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New evidence can lead to a change in scientific knowledge. (3 points) True False

The compound that was added to the Miller-Urey experiment to allow pre-cell enclosures to form was ammonia.

In the Miller-Urey experiment, Stanley Miller and Harold Urey aimed to simulate the conditions of the early Earth's atmosphere to investigate the origins of life. They created an apparatus that contained a mixture of gases, including methane, ammonia, hydrogen, and water vapor. The mixture was then exposed to an electric spark to simulate lightning, and the resulting products were analyzed.

Ammonia played a crucial role in the formation of pre-cell enclosures, such as lipid bilayers, which are essential components of cell membranes. The ammonia in the mixture reacted with the other gases and water vapor to produce a variety of organic compounds, including amino acids, which are the building blocks of proteins. The amino acids then polymerized to form long chains, which eventually led to the formation of lipids. These lipids could then self-assemble into enclosed structures, such as vesicles, that are similar to the cell membranes of modern cells.

Overall, the addition of ammonia to the Miller-Urey experiment played a significant role in creating the conditions that allowed for the formation of pre-cell enclosures, which are critical steps in the origins of life.

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Answer: C

Explanation:

Answer:

The number of people in that specific area.

Explanation:

Answer:

I don't know the exact answer you are looking for

Answer:

A ) additional test/trial are needed

Answer:

Water is needed for iron to rust.....

Explanation:

As you can see the liquid in tube A is water liquid in tube B is a drying agent and the liquid in Tube C is Boiled water with oil above .

The only change was in Tube A, a red-brown deposit which is rust.

And Tube B and C didn't have any change.

Which results that only water can change iron to rust.

U 2 can help me by marking as brainliest.........

Answer:

In level 1, you balanced the equation N2 + H2 →  

✔ 2

NH3. What number did you place in front of ammonia (NH3)?

In level 2, you balanced the equation C + H2O → CH4 +  

✔ 1

CO2. What number did you place in front of carbon dioxide (CO2)?

In level 3, you balanced the equation NH3 + O2 → NO2 +  

✔ 6

H2O. What number did you place in front of water?

Explanation:

Edge:2020

Answer: 2,1,&6

Explanation: the answer

Answer:

it would sink to the bottom of the ocean and break in half

Explanation:

Explanation:

so if the ship was on displaced water then the ship would sink to the bottom of the ocean

COVID is a condition that occurs when individuals continue to have symptoms or develop new ones after recovering from COVID-19.

In addition to affecting human health, the presence of Long COVID can also have economic impacts, particularly on GDP growth, global imbalance, and inflation.

This essay will outline how Long COVID can affect the economy in both the short and long term.  Short-term impact of Long COVID on GDP growth, global imbalance, and inflation In the short term, Long COVID's presence is likely to have a negative impact on GDP growth.

In the immediate aftermath of a pandemic, many people may not have the confidence to return to work, travel, or participate in other activities. As a result, there may be a reduction in demand for goods and services, which can lead to a decrease in GDP growth.

In addition, businesses may face additional costs related to employee absenteeism and illness, which can further harm GDP growth. Long COVID can also lead to global imbalances, particularly in countries where the virus is prevalent.

For example, if a significant portion of a country's population is experiencing Long COVID, this can lead to a reduction in exports, as businesses may not be able to produce or deliver goods and services as efficiently.

This can lead to an increase in imports, which can contribute to a trade deficit and further harm the economy. Finally, Long COVID can lead to inflation in the short term, particularly if supply chains are disrupted.

As businesses face increased costs related to employee absenteeism and illness, they may need to increase prices to maintain profitability.

In addition, if supply chains are disrupted due to Long COVID, businesses may need to pay more for raw materials and other inputs, which can lead to an increase in prices. Long-term impact of Long COVID on GDP growth, global imbalance, and inflation In the long run, Long COVID's impact on the economy is less clear.

Some economists argue that the long-term impact of Long COVID on the economy will be minimal, particularly if effective treatments and vaccines are developed.

These individuals argue that the negative short-term impacts of Long COVID on the economy will be offset by increased spending in the future, as people resume normal activities.

Others argue that Long COVID's impact on the economy will be more significant, particularly if individuals continue to experience symptoms and are unable to return to work.

These individuals argue that Long COVID could lead to a reduction in human capital, as people may not be able to participate in the labor market as efficiently. This could lead to a reduction in productivity and harm GDP growth.

Similarly, Long COVID could contribute to global imbalances in the long term, particularly if it continues to be prevalent in certain countries. If a significant portion of the population is unable to participate in the labor market, this can lead to a reduction in exports and a trade deficit.

Finally, Long COVID could contribute to inflation in the long term, particularly if it leads to a reduction in productivity. If businesses are unable to produce goods and services as efficiently due to Long COVID, this can lead to an increase in prices over time.

In conclusion, the presence of Long COVID can have a significant impact on the economy in both the short and long term. While the short-term impact may be more significant, the long-term impact of Long COVID is still uncertain and will depend on a variety of factors, including the effectiveness of treatments and vaccines.

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Long Covid is when people have continued symptoms or health difficulties after recovering from Covid-19.

Long Covid* can affect GDP growth, global imbalances, and inflation in the short and long term.

Long Covid may hurt the economy temporarily. Long Covid can impair productivity and labour force participation. This can lower GDP and economic output. Long Covid treatment expenses can strain healthcare systems and raise inflationary pressures.

Countries with a higher prevalence of Long Covid may have a bigger load on their healthcare systems and workforce, which may aggravate economic inequities. Long Covid may worsen global inequities in countries with poor resources or healthcare facilities.

Long Covid has long-term effects. Long-term health issues can impair productivity and make returning to work difficult, lowering GDP growth. Long-term healthcare costs with Long Covid may increase government deficits and debt.

Long Covid may increase cost-push inflation. Healthcare costs, such as treatment and rehabilitation, can raise medical product and service prices. Inflationary pressures reduce consumers' purchasing power and corporate profitability, hurting the economy.

Long Covid can have complex impacts on GDP growth, global imbalances, and inflation in the short and long term. These implications will depend on Long Covid's severity and persistence, healthcare responses, and pandemic-related economic policy.

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The value of R from the ideal gas equation is 0.082 atm.L/K/mol.

The ideal gas equation is the equation that shows the relationship between pressure, and volume. moles of a gas and the temperature of a gas under ideal conditions.

The ideal gas equation is given below as follows:

PV = nRT

At standard temperature and pressure, the values of the variables are given below;

Pressure, P = 1 atm

Volume, V = 22.4 Liters

Number of moles, n = 1 mole

Temperature, T = 273.15 K

R = PV/nT

R = 1 * 22.4 / (273.15 * 1)

R = 0.082 atm.L/K/mol

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The following is not a correct statement concerning the Friedel-Crafts acylation of benzene is A. The benzene ring attacks an acylium ion.

The Friedel-Crafts acylation of benzene involves the substitution of a hydrogen atom on a benzene ring with an acyl group (RC=O), which is often produced by the reaction of an acyl chloride with a Lewis acid catalyst such as AlCl3. During the reaction, the acylium ion (R-C=O+) is generated and subsequently reacts with benzene to form the acylated product.

As per the above explanation, the benzene ring does not attack an acylium ion, but rather it is the acylium ion that attacks the benzene ring, thus the statement is incorrect. Therefore, option A "The benzene ring attacks an acylium ion" is not a correct statement concerning the Friedel-Crafts acylation of benzene.

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Answer:

a. 21.7824 g

b. 0.2362 g

c. 31.5273 g

Please see the answers in the picture attached below.

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

The mass of solute required in each case can be obtained form the stoichiometry of the reaction.

We know that the mass of each solution can be obtained from the relation;

mass/molar mass = concentration × volume

mass = concentration × volume × molar mass

a)

mass =  0.125 M  ×  1.00 L ×  174 g/mol = 21.75 g

b) mass = 0.015 M  × 375 /1000 × 42 g/mol = 0.24 g

c) mass = 0.350 M × 500/1000 × 180 g/mol =31.5 g

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Answer:

The most correct option here is D

Explanation:

The difference between a solid (ice) and a liquid (water)/gas (steam) is that the particles in a solid is tightly packed (and do not move) as against the particles in liquid which moves quite freely or those in gases that move very freely.

When a solid (for example ice) is subjected to heat, it's particles receives the heat energy, hence have a higher temperature, and starts moving from its compact position which turns the solid into liquid. This was what happened to the ice in Cynthia's iced tea. The ice got/absorbed an increased temperature from the surrounding tea and it's particles began to move (more freely) thereby causing the ice to melt.

Answer:

D

Explanation:

The balanced equation of the copper (II) hydroxide precipitation reaction can be written as follows;Cu(OH)2 (s) → Cu2+ (aq) + 2 OH- (aq)We can express the solubility product constant (Ksp) for this reaction in a mathematical equation as follows;Ksp = [Cu2+] [OH-]2

The balanced equation of the copper (II) hydroxide precipitation reaction can be written as follows;Cu(OH)2 (s) → Cu2+ (aq) + 2 OH- (aq)We can express the solubility product constant (Ksp) for this reaction in a mathematical equation as follows;Ksp = [Cu2+] [OH-]2

To find the correct solubility product constant for the reaction shown above, we must first determine the balanced chemical equation for the reaction. After writing the balanced equation, we can then identify the reactants and products present in the chemical reaction.

After identifying the products and reactants present, we can then write the expression for the solubility product constant (Ksp) for the chemical reaction. From the chemical equation shown above, the correct solubility product constant for copper (II) hydroxide (Cu(OH)2) precipitation reaction is given by;Ksp = [Cu2+] [OH-]2The answer is a mathematical equation and so it is not possible to provide a value in this case. Thus, the correct solubility product constant for the reaction shown above is expressed as Ksp = [Cu2+] [OH-]2.

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Answer:Reactants are starting materials and are written on the left-hand side of the equation. Products are the end-result of the reaction and are written on the right-hand side of the equation.

Explanation:

The reactants in a balanced chemical reaction are the starting material which reacts together to give the products in by the regrouping of atoms in the reactants.

The balanced chemical equation of a reaction represents the perfect stoichiometry of each reactants and products with their states of matter in brackets.

In a balanced reaction, the number of each element in the reactant side must be equal to their number in the product side. The number of each elements and groups in a reaction can be balanced by multiplying with suitable integers.

The atoms in the reactants are regrouping to form the products. Thus, the identity of  the new products is entirely different form that of reactants in the reaction.

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When viewing the euglena in lab, we should be able to positively identify the chloroplast and  stigma.

Chloroplasts are plant cell organelles that convert light energy into relatively stable chemical energy via photosynthetic process. By doing so, they sustain life on the Earth. Chloroplasts also provide diverse metabolic activities for the plant cells, including the synthesis of fatty acids, membrane lipids,

Chloroplasts are a type of plastid—round, oval, or disk-shaped body that is involved in synthesis and storage of foodstuffs. Chloroplasts are distinguished from other types of the plastids by their green color, which results from the presence of two pigments, chlorophyll a and chlorophyll b. A function of those pigments is to absorb light energy for process of photosynthesis.

Other pigments, such as carotenoids, are also present in the chloroplasts and serve as accessory pigments, trapping solar energy and passing it to chlorophyll. In plants, chloroplasts occur in all the green tissues, though they are concentrated particularly in the parenchyma cells of the leaf mesophyll.

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The temperature change when 720.0 g of steam at 400.0 °C absorbs 800.0 kJ of heat energy is 265 °C.

Endothermic reactions are reactions in which heat is absorbed by the reaction system from the surroundings.

Exothermic reactions are reactions in which heat is given off by the reaction system to the surroundings.

The temperature change when 720.0 g of steam at 400.0 °C absorbs 800.0 kJ of heat energy is calculated as follows:

temperature change = heat change / mass * specific heat

Specific heat of water = 4.18 J/g/°C

mass of water = 720 g

heat absorbed = 800 kJ or 800000 J

temperature change = 800000 / (4.18 * 720)

temperature change = 265 °C

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Answer:

266 Celsius

Explanation:

q=mst

t=q/ms

800.0 kj x 1000 = 800000 J

water specific heat = 4.18 or 4.184

\(t=\frac{800000J}{4.18x720C} = 265.8 C or 266 C\)

Answer:

Explanation: 15 grams trust me.!!

The compound is called cis-3-bromocyclohexanecarboxylic acid. Out of the available possibilities, this is the best decision.

The most significant functional group in C=O is the carboxylic acids. Some carboxylic acids, such citric acid, lactic acid, or fumaric acid, are produced through fermentation; the majority of these types of carboxylic acids are used in the food sector. This class of organic molecules can be obtained through several methods.

Carboxylic acids play a significant role in organic chemistry and are used to create a variety of derivatives, including esters, acid anhydrides, acid chlorides, amides, etc. They are organic substances with one or more carboxyl groups in the molecules of their molecules.

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The balanced equation is K3PO4 + 3HCl --> 3KCl + H3PO4.

In order to balance the equation, coefficients must be added to each element or molecule in the equation so that the same number of atoms of each element is present on both sides.

Starting with the potassium ions (K), there are 3 on the left side and only 1 on the right side.

Therefore, a coefficient of 3 must be added to KCl to balance the K atoms. Next, the phosphorous ion (PO4) is already balanced with 1 on each side.

Finally, looking at the hydrogen ions (H), there are 3 on the left and 1 on the right, so a coefficient of 3 must be added to HCl to balance the H atoms. This results in the balanced equation: K3PO4 + 3HCl --> 3KCl + H3PO4.

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Answer:

E = 65.37×10⁻²² J

Explanation:

Given data:

Energy of photon = ?

Frequency of photon = 9.86×10¹² Hz

Solution:

Formula:

E = h.f

Here h is planck's constant its value is 6.63×10⁻³⁴ js.

E = 6.63×10⁻³⁴ js × 9.86×10¹² Hz

  Hz =  s⁻¹

E = 65.37×10⁻²² J

The energy of photon is 65.37×10⁻²² J.

The volume of the oxygen was found to increase linearly with the increase in current.

Electrolysis has to do with the process of the decomposition of the compound by the passage of direct current through the substance.

The quantity of electric current flowing through the water directly correlates to the volume of hydrogen and oxygen created during the electrolysis of water.

The relationship can be seen to be irregular in the case of the volume of the hydrogen from the table but the volume of the oxygen was found to increase linearly with current.

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In the picture representation of electromagnetic waves,

a) Lowest frequency - C

b) Second Highest energy - A

c) Highest energy - B

d) Shortest wavelength - B

Wavelength can be defined as the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire. In wireless systems, this length is usually mentioned in meters (m), centimeters (cm), or millimeters (mm).

If the wavelength of electromagnetic waves is low, the frequency of a wave is also low and the energy is low.

If the wavelength of electromagnetic waves is short, the frequency of a wave is also high and the energy is high.

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The full electron configuration for S2- is 1s2 2s2 2p6 3s2 3p6. The atomic symbol for the noble gas that also has this electron configuration is Ar, which stands for Argon.

Neutral sulfur (S) atom and then add 2 electrons to account for the 2- charge.

The atomic number of sulfur is 16, so a neutral sulfur atom has 16 electrons. The electron configuration for a neutral sulfur atom is:

1s² 2s² 2p⁶ 3s² 3p⁴

Now, to account for the 2- charge, we need to add 2 electrons to the configuration. This will give us:

1s² 2s² 2p⁶ 3s² 3p⁶

Therefore, This electron configuration corresponds to a noble gas, which is argon (Ar). The atomic symbol for the noble gas that has the same electron configuration as S2- is Ar.

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The percentage of copper (by mass) in copper(II) nitrate trihydrate is approximately 100%.

To determine the percentage of copper (by mass) in copper(II) nitrate trihydrate, we need to calculate the molar mass of copper(II) nitrate trihydrate and the molar mass of copper in it.

The molar mass of copper(II) nitrate trihydrate can be calculated by adding up the molar masses of its individual components: copper (Cu), nitrate (NO3), and water (H2O).

Molar mass of Cu(NO3)2·3H2O = (Molar mass of Cu) + (2 × Molar mass of N) + (6 × Molar mass of O) + (3 × (Molar mass of H2O))

Molar mass of Cu(NO3)2·3H2O = (63.55 g/mol) + (2 × 14.01 g/mol) + (6 × 16.00 g/mol) + (3 × (18.02 g/mol))

Molar mass of Cu(NO3)2·3H2O ≈ 241.60 g/mol

Next, we can calculate the molar mass of copper in copper(II) nitrate trihydrate.

Molar mass of copper ≈ 241.60 g/mol

Finally, to calculate the percentage of copper (by mass) in copper(II) nitrate trihydrate, we divide the molar mass of copper by the molar mass of copper(II) nitrate trihydrate and multiply by 100.

Percentage of copper (by mass) = (Molar mass of copper / Molar mass of Cu(NO3)2·3H2O) × 100

Percentage of copper (by mass) = (241.60 g/mol / 241.60 g/mol) × 100

Percentage of copper (by mass) ≈ 100%

Consequently, copper(II) nitrate trihydrate contains almost 100% of copper (by mass).

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The remaining electron configuration, starting at 3p, is \(\(\mathrm{3p^3 4s^2 3d^5}\)\). In the given configuration, \(3p^3\) represents the filling of the 3p orbital with three electrons.

The question states that another atom has nine more electrons, so we need to determine how these additional electrons fill the remaining orbitals. The next orbital to fill after 3p is 4s. The 4s orbital can hold a maximum of two electrons, so we fill it with two electrons: \(4s^2\).

Next, we move to the 3d orbital. It can hold a maximum of ten electrons, and we need to add nine more. Therefore, we fill the 3d orbital with five electrons: \(3d^5\).

Putting it all together, the remaining configuration is \(\(\mathrm{3p^3 4s^2 3d^5}\)\).

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The vapοr pressure οf the sοlutiοn at 310 K is apprοximately 46.57 tοrr.

Tο calculate the vapοr pressure οf the sοlutiοn, we need tο determine the mοle fractiοn οf water (sοlvent) and sucrοse (sοlute) in the sοlutiοn.

Mοles οf water:

mοlar mass οf water (H₂O) = 18.015 g/mοl

mοles οf water = mass οf water / mοlar mass οf water

mοles οf water = 170 g / 18.015 g/mοl = 9.438 mοl

Mοles οf sucrοse:

mοlar mass οf sucrοse (C₁₂H₂₂O₁₁) = 342.296 g/mοl

mοles οf sucrοse = mass οf sucrοse / mοlar mass οf sucrοse

mοles οf sucrοse = 38.2 g / 342.296 g/mοl = 0.1116 mοl

Next, we can calculate the mοle fractiοn οf water and sucrοse:

Mοle fractiοn οf water (Xᵢ):

Xᵢ = mοles οf water / (mοles οf water + mοles οf sucrοse)

Xᵢ = 9.438 mοl / (9.438 mοl + 0.1116 mοl) = 0.9881

Mοle fractiοn οf sucrοse (X₂):

X₂ = mοles οf sucrοse / (mοles οf water + mοles οf sucrοse)

X₂ = 0.1116 mοl / (9.438 mοl + 0.1116 mοl) = 0.0119

Nοw we can use Raοult's law tο calculate the vapοr pressure οf the sοlutiοn:

P = Xᵢ * Pᵢ

where P is the vapοr pressure οf the sοlutiοn and Pᵢ is the vapοr pressure οf the pure cοmpοnent (water).

Substituting the values:

P = Xᵢ * Pᵢ

P = 0.9881 * 47.08 tοrr

P = 46.57 tοrr

Therefοre, the vapοr pressure οf the sοlutiοn at 310 K is apprοximately 46.57 tοrr.

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The chlorine element is present in group 7.

The elements which has 7 valence electrons , is kept in group 7.

1) Chlorine (Cl):

The atomic number of chlorine is 17 and its electronic configuration is 2,8,7. It has 7 valence electrons. Hence, it will be kept in group 7.

2) Oxygen (O):

The atomic number of oxygen is 8 and its electronic configuration is 2,6.

It has 6 valence electrons. Hence, it will be kept in group 6.

3) Lithium (Li)

The atomic number of chlorine is 3 and its electronic configuration is 2,1. It has 1 valence electrons. Hence, it will be kept in group 1.

4) Calcium (Ca):

The atomic number of calcium is 20 and its electronic configuration is 2,8,8,2. It has 2 valence electrons. Hence, it will be kept in group 2.

Therefore, chlorine element will be kept in group 7.

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