and CosB = BC/AB

The ratio of the two angles BC/AB ÷ BC/AB = 1

I notice that the ratio of sinA and cosB gives 1

b) The ratio of CosA and SinB will give

BC/AB ÷ BC/AB

= BC/AB * AB/BC = 1

For page 5 number 3

Tan28 = g/i

g/12.2 = tan28

cross multiplying to have

g = 12.2*tan28

g = 12.2 * 0.5317

g = 6.5

b) the angle I is given as 90-28 degrees

<I = 62 degrees

To find the side h we use the Pythagoras theorem

h² = (12.2)² + (6.5)²

h² = 148.84 +42.25

h²= 191.09

h=√191.09

h= 13.8

For page 6

1) Sin42 = x/18

x=18*sin42

x = 18*0.6691

x = 12.0

2) cos28 = 6/x

xcos28 = 6

x = 6/cos28

x [= 6/0.8829

x = 6.8

3)  Tan63 = x/34

x = 34*tan63

x= 34*1.9526

x = 66.4

4) Sin50 123/x

xsin50 = 123

x = 123/sin50

x = 123/0.7660

x =160.6

5)  Sin57 = P/8

Pole = 8sin57

the pole = 8*0.8387

The pole = 6.7

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Answer:

yes

Step-by-step explanation:

A falling stone is at a certain instant 178 feet above the ground and 3 seconds later it is only 10 feet above the ground. The stone was dropped from a height of approximately 14.75 feet.

To find the height from which the stone was dropped, we can use the equations of motion.

Determine the time taken to fall from 178 feet to 10 feet.

The time taken can be calculated using the equation h = (1/2)\(gt^2\),

where h is the height, g is the acceleration due to gravity (approximately 32 ft/\(s^2\)), and t is the time.

Rearranging the equation,

we have t = \(\sqrt{((2h)/g)\). Substituting the values,

we get t = \(\sqrt{((2 * 168) / 32)\) ≈ 2.06 seconds.

Calculate the initial height.

Since the stone fell for 3 seconds after being at a height of 178 feet,

we subtract the time taken in step 1 from the given time.

Thus, the stone took 3 - 2.06 ≈ 0.94 seconds to fall from the initial height to 178 feet.

Using the equation h = (1/2)\(gt^2\) and substituting the values,

we get h = (1/2) ×32×\((0.94)^2\)≈ 14.75 feet.

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Considering the equation of an ellipse, it is found that the height of the tunnel 10 feet from the edge is of 14 feet.

The following is the equation for a horizontal ellipse of center with coordinates (h,k):

(x - h)²/a² + (y - k)²/b² = 1.

In relation to this issue, we have that:

The origin is where the center is.

Since the major axis is 70, 2a = 70 and a = 35.

The maximum height is 20, therefore b is equal to 20.

As a result, the ellipse's equation is as follows:

x²/35² + y²/20² = 1.

It is determined that x = 25 when the tunnel is 10 feet from the edge since 35 – 10 = 25; therefore, the height y is calculated as follows:

25²/35² + y²/20² = 1

0.51 + y²/20² = 1

y²/20² = 0.49

y² = 20² x 0.49

y =√(20² x 0.49)

y = 14 feet.

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we can predict that for each liter increase in displacement, the horsepower will increase by 126.593, on average

(a) To estimate how much more horsepower should one expect the larger engine to produce, we can calculate a 95% confidence interval for the mean difference in horsepower between the 2.9 and 3.7 liter engines. We can use the following formula:

mean difference ± t(α/2, n-2) x SE

where mean difference is the difference in mean horsepower between the two engine sizes, t(α/2, n-2) is the t-value for a two-sided interval with α = 0.05 and n-2 degrees of freedom, and SE is the standard error of the difference in means.

Using R or a similar software, we can calculate the mean and standard deviation of horsepower for each engine size, and then use these values to calculate the mean difference and SE:

mean_hp_2.9 <- mean(df$Horsepower[df$Displacement == 2.9])

mean_hp_3.7 <- mean(df$Horsepower[df$Displacement == 3.7])

sd_hp_2.9 <- sd(df$Horsepower[df$Displacement == 2.9])

sd_hp_3.7 <- sd(df$Horsepower[df$Displacement == 3.7])

n_2.9 <- length(df$Horsepower[df$Displacement == 2.9])

n_3.7 <- length(df$Horsepower[df$Displacement == 3.7])

mean_diff <- mean_hp_3.7 - mean_hp_2.9

SE <- sqrt((sd_hp_2.9^2 / n_2.9) + (sd_hp_3.7^2 / n_3.7))

t_val <- qt(0.025, df = n_2.9 + n_3.7 - 2)

ci_lower <- mean_diff - t_val * SE

ci_upper <- mean_diff + t_val * SE

The resulting confidence interval is (22.67, 91.33), which means we can be 95% confident that the true mean difference in horsepower between the two engine sizes falls between 22.67 and 91.33.

Therefore, we can expect the larger 3.7 liter engine to produce between 22.67 and 91.33 more horsepower than the 2.9 liter engine, on average.

(b) We do not have any qualms about presenting this interval as an appropriate 95% range. The p-value for the two-sided hypothesis B, = 0 is not relevant in this context, and the value of 2 is not too low. There are outliers in the data, but they do not necessarily need to be removed in order to calculate a confidence interval.

(c) To estimate the expected horsepower of a car with a 3.7 liter engine, we can use the linear regression model:

Horsepower = β0 + β1 x Displacement + ε

where β0 and β1 are the intercept and slope coefficients, respectively, and ε is the error term assumed to be normally distributed with mean 0 and constant variance.

We can use R or a similar software to fit this model to the data:

fit <- lm(Horsepower ~ Displacement, data = df)

summary(fit)

From the summary output, we can see that the estimated slope coefficient is 126.593 and the estimated intercept coefficient is -16.461. This means that we can predict that for each liter increase in displacement, the horsepower will increase by 126.593, on average.

To estimate the expected horsepower of a car with a 3.7 liter engine, we can plug in 3.7 for Displacement in the regression equation and calculate the corresponding

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Answer:

I GOTCHU THE ANSWER IS -10

Step-by-step explanation:

Answer:

2 x 3(the 3 is above the 2x) + 7 x 2(the 2 is above the 7x) − 18 x

Step-by-step explanation:

can I have brainliest please? :)

Answer:

Lead coeficcent: -3 term 7

Step-by-step explanation:

7 is the only constant and -3 is the grates coeficcent.

The student work shows the evaluation process solution is lim x→a (a - x) = -1 ×lim x→a (x - a) = -1 × 0 = 0

The student's work contains several mistakes

Mistake 1: The student incorrectly wrote "lim x a-x 0." The correct notation should be "lim x→a (a - x) = 0" to indicate that are taking the limit of (a - x) as x approaches a, and the limit evaluates to 0.

Mistake 2: In the next line, the student wrote "lim a - a ata" instead of evaluating the limit correctly. It seems like there was a typographical error. The correct expression should be "lim x→a (a - a) = 0" since (a - a) is always equal to 0.

Mistake 3: The student wrote "0 a+x" without indicating any operation or limit. It is unclear what the student meant in this step.

Mistake 4: The student wrote "2a x → a where a <- 1." This notation is incorrect and unclear. It seems like the student was attempting to indicate the limit as x approaches a, where a is less than -1. However, the notation used is not standard and can be confusing.

To correct the solution,

Given: lim x→a (a - x)

simplify this expression by rearranging the terms:

lim x→a (-1) × (x - a)

Since (-1) × (x - a) is equivalent to (a - x), the expression becomes:

lim x→a (a - x) = lim x→a (-1) ×(x - a)

Now, we can evaluate the limit:

lim x→a (-1) ×(x - a) = -1 × lim x→a (x - a)

Taking the limit of (x - a) as x approaches a,

lim x→a (x - a) = 0

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Option A is correct. If segment DC bisects segment AB, then point D is equidistant from points A and B because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects. This can be obtained using perpendicular bisector theorem.

Perpendicular bisector theorem : In a plane, if we choose a point, say D, on the perpendicular bisector,say PQ, drawn from segment, say AB, then the point D is equidistant from the endpoints, that is A and B, of the segment.

That is, perpendicular bisector PQ of line segment AB is the line with         Q = 90° and Q is the midpoint of AB ⇒ AQ = BQ. A point on PQ say D is equidistant from A and B ⇒AD and BD.

Thus in the given question we can use perpendicular bisector theorem.

Here DC is the perpendicular bisector of the line segment AB and therefore AD and BD are equal.

Hence it is clear that Option A is correct.

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Answer:

yes it's a right angle triangle

Step-by-step explanation:

by using Pythagoras theorem

H2= b2 + p2

5^2= 3^2+ 4^2

25= 25

hope it helps

Answer:

\(2p^2\)

Step-by-step explanation:

Step 1: Apply the exponentiation property:

\((8p^6)^\frac{1}{3} = 8^\frac{1}{3} * (p^6)^\frac{1}{3}\)

Step 2: Simplify the cube root of 8:

The cube root of 8 is 2:

\(8^\frac{1}{3} =2\)

Step 3: Simplify the cube root of \((p^6)\):

The cube root of \((p^6)\) is \(p^\frac{6}{3} =p^2\)

Step 4: Combine the simplified terms:

\(2 * p^2\)

So, the simplified expression is \(2p^2\).

The two charges q1=-5c and q2=-8c are placed 20 cm apart from each other. Given two charges, q1 = -5C and q2 = -8C, placed 20 cm apart, you might be interested in finding the electrostatic force between them.

Given two charges, q1 = -5C and q2 = -8C, placed 20 cm apart, you might be interested in finding the electrostatic force between them. To do this, we can use Coulomb's Law:
F = (k * |q1 * q2|) / r^2
Where:
- F is the electrostatic force
- k is the electrostatic constant (8.9875517923 × 10^9 N m²/C²)
- q1 and q2 are the charges (-5C and -8C)
- r is the distance between the charges (20 cm or 0.2 m)
Now, plug the values into the formula and calculate the force:
F = (8.9875517923 × 10^9 N m²/C² * |-5C * -8C|) / (0.2 m)^2
F = (8.9875517923 × 10^9 N m²/C² * 40 C²) / 0.04 m²
F = 8,987,551,792.3 N (approx.)
The electrostatic force between the two charges, 20 cm apart, is approximately 8,987,551,792.3 Newtons.

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Answer: 1155ft

Step-by-step explanation:

assuming that 70 m/s is the terminal velocity

1 meter=3.3 ft

70 meters= 231

231×5= 1155ft

Answer:

The values of a,b and c are 1, -3 and -2 respectively.

Step-by-step explanation:

The general form of quadratic equation is given by :

\(ax^2+bx+c=0\) .....(1)

Here, a,b and c are constants

The given equation is :

\(x^2-3x-2=0\)

We can also write the above equation as :

\(x^2+(-3x)+(-2)=0\) ....(2)

If we compare equation (1) and (2), we get :

a = 1

b = -3 and

c = -2

So, the values of a,b and c are 1, -3 and -2 respectively.

Answer:

i think its option B

Step-by-step explanation:

i dont know if its right or not sorry but hope this helps :)

Answer:

a. 1.37

b. 1.37

c. 1.37

all of them are 1.37 or they are all 137

Step-by-step explanation:

The total surface area of the pyramid is 240.6 square inches.

It will be equal to the sum of the areas of the base and the 4 triangular faces.

First the base, it is a rectangle of 11 in by 7 in, then the area is:

A = 11in*7in = 77 in²

Then the triangles, remember that the area of a triangle is the product between the base and the height divided by 2, then the area of the front triangle is:

a = 11in*8.7in/2 = 47.85in²

The one that faces to the right:

a' = 9.7in*7in/2 = 33.95in²

And we have two of each of these faces, then the total surface area is:

area = 77 in² + 2*47.85in² + 2*33.95in²

area = 240.6 in²

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Hello!

Let's separate this problem into three steps:

 --> finding area of triangle 1 (x2)

        height: 8.7in    and     base: 11in

 --> finding area of triangle 2 (x2)

       height: 9.7in   and     base: 7in

 --> finding area of rectangle base

      length: 11in    and     base: 7in

Let's do just that:

 --> area of triangle 1

      \(\dfrac{1}{2} *8.7*11*2=95.7\)

 --> area of triangle 2

        \(\dfrac{1}{2} *9.7*7*2=67.9\)

 --> area of rectangle base:

        \(11*7=77\)

Let's add these areas together to get  ==> surface area

     \(\text{Surface Area}=95.7+67.9+77=240.6\text{ in}^2\)

Answer: 240.6 or Choice 4

Step-by-step explanation:

\((6x^2-5x+7)(3x+4)\)

\(=(6x^2-5x+7)(3x)+(6x^2-5x+7)(4)\)

\(=(6x^2)(3x)+(-5x)(3x)+(7)(3x)+(6x^2)(4)+(-5x)(4)+(7)(4)\)

\(=18x^3-15x^2+21x+24x^2-20x+28\)

\(=18x^3+9x^2+x+28\)

In this problem, we are given a variable resistor R and an 8-Ω resistor in parallel. We are asked to find the rate at which the resistance R is changing when it is equal to 6.0 Ω.

Given that RT = 8R / (8 + R), we can differentiate this equation with respect to time t using the quotient rule. Let's denote dR/dt as the rate of change of R with respect to time. Applying the quotient rule, we have:

dRT/dt = \([ (8)(dR/dt)(8 + R) - (8R)(dR/dt) ] / (8 + R)^2\)

To find the rate at which R is changing when R = 6.0 Ω, we substitute R = 6.0 into the above equation:

dRT/dt = \([ (8)(dR/dt)(8 + 6.0) - (8)(6.0)(dR/dt) ] / (8 + 6.0)^2\)

Simplifying further, we have:

dRT/dt = \([ (8)(dR/dt)(14) - (48)(dR/dt) ] / (14)^2\)

dRT/dt = (112(dR/dt) - 48(dR/dt)) / 196

dRT/dt = 64(dR/dt) / 196

dRT/dt = 16(dR/dt) / 49

Therefore, the rate at which R is changing when R = 6.0 Ω is equal to 16/49 times the rate of change of RT.

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Answer:

See below

Step-by-step explanation:

\(2 {x}^{2} - 11x + 14 = 0 \\ dividing \: throughout \: by \: 2 \\ \\ \frac{ 2{x}^{2} }{2} - \frac{11}{2} x + \frac{14}{2} = \frac{0}{2} \\ \\ {x}^{2} - \frac{11}{2} x + 7 = 0 \\ \\ {x}^{2} - \frac{11}{2} x = - 7 \\ \\ {x}^{2} - 2 \times \frac{11}{4} x = - 7 \\ \\ {x}^{2} - 2 \times \frac{11}{4} x + \bigg(\frac{11}{4} \bigg)^{2} = \bigg(\frac{11}{4} \bigg)^{2} - 7 \\ \\ { \bigg(x - \frac{11}{4} \bigg )}^{2} = \frac{121}{16} - 7 \\ \\ { \bigg(x - \frac{11}{4} \bigg )}^{2} = \frac{121}{16} - 7 \\ \\ { \bigg(x - \frac{11}{4} \bigg )}^{2} = \frac{121 - 112}{16} \\ \\ {{ \bigg(x - \frac{11}{4} \bigg )}^{2} = \frac{9}{16} } \\ \\ \purple{{ \bigg(x + ( - \frac{11}{4}) \bigg )}^{2} = \frac{9}{16} }\)