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Need help Physics Will make Brainliest
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Force between q1 and q2
F= (8.99*10^9)(8*10^-6)(3.5*10^-6)
F= 25.2 N
Meaning 25.2 N to the right
Force between q2 and q3
F= (8.99*10^9)(3.5*10^-6)(-2.5*10^-6)
F= -3.5 N
Meaning 3.5 N to the left
Resultant force= 25.2-3.5
Resultant force on q2= 21.6 N to the right
Hope this helps :)
The net force on particle q₂ is 1.05 x 10¹³ N, directed towards particle q1.
To find the net force on particle q₂, we need to calculate the force between q₁ and q₂, and the force between q₂ and q₃, and then add these two forces together.
The force between two point charges can be calculated using Coulomb's law, which states that
F = k × q₁× q₂ / r²
where F is the force, k is Coulomb's constant (9.0 x 10⁹ N m² / C²), q₁ and q₂ are the magnitudes of the charges, and r is the distance between the charges.
The force between q₁ and q₂ is
F₁ = k × q₁ × q₂ / r₁²
where r₁ = 0.10 m.
Substituting the values, we get
F₁ = 9.0 x 10⁹ N m² / C² × 8.0 C × 3.5 C / (0.10 m)² = 2.52 x 10¹³ N
The force between q₂ and q₃ is
F₂ = k × q₂ × q₃ / r₂²
where r₂ = 0.15 m.
Substituting the values, we get
F₂ = 9.0 x 10⁹ N m² / C² × 3.5 C × (-3.5 C) / (0.15 m)² = -1.47 x 10¹³ N
Note that the negative sign indicates that the force is attractive, since q₂ and q₃ have opposite signs.
The net force on q₂ is the vector sum of F₁ and F₂
\(F_{net}\) = F₁ + F₂ = 2.52 x 10¹³ N - 1.47 x 10¹³ N = 1.05 x 10³ N
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A rollercoaster slows as it travels up a hill.
Speed
Velocity
Acceleration
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Please mark me brainliest !!
WILL MARK BRAINLIEST PLS HELPPP -- Which of Newton’s Laws explains why the satellite would collide with the moon if gravity is “turned off?”
picture attached
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Answer:
b
Explanation:
You put your book on the bus seat next to you. When the bus stops suddenly the book slides forward off the seat. Why?
A.) The book received a push from the seat hitting it.
B.) The force applied by the bus caused it to accelerate forward.
C.) The book's inertia carried it forward.
D.) The book could never slide forward to begin with.
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Answer:
C) The book's inertia carried it forward.
When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.
The law of Conservation of energy states that energy can be transformed from one form to another, but it cannot be _______ or ________.
A. radiated, conducted
B. created, changed
C. changed, destroyed
D. created, destroyed
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Answer:
D
Explanation:
what do you mean by MA of a lever is 3 , VR of a lever is 4 and efficiency of a machine is 60%
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The voltage and power ratings of a particular light bulb, which are its normal operating values, are 110 V and 60 W. Assume the resistance of the filament of the bulb is constant and is independent of operating conditions. If the light bulb is operated at a reduced voltage and the power drawn by the bulb is 36 W. What is the operating voltage of the bulb?
a. 78 V
b. 72 V
c. 66 V
d. 90 V
e. 85 V
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Answer:
c. 66 V
Explanation:
p =IV
I =P/V
P1/V1=P2/V2
60/110=36/V2
0.55 = 36/V2
V2 =36/0.55 = 65.5V
V2 = 66V
Which of the following statements is NOT true?
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Answer:
D
Explanation:
hope i helped ya :D
Answer: The magnetic poles of Earth are at the same locations of as the geographic poles is false.
Explanation:
Personal computers are a fixture in most business and in many homes.
true or false
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true
Explanation:
computers have become a need in many businesses and homes we now living in a era of technology a computer is now a neccecity
The statement is True.
Personal computers have become an essential fixture in most businesses and households.
They have revolutionized the way we work, communicate, access information, and perform various tasks.
In the business world, personal computers are ubiquitous, serving as indispensable tools for productivity, data management, communication, and decision-making.
From small businesses to large corporations, computers have streamlined operations and enhanced efficiency.
Similarly, in homes, personal computers have become commonplace, enabling individuals and families to connect with the world, pursue online education, engage in entertainment, and manage various aspects of their lives.
With their versatility and functionality, personal computers have become an integral part of modern life, transforming the way we live and work.
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Scott drives a jeep 12 km east, then 4 km north, then finally 3 km west. He traveled a total distance of:
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Answer:
Using the pythagoras theorem
S²=9²+4²
S²=81+16
S²=97
S=9.85km.
In finding the direction
tan□=opposite/Adjacent
=4/9
□=23.96
¤=90-23.96
=66.03 degrees
9.85, N 66.03 E
what is the work done on the box from x = 0m to 16m
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Answer:
Explanation:
The Workdone is the product of force and distance, Hence, the Workdone on the box from distance x = 0 meters and x = 16 meters is 0 Joules.
Using the graph given :
The work done from x = 0 to x = 16 metres ;
The distance can be split evenly into :
(x = 0 to x = 8) and (x = 8 to x = 16)
Workdone = Force × distance
Workdone from ; x = 0 to x = 8 ;
Force at a distance of 8 meters = - 40N
Workdone = - 40N × 8 m = -320 Nm
Workdone from ; x = 8 to x = 16 ;
Force at a distance of 16 meters = 40 N
Workdone = 40 N × 8 m = 320 Nm
The total workdone :
(-320 + 320) Nm = 0 J
.
Therefore, the Workdone ls 0 Joules.
5. You are sitting at your dinner table and notice three peas have fallen off of your plate as shown below. if each pea has a mass of M= 0.230 g and D=3 cm find the magnitude and direction of the net gravitational force on the Pea labeled M1
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Given that the mass of the pea if m1 = 0.23 g = 0.023 kg
We have to find the net gravitational force.
The net gravitational force can be calculated by the formula
\(F1=m1\text{ g}\)Here, g = 9.81 m/s^2 is the acceleration due to gravity.
The net gravitational force can be calculated as
\(\begin{gathered} F1=0.023\times9.81 \\ =0.\text{ 226 N} \end{gathered}\)
Thus, the magnitude of net gravitational force is 0.226 N in the downward direction.
The way in which one atom interacts with another atom is mostly influenced by the configuration of the
A. electrons farthest from the nucleus.
B. protons in the center of the nucleus.
C. electrons closest to the nucleus.
D. protons on the outer edge of the nucleus.
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The way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.
Option A.
What is atom?An atom can be defined as the smallest part of a substance that cannot be broken down chemically. Each atom has a nucleus (center) made up of protons (positive particles) and neutrons (particles with no charge).
The arrangement of electrons in orbitals and shells around the nucleus is referred to as the electronic configuration of the atom.
Thus, we can conclude that the way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.
The remaining options do not fit the empty space properly, and they include;
protons in the center of the nucleus.electrons closest to the nucleus.protons on the outer edge of the nucleus.Learn more about electron configuration here: https://brainly.com/question/26084288
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What kind of object are the light rays interacting with in the model below?
Convex mirror
Convex lens
Concave mirror
Concave lens
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Answer:
Concave lens
.............
Luminous intensity depends on what values?
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It is dependent on the sensitivity of the eye to the entire spectrum of visible wavelengths emitted by the source, and the radiant flux (or radiant power) produced at each wavelength. We weight the radiant flux at each wavelength using the luminosity function V-lambda.
What is the altitude of Polaris at point A?
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The Polaris indicates the direction towards the north
The correct option for the latitude of the Polaris at point A, is the option;
10°
The reason the above option is correct is given as follows;
The Polaris, which is the Pole Star or North Star, is situated at approximately the north celestial pole, such that the northern sky turns around it and therefore, it appears almost to remain at a fixed location
Due to the location of the Polaris in the north celestial pole, the angle to the Polaris, and therefore, its altitude corresponds to the latitude of the observer above the equator)
Therefore, given that the latitude at point A, is 10°N, the altitude of the Polaris at point A is also 10°
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The Sun has a mass of 1.99x1030kg and is a distance of 1.49x1011m from Earth (mass: 3.97x1024kg), using the gravitational constant (6.67x10-11Nm2/kg2), determine force of gravity that exists between them.
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What is the mass (in kg) of a Puffin flying 10 m/s with 1000 J of KE?
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Answer:
20 kg
Explanation:
The kinetic energy (KE) of an object is given by:
KE = (1/2) * m * v^2
Where m is the mass of the object, and v is its velocity.
We can rearrange this formula to solve for the mass:
m = 2 * KE / v^2
Plugging in the values given:
m = 2 * 1000 J / (10 m/s)^2
m = 20 kg
Therefore, the mass of the Puffin flying at 10 m/s with 1000 J of KE is 20 kg.
A ball is thrown straight up. At the top of its path, the magnitude of the net force acting
on it is?
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Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?
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Based on the information, it should be noted that the resistance R is 0.5 Ω.
How to calculate the resistanceWhen S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:
Z = jωL - 1/(jωC)
Since i leads e by 30°, we can express the phasor relationship as:
I = k * e^(j(ωt + θ))
Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)
Re(Z) = 0
By equating the real parts, we get:
0 = 0 - 1/(120πC)
Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:
Z = R + jωL - 1/(jωC)
Z = R + jωL
Im(Z) = ωL > 0
Substituting the angular frequency and rearranging the inequality, we have:
120πL > 0
L > 0
This condition implies that the inductance L must be greater than zero.
When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:
Z = R + jωL - 1/(jωC)
Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:
I = 0.5 * e^(j(ωt + θ))
By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:
Re(Z) = R
Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R
Therefore, the resistance R is 0.5 Ω.
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The definition of agility
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Thirty five soccer players were challenged to do as many sit-ups possible in two minutes
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Answer:
Explanation:
What is the question?
at what speed is the top of the ladder along w the electrician sliding down the wall at that instant
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The given problem can be exemplified in the following diagram:
We are given that a ladder is against a wall. According to the diagram, the ladder, the wall, and the floor form a right triangle, therefore, if "T" is the distance from the top to the floor and "B" is the distance from the bottom to the wall we can apply the Pythagorean theorem and we get:
\(T^2+B^2=14^2\)Now, since we want to know the speed, we will derivate implicitly with respect to time on both sides of the equation:
\(2T\frac{dT}{dt}+2B\frac{dB}{dt}=0\)Now we solve for the value of the speed of the top of the ladder, this is dT/dt:
\(2T\frac{dT}{dt}=-2B\frac{dB}{dt}\)The 2 cancels out:
\(T\frac{dT}{dt}=-B\frac{dB}{dt}\)Now we divide both sides by "T":
\(\frac{dT}{dt}=-\frac{B}{T}\frac{dB}{dt}\)Now, since we determine the value of "T" from the Pythagorean theorem, we get:
\(T^2+B^2=14^2\)Subtracting B squared from both sides:
\(T^2=14^2-B^2\)Taking the square root:
\(T=\sqrt[]{14^2-B^2}\)Now we replace these values in the formula for the velocity:
\(\frac{dT}{dt}=-\frac{B}{\sqrt[]{14^2-B^2}}\frac{dB}{dt}\)Now we have an expression for the velocity of the top of the ladder. Replacing the given values:
\(\frac{dT}{dt}=-\frac{6ft}{\sqrt[]{14^2-(6ft)^2}}(1\frac{ft}{s})\)Solving the operations we get:
\(\frac{dT}{dt}=-0.47\frac{ft}{s}\)Therefore, the speed of the top of the ladder is -0.47 feet per second.
There is a uniform magnetic field of magnitude B, pervading all space, perpendicular to the plane of rod and rails. The rod is released from rest, and it is observed that it accelerates to the left. In what direction does the magnetic field point?
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The right hand rule to find the direction of the magnetic field for a falling bar is:
The charge is positive the magnetic field is outgoing, horizontally and towards us. The charge of the bar is negative, the magnetic field is incoming, that is horizontal away from us.
The magnetic force is given by the vector product of the velocity and the magnetic field.
F = q v x B
Where the bolds indicate vectors, F is the force, q the charge on the particle, v the velocity and B the magnetic field.
In the vector product, the vectors are perpendicular, which is why the right-hand rule has been established, see attached:
The thumb points in the direction of speed. Fingers extended in the direction of the magnetic field. The palm is in the direction of the force if the charge is positive and in the opposite direction if the charge is negative.
They indicate that the bar is dropped, therefore its speed is vertical and downwards, it moves to the left therefore this is the direction of the force, we use the right hand rule, the magnetic field must be horizontal, we have two possibilities:
If the charge is positive the magnetic field is outgoing, horizontally and towards us. If the charge of the bar is negative, the magnetic field is incoming, that is, horizontal away from us
In conclusion using the right hand rule we can find the direction of the magnetic field for a falling bar is:
The charge of the bar is negative, the magnetic field is incoming, that is horizontal away from us.The charge is positive the magnetic field is outgoing, horizontally and towards us.
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Select the correct answer
A periodic wave travels from one medium to another. Which pair of variables are likely to change in the process?
A
velocity and wavelength
B
velocity and frequency
C
frequency and wavelength
D.
Frequency and Phase
E.
Wavelength and phase
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Answer:
velocity and wavelength
Explanation:
When a ray of light moves from one medium to another, the ray of light changes the direction when it enters the second medium, refraction of light occurs.
When it changes the direction, the frequency will remain the same because it depends only on the source not on the medium.
As the refractive index of two medium is not same, it means the wavelength will change.
Also, speed = frequency × wavelength
So, wavelength and velocity changes. Hence, the correct option is (a).
Answer:
velocity and wavelength
Explanation:
A scientist adds different amounts of salt to 5 bottles of water. She then measures how long it takes for the water to boil. What is the responding variable in this experiment
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Answer:
the responding variable is the water boiling
Explanation:
a responding variable is the same thing as a dependent variable and an independent variable you change the independent variable is the amount of salt, the control group is how long water takes to boil without adding salt, and a constant is the same amount of water
The refractive indices of materials A and B have a ratio of nA/nab=1,33. The speed of light in material A is 1.25 times 10^8m/s. What is the speed of light in material B?
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The speed of light in material B is 1.6625 × 108 m/s.
The refractive index of a material is its optical density relative to that of a vacuum.
Material B has a refractive index of nB, and its speed of light is vB.
The speed of light in material A is given as 1.25 x 108 m/s.
The refractive indices of materials A and B have a ratio of nA/nB = 1.33.
We will use the formula:
nA/nB = vB/vA = nA/nB.
Therefore, nA/nB = vB/1.25 x 108 m/s.
This equation can be rearranged to give the speed of light in material B:
vB = nA/nB × 1.25 x 108 m/s.
Therefore, vB = 1.33 × 1.25 × 108 m/s.
We will perform this calculation:
vB = 1.6625 × 108 m/s.
Therefore, the speed of light in material B is 1.6625 × 108 m/s.
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If you know the position vectors of a particle at two points along its path and also know the time it took to move from one point to the other, can you determine the particles instantenious velocity? its average velocity? explain.
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We need the position vectors of a particle at two points along its path and also know the time it took to move from one point to the other to find the instantaneous velocity but not the average velocity.
What is the velocity?We need to take a moment to be able to explain to ourselves again the meaning of the term velocity. Let us recall that the term velocity would have to do with the change in the position of an object with time.
We know that the velocity is a vector quantity and as such we must have to look at the direction in which the distance that has been covered has passed through and this is something that we must keep in mind as we work through this question.
Now, we know that the velocity is the change in position as such we need the two positions of the object and the approximate time taken to make the change.
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assignment questions
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Answer:
which on a is the question
When a 2.50 - kg object is hung vertically on a certain light spring described by Hooke’s law, the
spring stretches 2.76 cm. (a) What is the force constant of the spring? (b) If the 2.50 - kg object is
removed, how far will the spring stretch if a 1.25 - kg block is hung on it? (c) How much work must
an external agent do to stretch the same spring 8.00 cm from its unstretched position?
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The work done in the spring is calculated to be 2.8 J
What is Hooke's law?Hooke's law states that, the extension of a given material is directly proportional to the applied force as long as the elastic limit is not exceeded . First, we must bear in mind that the material must remain within the elastic limit for us to apply the Hooke's law in solving the problem.
Now;
From Hooke's law;
F = Ke
F = force applied
K = force constant
e = extension
F = W = mg = 2.50 - kg * 9.8 m/s^2 = 24.5 N
K = 24.5 N/ 2.76 * 10^-2
K = 888 N/m
e = F/K
F = W = 1.25 - kg * 9.8 m/s^2 = 12.25 N
e = 12.25 N/ 888 N/m = 0.014 m or 1.4 cm
Work done by an external agent = 1/2 Kx^2
= 0.5 * 888 * (8 * 10^-2)^2
= 2.8 J
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