pls someone help me with this plsss

the equation of the tangent line is: y = -25x - 16TTo find the slope (m) of the tangent line to the curve y = √(6 - 75x) at the point (-1, 9), we first need to find the derivative of the curve with respect to x.

Let's differentiate y with respect to x using the chain rule:

dy/dx = d(√(6 - 75x))/dx = (1/2)(6 - 75x)^(-1/2) * (-75)

Now, we can find the slope of the tangent line at the point (-1, 9) by evaluating the derivative at x = -1:

m = (1/2)(6 - 75(-1))^(-1/2) * (-75) = (1/2)(81)^(-1/2) * (-75)

m = -25

Now we have the slope of the tangent line, m = -25. To find the equation of the tangent line, we can use the point-slope form of a linear equation: y - y1 = m(x - x1). We have the point (-1, 9) and the slope -25, so:

y - 9 = -25(x - (-1))

Simplify the equation:

y - 9 = -25(x + 1)

y = -25x - 25 + 9

Therefore, the equation of the tangent line is:

y = -25x - 16

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Answer: He paid 0.50 cents in tax.

Step-by-step explanation:

Answer: hello the dot plots related to your question is missing attached below is the missing Dot plots

answer: The distribution for Group A is symmetric, and the distribution for Group B is skewed to the right.

Step-by-step explanation:

The true statement is

The distribution for Group A is symmetric, and the distribution for Group B is skewed to the right.

This is because the data value of 10 in Group B makes it to be skewed to the right

The total cost  of he meat with tax and tip is $ 22.42

To calculate the total cost with tax and tip, we need to follow these steps:

multiply the meal cost by the tip rate. when  the tip rate is 18%, we have:

Tip amount = $19.00 * 0.18 = $3.42

Add the meal cost, sales tax, and tip amount to get the total cost:

Total cost = Meal cost + Sales tax + Tip amount

= $19.00 + $3.42

= $ 22.42

Therefore, the total cost with tax and tip is $22.42

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The linear equation y = -6x + 2; -12x - 2y = -4 has no solution

y = -6x + 2

-12x - 2y = -4

-12x - 2y = -4

-12x - 2(-6x + 2) = -4

-12x + 12x -4 = -4

-12x + 12x = - 4 + 4

0 = 0

y = -6x + 2

y - 2 = -6x

x = (y - 2) / -6

-12x - 2y = -4

-12(y- 2)/ 6 - 2y = -4

(-12y + 24) / 6 - 2y = -4

-2y + 4 - 2y = 4

0 = 0

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Using the concepts of domain and range of functions, we have that:

10. The range is y ≥ 2.

11. The domain is all real numbers, the range is y ≤ 3, and it is a function.

12. The domain is (-4,3], and the range is (-5,5).

Hence, for these problems:

10. The range is y ≥ 2.

11. The domain is all real numbers, the range is y ≤ 3, and it is a function.

12. The domain is (-4,3], and the range is (-5,5).

In item 11, we have that it is a function because it has no vertically aligned points, that is, each value of x is associated with only one value of y.

In item 12, the open intervals are due to the open circles at the extremes of the domain and the range on the graph.

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Based on the given grade distribution, Paulina's conclusion (C) that most of the class made between a 71 and an 80 is the best conclusion among the options provided.

What is the average?

This is the arithmetic mean and is calculated by adding a group of numbers and then dividing by the count of those numbers. For example, the average of 2, 3, 3, 5, 7, and 10 is 30 divided by 6, which is 5.

To determine who has the best conclusion among Joe, Collin, Paulina, and Quannah, let's evaluate each statement in relation to the given grade distribution:

A. Joe said the average grade was a 75.

Since we have the grade distribution, we can calculate the average grade to verify Joe's statement. However, the distribution alone is not sufficient to determine the average grade. We would need additional information such as the exact values within each grade range. Therefore, we cannot determine if Joe's conclusion is the best based solely on the given information.

B. Collin said almost 15% made between a 91 and a 100.

Based on the given grade distribution, we can calculate the percentage of students who fall within the range of 91-100. In this case, it is 10 students out of a total of 35 students. So, the percentage is approximately 28.6%, not close to 15%. Therefore, Collin's conclusion is not accurate based on the given information.

C. Paulina said most of the class made between a 71 and an 80.

Considering the grade distribution, the largest number of students (12) falls within the range of 71-80. Thus, Paulina's conclusion aligns with the data and can be considered the best conclusion based on the given information.

D. Quannah said that most of the students understood the concepts that were not tested.

The given grade distribution does not provide information about the understanding of concepts. It solely represents the distribution of grades. Therefore, Quannah's conclusion cannot be determined based on the given information.

hence, Based on the given grade distribution, Paulina's conclusion (C) that most of the class made between a 71 and an 80 is the best conclusion among the options provided.

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Identical at both ends, a prism is a three-dimensional solid object 145.0625 in2.

the outer face, outside, or exterior limit of a thing; topmost or uppermost layer or area. the six surfaces of a cube; any face of a body or entity.

Surface area; the size or area of the outside of the face. the outside, especially in contrast to the inside nature: to investigate something more deeply. surface, a group of points arranged in two dimensions (flat surface), a group of points arranged in three dimensions (curved surface), or the perimeter of any three-dimensional object.

In general, a surface is a continuous barrier that separates two areas of a three-dimensional space.

There are small cracks all over the surface of the picture. There are tiny cracks all over the surface of the picture. The surface of the bowl is gleaming.

145.0625 in2

180.625 in2

264.625 in2

290.125 in2

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Answer:

D, X^2 -18 + 81 = -45 + 81

Step-by-step explanation:

it is complating squer method that used for solving x in a quadratic equetion . in this step you will add

(y/2)^2 if y is the cofitient of x .

Answer:

Step-by-step explanation:

well if you 6+2 is 8 that is the one's place then 50+10 is 60 that is the tens place then 300+100 is 400 that is the hundreds place and add 400+60+8 is 468

You Welcome

Answer:

x^2y^-4

Step-by-step explanation:

Answer:

i think the answer is x²y/6

number 3 going across the x axis

number 5 going across the y axis

The numbers arranged in order from least to greatest is: √146, 12.39, 12.62, 12⅝, and 12¾. The third option is correct.

The ordering of numbers refers to arranging numbers in a specific sequence based on their magnitude or value. The ordering of numbers is determined by their relative values. Comparisons are made between numbers to determine their position in the order.

12⅝ = 101/8 = 12.645

12.62 = 12.62

√146 = 12.0830

12.39 = 12.39

12¾ = 51/4 = 12.75

Therefore, the numbers arranged in order from least to greatest is: √146, 12.39, 12.62, 12⅝, and 12¾.

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To the nearest percent, the probability that an earthquake will occur while you are at work is approximately 23%.

The probability that an earthquake will occur while you are at work can be calculated by dividing the number of hours you are at work by the total number of hours in a year.
Step 1: Calculate the total number of hours in a year:
There are 24 hours in a day, so multiplying 24 by 365 (the number of days in a year) gives us 8,760 hours in a year.
Step 2: Calculate the number of hours you are at work in a year:
Since you work 8 hours per day, multiply 8 by 250 (the number of days you work in a year) to get 2,000 hours.
Step 3: Calculate the probability:
Divide the number of hours you are at work (2,000) by the total number of hours in a year (8,760) and multiply by 100 to convert to a percentage.
Probability = (2,000 / 8,760) * 100 = 22.83%
Therefore, to the nearest percent, the probability that an earthquake will occur while you are at work is approximately 23%.

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Answer:

x^2 + 77x + 670 = 0

Step-by-step explanation:

x^2 + bx + c = 0

100 - 10b + c = 0

4489 - 67b + c = 0

4389 - 57b = 0

b = 77

100 - 770 + c = 0

c = 670

The Laplace transform of the function f(t) =2t⁴ + 3t² + 5 is given by:

L[2t⁴ + 3t² + 5] = 2/s⁵ + 3/s³ + 5.

Here, we have,

To find the Laplace transform of the function f(t) = 2t⁴ + 3t² + 5,

we can apply the linearity property of the Laplace transform.

The Laplace transform of a constant is given by:

L[a] = a/s,

where 'a' is a constant and 's' is the complex variable.

Applying this property to each term in the function, we have:

L[2t⁴] = 2/s⁵,

L[3t²] = 3/s³,

L[5] = 5/s⁰.

Since s⁰ = 1, the Laplace transform of the constant term 5 is simply 5.

Combining these results using the linearity property, we get:

L[2t⁴ + 3t² + 5] = 2/s⁵ + 3/s³ + 5.

Therefore, the Laplace transform of the function f(t) =2t⁴ + 3t² + 5 is given by:

L[2t⁴ + 3t² + 5] = 2/s⁵ + 3/s³ + 5.

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Answer:

40

Step-by-step explanation:

y = 4

z = 2

8y + 12 - 2z

8(4) + 12 - 2(2)

32 + 12 - 4

44 - 4

40

Answer:

40

Step-by-step explanation:

Answer: x = 18 and y = 14
The difference is 4, and half of 18 is 9 and 9 + 14 is 23

Step-by-step explanation:

Keep the 2 numbers as 2 variables
x - y = 4

x + (y/2) = 23

We can use the substitution method here

x = 4 + y

4+y + (y/2) = 23

y = 14

x = 4 + y

x = 4 + 14

x = 18

Answer:

Cost of 15 oranges=Rs. 40

Cost of 1 orange=Rs.  

15

40

​

Cost of 3 dozen oranges=

15

40

​

×3×12(1 dozen=12)

∴ Cost of 3 dozen oranges=Rs. 96.

Step-by-step explanation:

Hope it helps and have a great day

To calculate the cash balance at the end of the period, we need to consider the cash inflows and outflows.

Starting cash balance: $4,520

Cash inflows: $1,654 (receivables collected)

Cash outflows: $1,961 (payments to suppliers) + $500 (cash expenses)

Total cash inflows: $1,654

Total cash outflows: $1,961 + $500 = $2,461

To calculate the cash balance at the end of the period, we subtract the total cash outflows from the starting cash balance and add the total cash inflows:

Cash balance at the end of the period = Starting cash balance + Total cash inflows - Total cash outflows

Cash balance at the end of the period = $4,520 + $1,654 - $2,461

Cash balance at the end of the period = $4,520 - $807

Cash balance at the end of the period = $3,713

Therefore, the cash balance at the end of the period is $3,713.

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The value of x is: 75°

360° - 128° - 85° - 72° = 75°

It cannot be determined. At least one other point on the line is needed to determine if x is proportional to y

Given data ,

A point on a straight line has an x-coordinate of 3 and a y-coordinate of 6

Now , A single point on a straight line does not define the connection between x and y. We must evaluate the connection between x and y for several places on the line in order to establish if x is proportional to y.

As a result, the relationship between x and y cannot be inferred only from the supplied location (3, 6). To establish the proportionality between x and y, at least one more point on the line is required

Hence , the equation of line is solved

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Answer:

\(\frac{1}{x^{\frac{5}{3}}}\)

Step-by-step explanation:

\(\frac{-5}{3}=-\frac{5}{3}\\x^{-\frac{5}{3}}\\x^{-\frac{5}{3}}=\frac{1}{x^{\frac{5}{3}}}\\\frac{1}{x^{\frac{5}{3}}}\)

➲ Hope this helps.

Answer:

The coefficient of n sub 3 will be the -5.

Answer:

1,875$ in intrest

Step-by-step explanation:

10000x.0375x5=1875

dy/dt = 10/3 when x = 1, y = 2, and dx/dt = 5. We can calculate it in tis manner:

Given that x and y are functions of t. The values of dx/dt, x = 1 and y = 2 are given. Also, y³ = 2x⁴ + 6

We have to find dy/dt.

Let's find the value of x at t = 1, using dx/dt=5∴ (d/dt)x = 5⇒ (d/dt)x = (d/dt)(1) = 5

Integrating both sides w.r.t t, we get,⇒ ∫(d/dt)x dt = ∫5 dt⇒ x = 5t + C1

Where C1 is the constant of integration. Given that x = 1 at t = 0. So, substituting these values in the above equation, we get,1 = 5(0) + C1⇒ C1 = 1So, x = 5t + 1

Also, we are given that y³ = 2x⁴ + 6By differentiating w.r.t t on both sides, we get,⇒ (d/dt)y³ = (d/dt)(2x⁴ + 6)⇒ 3y² (d/dt)y = 8x³ (d/dt)x⇒ (d/dt)y = 8x³ (d/dt)x / 3y²Now, we know that (d/dt)x = 5 and x = 1, y = 2.

So, substituting these values in the above equation, we get,(d/dt)y = 8(1³)(5) / 3(2²)⇒ (d/dt)y = 20/12⇒ (d/dt)y = 5/3

Therefore, dy/dt = 5/3
To find dy/dt, first differentiate the given equation y^3 = 2x^4 + 6 with respect to t using the chain rule.

Differentiating both sides with respect to t, we get:

3y^2(dy/dt) = 8x^3(dx/dt)

Now, substitute the given values x = 1, y = 2, and dx/dt = 5 into the equation:

3(2)²(dy/dt) = 8(1)^3(5)

12(dy/dt) = 40

Solve for dy/dt:

dy/dt = 40/12

Simplify the fraction:

dy/dt = 10/3

Therefore, dy/dt = 10/3 when x = 1, y = 2, and dx/dt = 5.

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12. 5x² - 180 = 0

5x² = 0 + 180

5x² = 180

x² = 180/5

x² = 36

x = √36

x = 6

13. 3x² - 100 = 332

3x² = 332 + 100

3x² = 432

x² = 432/3

x² = 144

x = √144

x = 12

14. ⅔x² - 8 = 16

⅔x² = 16 + 8

⅔x² = 24

2x² = 24 × 3

2x² = 72

x² = 72/2

x² = 36

x = √36

x = 6

15. ½x² - 5 = 5

½x² = 5 + 5

½x² = 10

x² = 10 × 2

x² = 20

x = √20

16. x² + 1 = 3x² - 13

1 + 13 = 3x² - x²

14 = 2x²

14/2 = x²

7 = x²

√7 = x

17. 2(x² + 4) = 10

2x² + 8 = 10

2x² = 10 - 8

2x² = 2

x² = 2/2

x² = 1

x = √1

x = 1

18. 3(x² - 1) = 9

3x² - 3 = 9

3x² = 9 + 3

3x² = 12

x² = 12/3

x² = 4

x = √4

x = 2

19. 2(x + 3)² = 8

2(x² + 3² + 2×x×3) = 8

2(x² + 9 + 6x) = 8

2x² + 18 + 12x = 8

2x² + 12x = 8 - 18

2x² + 12x = -10

2(x² + 6x) = -10

x² + 6x = -10/2

x(x + 6) = -5

x + 6 = -5/x

6 = -5/x - x

6 = -5/x - x²/x

6 = (-5 -x²)/x

6x = -5 - x²

Answer:

$28,000+$1,000y and After 3 years James can earn more money if he changes to a job that pays him $29,000 plus a $500 raise each year

Answer:

Becky's age is equal to 20.

Step-by-step explanation:

The given expression is :

(7+11)-(8÷2)

Using Bodmas rule to solve it furthur,

(18)-4 = 14

According to the given condition, let the age is A.

The value is 6 less than her age,

14 = A-6

or

14+6 = A

A = 20

Hence, Becky's age is equal to 20.

Answer:

y equals -x/5 + 3

Answer:deformed penis

Step-by-step explanation:

1.2+&7(6–&67-7-7+7=6+7-66+7=7+7-7-