Can somebody help me with the top problem pls
Can somebody please help me ?
SSA
Step-by-step explanation:
put name of triangle abc are same
contractor steve agreed to complete a job in 30 days. after 6 days he found that the 8 people assigned to the work had already done $\frac{1}{3}$ of the job. if everyone works at the same rate, what is the least number of people he must keep on the job to ensure that the job will be completed on time?
Steve must keep at least 5 people on the job to ensure that the job will be completed on time, assuming that everyone works at the same rate.
This is because after 6 days, 8 people have already completed \($\frac{1}{3}$\)of the job, and the remaining job can be completed by 5 people working at the same rate in 24 days.
Let's assume that the entire job requires 100 units of work to be completed. After 6 days, 8 people have already completed \($\frac{1}{3}$\) of the job, which means they have completed \($\frac{1}{3}\cdot\)100= 33.33$ units of work in 6 days. Their combined rate of work is \($\frac{33.33}{6\cdot 8}\)=0.6944$ units per day per person.
Now, the remaining job that needs to be completed is 100-33.33=66.67 units of work. If we assume that x people need to be kept on the job to ensure that the job will be completed on time, then the equation becomes:\($\frac{66.67}{(30-6)\cdot x}\)=0.6944$
Simplifying this equation, we get: \($x\geq \frac{66.67}{24\cdot 0.6944}\)=4.29$ Since we can't have a fraction number of people, we must round up to the next integer. So, Steve must keep at least 5 people on the job to ensure that the job will be completed on time.
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Connie received $20 for her birthday from her grandparents. She used the money to buy an ice cream cone for herself and one for each of her four best friends. If each cone cost $3.15, how much money does Connie have left?
Answer:
4.25
Step-by-step explanation:
she has a total of 20 dollars and she wats to buy ice cream each at 3.15 for a total of 5 people including her self.
so 3.15(5) is 15.75
then subtract 15.75 from 20
20 - 15.75 = 4.25
Wen is factoring the polynomial, which has four terms. 6x3 – 12x2 7x – 14 6x2 (x – 2) 7(x – 2) Which is the completely factored form of his polynomial? (6x2 7) (x –2) (6x2 – 2) (x 7) (6x2 2) (x – 7) (6x2 – 7) (x 2).
The completely factored form of the Wen's polynomial, which has the four terms initial, is,
\((6x^2+7)(x-2)\)
What is the factor of polynomial?The factor of a polynomial is the terms in linear form, which are when multiplied together, give the original polynomial equation as result.
Wen is factoring the polynomial, which has four terms.
\(6x^3 - 12x^2+ 7x - 14\) '
Take out the greatest common factor from the equation and make separate groups as,
\(6x^2(x - 2)+ 7(x - 2)\\(x-2)(6x^2+7)\)
Rearrange the above equation as,
\((6x^2+7)(x-2)\)
Thus, the completely factored form of the Wen's polynomial, which has the four terms initial, is,
\((6x^2+7)(x-2)\)
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Answer:
A
Step-by-step explanation:
Trust me
show that cos 30 + 2 tan 60 can be written in the form k where k is an integer
Answer:
k = 4.33
Step-by-step explanation:
Cos 30 = 0.8660
Tan 60 = 1.732
2 Tan 60 = 2 (Tan 60)
2 Tan 60 = 2 (1.732)
2 Tan 60 = 3.464
Cos 30 + Tan 60 = 0.8660 + 3.464 = 4.33
k = 4.33
what are the major methods of recording unstructured observational data
The major methods of recording unstructured observational data are Narrative Description, Field Notes, Audio or Video Recording, Photography, Diagrams or Maps.
The major methods of recording unstructured observational data are:
1. Narrative Description: This method involves writing a detailed, chronological account of the observed events or behaviors, capturing the context and interactions as they occur naturally.
2. Field Notes: In this method, the observer takes brief, concise notes during the observation, focusing on key events, behaviors, or interactions. These notes can be expanded and organized later for further analysis.
3. Audio or Video Recording: Using audio or video equipment, the observer captures the events and interactions in their entirety. This allows for a more accurate record and the ability to review and analyze the data multiple times.
4. Photography: Taking photographs during the observation can provide a visual record of the events and behaviors. These images can supplement other data collection methods and help to illustrate specific aspects of the observation.
5. Diagrams or Maps: Drawing diagrams or maps of the observation setting can help capture the spatial relationships between individuals and objects, as well as the overall layout of the environment.
These methods can be used individually or in combination, depending on the research question and the specific needs of the study. Remember to always respect participants' privacy and obtain informed consent when necessary.
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What is the measure of angle QMN
Answer:
a straight line which is 180°
Use the Secant method to find solutions accurate to within 10^-4 for the following problems.  a. - 2x2 - 5 = 0,[1,4] x - cosx = 0, [0, 1/2] b. x2 + 3x2 - 1 = 0, 1-3.-2] d. *-0.8 -0.2 sin x = 0, (0./2] C. =
Use the Secant method to find solutions accurate to within 10⁻⁴ for the given problems.
What is the Secant method and how does it help in finding solutions ?The Secant method is an iterative root-finding algorithm that approximates the roots of a given equation. It is a modified version of the Bisection method that is used to find the root of a nonlinear equation. In this method, two initial guesses are required to start the iteration process.
The algorithm then uses these two points to construct a secant line, which intersects the x-axis at a point closer to the root. The new point is then used as one of the initial guesses in the next iteration. This process is repeated until the desired level of accuracy is achieved.
To use the Secant method to find solutions accurate to within
10 ⁻⁴ for the given problems, we first need to set up the algorithm by selecting two initial guesses that bracket the root. Then we apply the algorithm until the root is found within the desired level of accuracy. The Secant method is an efficient and powerful method for solving nonlinear equations, and it has a wide range of applications in various fields of engineering, physics, and finance.
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the value of the euro was $1.30 last week. during last week the euro depreciated by 5 percent. what is the value of the euro today?
If the value of the euro was $1.30 last week and during last week the euro depreciated by 5 percent, the value of the euro today is $1.235.
If the euro was worth $1.30 last week and depreciated by 5%, we can calculate the new value by multiplying the original value by (1 - depreciation rate).
Mathematically, the new value of the euro can be calculated as follows:
New Value = Original Value * (1 - Depreciation Rate)
New Value = $1.30 * (1 - 0.05)
New Value = $1.30 * 0.95
New Value = $1.235
Therefore, the value of the euro today is $1.235.
Depreciation is a term used to describe the decline in the value of a currency relative to another currency or to a basket of currencies. It can occur due to various reasons, such as changes in interest rates, inflation rates, political instability, or economic growth.
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what is 1/10 as a decimal does it equal 0.1
chris is comparing two music downloading websites. the first site charges a $15 membership fee and then charges $0.50 per song. the second website has no membership fee, but they charge $0.80 per song. how many songs will chris have to download before the two sites charge the same amount
Answer:
hE WILL HAVE TO DOWN LOAD 50 SONGS
Step-by-step explanation:
55% of professionals in a large city participate in professional networking. one company surveyed their 980 employees, 500 reported they engage in professional networking. at the 0.05 level of significance, is there evidence that the proportion of members who engaged in a professional networking within the last month is different from the established percentage?
The null hypothesis rejected represents there is evidence the proportion of members engaged in professional networking within last month is different from established percentage.
Using a hypothesis test we have,
Let p be the proportion of employees in the company who engage in professional networking within the last month.
The null hypothesis represents,
The proportion of employees who engage in professional networking within the last month is equal to the established percentage of 55%.
H0: p = 0.55
The alternative hypothesis represents ,
The proportion of employees who engage in professional networking within the last month is different from 55%.
Ha: p ≠ 0.55
Use a two-tailed z-test for the proportion to test this hypothesis, with a significance level of 0.05.
The test statistic is,
z = (p₁ - p) / √(p(1-p)/n)
p₁ is the sample proportion
p is the hypothesized proportion
And n is the sample size.
Here,
p = 0.55
n = 980
p₁ = 500/980
= 0.51.
Substituting these values, we get,
z = (0.51 - 0.55) / √(0.55(1-0.55)/980)
= -1.96
The critical values for a two-tailed test with a significance level of 0.05 are ±1.96.
Since the test statistic (-1.96) falls within the critical region.
Reject the null hypothesis
Therefore, there is evidence that the proportion of employees who engage in professional networking within the last month is different from the established percentage of 55%.
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a student earned a grade of 80% on a math test that had 20 problems how many problems on this test did the student answer correctly
Answer:
16
Step-by-step explanation:
To find 80% of 20, multiply .80 x 20
.80×20 = 16
This is how you multiply percentages--put the decimal point 2 places to the left, then multiply. In this case, you're looking at 80%, so move the decimal point two places to the left
80.0 becomes .80
Then multiply that by the number you're trying to find the percentage of
Simplify the expression given below.
X+2/x^3+2x^2-9x-18 divided by 3x+1 / x^2-9
A. 1 / (x+3)(x-3)
B. 3x +1
C. 1 / 3x+1
D. 3x + 1 / (x+3) (x-3)
Answer:
D
Step-by-step explanation: your welcome have a good day
Answer:
C. \( \dfrac{1}{3x + 1} \)
Step-by-step explanation:
\( \dfrac{x + 2}{x^3 + 2x^2 - 9x - 18} \div \dfrac{3x + 1}{x^2 - 9} = \)
Factor all polynomials.
\( = \dfrac{x + 2}{x^2(x + 2) -9(x + 2)} \div \dfrac{3x + 1}{(x + 3)(x - 3)} \)
\( = \dfrac{x + 2}{(x^2 - 9)(x + 2)} \div \dfrac{3x + 1}{(x + 3)(x - 3)} \)
\( = \dfrac{x + 2}{(x + 3)(x - 3)(x + 2)} \div \dfrac{3x + 1}{(x + 3)(x - 3)} \)
To divide by a fraction, multiply by its reciprocal.
\( = \dfrac{x + 2}{(x + 3)(x - 3)(x + 2)} \times \dfrac{(x + 3)(x - 3)}{3x + 1} \)
Cancel out common factors in the numerator and denominator.
\( = \dfrac{1}{3x + 1} \)
having a small brain moment, can you please help and show work
Answer:
The value if x is 0.9875.
Step-by-step explanation:
First, we have to get rid of brackets by expanding :
\(0.5(2x + \frac{3}{4} ) - \frac{1}{3} (0.1 + x) = 1\)
\(0.5(2x) + 0.5( \frac{3}{4} ) - \frac{1}{3} (0.1) - \frac{1}{3} (x) = 1\)
\(x + \frac{3}{8} - \frac{1}{30} - \frac{1}{3} x = 1\)
Next you have to collect like terms :
\(x - \frac{1}{3} x + \frac{3}{8} - \frac{1}{30} = 1\)
\( \frac{2}{3} x + \frac{41}{120} = 1\)
Lastly, you can solve x :
\( \frac{2}{3} x = 1 - \frac{41}{120} \)
\( \frac{2}{3} x = \frac{79}{120} \)
\(x = \frac{79}{120} \div \frac{2}{3} \)
\(x = \frac{79}{80} \)
\( x = 0.9875\)
Triangulation is a method of finding the location of an object based on measurements made from two other locations.
Triangulation is the method of finding the location of an object based on the measurements made from the two other locations. The above statement is true statement.
Triangulation is the division of a face or plane polygon into a series of triangles, usually with the limitation that each side of a triangle is fully shared by two adjacent triangles. In geometry, triangulation is the division of planar objects into triangles, or more broadly, the division of high-dimensional geometric objects into simplifications. Triangulation of a 3D volume involves subdivision into packed tetrahedra that directly measure distances to points. It is a method for finding the location of the object.
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A student was asked to simplify the expression 2(x+3)+(4x−8)−7x .
Answer:
-x -2
Step-by-step explanation:
1- Apply the Distributive Property
2- Calculate the product or quotient
3- Determine the sign
4- Reorder and gather like terms
Collect coefficients of like terms
Calculate the sum or difference
Please help me with these questions!! this is due at 11:59 pm EST. If you could explain how you got your answers too, that would be so helpful!! (please show your work)use the right triangle ️RST and the given information to solve each problem. 7. Find TM if RM = 4 and MS = 9 8. Find RT if RS = 20 and RM = 8 9. Find TS if RM = 5 and MS = 7 10. Find RT if RM = 1/2 and MS = 1/4 thank you so much if you can help me!!
We can make a drawing to see better:
7) We know that RM = 4 and MS = 9, so:
\(\begin{gathered} \tan a=\frac{MS}{RM}=\frac{TM}{MS} \\ TM=\frac{MS^2}{RM}=\frac{9^2}{4}=\frac{81}{4}=20.25 \end{gathered}\)The answer is TM = 20.25
8) We know that RS = 20 and RM = 8, so:
\(\begin{gathered} \sin b=\frac{RM}{RS}=\frac{RS}{RT} \\ RT=\frac{RS^2}{RM}=\frac{20^2}{8}=\frac{400}{8}=50 \end{gathered}\)The answer is RT = 50.
9) We know that RM = 5 and MS = 7, so:
\(\begin{gathered} \tan b=\frac{RM}{MS}=\frac{RS}{TS} \\ TS=RS\cdot\frac{MS}{RM} \\ RS=\sqrt[]{RM^2+MS^2} \\ TS=\sqrt[]{RM^2+MS^2}\cdot\frac{MS}{RM} \\ TS=\sqrt[]{5^2+7^2}\cdot\frac{7}{5}=\sqrt[]{25+49}\cdot\frac{7}{5} \\ TS=\sqrt[]{74}\cdot\frac{7}{5}\approx12.043 \end{gathered}\)The answer is TS = 12.043
10) We know that RM = 1/2 and MS = 1/4, so:
\(\begin{gathered} \sin b=\frac{RM}{RS}=\frac{RS}{RT} \\ RT=\frac{RS^2}{RM}=\frac{RM^2+MS^2}{RM} \\ RT=\frac{(\frac{1}{2})^2+(\frac{1}{4})^2}{\frac{1}{2}}=2\cdot(\frac{1}{4}+\frac{1}{16}) \\ RT=2\cdot\frac{4+1}{16}=\frac{5}{8}=0.625 \end{gathered}\)The answer is RT = 5/8 = 0.625
4/3 and 8/6 which is bigger.
"(help meeeee)"
50 POINTS FOR THE CORRECT ANSWER!
So
f(2)
f(1)-317-314f(3)
f(2)-314-311f(4)
f(3)-311-38Sam purchased a laptop at $800 each year the laptop will lose 12% of its value each year what would it be the approximate value of Sam's laptop after 7 years
Answer:
$326.94
Step-by-step explanation:
For this equation you are going to do a exponential function, since we are working with percents. To do this you will make the equation
(starting price)x(1-percent)^(t) t=years
which will create the equation
800(0.88)^t
You will then plug in t=7
800(0.88)^7 =
800(0.409) =
326.94 (you will cut it off at the hundredth position because it is working with money)
When Fredrick buys a cup of coffee he is given change of €1.65 when he should have received €1.50. Find percentage error
When Frederick purchases a cup of coffee, he gets handed €1.65 in change rather than the expected €1.50. The error percentage is 9.09%
Explain about the percentage error?The variation between the real value and the predicted value, in relation to the theoretical value, is known as percentage error.
When compared to the real number and expressed in percent format, percentage error seems to be the gap between the anticipated amount and the actual number. The equation is as follows:
To put it another way, you divide the deviation between the true answer and the answer you guessed by the true answer to get the percent.
Amount paid by Fredrick for cup of coffee: €1.65
Actual amount: €1.50.
percentage error = (amount paid - actual amount)/amount paid * 100 %
percentage error = (1.65 - 1.50)/1.65 * 100
percentage error = 9.09%
Thus, When Frederick purchases a cup of coffee, he gets handed €1.65 in change rather than the expected €1.50. The error percentage is 9.09%
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im stuck on this question helm me out I will mark you as brainliest
Answer: it is =4176000000000000
Step-by-step explanation:
(2.9)(100000)(7.2)(10^2)
5(10^−8)
=
(290000)(7.2)(10^2)
5(10^−8)
=
2088000(10^2)
5(10^−8)
=
(2088000)(100)
5(10^−8)
=
208800000
5(10^−8)
=
208800000
5(1/100000000)=
208800000/1
20000000
=4176000000000000
hope i helped
-lvr
Rewrite the expression in nonradical form without using absolute values for the indicated values of theta.
1 − cos2 (theta)
; 2.5 < theta < 3
To rewrite the expression 1 - cos^2(theta) without using absolute values for the given values of theta (2.5 < theta < 3), we can utilize the trigonometric identity for cosine squared:
cos^2(theta) = 1 - sin^2(theta)
Now, let's substitute this identity into the expression:
1 - cos^2(theta) = 1 - (1 - sin^2(theta))
= 1 - 1 + sin^2(theta)
= sin^2(theta)
Therefore, for the given range of theta (2.5 < theta < 3), the expression 1 - cos^2(theta) is equivalent to sin^2(theta).
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What are the roots of the polynomial equation? Round noninteger roots to the nearest hundredth. –26, –9.81, 1.94 –26 –2 –2, 0.11, 4.39
The polynomial equation with roots -26, -2, and 4.39 is:
x³ + 15.22x² - 239.44x + 1049.44 = 0
The given root of 0.11 is not a root of this equation.
What are polynomial equation?Any equation with a sum of terms that includes constant coefficients multiplied by one or more variables raised to a non-negative integer power constitutes a polynomial equation.
If the roots of a polynomial equation are -26, -2, and 4.39, then the factored form of the polynomial equation can be written as:
(x + 26)(x + 2)(x - 4.39) = 0
Expanding this equation gives us:
(x + 26)(x² - 2x - 8.78x + 8.78×2) = 0
Simplifying further, we get:
(x + 26)(x² - 10.78x + 38.44) = 0
Multiplying out the second factor, we get:
x³ - 10.78x² + 38.44x + 26x² - 277.88x + 1049.44 = 0
Combining like terms, we get:
x³ + 15.22x² - 239.44x + 1049.44 = 0
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Which of the following are the two most commonly used measures of variability? O a. Variance and mode b. Mean and range O c Variance and standard deviation O d. Sample mean, and sample variance
The two most commonly used measures of variability are variance and standard deviation.
1. Variance: Variance measures how spread out a set of data points is from the mean. It calculates the average of the squared differences between each data point and the mean. The formula for variance is sum of squared differences divided by the number of data points.
Example: Let's say we have a set of data points: 2, 4, 6, 8, and 10. The mean of these data points is 6. The differences between each data point and the mean are: -4, -2, 0, 2, and 4. Squaring these differences gives us: 16, 4, 0, 4, and 16. The sum of these squared differences is 40. Dividing this sum by the number of data points (5) gives us a variance of 8.
2. Standard Deviation: Standard deviation is the square root of variance. It measures the average distance between each data point and the mean. Standard deviation is often preferred over variance because it is in the same unit as the data points, making it easier to interpret.
Example: Using the same set of data points as above, the variance is 8. Taking the square root of 8 gives us a standard deviation of approximately 2.83.
In summary, variance measures how spread out the data points are from the mean, while standard deviation gives us a more intuitive understanding of the variability by providing a measure in the same unit as the data points. These measures help us understand how the data is distributed and how much it deviates from the average.
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LOTS OF POUNT PLS HELP
Answer:
Option 2
Step-by-step explanation:
Using the quadrstic formula,
\(\tan \theta=\frac{-2 \pm \sqrt{2^2 - 4(\sqrt{3})(-\sqrt{3})}}{2\sqrt{3}} \\ \\ =\frac{-2 \pm 4}{2\sqrt{3}} \\ \\ =\frac{-1 \pm 2}{\sqrt{3}} \\ \\ = -\sqrt{3}, \frac{1}{\sqrt{3}}\)
Case 1
\(\tan \theta=-\sqrt{3} \implies \theta=\frac{2\pi}{3}, \frac{5\pi}{3}\)
Case 2
\(\tan \theta=\frac{1}{\sqrt{3}} \implies \theta=\frac{\pi}{6}, \frac{7\pi}{6}\)
The number of years it will take for $510 to grow to $1,010.18 at 5 percent compounded annually is ____
Answer:
13.66 years
Step-by-step explanation:
Given data
P=$510
A=$1,010.18
R=5%
t= ln(A/P)/r
susbstitute
t= ln(1,010.18/510)/0.05
t=ln1.980/0.05
t= 0.683/0.05
t= 13.66
Hence the time is 13.66 years
c find the thirteen adjacent digits in the 1000-digit number that have the greatest product. what is the value of this product?
The thirteen adjacent digits in the 1000-digit number that have the greatest product are 9, 9, 8, 9, 0, 0, 8, 8, 5, 2, 4, 3, and 5, and the value of this product is 23,514,624,000.
We can begin by storing the 1000-digit number as a string and then iterating over it to find the thirteen adjacent digits with the greatest product:
```c
#include <stdio.h>
int main() {
char num[] = "73167176531330624919225119674426574742355349194934"
"96983520312774506326239578318016984801869478851843"
"85861560789112949495459501737958331952853208805511"
"12540698747158523863050715693290963295227443043557"
"66896648950445244523161731856403098711121722383113"
"62229893423380308135336276614282806444486645238749"
"30358907296290491560440772390713810515859307960866"
"70172427121883998797908792274921901699720888093776"
"65727333001053367881220235421809751254540594752243"
"52584907711670556013604839586446706324415722155397"
"53697817977846174064955149290862569321978468622482"
"83972241375657056057490261407972968652414535100474"
"82166370484403199890008895243450658541227588666881"
"16427171479924442928230863465674813919123162824586"
"17866458359124566529476545682848912883142607690042"
"24219022671055626321111109370544217506941658960408"
"07198403850962455444362981230987879927244284909188"
"84580156166097919133875499200524063689912560717606"
"05886116467109405077541002256983155200055935729725"
"71636269561882670428252483600823257530420752963450";
int length = sizeof(num) - 1; // subtract 1 to exclude null terminator
long long max_product = 0;
for (int i = 0; i < length - 12; i++) {
long long product = 1;
for (int j = 0; j < 13; j++) {
product *= num[i + j] - '0'; // convert digit character to integer
}
if (product > max_product) {
max_product = product;
}
}
printf("%lld", max_product);
return 0;
}
```
In the outer loop, we iterate from index 0 to index 986 to ensure we have at least 13 digits remaining. In the inner loop, we calculate the product of the next 13 digits using the current index as the starting point. We convert each digit character to its integer value by subtracting the character code for '0'. If the product is greater than the previous maximum product, we update the maximum product. Finally, we print the maximum product.
The output is:
```
23514624000
```
Therefore, the thirteen adjacent digits in the 1000-digit number that have the greatest product are 9, 9, 8, 9, 0, 0, 8, 8, 5, 2, 4, 3, and 5, and the value of this product is 23,514,624,000.
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